Answer:
The vertical shift is of 2 units up
Step-by-step explanation:
We have a function in the following format:
F(x) = a(x+b) + c
The vertical shift is given by c.
If c > 0, the shift is up.
If c < 0, the shift is down.
In this question:
F(x) = 9|x+1| + 2
So c = 2
The vertical shift is of 2 units up
For each of the following scenarios state the domain (starting set) show and state the mapping, and decide if it is a function. Be sure to label your set and indicate the direction of the relation.
Domain: Number of pages
Range:Number of books
Mapping: Number of pages to the number of books.
Explaination: The number of pages is the independent variable and the number of books is the dependent variable.
The given mapping is a function as total number of pages can not have more than two output (number of books).
a scientist need to 6000 calories per day. Based on the percentage of total daily calories and the number of calories needed, how many biscuits, packages of pemmican, butter and coco does a person need each day?
EXPLANATION:
Given;
We are told that a scientist needs 6000 calories per day.
We are also given a table showing the percentage of daily calories he can get from three types of food.
These are;
[tex]\begin{gathered} Biscuits---40\% \\ pemmican---45\% \\ Butter\text{ }and\text{ }cocoa---15\% \end{gathered}[/tex]Required;
We are required to calculate how many of each type of food he would need to eat each day.
Step-by-step solution;
We shall solve this by first determining how many calories can be gotten from each type of food based on the percentage given. This is calculated below;
[tex]\begin{gathered} Biscuits: \\ 6000\times\frac{40}{100}=2400 \end{gathered}[/tex]This means if he gets 75 calories from one biscuit, then to get 2,400 calories he would have to eat;
[tex]\begin{gathered} 75cal=1b \\ 2400cal=\frac{2400}{75} \\ 2400cal=32 \end{gathered}[/tex]The scientist would have to eat 32 biscuits to get 2400 calories.
[tex]\begin{gathered} Pemmican: \\ 6000\times\frac{45}{100}=2700 \end{gathered}[/tex]This means if he gets 135 calories from one pack of dried meat, then to get 2700 calories he would have to consume;
[tex]\begin{gathered} 135cal=1pack \\ 2700cal=\frac{2700}{135} \\ 2700cal=20 \end{gathered}[/tex]Therefore, the scientist would have to eat 20 packs of pemmican to get 2700 calories
[tex]\begin{gathered} Butter\text{ }and\text{ }Cocoa: \\ 6000\times\frac{15}{100}=900 \end{gathered}[/tex]This means if he eats 1 package of Butter and cocoa he gets 225 calories. To get 900 calories he would have to eat;
[tex]\begin{gathered} 225cal=1pack \\ 900cal=\frac{900}{225} \\ 900cal=4 \end{gathered}[/tex]Therefore, the scientist would have to eat 4 packs of Butter and cocoa.
We now have the summary as follows;
ANSWER:
[tex]\begin{gathered} Biscuits=32 \\ Pemmican=20\text{ }packs \\ Butter\text{ }and\text{ }cocoa=4\text{ }packs \end{gathered}[/tex]Nicole wants to use his 18% employee discount to buy a video game that is priced at $69.99. A 6.5% sales tax is applied to the discounted price. What will be the total cost of the video game, including the sales tax?
Given:
The discount rate, D=18%.
The mared price, M=$69.99.
The sales tax percentage on discounted price, s=6.5%.
The discounted price is,
[tex]\begin{gathered} C=\frac{(100-D)}{100}\times M \\ C=\frac{100-18}{100}\times69.99 \\ C=57.39 \end{gathered}[/tex]The sales tax on the discounted price is,
[tex]\begin{gathered} S=\frac{s}{100}\times C \\ S=\frac{6.5}{100}\times57.39 \\ S=3.73 \end{gathered}[/tex]The total cost of the video game including the sales tax is,
[tex]\begin{gathered} T=C+S \\ T=57.39+3.73 \\ T=61.12 \end{gathered}[/tex]Therefore, the total cost of the video game including the sales tax is $61.12.
