Answer:
I don't know why 27.6 g is not the correct answer. I believe that it is correct.
27.6 grams of [tex]H_{2}[/tex].
Explanation:
The balanced equation tells us that 17 moles of hydrogen will react completely with 8 moles of carbon monoxide. That is a molar ratio of 17/8 moles H2/molesCO.
If we start with 6.5 moles of CO, we need:
(6.5 moles CO)*(17/8 moles H2/moles CO) = 13.8 moles of H2 (3 sig figs)
Convert 13.8 moles of H2 into grams H2 by multiplying by the molar mass iof H2 (2g/mole):
(13.8 moles H2)*(2 g H2/mole H2) = 27.6 grams of [tex]H_{2}[/tex].
17) 4NH3 + 502 → 4NO + 6H2OIf 73 grams of NH3 are reacted and 101 grams of H20 are actually produced, what is the percentyield?
Answer
%Yield = 87.2%
Explanation
Given:
mass of NH3 reacted = 73 g
mass of H2O produced = 101 g
We know:
molar mass of NH3 = 17,031 g/mol
molar mass of water = 18.01528 g/mol
Required: % Yield
Solution:
The formula used to calculate the percentage yield is:
%Yield = (actual yield/theoretical yield) x 100
The actual yield of H2O produced = 101 g
Now lets calculate the theoretical yield first.
First find the number of moles of NH3, and use stoichiometry to find the theoretical mass of water.
n = m/M n is the moles, m is the mass and M is the molar mass.
n = 73/17,031 g/mol
n = 4.29 mol
Using the stoichiometry, there molar ratio between NH3 and H2O is 4:6
Therefore the moles of H2O = 4.29 x (6/4)
n of H2O = 6.43 mol
The theoretical mass can then be calculated:
m = n x M
m = 6.43 mol x 18.01528 g/mol
m = 115.83 g
%Yield = (101 g/115.83)*100
%Yield = 87.2%
naoh is hygroscopic, meaning it absorbs water from the air. you can measure the amount of water it absorbs by taking its mass before and after removing the water in an oven (by the difference in mass before and after). would you use an analytical or top-loading balance for this?
It is better to use the analytical balance for smaller amounts of sodium hydroxide (up to a couple of grams).
The sensitivity of the analytical balance goes to a couple of tenths of a milligram, while the sensitivity of a top-loading balance goes to tens of milligrams at best. The amount of water absorbed by sodium hydroxide is significant, but not too great relative to the mass of the sample. With this in mind, it is far more recommendable to use the analytical balance over the top-loading balance in order to be able to register the change in mass at all.
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Which value is equivalent to 660.3 °C on the Kelvin temperature scale?
349.06 K
1,220.54 K
933.45 K
387.15 K
The difference between a kelvin (K), which is a division of the kelvin scale, and a degree on the Celsius scale is where zero is. The zero point on the Kelvin scale is at absolute zero, whereas the zero point on the Celsius scale is the freezing point of water. As a result, 0oK equals -273.15oC and 0oC equals 273.15 kelvins.
Answer : C.933.45K
How come 0 C is 273 Kelvin?At 0 degrees Celsius, or 273 Kelvin, water freezes. Also, -273 degrees Celsius are the same as 0 Kelvin. Therefore, multiply the Celsius degree by 273 to convert it to Kelvin. And to convert from Kelvin to Celsius, just take 273 out.
Celsius to Kelvin conversion: Kelvin = Celsius + 273 1.5. The figure of 273 is also used instead of 273.15
Solution :
K = ° C + 273.15
K = 660.3 + 273.15
K = 933.45
Answer :660.3°C = 933.45k
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I need help with this pls it due tomorrow and I need it please please
Answer: Physical - Color, density, boiling/melting point, magnetism, texture, and odor
Chemical - reactivity, combustibility, color change, and temperature change
Explanation:
Physical properties are changes to a substance that can be reversed and refer to its state at the time. Chemical properties are properties that are observable during or after a chemical reaction and cannot be reversed since the reaction has changed the state of the substance.
