20. PT = 2x, TR = y + 3, QT = 3x, TS = 2y


21. PT = 8x, TR = 6y, QT = 2x + 2, TS = 2y


I’m confused on these question

The number line represents all possible numbers of signatures Ali could collect is Number line A.

We have,

Ali currently has 520 signatures.

Now, number of signatures Ali need

= 1,000 - 520

= 480

So, the possible number depending on how many weeks he wants to spend getting signatures.

480/6 = 80

480/5 = 96

480/4 = 120

480/3 = 160

480/2 = 240

480/1 = 480

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The probability that a randomly selected golf ball will be purple is 1/6

From the question, we have the following parameters that can be used in our computation:

The probability that a randomly selected golf ball will be purple is calculated as

Probability = Purple/Number of golf balls

Substitute the known values in the above equation, so, we have the following representation

Probbaility = 2/12

Simplify

Probbaility = 1/6

Hence, the value of the probability is 1/6

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Answer:

The 18 oz jar is the better buy.

Step-by-step explanation:

[tex] \frac{ - 9}{20} [/tex]

is greater

The correct option is NO, the line XY is not tangent to the circle Z.

The tangent to a circle theorem states that a line is tangent to a circle if and only if the line is perpendicular to the radius drawn to the point of tangency

For the line XY to be tangent to the circle Z implies line XZ is perpendicular to line XY which will make the triangle XYZ a right triangle

So by Pythagoras rule, the sum of the square for the sides XZ and XY must be equal to the square of YZ, otherwise, XY is not a tangent to the circle Z

XY² = 5² = 25

XZ² + XY² = 8² + 10² = 164.

In conclusion, since XZ² + XY² is not equal to XY², then XY is not tangent to the circle Z.

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Chaneece did not find the correct solution

From the question, we have the following parameters that can be used in our computation:

x and y are the integers

So, we have

x + y ≤ 40

x - y ≥ 20

Add the equations

So, we have

2x = 60

Divide

x = 30

Next, we have

30 + y ≤ 40

So, we have

y ≤ 10

This means that

x = 30 or between 20 and 30

y = 10 or between 0 and 10

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The confidence interval for the proportion of left-handed golfers is (0.27, 0.31).

We have,

We will calculate the confidence interval for the proportion of left-handed golfers in a survey of 2,360 golfers.

The given information includes 29% being left-handed and a margin of error of 2%.

To calculate the confidence interval, follow these steps:

1. Convert the percentages to decimals:

0.29 for the proportion of left-handed golfers and 0.02 for the margin of error.

2. Add and subtract the margin of error from the proportion of left-handed golfers:

0.29 + 0.02 and 0.29 - 0.02.

3. Calculate the lower and upper limits of the confidence interval:

0.29 - 0.02

= 0.27 and 0.29 + 0.02

= 0.31.

Thus,
The confidence interval for the proportion of left-handed golfers is (0.27, 0.31).

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To find the simplest function f and a number a, we can begin by simplifying the expression within the limit. We can use the formula for the difference of squares to rewrite the numerator as (x^40 + x^20 + 1)(x^20 - 1). Similarly, we can use the formula for the difference of cubes to rewrite the denominator as (x - 1)(x^2 + x + 1)(x^3 + x^2 + 1)(x^6 + x^3 + 1).

Canceling out the common factor of x - 1 in the numerator and denominator, we are left with:

limx→1(x^20 + x^10 + 1)(x^20 - 1) / (x^2 + x + 1)(x^3 + x^2 + 1)(x^6 + x^3 + 1)

To find the simplest function f, we can let f(x) = x^20 + x^10 + 1. Then, f'(x) = 20x^19 + 10x^9, so f'(1) = 30.

Therefore, we can rewrite the limit as:

limx→1 [f(x) - 1] / [(x - 1)(x^2 + x + 1)(x^3 + x^2 + 1)(x^6 + x^3 + 1)]

Using L'Hopital's rule or factoring, we can simplify the denominator to (1 + 1 + 1)(1 + 1)(1 + x + x^2)(1 + x^3 + x^6), which equals 9(1 + x + x^2)(1 - x + x^2)(1 + x^3 + x^6).

