2. Find the approximate volume of the cone. Use alt+227 or pi for pi as needed.

SHOW YOUR WORK

2. Find The Approximate Volume Of The Cone. Use Alt+227 Or Pi For Pi As Needed.SHOW YOUR WORK

Answers

Answer 1

Answer:

[tex] v = \frac{1}{3} h\pi \: r { }^{2} \\ = \frac{1}{3} \times 3 \times \pi \times2 ^{2} \\ \frac{1}{3 } \times 3 \times \pi \times 4 \\ \frac{1}{3} \times 12\pi \\ 4\pi \: cm {}^{3} is \: the \: answer[/tex]

the answer is 4 pie cm cube

may I get branliest


Related Questions

The following are distances (in miles) traveled to the workplace by 6 employees of a certain computer company. 11, 6, 36, 16, 5, 40 Send data to calculator Find the standard deviation of this sample o

Answers

The sample standard deviation is approximately 15.29 miles.

Using the formula for sample standard deviation:

Find the mean of the data:

mean = (11 + 6 + 36 + 16 + 5 + 40) / 6 = 114 / 6 = 19

Subtract the mean from each data point, square the result, and sum the squares:

[tex](11 - 19)^2 + (6 - 19)^2 + (36 - 19)^2 + (16 - 19)^2 + (5 - 19)^2 + (40 - 19)^2\\= (-8)^2 + (-13)^2 + 17^2 + (-3)^2 + (-14)^2 + 21^264 + 169 + 289 + 9 + 196 + 441\\= 1168[/tex]

Divide the sum of squares by (n-1), where n is the sample size:

[tex]s^2 = 1168 / (6-1) = 233.6[/tex]

Take the square root of [tex]s^2[/tex] to find the sample standard deviation:

s = sqrt(233.6) ≈ 15.29

Therefore, the sample standard deviation is approximately 15.29 miles.

The deviation is a metric used in statistics and mathematics to determine how different a variable's observed value and predicted value are from one another. The deviation is the distance from the centre point, to put it simply.

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1. Prove that each function is uniformly continuous on the given set by directly verifying the E - 8 property in Definition 5.4.1. (a) f(x) = x^3 on (0,2] (b) f(x)= 1/2 on (2,[infinity] ) (c) f(x) = x-1 /x+1 on (0,[infinity] ) 4.1 DEFINITION Let f:D R. We say that f is uniformly continuous on Dif for every e > 0 there exists a 8 >0 such that Sx)-f()

Answers

a. At (0,2] f is uniformly continuous.

b. At (2,∞) f is uniformly continuous.

c. At (0,∞) f is uniformly continuous.

What is function?

A function connects an input with an output. It is analogous to a machine with an input and an output. And the output is somehow related to the input. The standard manner of writing a function is f(x) "f(x) =... "

(a) Let f(x) = x³ on (0,2]. Let ε > 0 be given. We need to find a δ > 0 such that |x - y| < δ implies |f(x) - f(y)| < ε for all x,y in (0,2]. Note that |f(x) - f(y)| = |x³ - y³| = |x - y||x² + xy + y²|. Since x,y ∈ (0,2], we have x² + xy + y² ≤ 12. Thus, if we choose δ = ε/12, then for any x,y ∈ (0,2] such that |x - y| < δ, we have |f(x) - f(y)| < ε. Hence, f is uniformly continuous on (0,2].

(b) Let f(x) = 1/2 on (2,∞). Let ε > 0 be given. We can choose any δ > 0 since for any x,y ∈ (2,∞), we have |f(x) - f(y)| = 0 < ε. Thus, f is uniformly continuous on (2,∞).

(c) Let f(x) = (x-1)/(x+1) on (0,∞). Let ε > 0 be given. We need to find a δ > 0 such that |x - y| < δ implies |f(x) - f(y)| < ε for all x,y in (0,∞). Note that |f(x) - f(y)| = |(x-1)/(x+1) - (y-1)/(y+1)| = |(x-y)(2/(x+1)(y+1))|. Thus, if we choose δ = ε/2, then for any x,y in (0,∞) such that |x - y| < δ, we have |f(x) - f(y)| = |(x-y)(2/(x+1)(y+1))| < ε. Hence, f is uniformly continuous on (0,∞).