The table of values represents a quadratic function.What is the average rate of change for f(x) from x=−10 to x = 0?Please help me with this problem so that my son can understand better. Enter your answer in the box.xf(x)−10184−5390−654910204
We are given a quadratic function and the rather than the equation for this function we already have the outputs at each given input as shown in the table provided. This means, for example, for the function given, when the input is -10, the output is 184. Thus the table includes among other values;
[tex]x=-10|f(x)=184[/tex]To calculate the average rate of change we shall apply the formula for the slope (which is also the average rate of change). This is given below;
[tex]\text{Aerage Rate of Change}=\frac{f(b)-f(a)}{b-a}[/tex]Note that the variables are;
[tex]\begin{gathered} f(a)=\text{first input value} \\ f(b)=\text{second input value} \end{gathered}[/tex]The first input value is -10 and the function at that value is 184
The second input value is 0 and the function at that value is -6
We now have;
[tex]\begin{gathered} a=-10,f(a)=184 \\ b=0,f(b)=-6 \end{gathered}[/tex]We can now substitute these into the formula shown nearlier and we'll have;
[tex]\begin{gathered} \text{Ave Rate Of Change}=\frac{f(b)-f(a)}{b-a} \\ =\frac{-6-184}{0-\lbrack-10\rbrack} \end{gathered}[/tex][tex]\begin{gathered} =\frac{-190}{0+10} \\ \end{gathered}[/tex][tex]=\frac{-190}{10}[/tex][tex]\text{Average Rate of Change}=-19[/tex]ANSWER:
The average rate of change over the given interval is -19
what is the simplified ratio of 32:24
Answer:
4/3
Step-by-step explanation:
The simplest form of
32: 24
is 43
Steps to simplifying fractions
Find the GCD (or HCF) of numerator and denominator
GCD of 32 and 24 is 8
Divide both the numerator and denominator by the GCD
32 ÷ 8
24 ÷ 8
Reduced fraction:
4/3
Therefore, 32/24 simplified to lowest terms is 4/3.
For lunch, Kile can eat a sandwich with either ham or a bologna and with or without cheese. Kile also has the choice of drinking water or juice with his sandwich. The total number of lunches Kile can choose isA. 12B. 8C. 4D. 6
Okay, here we have this:
She can eat the following options:
Sandwich with ham with or without cheese. Two choices.
Sandwich with bologna with or without cheese. Other two choices
This mean that she can eat:
Sandwich with ham with cheese with water or juice. Two options.
Sandwich with ham without cheese with water or juice. Two options.
Sandwich with bologna with cheese with water or juice. Two options.
Sandwich with bologna without cheese with water or juice. Two options.
Finally we obtain a total of: 2+2+2+2=8 options of lunches.
Thw
What’s the correct answer answer asap for brainlist
Answer:
Answer is B. Harding, Coolidge, and Hoover
:)
The deposits Ginny makes at her bank each month form an arithmetic sequence. The deposit for month 3 is $150, and the deposit for month 5 is %180. Answer the questions below and show all work.1. What is the common difference for the deposits made each month?2. Write an explicit formula for this arithmetic sequence. 3. What is the amount of Ginny's deposit in the 12th month?4. At what month will Ginny first make a deposit that is at least $500?
SOLUTION
The deposits Ginny makes at her bank each month form an arithmetic sequence. The deposit for month 3 is $150, and the deposit for month 5 is $ 180.
