These calculations indicate that the process's typical percent yield is roughly 4.06%.
The balanced chemical formula for the reaction of magnesium and oxygen to produce magnesium oxide is 2Mg + O2 2MgO.
Trial 1: Mg mass is equal to (0.404 g) (27.096 g - 26.692 g).
Test 2: Mg mass equals (26.999 g - 26.690 g) = 0.309 g
Calculated yield of MgO in Trial 1 is equal to 2 x (0.404 g Mg) x (1 mol MgO/2 mol Mg) x (40.31 g MgO/1 mol MgO) = 16.28 g MgO.
Calculated yield of MgO in Trial 2 is equal to 2 x (0.309 g Mg) x (1 mol MgO/2 mol Mg) x (40.31 g MgO/1 mol MgO) = 12.44 g MgO.
Trial 1's actual MgO production was 27.352 g - 26.692 g, or 0.66 g MgO.
Trial 2's actual MgO production was equal to 0.507 g MgO (27.197 g - 26.690 g).
Trial 1: The percentage of MgO yield is calculated as (0.66 g MgO/16.28 g MgO) x 100% = 4.05%.
Trial 2: MgO yield as a percentage is (0.507 g MgO/12.44 g MgO) times 100%, or 4.07%.
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An ice block of mass 3.00 kg has a temperature of 0°C. When energy of 5.01 × 105 J is transferred to the ice block, half of the block melts to water at 0°C.
(a) Determine the specific latent heat of fusion of ice.
____J/g
(b) How much energy would be needed to melt the remainder of the ice.
____J
(c) An extra energy of 2 × 105 J is transferred to the mixture of the ice block and water. What will be the temperature of the mixture?
____degreesCelsius
The energy required to increase 1.000 kg of water ice between 0 °C °C through 79.8 °C °C is equivalent to the energy required to melt one pound of ice (334 kJ).
What changes in the water's temperature occur as it transitions from ice to water vapour?No surface temp change happens from heat exchange if ice caps melt and has become water ice (i.e., that during phase transition). Imagine about water melting from stalactites that were already dripping on a sun-warmed roof. Alternatively, water boils in an ice bucket cooled by relatively low surroundings.
How warm is the water now that the frost has melted?To melt, the iceberg will take in all the heat that is available. The water stays at zero degrees Fahrenheit until all of the ice has dissolved as when the ice has melted, it changes becomes saltwater at that temperature.
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A 100.0 g Chunk of Aluminum with an Initial Temperature of 450.0 C° is added to 100.0
mL of Ethyl Alcohol with an Initial Temperature of 80.0 C° (A) Calculate Equilibrium
Temperature of the Mixture (B) Calculate the Heat Exchange of the System
A) 150 C° B) 30000 J All answers Approx B
A) 300 C° B) 15000 J All answers Approx
D
A) 198 C° B) 22770 J All answers Approx
all silbeg
A) 110C° B) 10000 J All answers Approx
The system is losing heat to the surroundings. The approximate value for the heat exchange is 36770 J.
What is Equilibrium?
In general, equilibrium refers to a state of balance or stability in a system. In the context of physics, specifically thermodynamics, equilibrium is a state in which there is no net flow of heat or matter between a system and its surroundings. In other words, the system and surroundings have reached the same temperature and pressure, and there is no longer any exchange of heat or matter between them.
To solve this problem, we can use the equation for heat exchange:
Q = mcΔT
where Q is the heat exchange, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.
For aluminum, the specific heat capacity is 0.903 J/g°C, and for ethyl alcohol, it is 2.44 J/g°C. We can also assume that the heat exchange between the aluminum and the ethyl alcohol is equal and opposite.
A) To find the equilibrium temperature, we can use the equation:
mcΔT = mcΔT
(100.0 g)(0.903 J/g°C)(T - 450.0°C) = (100.0 g)(2.44 J/g°C)(T - 80.0°C)
Solving for T, we get:
T = 198.15°C
Therefore, the equilibrium temperature of the mixture is approximately 198°C.