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a) - A casual LTI discrete-time system develops an output y[n] = (0.4)"u(n) - 0.3(0.4)n-1u(n − 1). for the input x[n] = (0.2)"u(n). (i) Determine the transfer function of the system (ii) Determine the difference equation characterizing the system

Answers

(i) The transfer function of the system is:

H(z) = (0.4)^z / (0.2)^z - 0.3(0.4)^(z-1) / (0.2)^{z-1} - 2

(ii) The difference equation characterizing the system is:
y[n] = (0.4)^n x[n] - 0.3(0.4)^(n-1) x[n-1]

(i) To determine the transfer function of the system, we can take the Z-transform of both the input and output:

X(z) = (0.2)^z / (z - 0.4)
Y(z) = (0.4)^z / (z - 0.4) - 0.3(0.4)^(z-1) / (z - 0.4)

Then we can solve for the transfer function H(z) by dividing Y(z) by X(z):

H(z) = Y(z) / X(z)
    = (0.4)^z / (z - 0.4) - 0.3(0.4)^(z-1) / (z - 0.4) * (z - 0.4) / (0.2)^z
    = (0.4)^z / (0.2)^z - 0.3(0.4)^(z-1) / (0.2)^{z-1} - 2

So the transfer function of the system is H(z) = (0.4)^z / (0.2)^z - 0.3(0.4)^(z-1) / (0.2)^{z-1} - 2.

(ii) To determine the difference equation characterizing the system, we can use the formula for the output y[n] of a discrete-time LTI system with input x[n]:

y[n] = sum{k=0}{N-1} h[k] x[n-k]

where h[k] is the impulse response of the system. In this case, the impulse response can be found by setting x[n] = delta[n], the unit impulse function, and solving for y[n]:

h[n] = y[n] / delta[n]
    = (0.4)^n - 0.3(0.4)^(n-1)

So the difference equation characterizing the system is:

y[n] = (0.4)^n x[n] - 0.3(0.4)^(n-1) x[n-1]

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3.3.5. For The Following Functions, Sketch The Fourier Cosine Series Of F(X) And Determine Its Fourier Coefficients: 1 X

Answers

As we add more terms to the series, the plot approaches the original function f(x) = 1/x. Note that the series is only defined for x > 0, since f(x) is not defined at x = 0.

To sketch the Fourier cosine series of f(x) = 1/x, we need to first determine the Fourier coefficients. Recall that the Fourier cosine series is given by:

f(x) = a0/2 + ∑[n=1 to ∞] an cos(nπx/L)

where L is the period of the function (in this case, L = 2), and the Fourier coefficients are given by:

an = (2/L) ∫[0 to L] f(x) cos(nπx/L) dx

Using f(x) = 1/x, we can compute the Fourier coefficients as follows:

a0 = (2/L) ∫[0 to L] f(x) dx
  = (2/2) ∫[0 to 2] 1/x dx
  = ∞ (divergent)

an = (2/L) ∫[0 to L] f(x) cos(nπx/L) dx
  = (2/2) ∫[0 to 2] (1/x) cos(nπx/2) dx
  = (-1)^n π/2 (n ≠ 0)

Note that a0 is divergent, which means that the Fourier cosine series of f(x) will not have a constant term. Therefore, the Fourier cosine series of f(x) is given by:

f(x) = ∑[n=1 to ∞] (-1)^n π/2 cos(nπx/2)

To sketch this series, we can plot the partial sums of the series for a few values of n. For example, we can plot:

f1(x) = (-1)^1 π/2 cos(πx/2)
f2(x) = (-1)^1 π/2 cos(πx/2) + (-1)^2 π/2 cos(2πx/2)
f3(x) = (-1)^1 π/2 cos(πx/2) + (-1)^2 π/2 cos(2πx/2) + (-1)^3 π/2 cos(3πx/2)

and so on, up to some value of n. Here is what the plots look like for n = 1, 2, and 3:

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Find the value of each variable.
y
X =
30
X
8
60°
=and y=
(Simplify your answers. Type exact answers, using radicals as needed.)
www

Answers

The value of variable x and y in the right triangle are 4 and 4√3 units respectively.

How to find the side of a right angle triangle?

A right angle triangle is a triangle that has one of its angles as 90 degrees.

