2.) In the coordinate plane, the line with equation y = 5x - 10 crosses the x-axis at the point with coordinates (a, b) What is the value of a? Explain or show your work.​

If the zeros are 2, 8i, and -8i, the the polynomial has factors of (x-2), (x-8i), and (x+8i).

If we multiply those factors, we'll get our polynomial:

    (x-2)·(x-8i)·(x+8i) = (x-2)·(x^2+64)

                               = x^3 - 2x^2 + 64x - 128

In response to the stated question, we may state that therefore, the expressions value of vector will be n = 25.73.

An expression in mathematics is a collection of numbers, variables, and mathematical (such as addition, reduction, multiplication, division, exponentiation, etc.) that express a quantity or value. Expressions might be as basic as "3 + 4" or as complicated as "(3x2 - 2) / (x + 1)". They may also contain functions like "sin(x)" or "log(y)". Expressions can also be evaluated by substituting values for the variables and performing the mathematical operations in the order specified. If x = 2, for example, the formula "3x + 5" equals 3(2) + 5 = 11. Expressions are commonly used in mathematics to describe real-world situations, construct equations, and simplify complicated mathematical topics.

to find vector and magnitude we have

[tex]n^2 = (22.5)^2 + (12.5)^2\\n^2 = 506.25 + 156.25\\n^2 = 662.5\\n = \sqrt(662.5)\\n = 25.73[/tex]

therefore, the value of vector will be n = 25.73.

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According to the given information EF = 8 and DF = 7.

A triangle is a three-sided polygon made up of three line segments that connect at three endpoints, called vertices. The study of triangles is an important part of geometry, and it has applications in various fields such as engineering, architecture, physics, and computer graphics.

Since triangle ABC and triangle DEF are similar, their corresponding sides are proportional. That is:

AB/DE = BC/EF = AC/DF

We are given AB = 40, BC = 64, AC = 56, and DE = 5. We can use the ratio AB/DE = BC/EF to find EF:

AB/DE = BC/EF

40/5 = 64/EF

8 = 64/EF

EF = 64/8

EF = 8

So EF = 8.

Similarly, we can use the ratio AC/DF to find DF:

AC/DF = AB/DE

56/DF = 40/5

56/DF = 8

DF = 56/8

DF = 7

So DF = 7.

Therefore,according to the given information EF = 8 and DF = 7.

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The probability that the total sum of all rolls does not exceed 375 is approximately 0.7165

Assuming the die is a fair six-sided die, the possible outcomes for each roll are numbers 1 through 6, each with a probability of 1/6.

Let X be the total sum of all rolls. Then X follows a discrete uniform distribution with parameters n = 104 (number of rolls) and a = 1 (minimum value of each roll). The expected value of X is:

E(X) = n × (a + b) / 2 = 104 × (1 + 6) / 2 = 365

The variance of X is

Var(X) = n × (b - a + 1)^2 / 12 = 104 × 6^2 / 12 = 312

The standard deviation of X is

SD(X) = sqrt(Var(X)) = sqrt(312) = 17.67

To calculate the probability that the total sum of all rolls does not exceed 375, we need to calculate the cumulative distribution function (CDF) of X and evaluate it at 375

P(X <= 375) = F(375)

where F(x) = P(X <= x) is the CDF of X.

Using the normal approximation to the binomial distribution, we can approximate X as a normal distribution with mean E(X) = 365 and standard deviation SD(X) = 17.67

Z = (X - E(X)) / SD(X)

Z follows a standard normal distribution with mean 0 and standard deviation 1.

P(X <= 375) = P(Z <= (375 - E(X)) / SD(X))

= P(Z <= (375 - 365) / 17.67)

= P(Z <= 0.566)

Using a standard normal distribution table or a calculator, we can find that P(Z <= 0.566) is approximately 0.7165.

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The given question is incomplete, the complete question is :

A die is continuously rolled 104 times. what is the probability that the total sum of all rolls does not exceed 375 ?

The "x is small" approximation only works when the initial concentration of the reactant is relatively large and the equilibrium constant is small.

