Taking into account the reaction stoichiometry, given 0.842 g of NH₃ and 0.728 g of O₂, NH₃ is the excess reactant.
Reaction stoichiometryThe balanced reaction is:
4 NH₃ + 5 O₂ → 4 NO + 6 H₂O
By reaction stoichiometry, the following amounts of moles of each compound participate in the reaction:
NH₃: 4 molesO₂: 5 molesNO: 4 molesH₂O: 6 molesThe molar mass of the compounds is:
NH₃: 17 g/moleO₂: 32 g/moleNO: 30 g/moleH₂O: 18 g/moleBy reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
NH₃: 4 moles ×17 g/mole= 68 gramsO₂: 5 moles ×32 g/mole= 160 gramsNO: 4 moles ×30 g/mole= 120 gramsH₂O: 6 moles ×18 g/mole= 108 gramsDefinition of limiting and excess reagentThe limiting reactant is the one that is found in the least amount and, therefore, will be finished first at the time of the chemical reaction, resulting in the end of the reaction. In other words, when this reagent is finished, it will no longer be possible to continue generating a certain product.
The reactant in excess is one of which there is more than what is necessary for the chemical reaction to take place.
Limiting and excess reagent in this caseTo determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 68 grams of NH₃ reacts with 160 grams of O₂, 0.842 grams of NH₃ reacts with how much mass of O₂?
mass of O₂= (0.842 grams of NH₃× 160 grams of O₂)÷68 grams of NH₃
mass of O₂= 1.98 grams
But 1.98 grams of O₂ are not available, 0.728 grams are available. Since you have less mass than you need to react with 0.842 grams of NH₃, O₂ will be the limiting reagent.
Then, NH₃ will be the excess reactant.
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Oxides of active metals react with water to produce____
Metals react with water and produce a metal oxide and hydrogen gas. Metal oxides that are soluble in water dissolve in it to further form metal hydroxide. When a metal and water react.
metal oxide and hydrogen gas are formed. The fundamental equation for the metal reaction with water is metal + water = metal oxide + hydrogen. Cold water swiftly reacts with the metals sodium, potassium, and calcium to generate hydroxides. In most cases, they react with water to generate bases or with acids to form salts. MO + H2O M(OH)2 (M = a group 2 metal) As a result, these compounds are frequently referred to as basic oxides. Magnesium oxide, for example, interacts with water to generate magnesium hydroxide, which turns red litmus blue, showing that it is a base. Magnesium oxide + Water Magnesium hydroxide is the chemical formula for this reaction.
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Describe the properties of microwaves using some of the prompt words listed below: reflected,glass,plastic,atmosphere,Ionosphere ,absorbed,frequency,wavelength, heat,Vibrate.
The radiations that can emit electromagnetic energy with shorter wavelengths are these ones. Because metal surfaces reflect microwaves, Occurrences including refraction, diffraction, reflection, and interference have an impact on the transmission of microwaves.
How do microwaves and infrared waves behave?Waves made up of shifting magnetic and electric fields are used to transport both infrared and microwave energy. The heat from these waves is produced. Although they are just past the human eye's range of visibility, infrared and microwave photons can both be felt as warmth.The radiations that can emit electromagnetic energy with shorter wavelengths are these ones. Because metal surfaces reflect microwaves, Occurrences including refraction, diffraction, reflection, and interference have an impact on the transmission of microwaves.Waves made up of shifting magnetic and electric fields are used to transport both infrared and microwave energy. The heat from these waves is produced.To learn more about microwaves refer to:
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How many moles of H2O are formed?
The number of moles of water that are produced from the reaction of the combustion of 0.20 moles of ethane, C₂H₆ is 0.6 moles.
What number of moles of water are produced from the reaction of the combustion of 0.20 moles of ethane, C₂H₆?The number of moles of water that are produced from the reaction of the combustion of 0.20 moles of ethane, C₂H₆ is obtained from the mole ratio as given in the equation of the reaction.
The equation of the reaction is given below as follows:
2 C₂H₆ + 5 O₂ ---> 2 CO₂+ 6 H₂O
From the equation of the reaction, 6 moles of water are produced from the combustion of 2 moles of ethane.