The variable x and y can be as follows:

cos 60° = adjacent / hypotenuse

cos 60° = x / 8

cross multiply

x = 8 cos 60°

x = 8 × 0.5

x = 4 units

Let's find the value of y as follows:

sin 60° = opposite / hypotenuse

Therefore,

sin 60° =  y / 8

cross multiply

y = 8 sin 60

y = 8 × √3 / 2

y = 4√3 units  

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Janie is selling tickets for a high school play. Child tickets cost $3 and adult tickets cost $14.
She sells 215 tickets and collects $1965.

Answers

Answer:

A = 120; C = 95

Step-by-step explanation:

We will need a system of equations to solve for C, the number of child tickets and A, the number of adult tickets.

We know that the sum of the revenue earned from both the child tickets and the adult tickets = the total revenue

(price of child tickets * quantity of child tickets) + (price of adult tickets * quantity of adult tickets) = 1965

Thus, our first equation is 3C + 14A = 1965

We also know that the sum of the total number of child and adult tickets = the the total number of tickets

total quantity of child tickets + total quantity of adult tickets = 215

Thus, our other equation is C + A = 215

We can solve using substitution by first isolating c in the second equation:

[tex]C+A=215\\C=-A+215[/tex]

Now, we can plug in the equation we just made for C in the first equation in our system to solve for A:

[tex]3(-A+215)+14A=1965\\-3A+645+14A=1965\\11A+645=1965\\11A=1320\\A=120[/tex]

Finally, we can solve for C using the second equation in our system by plugging in 120 for A:

[tex]C+120=215\\C=95[/tex]

PLEASE HELP I CANT DO IT I DONT UNDERSTAND THIS AND MY TEACHER DOESNT KNOW HOW TO EXPLAIN PROPERLY !
Use a net to find the surface area of the prism.

Answers

Answer:

[tex]SA=1657 cm^2[/tex]

Step-by-step explanation:

Surface Area Formula for Rectangular Prism.

[tex]SA=2*[ (l*h) + (w*h) + (l*w)][/tex]

Your l = 15 cm , w = 6.5 cm , and h = 34 cm.

Plug these values into the equation.

[tex]SA=2*[ (15*34) + (6.5*34) + (15*6.5)][/tex]

[tex]SA=2*[(510)+(221)+(97.5)][/tex]

[tex]SA=2*[510+221+97.5][/tex]

[tex]SA=2*(828.5)[/tex]

[tex]SA=1657 cm^2[/tex]

probability
selected point within the circle falls in the
red-shaded square.
4
5
5
P = [?]
Enter as a decimal rounded to the nearest hundredth.
Enter

Answers

The probability that the point lies on the square is P = 0.498

How to find the probability?

to find that probability, we need to take the quotient between the area of the square and the area of the circle.

We can see that the square has a side length of 5 units, then its area is.

A = 5*5 = 25 square units.

The circle has a radius of 4 units, then its area is:

A' = 3.14*4^2 = 50.24 square units

Then the probability is:

P = 25/50.24 = 0.498

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Somebody help me I need the answer?

Answers

For equation A+C=B the matrix C is [tex]\left[\begin{array}{ccc}-2&-7\\-5&8\end{array}\right][/tex] and C-B=A then C is [tex]\left[\begin{array}{ccc}2&-9\\7&0\end{array}\right][/tex]

The given matrix A = [tex]\left[\begin{array}{ccc}2&-1\\6&-4\end{array}\right][/tex]

B=[tex]\left[\begin{array}{ccc}0&-8\\1&4\end{array}\right][/tex]

Now the equation is A+C=B

[tex]\left[\begin{array}{ccc}2&-1\\6&4\end{array}\right][/tex]+C  =[tex]\left[\begin{array}{ccc}0&-8\\1&4\end{array}\right][/tex]

C=[tex]\left[\begin{array}{ccc}0&-8\\1&4\end{array}\right][/tex]- [tex]\left[\begin{array}{ccc}2&-1\\6&-4\end{array}\right][/tex]

C=[tex]\left[\begin{array}{ccc}-2&-7\\-5&8\end{array}\right][/tex]

Now equation is C-B=A

C=A+B

= [tex]\left[\begin{array}{ccc}2&-1\\6&-4\end{array}\right][/tex]+[tex]\left[\begin{array}{ccc}0&-8\\1&4\end{array}\right][/tex]

C=[tex]\left[\begin{array}{ccc}2&-9\\7&0\end{array}\right][/tex]

Hence, for equation A+C=B the matrix C is [tex]\left[\begin{array}{ccc}-2&-7\\-5&8\end{array}\right][/tex] and C-B=A then C is [tex]\left[\begin{array}{ccc}2&-9\\7&0\end{array}\right][/tex]

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34 Assume a 1/2" hole iş drilled 1 1/2" off-center on a 4" diameter circular disc. la shaft is keyed through the 1/2" hole and the disc is used as a cam, the lift cam will be A. 2 3/4" B. 3" C. 3 1/4" D. 3 1/2

Answers

The cam lift is 3 1/2 inches, which is option D.