What does the "x is small" approximation mean? The x is small approximation does not mean that x is zero. If that were the case, the reactant and product concentrations wouldn't change from their initial values. The x is small approximation just means that when x is added or subtracted to another number, it doesn't change that number by very much. When does the "x is small" approximation work? The "x is small" approximation only works when the initial concentration of the reactant is relatively large and the equilibrium constant is small. What is the <5% rule? The x is small approximation must satisfy the <5% rule, whereby the x approximation divided by the number it was subtracted from is less than 5% (or 0.05). What is the method of successive approximation? The method of successive approximation is solving for x as if it were small, and then substituting the value obtained back into the equation (where x was initially neglected) to solve for x again. This can be repeated until the calculated value of x stops changing with each iteration, an indication that we have arrived at an acceptable value for x.

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The enthalpy change of each step in the cycle must be added together to obtain the enthalpy of formation of the desired compound.

The enthalpy of formation of a compound that cannot be synthesized directly from the constituent elements can be calculated using the Hess's Law. Hess's Law states that the enthalpy change of a reaction is independent of the route taken from reactants to products. This law allows for the enthalpy of formation of a compound to be determined by summing the enthalpy changes of a series of known reactions, referred to as a ‘thermochemical cycle’, which lead to the compound of interest. To use this law, the enthalpy of formation of the intermediate species formed during the reaction must be known.

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Answer:

Step-by-step explanation:

To find when people stop watching the video, we need to find the maximum point of the quadratic function y = -0.75x² + 9.75x.

The x-coordinate of the maximum point of a quadratic function can be found using the formula x = -b/2a, where a and b are the coefficients of the quadratic function.

Using the formula with a = -0.75 and b = 9.75, we get:

x = -9.75 / 2(-0.75)

x = -9.75 / -1.5

x = 6.5

Therefore, the maximum number of views per day will occur on the 6.5th day after the video was posted.

To determine when people stop watching the video, we need to check the values of y after this point.

When x > 6.5, the quadratic function becomes negative, which means that the number of views per day will start to decrease. Therefore, people stop watching the video after 6.5 days (or sometime around the 7th day).

Answer:27.5

Step-by-step explanation:

i did this with a calculator, but the answer is

27.5

280 dogs in all of the city's animal shelters are puppies. The solution has been obtained by using ratios.

What is ratio?

The ratio between two amounts of the same unit can be used to determine how much of one quantity is included in the other.

We are given that different animal shelters in a city shows that 10 of the 70 dogs are puppies and the city's animal shelters collectively house 1,960 dogs each year.

So, from this we get the ratio as

⇒ [tex]\frac{10}{70}[/tex] = [tex]\frac{x}{1960}[/tex]

Now, by cross multiplying, we get

⇒ 19,600 = 70x

⇒ x = 280

Hence, 280 dogs in all of the city's animal shelters are puppies.

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There are 4896 ways of arranging 7 pets in a row of 7 chairs such that at least 2 cats are next to each other.

Arrangement of entities can be done using permutation and combination in mathematics.

Consider the distributions where 2 cats are not next to each other as

C D C D C D C.

There are 4! ways to seat the cats, and 3! ways to seat the dogs that gets us N=4! 3! = 144

There are a total of 7!=5040 possible ways to seat both cats and dogs.

At least 2 cats seat together= All possible arrangements- None of the cat seat together.

Thus the number of seatings where at least 2 cats are adjacent is

5040-144 = 4896

So, there are 4896 arrangements can be made so that at least 2 of the cats seat together.

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Mark needs to invest 5572.24 hours (rounded to one decimal place) of study time in order to achieve an A letter grade in this course.

To determine the estimated minimum number of hours Mark should study, we need to solve for the number of hours such that his predicted score, given by the regression equation from part (b), is at least 90.

The regression equation is as follows: Predicted score = 48.74 + 0.00726(number of hours studied)

Setting the predicted score equal to 90 and solving for the number of hours studied gives:90 = 48.74 + 0.00726 (number of hours studied)

Solving for the number of hours studied gives: number of hours studied = (90 - 48.74)/0.00726= 5572.24

Therefore, Mark should study for 5572.24 hours (rounded to one decimal place) to receive a letter grade of A for this course.

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Answer: 3 5/8 pizzas were there at the start of the party.

Step-by-step explanation:

At the party let number of pizzas were = x Aisha and her friends ate 2 1/2 pizzas after which 1 1/8 pizzas were left.