Plugging in f'(1) and simplifying, we get:

limx→1 [f(x) - 1] / [(9)(1 + x + x^2)(1 - x + x^2)(1 + x^3 + x^6)]

= [f'(1)] / [9(1 + 1 + 1)(1 + 1)(1 + 1 + 1)(1 + 1 + 1 + 1 + 1 + 1)]

= 30 / 1944

Therefore, the value of the limit is 30 / 1944.
a. To find the simplest function f and the number a, we first recognize that the given limit represents the derivative of a function f at a point a:

lim(x→1) [(x^80 - 1) / (x - 1)]

We can use the definition of a derivative, which is:

f'(x) = lim(h→0) [(f(x + h) - f(x)) / h]

Comparing this with the given limit, we have:

f(x + h) = x^80
f(x) = 1

Here, x + h = x^80 and x = 1. So, f(1) = 1. Since f'(a) is given at x = 1, we have:

a = 1

The simplest function f is a power function of the form f(x) = x^n. To find n, we consider the fact that f(1) = 1:

1^n = 1

The simplest solution is when n = 1, so f(x) = x.

b. Now, we determine the value of the limit by finding f'(a). Since we found that f(x) = x, we can calculate its derivative:

f'(x) = d(x)/dx = 1

Now, we can find f'(a) by substituting a = 1:

f'(1) = 1

So, the value of the limit is 1.

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Answer:

We need at least 42 particles to estimate the population mean within 3.2 micrometers with 99% confidence.

Step-by-step explanation:

The problem is not related to the definition of N99 masks, but it involves statistical inference.

To solve this problem, we need to use the central limit theorem, which states that the sample mean of a large sample will be approximately normally distributed, regardless of the underlying distribution of the population.

We can use the formula for the margin of error to find the sample size needed to estimate the population mean within a certain margin of error with a certain level of confidence.

Assuming a normal distribution with a standard deviation of (21-5)/2 = 8 micrometers, we can use the following formula:

Margin of error = z * (standard deviation / sqrt(sample size))

where z is the z-score corresponding to the desired level of confidence. For a 99% confidence level, the z-score is 2.576.

We want the margin of error to be 3.2 micrometers, so we can solve for the sample size:

3.2 = 2.576 * (8 / sqrt(sample size))

sqrt(sample size) = 2.576 * 8 / 3.2

sqrt(sample size) = 6.44

sample size = 6.44^2 = 41.5

Therefore, we need at least 42 particles to estimate the population mean within 3.2 micrometers with 99% confidence.

A basis for W is {[tex]x^2 - 1, x - 1[/tex]}, and the dimension of W is 2. Any polynomial in W can be written as a linear combination of the two polynomials [tex]x^2 - 1[/tex] and x - 1. Since these two polynomials are linearly independent, they form a basis for W.

a) To show that W is a subspace of P2, we need to show that it satisfies the three conditions of a subspace:

i) W contains the zero vector:

The zero polynomial p(x) = 0 satisfies p(1) = 0, so it is in W.

ii) W is closed under addition:

Let p(x) and q(x) be polynomials in W. Then:

[tex](p+q)(1) = p(1) + q(1) = 0 + 0 = 0,[/tex]

so p+q is also in W.

iii) W is closed under scalar multiplication:

Let p(x) be a polynomial in W, and let c be a scalar. Then:

[tex](cp)(1) = c(p(1)) = c(0) = 0,[/tex]

so cp is also in W.

Since W satisfies all three conditions, it is a subspace of P2.

b) We can conjecture that the dimension of W is 2, because P2 is a vector space of dimension 3, and the condition p(1) = 0 imposes a single linear constraint on the coefficients of a polynomial in P2.

c) To find a basis for W, we need to find a set of linearly independent polynomials that span W. Let p(x) = [tex]ax^2 + bx + c[/tex] be a polynomial in W. Then:

p(1) = a + b + c = 0.

Solving for c, we get:

c = -a - b.

So any polynomial in W can be written as:

P(x) = [tex]ax^2 + bx - a - b = a(x^2 - 1) + b(x - 1).[/tex]

Thus, the set [tex]{x^2 - 1, x - 1[/tex]} spans W. To check linear independence, we set up the equation:

[tex]a(x^2 - 1) + b(x - 1)[/tex]= 0.

This gives us two equations:

a = 0 and b = 0.

Thus, the set[tex]{x^2 - 1, x - 1}[/tex] is linearly independent, and hence it is a basis for W.

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Here are three different sequences starting with 1, 2, and 4 respectively, where the terms are generated by a simple rule:

1) Sequence starting with 1: 1, 3, 5, 7, 9...
This sequence is generated by adding 2 to the previous term.

