19. The passing marks in an examination is 40%. If Seema gets 130 marks, she fails by ups 2 marks. Find the total marks.​

Answers

Answer 1

Given :-

Passing marks in an exam is 40% .Seema gets 130 marks and fails by 2 marks.

To find :-

The maximum marks for the exam .

Solution :-

According to the Question ,

[tex]\dashrightarrow[/tex] Passing marks = 40% .

[tex]\dashrightarrow[/tex] Seema's marks = 130 .

Let us take the maximum marks be x . Then ,

[tex]\dashrightarrow[/tex] Passing marks = 130 + 2

[tex]\dashrightarrow[/tex] Passing marks = 132

And , by question ,

[tex]\dashrightarrow[/tex] 40x/100 = 132

[tex]\dashrightarrow[/tex] x = 132 * 100/40

[tex]\dashrightarrow[/tex] x = 330

Hence the maximum marks for the exam is 330.

Answer 2

Given :

Passing marks in the examination = 40% .

Marks obtained by Seema = 130 .

So, Let us assume the maximum marks as x .

Also,

Passing marks = 132 [ ∵ Seema got 130 marks and she failed by 2 marks ]

According to the question :

[tex] \\ \tt : \implies\dfrac{40x}{100} = 132 \\ \\ \tt : \implies\dfrac{4 \cancel{0}x}{10 \cancel{0}} = 132 \\ \\ \: \: \: \tt \: : \implies 4x = 132 \times 10 \\ \\ \tt : \implies \: 4x = 1320 \\ \\ \tt : \implies \: x = \frac{1320}{4} \\ \\ \tt : \implies \: x = 330 \: \: \\ [/tex]

Hence, The total marks is 330 .


Related Questions

Need help NOW on HS geometry

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It would be A) 13 because 7 (13) - 1 = 90 and that angle is 90 degrees

Help please!!!!!!!!!!!!!

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Answer:

Hm? Is there meant to be a file, if so I can’t see it. :((

Step-by-step explanation:

Please help me with this question.

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they are equivalent. combine like terms on the first one and 9x-4x+25 can be simplified to 5x+25.

Find the value of √1600×8²+√4225​

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Step-by-step explanation:

√1600×8²+√4225

40 x 64 + 65

= 2625

Ok done. Thank to me :>

Please solve this question

Answers

Answer:

46?

Step-by-step explanation:

23*2=46

Answer:

37.31 cm

Step-by-step explanation:

∡ AB = 180 - 148 = 32° = ∡ DE

∡ CD = 360 - ∡ AE - ∡ AB - ∡ BC - ∡ DE = 360 - 148 - 32 - 87 - 32 =61°

∡ CE = 61 + 32 = 93°

arc length = 2[tex]\pi[/tex]r [tex]\frac{angle}{360}[/tex] = 2×3.14×23×[tex]\frac{93}{360}\\[/tex] = 37.31 cm

Which quantity of fruit contains an amount of vitamin C closest to the combined


amount of vitamin C in 50 g grams of acerola cherries and 150 g grams of


kiwifruit?


A. 2,000 g grams of black currants


B. 800 g grams of guava


C. 1,800 g grams of pineapple


D. 600 g grams of strawberries

Answers

Answer:

c would be the closest due to the total amount of vitamin c in the objects.

The quantity of fruit which contains an amount of vitamin C closest to the combined content is: C. 1,800 g grams of pineapple.

How to calculate the amount of vitamin.

In this exercise, we would determine the amount of vitamin C that is present in a combination of 50 grams of acerola cherries and 150 grams of kiwifruit.

For acerola cherries:

100 grams of acerola cherries = 1678 mg.

50 grams of acerola cherries = X mg.

Cross-mutiplying, we have:

X = 83,900/100 = 839 mg.

For kiwifruit:

100 grams of kiwifruit = 105 mg.

150 grams of kiwifruit = Y mg.

Cross-mutiplying, we have:

Y = 15,750/100 = 157.5 mg.

Combine vitamins = 157.5 + 839 = 996.5 mg.

Based on intuition, we would choose 1,800 grams of pineapple.

100 grams of pineapple = 56 mg

1,800 grams of pineapple = Z mg.

Cross-mutiplying, we have:

Z = 100,800/100 = 1008 mg.

Thus, 996.5 mg of vitamin C is closest to 1008 mg.

Note: If you do the above computations for other quantities of fruit, you'll get a value far from 996.5 mg.

Read more on vitamins here: https://brainly.com/question/9348916

A grocery store sells steak for $6.10 per pound. What would be the cost of 2 3/5 lb. of steak?