Distillation is a process used to separate a mixture of liquids based on different
a. boiling points
b.
densities
freezing points
d. solubilities
Answer:
freezing points hope it helps u
Distillation is a process used to separate a mixture of liquids based on different freezing points. Therefore, option C is correct.
What is distillation ?Distillation is the process of turning a liquid into a vapor, which is then condensed back into a liquid state. The simplest illustration of it is when steam from a kettle condenses into drops of distilled water that are left on a cold surface.
In general, distillation is the process of vaporizing a liquid to its boiling point, then condensing it back into a liquid to separate it from impurities or other solutes.
Among the many industrial uses of distillation are the production of alcoholic drinks, water purification, and oil refining. Distillation is a physical procedure that removes desired pure compounds from an initial source using heat and other techniques.
Thus, option C is correct.
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diazomethane is a highly poisonous, explosive compound because it readily evolves n2. diazomethane has the following composition by mass: 28.57% c; 4.80% h; and 66.64% n. the molar mass of diazomethane is 42.04 g>mol. find the molecular formula of diazomethane, draw its lewis structure, and assign formal charges to each atom. why is diazomethane not very stable? explain.
The molecular formula of diazomethane is CH₂N₂, and the main reason for its instability is precisely the fact that it can very easily evolve nitrogen, as nitrogen's triple bond is one of the strongest covalent bonds in nature, and the energy released in its formation is more than enough to compensate the energy lost in the breaking of C-N bonds. The Lewis structure of diazomethane with the formal charges is attached below.
To obtain the molecular formula of diazomethane, we can imagine that we have 100 g of it. Now we can calculate the number of moles (n) for each of the elements, using their respective masses (m) and molar masses (M = 12 g/mol for carbon, 1 g/mol for hydrogen, and 14 g/mol for nitrogen):
n = m/M
n(C) = 28.57 g / 12 g/mol
n(C) = 2.38 mol
n(H) = 4.80 g / 1 g/mol
n(H) = 4.80 mol
n(N) = 66.64 g / 14 g/mol
n(N) = 4.76 mol
We now divide each of these numbers with the smallest of them (2.38) to calculate the molar ratio of the elements:
carbon: 2.38 / 2.38 = 1
hydrogen: 4.80 / 2.38 = 2
nitrogen: 4.76 / 2.38 = 2
Now we use these numbers to get the empirical formula of diazomethane: CH₂N₂.
The molar mass of the empirical formula is:
12 g/mol + 2 * 1 g/mol + 2 * 14 g/mol = 42 g/mol
Since this value is equal to the molar mass given to us, that means that CH₂N₂ is also the molecular formula of diazomethane.
what mass of magnesium bromide is formed when one grams of magnesium reacts with 5 g of bromine
Taking into account the reaction stoichiometry, a mass of 7.57 grams of MgBr₂ is formed when one grams of magnesium reacts with 5 g of bromine.
Reaction stoichiometryIn first place, the balanced reaction is:
Mg + Br₂ → MgBr₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
Mg: 1 moleBr₂: 1 moleMgBr₂: 1 moleThe molar mass of the compounds is:
Mg: 24.31 g/moleBr₂: 159.8 g/moleMgBr₂: 184.11 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
Mg: 1 mole ×24.31 g/mole= 24.31 gramsBr₂: 1 mole ×159.8 g/mole= 159.8 gramsMgBr₂: 1 mole ×184.11 g/mole= 184.11 gramsLimiting reagentThe limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.
Limiting reagent in this caseTo determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 24.31 grams of Mg reacts with 159.8 grams of Br₂, 1 grams of Mg reacts with how much mass of Br₂?
mass of Br₂= (1 grams of Mg× 159.8 grams of Br₂) ÷24.31 grams of Mg
mass of Br₂= 6.57 grams
But 6.57 grams of Br₂ are not available, 5 grams are available. Since you have less mass than you need to react with 1 grams of Mg, Br₂ will be the limiting reagent.
