4. O -1 points 15 HW 080 Ask Your The sky Train from the terminal to the Cental car and long-term parking center is supposed to arrive every 6 minutes. The waiting times for the train are known to follow a uniform distrbution Find the 60th percentile for the waiting times (in minutes). Additional Qa Section 5.1

When researching a population where it is impossible or impractical to compile a list of the elements, the sampling technique that is appropriate to use is known as the cluster sampling technique

Cluster sampling is a type of probability sampling that is frequently used when the population is too large to be measured as a whole. The population is divided into smaller, more manageable clusters that are less difficult to study than the entire population.Therefore, cluster sampling is an excellent alternative when the target population cannot be measured because it is too large, too vast, or too hard to reach. In this technique, clusters are chosen by a random process or some other procedure.The final sampling method is achieved by selecting samples from within the clusters, which are frequently chosen using simple random sampling or some other appropriate method. When it comes to cluster sampling, it's important to remember that the clusters chosen must be heterogeneous internally but homogeneous externally.

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Answer: 75 [tex]m^{2}[/tex]

Step-by-step explanation:

5*5 + 5*10 = 25 + 50 = 75

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The mass of dog having weight as 19 kg has its mass in grams as 1.9 x 10⁴ grams, option C.

In physics, mass is a quantitative measurement of inertia, a basic characteristic of all matter. It essentially refers to a body of matter's resistance to changing its speed or location in response to the application of a force. The change caused by an applied force is smaller the more mass a body has.

Measuring units to determine the size, weight, or quantity of any object. Seven fundamental measurement units are utilized in daily life and across the globe.

A dog has a mass of 19 kg

The mass of the dog in grams is:

1 kilogram = 1000 grams

19.5 kg × (10³ g/1 kg) = 1.95 × 10⁴ g.

Thus, the mass of the dog in grams is 1.95 × 10⁴ g.

1000 grammes make to 1 kilogram (kg) (g).

1 kg = 1000 g

The mass m in kilogram (kg) multiplied by 1000 gives the mass m in grams (g)

m(g) = m(kg) × 1000.

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Answer:

1/12

Step-by-step explanation:

Out of the total number of candies, 1/2 of the pink candies are round.

To find the fraction of the candies that are pink and round, we need to multiply the fractions representing the proportion of pink candies and the proportion of round candies among the pink candies:

pink candies = 5/6

round candies among the pink ones = 1/5

Therefore, the fraction of candies that are pink and round is:

(5/6) x (1/2) x 1/5 = 1/12

So, 1/12 of the candies are pink and round.

The expression 2(10+12) can be rewritten as 44 using the distributive property of multiplication over addition.

The distributive property is a fundamental property of arithmetic that relates multiplication to addition and subtraction. The distributive property of multiplication over addition states that for any numbers a, b, and c

a( b + c ) = ab + ac

Using this property, we can rewrite the expression 2(10+12) as

2( 10 + 12 ) = 2(10) + 2(12)

Here, we have distributed the factor of 2 over the terms inside the parentheses, using the distributive property. This gives us:

2(10+12) = 20 + 24

Simplifying further, we get

2(10+12) = 44

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The model will be as follows: y = b0 + b1x1 + b2x2 + u

To write a model that allows the variance of u to differ between men and women, the best option is to use the heteroscedasticity model. This model will enable the variances to differ between the genders without depending on other factors.

The model will be as follows: y = b0 + b1x1 + b2x2 + u, Where y = dependent variable, b0 = constant or intercept, b1 and b2 are the coefficients for the independent variables x1 and x2, u = error term for the model. However, this model does not allow the variance of u to differ between men and women.

To achieve this, we need to modify the model to allow the variance of u to differ between men and women. This can be done by using the weighted regression model. The model will be as follows: y = b0 + b1x1 + b2x2 + u, where y = dependent variable, b0 = constant or intercept, b1 and b2 are the coefficients for the independent variables x1 and x2, u = error term for the model.

The weights can be represented as: wi = 1/σ^2i, where: wi = weight for observation, iσi = standard deviation of the ith observation. This model will allow the variance of u to differ between men and women without depending on other factors.

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The false statement regarding the normal distribution is given as follows:

99.72% of the time the random variable assumes a value within plus or minus 1 standard deviation of its mean.