Therefore the equation formed will be

x- 2 1/2= 1 1/8

x-(5/2)= 9/8

x= 9/8 + 5/2

x= 29/8= 3 5/8

Therefore 3 5/8 pizzas were there at the start of the party.

Free Water ≈ 0 M (as bound water is approximately equal to total water). To find the equilibrium concentrations for the two complexes at different temperatures, we can use the provided values in the table:

Ice Water:
[CoCl₄]²⁻ = 3.331x10⁻⁶ M
[Co(H₂O)₆]²⁺ = 0.04246 M
Room Temperature:
[CoCl₄]²⁻ = 3.183x10⁻⁶ M
[Co(H₂O)₆]²⁺ = 0.04243 M
Warm Water:
[CoCl₄]²⁻ = 0.0000957 M
[Co(H₂O)₆]²⁺ = 0.04151 M
#19) To find the equilibrium free chloride concentration at room temperature, use the formula:
Free Chloride = Total Chloride - Bound Chloride
Total Chloride = [CoCl₄]²⁻
Bound Chloride = 4 * [CoCl₄]²⁻ (since 4 chloride ions are used for each complex)
At room temperature:
Free Chloride = Total Chloride - 4 * 3.183x10⁻⁶ M
Free Chloride ≈ 0 M (as bound chloride is approximately equal to total chloride)
#20) To find the equilibrium free water concentration at room temperature, use the formula:
Free Water = Total Water - Bound Water
Total Water = [Co(H₂O)₆]²⁺
Bound Water = 6 * [Co(H₂O)₆]²⁺ (since 6 water molecules are used for each complex)
At room temperature:
Free Water = Total Water - 6 * 0.04243 M.

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The area of the parallelogram above is 490 metres squared.

A parallelogram is a quadrilateral with opposite sides equal to each other and opposite sides parallel to each other.

The area of a parallelogram can be calculated as follows:

area of a parallelogram = bh

where

Therefore,

b = 49 metres

h = 10 metres

Therefore,

area of a parallelogram = 10 × 49

area of a parallelogram = 490 metres squared

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Answer:

(a) Pour montrer que la suite (Un) est géométrique, il suffit de vérifier que le quotient de deux termes consécutifs est constant. Soit n un entier naturel non nul. Alors :

Un+1 / Un = (Un-4) / (Un) = 1 - 5/Un

Donc, pour tout n E N*, on a :

Un+1 / Un = 1 - 5/Un = (Un / Un) - (5/Un) = (Un - 5) / Un

On a bien trouvé une raison q = -5/1, et un premier terme U1 = U1 - 5.

(b) La raison de la suite (Un) est q = -5/1. En utilisant la formule générale de la suite géométrique, on obtient :

Un = U1 * q^(n-1) = (U1 - 5) * (-5)^(n-1)

En particulier, on a :

U_n = U_1 * q^{n-1} = (U_1 - 5) * (-5)^{n-1} = U_12 = (U_1 - 5) * (-5)^{12-1}

(c) On n'a pas suffisamment d'informations pour déterminer la valeur de U1, donc on ne peut pas calculer directement la valeur de U12.

The set of ordered pairs (2,1), (3,3), (4,6), (2,3) is NOT a function because the input value of 2 corresponds to both the output values of 1 and 3.

For a set of ordered pairs to be a function, each input (x-value) must correspond to only one output (y-value). Therefore, if there exists an input (x-value) that corresponds to more than one output (y-value), then the set of ordered pairs is NOT a function.

Let's check each set of ordered pairs:

Therefore, the set of ordered pairs that is NOT a function is (2,1), (3,3), (4,6), (2,3).

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Answer:

2.80

Step-by-step explanation:

It asks to find the shipping and handling price.

The first step is take that percentage, 20% and convert into decimal form. Then you need to multiply that by the original price. So it would be 0.2 x 14.

That gives you 2.80 which is the shipping and handling price. That's all you have to do.

The equation of an exponential decay function with a range of (-∞,10), vertical shrink of 3/4, and vertical shift up 10 units is f(x) = 10 - (3/4)^x.

An exponential decay function can be written as f(x) = ab^x where b is the base of the exponential function and a is the initial value. If b is between 0 and 1, the function will exhibit exponential decay. Since we need a vertical shrink of 3/4, we can set b = 3/4.