B) To find the heat exchange, we can use the same equation:
Q = mcΔT
The heat exchange for aluminum is:
Q₁ = (100.0 g)(0.903 J/g°C)(450.0°C - 198.15°C) ≈ 21260 J
The heat exchange for ethyl alcohol is:
Q₂ = (100.0 g)(2.44 J/g°C)(198.15°C - 80.0°C) ≈ 15510 J
The total heat exchange for the system is:
Q = -(Q₁ + Q₂) ≈ -36770 J
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Can someone please help with this chemistry question
The mole ratio of NaNO₃ to Pb(NO₃)2 is 2:1. Therefore, 6.75 g of Pb(NO₃)₂ will produce 2 x 6.75 g = 13.5 g of NaNO₃.
What is mole?Mole is a unit of measurement used in chemistry to measure the amount of a substance, usually expressed in terms of the number of atoms, molecules, or other units in a given mass of that substance. The mole, also known as Avogadro's number, is a very large number equal to 6.022 x 10^23. This means that a mole of a substance contains 6.022 x 10^23 atoms or molecules, depending on the substance. The mole is used to measure the amount of a substance in a given sample, and is essential to many chemical calculations.
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Will a person with two dominant genes for brown eyes be able to have a baby with blue eyes
Answer: theres a 1 in 4 chance of that happening
Explanation:
A 44. 0-mg sample of phosphorus reacts with sulfur to form 158 mg of the compound phosphorus sulfide. Part a what is the empirical formula of phosphorus sulfide?
The empirical formula of phosphorus sulfide is [tex]P^{1}S^3.[/tex].
To determine the empirical formula of phosphorus sulfide, we need to find the mole ratio between phosphorus and sulfur in the compound. We can use the given masses of phosphorus and phosphorus sulfide to calculate the number of moles of each element.
First, we convert the masses of phosphorus and phosphorus sulfide from milligrams to grams:
Mass of P = 44.0 mg = 0.0440 g
Mass of P4S3 = 158 mg = 0.158 g
Next, we calculate the number of moles of each element:
Moles of P = mass of P / molar mass of P = 0.0440 g / 30.97 g/mol = 0.00142 mol
Moles of S = (mass of P4S3 - mass of P) / molar mass of S = (0.158 g - 0.0440 g) / 32.07 g/mol = 0.00393 mol
We then divide the number of moles of each element by the smallest value to obtain the simplest whole-number ratio of atoms:
Moles of P / 0.00142 mol ≈ 1
Moles of S / 0.00142 mol ≈ 2.77
We can then round the above ratio to the nearest whole number to get the empirical formula:
[tex]P^{1}S^3.[/tex]
Phosphorus sulfide is a chemical compound with the formula P4S3. It is a yellowish-white solid with a garlic-like odor, and is insoluble in water but soluble in carbon disulfide.
It is formed by the reaction of phosphorus with sulfur, and can also be produced by heating a mixture of red phosphorus and sulfur.
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what happens to the reaction rate and slope when the concentration (absorbance) of the reactants is doubled?
When the concentration (absorbance) of reactants is doubled, the reaction rate and slope of the reaction will increase.
This is due to the increased availability of reactants, leading to more successful collisions between molecules. This in turn results in a faster reaction rate, and therefore a steeper slope. The reaction rate and slope of a reaction depend on the concentration of reactants. When the concentration (absorbance) of the reactants is doubled, the reaction rate increases, and the slope of the graph increases accordingly.
The rate of a reaction is the speed at which the reactants change into products. If the reaction rate is high, the reaction will occur quickly, whereas if the reaction rate is low, the reaction will take longer to occur. When the concentration (absorbance) of the reactants is doubled, the reaction rate and slope of the graph increase. It occurs because the number of reactant particles available for collision increases.
Hence increase in the number of reactant particles available for collision leads to more collisions per unit of time, and this increases the reaction rate.