Mass of MgBr₂ formedConsidering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 24.31 grams of Mg form 184.11 grams of MgBr₂, 1 grams of Mg form how much mass of MgBr₂?
mass of MgBr₂= (1 grams of Mg× 184.11 grams of MgBr₂)÷ 24.31 grams of Mg
mass of MgBr₂= 7.57 grams
Then, a mass of 7.57 grams of MgBr₂ can be produced.
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A salvage yard contains a mixture of iron, glass, aluminum, and plastic. which property of iron does the salvage yard take advantage of when separating the iron from the rest of the materials?
Magnetic property of iron will help in seperating iron from rest of the materials.
Iron is a metal and have magnetic property. Magnetic property is property of metal in which metal has the attraction power to attract other metal. Iron is ferromagnetic but it requires certain temperature and certain conditions. It occurs below 770°C, which is curie temperature.
There are 5 magnetic properties
Property 1: Intensity of magnetisationProperty 2: Magnetic Field (H) or Magnetic intensity. Property 3: Magnetic susceptibilityProperty 4: RetentivityProperty 5: Coercivitytypes of magnetic materials
Diamagnetic Material,Paramagnetic Materials,Ferromagnetic Materials,Antiferromagnetic Materials,Ferrimagnetic Materials.
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a solution contains an unknown hazardous chemical. we will call it chemical x. you must determine the concentration in molarity for chemical x in that solution. you know that the solution has 36% by mass of chemical x. you know that the molecular mass of chemical x is 36.46g and you know that the density of the solution is 1.18 g/ml. what is the concentration in molarity for the chemical x in this solution?
The molarity of the chemical X is 11.65 M.
To calculate the molarity (c) of the solution, we need the number of moles (n) of substance X and the volume (V) of the solution. We can assume that we have 100 mL = 0.1 L of the solution. Now we have the volume, and we can use it to calculate the mass (m) of the solution using its density (d = 1.18 g/mL):
d = m/V ⇒ m = d * V
m = 1.18 g/mL * 100 mL
m(solution) = 118 g
From this, we can obtain the mass of substance X using the mass percentage (%w = 36% = 0.36):
m(X) = %w * m(solution)
m(X) = 0.36 * 118 g
m(X) = 42.48 g
Now that we have the mass of X, we divide it by its molar mass (M = 36.46 g/mol) to obtain the number of moles:
n = m/M
n = 42.48 g / 36.46 g/mol = 1.165 mol
Finally, we calculate the molarity of the solution:
c = n/V
c = 1.165 mol / 0.1 L = 11.65 M
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Beryllium, the first element in group 2, has an atomic number of 4. The second element in this group has an atomic number of.
The second element in group 2 has an atomic number of 12.
We can describe atomic number as the number of protons that are present in the nucleus of an atom. The number of protons is equal to the number of electrons, hence the atomic number is the number of protons or the number of electrons in an atom.
Beryllium has an atomic number of 4 because the element Beryllium has 4 protons.
In the periodic table, you will find that the second element in group 2 is Magenium. The atomic number of Magnesium is 12 because Magnesium has 12 protons in the nucleus of its atom.
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help me please!
What pressure will be required for neon at 30°C to have the same density as nitrogen at 20°C and 1.0 atm?
Ideal gas law is valid only for ideal gas not for vanderwaal gas. Therefore, the pressure that will be required for neon at 30°C to have the same density as nitrogen at 20°C and 1.0 atm is 1.44atm.
What is ideal gas equation?
Ideal gas equation is the mathematical expression that relates pressure volume and temperature. There is no force of attraction between the particles.
