We are given the following expression:
[tex]4y+3+6x[/tex]The numerical coefficient is the number that multiplies a variable, in this case, the first variable is "y" and the numerical coefficient is 4.
The constant in an expression is the number that does not multiply any variable, in this case, the constant is 3.
what is 9=-1/4x+4 in standard form
The standard form in which the equation must be written is -1/4x = 5
Standard Equation FormStandard form is just another way to write a linear equation equation along with slope intercept form and point slope form.
Standard form appears in the form ax + by = c
Where a, b and c are integers and a must be positive
In the given equation 9 = -1/4x + 4, we can rewrite this into standard equation of line by
-1/4x + 4 = 9
-1/4x + 4 - 9 = 0
-1/4x - 5 = 0
-1/4x = 5
The standard form of the equation is -1/4x = 5
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hello! i need help on this question and the (select) questions have the options of 1997 to 2006
To find the average rate of change, we use the following formula
[tex]r=\frac{f(b)-f(a)}{b-a}[/tex]Where a = 1998, f(a) = 856, b = 2001, and f(b) = 1591.
[tex]r=\frac{1591-856}{2001-1998}=\frac{735}{3}=245[/tex](a) The average rate of change between 1998 and 2001 is 245.We use the same formula between 2002 and 2006, where a = 2002, f(a) = 1483, b = 2006, and f(b) = 745.
[tex]r=\frac{745-1483}{2006-2002}=\frac{-738}{4}=-184.5[/tex](b) The average rate of change between 2002 and 2006 is -184.5.(c) As you can observe, the population was increasing from 1997 to 2001.(d) The population was decreasing from 2001 to 2006.960 watts hour per how many watts hour does it consume in 4 days and 6 hours
Answer:
Explanation:
[tex]undefined[/tex]A plumber charges $14 for transportation and $30 per hour for repairs. Complete the expression that can be used to find the cost in dollars for a repair that takes h hours.An expression that can be used to find the cost in dollars for a repair that takes h hours is ____ + ____h.
A plumber charges $14 for transportation and $30 per hour for repairs.
Complete the expression that can be used to find the cost in dollars for a repair that takes h hours.
An expression that can be used to find the cost in dollars for a repair that takes h hours is ____ + ____h.
_______________________________________________________________________
Charges
14 + 30* h
________________________________
Answer
An expression that can be used to find the cost in dollars for a repair that takes h hours is _14___ + _30___h.
____________________________________________
30 per hour, if it's two hours then 60 for example
convert 85 degrees to radians
To convert 85 degrees to radians, consider:
[tex]\pi=180^o^{}[/tex]Let
[tex]x=85^o[/tex]Then
[tex]\begin{gathered} 180x=85\pi \\ x=\frac{85\pi}{180} \\ \\ =\frac{17}{36}\pi \end{gathered}[/tex]f(x) = 4x - 2 for x = 0
Substituting x = 0 into the function we get:
f(0) = 4(0) - 2
f(0) = 0 - 2
f(0) = -2
how many drahms areequivalent to 300 grains?
hello
to solve this question, we need to know how many grains is in 1 gram
[tex]\begin{gathered} 1\text{grams}=15.43\text{grains} \\ \end{gathered}[/tex]now let 300 grains be equal to x grams
[tex]\begin{gathered} 1\text{grams}=15.43\text{grain} \\ \text{xgrams}=300\text{grains} \\ \text{cross multiply both sides and solve for x} \\ x\times15.43=1\times300 \\ 15.43x=300 \\ \text{divide both sides by 19.44} \\ \frac{15.43x}{15.43}=\frac{300}{15.43} \\ x=\frac{300}{15.43} \\ x=19.44 \end{gathered}[/tex]300 grains will weigh 19.44g
Skis are listed by a manufacturer for $850, less trade discounts of 35% and 18%. What further rate of discount should be given to bring the net price to $446?
