9. a basketball whose mass is 0.540 kg falls from rest through a height of 5.65 m, and then bounces back. on its way up it, passes by a height of 3.25 m with a speed of 2.35 m/s. how much energy is lost during the bounce?

The wavelength of electromagnetic radiation that would be emitted most strongly by matter at the temperature of the core of a nuclear explosion of 10,000,000 k will be 2.898 × 10^-10 meters.

The wavelength of electromagnetic radiation emitted by matter at a certain temperature can be determined using Wien's displacement law, which states that the wavelength of maximum emission (λmax) is inversely proportional to the temperature of the object:

λmax = b / T

where b is a constant known as Wien's displacement constant, equal to 2.898 × 10^-3 m·K.

Substituting the given temperature of 10,000,000 K into this equation, we get:

λmax = (2.898 × 10^-3 m·K) / (10^7 K) = 2.898 × 10^-10 m

Therefore, the wavelength of electromagnetic radiation emitted most strongly by matter at the temperature of the core of a nuclear explosion is approximately 2.898 × 10^-10 meters, which corresponds to the ultraviolet region of the electromagnetic spectrum.

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The projectile will be moving at a speed of 57.21 m/s when it reaches the top of its trajectory.

When a projectile is fired at a speed of 138 and an upward angle of 65 degrees, the speed at the top of the trajectory can be calculated. To solve this problem, you need to understand some basic physics concepts. Here's how you can solve this problem:
1. First, identify the given values and write them down:
Initial velocity (u) = 138 m/s
Angle of projection (θ) = 65 degrees
Acceleration due to gravity (g) = 9.81 m/s²
2. Now, break down the initial velocity into its horizontal and vertical components:
Initial velocity in the horizontal direction = u cos θ
Initial velocity in the vertical direction = u sin θ
3. Use the equation of motion to calculate the time taken by the projectile to reach the top of its trajectory:
u sin θ = gt/2
t = 2u sin θ/g
4. Use the time obtained in step 3 to calculate the velocity at the top of the trajectory:
v = u cos θ
Where,
v = final velocity
u = initial velocity
θ = angle of projection
5. Substitute the given values in the equation to get the final answer:
v = u cos θ
v = 138 cos 65
v = 57.21 m/s
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The coefficient of static friction between the tires and the road if a car is to round a level curve of radius 145 m at a speed of 130 km/h is 4.64

Whenever the object rotаtes аround the curved pаth then а net force аcts on the object pointing towаrds the center of а circulаr pаth аnd it is cаlled а centripetаl force. Mаthemаticаlly, we cаn write;

Centripetаl Force = [tex]\frac{mv^{2} }{r}[/tex]

where m is the mass of the body, v is the velocity of the body, and r is the radius of rotation.

We are given:

Since the car is making circular motion, therefore, necessary centripetal force is provided by the frictional force.

frictional force = centripetal force

μsmg = [tex]\frac{mv^{2} }{r}[/tex]

μs = [tex]\frac{v^{2} }{rg}[/tex]

μs = [tex]\frac{81.25^{2} }{145.9.81}[/tex]

μs = 4.64

Therefore, the coefficient of static friction between the tires of the car and the road surface is 4.64.

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Through the coil, the magnetic flux rises. The coil will experience a voltage as a result. This voltage will cause a current to flow. The amount of the emf increases with speed and is 0 in the absence of motion.

A current will be induced in a coil of wire if it is exposed to a shifting magnetic field. Because of an electric field that is being generated, which drives the charges to move around the wire, current is flowing.

Self-Inductance: When current passes through a coil, a magnetic field and consequent magnetic flux are created.

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The formula for calculating capacitance is as follows:

C = Q/V

Where,

C = capacitance (Farads)

Q = charge (Coulombs)

V = voltage (Volts)

As given,

Q = 27.0 μC

V = 9.00 V

Substituting the given values in the above equation

C = 27.0 μC/9.00 V = 3.00 μF

Therefore, the value of capacitance is 3.00 μF.