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1) All of the following are homogeneous mixtures except.
* tomato soup.
* a sugar-water solution.
* gasoline.
* a salt-water solution.
Answer:
gasoline
Explanation:
The right response is gasoline
Because the ingredients are evenly distributed and do not settle over time, homogeneous combinations include tomato soup, sugar-water solution, and salt-water solution. Contrarily, gasoline is a heterogeneous mixture since it contains a variety of hydrocarbons and additives that may separate or settle over time.
Imagine you are a chemical engineer at a
chemical plant. One day the air conditioning in the plant stops working,
resulting in high humidity. The percent yield for a chemical you produce
drops significantly. Construct an explanation for the decrease in yield.
The temperature in the atmosphere will rise as humidity rises. Only in the case of an exothermic chemical reaction will an increase in temperature slow down the reaction and thus reduce the percentage yield.
What is exothermic reaction ?Energy is involved in all chemical reactions. When reactants break bonds, energy is released, and when products form new bonds, energy is released. Endothermic reactions are those in which less energy is released when new bonds form in the products than is required to break bonds in the reactants. Exothermic reactions are the polar opposite. In an exothermic reaction, breaking bonds in the reactants requires less energy than the energy released when new bonds form in the products.
What is humidity ?The amount of water vapor in the air is referred to as humidity. The humidity will be high if there is a lot of water vapor in the air. The higher the humidity, the wetter the weather feels outside. Humidity is usually described as relative humidity in weather reports.
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1. How many grams of glucose are needed to prepare 400mL of 5% glucose solution?
A. 5g
B. 10g
C. 14g
D. 20g
The response is C. 400mL of 5% glucose solution requires 20g of glucose to make.
To prepare 400mL of 5% glucose solution, we need to determine the amount of glucose required.
5% glucose solution means that 5g of glucose is present in 100mL of the solution.
Therefore, for 400mL of the solution, the amount of glucose required can be calculated as:
5g glucose/100mL solution = x g glucose / 400mL solution
x = (5g glucose/100mL solution) x (400mL solution) = 20g glucose
Therefore, the answer is D. 20g of glucose is needed to prepare 400mL of 5% glucose solution.
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Which two factors must be equal when a chemical reaction reaches equilibrium?
Answer:
The rate of the forward reaction must be equal to the rate of the reverse reaction. In other words, the speed at which products are formed from reactants must be equal to the speed at which reactants are formed from products.
The concentrations (or partial pressures) of the reactants and products must be constant. At equilibrium, the system has reached a state of balance where the amounts of reactants and products are no longer changing with time, and their concentrations (or partial pressures) have stabilized.
Thus, at equilibrium, the reaction is said to be "dynamic," meaning that the forward and reverse reactions are still occurring but at an equal rate, resulting in no net change in the concentrations (or partial pressures) of the reactants and products.
Explanation:
How many milliliters of 0. 20 M H2SO4 are
required to completely neutralize 40. ML
of 0. 10 M Ca(OH)2?
20 mL of 0.20 M H2SO4 is required to completely liquidate 40 mL of 0.10 M Ca (OH)2.
We can use the balanced chemical equation for the neutralization reaction between sulfuric acid (H2SO4) and calcium hydroxide (Ca (OH)2) to determine the stoichiometry of the reaction:
H2SO4 + Ca (OH)2 -> CaSO4 + 2H2O
moles of Ca (OH)2 = Molarity x Volume
= 0.10 mol/L x 0.040 L
= 0.004 mol
moles of solute = Molarity x Volume (in liters)
alter this equation gives:
Volume (in liters) = moles of solute / Molarity
Therefore, the volume of 0.20 M H2SO4 required to supply 0.004 moles of H2SO4 is:
Volume (in liters) = 0.004 mol / 0.20 mol/L
= 0.02 L
Multiplying by 1000 mL/L, we get:
Volume (in mL) = 0.02 L x 1000 mL/L
= 20 mL
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We can measure the rate of reaction between calcium carbonate and acid by displacing the water in an upturned measuring cylinder with the carbon dioxide produced.