2) Sequence starting with 2: 2, 4, 8, 16, 32...
This sequence is generated by multiplying the previous term by 2.

3) Sequence starting with 4: 4, 7, 10, 13, 16...
This sequence is generated by adding 3 to the previous term.

Now, to suggest a closed formula for the sum of these sequences, we can use the formula for the sum of an arithmetic sequence:
S_n = n/2(2a + (n-1)d)

Where:
- S_n is the sum of the first n terms of the sequence
- a is the first term of the sequence
- d is the common difference between consecutive terms of the sequence
- n is the number of terms in the sequence

For the first sequence (1, 3, 5, 7, 9...), a=1 and d=2 (since we add 2 to the previous term to get the next term). If we want to find the sum of the first 10 terms of this sequence, we can plug in these values into the formula:

S_10 = 10/2(2(1) + (10-1)2)
S_10 = 10/2(2 + 18)
S_10 = 10/2(20)
S_10 = 100

Therefore, the sum of the first 10 terms of this sequence is 100.

You can use a similar method to find the sum of the other two sequences as well.

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To find dx/dt and dy/dt for the given curve with parametric equations y = Int and x = 4ts, we can use the chain rule of differentiation.

First, let's find dx/dt:

dx/dt = d/dt (4ts)

Using the product rule of differentiation, we get:

dx/dt = 4s + 4t(ds/dt)

However, we don't know what ds/dt is. But we do know that s = x/4t, so we can use the quotient rule of differentiation to find ds/dt:

ds/dt = d/dt (x/4t)

ds/dt = (4t(dx/dt) - x(4(dt/dt))) / (4t)^2

Simplifying this expression, we get:

ds/dt = (dx/dt)/t - x/(4t^2)

Substituting this back into the expression for dx/dt, we get:

dx/dt = 4s + 4t[(dx/dt)/t - x/(4t^2)]

Simplifying this expression, we get:

dx/dt = 4s - (x/t)

Next, let's find dy/dt:

dy/dt = d/dt(Int)

Since Int is a constant, its derivative with respect to t is 0. Therefore,

dy/dt = 0

In summary, we have found that:

dx/dt = 4s - (x/t)

dy/dt = 0

This means that the slope of the curve at any point is given by dx/dt, and that the curve is horizontal (i.e. dy/dt = 0) at every point.

Explaining this in 200 words:

To find the derivative of a curve with parametric equations, we use the chain rule of differentiation. By differentiating x and y with respect to t, we can express dx/dt and dy/dt in terms of s and t. In this particular example, we first found dx/dt using the product rule of differentiation. We then used the quotient rule to find ds/dt, which allowed us to substitute back into the expression for dx/dt. Finally, we found dy/dt by differentiating the constant Int with respect to t.

The resulting expressions for dx/dt and dy/dt tell us important information about the curve. The slope of the curve at any point is given by dx/dt, which we found to be 4s - (x/t). This means that the slope of the curve varies depending on the values of s and t. The curve is horizontal (i.e. dy/dt = 0) at every point, which means that it does not rise or fall as t changes. Overall, finding the derivatives of parametric curves allows us to better understand their behavior and properties.

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Answer:

x= 9 in

Step-by-step explanation:

Volume = L ×W ×h

153 in3 =2in ×8.5in × h

153 in3 = 17in2 ×h

h = 153 in3/17in2

h = 9 inch

so the height if the figure has 9in length

The only remainders that may result from modular division with a divisor of 3 are 0 and 1. Since the dividend must be divisible by 3, the only viable responses are 0 (if the remainder is 1), 1 (if the remaining is 1), or 2 (if the remainder is 2).

The residue when dividing is known as the modulo operation (abbreviated "mod" or "%" in several computer languages). For instance, "5 mod 3 = 2" indicates that 2 remains after multiplying 5 by 3. This kind of operator—the percentile operator—is identified by the symbol the%.

The modulus operator, which operates between two accessible operands, is an addition to the C arithmetic operators. To obtain a result, it divides the supplied numerator by the supplied denominator.

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The end of the stencil located at (9, 3).

We have,

The beginning of the left edge of the stencil falls at (1, −1).

She wants to align an important detail on the left edge of her stencil at

(3, 0).

Ratio = m:n = 1:3

Using section formula

3 = (x + 3)/4

x+3 = 12

x = 9

and, 0 = (y - 3)/4

y= 3

Thus, the end point are (9, 3).