The formula for calculating charge stored is as follows:

Q = CV

Where,

Q = charge (Coulombs)

C = capacitance (Farads)

V = voltage (Volts)

As given,

C = 3.00 μF

V = 12.0 V

Substituting the given values in the above equation,

Q = (3.00 × 10⁻⁶ F) × 12.0 V = 36.0 μC

Therefore, the charge stored is 36.0 μC.

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The bike and rider must halt at a breaking distance of 5.17 meters.

d=2.2v+fracv220 gives the braking distance, in feet, of a car moving at v miles per hour. Most motorcycle riders have a maximum braking force (what an experienced rider can do) of about 1 G, which, at 45 mph, results in a complete stop of the motorcycle in 67 feet (20 meters).

To resolve this issue, we can apply the equation of motion for uniformly accelerated motion:

v² = u² + 2as

To solve for s, we can rewrite the equation as follows:

s = (v² - u²) / (2a)

We are aware that the acceleration is determined by dividing the net force by the mass:

a = F_net / m

where m is the mass and F net is the net force.

a = F_net / m = -140 N / 82.0 kg

= -1.71 m/s²

We may now change the values for s in the equation:

s = (0² - 4.2²) / (2*(-1.71))

= 5.17 m

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Blood flows with a speed of 30 cm/s along a horizontal tube with a cross-section diameter of 1.6 cm.The speed of blood flow in the part of the same tube that has a diameter of 0.8 cm is 15 cm/s.

To arrive at this answer, we can use the formula for the flow rate of a fluid in a pipe:
Q = A × V
where Q is the flow rate, A is the cross-sectional area of the pipe, and V is the velocity of the fluid.
Therefore, if we substitute the values for A and V of the first section, we can calculate the flow rate for that section:
Q1 = A1 × V1
Q1 = π ×(1.6 cm/2)² × 30 cm/s
Q1 = 24.72 cm³/s
Now we can use the flow rate and the cross-sectional area of the second section to calculate the velocity of the fluid:
Q1 = A2 × V2
V2 = Q1 / A2
V2 = 24.72 cm³/s / (π × (0.8 cm/2)²)
V2 = 15 cm/s
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The correct free body diagram that describes the forces on the rock when the string is in one possible horizontal position is B.

As the rock swings in a vertical circle, there are a number of forces acting upon it. These forces are gravity, tension and centrifugal force. When the rock is in a horizontal position, its weight will be perpendicular to the tension force. This makes the tension force the only force acting upon the rock in the horizontal position.

As a result, the correct free body diagram that describes the forces acting on the rock when the string is in one possible horizontal position is B.

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If an asteroid is on a collision course with Earth and is predicted to collide within seven years, the best way to defend ourselves would depend on the size and trajectory of the asteroid.

An asteroid is a small, rocky object that orbits the Sun. Most asteroids are found in the asteroid belt, a region between the orbits of Mars and Jupiter. Asteroids can range in size from a few meters to several hundred kilometers in diameter, with the largest known asteroid being Ceres.

Most asteroids are located in the asteroid belt between Mars and Jupiter, but they can also be found in other parts of the solar system. Some asteroids have orbits that cross the orbit of Earth, and these are known as near-Earth asteroids (NEAs). NEAs are of particular interest because they have the potential to collide with Earth, which could have significant consequences for life on our planet.

Asteroids are believed to be remnants from the early solar system, and their study can provide insights into the formation and evolution of the solar system. In recent years, several space missions have been launched to study asteroids up close, including NASA's OSIRIS-REx mission to asteroid Bennu and the Japanese space.

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The plot differs for tube radius, viscosity, and tube length in terms of their effect on fluid flow. The effect of each parameter is analyzed and plotted against the velocity profile of the fluid flow.

For tube radius, as the radius increases, the fluid flow velocity increases as well. This can be observed in the plot where the velocity profile is a bell-shaped curve, with the peak shifting to the right as the radius increases.

For viscosity, the effect is the opposite. As viscosity increases, the fluid flow velocity decreases. This can be observed in the plot where the velocity profile is a flatter curve, with a smaller peak as the viscosity increases.