The mole ratio is 1 : 3
The number of moles of water produced from 0.2 moles of ethane = 0.2 * 3 moles
The number of moles of water produced = 0.6 moles
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Complete question:
How many moles of H₂O is formed from 0.20 moles of C₂H₆?
Equation of the reaction: 2 C₂H₆ + 5 O₂ ---> 2 CO₂+ 6 H₂O
12. What is the freezing point of a solution made by mixing 56.5 grams of NaCl and 615.0
grams of water? (Kr of water is 1.86 °C/m)
The freezing point of a solution made by mixing 56.5 grams of NaCl and 615.0 grams of water -5.84 °C.
What is the freezing point depression of the solution?The freezing point depression that occurs in water when mixing 56.5 grams of NaCl and 615.0 grams of water is determined using the freezing point depression formula as given below:
ΔTf = Kf * m * i
where;
ΔTf is the freezing point depression
Kf is a constant
m is the molality of the solution
i = constant
For the given solution;
Kf = 1.86
i = 2 (NaCl produces two ions)
Molality = moles of solute/mass of solvent in kg
Mass of solvent = 615.0 g or 0.615 kg
Moles of NaCl = mass / molar mass
Molar mass of NaCl = 58.5
Mass of NaCl = 56.5
Moles of NaCl = 56.5/58.5
Moles of NaCl = 0.966 moles
Molality = 0.966/0.615
Molality = 1.57 molal
ΔTf = 1.86 * 1.57 * 2
ΔTf = 5.84
The freezing point of solution = 0 - 5.84
The freezing point of solution = -5.84 °C
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calculate the molecular weight (in amu) of monosodium glutamate.
Answer:
169.364 amu
Explanation:
Hey there!
To find the molecular weight, you have to first convert this into a chemical formula:
C5H8NO4Na
Now we have to find the mass for each of the elements and add them up to get our final answer
(12.06x5) + (1.008 x 8) + (14.01) + (16 x 4) + (22.99)
Adding all of it up we get:
169.364 amu
A tudent repeated weighed a lead block know to have a true ma of 13.00 g. The reult of the 4 trial are: 12.78 g, 12.82 g, 12.75g and 12.80 g. State the reult of 4 trial i precie, accurate or both or none. Explain.
The result of the four trials by the student is precise to the actual weight of the lead block.
Since we have been alive for millions of years, we have acquired a sense of measurement, which is necessary for us to comprehend the outside world. Tools that provide scientists a number are necessary for measurements. The issue here is that every measurement, using any measuring device, has some level of uncertainty in the outcome. Error is the name given to this uncertainty. When taking measurements, accuracy and precision are two crucial considerations. These two phrases describe how closely a measurement resembles a value that is understood or accepted.
Accuracy refers to an instrument's capacity to measure exact values. It is, in other words, the degree to which the measured value resembles a standard or real value. Accuracy is possible by obtaining quick readings.
The precision of a substance is defined as the similarity between two or more measurements.
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noble gases . a. make hydrogen bonds b. make ionic bonds c. make covalent bonds d. make polar bonds e. do not bond
Noble gases are very less reactive. The correct is noble gases e) do not bond.
The noble gases are the very less reactive. The valence shell or the outer most shell are fully filled and this is the reason it can not share the electrons or gain the electrons to form the bond. The noble gas are belongs to the group 18 in the periodic table. The noble gases are : helium, neon, argon, krypton, xenon and the radon. They are non reactive gases and called as inert.
Thus, The noble gases don not form the chemical bond and they are very stable.
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a tank at is filled with of sulfur hexafluoride gas and of dinitrogen difluoride gas. you can assume both gases behave as ideal gases under these conditions. calculate the mole fraction and partial pressure of each gas, and the total pressure in the tank. be sure your answers have the correct number of significant digits.
The mole fraction, the partial pressure of SF6, the mole fraction of N2F2, the partial pressure of SF6, the partial pressure of N2F2, and the total pressure in the tank are all 0.62, 1.18, and 0.72 atm, respectively.