We also need a vertical shift of 10 units, so we add 10 to the function. The resulting function is: f(x) = 10 - (3/4)^x. Therefore, the equation of an exponential decay function with a range of (-∞,10), vertical shrink of 3/4, and vertical shift up 10 units is f(x) = 10 - (3/4)^x.

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Answer:

g(x) = (x + 3)2 - 2

Step-by-step explanation:

I think that's the one I just did this class so

Answer:

n=12

Step-by-step explanation:

sum of interior angles of polygon with n sides = (n-2)180

measure of an interior angle of a polygon times the number of sides (n) = sum of interior angles of polygon with n sides, therefore:

(n - 2)180 = 150n

180n - 360 = 150n

30n = 360

n = 360/30 = 12

a) The degree of freedom for a sample size 25 is equals to the 24 and the critical value t* for 80% confidence interval and degree of freedom 24 is equals to 1.318.

b) The degree of freedom for a sample size 55 is equals to the 54 and the critical value t* for 98% confidence interval and degree of freedom 54 is equals to 2.403.

The t-distribution has a bell-shaped density curve but has more variance (spread) than a normal bell curve.

Step 1: First express the confidence level as a number (in decimal) c with 0<c<1.

Step 2: Determine the significance level, denoted

α, by α = 1 − c.

Step 3: Use the t-distribution table to obtain the t-score (critical value) tα/2 where (i) the α is from Step 2 and (ii) the degrees of freedom equals n−1, where n is the sample size.

a) 80% of confidence interval and observation of

Sample size, n = 25

From above definition, degree of freedom= n - 1 = 25 - 1 = 24 and c = 80%

= 0.80

Significance level, α = 1- c = 1 - 0.80 = 0.20

and α/2 = 0.10 then use the t-table the critical t-value for this 80% confidence interval, t₀.₁₀ = 1.711.

b) 98% confidence interval with 55 observations. So, Sample size, n = 55

degree of freedom = n - 1 = 55 - 1 = 54,

c = 98% = 0.98

Significance level, α = 1-0.98 = 0.02

and α/2 = 0.01, then use the t-table the critical t-value for this 98% confidence interval, t₀.₀₁ = 2.669

Hence required value is 2.669.

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The coordinate of the point U that divides the line ST in the ratio 2:5 is: (12:6)

The formula for the division of line segments in the ratio m:n is

P = {[(mx2 + nx1)/(m + n)], [(my2 + ny1)/(m + n)]}

We are given the coordinates of line Segment ST as: S(10, 2) and T(17, 16)

Thus, if the ratio is 2:5, we have:

U(x, y) = {[(2*17 + 5*10)/(2 + 5)], [(2*16 + 5*2)/(2 + 5)]}

U(x, y) = (84/7), (42/7)

U(x, y) = (12, 6)

Thus, that is the coordinate of the point U that divides the line ST in the ratio 2:5.

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1: The measure of arc JML is: arc JML = 176°

3: m∠WXY = 59°

5: The measure of the arc is: arc FE = 54°

7: The measure of the angles are: m∠A  = 79° and m∠B  = 112°

9: The value of x is: x = 9

No. 1

The measure of inscribed angle is half the measure of its intercepted arc. That is:

∠ JKL = 1/2 * arc JML

88 = 1/2 * arc JML

arc JML = 2 * 88

arc JML = 176°

No. 3

arc WY =  360 - 86 - 156 = 118° (sum of angles in a circle)

m∠WXY = 1/2 * arc WY

m∠WXY = 1/2 * 118

m∠WXY = 59°

No. 5

An angle inscribed in a semicircle is a right angle. Thus, m∠DFE = 90°

m∠EDF = 180 - 90 - 63 = 27° (sum of angles in a triangle)

m∠EDF  = 1/2 * arc FE

27°  = 1/2 * arc FE

arc FE = 2 * 27

arc FE = 54°

No. 7

The opposite angle in a cyclic quadrilateral add up to 180°. That is:

m∠A + m∠C  = 180°

m∠A + 101 = 180

m∠A  = 180 - 101

m∠A  = 79°

m∠B + m∠D  = 180°

m∠B + 68 = 180

m∠B  = 180 - 68

m∠B  = 112°

No. 9

67 = 1/2 * (16x - 10)

67 * 2 = (16x - 10)

16x - 10 = 134

16x  = 134 + 10

16x = 144

x = 144/16

x = 9

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Answer:

y = {18 x + 14, 14 - 15 x, 14 - 39 x}

Step-by-step explanation:

There is zero context to this, so I have no clue if this helps or even answers your question. Try harder with the question next time.