To determine the lift of the cam, we need to find the distance from the center of the disc to the highest point of the cam surface.

First, we can find the distance from the center of the disc to the edge of the 1/2" hole. Since the hole is drilled 1 1/2" off-center, this distance is:

(4"/2) - 1 1/2" = 1"

Next, we can find the radius of the cam surface by adding the radius of the shaft (1/2") to the distance from the center of the disc to the edge of the 1/2" hole (1"):

1/2" + 1" = 1 1/2"

Finally, we can find the distance from the center of the disc to the highest point of the cam surface by adding the radius of the disc (4"/2 = 2") to the radius of the cam surface (1 1/2"):

2" + 1 1/2" = 3 1/2"

Therefore, the lift of the cam is 3 1/2 inches, which is option D.

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Write a general form of an explicit function for what the nth term of any arithmetic sequence would be in terms of a and d. Use the form below to write your function. Type the correct answer in the box.

(CORRECT ANSWER SHOWN IN PICTURE)

Answers

Answer:

Step-by-step explanation:

Simplify (step by steps, thanks!)

Answers

The simplified expression is given by (x² - 3x - 3) / ((x + 3)(x - 2)(x - 4)).

To simplify this expression, we need to find a common denominator for the two fractions and then combine them. To do this, we need to factor the denominators of both fractions.

Let's start with the first fraction's denominator:

x² + x - 6

We need to find two numbers that multiply to -6 and add to +1. These numbers are +3 and -2. Therefore, we can write:

x² + x - 6 = (x + 3)(x - 2)

Now let's factor the second fraction's denominator:

x² - 6x + 8

We need to find two numbers that multiply to 8 and add to -6. These numbers are -2 and -4. Therefore, we can write:

x² - 6x + 8 = (x - 2)(x - 4)

Now we can rewrite the original expression with a common denominator:

(x(x - 2) - (1)(x + 3)) / ((x + 3)(x - 2)(x - 4))

Next, we can simplify the numerator:

(x² - 2x - x - 3) / ((x + 3)(x - 2)(x - 4))

(x² - 3x - 3) / ((x + 3)(x - 2)(x - 4))

Finally, we can't simplify this expression any further. Therefore, the simplified expression is:

(x² - 3x - 3) / ((x + 3)(x - 2)(x - 4))

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"subject : signals and systems
question: convolution sum/integral?"1. Perform each of the following addition or subtraction operations. Express your answers in simplest form and state any non-permissible values.
a. 4x/2x+5 + 10/2x+5
b. 3y/8 - 5/6y

Answers

The simplified difference is:

3y/8 - 5/6y = (-y)/24

Note that there are no non-permissible values in this case.

a. 4x/(2x+5) + 10/(2x+5)

To add these two expressions, we need to find a common denominator. In this case, the common denominator is (2x+5):

4x/(2x+5) + 10/(2x+5) = (4x+10)/(2x+5)

Now we can simplify the numerator by factoring out a 2:

(4x+10)/(2x+5) = 2(2x+5)/(2x+5)

And we can cancel out the common factor of (2x+5):

2(2x+5)/(2x+5) = 2

Therefore, the simplified sum is:

4x/(2x+5) + 10/(2x+5) = 2

Note that the non-permissible value is x = -2.5, since this value would make the denominator equal to zero.

b. 3y/8 - 5/6y

To subtract these two expressions, we also need a common denominator. In this case, the common denominator is 24y:

3y/8 - 5/6y = (9y^2)/(24y) - (20y)/(24y)

We can simplify the first term in the numerator by canceling out a common factor of 3:

([tex]9y^2[/tex])/(24y) = (3y)/8

So the subtraction becomes:

3y/8 - 5/6y = (3y)/8 - (10y)/12

Now we can find a common denominator of 24:

(3y)/8 - (10y)/12 = (9y)/24 - (10y)/24

Simplifying the numerator gives:

(9y)/24 - (10y)/24 = (-y)/24

Therefore, the simplified difference is:

3y/8 - 5/6y = (-y)/24

Note that there are no non-permissible values in this case.