We must first determine how many moles of each gas are present in the tank in order to calculate their mole fraction and partial pressure. You can use the equation 8.5 / (8.5 + 5.2) = 0.62 if the tank is filled with 8.5 moles of sulfur hexafluoride gas and 5.2 moles of dinitrogen difluoride gas.
Nitrous oxide mole fraction is calculated as follows: (moles of N2F2) / (moles of total both gases) = 5.2 / (8.5 + 5.2) = 0.38.
The ideal gas law, PV = nRT, can be used to determine the tank's overall pressure. The total pressure in the tank can be calculated using the volume of the tank and the number of moles of each gas, assuming a constant temperature.
The formula below to determine the temperature and tank volume if the temperature is 25 degrees Celsius and the tank has a volume of 12 liters.
(Total Pressure) = (8.314 J/mol × K)(298 K) / (12L) (Total Moles).
Approximately is the total tank pressure.
Nine atmospheres.
Then: when considering SF6 partial pressure.
1.18 atm is equal to (0.62) × 1.9 atm.
N2F2 has the following partial pressure:
0.38 and 1.9 atm equals 72 atm.
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an object movings at a velocity of 0.327 m/s (v) travels 45.6 m (d). determine the time (t) that the object was moving
The time that the object was moving is 139.6 seconds.
Calculating the time (t) that the object was moving:To determine the time (t) that the object was moving, you can use the formula:
t = d
v
where,
d = the distance the object travels
v = its velocity
d = 45.6 m
v = 0.327 m/s
Substituting the given values:
t = 45.6 m
0.327 m/s
t = 139.6 seconds
Hence, the time that the object was moving is 139.6 seconds.
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What is the water referred to as in a solution of a carbonated beverage?
(A) a precipitate
(B) a solvent
(C) a solute
(D) saturated
Answer: B: a solvent
Explanation: I hope this helps!
Chemistry Qurstion attached
The number of moles of the oxygen that have been produced is 51.9 moles.
What mass of the oxygen can be obtained?We know that we can be able to use the stoichiometry of the reaction to be able to obtain the reactants and the products of the reaction. In this case we have the decomposition of the aluminum oxide.
We know that;
Number of moles of the aluminum oxide = 34.6 moles
If 2 moles of the aluminum oxide produces 3 moles of oxygen
34.6 moles of the aluminum oxide would produce
34.6 * 3/2
= 51.9 moles
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Calculate the volume in mL of a 1.420 M NaOH solution required to titrate the following solutions:
(a) 25.00 mL of a 2.430 M HCI solution
(b) 25.00 mL of a 4.500 M H2SO4 solution
(c) 25.00 mL of a 1.500 M H3PO4 solution
Neutralizing each mole of [tex]$\mathrm{H}_3 \mathrm{PO}_4$[/tex] will therefore, take three moles of NaOH.
How do you calculate volume needed to titrate?Put the titration formula to use. The formula is molarity (M) of the acid x volume (V) of the acid = molarity (M) of the base x volume (V) of the base if the mole ratio between the titrant and analyte is 1:1. The number of moles of solute per litre of solution is how a solution's concentration, or molarity, is stated.
1M = 1 mol L
[tex]$34.55 \mathrm{~mL}=\frac{34.55}{1000}=0.03455 \mathrm{~L}$[/tex]
n = cV = 0.03455 × 1.500 = 0.05183 mol.
