To solve this equation, we need to subtract both, 9c - 3c:
[tex]9c\text{ - 3c = 6c = 48}[/tex]Dividing by 6 at both sides of the equation
[tex]\frac{6c}{c}\text{ = }\frac{48}{6}[/tex]Then
[tex]c\text{ = 8}[/tex]Then the answer C = 8. (Option D)
Write a value that will make the relation not represent a function
Given:
There are given that the data for x and y are in the form of a table.
Explanation:
According to the concept of function:
The function is not defined when the value of x will be repeated.
That means if the input value is repeated again and again then the given relation will not function.
In the given relation, we can put 7 into the input box.
Final answer:
Hence, the value is 7.
Use the multiplication method to solve the following systems of equations. c + 3t = 7 and 3c – 2t = –12
5x – 4z = 15 and –3x + 2z = 21
–4m + 3n = 50 and 2m + n = 10
2p – 4q = 18 and –3p + 5q = 22
3a + 4b = 51 and 2a + 3b = 37
After solving the system of equations we get the values as:
c=-2 and t=3x= -57 and z=-75m=-2 and n=14p=-89 and q=-49a=5 and b=9Given the equations are as follows, we need to solve them using multiplication method:
c+3t=7 and 3c-2t=-12take c+3t=7
rearrange the terms.
c = 7-3t
substitute c value in other equation.
3(7-3t)-2t=-12
21-9t-2t=-12
21-11t=-12
-11t = -12-21
-11t=-33
t=33/11
t=3
now substitute t value in c = 7-3t
c = 7-3(3)
c=7-9
c=-2
hence t and c values are 3 and -2.
5x – 4z = 15 and –3x + 2z = 21take 5x – 4z = 15
5x = 15+4z
x=15+4z/5
substitute x value in other equation.
-3(15+4z/5)+2z=21
-45-12z+10z=105
-45-2z=105
-2z=105+45
z=-75
substitute z value in x=15+4z/5
x=15+4(-75)/5
x=-57
hence x and z values are -57 and -75.
–4m + 3n = 50 and 2m + n = 10consider, -4m+3n=50
3n = 50+4m
n=50+4m/3
substitute n value in other equation.
2m+n=10
2m+50+4m/3 = 10
6m+50+4m=30
10m=30-50
10m=-20
m=-2
substitute m value in n=50+4m/3
n = 50+4(-2)/3
n = 50-8/3
n = 42/3
n = 14
hence m and n values are -2 and 14.
2p – 4q = 18 and –3p + 5q = 22consider 2p - 4q = 18
2p = 18+4q
p = 9+2q
substitute p value in other equation.
-3p+5q=22
-3(9+2q)+5q=22
-27-6q+5q=22
-27-q=22
-q = 22+27
q = -49
now p = 9+2q
p = 9+2(-49)
p = 9-98
p=-89
hence p and q values are -89 and -49.
3a + 4b = 51 and 2a + 3b = 37consider 3a + 4b = 51
3a = 51-4b
a=51-4b/3
substitute a value in other equation.
2(51-4b/3)+3b=37
102-8b+9b=111
102+b=111
b=111-102
b=9
now, a=51-4(9)/3
a = 51-36/3
a = 15/3
a = 5
hence a and b value are 5 and 9.
Therefore, we solved the required system of equations.
Learn more about System of equations here:
brainly.com/question/13729904
#SPJ1
Find the probability that a randomly chosen point is the figure lies in the shaded region. Give all answers in fraction and percent forms.help with number 5 or all of them if u can pls
NUMBER 5:
INFORMATION:
We have a trapeze and, we need to find the probability that a randomly chosen point is the figure lies in the shaded region
STEP BY STEP EXPLANATION:
To find the probability, we must divide the area of the shaded region by the total area of the trapeze
[tex]\text{ Probability}=\frac{Shaded\text{ area}}{Total\text{ area}}[/tex]- Total area:
To calculate the total area, we must use the formula for the area of a trapeze
[tex]A_{trapeze}=\frac{(b_1+b_2)h}{2}[/tex]Where, b1 and b2 are the bases and h is the height
Then, analyzing the trapeze we can see that b1 = 20, b2 = 14 and h = 12
[tex]A_{total}=A_{trapeze}=\frac{(20+14)12}{2}=204[/tex]So, the total area is 204 square units
- Shaded area:
To find the shaded area, we must subtract the no shaded area from the total area.