Answers

Answer:

$15.86

Step-by-step explanation:

Make 2 3/5 improper fraction (5 times 2 and add 3 equals 13)

13/5 times 6.1 ( or 6 1/10 or 61/10)

equals 793/50

divide

answer is 15.86

Which set of numbers are ordered from least to greatest?
O A. 7,1-41, -7,0,-131, 3
B. -31, -7,0,3,7, 1-4]
C. -7,-131,0,3, 4,7
D. 7.1-41,3,0.-131, -7

Answers

The answer is B. -31, -7, 0 , 3, 7, 1, 4

The population of a pigeons in a city is 100 and is growing exponentially at 20% per year. Write a function to represent the population of pigeons after
t
t years, where the monthly rate of change can be found from a constant in the function. Round all coefficients in the function to four decimal places. Also, determine the percentage rate of change per month, to the nearest hundredth of a percent

Answers

Answer:

p(t) = 100×1.0153^(12t)1.53% per month

Step-by-step explanation:

In general, the function will be written ...

  p(t) = (initial value)×(growth factor)^t

where t is in units comparable to those applicable to the growth factor. The growth factor is found from ...

  growth factor = 1 + growth rate

Here, the growth rate is given as 20% per year, so the growth factor per year is ...

  1 +20% = 1.20

The initial value is given as 100, so we can write the exponential function as ...

  p(t) = 100×1.20^t

__

The time period units for t are supposed to be years, but we want to find the growth rate for a month. We can do that by recognizing there are 12 months in a year. In the above equation, we can use (1/12)(12t) in place of t, then figure the growth factor (and growth rate) per month.

  p(t) = 100×(1.20^(1/12))^( 12t)

  p(t) = 100×1.0153^(12t) . . . . population exponential function

This shows the monthly growth factor is 1.0153, so the monthly rate of change (growth rate) is ...

  1.0153 -1 = 0.0153 = 1.53% . . . . monthly rate of change

Answers:

Function is [tex]P(t) = 100(1.0153)^{12t}\\\\[/tex]Monthly growth rate is roughly 1.53%

=====================================================

Explanation:

The population starts at 100 pigeons. After a year, the population goes up by 20%, meaning the population goes up by 20. It lands on 120 after a full year (100+20 = 120).

Dividing the "before" and "after" population amounts gets us 120/100 = 1.20

If we didn't worry about the monthly rate, and only cared about the annual rate of growth, then the population function would be

[tex]P(t) = 100(1.20)^t[/tex]

where t is the number of years and P(t) is the population for that year number. Notice how the 1.20 is the base of the exponential to quickly tell the reader the annual rate of growth. We read off the .20 portion and that converts to 20% after moving the decimal 2 spots to the right.

If we were to plug t = 0 into that function, then we'd get P(0) = 100. Inputting t = 1 leads to P(1) = 120. This helps confirm we have the correct annual growth rate function.

---------------------

Unfortunately, your teacher doesn't want the annual growth rate function. Instead, they want you to write a function where the reader can easily pick out the monthly rate of change without having to do any math. This is due to the instructions that "the monthly rate of change can be found from a constant in the function". Let m be this constant.

Since t is the number of years, this means t = 1/12 represents 1/12 of a year, aka 1 month. If you were to compute P(1/12), then you should get roughly 101.530947049973

Divide this amount over the initial population to find m.

m = 101.530947049973/100 = 1.01530947049973

So we get m = 1.0153 after rounding to four decimal places.

The number m is in the form 1+x. Solving 1+x = m will lead to x = 0.0153 to indicate a monthly rate of change is roughly 1.53% since we move the decimal point 2 spots to the right to go from 0.0153 to 1.53%

The pigeon population is increasing by roughly 1.53% each month.

This is why computing this m value leads to the reader able to spot the monthly rate of change without having to resort to a calculator. All they have to do is read the digits to the right of the decimal point and convert that to percentage form.

---------------------

An alternative way to compute this value is to use this formula

m = (1+r)^(1/12)

We'll plug in the annual rate r = 0.20 to get:

m = (1+r)^(1/12)

m = (1+0.20)^(1/12)

m = 1.01530947049973

m = 1.0153

We get the same approximate value as earlier.

---------------------

Whichever method you use, you should get roughly m = 1.0153

We're given that A = 100 is the initial population

So we'll then be able to form this function

[tex]P(t) = A*(m)^{12t}\\\\P(t) = 100(1.0153)^{12t}\\\\[/tex]

This represents the monthly growth of the population where t is in years. Note that after something like t = 3 years, we have 12t = 12*3 = 36 months pass by. So that's why the 12t is in the exponent rather than simply t.

Once again, for comparison we have...

[tex]P(t) = 100(1.20)^{t}\\\\[/tex] for annual growth[tex]P(t) = 100(1.0153)^{12t}\\\\[/tex] for monthly growth

Each function has t represent the number of years. The difference is the base of each exponential to tell us the respective annual or monthly growth rate. Also, the exponent up top must be adjusted depending on which you go for.