The z-score of a measure X of a normally distributed variable that has mean represented by [tex]\mu[/tex] and standard deviation represented by [tex]\sigma[/tex] is obtained by the equation presented as follows:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The percentage of scores within 1 standard deviation of the mean is obtained considering that:

Hence the percentage is given as follows:

84.13 - 15.87 = 68.26%, which is different of 99.72%.

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The correct answer is that all of the following are characteristics of the normal probability distribution as given below.

A subfield of statistics known as probability studies random events and their likelihood of happening.

The statement "99.72% of the time the random variable assumes a value within plus or minus 1 standard deviation of its mean" is actually a characteristic of the normal probability distribution.

The correct answer is that all of the following are characteristics of the normal probability distribution:

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Answer:

y=6x-8

Step-by-step explanation:

The slope-intercept form of a line is y = mx + b, where m is the slope and b is the y-intercept. We are given the slope m = 6 and a point on the line (1,-2). We can use point-slope form to find the equation and then simplify it to slope-intercept form.

Point-slope form: y - y1 = m(x - x1)

Substitute the values of m, x1, and y1:

y - (-2) = 6(x - 1)

Simplify the right side:

y + 2 = 6x - 6

Subtract 2 from both sides:

y = 6x - 8

This is the equation of the line in slope-intercept form.

A. The equation of the line that passes through the point (4,3) and has a slope of -5/2 is y = (-5/2)x + 13.

B. The x-intercept of the equation is x = 26/5 or 5.2

A. To find the equation of a line that passes through the point (4,3) and has a slope of -5/2, we can use the point-slope form of a linear equation:

y - y1 = m(x - x1)

where m is the slope, and (x1, y1) is the given point.

Substituting the values, we get:

y - 3 = (-5/2)(x - 4)

Expanding the right side:

y - 3 = (-5/2)x + 10

Adding 3 to both sides:

y = (-5/2)x + 13

B. To find the x-intercept of this equation, we need to set y = 0 and solve for x:

0 = (-5/2)x + 13

Multiplying both sides by -2/5:

0 = x - (26/5)

Adding (26/5) to both sides:

x = 26/5

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Answer:

(2, 180)

Step-by-step explanation:

w(x)=-5x^2+20x+160

a=-5 b=20

x=-20/2x(-5)

x=2

w(2)=180

2, 180

The circumference of Circle C is found as 53π.

In the given figure:

AD = 28 and DB = 45

∠ADB = 1/2 *∠ACB

∠ADB = 90

Applying Pythagorean theorem in ΔABD.

AB² = AD² + DB²

AB² = 28² + 45²

AB = √2809

AB = 53

Radius = 53/2

circumference of Circle C:

C = 2πr

C = 2*π* (53/2)

C =  53π

Thus, the circumference of Circle C is found as 53π.

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Answer:

Area of the figure=126.5cm²

Step-by-step explanation:

As we can see based on the shape of the figure, we can divide it into a;

→ Triangle

→ Rectangle

Formulas that we need are;

⇒ Area of triangle =1/2×base×height

⇒ Area of rectangle =length × width

Let's solve the area of the triangle first;

Then the area of the rectangle;

Finally, we add the triangle and rectangle together-

Area of Triangle + Area of Rectangle = 38.5cm²+88cm²

Area of the figure=126.5cm²

RevyBreeze

Changing the value of "a" in the quadratic function affects the vertical stretch or compression and the direction of the opening of the parabola, compared to the graph of the quadratic parent function.

What is function?

A relationship or expression involving one or more variables

The function g(x) = 6x^2 is a quadratic parent function, which means it is the simplest form of a quadratic function.

When we change the value of "a" in the general form of a quadratic function:

f(x) = ax^2 + bx + c

we change the shape of the graph of the function. Specifically, changing the value of "a" stretches or compresses the graph vertically, and changes the direction of the opening of the parabola.

If "a" is positive, the parabola opens upwards, and if "a" is negative, the parabola opens downwards. The larger the absolute value of "a", the more stretched or compressed the parabola becomes.

In the case of g(x) = 6x^2, "a" is positive and equal to 6, which means the graph is stretched vertically by a factor of 6 compared to the parent function. The parabola opens upwards and is narrower than the parent function.

If we were to change the value of "a" to a different positive value, for example "a" = 3, the graph would still open upwards but would be less stretched than g(x) = 6x^2. On the other hand, if we were to make "a" negative, for example "a" = -6, the graph would open downwards, and be a reflection of the graph of g(x) = 6x^2 about the x-axis.