For tube length, there is a similar effect as tube radius. As the length increases, the fluid flow velocity decreases. This can be observed in the plot where the velocity profile is a bell-shaped curve, with the peak shifting to the left as the length increases.

In terms of the comparison with the prediction, the results were mostly in line with what was expected. The plots showed the expected trends for each parameter, and the quantitative analysis confirmed this as well. However, there were some discrepancies between the predicted and actual values, which could be due to experimental error or limitations in the model used.

Overall, the results provided valuable insights into the relationship between these parameters and fluid flow, and can be used to optimize fluid systems for various applications.

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Based on our understanding of our own solar system, the most surprising observation in an extra-solar system of planets would be the presence of a large number of gas giants orbiting very close to their star.

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The minimum angle at which the box would begin to move is given by the equation $\mu_{s} = \tan{\theta}$,is 21.8°.

Let's consider the following diagram: In the above, m is the mass of the box, θ is the angle of the incline, N is the normal force, f is the force of friction, and mg is the gravitational force acting on the box in the downward direction.

The box will be at the threshold of sliding up or down the plane when the gravitational force acting down the plane is greater than the frictional force acting up the plane. Therefore, the minimum angle at which the box will start to move is:tanθ = μswhere μs is the coefficient of static friction=0.4 (Given). Thus,θ= tan-1 (0.4)θ = 21.8 degrees.

Therefore, the box will start to move when the angle of inclination of the plane is 21.8 degrees (minimum angle).

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It would take approximately 19.2 years for the asteroid to orbit once around the sun. But that none of the answer choices match the calculated value of approximately 19.2 years.

The period (T) of an orbit of a celestial body with semimajor axis (a) around the sun can be calculated using Kepler's third law:

T² = (4π² / GM) * a³

where G is the gravitational constant and M is the mass of the sun.

Plugging in the given value for the semimajor axis (a = 4 AU), we get:

T² = (4π² / (6.674 × 10⁻¹¹ m³/(kg s²) * 1.989 × 10³⁰ kg)) * (4 AU)³

T² = 3.652 × 10¹⁶ s²

Taking the square root of both sides, we get:

T = 6.04 × 10⁸ s

We can convert this time to years by dividing by the number of seconds in a year:

T = (6.04 × 10⁸ s) / (31,536,000 s/year)

T ≈ 19.2 years

Therefore, it would take approximately 19.2 years for the asteroid to orbit once around the sun. The closest answer choice is 16 years.

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The length of the string is 0.48 m.

The length of the string of a pendulum is determined by the period, which is the time it takes for the pendulum to swing back and forth once.

String length = (Gravitational acceleration x (Period)2) / (4π2)

Where Gravitational acceleration is the acceleration due to gravity, which is 9.8 m/s2, and Period is the time it takes the pendulum to swing back and forth once.

The period is 10 seconds divided by 15 swings, or 0.67 seconds.

String length = (9.8 m/s2 x (0.67 s)2) / (4π2) = 0.48 m.

Therefore, the length of the string is 0.48 m.

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In science, arguments to prove a hypothesis or theory can be supported by various approaches such as experiments, logic, findings of other scientists, and other approaches.

Experiments are a common method used to support arguments in science. They involve carefully designed procedures to test a hypothesis or theory and collect data that can be analyzed to support or refute the hypothesis or theory. The data collected can be used to provide evidence for the argument being made.

Logic is also used in science to support arguments. Logical reasoning involves using a set of premises or assumptions to arrive at a conclusion. Scientists often use logic to develop hypotheses and theories that can be tested through experiments or other means.

Findings of other scientists can also be used to support arguments. When multiple studies or experiments have been conducted on a particular topic, scientists may review and analyze the findings to arrive at a conclusion. The consensus among the scientific community can lend weight to an argument.

Other approaches to support arguments in science may include mathematical models, simulations, and observations. In general, scientists use a variety of approaches to support their arguments and conclusions in order to ensure that their findings are as accurate and reliable as possible.