We can see that the no shaded area is a rectangle with width = 14 and height = 12
Now, using the formula for the area of a rectangle
[tex]A_{rectangle}=\text{ width}\times\text{ height}=14\times12=168[/tex]Then, subtracting the area of the rectangle from the total area
[tex]A_{\text{ no shaded}}=204-168=36[/tex]So, the no shaded are is 36 square units.
Finally, the probability would be
[tex]\begin{gathered} \text{ Probability}=\frac{36}{204} \\ \text{ Simplifying,} \\ \frac{3}{17}\approx17.65\text{ \%} \end{gathered}[/tex]ANSWER:
the probability that a randomly chosen point is the figure lies in the shaded region is
[tex]\frac{3}{17}\approx17.65\text{ \%}[/tex]
Find (fog)(x) and (gof)(-1) for the functions f(x) = 3x² + 5 and g(x) = -x + 1
Answer:
Step-by-step explanation:
fog(x)=3(-x+1)^2+5
=3(x^2+2x+1)+5
=3x^2+6x+3+5
fog(x) =3x^2+6x+8
gof(x)=-(3x^2+5)+1
=-3x^2-5+1
gof(x)=-3x^2-4
gof(-1)=-3(-1)^2-4
=-3-4
gof(-1) =-7
If ¼ gallon of paint covers 1/12 of a wall, then how many quarters of paint are needed for the entire wall?
We know that
1 quarter gallon of paint ⇄ 1/12 wall
?? ⇄ 1 wall
Now we just divide both sides of the equivalence
[tex]\begin{gathered} \frac{1}{?}=\frac{\frac{1}{12}}{1} \\ \frac{1}{?}=\frac{1}{12} \end{gathered}[/tex]We clear the equation in order to find the unkown value
[tex]\begin{gathered} \frac{1\cdot12}{1}=\text{?} \\ 12=\text{?} \end{gathered}[/tex]Then, we need 12 quarters of paintUse the Quotient Rule to find the derivative of the function.f(x) = x/(x − 6)f'(x)=
ANSWER
[tex]\frac{-6}{(x-6)^2}[/tex]EXPLANATION
We want to find the derivative of the function:
[tex]f(x)=\frac{x}{x-6}[/tex]The quotient rule states that:
[tex]f^{\prime}(x)=\frac{v\frac{du}{dx}-u\frac{dv}{dx}}{v^2}[/tex]where u = the numerator of the function
v = the denominator of the function
From the function, we have that:
[tex]\begin{gathered} u=x \\ v=x-6 \end{gathered}[/tex]Now, we have to differentiate both u and v:
[tex]\begin{gathered} \frac{du}{dx}=1 \\ \frac{dv}{dx}=1 \end{gathered}[/tex]Therefore, the derivative of the function is:
[tex]\begin{gathered} f^{\prime}(x)=\frac{(x-6)(1)-(x)(1)}{(x-6)^2} \\ f^{\prime}(x)=\frac{x-6-x}{(x-6)^2} \\ f^{\prime}(x)=\frac{-6}{(x-6)^2} \end{gathered}[/tex]The sales tax on a table saw is $12.41. a. What is the purchase price of the table saw (before tax) if the sales tax rate is 7.3%? b. Find the total price of the table saw. a. The purchase price is $
We know that the tax rate is 7.3% and it corresponds to $12.41. We want to find the total price of the table saw without taxes, it is to say the 100%. We have the following equivalence:
100% ⇔ ??
7.3% ⇔ $12.41
If we divide both parts of the equivalence we will have the same result:
[tex]\frac{100}{7.3}=\frac{?\text{?}}{12.41}[/tex]Multiplying both parts of the equation by 12.41:
[tex]\begin{gathered} \frac{100}{7.3}=\frac{?\text{?}}{12.41} \\ \downarrow \\ \frac{100}{7.3}\cdot12.41=?\text{?} \end{gathered}[/tex]Now, we can find the total price of the table saw without taxes:
[tex]\begin{gathered} \frac{100}{7.3}\cdot12.41=170 \\ \text{??}=170 \end{gathered}[/tex]Answer A. the purchase price is 170
BThe total price of the table saw (it is to say, including taxes, $12.41), is
170 + 12.41 = 182.41
Answer B. the total price is 182.41
Comment on the similarities and differences for the graph of every polynomial function.
