10. Saul works two part-time jobs. Last week, he worked 14 hours at a shoe store, and 19
hours as a telemarketer. His total pay was $240.30. The week before, he made
$300.00 for 19 hours at the shoe store and 22 hours telemarketing. Find his hourly
wage for each job

Answer:

-5y

Step-by-step explanation:

[tex]\sqrt{y^2}[/tex] = y if x > 0

-5[tex]\sqrt{y^2}[/tex] = -5y

Answer:

  d = 12

Step-by-step explanation:

In intercept form, the equation of the plane is ...

  x/a +y/b +z/c = 1 . . . . . for x, y, z intercepts a, b, c

You have (a, b, c) = (2, 3, 4), so the equation of the plane is ...

  x/2 +y/3 +z/4 = 1

Multiplying by 12 gets rid of the fractions and puts the equation in standard form:

  6a +4y +3z = 12

The value of d is 12.

B

Step-by-step explanation:

calculate how long the lines are

Answer:

A 3-column table with 4 rows. Column 1 is labeled Number of Girls with entries 2, 8, 0, 4. Column 2 is labeled Height in Inches with entries 51, 52, 53, 54. Column 3 is labeled Total Height with entries 102, 416, 0, 216. The national average height for girls in the sixth grade is also 52 inches. Find the average height of the girls in this class. The total number of girls is . The total height of the girls is inches. The expression to find the mean is . The average height of the girls in this class is inches.

Step-by-step explanation:

mark me brainliest ok

Answer:

Length = 24

Step-by-step explanation:

It says, " Both the length and  width are increased by the same amount..." this means that both 12m and 5m were increased. So 12 + 12 = 24 and 5 + 5 = 10.

lol Looks like someone has the same math assignment as me

Answer:

10y

Step-by-step explanation:

product means to multiply so you would multiply y and 10 so the options would be

10y

y x 10

Answer:

  c) ASA

Step-by-step explanation:

Angles at either end of the shared line segment are marked congruent, so the triangles can be shown to be congruent using the ASA postulate. (The shared segment is congruent to itself.)

Answer:

7y-3.5+7y-3.5+3.5y+10+3.5y+10

Step-by-step explanation:

21y+13

pls brainliest

Answer: y=2/3x+4

Step-by-step explanation:

this will be written out in y=mx+b form. M stands for the slope, and b stands for the y-intercept, or where the line intersects with the y-axis.

going left to right, the line slopes upward, therefore it is a positive slope. This means that the “m” part of the equation will be a positive number. When finding the slope, we use rise over run. On your graph, if you take one point and rise 2, then run right 3, you will find another point! We have now found that the slope is 2/3x.

let’s plug this into our equation. Y=2/3x +b

lastly, we find the y-intercept. This is simply where the line intersects with the y-axis. In this case, it is positive 4. So the y-intercept is 4.

our final equation is: y=2/3x +4

i hope this is helpful.

[tex]Area = \frac{(6 + 10) \times 7}{2} \\ [/tex]

[tex]Area = \frac{16 \times 7}{2} \\ [/tex]

[tex]Area = \frac{2 \times 8 \times 7}{2} \\ [/tex]

[tex]Area = 8 \times 7[/tex]

[tex]Area = 56 \: \: {in}^{2} [/tex]

Answer:

Area: [tex]56in^2[/tex]

Step-by-step explanation:

The formula for the area of a trapezoid is:

[tex]A = \frac{a+b}{2}h[/tex]

so replacing with the given values we get:

[tex]a = 6in\\h = 7in\\b = 10in[/tex]

[tex]A = \frac{6in+10in}{2}7in = 56in^2[/tex]

So our final answer is [tex]56in^2[/tex]

Answer:

The value of the 5 in 50.89 is 100 times the value of the 5 in 261.58

Step-by-step explanation:

The 5 in 50.89 is in the 10's place

The 5 in 261.58 is in the 1/10's place

1/10(100) = 10

The value of the cosine of angle [tex]k[/tex] is 1.

Given a point [tex](x,y)[/tex] that is a terminal arm of an angle [tex]k[/tex] in standard position, by trigonometric relations we have the following expression for the cosine:

[tex]\cos k = \frac{x}{\sqrt{x^{2}+y^{2}}}[/tex] (1)

Where:

If we know that [tex]x = 5[/tex] and [tex]y = 0[/tex], then the cosine of the angle [tex]k[/tex] is:

[tex]\cos k = \frac{5}{\sqrt{5^{2}+0^{2}}}[/tex]

[tex]\cos k = 1[/tex]

The value of the cosine of angle [tex]k[/tex] is 1.