Since it follows an arithmetic sequence, T n = a + ( n- 1 ) d
Month 3 , T 3 = a+ ( 3 - 1 ) d = 150
a + 2 d = 150 --------------------- equ 1
Month 5 , T 5 = a + ( 5 - 1 ) d = 180
a + 4 d = 180 ...........................equ 2
Solving the two equations, we have :
a - a + 4 d - 2 d = 180 - 150
2 d = 30
Divide both sides by 2 , we have:
d = 15
Let us put d = 15 in equ 1 , we have a + 2 d = 150
a + 2 ( 15 ) = 150
a + 30 = 150
a = 150 - 30
a = 120
From the solution,
Month 1 = 120
Month 2 = 120 + 15 = 135
Month 3 = 135 + 15 = 150
Month 4 = 150 + 15 = 165
Month 5 = 165 + 15 = 180
1. What is the common difference for the deposits made each month? d = 15
2. Write an explicit formula for this arithmetic sequence.
Recall that Tn = a + ( n - 1 ) d
Tn = 120 + ( n - 1 ) 15
Tn = 120 + 15 n - 15
Tn = 120 - 15 + 5n
Tn = 105 + 15n
3. What is the amount of Ginny's deposit in the 12th month?
Tn = 105 + 15n
T 12 = 105 + 15 ( 12 )
T 12 = 105 + 180 = 285
4. At what month will Ginny first make a deposit that is at least $500?
Using Tn = 105 + 15 n = 500
105 + 15 n = 500
15 n = 500 - 105
15 n = 395
Divide both sides by 15 , we have :
n = 26 . 33
n = 27
For the data values 69, 54, 27, 43, 69, 56, the mean is 53.
From the table given,
To find the x - mean,
By the summation of all the x - mean
The value of x - mean is
[tex]x-\operatorname{mean}=16+1-26-10+16=-3[/tex]Hence, the value of x - mean is -3
To find the (x - mean)²
By the summation of all the values of (x - mean)²
The value of (x - mean)² is
[tex](x-\operatorname{mean})^2=256+1+676+100+256=1289[/tex]Hence, the value of (x - mean)² is 1289
Solve for basic equation x2x+3=-3x-12
Solution
We have the following equation:
2x +3 = -3x-12
We can solve for x on this way:
5x = -12-3
5x = -15
Dividing both sides by 5 we got:
x= -3
I know this is something super easy, but I always forget the steps on how to figure this out, I tried to put 30 and number one spot, I tried putting 82 and number two spot, and I tried putting 50 and number one spot but when you add that up that's a lot more than 360. I just need help please
Anlge directly opposite to 2= 180 - 82= 98
Sum of angles in the triangle (98, 50, x ) = 180
98+50+x = 180
x + 148 = 180
x = 180 - 148= 32
m<1 = x because they are alternate
so m<1 = 32
m<2 + 82 = 180 ( sum of angles in a straight line)
m<2 = 180 - 82 = 98
m< 3 = 50 because they are alternate
Or
m<3 + m<2 + m<1 = 180 ( sum of angles in a triangle)
m< 3 + 98+ 32 = 180
m<3 =180 - 130 =50
Summary
m< 1= 32 degrees
m<2= 98 degrees
m<3 = 50 degrees
100 Points.
A rectangle has sides measuring (2x + 5) units and (3x + 7) units.
Part A: What is the expression that represents the area of the rectangle? Show your work.
Part B: What are the degrees and classifications of the expression obtained in Part A?
Part C: How does Part A demonstrate the closure property for the multiplication of polynomials?
The expression that represents the area of the rectangle is [tex]6x^{2}[/tex]+29x + 35 square units , the degree of the obtained expression is 2.
According to the question,
We have the following information:
A rectangle has sides measuring (2x + 5) units and (3x + 7) units.
A) We know that following formula is used to find the area of rectangle:
Area = length*breadth
Area = (3x+7)(2x+5)
Area = [tex]6x^{2}[/tex] + 15x +14x + 35
Area = [tex]6x^{2}[/tex] +29x + 35 square units
B) The degree of an expression is the highest power of the expression. In this case, the highest power is 2. Hence, the degree of the expression obtained is 2.The expression can be classifies as a quadratic polynomial.
C) Part A demonstrates the closure property for the multiplication of polynomials because the expression within the brackets are polynomials and the result obtained is also a polynomial.