There are different graphs of polynomial functions. In terms of shape, it can go from a straight line, slanting line, parabola, to curvy graphs especially when we are graphing polynomial functions with degrees 3 or higher.
See examples below:
However, what is similar to these graphs is that each graph is continuous or has no breaks and the domain of every polynomial function is the set of all real numbers.
Find the most important variable in the problem. A bag of marbles is full with 20 marbles, 12 of which are yellow. How many are not yellow? A. the total number of marbles B. the number of yellow marbles C. the number of marbles that are not yellow
Since there are 20 marbles and 12 of them are yellow; the marbles that are not yellow is not the same number as the marbles, and neither the number of Yellow marbles because they are yellow. So the answer is C.
Consider function f, where B is a real number.
f(z) = tan (Bz)
Complete the statement describing the transformations to function f as the value of B is changed.
As the value of B increases, the period of the function
When the value of B is negative, the graph of the function
shy
and the frequency of the function
If the value of B increases, the period of the function decreases, and the frequency of the function increases. When the value of B is negative, the graph of the function reflects over the y-axis.
How to estimate the graph and the frequency of the function?Let the tangent function be f(z) = tan (Bz)
The period exists [tex]$P=\frac{\pi}{|B|}$[/tex]
The frequency exists [tex]$F=\frac{1}{P}=\frac{|B|}{\pi}$[/tex].
The period exists inversely proportional to B, therefore, as B increases, the period decreases.
Frequency exists inversely proportional to the period, therefore, as the period decreases, the frequency increases.
When B is negative, we get f(z) = tan -Bz = f(-z), therefore, the function exists reflected over the y-axis, as the graph at the end of the answer shows, with f(z) exists red(B positive) and f(-z) exists blue(B negative).
As the value of B increases, the period of the function decreases, and the frequency of the function increases. When the value of B exists negative, the graph of the function reflects over the y-axis.
To learn more about the frequency of the function refer to:
https://brainly.com/question/27195128
#SPJ13
A teacher determines the linear equation y=12x + 40 best models the number of points a student should earn on a test, y, if the student studies for x hours. Which statement is true
Given the equation:
y = 12x + 40
Where x represents the number of hours and y represents the number of points the student should earn.
To find the correct statement substitute the number of hours and points given for x and y respectively. If the left hand side of the equation equals the right hand side then the statement is the true.
We have:
1. A student who studies for 3 hours should earn about 76 points.
x = 3
y = 76
Substitute 3 for x and 76 for y.
y = 12x + 40
76 = 12(3) + 40
76 = 36 + 40
76 = 76
This statement is true.
2.
what's the difference between two whole number 1/2 percent of 36 and 30% of 10
Here, we proceed step by step, to obtain our answer,
[tex]\frac{1}{2}[/tex] % of 36 can be written as ,
0.5 % of 36 , which means,
100 % refers to 36, then
0.5 % refers to what, thus, by cross multiplication we get,
0.5 % of 36 = [tex]\frac{0.5 X 36}{100}[/tex] = 0.18 ___(1), which can be expressed in whole numbers as 0.
Now, 30 % of 10 means,
100 % refers to 10, then
30 % refers to what, thus, by cross multiplication we get,
30 % of 10 = [tex]\frac{30 X 10}{100}[/tex] = 3 __(2)
From equations (1) and (2),
the whole numbers that we obtain are 0 and 3, respectively,
Thus the difference between these two whole numbers is,
= 3 - 0 = 3.
To know more about percentage, visit,
https://brainly.com/question/26497520
#Percentage
A rectangular garden has a walkway around it. The area of the garden is 2(4.5x +1.5). Thecombined area of the garden and the walkway is 3.5(8x + 4). Find the area of the walkway aroundthe garden as the sum of two terms.The area of the walkway around the garden is(Simplify your answer. Use integers or decimals for any numbers in the expression.)
In this case, we'll have to carry out several steps to find the solution.
Step 01:
DataL
garden area = 2(4.5x +1.5)
garden + walkway area = 3.5(8x + 4)
walkway area = ?