The Solution:
The listing price of the Skis by a manufacturer is $850.
A trade discount of 35% was allowed.
[tex]\begin{gathered} 35\text{ \% of \$850=0.35}\times850=\text{ \$297.50} \\ \text{Price}=850-297.50=\text{ \$552.50} \end{gathered}[/tex]Allowing an extra discount of 18%, we get
[tex]\begin{gathered} 18\text{ \% of \$}552.50=0.18\times552.50=\text{ \$99.45} \\ \text{Price}=552.50-99.45=\text{ \$453.05} \end{gathered}[/tex]We are required to find what further rate of discount should be given to bring the net price to $446.00
[tex]\begin{gathered} 453.05-446.00=7.05 \\ To\text{ find the required percentage of discount, we have} \\ \frac{7.05}{453.05}\times100=0.0155612\times100=1.55612\approx1.56\text{\%} \end{gathered}[/tex]Therefore, the correct answer is 1.56%
Solve the following expression when
r = 22
r
11+3+r
11 +3 + r
11+3 = 14
So 14 + 22 is 36
Ans:36
Hope this helps!
Find the values of w and x that makeup NOPQ a parallelogram. A. W = 1/2 X = 1/2 B. W = 3 X = 2 C. W = 2 X = 2 D. W = 3 X = 1/2 Please select the best answer from the choices Provided
Solution
Step 1:
Properties of Parallelograms Explained
1. Opposite sides are parallel. ...
2. Opposite sides are congruent. ...
3. Opposite angles are congruent. ...
4. Same-Side interior angles (consecutive angles) are supplementary. ...
5. Each diagonal of a parallelogram separates it into two congruent triangles. ...
6. The diagonals of a parallelogram bisect each other.
Step 2:
The diagonals of a parallelogram bisect each other.
[tex]\begin{gathered} The\text{ }diagonals\text{ }of\text{ }a\text{ }parallelogram\text{ }bisect\text{ }each\text{ }other. \\ w\text{ + 7 = 5w - 5} \\ and \\ \frac{3}{2x}\text{ = 3} \end{gathered}[/tex]Step 3
[tex]\begin{gathered} Solve\text{ for w:} \\ w\text{ + 7 = 5w - 5} \\ Add\text{ similar terms} \\ 7\text{ + 5 = 5w - w} \\ 12\text{ = 4w} \\ w\text{ = }\frac{12}{4} \\ w\text{ = 3} \end{gathered}[/tex]Step 4
[tex]\begin{gathered} Solve\text{ for x:} \\ \frac{3}{2x}\text{ = 3} \\ 3\times2x\text{ = 3} \\ \\ 6x\text{ = 3} \\ \\ x\text{ = }\frac{3}{6} \\ \\ x\text{ = }\frac{1}{2} \end{gathered}[/tex]Final answer
[tex]\text{w = 3 . x = }\frac{1}{2}[/tex]Pls help me :( thx ur the best
Answer:
here you go, but when you go to Kumon you should do the work that they give you, it helps in the long run I promise
----from a former Kumon student, now I grade papers for Kumon
Please mark Brainiest
Answers to page 1 -2
1) 1 1/2
2) 1 1/8
3) 32/63
4) 1 3/40
5) 31/60
6) 11/35
7) 11/35
8) 17/20
9) 1 1/24
10) 27/28
11) 5/6
12) 1/4
Answers to page 3-4
1) 13/24
2) 1 2/45
3) 11/20
4) 2/3
5) 4/5
6) 5/21
7) 1 1/35
8) 67/72
9) 52/165
10) 23/36
11) 9/10
12) 5/6
Those are all the answers. btw the slashes are the line between the fractions if u get what I mean. :)
A car's cooling system has a capacity of 20 quarts. Initially, the system contains a mixture of 7 quarts of antifreeze and 13 quarts of water. Water runs into the system at the rate of 1 gal min , then the homogeneous mixture runs out at the same rate. In quarts, how much antifreeze is in the system at the end of 5 minutes? (Round your answer to two decimal places.)