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Determine the equation of the ellipse with foci (5,8) and (5,-2), and a major axis of length 26.

Answers

The equation of the ellipse is

((x - 5)^2) / 12^2 + ((y - 3)^2) / 13^2 = 1

How to get the equation of the ellipse

Calculate the distance between the foci (2c):

2c = |8 - (-2)| = 10

c = 5

Determine the length of the semi-major axis (a):

a = 26 / 2 = 13

Solving for the center of the ellipse, denoted by (h, k):

h = (5 + 5)/2 = 5

k = (8 + -2)/2 = 3

hence, center of the ellipse is (5, 3).

solving for the length of the semi-minor axis denoted by (b):

a^2 = b^2 + c^2

knowing that the values of parameter a and c, so we can solve for b:

13^2 = b^2 + 5^2

169 = b^2 + 25

b^2 = 144

b = 12

equation of the ellipse:

((x - h)^2) / b^2 + ((y - k)^2) / a^2 = 1

Plugging in the values:

((x - 5)^2) / 12^2 + ((y - 3)^2) / 13^2 = 1

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Consider an inhomogeneous differential equation
f""(x) = ex.
a) 'Guess' a solution of the inhomogeneous equation f""(x) = e.
b) Describe all solutions of the homogeneous equation f""(x) = 0
c) Describe all solutions of the inhomogeneous equation ƒ""'(x) = e*.

Answers

To answer your question about the inhomogeneous differential equation.

a) To guess a solution for the inhomogeneous equation f''(x) = e^x, we first observe that the right side of the equation is e^x. A function whose second derivative is e^x is a linear combination of e^x, x*e^x, and x^2*e^x. Therefore, we can guess the solution to be f(x) = A*x^2*e^x + B*x*e^x + C*e^x, where A, B, and C are constants to be determined.

b) To describe all solutions of the homogeneous equation f''(x) = 0, we can note that the second derivative of a linear function is zero. Therefore, the general solution of the homogeneous equation is f(x) = Ax + B, where A and B are constants.

c) To describe all solutions of the inhomogeneous equation f'''(x) = e^x, we combine the particular solution from part a) with the general solution from part b). This gives us the general solution for the inhomogeneous equation: f(x) = A_1*x^2*e^x + B_1*x*e^x + C_1*e^x + A_2*x + B_2, where A_1, B_1, C_1, A_2, and B_2 are constants.

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What are the exact values of the cosecant, secant, and cotangent ratios of 5pi/6?

Answers

The exact values of the cosecant, secant, and cotangent ratios of 5π/6 are 2, -2/√3, and -√3, respectively.

Solution to the cosecant, secant and cotangent

To find the exact values of the cosecant, secant, and cotangent ratios of an angle of 5π/6, we need to use the definitions of these trigonometric functions and the values of the sine, cosine, and tangent of this angle.

First, we can find the sine and cosine of 5π/6 using the unit circle or reference angles:

sin(5π/6) = sin(π/6) = 1/2

cos(5π/6) = -cos(π/6) = -√3/2

Then, we can use the definitions of the cosecant, secant, and cotangent ratios:

cosec(5π/6) = 1/sin(5π/6) = 1/(1/2) = 2

sec(5π/6) = 1/cos(5π/6) = -2/√3

cot(5π/6) = cos(5π/6)/sin(5π/6) = (-√3/2)/(1/2) = -√3

Therefore, the exact values of the cosecant, secant, and cotangent ratios of 5π/6 are 2, -2/√3, and -√3, respectively.

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tais is shipping a coat to her grandmother when folded the coat has a volume of 10,000 cubic centimeters is a box with the dimensions shown large to ship the coat explain your answer.

Answers

Answer: The box is large enough to ship the coat.

15000cm to the power of 3>10000cm to the power of 3

Step-by-step explanation:

V box=25x30x20

         =750+20

         =15000cm to the power of 3

So the box is large enough to ship the coat

You rent an apartment that costs $1800 per month during the first year, but the rent is set to go up $90 per year. What would be the monthly rent during the 10th year of living in the apartment?