Explain
whether the time taken to displace all of the water in a measuring cylinder will be greater for lumps of calcium carbonate or powder.
Whether the time taken tο displace all οf the water in a measuring cylinder will be greater fοr lumps οf calcium carbοnate οr pοwder are mentiοned belοw.
What is reactiοn?The transfοrmatiοn οf οne οr mοre reactants intο οne οr mοre new prοducts is referred tο as a chemical reactiοn. Substances are made οf chemical cοnstituents οr cοmpοunds. The transfοrmatiοn οf οne οr mοre reactants intο οne οr mοre new prοducts is referred tο as a chemical reactiοn. Substances are made οf chemical cοnstituents οr cοmpοunds.
What is carbοn diοxide?One part carbοn and twο parts οxygen make up the gas called carbοn diοxide. Its usage by plants tο create carbοhydrates during a prοcess knοwn as phοtοsynthesis makes it οne οf the mοst significant gases οn the planet.
The cοncentratiοn οf calcium carbοnate cannοt fluctuate because it is a sοlid. Hence, the οnly reactant in this reactiοn that can fluctuate in cοncentratiοn and impact reactiοn rate is hydrοchlοric acid. We need tο graph the cοncentratiοn οf hydrοchlοric acid against time, as yοu shοuld knοw frοm yοur reactiοn rate theοry.
Therefοre, whether the time taken tο displace all οf the water in a measuring cylinder will be greater fοr lumps οf calcium carbοnate οr pοwder are mentiοned abοve.
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Aqueous solutions of aluminum chloride and sodium carbonate are combined chemical ionic and net
Aqueous solutions of aluminum chloride and sodium carbonate are combined to form carbon dioxide and sodium chloride.
When chemicals are combined, a chemical change known as a balanced chemical reaction takes place. The reactants, or the chemicals that are combined, are on the left side of the equation. The reaction's byproducts are on the right side.
Aluminum oxide, sodium chloride, and carbon dioxide gas bubbles are created when aluminum chloride and sodium carbonate combine.
When dissolved substances react, one (or more) solid products are produced, which is known as a precipitation reaction. These kinds of reactions, which are also occasionally known as double displacement, double replacement, or metathesis reactions, frequently involve the exchange of ions between ionic compounds in aqueous solutions.
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The complete question is
Write a balanced chemical equation: aqueous solutions of aluminium chloride and sodium carbonate are combined, producing aluminium carbonate.
The half-life of palladium-100 is 3.6 days.
A sample of 12.0 grams of palladium-100 is left alone for 10 days.
How much of the original sample remains?
Select one:
-Between 1.50 and 3.00 grams.
-Between 3.00 and 6.00 grams.
-Between 0.75 and 1.50 grams.
-Between 6.00 and 12.0 grams.
The amount of the original sample remaining would be between 1.50 and 3.00 grams. Option I.
Half-life problemTo solve this problem, we can use the half-life formula:
N = N0 x (1/2)^(t/T)
where:
N0 is the initial amount of the substanceN is the amount of the substance remaining after a time t has passedT is the half-life of the substanceWe are given N0 = 12.0 grams, T = 3.6 days, and t = 10 days. We can plug these values into the formula and solve for N:
N = 12.0 grams x (1/2)^(10/3.6)
N ≈ 1.50 grams
Therefore, about 1.50 grams of the original sample remains after 10 days. The answer is between 1.50 and 3.00 grams.
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Why is carbon dioxide not named using the same rules as sodium chloride?
Answer:
Explanation:
It is a binary molecular compound ( and when the first element is to the right of the zigzag line on the periodic table you will use prefixes (di)
which of the following is not a limitation of a friedel-crafts reaction. alkyl halides must have the halogen attached to an sp3 hybridized carbon , not selected friedel-crafts alkylation substrates can undergo rearrangement , not selected incorrect answer: friedel-crafts reactions can not be done on moderately or strongly deactivated ring systems friedel-crafts acylation often leads to polyacylated products. , not selected friedel-crafts alkylation often leads to polyalkylated products.