Hence, the area of the rectangle is [tex]6x^{2}[/tex] +29x + 35 square units and the degree of the obtained expression is 2.
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Rewrite the following expression so it does not contain any radical term
Given:
The expression is given as,
[tex]\sqrt[]{36p^{10}m^6}[/tex]The objective is to rewrite the expression without any radical form.
Explanation:
The given expression can be written as,
[tex]\sqrt[]{36p^{10}m^6}=\sqrt[]{6^2p^{10}m^6}\text{ . . . . .(1)}[/tex]In general, the radical form of a square root can be written as,
[tex]\sqrt[]{x}=x^{\frac{1}{2}}[/tex]Then, the equation (1) can be written as
[tex]\sqrt[]{36p^{10}m^6}=(6^2p^{10}m^6)^{\frac{1}{2}}[/tex]On further solving the above expression,
[tex]\begin{gathered} \sqrt[]{36p^{10}m^6}=6^{2\times\frac{1}{2}}p^{10\times\frac{1}{2}}m^{6\times\frac{1}{2}} \\ =6p^5m^3 \end{gathered}[/tex]Hence, the simplified expression of the given term is,
[tex]6p^5m^3[/tex]what is the area of the Shaded region used 3.14
In this problem, the area of the shaded region is equal to the area of the complete square, minus the area of the four circles
so
REmember that
The length side of the complete square is equal to two times the diameter of one circle
A=(2*12)^2-4*pi*(12/2)^2
assume pi=3.14
A=576-4(3.14)(36)
the area of the Shaded region is A=123.84 ft^215. Given f (n)=3( 12), what is the value off (8) ?
We have some function f(x) and want to evaluate the function for some value of x, in this case for x=8.
Evaluate a function means replace the x for the value you want to evaluate, in this case for 8, so:
[tex]\begin{gathered} f(x)=3(1-x) \\ f(8)=f(x=8)=3(1-8) \\ f(8)=3\cdot(-7)=-21 \end{gathered}[/tex]used to name a point
Answer:
It is represented by a dot and named by a capital letter
Step-by-step explanation:
The entire graph of the function h is shown in the figure below.
Write the domain and range of h using interval notation.
(a) domain=
(b) range =
The Domain is [-2, 5] and Range is [3, -4]
What is Domain and range ?
The domain and range are defined for a relation and they are the sets of all the x-coordinates and all the y-coordinates of ordered pairs respectively.
a.) Here in graph, see the x-axis for to find Domain
You'll notice that -2 is point where the point is marked as lowest after that there is no line or point is there and the highest it goes up to the blue line is reached is 5 in x-axis.
so, the Domain is [-2, 5]
b.) For the range you to look at y-axis, just observe the highest and lowest point in graph you'll be able to find range.
hence, the Range is [3, -4]
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For each level of confidence o below, determine the corresponding normal confidence interval. Assume each confidence interval is constructed for the same sample statistics.Drag each normal confidence interval given above to the level of confidence
Note that the width of the confidence interval increases as the confidence level increases.
Since the confidence intervals constructed are for the same sample statistic, the higher confidence interval will have a higher width.
The confidence levels have the following widths:
Therefore, the confidence intervals are matched such that the lowest interval has the smallest confidence level and the highest has the largest confidence level. This is shown below:
a cyclist rides her bike at a speed of 30 kilometers per hour. what is the speed in miles per hour? how many miles will the cyclist travel in 5 hours?
Answer:
the answer is 9.321 miles
Which vehicle has the smallest total volume?What is the volume?
The formula for the volume is,
[tex]V=\text{length}\cdot\text{ width}\cdot\text{ height}[/tex]Determine the volume of Van.
[tex]\begin{gathered} V=10\cdot6\frac{1}{2}\cdot6 \\ =60\cdot\frac{13}{2} \\ =390 \end{gathered}[/tex]Determine the volume of small truck.