To learn more on trigonometric relations, we kindly invite to check this verified question: https://brainly.com/question/6904750

Answer:

C

Step-by-step explanation:

Answer:

  (d)  a1 = 11

Step-by-step explanation:

Put the numbers in the given formula and solve for a1.

  a5 = 176 = a1(r^(5-1)) = a1·r^4

  a7 = 704 = a1(r^(7-1)) = a1·r^6

Dividing a7 by a5 gives ...

  a7/a5 = (a1·r^6)/(a1·r^4) = r^2 = 704/176 = 4

Then a1 is ...

  a1 = a5/(r^4) = 176/(r²)² = 176/(4²) = 11

The first term is 11.

Hi, mal :> hehehe

( its [tex]a_{1} = -11[/tex])

Your welcome..... ;]

The perimeter of a triangle is the sum of its side lengths.

The perimeter of triangle ACD is 40 units

Start by calculating the values of x and y, using the following equivalent ratios

[tex]6 : 4 = x - 2 : x - 4[/tex]

[tex]6 : 10 = 6 + x - 2 : y[/tex]

So, we have:

[tex]6 : 4 = x - 2 : x - 4[/tex]

Express as fraction

[tex]\frac 64 = \frac{x-2}{x-4}[/tex]

Cross multiply

[tex]6x - 24 = 4x - 8[/tex]

Collect like terms

[tex]6x - 4x = 24 - 8[/tex]

[tex]2x = 16[/tex]

Divide both sides by 2

[tex]x = 8[/tex]

Also, we have:

[tex]6 : 10 = 6 + x - 2 : y[/tex]

Express as fraction

[tex]\frac 6{10} = \frac{6 + x -2}{y}[/tex]

Substitute 8 for x

[tex]\frac 6{10} = \frac{6 + 8 -2}{y}[/tex]

[tex]\frac 6{10} = \frac{12}{y}[/tex]

Cross multiply

[tex]6y = 120[/tex]

Divide both sides by 6

[tex]y = 20[/tex]

The perimeter of triangle ACD is then calculated as:

[tex]P =6 + x - 2 + y + x - 4 + 4[/tex]

Substitute values for x and y

[tex]P =6 + 8 - 2 + 20 + 8 - 4 + 4[/tex]

[tex]P =40[/tex]

Hence, the perimeter of triangle ACD is 40 units

Read more about perimeter at:

https://brainly.com/question/19576164

Answer:

I believe it's the middle graph. since their is a closed dot on the first line and the other 2 inequality symbols indicate that their are 2 open dots, I think the middle is correct

Answer:

15

Step-by-step explanation:

17 squared minus 8 squared it is the pythagorean theorem but backwards. c squared minus b squared equals a squared. in this case a is b. 17 times 17 is 289 and then subtract 8 squared or 64 to get 225. then we need to find the squared root of 225 which is 15 and this is the answer

Answer:

only{(0,0), (3,0), (5,0)}    (the x axis)

Step-by-step explanation:

as all the others have more than one possible output y for a unique input x

Answer:

C = -1 1/9° or -1.11°

Step-by-step explanation:

Use the formula given, and input 30 for F

[tex]C = 5/9(F - 32)\\\\C = 5/9(30 - 32)\\\\C = 5/9(-2)\\\\C = -10/9 = -1 \frac{1}9 = -1.11[/tex]

30°F ≈ -1.11°C

-Chetan K

This value is approximate.

==================================================

Explanation:

You're given a temperature of 30 degrees F and your teacher wants to know the Celsius version of this temperature. Plug in F = 30 and simplify.

[tex]C = \frac{5}{9}(F-32)\\\\C = \frac{5}{9}(30-32)\\\\C = \frac{5}{9}(-2)\\\\C \approx 0.5555*(-2)\\\\C \approx -1.111\\\\[/tex]

The temperature 30 degrees F converts to approximately -1.111 degrees C. Fahrenheit temperatures below 32 degrees are below 0 when converted over to Celsius.

Answer:

y = −x + 5

Explanation:

Use the slope formula and slope-intercept form y = mx + b to find the equation.

Hope this helped. Have a good one!

Answer:

1):Reaction

2):Action

3):Thought

4): Dialogue

Step-by-step explanation:

Answer:

Step-by-step explanation:

Hoped this helped.

Answer: 35°

Step-by-step explanation: We have to find the measure of angle XYZ. We know, the angle subtended at the center is the average of the measure of arc intercepted by its angle and its vertical angles. Therefore, the value of ∠XYZ = 35°.

I hope this helps!

-Notsonerdy

[tex]\begin{array}{llll} x~-2y=-13\\ 5x+2y=-17\\ \cline{1-1} 6x+0y=-30 \end{array}\qquad \implies 6x=-30\implies x=\cfrac{-30}{6}\implies x=-5 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{substituting on the 1st equation}}{(-5)-2y=-13\implies }-2y=-8\implies y = \cfrac{-8}{-2}\implies y = 4 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill (-5~~,~~4)~\hfill[/tex]