In summary, changing the value of "a" in the quadratic function affects the vertical stretch or compression and the direction of the opening of the parabola, compared to the graph of the quadratic parent function.

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The coordinates of point Q in the parallelogram is (2b + 2a,2c)

The coordinates are given as:

P(2b, 2c) Q(?, ?) S(0, 0) R(2a, 0)

The parallelogram form of the object indicates that the distances PQ and RS are equal.

The distance RS is calculated as:

RS = ( 2a - 0, 0)

This gives

RS = (2a, 0)

Coordinate Q is calculated as:

Q = P + RS

This gives

Q = (2b,2c) + (2a,0)

Evaluate the sum

Q = (2b + 2a,2c)

Hence, the coordinates of point Q is (2b + 2a,2c)

Midpoint of SQ=(b+ a ,c)

Midpoint of PR=(a+ b, c)

hence, SQ and PR bisect each other.

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The value of angle CI is equal to 40 for the triangle.

What is geometry?

Geometry is one of the oldest branches of mathematics, along with arithmetic. It is concerned with spatial properties such as figure distance, shape, size, and relative position.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that I is the incenter of the triangle AI = 3x+7, BI = 5x-11, and CI = 52-2x.

The value of BI will be calculated as,

AI = BI

3x + 7 = 5x - 11

2x = 18

x = 6

Now for the value of angle CI:

CI = 52 - 2x

CI = 52 - 2 x 6

CI = 52 - 12

CI = 40

Therefore, the value of angle CI is equal to 40 for the triangle.

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[tex]\qquad \qquad \textit{Inverse Trigonometric Identities} \\\\ \begin{array}{cccl} Function&Domain&Range\\[-0.5em] \hrulefill&\hrulefill&\hrulefill\\ y=cos^{-1}(\theta)&-1 ~\le~ \theta ~\le~ 1& 0 ~\le~ y ~\le~ \pi \\\\ y=tan^{-1}(\theta)&-\infty ~\le~ \theta ~\le~ +\infty &-\frac{\pi}{2} ~\le~ y ~\le~ \frac{\pi}{2} \end{array} \\\\[-0.35em] ~\dotfill[/tex]

[tex]cos^{-1}\left( -\cfrac{\sqrt{2}}{2} \right)\implies \theta \hspace{5em}\stackrel{\textit{so we can say}}{cos(\theta )=-\cfrac{\sqrt{2}}{2}} \\\\\\ \theta =cos^{-1}\left( -\cfrac{\sqrt{2}}{2} \right)\implies \stackrel{ \textit{on the II Quadrant} }{\theta =\cfrac{3\pi }{4}} \\\\[-0.35em] ~\dotfill\\\\ sin\left[ cos^{-1}\left( -\cfrac{\sqrt{2}}{2} \right) \right]\implies sin\left( \cfrac{3\pi }{4} \right)\implies \boxed{\cfrac{\sqrt{2}}{2}}[/tex]

now let's find the angle for the inverse tangent

[tex]sin\left( \cfrac{\pi }{2} \right)\implies 1\hspace{5em}\stackrel{\textit{so we can say}}{tan^{-1}\left[ sin\left( \frac{\pi }{2} \right) \right]}\implies tan^{-1}(1) \stackrel{ \textit{on the I Quadrant} }{\implies\boxed{\cfrac{\pi }{4}}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ sin\left[ cos^{-1}\left( -\frac{\sqrt{2}}{2} \right) \right]~~ + ~~tan^{-1}\left[ sin\left( \frac{\pi }{2} \right) \right]\implies \cfrac{\sqrt{2}}{2}~~ + ~~\cfrac{\pi }{4} \implies \boxed{\cfrac{2\sqrt{2}+\pi }{4}}[/tex]

for the sine function we end up in the II Quadrant because the inverse cosine function range is constrained to the I and II Quadrants only, so our angle comes from that range.

Likewise, our angle from the inverse tangent comes from the I Quadrant, because inverse tangent range is only I and IV Quadrants.

The solution of the match is

(1) Orthocenter          (C) The point at which the altitudes of a triangle                                                

                                              meet.

(2) Centroid                 (D) The point at which the medians of a triangle

                                             meet.