Step 02:
walkway area:
walkway area = 3.5(8x + 4) - 2(4.5x +1.5)
= 28x + 14 - 9x - 3
= 19x + 11
The answer is:
The area of the walkway around the garden is 19x + 11
some animals on farms eat hay to get energy. A cow can eat 24 pounds of hay each day Write and evaluate an expression to find how many pounds a group of 12 cows can eat in two weeks. will send image
1 day a cow can eat = 24 pounds
1 day 12 cows can eat = 24 x 12
2 weeks = 14 days
therefore:
12 cows can eat in two weeks = 24 x 12 x 14 or 12 ( 24x14 )
answer: A. 12(24x14)
A pancake recipe asked for one and 2/3 times as much milk as flower if two and one half cups of milk is used what quantity of flower would be needed according to the recipe?
Let x be the quantity of flour used
Let y be the quantity of milk used
A pancake recipe asked for one and 2/3 times as much milk as flour:
[tex]y=1\frac{2}{3}x[/tex]If two and one half cups of milk is used what quantity of flower would be needed according to the recipe?
Find x when y=2 1/2:
[tex]2\frac{1}{2}=1\frac{2}{3}x[/tex]Write the quantities as fractions;
[tex]\begin{gathered} 2+\frac{1}{2}=(1+\frac{2}{3})x \\ \\ \frac{4}{2}+\frac{1}{2}=(\frac{3}{3}+\frac{2}{3})x \\ \\ \frac{5}{2}=\frac{5}{3}x \end{gathered}[/tex]Solve x:
[tex]x=\frac{\frac{5}{2}}{\frac{5}{3}}=\frac{15}{10}[/tex]Write the answer as a mixed number:
[tex]\frac{15}{10}=\frac{10}{10}+\frac{5}{10}=1+\frac{5}{10}=1+\frac{1}{2}=1\frac{1}{2}[/tex]Then, for 2 1/2 cups of milk would be needed 1 1/2 cups of flourAnswer: 1 1/2a line intersects the points (2,2) and (-1, 20).What is the slope of the line in simplest form?m = _
Given: The points a line intersects as shown below
[tex]\begin{gathered} Point1:(2,2) \\ Point2:(-1,20) \end{gathered}[/tex]To Determine: The slope of the line in its simplest form
Solution
The formula for finding the slope of two points is as shown below
[tex]\begin{gathered} Point1:(x_1,y_1) \\ Point2:(x_2,y_2) \\ slope=\frac{y_2-y_1}{x_2-x_1} \end{gathered}[/tex]Let us apply the formula to the given points
[tex]\begin{gathered} Points1(x_1,y_1)=(2,2) \\ Point2(x_2,y_2)=(-1,20) \\ slope=\frac{20-2}{-1-2} \\ slope=\frac{18}{-3} \\ slope=-6 \end{gathered}[/tex]Hence, the slope of the line in simplest form is -6
Would you rather have a savings account that pays 5% interest compounded semiannually or one that pays 5% interest compounded daily? Explain.
Saving account that pays 5% interest compounded daily is much better than the account that pays 5% interest compounded semiannually.
As given in the question,
Interest rate = 5%
Types of account = Saving account
Pays the interest in two forms :
Compounded semiannually and Compounded daily
Saving account that pays 5% interest compounded daily is much better than the account that pays 5% interest compounded semiannually.
Reason :
Frequency of interest given on compounded daily is much higher and increase the amount much faster as compare to compounded semiannually.
When interest compounded daily generate 365 compounding periods a year, where as compounded semiannually generates two times in a year.
Therefore, saving account that pays 5% interest compounded daily is much better than the account that pays 5% interest compounded semiannually.
Learn more about interest here
brainly.com/question/13324776
#SPJ1
Write the inequality stamens in a describing the numbers (-∞,-5)
The numbers are given to be:
[tex](-\infty,-5)[/tex]This is written in Interval notation.
In "Interval Notation" we just write the beginning and ending numbers of the interval, and use:
a) [ ] a square bracket when we want to include the end value, or
b) ( ) a round bracket when we don't.
Because the interval given uses round brackets, the inequality will contain all real numbers between negative infinity and -5, but not including negative infinity and -5.
Therefore, the inequality will be:
[tex]-\inftyi432--5-4-3-2-1(3.1)2 3 45 X(0,-1)What is the equation of the line that is parallel to thegiven line and has an x-intercept of -3?Oy=x+3Oy=x+2Oy=-x+3Oy=-³x+2
Explanation:
Step 1. We are given the graph of a line and we need to find the equation of the line parallel to it that has an x-intercept of -3.