[tex]$\mathrm{H}_3 \mathrm{PO}_4$[/tex] exists inorganic. All three of its H atoms required to neutralized. It takes one [tex]$\mathrm{OH}^{-}$[/tex]to neutralize each H from [tex]$\mathrm{H}_3 \mathrm{PO}_4$[/tex]. Each formula unit of NaOH will provide one [tex]$\mathrm{OH}^{-}$[/tex]ion. Neutralizing each mole of [tex]$\mathrm{H}_3 \mathrm{PO}_4$[/tex] will therefore, take three moles of NaOH
[tex]$n(\mathrm{NaOH})=3 n\left(\mathrm{H}_3 \mathrm{PO}_4\right)=3 \times 0.05183=0.1555 \mathrm{~mol} \text {. }$$[/tex]
[tex]$V=\frac{n}{c}=\frac{0.1555}{1.420}=0.1095 \mathrm{~L}=0.1095 \times 10^3 \mathrm{~mL}=109.5 \mathrm{~mL} \text {. }$$[/tex]
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how does excessive burning of fossil fuels affect our planet
Excessive burning of fossil fuels such as coal, oil, and natural gas can have a significant impact on our planet. The primary way in which burning fossil fuels affects the planet is through the release of greenhouse gases, such as carbon dioxide (CO2) into the atmosphere.
These gases trap heat from the sun, which causes the Earth's temperature to rise, a phenomenon known as global warming. This can lead to a variety of negative effects, such as:
Climate change: The increase in temperature can cause more frequent and severe weather events such as heat waves, droughts, and floods. It can also cause sea levels to rise and glaciers to melt, leading to coastal flooding and changes in precipitation patterns.
Loss of biodiversity: Warmer temperatures can cause species to migrate or die out, leading to a loss of biodiversity. Changes in precipitation patterns can also affect the survival of certain species.
Ocean acidification: The ocean absorbs a large amount of CO2, which can cause the pH of seawater to decrease, making it more acidic. This can harm marine life, especially those that have shells or skeletons made of calcium carbonates, such as coral and certain types of plankton.
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for a reversible reaction in a 2.00 liter container at equilibrium, the following amounts were found in equilibrium at 400 degrees Celsius:0.0420 mole N2, 0.516 mole H2 and 0.0357 mole NH3. Calculate the equilibrium constant.
N2(g) + 3H2(g)--> 2NH3
( please disregard the arrow, the reaction is a reversible)
Answer:
The equilibrium constant for the reversible reaction N2(g) + 3H2(g) <---> 2NH3 at 400 degrees Celsius is given by K = [NH3]2/[N2][H2]3 = (0.0357)2/(0.0420)(0.516)3 = 0.000457.
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How many Br-ions are present in 1.00 moles of FeBr3?
a. 6.022 x 10^23
b. 12.04 x 10^23
c. 1.81 x 10^24
d. 6.02 x 10^25
1.81 x 10^24 Br-ions are present in 1.00 moles of FeBr3
Avogadro's number of representative particles is included in one mole of a substance.
6.02 x 1023 particles make up 1 mole.
How many of each sort of atom there are in a typical particle is indicated by the chemical formula of the molecule. One mole of iron(III) ions and three moles of bromide (Br-) ions make up the formula FeBr3, which states that. The quantity of Br- ions is thus:
1.81 × 1024 Br- ions from 3 x 6.0223
When thinking about atoms and molecules, a mole is a helpful unit of measurement. Compounds are created when modest whole-number ratios of atoms mix. Quantities are reported in moles for the purpose of employing mathematical relationships in computations since atoms of various elements have different masses. For instance, the proportion of iron(III) ions to bromide ions in FeBr3 is the same as the proportion of moles of iron(III) ions to moles of bromide ions, but not the proportion of masses of the two types of ions.
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what is the maximum mass of aluminum chloride that can be formed when reacting 32.0 g of aluminum with 37.0 g of chlorine?
The amount of AlCl3 that may be created from 22.0g of Al is shown by this equation.
22.0g Al multiplied by (1 mol Al/26.98g) by (2 mol AlCl3/2mol Al) by (133.34 g/1mol AlCl3) results in 108.66g AlCl3.
This equation illustrates the amount of AlCl3 that may be created from 27.0g of Cl2.
33.87g AlCl3 is obtained by multiplying 27.0g Cl2 by (1 mol Cl2/70.91g) x (2mol AlCl3/3 mol Cl2) x 133.34g.
This demonstrates that the limiting reactant is chlorine. The maximum amount of AlCl3 that can be created before the chlorine runs out is 33.87 grams.
The solution, using significant digits, is 33.8g of AlCl3.