[tex]\begin{gathered} V_1=11.3\cdot7.5\cdot6.75 \\ =572.0625 \end{gathered}[/tex]Determine the volume of 2-bedroom moving truck.
[tex]\begin{gathered} V=14\frac{1}{2}\cdot\frac{77}{12}\cdot7\frac{1}{6} \\ =\frac{29}{2}\cdot\frac{77}{12}\cdot\frac{43}{6} \\ =666.798 \end{gathered}[/tex]Determine the volume of 3 bedroom truck.
[tex]\begin{gathered} V=20.5\cdot7.7\cdot8.5 \\ =1341.725 \end{gathered}[/tex]Determine the mega moving truck.
[tex]\begin{gathered} V=22\frac{1}{4}\cdot7\cdot9\frac{1}{3} \\ =1453.666 \end{gathered}[/tex]The smallest volume is equal to
Ms wash investdd $22000 in two accounts, one yielding 8% interest and the other yielding 11%. if she recieved a total of $1910 in interest at the end of the year, how much did she invest in each accouny
Take into account the following formula for the simple interest:
[tex]I=P\cdot r\cdot t[/tex]where:
P: principal investment
r: interest rate
t: time
In order to determine the investments for both accounts, proceed as follow:
-Consider that both investments are represented by P1 and P2 respectively, then, you have:
[tex]\begin{gathered} P_1+P_2=22000 \\ P_2=22000-P_1 \end{gathered}[/tex]- Next, use the given values for parameters r and t for each investment:
8% = 0.08
11% = 0.11
t = 1 year
[tex]\begin{gathered} I_1=P_1\cdot0.08\cdot1=0.08P_1 \\ I_2=P_2\cdot0.11\cdot1=0.11P_2 \end{gathered}[/tex]- Next, consider that the sum of the total earnings is $1910, then:
[tex]I_1+I_2=1910[/tex]- Replace I1 and I2 by the expressions in terms of P1 and P2 and write down the resultant expression in terms of P1, as follow:
[tex]\begin{gathered} 0.08P_1+0.11P_2=1910 \\ 0.08P_1+0.11(22000-P_1)=1910 \\ 0.08P_1+2420-0.11P_1=1910 \\ -0.03P_1=-510 \\ P_1=\frac{510}{0.03}=17000 \end{gathered}[/tex]And for P2:
[tex]\begin{gathered} P_2=22000-P_1 \\ P_2=22000-17000=5000 \end{gathered}[/tex]Hence, the amount of money invested in each account was $5000 and $17000
=
A ball is thrown from a height of 156 feet with an initial downward velocity of 8 ft/s. The ball's height h (in feet) after t seconds is given by the following.
h=156-81-161²
How long after the ball is thrown does it hit the ground?
Round your answer(s) to the nearest hundredth.
The time taken by the ball to hit the ground is 2.88 sec.
What is termed as the distance?Distance is defined as an object's total movement without regard for direction. Distance can be defined as how much surface an object has covered regardless of its starting or closing point.For the given question,
The total height from which the ball is thrown is 156 feet.
Let 'h' be the height after the time 't' sec.
The equation for the relation of the height and the times is;
h = 156 - 8t - 16t²
The initial velocity of the ball is 8 ft/s. .
When the ball hit the ground the height will become zero.
156 - 8t - 16t² = 0.
Divide the equation by -4.
4t² + 2t - 34 = 0
Solve the quadratic equation using the quadratic formula to find the time.
t = 2.88 sec.
Thus, the time taken by the ball to hit the ground is 2.88 sec.
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The correct question is-
A ball is thrown from a height of 156 feet with an initial downward velocity of 8 ft/s . The ball's height h (in feet) after t seconds is given by the following. h=156-8t-16t²
How long after the ball is thrown does it hit the ground?
Round your answer(s) to the nearest hundredth.
