Chemistry Middle School

1.46 g H2 is allowed to react with 10.5 g N2, producing 2.72 g NH3. What is the theoretical yield in grams for this reaction under the given conditions?
Express your answer to three significant figures and include the appropriate units.

Answers

Answer 1

Answer : The theoretical yield in grams for this reaction under the given conditions is, 8.28 grams.

Explanation : Given,

Mass of [tex]H_2[/tex] = 1.46 g

Mass of [tex]N_2[/tex] = 10.5 g

Molar mass of [tex]H_2[/tex] = 2 g/mol

Molar mass of [tex]N_2[/tex] = 28 g/mol

First we have to calculate the moles of [tex]H_2[/tex] and [tex]N_2[/tex].

[tex]\text{Moles of }H_2=\frac{\text{Given mass }H_2}{\text{Molar mass }H_2}[/tex]

[tex]\text{Moles of }H_2=\frac{1.46g}{2g/mol}=0.73mol[/tex]

and,

[tex]\text{Moles of }N_2=\frac{\text{Given mass }N_2}{\text{Molar mass }N_2}[/tex]

[tex]\text{Moles of }N_2=\frac{10.5g}{28g/mol}=0.375mol[/tex]

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

[tex]3H_2+N_2\rightarrow 2NH_3[/tex]

From the balanced reaction we conclude that

As, 3 mole of [tex]H_2[/tex] react with 1 mole of [tex]N_2[/tex]

So, 0.73 moles of [tex]H_2[/tex] react with [tex]\frac{0.73}{3}=0.243[/tex] moles of [tex]N_2[/tex]

From this we conclude that, [tex]N_2[/tex] is an excess reagent because the given moles are greater than the required moles and [tex]H_2[/tex] is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of [tex]NH_3[/tex]

From the reaction, we conclude that

As, 3 mole of [tex]H_2[/tex] react to give 2 mole of [tex]NH_3[/tex]

So, 0.73 mole of [tex]H_2[/tex] react to give [tex]\frac{2}{3}\times 0.73=0.487[/tex] mole of [tex]NH_3[/tex]

Now we have to calculate the mass of [tex]NH_3[/tex]

[tex]\text{ Mass of }NH_3=\text{ Moles of }NH_3\times \text{ Molar mass of }NH_3[/tex]

Molar mass of [tex]NH_3[/tex] = 17 g/mole

[tex]\text{ Mass of }NH_3=(0.487moles)\times (17g/mole)=8.28g[/tex]

Therefore, the theoretical yield in grams for this reaction under the given conditions is, 8.28 grams.

Related Questions

How does water's dissolving power support life on Earth?

Answers

The dissolving power of water is very important for life on Earth. Wherever water goes, it carries dissolved chemicals, minerals, and nutrients that are used to support living things. Because of their polarity, water molecules are strongly attracted to one another, which gives water a high surface tension

all but one is a method of passve transport in cells

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sodium/potassium pump
facilitated transport​

Answers

Answer:

The answer is Osmosis........

Answer:

osmosis

Explanation:

osmosis is a method of passive transport in cells. osmosis in passive transport cells is of water

The reaction, C2H6) (l) + 3)2 (g) produces 2CO2 (g) + 3H2) (g), is the combustion of ethanol. What occurs as the reaction proceeds.

Answers

Answer:

So as the reaction proceeds we lose energy as the reaction is exothermic due to the delta H being negative, this shows that heat flows from the system to its surroundings.

Explanation:

2H6O (l) + 3O2 (g) = 2CO2 (g) + 3H2O (g)

2CH3CH2OH(l) + 3O2(g) = 2CO2(g) + 3H2O(g) ΔH = -1234.8kJ/mol

I'm pretty sure this is what your equation is supposed to be, seems to be an error where you've pasted it and it's replaced the O's with )

So as the reaction proceeds we lose energy as the reaction is exothermic due to the delta H being negative, this shows that heat flows from the system to its surroundings.

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