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The probability of this going undetected during an 8-hour shift is 0.503, which is approximately 50%.

SDO stands for standard deviation of the observed sample proportion. It measures the variability in the proportion of parts that require additional work in the samples of 25.

To find the cutoff value for inspections, we need to first calculate the mean and standard deviation of X. Since the rate of parts requiring additional work is 12 in 1000, the probability of a part requiring additional work is p = 0.012. Therefore, the mean of X is np = 25 x 0.012 = 0.3 and the standard deviation of X is sqrt(np(1-p)) = sqrt(25 x 0.012 x 0.988) = 0.546. The cutoff value is mean + 3*standard deviation = 0.3 + 3 x 0.546 = 1.938. Rounded up to the nearest integer, the cutoff value is 2.

When the punch is sufficiently sharp, X follows a binomial distribution with parameters n = 25 and p = 0.012. The probability that X exceeds the pre-set cutoff value of 2 is P(X > 2) = 1 - P(X <= 2) = 1 - (P(X = 0) + P(X = 1) + P(X = 2)) = 1 - (0.744 + 0.227 + 0.029) = 0.

If the punch is dull and the rate of parts requiring additional work increases to 5 in 100, the probability of a part requiring additional work is p = 0.05. When X follows a binomial distribution with parameters n = 25 and p = 0.05, the probability that X exceeds the cutoff value of 2 is P(X > 2) = 1 - P(X <= 2) = 1 - (P(X = 0) + P(X = 1) + P(X = 2)) = 1 - (0.374 + 0.382 + 0.188) = 0.056.

If the punch is dull and the rate of parts requiring additional work increases to 5 in 100, the probability of X exceeding the cutoff value during a single hour is 0.056. Therefore, the probability of this going undetected during an 8-hour shift is (1 - 0.056)^8 = 0.503, which is approximately 50%.

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Answer:

To find out how many faygos James can buy, we need to divide the total amount he has by the price of each Faygo.

Remember, if you don't know something you can always put an X in your equation because we're going to solve it anyways. We know that 10 Faygo's cost $22, so in order to find the price of 1 Faygo we have to divide $22/10 = $2.20.

Therefore, we can set up the equation:

$2.20x = $6.60

Simplifying (by putting x at the front of the equation), we get:

x = $6.60 / $2.20

x = 3

So James can buy 3 Faygo's for $6.60.:)

The new basis is x₂, x₄, and x₆, with a non-artificial cost of 3x₂ - M/2x₃ + M/2.

What is inequalities?

In mathematics, an inequality is a mathematical statement that indicates that two expressions are not equal. It is a statement that compares two values, usually using one of the following symbols: "<" (less than), ">" (greater than), "≤" (less than or equal to), or "≥" (greater than or equal to).

(a) Using the Big M method, we first rewrite the constraints in standard form by introducing slack variables x₄ and x₅ as follows:

x₁ - 2x₂ + x₃ + x₄ = 20

2x₁ + 4x₂ + x₃ + x₅ = 50

We then introduce artificial variables x₆ and x₇ to handle the inequalities in the first constraint as follows:

x₁ - 2x₂ + x₃ + x₄ - x₆ = 20

2x₁ + 4x₂ + x₃ + x₅ + x₇ = 50

We can now construct the initial simplex tableau as follows:

BV    x₁   x₂   x₃   x₄   x₅   x₆   x₇   RHS

x₄ 1 -2 1 1 0 0 0 20

x₅ 2 4 1 0 1 0 0 50

x₆ 1 -2 1 0 0 1 0 20

x₇ 2 4 1 0 0 0 1 50

Zj-Cj -M M -M 0 0 M M 0

where BV denotes the basic variables, RHS denotes the right-hand side coefficients, and Zj-Cj denotes the relative profits or costs. We set M to a large positive number (e.g., M=1000) to penalize the artificial variables. The initial artificial basic feasible solution is x₄ = 20, x₅ = 50, x₆ = 20, x₇ = 0, with an artificial cost of Mx₆ + Mx₇ = 2000.