Since the new line will be a parallel line it means that it will have the same slope. Therefore, our first step is to find the slope of the current line.
Given any line, we find the slope as shown in the following example diagram:
Step 2. Using the previous method, the slope of our line is:
The new line will have the same slope of 2/3.
Step 3. We are also told that the x-intercept of the new line is -3, which means that the new line will cross the y-axis at x=-3, that point is:
(-3,0)
We will label that point of our new line as (x1,y1):
[tex]\begin{gathered} (x_1,y_1)\rightarrow(-3,0) \\ \downarrow \\ x_1=-3 \\ y_1=0 \end{gathered}[/tex]Step 4. So far, we know that the new line will have a slope of 2/3:
[tex]m=\frac{2}{3}[/tex]And that it includes the point (-3,0) where x1=-3 and y1=0.
To find the equation, we use the point-slope equation:
[tex]y-y_1=m(x-x_1)[/tex]Step 5. Substituting the known values into the formula:
[tex]y-0=\frac{2}{3}(x-(-3))[/tex]Solving the operations:
[tex]\begin{gathered} y=\frac{2}{3}(x+3) \\ \downarrow \\ \boxed{y=\frac{2}{3}x+2} \end{gathered}[/tex]Answer:
[tex]\boxed{y=\frac{2}{3}x+2}[/tex](1.2 x 10^7)(2.2 x 10^-3)
The value of the expression is:
2.64 x 10² or 26400
Step - by - Step Explanation
From the question;
(1.2 x 10⁷ )(2.2 x 10⁻³)
To sim plify the expression above, we will multiply the decimal part and then apply indices to the exponent.
That is;
[tex]1.2\times2.2\times10^{7-3}[/tex][tex]=2.64\times10^2[/tex]Or
=26400
Function g is defined as g(x)=f (1/2x) what is the graph of g?
Answer:
D.
Explanation
We know that g(x) = f(1/2x)
Additionally, the graph of f(x) passes through the point (-2, 0) and (2, 0).
It means that f(-2) = 0 and f(2) = 0
Then, g(-4) = 0 and g(4) = 0 because
[tex]\begin{gathered} g(x)=f(\frac{1}{2}x_{}) \\ g(-4)=f(\frac{1}{2}\cdot-4)=f(-2)=0 \\ g(4)=g(\frac{1}{2}\cdot4)=f(2)=0 \end{gathered}[/tex]Therefore, the graph of g(x) will pass through the points (-4, 0) and (4, 0). Since option D. satisfies this condition, the answer is graph D.
Question 2 Multiple Choice Worth 2 points)(08.07 LC)Two friends are reading books. Jimmy reads a book with 21,356 words. His friend Bob reads a book with one-and-a-half times as many words. Which expressionrepresents the number of words Bob reads?O 21,356 x 2O 21,356 x6 x 1nents1adesO 21,356 xO 21.356 x112Question 3 Multiple Choice Worth 2 points)(08.07 LC)Question 1 (Answered)OVIOUS QuestionNexd Quest
The number of words of the book Jimmy reads os 21,356, and the number of words of the book Bob reads is one-and-a-half times (that is, 1.5x) as many words, so to find the number of words Bob reads, we just need to multiply the number of words of Jimmy's book by the factor of 1.5:
[tex]21356\cdot1.5=32034[/tex]Which of the following could be an example of a function with a domain (-0,) and a range (-0,2)? Check all that apply. A. V= - (0.25)* - 2 - B. v= -(3)*-2 O c. v= -(3)*+2 1 v= - (0.25)*+2 D.
It is desired that the domain and range of the function should, respectively, be
[tex]\begin{gathered} \text{Domain}=(-\infty,\infty) \\ \text{Range}=(-\infty,2) \end{gathered}[/tex]Observe the given choices of function.
It is evident that all the functions are exponential functions, so their domain must be the set of all real numbers,
[tex](-\infty,\infty)[/tex]Now, we have to check the range of each of the 4 given functions.