---------------------

You may be wondering: "what if the exponent in the monthly growth rate function wasn't 12t?". Let's find out. We'll assume the monthly growth rate function is [tex]P(t) = 100(1.0153)^{t}\\\\[/tex] and show that an error happens.

If we plugged in something like t = 1, we should get P(t) = 120 like mentioned earlier.

[tex]P(t) = 100(1.0153)^{t}\\\\P(1) = 100(1.0153)^{1}\\\\P(1) = 100(1.0153)\\\\P(1) = 101.53\\\\[/tex]

That value of 101.53 is the approximate population number after 1 month, rather than 1 year. Making the exponent 12t will fix the issue.

Some information about a direct variation is given in the table below. If the equation
of this direct variation is y = kx , find the coefficient k and fill in the missing
information.

Answers

Answer:

Step-by-step explanation:

y = kx ;

k = [tex]\frac{y}{x}[/tex] ; x = [tex]\frac{y}{k}[/tex]

~~~~~~~~~~~~~

k = [tex]\frac{1}{2}[/tex] ÷ 1 = [tex]\frac{1}{2}[/tex]

[tex]y_{1}[/tex] = [tex]\frac{1}{2}[/tex] × ( - 8 ) = - 4

[tex]y_{2}[/tex] = [tex]\frac{1}{2}[/tex] × ( - 4 ) = - 2

[tex]y_{3}[/tex] = [tex]\frac{1}{2}[/tex] × 2 = 1

[tex]x_{5}[/tex] = [tex]\frac{1}{3}[/tex] ÷ [tex]\frac{1}{2}[/tex] = [tex]\frac{2}{3}[/tex]

[tex]x_{6}[/tex] = - [tex]\frac{1}{4}[/tex] ÷ [tex]\frac{1}{2}[/tex] = - [tex]\frac{1}{2}[/tex]

[tex]x_{7}[/tex] = 0

( x , y ) : ( - 8 , - 4 ), ( - 4 , - 2 ), ( 2 , 1 ), ( 1 , [tex]\frac{1}{2}[/tex] ), ( [tex]\frac{2}{3}[/tex] , [tex]\frac{1}{3}[/tex] ), ( - [tex]\frac{1}{2}[/tex] , - [tex]\frac{1}{4}[/tex] ), ( 0 , 0 )

is (1, 3) a solution to the system of equations


8x + y = 11


12x + 2y = 18

Answers

Answer:

(1, 3) a solution to the system of equations

8x + y = 11

12x + 2y = 18

Step-by-step explanation:

ay están todos los deberes de la semana pasada gunnorni

Answer:

x=1 and y=3

Step-by-step explanation:

yes x=1 and y=3 is the solution for the equation.just by making y in the first equation subject of the formula and replacing in the second equation.

Give the number and type of solutions of the equation.

Answers

Answer:

B. 2 non-real solutions

Step-by-step explanation:

Compare the left and right side of the given equation in terms of the lines they represent:

x² is a parabola with non-negative value- 3x - 7 is a line with negative slope and negative y-intercept

Their intersection seems not possible. Lets graph and confirm.

See attached below.

It means there are no real solutions. Correct answer choice is B

3c+2=20
c
ok anwer this

Answers

Answer:

3c =20-2

3c = 18

c = 18÷3

=6

Answer:

Here is Your answer

Step-by-step explanation:

Hope u Like it

C = 2/17

Plz Mark me As Brainiest

Can someone help me? ​

Answers

Answer:

I figure you could simplify it by multiplying both sides by 6, resulting in -31+23=-30+18-1+5

-8=-8

Step-by-step explanation:

A mosquito flies at a speed of 40.2 meters per minute.

At this rate, how many meters can it fly in 5 minutes?

PLZ HELP

Answers

Answer:

201

Step-by-step explanation:

40.2*5=201

201 meters per minute

Can someone help me with this plis

Answers

Answer:

it is c

Step-by-step explanation:

Help please, 9th grade math.

Answers

Answer:

table k

Step-by-step explanation:

4:3 ratio

Sorry I did this in 6th grade, I’ll help tho!

READ THIS, it helps!

24 and 18 (divide each by 3 and you get your 8 and 6)

48 and 36 ( divide both by 6 and you get 8 and 6)

64 and 48 ( you divide 64 by 8 and get 8 and divide 48 by 6 and you get 8)

Answer: Table K
Hope this helps!!

How i can answer this question

Answers

60m

How?

5m × 3m × 4m

5m × 3m = 15m

15m × 4m = 60m

Therefore

the answer is 60

-X + 2y= -3 and -8x — 3y= -5

Answers

Answer:

x=1, y=-1. (1, -1).

Step-by-step explanation:

-x+2y=-3

-8x-3y=-5

----------------

-8(-x+2y)=-8(-3)

-8x-3y=-5

------------------------

8x-16y=24

-8x-3y=-5

-----------------

-19y=19

y=19/-19

y=-1

-x+2(-1)=-3

-x-2=-3