After 5 minutes there will be 2.29376 quarts of antifreeze in the system.
Given,
The capacity of the cooling system of a car = 20 quarts
The mixture in the system is 7 quarts of antifreeze and 13 quarts of water.
The running rate of water = 1 gal/min
Homogenous mixture also runs 1 gal/min
We have to find the antifreeze in the system at the end of 5 minutes;
Here,
1 quart = 0.25 gallons
7 x 0.25 = 1.75 gallons of antifreeze
13 x 0.25 = 3.25 gallons of water
1 = 0.2 of 5
Minute 1 = 1.75 x 0.8 = 1.4Minute 2 = 1.4 x 0.8 = 1.12Minute 3 = 1.12 x 0.8 = 0.896Minute 4 = 0.896 x 0.8 = 0.7168Minute 5 = 0.7168 x 0.8 = 0.573440.57344 gallons = 2.29376 quarts
After 5 minutes there will be 2.29376 quarts of antifreeze in the system.
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A pendulum swings through an angle of 14° each second. If the pendulum is 14 cm in length and the complete swing from right to left last two seconds what area is covered by each complete swing?
Answer;
[tex]\text{Area = 47.90 cm}^2[/tex]Explanation;
Firstly, we need a diagrammatic representation to get what is described in the question.
We have this as follows;
Now, from what we have here, the total angle swept by the pendulum moving from left to right is 28 degrees
To get the area, we simply need to find the area of the sector formed by the by pendulum
Mathematically, we have the area of a sector calculated as follows;
[tex]A\text{ = }\frac{\theta}{360}\times\pi\times R^2[/tex]theta is the angle made by the pendulum in one complete swing which is 28 degrees
pi is 22/7
R is the length of the pendulum which is 14 cm
Substituting these values in the formula above, we have it that;
[tex]\begin{gathered} A=\frac{28}{360}\times\frac{22}{7}\times14^2 \\ \\ A=47.90cm^2 \end{gathered}[/tex]Type your response in the box.Use the information in the table to determine some similarities and differences between linear and exponentialequations. Include observations about the forms of both equations and the placement of the independent variablein the equations.f(3) = 5(3)s() = 2x+55057121192
Ok let's talk about some similarities and differences between linear and exponential equations.
In the linear functions the rate of change is constant. While in the exponential fuctions the rate of change is not constant.
In linear function the graph is a straight line. in the exponential fuctions graph is an exponential curve.
In linear functions the placement of the independent variable is is multiplying a coefficient. In the exponential fuctions the placement of the independent variable is as the power of a coefficient.
a lampshade has a radius of 9in what is the circumference of the top of the shade use 3.4 to approximate Pi round your answer to the nearest whole number
The top of the lampshade is circular in shape
[tex]\begin{gathered} \text{The circumference of a circle = 2}\pi r \\ \text{where }\pi=3.14,\text{ r= radius of the circle} \\ \text{The radius , r=9 in} \\ \text{Circumference = 2 x 3.14 x }9 \\ \text{Circumference = }56.52\text{ in} \end{gathered}[/tex]The circumference of the top of the shade is 56.52 inches
What is the starting value of the exponential function below?
The starting value of an exponential function is the value that it takes when x=1.
In this case, we can see that y=3 when x=1.
Then, the starting value is equal to 3.
Kaylee read 1 book in 4 months. What was her rate of reading, in books per month? Give your answer as a whole number or a FRACTION in simplest form.On the double number line below, fill in the given values, then use multiplication or division to find the missing value.
If Kaylee read 1 book in 4 months, this means that in 1 month, she read 1/4 of the book. We can see this in the following figure:
Which term is −20,155,392 for the following sequence, assuming that the pattern continues?
2, −12, 72, −432, …
a9
a10
a11
a12
The term that is the −20,155,392 in the sequence is a₁₀.