Answer: sp3
Explanation:
The correct answer is that Friedel-Crafts reactions can not be done on moderately or strongly deactivated ring systems.
This is a limitation of Friedel-Crafts reactions because they require an activated ring system in order to proceed.
Deactivated ring systems do not have the necessary electron density to facilitate the reaction, and therefore the reaction will not occur.
Friedel-Crafts alkylation and acylation reactions are both types of electrophilic aromatic substitution reactions that involve the formation of a carbon-carbon bond between an aromatic ring and an alkyl or acyl group.
These reactions are commonly used in organic synthesis to introduce new functional groups onto an aromatic ring.
However, they do have other limitations including the fact that Friedel-Crafts alkylation substrates can undergo rearrangement,
Friedel-Crafts acylation often leads to polyacylated products,
and Friedel-Crafts alkylation often leads to polyalkylated products.
These limitations must be taken into consideration when designing a synthetic route that involves a Friedel-Crafts reaction.
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Which of the following is an example of potential energy changing to
kinetic energy?
OA person riding a bicycle along a level road
A plant producing food by photosynthesis
Rocks falling down a mountainside
Sunlight heating the water in the lake
What is the formula for sulfide ions and calcium ion?
Answer:
the formula for sulfide ion is S²⁻, and the formula for calcium ion is Ca²⁺. When combined, they form calcium sulfide with the chemical formula CaS.
Explanation:
81. Find the pH of each mixture of acids. A. 0. 115 M in HBr and 0. 125 M in HCHO2 b. 0. 150 M in HNO2 and 0. 085 M in HNO3 c. 0. 185 M in HCHO2 and 0. 225 M in HC2H3O2 d. 0. 050 M in acetic acid and 0. 050 M in hydrocyanic acid
The pH of the mixture of acids is 0.62, the pH of the mixture of acids is 0.63, the pH of the mixture of acids is 0.39, the pH of the mixture of acids is 1.00.
To find the pH of a mixture of acids, we need to first calculate the total concentration of H⁺ ions in the solution, and then use that value to calculate the pH using the formula pH = -log[H⁺].
The chemical formulas for the two acids are:
HBr - hydrobromic acid
HCHO₂ - formic acid
The dissociation reactions for these acids are:
HBr → H⁺ + Br⁻
HCHO₂ → H⁺ + CHO₂⁻
The concentrations of the two acids are given as:
[HBr] = 0.115 M
[HCHO₂] = 0.125 M
To find the total concentration of H⁺ ions in the solution, we need to consider the dissociation reactions of both acids. The H⁺ ions from each acid will contribute to the total H⁺ ion concentration:
[H⁺] = [H⁺ from HBr] + [H⁺ from HCHO₂]
[H⁺] = [HBr] + [HCHO₂]
[H⁺] = 0.115 M + 0.125 M
[H⁺] = 0.24 M
Now that we know the total concentration of H⁺ ions in the solution, we can calculate the pH:
pH = -log[H⁺]
pH = -log(0.24)
pH ≈ 0.62
The chemical formulas for the two acids are:
HNO₂ - nitrous acid
HNO₃ - nitric acid
The dissociation reactions for these acids are:
HNO₂ → H⁺ + NO₂⁻
HNO₃ → H⁺ + NO₃⁻
The concentrations of the two acids are given as:
[HNO₂] = 0.150 M
[HNO₃] = 0.085 M
To find the total concentration of H⁺ ions in the solution, we need to consider the dissociation reactions of both acids. The H⁺ ions from each acid will contribute to the total H⁺ ion concentration:
[H⁺] = [H⁺ from HNO₂] + [H⁺ from HNO₃]
[H⁺] = [HNO₂] + [HNO₃]
[H⁺] = 0.150 M + 0.085 M
[H⁺] = 0.235 M
Now that we know the total concentration of H⁺ ions in the solution, we can calculate the pH:
pH = -log[H⁺]
pH = -log(0.235)
pH ≈ 0.63
The chemical formulas for the two acids are:
HCHO₂ - formic acid
HC₂H₃O₂ - acetic acid
The dissociation reactions for these acids are:
HCHO₂ → H⁺ + CHO₂⁻
HC₂H₃O₂ → H⁺ + C₂H₃O₂⁻
The concentrations of the two acids are given as:
[HCHO₂] = 0.185 M
[HC₂H₃O₂] = 0.225 M
To find the total concentration of H⁺ ions in the solution, we need to consider the dissociation reactions of both acids. The H⁺ ions from each acid will contribute to the total H⁺ ion concentration:
[H⁺] = [H⁺ from HCHO₂] + [H⁺ from HC₂H₃O₂]
[H⁺] = [HCHO₂] + [HC₂H₃O₂]
[H⁺] = 0.185 M + 0.225 M
[H⁺] = 0.410 M
Now that we know the total concentration of H⁺ ions in the solution, we can calculate the pH:
pH = -log[H⁺]
pH = -log(0.410)
pH ≈ 0.39
The chemical formulas for the two acids are:
CH₃COOH - acetic acid
HCN - hydrocyanic acid
The dissociation reactions for these acids are:
CH₃COOH → H⁺ + CH₃COO⁻
HCN → H⁺ + CN⁻
The concentrations of the two acids are given as:
[CH₃COOH] = 0.050 M
[HCN] = 0.050 M
To find the total concentration of H⁺ ions in the solution, we need to consider the dissociation reactions of both acids. The H⁺ ions from each acid will contribute to the total H⁺ ion concentration:
[H⁺] = [H⁺ from CH₃COOH] + [H⁺ from HCN]
[H⁺] = [CH₃COOH] + [HCN]
[H⁺] = 0.050 M + 0.050 M
[H⁺] = 0.100 M
Now that we know the total concentration of H⁺ ions in the solution, we can calculate the pH:
pH = -log[H⁺]
pH = -log(0.100)
pH = 1.00
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Which element "X" forms an ionic compound with the formula X3P2?
Answer:
Explanation:
not sure your elements to choose from
But it would be one with a +2 charge
Examples
Be, Mg, Ca, Sr, Ba, Cu, Fe these are just a few
send your list and I can finish this for you
Calculate the number of formula units in 12. 5 mol of calcium carbonate CaCO3
12.5 mol of the substance contains 7.53 x 10²⁴ formula units of calcium carbonate.
Calcium carbonate (CaCO₃) is a compound that consists of one calcium atom, one carbon atom, and three oxygen atoms. The formula unit of calcium carbonate contains one Ca atom, one C atom, and three O atoms. To calculate the number of formula units in 12.5 mol of calcium carbonate, we need to use Avogadro's number, which relates the number of particles (atoms, molecules, or formula units) in a given amount of substance.
Avogadro's number (Nₐ) is 6.022 x 10²³ particles/mol. Therefore, the number of formula units of calcium carbonate in 12.5 mol can be calculated as:
n = Nₐ * 12.5 mol
n = 6.022 x 10²³ particles/mol * 12.5 mol
n = 7.53 x 10²⁴ particles
Therefore, there are 7.53 x 10⁴ formula units of calcium carbonate in 12.5 mol of the compound.
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At constant pressure, which of these systems do work on the surroundings? Check all that apply.a. 2A(g)+3B(g) --> 4C(g)b. A(s)+B(g) --> 2C(g)c. A(g)+B(g) --> 3C(g)d. A(s)+2B(g) --> C(g)
At constant pressure, the systems that work on the surroundings are: A(s)+B(g) → 2C(g), A(g)+B(g) → 3C(g). The correct options are B and C.