The initial entering basic variable is x₂, which has the most negative relative profit of -M. To determine the leaving basic variable, we compute the minimum ratio test for each row:

x₁: 20/1 = 20

x₂: 50/4 = 12.5

x₆: 20/1 = 20

x₇: 50/4 = 12.5

The minimum ratio is 12.5 for x₂ and x₇, which means either of these variables can leave the basis. Since x₇ has a higher index, we choose it to leave the basis. To perform the pivot operation, we divide row 3 by 2 and subtract 2 times row 1 from it:

BV    x₁   x₂   x₃   x₄   x₅   x₆   x₇   RHS

x₄ 0 -2 0 -1 0 1 0 0

x₅ 0 8 0 2 1 0 0 50

x₂ 1 -2 1 0 0 0.5 -0.5 10

x₁ 0 8 -1 0 0 -0.5 0.5 10

Zj-Cj -M 3 -M/2 0 0 M/2 -M/2 2000

The new basis is x₂, x₄, and x₆, with a non-artificial cost of 3x₂ - M/2x₃ + M/2.

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Amani would need to pay $66.15 for the scooter with the discount and sales tax included.

If the regular price of the scooter is $70, and it is on sale for 10% off, the sale price would be:

Sale price = Regular price - 10% of Regular price

Sale price = $70 - 0.1*$70

Sale price = $63

So the sale price of the scooter is $63.

Next, we need to add the 5% sales tax to the sale price to get the total price of the scooter. To do this, we can calculate the amount of sales tax as:

Sales tax = 5% of the Sale price

Sales tax = 0.05*$63

Sales tax = $3.15

Therefore, the total price of the scooter, including the 10% discount and 5% sales tax, would be:

Total price = Sale price + Sales tax

Total price = $63 + $3.15

Total price = $66.15

So Amani would need to pay $66.15 for the scooter with the discount and sales tax included.

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When reporting the results of a one sample t test with 24 participants and a t-value of .92 that is not statistically significant, it is important to state that the sample did not provide sufficient evidence to reject the null hypothesis.

This means that there was not enough evidence to support the claim that the sample mean is significantly different from the population mean. Therefore, it is necessary to accept the null hypothesis. It is also important to report the level of significance used in the study, as well as the degrees of freedom. For example, if the level of significance was set at .05, and the degrees of freedom were 23, the results could be reported as follows: "The results of the one sample t test revealed that there was not a significant difference between the sample mean and the population mean (t(23) = .92, p > .05).

Therefore, the null hypothesis is accepted." Overall, it is important to be transparent in reporting the results of any statistical test and to provide enough information to allow others to replicate the study or understand the results.

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The slope of any line parallel to the given line is also 9.

The slope of any line perpendicular to the given line is -1/9.

We have,

The given line is y = 9x - 6

This is in the form of y = mx + c.

So,

The slope of the line is 9.

Now,

Parallel lines have the same slope,

So the slope of any line parallel to the given line is also 9.

Perpendicular lines have negative reciprocal slopes,

So the slope of any line perpendicular to the given line is -1/9.

Thus,

The slope of any line parallel to the given line is also 9.

The slope of any line perpendicular to the given line is -1/9.

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Answer: So greatest to least would be 0.4,    0.34,   1/4   21%,  and 3/100 for the least

Step-by-step explanation:

1/4=0.25

0.4=0.40

21%=0.21

0.34=0.34

3/100=0.03

The probability of event C given that event A did not occur is 4/52 ÷ 1/36 = 27/52.

a. There are 52 possible outcomes for drawing one card and 6 x 6 = 36 possible outcomes for rolling 2 dice, so the total number of possible outcomes is 52 x 36 = 1,872.

b. The probability of drawing a number greater than 6 is 10/52 (there are 16 cards that meet this criteria: 4 Kings, 4 Queens, and 8 Jacks).

c. The probability of rolling a 7 with two dice is 6/36 or 1/6.

d. Since A and B are independent events, we can multiply their probabilities to find the probability of both events occurring: P(A and B) = P(A) x P(B) = (10/52) x (1/6) = 5/156.

e. To find P(A or C), we add the probabilities of the two events and then subtract the probability of their intersection, since drawing a Queen also satisfies the condition of event A: P(A or C) = P(A) + P(C) - P(A and C) = (10/52) + (4/52) - (1/52) = 13/52 = 1/4.

f. A and B are independent events, since drawing a card has no effect on the probability of rolling two dice.

g. A and C are dependent events, since drawing a Queen affects the probability of drawing a number greater than 6.

h. If event A does not occur, it means that a card less than or equal to 6 was drawn. Since there are 36 possible outcomes for rolling 2 dice and only 1 of them results in a 7, the probability of event B occurring is 1/36. Given that event A did not occur, the probability of event C is simply the probability of drawing a Queen, which is 4/52. Therefore, the probability of event C given that event A did not occur is 4/52 ÷ 1/36 = 27/52.