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2. A glass container is filled with 150 molecules of
gas. If 200 more molecules are added to the
container, pressure inside will…
A. decrease
B. increase
C. remain the same
D. not enough information
CU
II
Answer:
B. increase
Explanation:
the pressure will increase because there is more molecules inside the container
s 6 hno3 --> h2so4 6 no2 2 h2o in the above equation how many moles of water can be made when 96.00 moles of hno3 are consumed?
The balanced equation states that for every 6 moles of HNO3 consumed, 2 moles of H2O are produced.
In this case, we are given that 96.00 moles of HNO3 are consumed in the reaction. To find the number of moles of H2O produced, we can use the stoichiometry of the balanced equation. We know that for every 6 moles of HNO3 consumed, 2 moles of H2O are produced. Therefore, we can use the proportion: 2 moles H2O/ 6 moles HNO3 = x moles H2O / 96.00 moles HNO3. Solving for x gives: x = (2 * 96.00) / 6 = 16 moles of H2O are produced when 96.00 moles of HNO3 are consumed. It's important to note that the balanced equation provides the stoichiometry of the reaction which helps us to calculate the number of moles of product produced from the given number of moles of reactant. The balanced equation also tells us that the reaction is stoichiometrically balanced and the number of moles of reactant and product are in a defined ratio.
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Subscript of H2 is blank indicating that H2 contains two hydrogen atoms
Subscript of [tex]H_2[/tex] is number indicating that [tex]H_2[/tex] contains two hydrogen atoms.
What is subscript?A subscript is a character that is printed slightly below and to the side of another character, commonly a letter or a number.
Chemists frequently employ subscripts in their formulations. When writing the chemical formula for water, H2O, a scientist would place the number 2 lower and smaller than the letters to either side of it.
To display the number of electrons in a specific sublevel, use superscripts.
Thus, the subscript of hydrogen represents the number of atoms.
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Consider the reaction:
2NO(g) + O2(g) + 2NO2(g)
Given an initial mass of 16. 07 g NO, an excess of Oz, and assuming that all of the reactant is converted to product(s), and none is lost, calculate the mass (g) of NO2 produced
by the reaction.
The mass of NO2 produced by the reaction is 24.61g when the initial mass of 16.07g NO, an excess of O2 is converted to product NO2.
Given the chemical reaction: 2NO(g) + O2(g) + 2NO2(g)
The equation is balanced.
The initial mass of NO is (m) = 16.07g
Here first we calculate the number of moles of NO is used = mass/Molar mass of NO
moles of NO used = 16.07/30 = 0.535
An excess of O2 is used so we can neglect that.
Now calculate the moles of NO2 produced.
moles of NO2 = 0.535 x 2 mol(NO2) / 2mol(NO) = 0.535
we can determine that NO is the limiting reactant.
To convert from moles to mass, use the product's molar masses.
Molar mass of NO2 = 46g/mole
Then the mass of NO2 produced = 0.535 x 46 x 1 = 24.61g
Hence the mass of NO2 produced by the reaction is 24.61g
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how many years would it take for three quarters of the original amount of carbon 12 in the sample to become stable
The half-life of carbon-12, the most common isotope of carbon, is approximately 5,730 years.
This means that after 5,730 years, half of the original amount of carbon-12 in a sample will have decayed into a stable isotope (nitrogen-14). Therefore, it would take approximately 11,460 years for three quarters of the original amount of carbon-12 in a sample to become stable. Importantly, carbon-12 is not radioactive and hence does not decay into a stable isotope, but it is used in carbon dating because it is a stable isotope of carbon. Dating depends on the decay of other isotopes, such as carbon-14 or radiocarbon.
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Write electron configurations for… a. sodium b. iodine c. iron
Answer: a. The electron configuration for sodium (atomic number 11) is:
1s² 2s² 2p⁶ 3s¹
b. The electron configuration for iodine (atomic number 53) is:
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹0 4p⁶ 5s² 4d¹0 5p⁵
c. The electron configuration for iron (atomic number 26) is:
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁶
based on the following information, which compound has the strongest intermolecular forces? substance dhvap (kj/mol) argon (ar) 6.3 benzene (c6h6) 31.0 ethanol (c2h5oh) 39.3 water (h2o) 40.8 methane (ch4) 9.2 a. water b. ethanol c. methane d. benzene e. argon
Based on the given information, B: Ethanol is the compound that has the strongest intermolecular forces.