-x=-3+2

-x=-1

x=1

(1, -1)

Answer:

x = 1, y = -1

or as an ordered pair, (1, -1).

Step-by-step explanation:

  -x  + 2y = -3

-8x — 3y = -5

Multiply first equation by -8:

8x - 16y = 24

Add this equation to the second equation:

-19y = 19

y = -1.

Plug y = -1 into the second equation:

-8x - 3(-1) = -5

-8x + 3 = -5

-8x = -8

x = 1.

a statue of abraham lincoln casts a 9-foot shadow at the same time the white house casts 48-foot shadow . if the white house is 70 feet tall , how tall is the statue of abraham lincoln

Answers

Step-by-step explanation:

let's ignore the question, if the statue can cast an isolated shadow based on its location ...

2 objects and their shadows create 2 similar right-angled triangles.

that means all angles are the same, and the side lengths of one triangle correlate to the corresponding side lengths of the other triangle via the same factor.

so,

48 × f = 9

f = 9/48 = 3/16

therefore, the height of the statue is

70 × f = 70 × 3/16 = 210/16 = 13.125 ft

Write 15.5 as a fraction in the simplest form and as a decimal

Answers

Fraction; 13/200
Decimal: 0.155

what is the domain of the function

Answers

Answer:

  (a)  -∞ < x < ∞

Step-by-step explanation:

Unlike the square root function, the cube root function is defined for all values of its argument. Here, x can take on any value and the function will be defined for that value.

  -∞ < x < ∞

i need help with this question (3x56-7+76)/99=

Answers

Answer:

x^56+23/33

Step-by-step explanation:

The has the power of 56

Can you please help me

Answers

Answer:  Attached.

Step-by-step explanation:

Either solve the equations directly, or graph them and look for the point of intersection.  

How I can apply the distribute property to this question?

Answers

Answer:

6(4c+6d+3)

Step-by-step explanation:

First, find the greatest common factor, which is 6, in this case.

24/6=4

36/6=6

18/6=3

6(4c+6d+3)

-hope it helps

Overnight the low temperature dropped to-6 degrees Fahrenheit. If the temperature during the was 11 degrees Fahrenheit, what was the difference between the high and low temperatures?

Answers

Answer:

17 degrees F

Step-by-step explanation:

11 - (-6) = 17

Subtracting a negative is the same as adding.

For 18-20, factor each of the following and show work.

18. 5x^4 - 25x

19. 4x^2 - 9

20. x^2+8x+12

Answers

Step-by-step explanation:

20. x^2+8x+12

x^2 + 6x +2x + 12

X(X+6) + 2(X+6)

(X+2) (X+6)

18. 5x^4 - 25x

5x(x^3-5)

19. 4x^2 - 9

4x^2/4 -9/4 = 0/4

x^2 = 9/4

X=√9/4

Find the 62nd term of the arithmetic sequence
15, 13, 11, ...

Answers

Answer:

[tex]a_{62}=-107[/tex]

Step-by-step explanation:

This is an arithmetic sequence:

[tex]a_n=a_1+(n-1)d[/tex]

where d is the common difference and n is the index of any given term.

The common difference of the given sequence is -2:

[tex]13-15=-2\\11-13=-2[/tex]

Using the first term and the common difference, you can write the equation for this sequence:

[tex]a_n=15+(n-1)(-2)[/tex]

And using that equation, you can find the 62nd term:

[tex]a_{62}=15+(62-1)(-2)\\a_{62}=15+(61)(-2)\\a_{62}=15-122\\a_{62}=-107[/tex]

The weight of an object on moon is 1/6 of its weight on Earth. If weight of an object on Earth is 18/5 kg, what would be its weight on moon? ​Please help me!!!!​

Answers

Answer:

3/5 kg

Step-by-step explanation:

The weight of an object on Moon is 6 times smaller than same on Earth.

If it weights 18/5 kg on Earth then its weight  on Moon is:

18/5 * 1/6 = 3/5 kg

Answer:

Solution given:

weight of moon=1/6 th of Earth

If weight of Earth is 18/5 kg

weight of moon=?

we have

weight of moon: 1/6 of weight of Earth

=1/6*18/5

=3/5kg

Its weight on moon is 3/5 kg

write the tangent of ∠T as a fraction

Answers

Answer:

[tex]\tan \angle T = \dfrac{SR}{TS} = \dfrac 43[/tex]

Step-by-step explanation:

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