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Answer:

The answer is actually 2.

C= 2cm.

By using the given transformation rule and graph, the coordinates for the red triangle include the following:

Red Vertex Names                Red Triangle Vertices

A'                                                      (5, 2)

B'                                                      (3, 5)

C'                                                      (1, 4)

In Geometry, a reflection over or across the y-axis or line x = 0 is represented and modeled by this transformation rule (x, y) → (-x, y).

By applying a reflection over the y-axis to the coordinate of the given triangle ABC, we have the following coordinates:

(x, y)                             →                 (-x, y).

Coordinate A = (-5, 2)   →  Coordinate A' = (-(-5), 2) = (5, 2).

Coordinate B = (-3, 5)   →  Coordinate B' = (-(-3), 5) = (3, 5).

Coordinate C = (-1, 4)   →  Coordinate C' = (-(-1), 4) = (1, 4).

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The amount we will have after to be paid $13,177.97

We have,

P = $ 8100

R= 7.2%

T= 7 year

r = R/100

r = 7.2/100

r = 0.072 rate per year,

Then solve the equation for A

A = P(1 + r/n[tex])^{nt[/tex]

A = 8,100.00(1 + 0.072/1[tex])^{(1)(7)[/tex]

A = 8,100.00(1 + 0.072)⁷

A = $13,177.97

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Answer:

[tex]\frac{2A}{b} = h[/tex]

Step-by-step explanation:

[tex]A = \frac{1}{2}bh[/tex]

1. Multiply both sides by 2 to cancel out the 1/2 from the right side.

[tex]2A = bh[/tex]

2. Divide both sides by B so it cancels out the B on the right side.

[tex]\frac{2A}{b} = h[/tex]

The option that will give the smallest value for dx for a given 3 number of intervals is C. A midpoint Riemann sum approximation.

This is because the midpoint Riemann sum often provides a more accurate approximation of the definite integral compared to left-hand or right-hand Riemann sums and trapezoid approximations. The trapezoid approximation will give the smallest value for dx for a given number of intervals compared to the actual value of the definite integral, a midpoint Riemann sum approximation, a left-hand Riemann sum approximation, and a right-hand Riemann sum approximation. This is because the trapezoid rule takes into account the average of the heights of the left and right endpoints of each interval, resulting in a more accurate approximation than the other methods.

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The equation x² + 2x + __ = (__)² should be completed by the following:

D. 1; x + 1.

x² + 2x + 1 = (x + 1)²

In Mathematics and Geometry, the general form of a quadratic function can be modeled and represented by using the following quadratic equation;

y = ax² + bx + c

Where:

In order to complete the square, we would have to add (half the coefficient of the x-term)² to both sides of the quadratic equation as follows:

x² + 2x + (2/2)² = (2/2)²

x² + 2x + (1)² = (1)²

x² + 2x + 1 = (x + 1)²

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Q1 = 44000 + (-0.6745) * 12166 = 36753 (rounded to the nearest whole number)

a. The distribution of X is normal with mean 44,000 and standard deviation 12,166.

b. Let Z be the standard normal variable. Then,

Z = (57239 - 44000) / 12166 = 1.0933

Using a standard normal table or calculator, we find that P(Z < 1.0933) = 0.8628. Therefore, the probability that a randomly selected acre in the forest has fewer than 57,239 ants is 0.8628.

c. Let Z1 and Z2 be the standard normal variables corresponding to 44,753 and 59,087, respectively. Then,

Z1 = (44753 - 44000) / 12166 = 0.0611

Z2 = (59087 - 44000) / 12166 = 1.2463

Using a standard normal table or calculator, we find that P(0.0611 < Z < 1.2463) = 0.3653. Therefore, the probability that a randomly selected acre has between 44,753 and 59,087 ants is 0.3653.

d. The first quartile corresponds to the cumulative probability of 0.25 in a standard normal distribution. Using a standard normal table or calculator, we find that the Z-score corresponding to a cumulative probability of 0.25 is approximately -0.6745. Therefore, the first quartile of the distribution of ants per acre in the forest is:

Q1 = 44000 + (-0.6745) * 12166 = 36753 (rounded to the nearest whole number)

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