8. Find the polynomial function of degree 3 for the given conditions I.f(1) = 32 and x-2, x-3,x+1 are factors of the polynomial II.f(3) = -24 and 5,2,4 are zeros of the polynomial​

Answers

Answer 1

Part I

In factored form, [tex]f(x)=a(x-2)(x-3)(x+1)[/tex]. Substituting x=1,

[tex]f(1)=32=a(1-2)(1-3)(1+1)\\\\\implies 32=4a\\\\a=8\\\\\therefore f(x)=8(x-2)(x-3)(x+1)[/tex]

Part II

In factored form, [tex]f(x)=a(x-5)(x-2)(x-4)[/tex]. Substituting x=3,

[tex]f(3)=-24=a(3-5)(3-2)(3-4)\\\\\implies 24=2a\\\\a=12\\\\\therefore f(x)=12(x-5)(x-2)(x-4)[/tex]


Related Questions

determine the equation of line from the graph

Answers

Answer:

y = 2x

Step-by-step explanation:

The slope is 2.  Find a point on the line, to go back to the line, go up two and one to the right.  You will be back on the line.  This pattern repeats over and over and again.

WILL GIVE BRAINLOST TO BEST QUSTION

The cost of a ride in a taxi is $4 for the first half-mile plus a constant amount per half-mile after that. The sequence below shows the pattern of numbers that appear on the driver's screen.

2.50, 2.75, 3, 3.25, 3.50,...

Which of the following is the Recursive Function that can be used to determine f(x), the cost in dollars, for a ride in the tax of, x. half miles?

Answers

Answer:

I don't know men iam grade 7 student

Given:m angle 2+m angle 3 =180, angle 2 and angle 5 are supplementary
Prove:p l l q

Answers

The value of x is 29° and it's a supplementary angles.

What are supplementary angles?

Supplementary angles simply means the angles that have a sum that is equal to 180°

In this case, we have been given two angles. It's important to equate them together. This will be illustrated as:

2x + 15 + 5x - 38 = 180

Collect like terms

7x - 23 = 180

Collect like terms

7x = 180 + 23

7x = 203

Divide

x = 203/7

x = 29°

The complete question is written below.

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Complete question

Given angle P is 2x + 15. and angle Q is 5x - 38. Prove that they are supplementary

4. En un vecindario, un camión de helados pasa cada 8 días y un food truck pasa cada 2
semanas. Se sabe que 15 días atrás ambos vehículos pasaron en el mismo día. Raúl M
cree que dentro de un mes los vehículos volverán a encontrarse y Oscar cree esto
ocurrirá dentro de dos semanas. ¿Quién está en lo cierto?

Answers

Answer:

???

Step-by-step explanation:

Is there a English version for this question?

Hey , I have a quick question about a Homework in math I got confused on how to solve the listed to formula [tex] \frac{x - 3}{2} - 4 \ \textless \ \frac{x}{3} [/tex]

Answers

Solution

- The question would like us to solve the following

[tex]\frac{x-3}{2}-4<\frac{x}{3}[/tex]

- The solution is outlined below:

[tex]\begin{gathered} \frac{x-3}{2}-4<\frac{x}{3} \\ \\ Collect\text{ like terms:} \\ Add\text{ 4 to both sides and Subtract }\frac{x}{3}\text{ from both sides} \\ \\ \frac{x-3}{2}-\frac{x}{3}<4 \\ \\ We\text{ need the LCM of 2 and 3. } \\ The\text{ LCM is }2\times3=6 \\ \\ Thus,\text{ multiply both sides by 6 in order to remove the denominator} \\ 2\frac{}{} \end{gathered}[/tex][tex]\begin{gathered} 6\left(\frac{x-3}{2}\right?-6\left(\frac{x}{3}\right?<4\times6 \\ \\ 3\left(x-3\right)-2x<24 \\ Expand\text{ the bracket} \\ 3x-9-2x<24 \\ x-9<24 \\ Add\text{ 9 to both sides} \\ x<33 \end{gathered}[/tex]

Final Answer

The answer is x < 33

The perimeter of a rectangle is 82 cm the length is 1 cm more than three times the width find the length and the width of the rectangle

Answers

The length will then be L = 18(41/19) = 738/19 cm.

As a check, the area should be A = LW = (738/19)(41/19) = 30258 cm2

sorry if this isn't much help but i had a similar problem once and i used the same steps for your question

24. The temperature in ° F on 20 days during the month of June
was as follows:
70° F, 76° F,
74° F, 74° F,
76° F,
78° F,
74° F,
76° F,
70° F, 70° F, 72° F,
78° F, 76° F,
74° F,
74° F, 78° F, 80° F,
80° F, 76° F
78° F

What is the mode of temperature for the month of June?