Intermolecular forces (IMF) are the forces that hold molecules of a substance together. The strength of IMF is directly related to the boiling point of a substance. So, the stronger the IMF, the higher the boiling point will be.
The information provides the heat of vaporization (DHvap) for each substance, which is the energy required to convert a liquid into a gas. The higher the DHvap value, the stronger the IMF because more energy is required to overcome the forces that hold the molecules together.
When comparing the DHvap values, we can see that Ethanol (C2H5OH) has the highest DHvap value of 39.3 kJ/mol, followed by water (H2O) with 40.8 kJ/mol. This means that ethanol has stronger intermolecular forces than water, that's why ethanol has a higher boiling point than water.
Therefore, based on the DHvap values, Ethanol has the strongest intermolecular forces.
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based on the stoichiometry of the reaction, how many grams of benzophenone is an equimolar amount to the bromobenzene used in the experiment?
The bromobenzene used in the experiment was equimolar to 3.7 grams of benzophenone. The correct answer is C.
The stoichiometry of a chemical reaction tells us the relative amounts of reactants and products involved in the reaction. In this case, the reaction is between bromobenzene and benzophenone to form a new compound.
The balanced equation for this reaction is:
C6H5Br + C6H5COC6H5 → C6H5COC6H5 + C6H5Br.From the equation, we can see that one mole of bromobenzene reacts with one mole of benzophenone. Therefore, an equimolar amount of benzophenone is the same as the amount of bromobenzene used in the experiment. Since the molar mass of benzophenone is 182.23 g/mol, we can use this value to calculate the mass in grams by multiplying it with the number of moles.
To calculate the equimolar amount of benzophenone, we use the following formula:
mass of benzophenone = (mass of bromobenzene / molar mass of bromobenzene) x molar mass of benzophenoneLet's assume that the mass of bromobenzene used in the experiment is x. Hence:
mass of benzophenone = (x / 157.02 g/mol) x 182.23 g/molmass of benzophenone = x x 182.23/157.02 g/molTherefore, the equimolar amount of benzophenone is 3.7 grams.
This question should be provided with answer choices, which are:
A 2.2 B. 2.8 C. 3.7 D. 1.4The correct answer is C.
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flask a contains molecules of elemental oxygen and molecules of elemental hydrogen, while flask b contains only molecules that are made of both oxygen and hydrogen. how would the contents of these flasks be defined?
Flask a contains molecules of oxygen and hydrogen which are gases while flask b contains molecules made up of both oxygen and hydrogen I.e water.
Oxygen in the atmosphere is a molecule because it contains molecular bonds. It is not a compound because it is made from atoms of only one element - oxygen. This type of molecule is called a diatomic molecule, a molecule made from two atoms of the same type.same as oxygen, hydrogen molecules are also formed of two hydrogen atoms hence, it is also a molecule.But as flask b contains compound made up of both hydrogen and oxygen and the compound is water .go through the given link below to know more about molecules:-
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what is the de broglie wavelength of an oxygen molecule at room temperature? compare this to the average distance between oxygen molecules in a gas at 1
The de Broglie wavelength of a particle is given by the equation:
λ = h / p.
Where λ is the de Broglie wavelength, h is Planck's constant (6.62607015 x 10^-34 Js) and p is the momentum of the particle.. The de Broglie wavelength of an oxygen molecule at room temperature is on the order of 4.8 x 10^-10 m. This wavelength is much smaller than the average distance between oxygen molecules in a gas at 1 atm, which is about 2 x 10^-10 m. This means that the de Broglie wavelength of an oxygen molecule is much smaller than the distance between the oxygen molecules and it is not possible to see the interference or diffraction patterns of individual molecules in most cases.