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Each player must pull with a force of 1250 N to drag the coach at a steady 2.0 m/s.

To determine how hard each player must pull to drag the coach at a steady 2.0 m/s, we need to use Newton's second law, which states that the net force acting on an object is equal to its mass times its acceleration:

Fnet = m * a

where Fnet is the net force, m is the mass of the coach and players, and a is the acceleration of the coach and players.

Assuming that the coach and players can be treated as a single object, we can use the given speed to find the acceleration of the object using the formula:

a = v² / (2 * d)

where v is the speed (2.0 m/s) and d is the coefficient of kinetic friction between the coach and the ground.

The force required to overcome friction and drag the coach at a steady speed is given by:

Ffriction = friction coefficient * Fnormal

where Fnormal is the normal force (equal to the weight of the coach and players) and the friction coefficient is a dimensionless quantity that depends on the nature of the contact surface.

Assuming a friction coefficient of 0.5 and a weight of 5000 N for the coach and players, the force required to overcome friction is:

F_friction = (0.5) * (5000 N) = 2500 N

The net force required to move the coach and players at a steady 2.0 m/s is therefore:

Fnet = Ffriction = 2500 N

Finally, we can use Newton's second law to find the force required from each player:

Fnet = m * a

2500 N = (m_coach + m_players) * (v² / (2 * d))

Solving for the mass (m_coach + m_players), we get:

m_coach + m_players = (2500 N * 2 * d) / v²

Assuming a value of 0.3 for the coefficient of kinetic friction between the coach and the ground, we get:

m_coach + m_players = (2500 N * 2 * 0.3) / (2.0 m/s)² = 562.5 kg

Therefore, the force required from each player is:

Fplayer = Fnet / 2 = 1250 N

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A bulb emits light ranging in wavelength from 2.64e-7 m to 8.66e-7 m. The maximum frequency of the light is [tex]1.14 \times 10^{15} Hz.[/tex]

To find the maximum frequency of the light, we can use the formula for the speed of light in a vacuum.

The speed of light (c) is given by [tex]3.00 \times 10^{8} m/s.[/tex]

We can use the following formula to find the frequency of light:

f = c / λ

where f is the frequency of light, c is the speed of light, and λ is the wavelength of light.

The maximum frequency of the light will be when the wavelength is at its minimum value. So, we can use the minimum wavelength in the formula above.

Hence, the maximum frequency of the light is given by:f = c / λmax

                                                                                              = [tex]3.00 \times 10^{8}  / 2.64 \times 10^{-7}[/tex]

                                                                                              = [tex]1.14 \times 10^{15} Hz.[/tex]

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Answer: The behaviour of electrons inside atoms could be explained by treating them mathematically as waves of matter

Explanation:

Erwin Schrödinger proposed the quantum mechanical model of the atom, which treats electrons as matter waves.

Answer:

[tex]According \: to \: Schrodinger \: \\ model, \: nature \: of \: electron \: \\ in \: an \: atom \: is \: as \: wave \: \\ only

[/tex]

Each aircraft must be moving at a speed of 85.75 km/hr towards each other to hear a pitch that is 2 times the emitted frequency.

What is frequency ?

Frequency is a physical quantity that describes the number of occurrences of a repeating event per unit of time. It is often measured in Hertz (Hz), which represents the number of cycles or vibrations per second.

In the context of waves, such as sound waves or electromagnetic waves, frequency refers to the number of complete cycles of the wave that occur in one second. A high frequency wave has more cycles per second than a low frequency wave.

Frequency is also an important concept in physics, particularly in the study of oscillations and waves. It is used to describe the behavior of systems that oscillate or vibrate, such as a simple pendulum or a guitar string. In these cases, the frequency of the oscillation is related to the natural frequency of the system, which is determined by its mass, stiffness, and other properties.