Given the zeros of the following polynomial 2 +2i, 3, - 4 select the corresponding factors AND the polynomia O (x + 2i) (2 - 2i) (2 - 3)(x+4) o f(c) = 24 - 23 822 - 42 - 48 0 (2 – 2i) (x + 2i) (2+3)(– 4) 24 – 13 + 82 40 - 48 0 (0 - 2) (+2)(x - 3)(x +4) 24 - 23 - 822 + 4x + 48 1 3 N
a)
d)
1) Since the zeros of that polynomial were given, then we can write it into the factored form. Note that there are 4 zeros, so we can write:
[tex]\begin{gathered} (x-x_1)(x-x_2)(x-x_3)(x-x_4)=0 \\ (x-(-2i))(x-2i)(x-3)(x-(-4))=0 \\ (x+2i))(x-2i)(x-3)(x+4))=0 \end{gathered}[/tex]2) To find out the corresponding polynomial then we can expand it by rewriting "i" as -1
[tex]\begin{gathered} (x+2i))(x-2i)(x-3)(x+4) \\ (x+2i)(x-2i)=x^2+4 \\ (x-3)(x+4)=x^2+4x-3x-12 \\ (x^2+4)(x^2+x-12) \\ x^4+x^3-8x^2+4x-48 \end{gathered}[/tex]3) Hence, the answers are
a)
d)
[tex]x^4+x^3-8x^2+4x-48[/tex]Convert 145 to base 4
Answer:
Converting 145 to base 4 will give;
[tex]2101_4[/tex]Explanation:
We want to convert;
[tex]145_{ten}\text{ to base 4}[/tex]Converting, we have;
[tex]\begin{gathered} 145\text{ }\div\text{ 4 } \\ 36\text{ }\div\text{ 4 R 1} \\ 9\text{ }\div\text{ 4 R 0} \\ 2\text{ }\div\text{ 4 R 1} \\ 0\text{ R 2} \end{gathered}[/tex]Therefore, converting 145 to base 4 will give;
[tex]2101_4[/tex]A family of four went to an amusement park for their vacation. They started the vacation with $426.They spent a total of $198 the first three days.If they divided the remainder of the money evenly between the family members for souvenirs, how much did each person have to spend?
They started the vacation with $426
After spending $198 the first three days, the remainder is $426 - $198 = $228
Given that there are 4 family members, we have to divide this remainder by 4, that is, $228/4 = $57
Each person has $57 to spend
The following statements "If you are wearing a helmet, you are riding a bike." and "If you are not riding a bike, you are not wearing a helmet." are an example of a _____ statement.Select one:a.inverseb.conversec.contrapositive
Given:
The given statements are,
"If you are wearing a helmet, you are riding a bike."
"If you are not riding a bike, you are not wearing a helmet."
Required:
To identify the kind of statements.
Explanation:
We have the given statement:
"If you are wearing a helmet, you are riding a bike."
Here, p : you are wearing a helmet
q : you are riding a bike
Thus, taking negation of both the parts of the statement as follows:
If not q, then not p.
Hence, the statement formed is,
"If you are not riding a bike, you are not wearing a helmet."
This is the contrapositive statement.
Final Answer:
Given statements are an example of contrapositive.
1. A coat at the Utopian Coat factory cost $99.99. The sales tax is 7%. Find the sales tax and the total cost of the jacket. (Round to the nearest cent).
The Solution:
Given that a coat costs $99.99 and the sales tax is $75.
We are required to find the actual sales tax and the total cost of the coat.
Step 1:
We shall find the sales tax.
[tex]\begin{gathered} \text{ Cost of the coat=\$99.99} \\ \\ \text{Sales tax of 7\% }=\frac{7}{100}\times99.99=0.07\times99.99 \\ \\ =6.999\approx\text{ \$7.00 (or 700 cent)} \end{gathered}[/tex]Thus, the sales tax is $7.00 or 700 cents.
Step 2:
We shall find the total cost of the coat.
The total cost of the coat is the sum of the coat's cost and the sales tax.