In this particular question, the following statements can be used to complete each sentence with either "increases" or "decreases":

- Phytic acid decreases the absorption of zinc from grains.

Oxalic acid decreases the absorption of calcium from spinach.

- Refinement of grains decreases the mineral content of grain products.-

Vitamin C increases the absorption of iron from foods.-

Vitamin D increases the absorption of calcium from foods.

Explanation:

Bioavailability refers to the proportion of a nutrient that is absorbed from food and made available for use in the body. Factors that alter bioavailability of minerals from foods include phytic acid, oxalic acid, refinement of grains, and vitamins C and D. Phytic acid, for instance, decreases the absorption of zinc from grains while oxalic acid decreases the absorption of calcium from spinach.

           Refinement of grains, on the other hand, decreases the mineral content of grain products. Conversely, vitamin C increases the absorption of iron from foods while vitamin D increases the absorption of calcium from foods.

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a force of 560J can raise a block weighing 8 N to a height of 70 meters. It's important to note that this calculation assumes no energy is lost due to friction or other factors, so in reality, the block may not reach exactly 70 meters.

How to calculate work?

To calculate the height to which a block weighing 8 N can be raised by a force of 560J, we need to use the formula for work done:

Work (W) = force (F) x distance (d) x cos(theta)

where theta is the angle between the force and the displacement. In this case, the force is the weight of the block (8 N), the distance is the height the block is raised (h), and theta is 0 degrees because the force is acting vertically upward and the displacement is in the same direction.

So, we can rearrange the formula to solve for the height (h):

h = W / (F x cos(theta))

Substituting the values we have, we get:

h = 560 J / (8 N x cos(0 degrees))

Since the cosine of 0 degrees is 1, we can simplify to:

h = 560 J / 8 N

h = 70 meters

Therefore, a force of 560J can raise a block weighing 8 N to a height of 70 meters. It's important to note that this calculation assumes no energy is lost due to friction or other factors, so in reality, the block may not reach exactly 70 meters.

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According to the question, we are given a triangle XYZ

where,

Angle sum property states that sum of all the angles of triangle is 180°. So by adding all the three angles we will get the required value of a.

∠X + ∠Y + ∠Z = 180°

30° + 20° + 2a° = 180°

50° + 2a° = 180°

2a° = 180° - 50°

2a° = 130°

a° = 130/2

a° = 65°

Therefore, required value of a is 65°

Answer:

B

Step-by-step explanation:

remember : the sum of all angles in a triangle is always 180°.

are you sure the third angle is called ZZ ?

I am rather sure it would be called XY !

so,

180 = ZX + ZY + XY = 30 + 20 + 2a

130 = 2a

a = 130/2 = 65°

Answer:

multiply BD and AC and you got it

Step-by-step explanation:

if yuo put ABD triangle over CEB you got a sqare, if you do it again you got a aqare 20x10

The equation of the line is 9x+8y + 19 = 0 and 5x - 4y+ 19 = 0 According to the given graphs, these are the equations of the graph.

Consider two points on the blue line.

The points are (5, -8) and ( -3,1 ).

Equation of the blue line is:

y - 1 = [tex]\frac{-8-1}{5+3} (x+3)[/tex]

8 (y - 1) = -9 ( x + 3)

8y - 8 = -9x -27

9x + 8y + 19 = 0

Therefore, the Equation of the blue line is 9x + 8y + 19 = 0.

Consider two points on the red line.

The points are (-3, 1) and ( 1,6 ).

Equation of the red line is:

y - 1 = [tex]\frac{6-1}{1+3} (x+3)[/tex]

4 (y - 1) = 5 (x + 3)

4y - 4 = 5x + 15

5x - 4y+ 19 = 0

Therefore, the Equation of the red line is 5x - 4y+ 19 = 0.

Hence, the equations for the given blue and red lines are completed.

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