Option A:
The function is given as,
[tex]y=-(0.25)^x-2[/tex]Consider the following,
[tex]\begin{gathered} x\rightarrow\infty\Rightarrow-(0.25)^x\rightarrow0\Rightarrow-(0.25)^x-2\rightarrow-2\Rightarrow y\rightarrow-2 \\ x\rightarrow-\infty\Rightarrow-(0.25)^x\rightarrow-\infty\Rightarrow-(0.25)^x-2\rightarrow-\infty\Rightarrow y\rightarrow-\infty \end{gathered}[/tex]Thus, we see that the range of the function is,
[tex]\text{Range}=(-\infty,-2)[/tex]Since this does not match with the desired range. This is not a correct choice.
Option B:
The function is given as,
[tex]y=-(3)^x-2[/tex]Consider the following,
[tex]\begin{gathered} x\rightarrow\infty\Rightarrow-(3)^x\rightarrow-\infty\Rightarrow-(3)^x-2\rightarrow-\infty\Rightarrow y\rightarrow-\infty \\ x\rightarrow-\infty\Rightarrow-(3)^x\rightarrow0\Rightarrow-(3)^x-2\rightarrow-2\Rightarrow y\rightarrow-2 \end{gathered}[/tex]Thus, we see that the range of the function is,
[tex]\text{Range}=(-\infty,-2)[/tex]Since this does not match with the desired range. This is not a correct choice.
Option C:
The function is given as,
[tex]y=-(3)^x+2[/tex]Consider the following,
[tex]\begin{gathered} x\rightarrow\infty\Rightarrow-(3)^x\rightarrow-\infty\Rightarrow-(3)^x+2\rightarrow-\infty\Rightarrow y\rightarrow-\infty \\ x\rightarrow-\infty\Rightarrow-(3)^x\rightarrow0\Rightarrow-(3)^x+2\rightarrow2\Rightarrow y\rightarrow2 \end{gathered}[/tex]Thus, we see that the range of the function is,
[tex]\text{Range}=(-\infty,2)[/tex]Since this exactly matches with the desired range. This is a correct choice.
Option D:
The function is given as,
[tex]y=-(0.25)^x+2[/tex]Consider the following,
[tex]\begin{gathered} x\rightarrow\infty\Rightarrow-(0.25)^x\rightarrow0\Rightarrow-(0.25)^x+2\rightarrow2\Rightarrow y\rightarrow2 \\ x\rightarrow-\infty\Rightarrow-(0.25)^x\rightarrow-\infty\Rightarrow-(0.25)^x-2\rightarrow-\infty\Rightarrow y\rightarrow-\infty \end{gathered}[/tex]Thus, we see that the range of the function is,
[tex]\text{Range}=(-\infty,2)[/tex]Since this exactly matches with the desired range. This is also a correct choice.
Thus, the we see that the functions in option C and D possess the desired domain and range.
Therefore, option C and option D are t
How do you determine 1 and 2/5 - 6/10 =
[tex]\frac{4}{5}[/tex].
Step-by-step explanation:1. Write the expression.[tex]1+\frac{2}{5} -\frac{6}{10}[/tex]
2. Rewrite the fractions with a common denominator.A common denominator is just a number that can be used as a denominator all fractions when we convert them through multiplications. A common denominator is usually found just by multiplying all denominators of all fractions. In this case, we don't need to go that far, since 5 could be a common denominator.This is how you do it:
[tex]1=\frac{1}{1} *\frac{5}{5}=\frac{5}{5} \\ \\\frac{2}{5}= \frac{2}{5}\\\\\frac{6}{10} =\frac{6/2}{10/2}=\frac{3}{5}[/tex]
3. Take all the rewritten fractions and rewrite the operation.[tex]\frac{5}{5} +\frac{2}{5} -\frac{3}{5}[/tex]4. Solve.[tex]\frac{5}{5} +\frac{2}{5} -\frac{3}{5} =\frac{5+2-3}{5} =\frac{4}{5}[/tex]
5. Express your result.[tex]1+\frac{2}{5} -\frac{6}{10}=\frac{4}{5}[/tex].
[tex]\frac{4}{5}[/tex].