Answers

Answer:

The original cost of the apartment: was $1800

The increased price of the apartment per year: $90

To figure this problem out we need to calculate how much the apartment would cost around the 10th year. To do that, we would first need to multiply the $90 increase per year and the 10th years of living in the apartment.

$90 x 10 = $900

Now that we know how much it increased, we need to add that to our original cost. So, we add $1800 and $900.

$1800 + $900 = $27000

Yay! Know we know our monthly rent is $27000 during the 10th year of living there.

Linearity of expectation II) Let X,Y be random variables and a,b,c be constants. Use properties of integration/summation to show that E(aX+bY +c)= aEX +bEY + c Consider both the discrete and continuous cases.

Answers

In the case of discrete random variables, the expectation of a function is defined as the sum of the function's values multiplied by their probabilities:

E(aX + bY + c) = ∑(aX + bY + c)P(X,Y)

We can break down the sum using properties of summation:

= a∑XP(X,Y) + b∑YP(X,Y) + c∑P(X,Y)

Since the sum of probabilities over all events equals 1:

= aE(X) + bE(Y) + c

For the continuous case, the expectation of a function is defined as the integral of the function's values multiplied by the joint probability density function (PDF):

E(aX + bY + c) = ∫∫(aX + bY + c)f(X,Y)dXdY

We can break down the integral using properties of integration:

= a∫∫Xf(X,Y)dXdY + b∫∫Yf(X,Y)dXdY + c∫∫f(X,Y)dXdY

Again, since the integral of the joint PDF over all events equals 1:

= aE(X) + bE(Y) + c

Thus, we have shown that for both discrete and continuous cases, the linearity of expectation holds:

E(aX + bY + c) = aE(X) + bE(Y) + c

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4.
How many different triangles can be formed whose 3 vertices are chosen from the rectangular array of 8
points shown?
The answer is 48 but I don’t know why.

Answers

There are indeed 48 triangles that can be chosen from the rectangular array shown .

How to find the 48 triangles ?

To find the 48 triangles, you should use the Combination formula which will show you the number of ways to pick 3 points when given 8 points.

C ( n, k ) = n! / ( k ! x ( n - k ) ! )

C ( 8 , 3 ) = 8 ! / (3 ! x ( 8 - 3 ) ! )

C ( 8, 3 ) = 336 / 6

C ( 8, 3) = 56

Now, there are technically 56 ways to pick the points but some of these ways are collinear and these cannot form triangles. Each row will have 4 such points so the number of ways to pick triangles is:

= 56 - ( 4 x 2 )

= 48 triangles

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kathy and tami are at point A

Answers

The value of MAS to the nearest degree, given the radius of the circle, is 103 degrees.

How to find the MAS?

Angle MAS can be found by the formula for calculating arc length which is:

L = ( n π r ) / 180

Further solving will give us:

n π r = 197 x 180 = 3, 546

n = 3, 546 / π r

n = 3, 546 / ( 3.14 x 110 )

n = 103 degrees

In conclusion, angle mAS can be found to be 103 degrees.

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to calculate the probability that if a woman has four children, they will all be girls, you should use the rule of blank .

Answers

The probability of a woman having four girls in a row is 6.25%.

To calculate the probability that if a woman has four children, they will all be girls, you should use the rule of multiplication. This rule states that to calculate the probability of two or more independent events occurring together, you multiply the probability of each individual event. In this case, the probability of each child being a girl is 0.5 (assuming an equal chance of having a boy or girl), so you would calculate the probability as 0.5 x 0.5 x 0.5 x 0.5 = 0.0625 or 6.25%. Therefore, the probability of a woman having four girls in a row is 6.25%.

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a normal distribution has mean 12 and standard deviation of 9. what is the standard normal random variable z transformed from x

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To find the standard normal random variable z transformed from x, we first need to calculate the z-score of x. The formula for the z-score is:

z = (x - mean) / standard deviation

Substituting the values given in the question, we get:

z = (x - 12) / 9

We can then transform this equation to solve for x in terms of z:

x = mean + z * standard deviation

Substituting the values for mean and standard deviation, we get:

x = 12 + z * 9

Therefore, the standard normal random variable z transformed from x is:

x = 12 + z * 9
To transform a given value (x) from a normal distribution with mean (μ) and standard deviation (σ) to a standard normal random variable (z), you can use the z-score formula:

z = (x - μ) / σ

In this case, the normal distribution has a mean (μ) of 12 and a standard deviation (σ) of 9. To transform any value x from this distribution to a standard normal random variable (z), you can follow these steps:

Step 1: Subtract the mean (μ) from the given value (x).
z = (x - 12)

Step 2: Divide the result by the standard deviation (σ).
z = (x - 12) / 9

Now you have the formula to transform any value x from the given normal distribution to a standard normal random variable (z).