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Please help Quick ASAP Hurry Chemistry
To drill or not to drill? That is the big question as Americans face climbing gas prices. A group of research scientists employed by Mobil Oil conducted a study on the feasibility of drilling for oil off the coast of California. They researched the impact of oil drilling on near-by ecosystems and investigated the likelihood of future oil spills. According to their data, coastal California would be an excellent location to drill for oil. Based on historical data, there is a very small chance of future oil spills.
According to this passage, research scientists concluded coastal California would be an excellent location to drill for oil. This conclusion is most likely based on
A. the declining populations in coastal areas.
B. possible job creations due to the new project.
C. the climbing gas price along with the need of gas supply.
D. historical data revealing little or no chance of an oil spill.
This conclusion that coastal California would be an excellent location to drill for oil is most likely based on:
D. Historical data revealing little or no chance of an oil spill.
How was the conclusion reached?The conclusion that coastal California will be ideal for oil drilling is based on the historical data that was examined by the analysts. This is a very good way of making environmental and business decisions.
If past data shows that a given trend or pattern is evident, then, intentional businesses should be able to base their findings on these.
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in this experiment, the pressure of the gas was 1.000 atm and the temperature was 294.6 k. what value do you get for the gas constant using the data you recorded for propane?
To calculate the gas constant using the data provided, you would use the ideal gas law equation: PV = nRT.
Assuming that the amount of propane (n) is given in moles and the volume (V) is given in liters, the ideal gas law equation can be rearranged to solve for R:
R = PV/nT
Given that the pressure (P) is 1.00 atm and the temperature (T) is 294.6 K, you can plug in these values and solve for R:
R = (1.00 atm) * (V) / (n) * (294.6 K)
Without knowing the exact values for V and n, it is not possible to determine the exact value for R. However, it is important to note that the units of R are L atm mol-1 K-1, and option A is the only choice that has the correct units, so the answer is A. 1.858 L atm mol-1 K-1.
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8.00 g of NaOH is dissolved in 5.00 L of water. Calculate the pH of the solution:
The pH of the solution prepared by dissolving 8.00 g of NaOH in 5.00 L of water is 12.598.
It is evident that from the given information, 8.00 g of NaOH (which is a strong base) has been dissolved in 5.00 L of water. So to calculate the pH of a solution we can use the formula:
m = n / M. Given :
n = 8.00 g / 40.00 g/mol = 0.200 mol
M = 40.00 g/mol
m = 0.200 mol / 5.00 L = 0.04 mol/L
By knowing the concentration of hydroxide ions, we can use the relationship:
[OH-] = 10^(-14) / [H+]
pH = -log[H+]
The product of [H+] and [OH-] is always equal to 10^(-14) at 25 degree Celsius. Hence,
[H+] * [OH-] = 10^(-14)
[OH-] = 10^(-14) / [H+]
Substituting the value of [OH-] in the above equation.
pH = - log(10^(-14) / 0.04 ) =
pH = - log(2.5*10^(-13)) =
Therefore, the pH of the solution is 12.598.
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The total number of sodium atoms in 46.0 grams of sodium is
Given,
Amount of sodium atoms = 46 grams
To find,
The total number of sodium atoms present in the given amount of sodium atoms.
We can simply solve this numerical problem by using the following process:
As per stoichiometry;
1 mole of any element contains Avogadro's number of atoms, that is, 6.022 x 10^23 atoms.
And, the molar mass of any element is equal to the atomic mass of the same element.
=> If the given amount of an element/compound is equal to its molar mass, then it contains 6.022 x 10^23 atoms/molecules.
=> Total number of atoms/molecules present in the given amount of the element/compound
= (total given mass)/(molar mass) x 6.022 x 10^23
Now,
the molar mass of sodium = 23 grams
Total number of sodium atoms present in the given amount of sodium atoms
= (total mass)/(molar mass) x 6.022 x 10^23
= 46 grams / 23 grams x 6.022 x 10^23
= 2 moles x 6.022 x 10^23
= 12.044 x 10^23 = 1.2044 x 10^24 atoms
Hence, 1.2044 x 10^24 sodium atoms are present in the given amount of sodium atoms.