Mathematically the relation between Pressure and temperature can be given as
P₁M₁=DRT₁
P₂M₂=DRT₂
Rearranging the two equation we get
P₁M₁÷T₁=P₂M₂÷T₂
where,
P = pressure
M= Molarity
D=density
T =temperature
R = Gas constant = 0.0821 L.atm/K.mol
Substituting all the given values, we get
(P₁×M₁)÷T₁=(P₂×M₂)÷T₂
(P₁×20)÷303=(1.0 ×28)÷293
P₁=1.44atm
Therefore, the pressure that will be required for neon at 30°C to have the same density as nitrogen at 20°C and 1.0 atm is 1.44atm.
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a 17.27 gram sample of aluminum initially at 92 oc is added to a container containing water. the final temperature of the metal is 25.1 oc. what is the total amount of energy in joules added to the water? what was the energy lost by the metal?
The heat released by metal and added to water is the same which is 1039.83 joule.
The equilibrium condition of the system depends on the heat released from both gold and water. The total heat received by the system will equal to total heat released by objects. It should follow
Q released = Q received
The heat can be defined by
Q = m . c . ΔT
where Q is heat, m is mass, c is the specific heat constant and ΔT is the change in temperature.
The given parameters are
m = 17.27 g = 0.01727 kf
T1 = 92 ⁰C
T2 = 25.1 ⁰C
c = 900 J/kg⁰C
By substituting the given parameters, we can calculate the heat
Q = m . c . ΔT
Q = 0.01727 . 900 . (92 - 25.1)
Q = 1039.83 joule
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a flexible container at an initial volume of 8.15 l contains 9.51 mol of gas. more gas is then added to the container until it reaches a final volume of 15.5 l. assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.
The number of moles added to increase the volume of the gas from 8.51 L to 15.5 L is 8.67 moles.
The initial volume of the gas is 8.15 L and final volume of gas is 15.5 L and the initial moles are 9.51 moles.
As per the Ideal gas equation,
PV = nRT
where,
P is pressure,
V is volume of gas,
n is the number of moles of gas,
R is the gas constant,
T is the temperature of the gas.
Rearranging the equation,
V/n = RT/P
The left side is constant, so, it is valid to see,
V₁/n₁ = V₂/n₂
V₁ is initial volume,
n₁ is the initial moles,
V₂ is the final volume,
n₂ is the final moles.
So, we can write this by putting the values,
8.51/(9.5) = 15.5/n₂
n₂ = 18.17
The number of moles added = n₁ - n₂
Added moles = 8.67 moles
The moles added are 8.67 moles.
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suppose there is a gaseous mixture of nitrogen and oxygen. if the total pressure of the mixture is 490 mmhg , and the partial pressure of nitrogen is 210 mmhg , calculate the partial pressure of oxygen in the mixture using dalton's law.
The partial pressure of Oxygen in the mixture is 280 mmHg.
The Sum of the partial pressure of elements in a solution equals the total pressure of the mixture as stated by Dalton's Law.
Total pressure = Partial pressure of Nitrogen + Partial pressure of Oxygen
P' = P₁ + P₂
The partial pressure is the pressure that each gas would exert if it alone occupied the volume of the mixture at the same temperature.
The system responds to changes in pressure, temperature, and chemical composition, phases may be created, eliminated, or altered in composition.
∴ 490 = 210 + P ₂
P₂ = 280 mm of Hg
Hence, the partial pressure of oxygen gas is 280 mm Hg.
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If you assumed 100 total atoms in a sample, how could you relate the % values shown in the sim into a number you could use for your calculation of average atomic mass?
If you assumed 100 total atoms in a sample, you could relate the % values shown in the sim into a number you could use for your calculation of average atomic mass is
Average atomic mass = ∑ ( isotope mass × % of abundance )
To calculated the average atomic mass, we have to multiply the isotopes mass of each to the % abundance then add .
the formula for the calculation of average atomic mass :
Average atomic mass = ∑ ( isotope mass × % of abundance )
Thus, If you assumed 100 total atoms in a sample, you could relate the % values shown in the sim into a number you could use for your calculation of average atomic mass is
Average atomic mass = ∑ ( isotope mass × % of abundance )
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2NaOH + CO₂ = Na₂CO3 + H₂O
Is this equation balanced?