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Determine whether the relationship is a function. Complete the explanation.
(6, 3), (5, 6), (-1, 1), (6, 9), (8,8)
Since (select)
(select) a function.
Input value is paired with (select)
output value, the relationship

Answers

The given relationship in the task content is not a function as more than one output value is paired with the same input value.

Is the given relationship a function?

Recall that a relationship is said to be a function only if one output value is attached to each input value of the relationship.

On this note, by observation; the pair of coordinates (6, 3) and (6, 9) implies that two output values are assigned to the same input value. Consequently, the given relationship is not a function.

The complete and correct sentence is therefore; Since one input value is paired with two output values; the relationship is not a function.

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The Transportation Safety Authority (TSA) has developed a new test to detect large amounts of liquid in luggage bags. Based on many test runs, the TSA determines that if a bag does contain large amounts of liquid, there is a probability of 0. 98 the test will detect it. If a bag does not contain large amounts of liquid, there is a 0. 07 probability the test will conclude that it does (a false positive). Suppose that in reality only 4 in 100 bags actuallycontain large amounts of liquid.

1. What is the probability a randomly selected bag will have apositive test? Give your answer to four decimal places.

2. Given a randomly selected bag has a positive test, what is theprobability it actually contains a large amount of liquid? Giveyour answer to four decimal places.

3. Given a randomly selected bag has a positive test, what is theprobability it does not contain a large amount of liquid? Give youranswer to four decimal places

Answers

1. What is the probability a randomly selected bag will have a positive test? Give your answer to four decimal places is 0.1032

2. Given a randomly selected bag has a positive test, what is the probability it actually contains a large amount of liquid is 0.3780

3. Given a randomly selected bag has a positive test, what is the probability it does not contain a large amount of liquid is  0.6219

Let's characterize the taking after occasions:

A: The pack contains huge sums of fluid.

B: The test is positive.

We are given the taking after probabilities:

P(A) = 0.04

P(B | A) = 0.98

P(B | not A) = 0.07

1. To discover the likelihood of a positive test, we are able to utilize the law of adding up to likelihood:

P(B) = P(B | A) P(A) + P(B | not A) P(not A)

= 0.98 * 0.04 + 0.07 * 0.96

= 0.1032

So the likelihood of a haphazardly chosen pack having a positive test is 0.1032 (adjusted to four decimal places).

2. To discover the likelihood that a sack really contains large amounts of fluid given a positive test, we are able to utilize Bayes' hypothesis:

P(A | B) = P(B | A) P(A) / P(B)

= 0.98 * 0.04 / 0.1032

= 0.3780

So the likelihood that a pack really contains expansive sums of fluid given a positive test is 0.3780 (adjusted to four decimal places).

3. To discover the likelihood that a sack does not contain expansive sums of fluid given a positive test, ready to utilize Bayes' hypothesis again:

P(not A | B) = P(B | not A) P(not A) / P(B)

= 0.07 * 0.96 / 0.1032

= 0.6219

So the likelihood that a pack does not contain expansive sums of fluid given a positive test is 0.6219 (adjusted to four decimal places). 

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Alex painted 178 ft2 of his apartment’s walls with 13 1 3 gallon of paint. He has 2 gallons of paint in all. If he wants to cover 1,000 ft2 of his apartment, does he have enough paint? Complete a true statement

Answers

From multiplcation operation, Alex has enough paint to cover 1,000 ft² of his apartment. The true statement is 2 gallons of paint will cover 1068 ft², Alex have enough paint of quantity 2 gallons.