Step-by-step explanation:1. Write the expression.[tex]1+\frac{2}{5} -\frac{6}{10}[/tex]
2. Rewrite the fractions with a common denominator.A common denominator is just a number that can be used as a denominator all fractions when we convert them through multiplications. A common denominator is usually found just by multiplying all denominators of all fractions. In this case, we don't need to go that far, since 5 could be a common denominator.This is how you do it:
[tex]1=\frac{1}{1} *\frac{5}{5}=\frac{5}{5} \\ \\\frac{2}{5}= \frac{2}{5}\\\\\frac{6}{10} =\frac{6/2}{10/2}=\frac{3}{5}[/tex]
3. Take all the rewritten fractions and rewrite the operation.[tex]\frac{5}{5} +\frac{2}{5} -\frac{3}{5}[/tex]4. Solve.[tex]\frac{5}{5} +\frac{2}{5} -\frac{3}{5} =\frac{5+2-3}{5} =\frac{4}{5}[/tex]
5. Express your result.[tex]1+\frac{2}{5} -\frac{6}{10}=\frac{4}{5}[/tex].
(3x² − 5x + 7) and (2x² + x − 2).
By using polynomial rule we can get 6x^4-7x^3+3x^2+17x-14
What is polynomial rule?
All exponent in the algebraic expressions must be non-negative integer in order for the algebraic expressions to be a polynomial.
A polynomial is defined as per an expression which is the composed of variables, constants and exponents, that are combined using the mathematical operations are such as addition, subtraction, multiplication and division.
Sol- (3x^2-5x+7).(2x^2+x-2)
(3x^2-2x^2+3x^2.x-3x^2.2)-5x.2x^2-5x.x+5x.2+7.2x^2+7.x-14
{polynomial multiplication rule}
=6x^4+3x^2-6x^2-10x^3-5x^2+1x+14x^2+7x-14
{Plus or minus with the same x coefficient}
We are get=
6x^4-7x^3+3x^2+17x-14
To know more about polynomial rule click-
https://brainly.com/question/2833285
#SPJ13
I need help with my math
Answer:
The fourth choice: y+3 = 1(x+2); y= x-1
Explanation:
The point slope form of a linear equation is
[tex]y-y_0=m(x-x_0)[/tex]where (x0,y0) is a point on the line and m is the slope.
Now we first calculate the slope.
[tex]m=\frac{3-(-3)}{4-(-2)}=\frac{6}{6}=1[/tex]therefore, we have
[tex]y-y_0=1(x-x_0)[/tex]Now we use (x0, y0) = (-2, -3) and get
[tex]y-(-3)_{}=1(x-(-2))[/tex][tex]\boxed{y+3=1\mleft(x+2\mright)}[/tex]which is our equation in point-slope form.
Now, we convert the equation above into the slope-intercept form.
Subtracting 3 from both sides gives
[tex]y+3-3=x+2-3[/tex][tex]\boxed{y=x-1}[/tex]which is the equation in slope-intercept form.
Hence, the answer to the question is
[tex]y+3=1(x+2);y=x-1[/tex]which is the fourth option.
Find the value of M and YZ if Y is between X and Z. XY = 5m YZ =m, and X2 = 25
Notice that XZ = XY + YZ
where XY = 5m
YZ = m and XZ =25
Thus,
25 = 5m + m
25 = 6m
Hence,
[tex]m\text{ = }\frac{25}{6}\text{ = 4}\frac{1}{6}\text{ }[/tex]But YZ = m
Therefore, YZ =
[tex]4\frac{1}{6}[/tex]Are they inverses?f(x) = 6x - 6, g(x) = 1/6x + 1
Given function,
f(x) = 6x - 6
or
y = 6x -6
The inverse of a function is calculated by replacing the values of x and y
therefore
Inverse (y = 6x - 6)
x = 6y - 6
x + 6 = 6y
6y = x + 6
y = x/6 + 6/6
y = 1/6*x + 1
or
g(x) = 1/6*x + 1
Hence, both are inverse of each other.
triangle QRS is shown below using the information given determine the measure of r
A solid plastic cube has sides of length 0.5 cm. Its mass is m g. Write a formula for its density in grams per cubic centimetres
The density of the cube is equal to ρ = m / L³.
What is the density of a plastic cube?
The density of the plastic cube (ρ), in grams per cubic centimeter, is equal to the mass of the cube (m), in grams, divide to the volume of the cube. The volume is equal to the cube of the side length (L), in centimeters. Then, the density of the plastic cube is:
ρ = m / L³
By using the definition of density, the density of the element is equal to ρ = m / L³.
To learn more on densities: https://brainly.com/question/15164682
#SPJ1