How to solve sequence?The sequence below is a geometric sequence.
Therefore, a geometric sequence can be represented as follows:
nth term = arⁿ⁻¹
where
a = first termn = number of termsr = common ratioTherefore, let's find which term is −20,155,392 for the sequence.
2, -12, 72, -432
r = -12 / 2 = 72 / -12 = -432 / 72 = -6
a = 2
Hence,
nth term = arⁿ⁻¹
−20,155,392 = 2 × -6ⁿ⁻¹
−20,155,392 / 2 = -6ⁿ⁻¹
- 10077696 = -6ⁿ⁻¹
6ⁿ⁻¹ = 10077696
6ⁿ⁻¹ = 6⁹
n - 1 = 9
n = 9 + 1
n = 10
Therefore, it's the 10th term.
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The term −20,155,392 is the tenth in the given geometric sequence.
The given sequence is below which is in a geometric pattern
2, -12, 72, -432
Here first term (a) = 2
The common ratio (r) = -12 / 2
The common ratio (r) = -6
We know that the nth term of the geometric sequence is
Tₙ = arⁿ⁻¹
Here Tₙ = −20,155,392
⇒ −20,155,392 = arⁿ⁻¹
Substitute the values of a and r in the above equation,
⇒ −20,155,392 = 2 × -6ⁿ⁻¹
⇒ −20,155,392 / 2 = -6ⁿ⁻¹
Apply the division operation,
⇒ - 10077696 = -6ⁿ⁻¹
⇒ 6ⁿ⁻¹ = 10077696
⇒ 6ⁿ⁻¹ = 6⁹
Equating exponents of the base
⇒ n - 1 = 9
⇒ n = 10
Therefore, the term −20,155,392 would be the tenth in the given sequence.
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Find fractional notation of 87.5%
To find the fractional notation, we have to transform 87.5% into a fraction. To do that, we just have to divide the percentage by 100.
[tex]\frac{87.5}{100}[/tex]Then, we multiply each part by 10.
[tex]\frac{87.5\times10}{100\times10}=\frac{875}{1000}[/tex]At last, we simplify the fraction by 125 to get 7/8.
[tex]\begin{gathered} \frac{875}{125}=7 \\ \frac{1000}{125}=8 \end{gathered}[/tex]Hence, the given percent, in fractional notation, is 7/8.What is the slope of the line shown in the graph
what is the most important piece of the software in a computer
Answer:
Step-by-step explanation:
the operating system
Answer:
An operating system is the most important software that runs on a computer. It manages the computer's memory and processes, as well as all of its software and hardware. It also allows you to communicate with the computer without knowing how to speak the computer's language.
Brainliest please?
Hope this helps
Find the point-slope equation for the line through (0,-2) and (4,1)
ANSWER:
STEP-BY-STEP EXPLANATION:
We can calculate the value of the slope using the following formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]we replace each value and we will be left with the following:
[tex]undefined[/tex]10 i You spin the spinner and flip a coin. Find the probability of the compound event. 3 LD t The probability of spinning a number less than 3 and flipping tails is
Compound probability = probability of first event * probability of second event
Let the spinning of the spinner be event A(First event)
Recall,
Probability = number of favourable outcomes/total number of outcomes
The numbers lesser than 3 are 1 and 2. thus, favourable outcomes = 2
total outcomes = 5
P(A) = 2/5
For event B(second event)
The coin has only head and tail
P(B) = 1/2
Thus, the probability of spinning a number less than 3 and flipping tails is
2/5 * 1/2
= 1/5
Two buses leave a station at the same time and travel in opposite directions. One bus travels 16(km)/(h) slower than the other. If the two buses are 1040 kilometers apart after 4 hours, what is the rate of each busSolve using a system of linear equations
Let x be the velocity (rate of change ) of one of the buses. We know that the other one travels 16 km/h slower; this means that the second velocity is:
[tex]x-16[/tex]Now the combined velocity would be:
[tex]2x-16[/tex]We know that the distance is equal to time by velocity, then we have that:
[tex]4(2x-16)=1040[/tex]Solving for x we have:
[tex]\begin{gathered} 4(2x-16)=1040 \\ 2x-16=\frac{1040}{4} \\ 2x-16=260 \\ 2x=260+16 \\ 2x=276 \\ x=\frac{276}{2} \\ x=138 \end{gathered}[/tex]Therefore the rate of the faster bus is 138 km/h and the rate for the slower bus is 122 km/h.