Balanced chemical equation :
A balanced equation is a chemical reaction equation in which the total charge and the number of atoms for each element in the reaction are the same for both the reactants and the products.
Given Equation :
[tex]2NaOH_{}[/tex] + [tex]CO_{2}[/tex] = [tex]Na_{2}CO_{3}[/tex] + [tex]H_{2}O[/tex]
Here, we have 2 sodium (Na) atoms, 4 Oxygen (O) atoms, 2 Hydrogen (H) atoms and 1 Carbon (C) atom on the left hand side of the equation (reactants).
Also we have 2 sodium (Na) atoms, 4 Oxygen (O) atoms, 2 Hydrogen (H) atoms and 1 Carbon (C) atom on the right hand side of the equation (products).
Hence , the given equation, [tex]2NaOH_{}[/tex] + [tex]CO_{2}[/tex] = [tex]Na_{2}CO_{3}[/tex] + [tex]H_{2}O[/tex] is a balanced chemical equation.
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The Dart Frog is a brightly colored frog. These bright colors could mean that this frog is poisonous, warning predators to stay away. Plants in the rainforest are normally crowded and have very little space. The big leaves of a Hosta Plant allow the plant to receive as much sunlight as possible when the sun is out.
What type of adaptations are these? Compare and contrast the adaptations of the Dart Frog and the Hosta Plant. Your answer should be 3–4 sentences long.
PLEASE HELP!! OPTIONS: LIFE CYCLE>PHYSICAL>BEHAVIORAL ADAPTION(ILL GIVE 20 POINTS!!)
The type of adaptation shown by the dart frog is physiological adaptation while the one shown by the Hosta plant is structural adaptation.
Types of adaptationAdaptation generally refers to the process by which living organisms adjust in order to continue to survive in an environment.
There are 3 main types of adaptations:
Behavioral adaptationsPhysiological adaptationsStructural adaptationsIn behavioral adaptation, organisms change their behavior for their continued survival in their environments. Without these modifications, they may find it to survive and reproduce in the environment.
Physiological adaptation refers to changes that are encoded into the system of organisms. Changes that are not behavioral nor structural but ensure the continued survival of organisms in their environment.
Structural adaptation refers to the modification of physical structures for continued survival. These modifications become necessary because the environment keeps changing.
Thus, bright coloration as a warning to predators by the dart frog is a physiological adaptation while the development of big leaves that ensures that as much sunlight as possible is received by the Hosta plant is a structural adaptation.
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Determine the valence of elements in substances: SiH4 CrO3 H2S CO SO3 SO2 Fe2O3 FeO HCI HBr Cl2O5 Cl2O7 PH3 K2O Al2O3 P2O5 NO2 N2O5 Cr2O3 SiO2 B2O3 SiH4 Mn2O7 MnO CuO N2O3
Answer:
see the explanation
Explanation:
1. IV
2. VI
3. II
4. IV
5. II
6. VI
7. IV
8. III
9. II
10. I
11. I
12. V
13. VII
14. III
15. I
16. III
17. V
18. IV
19. V
20. III
21. IV
22. III
23. IV
24. VII
25. II
26. II
27. III
6. Classify the following as physical changes (PC), chemical changes (CC), physical properties (PP), and chemical properties (CP):
a. __An iron scorches a shirt when you leave it in one spot too long.
b. __ The tires on your car seem to be getting low in very cold weather.
c. __ Your grandmother's silver tea set gets black with tarnish over time.
d. __ Spray-on oven cleaner converts grease in the oven into a soapy material.
e. __ An ordinary flashlight battery begins to leak with age and can't be recharged.
f. __ Acids produced by bacteria in plaque cause teeth to decay.
g. __ Sugar chars if overheated while making homemade candy.
h. __ Hydrogen peroxide fizzes when applied to a wound.
i. __ Dry ice "evaporates" without melting as time passes.