Answers

it’s between 74 and 76

Please help thank you

Answers

The value of the unknown angle in the triangle is as follows;

m∠S = 40 degrees

How to find the angle of a triangle?

The exterior angle theorem states that the measure of an exterior angle of a triangle is greater than either of the measures of the remote interior angles.

In other words,  an exterior angle of a triangle is equal to the sum of the two opposite interior angles.

The external angle is ∠JRS.

Therefore, m∠S can be found as follows:

∠JRS = m∠S + m∠T

Hence,

m∠S  = 3x + 4

m∠T = 8x + 4

∠JRS = 140°

Hence,

140 = 3x + 4 + 8x + 4

140 = 3x + 8x + 4 + 4

140 = 11x + 8

140 - 8 = 11x

132 = 11x

x = 132 / 11

x = 12

Therefore,

m∠S  = 3(12) + 4 = 40 degrees.

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DS
6) You and five friends went out to a movie. You all
shared a large tub of popcorn that cost $16.50,
and you ordered individual boxes of candy that
cost $3,72 per person. You and your friends decide
to split the bill evenly. How much did each of you
pay?

Answers

Answer:

You would each pay $6.42

Have a good one!

Solven - 8 + n = 1 -4n

Answers

We will solve as follows:

[tex]n-8+n=1-4n\Rightarrow2n+4n=1+8[/tex][tex]\Rightarrow6n=9\Rightarrow n=\frac{3}{2}[/tex]

Every rational number is positive.
A. True
B. False

Answers

Answer:

Step-by-step explanation: it is true because when the numerator and denominator both are positive integers both are negative integers it is a positive rational number.

help me please help :)

Answers

Step-by-step explanation:

12/4 = x/8

1st: cross multiply

96 = 4x

2nd: divide both sides by 4

96/4 = 4x/4

therefore x = 24

FInd the probability that a student walks to school

Answers

The probability that a student walks to school is 7/15

How to determine the probability of walking to school?

The tree diagram represents the given parameter

From the tree diagram, we have the following parameters

P(Rain) = 2/5

P(Rain and walk) = 1/6

P(No rain) = 3/5

P(No rain and walk) = 2/3

The probability of walking to school is then calculated as

P = P(Rain) x P(Rain and walk) + P(No rain) x P(No rain and walk)

Substitute the known values in the above equation

So, we have

P = 2/5 x1/6 + 3/5 x 2/3

Evaluate the products

P = 1/15 + 6/15

Evaluate the sum

P = 7/15

Hence, the probability is 7/15

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the population of a city will quadruple in 15 years. if its current population is 6,000, using the given rate of change, what will its approximate population be 7 years from now

Answers

Answer:

11200

Step-by-step explanation:

Write the following phrase as an algebraic expression. Use n for “a number."three increased by the quotient of a number and twoa 3+n / 2b.3+ n/2c. 3(n+ 2)d. 3+2n

Answers

The problem states that "three increased by a quotient", this implies that the three is separated from the quotient, therefore, we need to create the equation in the following manner:

[tex]3\text{ + }\frac{n}{2}[/tex]

The correct answer is "b".

juan went out to eat dnner,and the meal cost $60.00.If juan recived a 18% discount,what was the total value of the discount

Answers

Multiply by the decimal form of the percentage,

60 * 0.18 = 1.08

So the discount is for $1.08 off,

60 - 1.08 = 58.92

Giving a total of $58.92 after the discount is applied

please help tell me if correct or not

Answers

It is actually C, x = 11, because -11^2 would not equal to 121, like 11^2 would.

I need help with number 16 can I please get help?

Answers

We will break apart the figure into triangles, rectangles, squares etc. We will then find area of each individual figure and sum it.

We can break apart the figure as shown below:

Question 1

A triangle has sides of length 2 cm, 8 cm and 9 cm.
Calculate the value of the largest angle in this triangle.

Answers

Answer: You have to use a calculator

Step-by-step explanation:

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At 6:00 A.M. the temperature was 5°F below zero. At noon the temperature was 2°F above zero. At 6:00 P.M. the temperature was 7°F above zero. Which equation shows the change in temperature from 6:00 A.M. to 6:00 P.M.?