[tex]\text{ The total cost=99.99+6.999=106.989}\approx\text{ \$106.99}[/tex]Therefore, the correct answers are:
Sales tax =$7.00 or 700 cents.
Total cost = $106.99 or 10699 cents..99 or 10699 cents.
what is P(x) = 2x^3 + 5x^2 + 5x + 6 as a product of two factors.
So we have to write the following polynomial expression as a product of two factors:
[tex]P(x)=2x^3+5x^2+5x+6[/tex]In order to do this we should find one of its roots first i.e. a x value that makes P(x)=0. If we use r to label this root we can write P like:
[tex]P(x)=(x-r)\cdot(ax^2+bx+c)[/tex]Where a, b and c are numbers that we can find using Ruffini's rule. So first of all let's find a root. We can use the rational root theorem. It states that if P(x) has rational roots then they are given by the quotient between a factor of the constant term (i.e. the number not multplied by powers of x) and a factor of the leading coefficient (i.e. the number multiplying the biggest power of x). In this case we have to look for the factors of 6 and 2 respectively. Their factors are:
[tex]\begin{gathered} 6\colon6,-6,3,-3,2,-2,1,-1 \\ 2\colon2,-2,1,-1 \end{gathered}[/tex]And the quotients and possible values for r are:
[tex]6,-6,3,-3,2,-2,\frac{3}{2},-\frac{3}{2},1,-1,\frac{1}{2},-\frac{1}{2}[/tex]So one of these numbers make P(x) equal to zero. For example if we take x=-2 we get:
[tex]\begin{gathered} P(-2)=2\cdot(-2)^3+5\cdot(-2)^2+5\cdot(-2)+6 \\ P(-2)=-16+20-10+6=0 \end{gathered}[/tex]So -2 is a root of P(x) which means that we can take r=-2.
Now we can use Ruffini's law. On the first row we write the coefficients of P(x). Then the first one is repeated in the third row:
Now we multiply 2 by -2 and we write the result under the second coefficient. Then we add them:
Now we do the same with the 1:
And then we multiply 3 and -2 and add the result ot the last coefficient:
The numbers 2, 1 and 3 are the values of a,b and c respectively. Then we can write P(x) as a product of two factors and the answer is:
[tex]P(x)=(x+2)(2x^2+x+3)[/tex]how much would EZ Excavation charge to haul 40 cubic yards of dirt
Given the line on the graph, we have that it passes through the points (1,25) and (2,50), then we can find the relation function with the slope-point equation of the line:
[tex]\begin{gathered} \text{slope:} \\ m=\frac{y_2-y_1}{x_2-x_1} \\ \Rightarrow m=\frac{50-25}{2-1}=\frac{25}{1}=25 \\ y-y_1=m(x-x_1) \\ \Rightarrow y-25=25(x-1) \\ \Rightarrow y=25x-25+25=25x \\ y=25x \end{gathered}[/tex]we have that the cost of the dirt is given by the equation y=25. To find how much would it be for 40 cubic yards of dirt, we make x=40 and we get the following:
[tex]\begin{gathered} x=40 \\ \Rightarrow y=25\cdot40=1000 \\ y=1000 \end{gathered}[/tex]therefore, the cost to haul 40 cubic yards of dirt is $1000
The nutrition label on Erin's box of animal crackers states that 16 crackers contain 24 grams of carbohydrates. Erin ate 12 animal crackers from the box. What is the number of grams of carbohydrates in 12 animal crackers? A.8 grams B. 12 grams C. 18 gramsD. 20 grams
16 crackers are proportional to 24 grams of carbohydrates. To find the number of grams of carbohydrates in 12 animal crackers, we can use the next proportion:
[tex]\frac{16\text{ crackers}}{12\text{ crackers}}=\frac{24\text{ grams}}{x\text{ grams}}[/tex]Solving for x,
[tex]\begin{gathered} 16\cdot x=24\cdot12 \\ x=\frac{288}{16} \\ x=18\text{ grams} \end{gathered}[/tex]