The classification of the given processes as either physical changes (PC), chemical changes (CC), physical properties (PP), and chemical properties (CP): is as follows:
CC An iron scorches a shirt when you leave it in one spot too long.PC The tires on your car seem to be getting low in very cold weather.CC Your grandmother's silver tea set gets black with tarnish over time.CP Spray-on oven cleaner converts grease in the oven into a soapy material.CC An ordinary flashlight battery begins to leak with age and can't be recharged.CP Acids produced by bacteria in plaque cause teeth to decay.CC Sugar chars if overheated while making homemade candy.CP Hydrogen peroxide fizzes when applied to a wound.PP Dry ice "evaporates" without melting as time passes.What are physical and chemical changes?Physical changes are changes that occur in a substance that are easily reversible and only affect the physical properties of that substance.
In physical changes, no new substances are formed.
Some physical properties that may change in physical changes are color, taste, volume, mass, physical state, etc.
Chemical changes are changes that occur in a substance that are not easily reversible and which affect the chemical properties of that substance.
In chemical changes, new substances are formed.
Some chemical properties that may change in physical changes are oxidation state, combustibility, etc.
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Given: sulfur, 3.04 g, 1.47 cm³
Wanted: density of sulfur in g/cm³?
Answer:
2.068
Explanation:
D = M/V
3.04 /1.47
= 2.068
which of the following statements about a reaction rate is not true? group of answer choices reaction rate is the speed at which the reaction proceeds toward equilibrium. reaction rate is governed by the energy barrier between reactants and products. enzymes can accelerate the rate of a reaction. reaction rates are not sensitive to temperature. none of these.
The incorrect statement is, "reaction rate is the speed at which the reaction proceeds towards equilibrium".
The rate of the reaction is defined as the rate at which the reaction is taking place.
It is true that the rate of reaction is governed by the energy barrier between the reactant and the products.
Enzymes are special compounds which can accelerate the rate of reaction.
The rate of reaction is independent of the rate of temperature of the system. The rate of reaction depends on the concentration of the reactants.
Rate of the reaction is directly proportional to the increase in concentration of products.
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A chemist has a block of aluminum metal (density is 2.7 g/mL). The block weighs 1.9 g. What is the volume, in mL, of the aluminum block?
Answer: v = 0.70 ml
Explanation:
1. We can use the Density equation
(d = density (g/ml), m = mass (g), v = volume (ml))
D = m/v
2. Plug in what we have and solve for v.
2.7 = 1.9/v
v = 0.70 ml
A sample of 11.7 g of Fe2O3 reacts with 13.4 g CO to yield Fe and CO2.
The balanced chemical equation is:
Fe2O3(s)+3CO(g)⟶2Fe(s)+3CO2(g)
Which substance is the limiting reactant?
a. CO2
b. Fe
c. Fe2O3
d. CO
What is the theoretical yield of Fe?
mass of Fe: _________ g
If the actual experimental yield for Fe is 7.00 g, what is the percent yield of Fe?
percent yield: _________ %
In first place, the balanced reaction is:
Fe₂O₃ + 3 CO → 2 Fe + 3 CO₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
Fe₂O₃: 1 moleCO: 3 molesFe: 2 molesCO₂: 3 molesThe molar mass of the compounds is:
Fe₂O₃: 159.7 g/moleCO: 28 g/moleFe: 55.85 g/moleCO₂: 44 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
Fe₂O₃: 1 mole ×159.7 g/mole= 159.7 gramsCO: 3 moles ×28 g/mole= 84 gramsFe: 2 moles ×55.85 g/mole= 111.7 gramsCO₂: 3 moles ×44 g/mole= 132 gramsLimiting reagentThe limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction.