When two aircraft are moving towards each other, the sound waves from each aircraft are compressed, leading to a higher pitch than the emitted frequency. The pitch heard by the pilots of the aircraft can be calculated using the following formula:

Pitch heard = Emitted frequency * (Speed of sound + Speed of observer) / (Speed of sound - Speed of source)

Since the two aircraft are flying towards each other at the same speed, we can assume that the speed of one aircraft is x km/hr, and the speed of the other aircraft is also x km/hr. Therefore, the relative speed between the two aircraft is 2x km/hr.

Substituting the values given in the formula, we get:

2 * Emitted frequency = Emitted frequency * (343 + 2x) / (343 - x)

Simplifying this equation, we get:

686 - 2x = 343 + 2x

4x = 343

x = 85.75 km/hr

Therefore, each aircraft must be moving at a speed of 85.75 km/hr towards each other to hear a pitch that is 2 times the emitted frequency.

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If a truck has a linear acceleration of 1.85 m/s² and the wheels have an angular acceleration of 5.23 rad/s², the diameter of the truck's wheels   0.71 m.

Linear acceleration refers to the time rate of change of linear velocity, whereas angular acceleration refers to the time rate of change of angular velocity. This is the primary differential between linear and angular acceleration. Simply said, changes in an object's linear velocity with respect to time are represented by changes in linear acceleration.

The angular acceleration can be deduced immediately from the concept of α =ΔωΔt because the ultimate angular velocity and time are both provided.

The link between linear acceleration (a) and rotational acceleration is expressed as a = r×α . When the angular acceleration increases, so will the linear acceleration's strength. Increased wheel angular acceleration, for instance, denotes an accelerated vehicle.

Linear acceleration is the uniform acceleration caused by a moving body moving along a straight line. There are three equations that are essential in linear acceleration, depending on parameters like start and terminal velocities, displacements, times, and acceleration.

Given :

linear acceleration a = 1.85 m/s²

angular acceleration α  = 5.23 rad/s²

radius r = a/ α  = [tex]\frac{1.85}{5.23}[/tex] = 0.354 m

diameter  d = 2r = 2 × 0.354 = 0.71 m

diameter of the wheels is  0.71 m.

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A 5-gallon bucket of gold would weigh 86.84 pounds.

A five-gallon bucket of water weighs 40 pounds. Gold has a specific gravity of almost 20.

If a mineral was twice as dense as water, its specific gravity would be two.

Water has a specific gravity of 1.

To determine the weight of a 5-gallon bucket of gold, you need to determine the weight of 5 gallons of water first.One gallon of water weighs approximately 8.33 pounds; hence 5 gallons of water weigh 41.65 pounds.

Now, divide the weight of 5 gallons of water (41.65) by the specific gravity of gold (20):41.65/20 = 2.0825

The weight of a five-gallon bucket of gold would be 2.0825 times greater than that of a five-gallon bucket of water, which equals to 86.84 pounds (40 pounds + 46.84 pounds).

Therefore, a 5-gallon bucket of gold would weigh approximately 86.84 pounds.

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Answer:

100 feet at 75 mph.

mph expresses the speed or velocity in miles per hour. Speed means rate of change of distance with respect to time.

speed = distance/time

hence, distance = speed x time

The above equation is the relationship between distance, speed and time.

Coney Island is a famous destination known for its amusement parks, boardwalk, and beautiful beach.

One of its most popular attractions is the Thunderbolt, which is a steel roller coaster that gives riders a thrilling experience of high speeds, steep drops, and sharp turns.

The distance and speed at which riders get shot in the air on the Thunderbolt roller coaster are 100 feet and 75 mph, respectively.

This means that the ride launches riders at a height of 100 feet while travelling at a speed of 75 miles per hour.

This can be a scary experience, as the force of gravity can make riders feel like their organs are relocating.

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a..... 1.04 x 10⁻⁴ Vi

b.... 9500 V

A) Determine the capacitance (to the nearest 10 μF).

First, we should identify the formula that we will use to solve the problem.

The formula that relates to capacitance is:

C = 2E / V². Where C is the capacitance in farads, E is the energy stored in joules, and V is the voltage across the capacitor in volts.