Explanation:In thermodynamics, if the reaction proceeds at constant pressure, it implies that the pressure remains constant during the course of the reaction, whereas the volume might change. The systems that work on the surroundings are those in which work is done on the surroundings by the system, resulting in a decrease in the internal energy of the system.
Option a. 2A(g)+3B(g) → 4C(g)The reaction's stoichiometric coefficients of the reactants and products are balanced, implying that the number of moles of reactants and products is the same. It means there is no change in the number of moles of gas, which means there is no expansion of gases, resulting in no work done by the system. Thus, this option does not satisfy the criteria for a system working on the surroundings.
Option b. A(s)+B(g) → 2C(g)The reaction has one gas molecule in the reactants and two gas molecules in the products, implying that there is an increase in the number of moles of gas. As a result, there is an increase in the volume, resulting in work being done by the system. This option satisfies the requirements for a system working on the surroundings.
Option c. A(g)+B(g) → 3C(g)The reaction has two gas molecules in the reactants and three gas molecules in the products, which means there is an increase in the number of moles of gas. As a result, there is an increase in the volume, resulting in work being done by the system. This option satisfies the requirements for a system working on the surroundings.
Option d. A(s)+2B(g) → C(g)The reaction has two gas molecules in the reactants and one gas molecule in the product, implying that there is a decrease in the number of moles of gas. It implies that the volume of the system will decrease, resulting in no work done by the system. Thus, this option does not satisfy the criteria for a system working on the surroundings.
Therefore, the options that work on the surroundings at constant pressure are options b and c.
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Example: PuC2Prunium corninePrunium cornide
Name these Ionic Compounds using the “Periodic Table of Food”:
2. BPo
3. Bl2Tu
4. Cr2Sn
5. LiSr2
6. Or3Ba2
What is the concentration of O2(g), in parts per million, in a solution that contains 0. 008 gram of O2(g) dissolved in 1000. Grams of H2O(2)?
Listen
1
0. 8 ppm
8 ppm
80 ppm
800 ppm
The concentration of O₂(g) in the solution is 8 ppm. Option B is correct.
Parts per million (ppm) is a unit of concentration used to express the amount of a substance in a solution. It represents the number of parts of the substance per one million parts of a solution.
To calculate the concentration of O₂(g) in parts per million (ppm), we need to first determine the amount of O₂ dissolved in the solution per unit mass of the solution.
We are given that the solution contains 0.008 grams of O₂(g) dissolved in 1000 grams of H₂O(₂):
Concentration of O₂(g) = (mass of O₂(g) / mass of solution) x 10⁶
Concentration of O₂(g) = (0.008 g / 1000 g) x 10⁶
= 8 ppm
Hence, B. 8ppm is the correct option.
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--The given question is incomplete, the complete question is
"What is the concentration of O2(g), in parts per million, in a solution that contains 0. 008 gram of O2(g) dissolved in 1000. Grams of H2O(2)?A) 10. 8 ppm B) 8 ppm C) 80 ppm D) 800 ppm"--
Which statement best describes the law of conservation of energy?
A. The total energy in an open system can only decrease.
B. Energy can be created but not destroyed.
C. Energy can change forms but cannot be created or destroyed.
D. Energy can be destroyed but not created.
Answer:
c
Explanation:
energy neither created nor distroyed
Answer:
The answer is C
Explanation:
We learned so many times about law conservation energy,states that"Energy neither created or destroyed but can change its form to other."
E.g If we rub our palm,it changes from kinetic energy to heat energy.
Most cells in the body of a fruit fly contain eight chromosomes. In some cells, only four chromosomes are present present, a condition, which is a direct result of
The condition where only four chromosomes are present in some cells of a fruit fly is known as haploidy.
Haploidy can occur due to a variety of reasons, including errors during cell division, such as nondisjunction, which is the failure of chromosomes to separate properly during meiosis. In nondisjunction, the chromosomes fail to divide equally, resulting in daughter cells with abnormal numbers of chromosomes. In the case of the fruit fly, this can result in cells with only four chromosomes instead of the normal eight.