Limiting reagent in this caseTo determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 84 grams of CO reacts with 159.7 grams of Fe₂O₃, 13.4 grams of CO reacts with how much mass of Fe₂O₃?
mass of Fe₂O₃= (13.4 grams of CO× 159.7 grams of Fe₂O₃)÷ 84 grams of CO
mass of Fe₂O₃= 25.476 grams
But 25.476 grams of Fe₂O₃ are not available, 11.7 grams are available. Since you have less mass than you need to react with 13.4 grams of CO, Fe₂O₃ will be the limiting reagent.
Theoretical yieldThe theoretical yield is the maximum amount of product that could be formed from the given amounts of reagents.
Theoretical yield of FeConsidering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 159.7 grams of Fe₂O₃ form 111.7 grams of Fe, 11.7 grams of Fe₂O₃ form how much mass of Fe?
mass of Fe= (11.7 grams of Fe₂O₃×111.7 grams of Fe) ÷159.7 grams of Fe₂O₃
mass of Fe= 8.183 grams
Then, the theoretical yield of Fe is 8.183 grams.
Percent yieldThe percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.
The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:
percent yield= (actual yield÷ theoretical yield)×100%
Percent yield for the reaction in this caseIn this case, you know:
actual yield= 7 gramstheorical yield= 8.183 gramsReplacing in the definition of percent yield:
percent yield= (7 grams÷ 8.183 grams)×100%
Solving:
percent yield= 85.54%
Finally, the percent yield is 85.54%.
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Directions: Write the balanced equation for each of the following situations. . In addition, list the reaction type. YOU MUST TELL THE AMOUNTS OF EVERY SUBSTANCE THAT REMAINS IN THE CONTAINER AT THE END OF THE REACTION. ASSUME THAT ALL REACTIONS GO TO COMPLETION. If only STOICHIOMETRY, tell how much of the excess reactant is used!!!! Reaction Type a. Combination Reaction b. Decomposition Reaction c. Single Displacement / THIS IS ONE TYPE OF Oxidation Reduction Reaction d. Precipitation Reaction e. Gaseous Reaction f. Neutralization Reaction g. Combustion Reaction 5. 2.11 mg of hydrogen peroxide decomposes in the presence of manganese dioxide to form water and oxygen 5. Balanced Chemical Equation Reaction Type:At the completion of reactions: Grams of hydrogen peroxide: Grams of water: Grams of oxygen gas:
First, let's write the balanced chemical reaction:
2 H2O2 ---MnO2--> 2 H2O + O2
This reaction is a b. Decomposition Reaction of hydrogen peroxide.
Step 1. Let's transform 2.11 mg of H2O2 into moles using the following equation mole = mass / molar mass
Step 2. We are going to use the equation proportion to calculate the quantity in moles of each compound.
Step 3. We are going to transform moles into grams of each compound using the following equation: mass = mole x molar mass
Step 1.
We need to transform 2.11 mg to g. We just need to divide by 1000,
So: 2.11 x 10^-3 g of H2O
mole = 2.11 x 10^-3/34.02
mole = 6.20 x 10^-5 moles
Step 2.
2 moles of H2O2 ---- 2 moles of H2O
6.20 x 10^-5 moles ---- x moles of H2O
x = 6.20 x 10^-5 moles of H2O
2 moles of H2O2 ---- 1 moles of O2
6.20 x 10^-5 moles ---- x moles of O2
x = 3.10 x 10^-5 moles of O2
Step 3.
molar mass of O2 : 32 g/mol
molar mass of H2O: 18 g/mol
mass of H2O = 6.20 x 10^-5 x 18 = 1.12 x 10^-3 g
mass of O2 = 3.10 x 10^-5 x 32 = 9.92 x 10^-4 g
An engine overheats and causes a car to catch on fire- is this a physical or chemical property?
Answer:
physical
Explanation:
HAVE GREAT DAY!
Which of the following is true of electronegativity?
a) Noble gases are the most electronegative group of the periodic table.
b) The fewer protons found in the nucleus, the greater the electronegativity.
c) It describes the affinity an atom has for an electron.
d) Electronegativity increases as atomic radius increases.