(3) Circumcenter         (A) The point of intersection of the perpendicular                  

                                             bisectors of the sides of a triangle.

(4) Incentre                 (B) The point at which the three angle bisectors      

                                             of a triangle meet.

The orthocenter of a triangle is the point where the altitudes of the triangle intersect. The orthocenter is not always inside the triangle, and in some cases, it may lie outside the triangle.

The centroid of a triangle is the point where the three medians of the triangle intersect. The centroid is always inside the triangle, and it is also the center of mass of the triangle.

The circumcenter of a triangle is the point where the perpendicular bisectors of the sides of the triangle intersect.  The circumcenter is not always inside the triangle, and in some cases, it may lie outside the triangle.

The incentre of a triangle is the point where the three angle bisectors of the triangle intersect. The incentre is always inside the triangle, and it is also the center of the circle that is inscribed inside the triangle.

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Complete Question:

Match the following.

(1) Orthocenter         (A) The point of intersection of the perpendicular                  

                                             bisectors of the sides of a triangle.

(2) Centroid                 (B) The point at which the three angle bisectors of

                                             a triangle meet.

(3) Circumcenter         (C) The point at which the altitudes of a triangle

                                              meet.

(4) Incentre                 (D) The point at which the medians of a triangle

                                             meet.

The appropriate measure of variability for the data shown is the range, and its value is 48. The answer is: "The range is the best measure of variability, and it equals 48."

What is variability?

To determine the appropriate measure of variability for the data shown, we need to consider the characteristics of the data set. Since the data set is relatively small and discrete, the range would be an appropriate measure of variability.

To calculate the range, we subtract the smallest value from the largest value:

Largest value: 58

Smallest value: 10

Range = Largest value - Smallest value = 58 - 10 = 48

Therefore, the appropriate measure of variability for the data shown is the range, and its value is 48. The answer is: "The range is the best measure of variability, and it equals 48."

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The system of equations that has only one solution is the one where the equations have different slopes, it is the one in option C.

y = 4x - 5

y = -x - 5

A system of linear equations will have only one solution always that the lines are neither parallel nor the same line.

So, one way to check this, is to write both lines in the slope intercept form, and check that the two lines have different slopes.

For example, the first option will give.

y = -4x - 2

y = -4x + 5

These are parallel (same  slope different intercept), then this systm has no solutions.

The correct option will be C, where the system is:

y = 4x - 5

y = -x - 5

The slopes are different.

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Answer:

Step-by-step explanation:

Circle centre: (4,7)

Radius: 3

Equation is:

  [tex](x-h)^2+(y-k)^2=r^2[/tex]   (where (h,k) is center, r is radius)

  [tex](x-4)^2+(y-7)^2=3^2[/tex]

  [tex](x-4)^2+(y-7)^2=9[/tex]     (This is the general standard form )

in expanded form,

  [tex](x^2-8x+16)+(y^2-14y+49)=9[/tex]

  [tex]x^2+y^2-8x-14y+56=0[/tex]

Note: Unless stated either form is an acceptable answer.

The measure of the angle the cable car track makes with the valley floor is approximately 38.7 degrees.

The slope or inclination of a line or surface is sometimes referred to as the grade in mathematics. The ratio of the vertical change (rise) to the horizontal change (run) between any two locations on a line or surface is what is meant by this term. Usually, the grade is given as a percentage or a fraction. In engineering, building, and transportation, grades are frequently used to define the slope of roads, railroads, and other infrastructure. The grade, which refers to how steep the slope is when referring to a cable car, is a crucial element in determining the safety and effectiveness of the system.

To find the angle we use the trigonometric functions:

tan(θ) = grade = rise/run

Given that, the grade of the incline is 78%, then grade = 0.78.

θ = arctan(0.78) ≈ 38.7 degrees.

Hence, the measure of the angle the cable car track makes with the valley floor is approximately 38.7 degrees.

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0.4

The probability that an undergraduate business major intends to attend classes full-time in pursuit of an MBA degree depends on the individual student's preferences and situation. Generally speaking, studies have shown that about 40% of undergraduate business majors choose to pursue an MBA degree full-time after graduating. Therefore, the probability of an undergraduate business major pursuing an MBA degree full-time can be estimated at 0.4.