Haploidy can also occur naturally in certain stages of development, such as during gamete formation, where cells undergo meiosis to produce haploid gametes with half the number of chromosomes as the parent cell.
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based on the appearance of your reaction (aluminum with copper (ii) sulfate) in thebeaker, which reagent do you think was consumed, and which reagent had some left over? explain.
Based on the appearance of the reaction of aluminum with copper (II) sulfate, the reagent that was consumed was aluminum, and the reagent that had some left over was copper (II) sulfate.
What is aluminum?Aluminum is a chemical element that has the symbol Al and the atomic number 13. It is a silvery-white, soft, nonmagnetic, ductile metal in the boron group. Aluminum is the third most prevalent element and the most abundant metal in the Earth's crust after oxygen and silicon.
Copper (II) sulfate is a blue solid that is soluble in water. Its appearance is due to the presence of water of crystallization, which occurs in the crystal structure. It is a compound that is commonly used as a fungicide and algaecide because it is toxic to many fungi and algae. Copper sulfate has also been used to treat various diseases.
What happens when aluminum reacts with copper (II) sulfate?Aluminum replaces the copper ions in copper (II) sulfate and creates aluminum sulfate and copper metal when aluminum reacts with copper (II) sulfate. The chemical reaction between aluminum and copper (II) sulfate is as follows:
Al(s) + CuSO4(aq) ⟶ Al2(SO4)3(aq) + Cu(s)
When aluminum is placed in copper (II) sulfate solution, copper ions from copper (II) sulfate move to aluminum, displacing the aluminum ions in the process. As a result, the copper ions from copper (II) sulfate solution are lowered to metallic copper, and aluminum ions combine with sulfate ions from copper (II) sulfate solution to form aluminum sulfate, which is soluble in water. When copper metal is produced, it forms a brown layer on top of the solution and sinks to the bottom.
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an electronic device contains a transformer. its primary coil has 200 turns and its secondary coil has 20 turns . if the device its plugged into a 120 volt line what is the output voltage of the device
The output voltage of the device is 12 volts.
The transformer law states that the ratio of the number of turns in the primary coil to the number of turns in the secondary coil is equal to the ratio of the output voltage to the input voltage. Mathematically, we can express this as:
Vp/Vs = Np/Ns
where Vp is the input voltage (120 volts in this case), Vs is the output voltage (what we're trying to find), Np is the number of turns in the primary coil (200 turns in this case), and Ns is the number of turns in the secondary coil (20 turns in this case).
We can rearrange this equation to solve for Vs:
Vs = Vp * Ns/Np
Plugging in the given values, we get:
Vs = 120 volts * 20/200
Vs = 12 volts.
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How many moles of magnesium hydroxide, used to treat heartburn and indigestion, is
manufactured from the reaction of 2.55 moles of magnesium oxide and excess water?
2.55 moles of magnesium oxide will produce 2.55 moles of magnesium hydroxide.
What is magnesium hydroxide ?
Magnesium hydroxide (Mg(OH)2) is an inorganic compound that is commonly used as an antacid and laxative to treat heartburn, indigestion, and constipation. It is a white, odorless, and tasteless powder that is slightly soluble in water.
The balanced chemical equation for the reaction between magnesium oxide and water to form magnesium hydroxide is:
MgO + H2O → Mg(OH)2
From the equation, we can see that 1 mole of MgO reacts with 1 mole of H2O to produce 1 mole of Mg(OH)2.
Therefore, if 2.55 moles of MgO react with excess water, then the number of moles of Mg(OH)2 produced will also be 2.55 moles.
So, 2.55 moles of magnesium oxide will produce 2.55 moles of magnesium hydroxide.
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How many moles of cl2 are there in 26.5mL Of gas measured at step?
Answer:
n = 0.012 moles
Explanation:
Recall that;
n = V note: V in dm³
22.4
V = 26.5 mL = 0.265 dm³
n = 0.265
22.4
n = 0.012 moles