A. |5 – 7| = |–2| = 2°F

B. |2 – 7| = |–5| = 5°F

C. |–5 – 2| = |–7| = 7°F

D. |–5 – 7| = |–12| = 12°F

Answers

Based on the temperature at 6:00 am and the temperature at 6:00pm, the change in temperature can be shown by the formula D. |–5 – 7| = |–12| = 12°F.

How to find the change in temperature?

To find the change in temperature, you need to subtract the temperature at 6: 00 pm from the temperature at 6: 00 am.

The change in temperature is therefore:

= | temperature at 6 am - temperature at 6pm |

= | -5 - 7 |

= | - 12 °F|

The absolute value of - 12 °F is 12 °F which was therefore the change in temperature.

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given l || m || n, find the value of x

Answers

Answer:

x = 10

Step-by-step explanation:

(5x + 3) and 53 are corresponding angles and are congruent , then

5x + 3 = 53 ( subtract 3 from both sides )

5x = 50 ( divide both sides by 5 )

x = 10

The value of 'x' is highlighted in the box

In terms of ln(4) and ln(5), rewrite the expression: ln 500

Answers

Answer:

2ln5 + ln4 + ln5

Step-by-step explanation:

Think about how we can write 500 in terms of 4 and 5.

[tex]500 = 5^2*(4*5)[/tex]

So ln(500) can be written as ln(5^2*4*5)

Using log rules [tex]log_b(x*y)=log_b(x)+log_b(y)\\logb(x^a)=a*log(x)[/tex]

we can rewrite ln(500) to 2ln5 + ln4 + ln5

Select the correct answer.

What is the range of the function shown on the graph above?
A. -9 [tex]\leq[/tex] y [tex]\leq[/tex] 8
B. -7[tex]\leq[/tex] y [tex]\leq[/tex] -2
C.-8[tex]\leq[/tex] y [tex]\leq[/tex] 8
D.-2 [tex]\leq[/tex] y [tex]\leq[/tex] -7

Answers

Answer:

A

Step-by-step explanation:

The range is the y values.  The y value is as low as -10 and as high as 8.

To resolve 2(1-i) z² + (1+i) z + 3 (1 - i) = 0

Answers

Given:

There are given the complex equation:

[tex]2(1-i)z^2+(1+i)z+3(1-i)=0[/tex]

Explanation:

To find the value, we need to put the standard value of z into the above-given complex function:

[tex]\begin{gathered} 2(1-\imaginaryI)z^2+(1+\imaginaryI)z+3(1-\imaginaryI)=0 \\ 2(1-\imaginaryI)(x+yi)^2+(1+\imaginaryI)(x+yi)+3(1-\imaginaryI)=0 \end{gathered}[/tex]

Then,

[tex]\begin{gathered} 2(1-\imaginaryI)(x+y\imaginaryI)^2+(1+\imaginaryI)(x+y\imaginaryI)+3(1-\imaginaryI)=0 \\ (2x^2-2y^2+4xy+x-y+3)+i(-3+x+y-2x^2+2y^2+4xy)=0 \end{gathered}[/tex]

Then,

[tex](2x^2-2y^2+4xy+x-y+3)+\imaginaryI(-3+x+y-2x^2+2y^2+4xy)=0+0i[/tex]

So,

[tex]\begin{gathered} (2x^2-2y^2+4xy+x-y+3)+\imaginaryI(-3+x+y-2x^2+2y^2+4xy)=0+0i \\ 2x^2-2y^2+4xy+x-y+3=0 \\ -3+x+y-2x^2+2y^2+4xy=0 \end{gathered}[/tex]

Then,

[tex]\begin{gathered} x=0,y=-\frac{3}{2} \\ x=0,y=1 \end{gathered}[/tex]

Final answer:

Hence, the value of the given complex function is shown below:;

[tex]\begin{gathered} z=-\frac{3}{2}i \\ z=i \end{gathered}[/tex]

2g + (g + 5) >= 6g - 10 whats the solution set?

Answers

Answer: g ≤ 5

Step-by-step explanation: 2g + (g + 5) >= 6g - 10 ⇒ g ≤ 5

about 4% of the population has a particular genetic mutation. 300 people are randomly selected. find the standard deviation for the number of people with the genetic mutation in such groups of 300.

Answers

The standard deviation is a statistic that expresses how much variance or dispersion there is in a group of numbers. While a high standard deviation suggests that the values are dispersed throughout a wider range, a low standard deviation suggests that the values tend to be close to the established mean.

How to calculate the probability distribution's mean: Steps

change every percentage to a decimal probability.Create a probability distribution table in step two. Multiply each column's values. Combine the outcomes from step 3.