We have Mr. Alex painted his apartment. Area of his apartment'walls = 178 ft²

Quantity of paint used by him to paint his apartment'walls with area 178 ft² =[tex] \frac{1}{3} \: \: gallons[/tex]

Total quantity of paint used in all

= 2 gallons

We have to check the provide paint is enough or not to cover 1,000 ft² of his apartment. Let the required paint for 1000 ft² be x gallons. Using multiplcation, 1/3 gallons quantity of paint will cover the area of apartment = 178 ft², so, 1 gallons quantity of paint will cover the area of apartment = 178 ×3 ft²= 534 ft²

Now, 2 gallons quantity of paint will cover the area of apartment = 2× 534 ft² = 1068 ft²> 1000 ft²

But he wants to paint 1000 ft² of his apartment in 2 gallons quantity (x=1.9 gal ). So, he has enough paint to paint his apartment.

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Complete question:

The above figure complete the question.

Alex painted 178 ft2 of his apartment’s walls with 1/3 gallon of paint. He has 2 gallons of paint in all. If he wants to cover 1,000 ft2 of his apartment, does he have enough paint? Complete a true statement

Use Wallis's Formulas to evaluate the integral.

∫ cos^7 (x) dx

Answers

The value of the integral ∫ [tex]cos^7(x) dx[/tex] is[tex](3\pi /32).[/tex]

Wallis's formulas are used to evaluate integrals of the form:

∫ [tex]sin^{n(x)} cos^{m(x)} dx[/tex]

where n and m are non-negative integers. We can use the trigonometric identity[tex]cos^{2(x)] + sin^{2(x)} = 1[/tex] to convert the powers of cosine to powers of sine.

Here, we have m = 7, so we can use the identity [tex]cos^{2(x)} = 1 - sin^{2(x)}[/tex] to write:

[tex]cos^{7(x)} = cos^{6(x)}[/tex] × [tex]cos(x)[/tex]

[tex]= (1 - sin^2(x))^3[/tex] ×[tex]cos(x)[/tex]

Now, we can use a substitution of [tex]u = sin(x), du = cos(x) dx[/tex]to convert the integral to a form that can be evaluated using Wallis's formulas:

∫ [tex]cos^7(x) dx =[/tex] ∫ [tex](1 - sin^2(x))^3[/tex] × [tex]cos(x) dx[/tex]

= ∫ [tex](1 - u^2)^3 du[/tex]

Using Wallis's formulas, we have:

∫ [tex](1 - u^2)^3 du = (1/8)[/tex]× β[tex](4, 4)[/tex]

[tex]= (1/8)[/tex] ×[tex][(3\pi /4) / sin(3\pi /4)][/tex]

[tex]= (3\pi /32)[/tex]

Substituting [tex]u = sin(x)[/tex], we have:

∫ [tex]cos^7(x) dx =[/tex] ∫ [tex](1 - u^2)^3 du = (3π/32)[/tex]

Therefore, the value of the integral ∫ [tex]cos^7(x) dx[/tex] is [tex](3\pi /32).[/tex]

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Steven cleans his aquarium by replacing 2/3 or the water with new water, but that doesn’t clean the aquarium to his satisfaction. He decides to repeat the process, again replacing 2/3 of the water with new water. How many times will Steven have to do this so that at least 95% of the water is new water?

Help as quickly as possible!!!

Answers

Steven will have to repeat the process three times so that at least 95% of the water is new water

what is 48 - 36 and then divided by 36

Answers

Answer

The result of 48 - 36 is 12. Then, if you divide 12 by 36, the result is 0.3333 or 1/3.

Step-by-step explanation:

An airline knows from experience that the distribution of the number of suitcases that get lost each week on a certain route is approximately normal with L = 16.9 and 3.3. What is the probability that in a given week the airline will lose less than 20 suitcases?

Answers

The probability that in a given week the airline will lose less than 20 suitcases is approximately 0.8186 or 81.86%.

We are given that the distribution of the number of suitcases that get lost each week on a certain route is approximately normal with a mean of [tex]$\mu = 16.9$[/tex] and standard deviation of [tex]$\sigma = 3.3$[/tex]. We need to find the probability that in a given week the airline will lose less than 20 suitcases.

Let X be the number of suitcases lost in a week. Then we need to find P(X < 20).

Using the Z-score formula, we can standardize the variable X as:

[tex]Z=\frac{X-\mu}{\sigma}[/tex]

Substituting the given values, we get:

[tex]Z=\frac{20-16.9}{3.3}=0.91[/tex]

Now, we need to find the probability that Z is less than 0.91. We can use a standard normal distribution table or calculator to find this probability, which is approximately 0.8186.

Therefore, the probability that in a given week the airline will lose less than 20 suitcases is approximately 0.8186 or 81.86%.

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