-Зе - 10 - 4Solve and graph the inequality
The given inequality is expressed as
[tex]\begin{gathered} -\text{ 3e - 10 }\leq-4 \\ \end{gathered}[/tex]We would add 10 to both sides of the inequality. It becomes
[tex]\begin{gathered} -\text{ 3e - 10 + 10 }\leq-\text{ 4 + 10} \\ -\text{ 3e }\leq6 \end{gathered}[/tex]We would divide both sides by - 3. This would cause the inequality symbol to reverse. It becomes
[tex]\begin{gathered} \frac{-3e}{-3}\text{ }\ge\frac{6}{-3} \\ e\text{ }\ge-2 \end{gathered}[/tex]The graph would be
The shaded circle at the position of - 2 indicates that- 2 is inclusive
represent the following expressions as a power of the number a (a≠0):
(a^-1*a^-2)^-2
By using some exponent properties, we will see that the expression can be written as:
a^6
How to simplify the expression?
Here we need to use some exponent properties, these are:
(x^n)^m = x^(n*m)x^(-n) = (1/x)^nx^n*x^m = x^(n + m)Here we have the expression:
(a^(-1)*a^(-2))^(-2)
Using the third property we can write:
(a^(-1)*a^(-2))^(-2) = (a^(-1 - 2))^(-2) = (a^(-3))^(-2)
Now we use the first property:
(a^(-3))^(-2) = a^(-3*-2) = a^6
That is the expression simplified.
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If a2 -2ab + b2 = 9 and a
If a2 -2ab + b2 = 9 and a[tex]\begin{gathered} a^2-2ab+b^2=9 \\ a
Step 1
factorize
[tex]\begin{gathered} a^2-2ab+b^2=(a-b)^2 \\ \end{gathered}[/tex]then
[tex]\begin{gathered} (a-b)^2=9 \\ \sqrt{(a-b)^2}=\sqrt{9} \\ a-b=\pm3 \\ \\ aa-b=-3What is the image of (-5,1) after a dilation by a scale factor of 5 centered at the origin?
Explanation
Step 1
when you have a coordinate (x,y) and you want to get the image after a dilationi, make
[tex]\text{new image=(coordinate)}\cdot factor[/tex]then
let
coordinate=(-5,1)
dilation scale=5
now, replace
[tex]\begin{gathered} \text{new image=(coordinate)}\cdot factor \\ \text{new image=(-5,1)}\cdot5 \\ \text{new image=(}-25,5) \end{gathered}[/tex]I hope this helps you
Show that Polygon ZSCH
is a Scaled copy of
Polygon XJYN.
As ratio is not given, we cannot prove that they are scaled copy.
Define scaled copy.Corresponding portions, or parts that are at the same location in relation to the remainder of each figure, exist in both the original figure and its scaled copy. These components could be angles, points, or segments. Polygon 2, for instance, is a scaled-down version of Polygon 1. There is a point in Polygon 2 for each point in Polygon 1.
Given,
Polygon ZSCH is a Scaled copy of Polygon XJYN.
We simply calculate the ratio of the lengths of the two corresponding sides of two polygons to determine the scale factor. The scaling factor is known as such and the polygons are similar if the ratio is the same for all matching sides.
As ratio is not given, we cannot prove that they are scaled copy.
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please help me thank you