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The variable socioeconomic status ranges from upper class to lower class and is an example of the interval-ratio level of measurement. (option c)

Ordinal level of measurement is used to categorize variables that can be ranked in a specific order but do not have a uniform difference between them. For instance, a student's class rank can be categorized as first, second, or third. However, there is no uniform difference between the ranks.

Ratio level of measurement is used to categorize variables that have a meaningful zero point. For instance, height, weight, and age have a meaningful zero point.

However, in reality, it is difficult to find a person with zero income or zero education. Therefore, socioeconomic status can be considered an example of interval-ratio level of measurement but not an example of ratio level of measurement.

Hence option (c) is correct.

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The expression for the total amount of shoes for both people is 4X + 2.

As a result, total cost is the sum of fixed and variable costs, or TC = FC + VC = Kr+Lw.

Say Person 1 owns X pairs of shoes. So, Person 2 has two to three times as much as Person 1. This can be said as follows:

Person 2 possesses at least two more than three times Person 1's amount, so Person 2's amount is equal to 3X + 2.

By simply adding Person 1's and Person 2's shoe counts, we can determine the total number of shoes for both individuals, which results in:

Total equals the sum of the amounts given by Persons 1 and 2.

When we replace the value of Person 2's contribution, we obtain:

Amount total = X + (3X + 2)

If we simplify, we get:

Total = 4X plus 2

Hence, 4X + 2 is the total number of shoes for both individuals.

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Answer:

7/4

Step-by-step explanation:

if you divide 7/4, you will get 1.75 which is greater than 1.43.

Answer:

Hi, your answer is 7/4

Step-by-step explanation:

Hope this helps :D

The 99% confidence interval on the true mean EMG activity for all seniors in the class is option (a) [34.7296, 36.8704]

To calculate the 99% confidence interval for the true mean EMG activity for all seniors in the class, we can use the formula

CI = X ± Zα/2 (σ/√n)

where

X = sample mean = 35.8

Zα/2 = the critical value for the 99% confidence interval, which can be found using a standard normal distribution table or calculator. For a two-tailed test, α/2 = 0.005, so Zα/2 = 2.576.

σ = sample standard deviation = 2.5

n = sample size = 40

Substituting these values into the formula, we get

CI = 35.8 ± 2.576 (2.5/√40) = [34.7296, 36.8704].

Therefore, the correct option is (a) [34.7296, 36.8704]

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The trade balance must be negative.

If Canada imports more goods and services than it exports, the trade balance must be negative.

Here's a step-by-step explanation of why this is true and why options A and E are wrong:

1. The trade balance is calculated as the value of exports minus the value of imports. If imports are greater than exports, the trade balance will be negative (C). This m that Canada is seen spending more on goods and services from other countries than it is receiving from the sale of its own goods and services to other countries.

2. The current account balance includes the trade balance, but also considers other transactions such as income from investments and transfers like foreign aid. While it is possible that a negative trade balance could be offset by other positive inflows, we do not have enough information to determine whether the current account balance must be negative (A) or positive (B). Therefore, we cannot definitively say that A or B is true.

3. The financial account (formerly called capital account) balance records the net change in ownership of financial assets, such as stocks and bonds, between a country and the rest of the world. A negative financial account balance means that a country's residents are purchasing more foreign assets than foreign residents are purchasing of that country's assets. A positive financial account balance means the opposite. Since we only have information about the trade balance and not the financial transactions, we cannot determine whether the financial account balance must be negative (D) or positive (E).

Based on the information given, we can only conclude that the trade balance must be negative (C) if Canada imports more goods and services than it exports.

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Answer:

Proofs attached to answer

Step-by-step explanation:

Proofs attached to answer

Gillian pocket money is x, then Gillian  has [tex]5/12x[/tex]left after spending on snacks and bus fare.

The term "spending" refers to the act of spending money to buy goods or services. It is the act of exchanging money for something, usually a product, service, or experience. Buying groceries, paying for transportation, or purchasing clothing are all examples of spending. To avoid debt and achieve your financial goals, it is critical to manage your spending wisely in personal finance.

If Gillian spends one-third of her pocket money on snacks and one-quarter on bus fare, she spends 7/12 of her pocket money on snacks and bus fare.

This means she only has [tex]1 - 7/12 = 5/12[/tex] of her pocket money remaining.

As a result, if her pocket money is x, she has 5/12x left after paying for snacks and bus fare.

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