A specific genetic mutation affects 4% of the population. 300 persons are chosen at random. Find the standard deviation for the proportion of the 300 groups who have the genetic mutation.

Standard deviation is calculated as follows: 0.04 * 0.93/300 * sqrt(p*(1-p)/n) (0.000124).

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Add −1 3/10+2/5 using the number line.

Select the location on the number line to plot the sum.

Answers

The location on the number line to plot the sum of the given number is shown in the image attached below.

What is a number line?

In Mathematics, a number line simply means a type of graph with a graduated straight line which comprises both positive and negative numbers that are placed at equal intervals along its length.

This ultimately implies that, a number line primarily increases in numerical value towards the right and decreases in numerical value towards the left.

Note: Each interval on this number line represents 1/10.

Next, we would add the given numbers together as follows:

Number = −1 3/10 + 2/5

Number = −13/10 + 2/5

Number = (-13 + 4)/10

Number = -9/10 or -0.9.

Therefore, the sum would be located between -4/5 and -1.

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The area of a square is 144 square meters. What is the length (in meters) of one side of the square?

Answers

Answer:

12 m

Step-by-step explanation:

area = (side)²

(side)² = area

√(side)² = √(area)

side = √(area)

side = √(144 m²)

side = 12 m

oan, omb, apb and mpn are straight lines and an = 3oa. m is the midpoint of ob. oa = a ов = b ap = kab where k is a scalar quantity. express ab and mn in terms of a and b. express mp in terms of a, b and k. finally, find the value of k.

Answers

The values of the vectors obtained from the vector diagram are;

[tex]\overrightarrow{AB} = - a + b[/tex]

[tex]\overrightarrow{MN} = ( -2\cdot a + 0.5 \cdot b)[/tex]

[tex]\overrightarrow{MP} = ( -0.5\cdot b + a+ K \cdot ( - a + b)[/tex]

K = 2.5

What is a vector in geometry?

A vector can be expressed as a line segment that has a direction.

The given parameters are;

The straight lines are; OAN, OMB, APB, and MPN

AN = 3•OA

The midpoint of OB = M

The vectors

[tex] \overrightarrow{OA} = a[/tex]

[tex] \overrightarrow{OB} = b[/tex]

[tex]\overrightarrow{AP} = K \cdot \overrightarrow{AB} [/tex]

From the question diagram, we have;

[tex]\overrightarrow{AB} = - a + b[/tex]

[tex]\overrightarrow{AP} = K \cdot ( - a + b)[/tex]

[tex]\overrightarrow{MN} = ( -2\cdot a + 0.5 \cdot b)[/tex]

[tex]\overrightarrow{AN} [/tex] = 2•a

[tex]\overrightarrow{NP} = \overrightarrow{AP} - \overrightarrow{AN} [/tex]

[tex]\overrightarrow{NP} = -2\cdot a + K \cdot ( - a + b)[/tex]

[tex] \overrightarrow{MB} = 0.5 \cdot b[/tex]

[tex]\overrightarrow{PB} = -a + b - K \cdot ( - a + b)[/tex]

[tex]\overrightarrow{MP} =0.5 \cdot b - -a + b - K \cdot ( - a + b) = ( -0.5\cdot b + a+ K \cdot ( - a + b)[/tex]

[tex]\overrightarrow{MP} = ( -0.5\cdot b + a+ K \cdot ( - a + b)[/tex]

Given that we can write;

[tex]x \cdot \overrightarrow{NP} = \overrightarrow{NM}[/tex]

x × (-2•a + k•(-a + b)) = -3•a + 0.5•b

-2•x•a - k•x•a + x•k•b = -3•a + 0.5•b

Which gives;

-2•x - k•x = -3...(1), and x•k = 0.5...(2)

From (2), x = 0.5÷k

From (1), -2×(0.5÷k) - k×(0.5÷k) = 3

-k - 0.5 = -3

-k = -3 + 0.5 = -2.5

k = 2.5

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Hello I am not sure for what to do for the end of the equation.

Answers

ANSWER

25

EXPLANATION

We are given that p and q intersect to form <1 and <2 that are adjacent.

Let us represent that with a diagram:

We have that <1 and <2 are supplementary.

This means that they add up to 180 degrees.

So:

<1 + <2 = 180

4x - 3 + 3x + 8 = 180

Collect like terms:

4x + 3x + 5 = 180

7x = 180 - 5

7x = 175

x = 175 / 7

x = 25

That s the value of x for which <1 and <2 are supplementary.

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