Answer:
c) It describes the affinity an atom has for an electron.
Explanation:
C quite literally describes what electronegativity is, you can rule out most others by looking at periodic trends as attached below.
I need to determine electron configuration of rubidium and rubidium ion.
The atomic number of rubidium is 37, it means that its electron configuration is as follows:
[tex]1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^1[/tex]Rubidium is an alkali metal. Its ion is formed when it loses an electron. It means that the rubidium ion has 36 electrons instead of 37, and its configuration is as follows:
[tex]1s^22s^22p^63s^23p^64s^23d^{10}4p^6[/tex]The three isotopes of uranium are ^234<92U ^233<92 and ^232<92U how many proton neutron and electron are present in each isotopes
Answer: protons: 92
electrons: 92
1. neutrons: 234-92 = 142
2. Neutrons- 233-92 = 141
3. Neutrons 232-92= 140
Explanation:
Help please!!
Match the selected genotypes with the appropriate description.
For natural selection to cause evolution, it must select for or against one or more of the genotypes for a trait. In the simple case of a trait that is determined by a single gene with two alleles, there are five combinations of genotypes that nature can select:
1. either homozygote (AA or aa but not both)
2. both homozygotes (AA and aa)
3. either homozygote and the heterozygote (AA and Aa or aa and Aa)
4. the heterozygote (Aa)
5. all alleles (AA, Aa, and aa).
An example of disruptive selection because both extremes are favored to survive is a Selection for the homozygous dominant (AA).
The CCRS-delta 32 gene provided immunity to a deadly disease of bacterial origin, bubonic plague. People who are homozygous for the CCR5-della 32 gene variant are completely immune, while heterozygotes only have partial immunity and homozygous recessive have none is a Selection against the heterozygote and one homozygote.
Sickle cell disease - homozygous dominant contract malaria, homozygous recessive die young from sickle cell, heterozygotes immune to malaria is Selection for the heterozygote.
This type of selection will result in the extinction of the species as all genotypes are at a selective disadvantage is a Selection against all genotypes.
Huntington's disease is a single-gene disorder caused by a malfunctioning gene on chromosome 4. It is an autosomal dominant disease, which means that only one copy of the gene needs to be defective is a Selection against the heterozygote.
What are homozygotes and heterozygotes?Homozygotes are organisms that have the same copy of alleles for a given trait. For example, if the allele for height is H and h where H is the allele for tallness while h is for short.
The genotype of the homozygotes will be HH or hh
Heterozygotes are organisms that have different copies of alleles for a given trait. For example, if the allele for height is H and h where H is the allele for tallness while h is for short.
The genotype of the heterozygotes will be Hh.
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8. 00 g of ethane gas, c2h6, is burned in oxygen. What volume of carbon dioxide gas is produced at 1. 00 atm and 25. 0°c?.
By using the balanced reaction equation of ethane combustion, we can calculate that 12.8 L of carbon dioxide will be produced.
To calculate the answer to this, we need to write the balanced reaction equation:
2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O
Based on this, we can see that 2 moles of ethane produce 4 moles of carbon dioxide. Now, we need to calculate the number of moles (n) of ethane using its mass (m = 8.00 g) and its molar mass (M = 30.07 g/mol):
n = m/M
n = 8.00 g / 30.07 g/mol
n = 0.266 mol
Based on this, we can conclude that 2 * 0.266 mol = 0.532 mol of carbon dioxide was produced. Assuming that carbon dioxide acts as an ideal gas, we can use the ideal gas equation to calculate its volume:
PV = nRT ⇒ V = nRT/P
V - the volume of the gas
n - number of moles of gas (0.523 mol)
R - universal gas constant (0.08206 L*atm/K*mol)
T - temperature in Kelvins (25 °C = 298.15 K)
P - pressure (1.00 atm)
Now we plug all the known values into the equation:
V = 0.523 mol * 0.08206 L*atm/K*mol * 298.15 K / 1.00 atm
V = 12.8 L
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