Converting the energy to joules, we have: E = 250J.

Now we know that the voltage needs to drop to half of its initial value in 10 ms. We can use the following formula to calculate the capacitance: C = R x t / ln(Vi / Vf) where R is the resistance in ohms, t is the time in seconds, Vi is the initial voltage, and Vf is the final voltage, which is half of the initial voltage.

B) Plugging in the given values, we get:

C = 48 x 0.01 / ln(Vi / (Vi / 2))Simplifying and solving for capacitance, we get:

C = 1.04 x 10⁻⁴ ViNow we can use the energy formula to solve for Vi:Vi = √(2E / C)

Plugging in the given values, we get:Vi = √(2 x 250 / 1.04 x 10⁻⁴)Simplifying and solving for Vi, we get:Vi = 9469 V

Therefore, the capacitance that meets these specifications is 100 μF and the initial capacitor voltage that meets these specifications is 9500 V, to the nearest 100 V.

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The magnitude of the torque on the current loop is calculated using the formula τ=BIA sinθ, where B is the magnitude of the magnetic field, I is the current, A is the area of the loop, and θ is the angle between the magnetic field and the loop's plane. In this case, the magnitude of the torque is τ = (1.2 T)(0.5 A)(5 cm x 5 cm)sin(30°) = 7.5 x 10-3 Nm.

The torque is the rotational force that causes the loop to rotate. This is due to the fact that a force is exerted on the loop by the magnetic field when there is a current running through it. This force generates a torque on the loop, which will cause it to rotate until the angle between the plane of the loop and the magnetic field is 0°.

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The magnitude of the average force applied by the ball on the glove is 34 N.

The magnitude of the average force applied by the ball on the glove.

This can be done by using the equation for force, F = ma, where F is the force, m is the mass of the object, and a is the acceleration of the object.

The mass of the ball is 0.170 kg, and the acceleration is determined by the change in velocity of the ball and the distance the glove recoils, 15 cm, or 0.15 m.

Therefore, the acceleration of the ball is a = (30.0 m/s - 0 m/s)/(0.15 m) = 200 m/s^2.

Since we have the mass and the acceleration, we can calculate the force with the equation above. F = (0.170 kg)(200 m/s^2) = 34 N. Therefore, the magnitude of the average force applied by the ball on the glove is 34 N.

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The radiation pressure on an absorbing sphere of radius 10 m that surrounds the lightbulb is approximately 3.98 x 10^-13 Pa.

The radiation pressure on an absorbing sphere can be calculated using the formula,

P = (2 * I) / c

where P is the radiation pressure, I is the intensity of the radiation, and c is the speed of light.

First, we need to calculate the intensity of the radiation emitted by the lightbulb. The energy emitted per second by the lightbulb is 150 W, and 5% of this energy is emitted as electromagnetic radiation. Therefore, the energy emitted as radiation is,

E = 150 W * 0.05 = 7.5 W

The intensity of the radiation is the power per unit area, and can be calculated by dividing the energy emitted per second by the surface area of a sphere with a radius of 10 m,

I = E / (4 * pi * r^2) = 7.5 W / (4 * pi * 10^2 m^2) = 5.98 x 10^-5 W/m^2

Now we can calculate the radiation pressure, P = (2 * I) / c = (2 * 5.98 x 10^-5 W/m^2) / 3 x 10^8 m/s = 3.98 x 10^-13 Pa

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Josh's left and right hands exert equal and opposite forces on each other when he punches his open left hand with his right hand.

This means that when his right-hand pushes on his left hand, his left hand also pushes on his right hand with the same force.

This is Newton's Third Law of Motion:

"For every action, there is an equal and opposite reaction."

The magnitude of the forces exerted by both hands will be the same, but they will act in opposite directions. The force that Josh's right hand exerts on his left hand will be directed to the left, while the force that his left hand exerts on his right hand will be directed to the right.

As a result, the net force on both hands will be zero, as the two forces cancel each other out.

In summary, Josh's hands will be exerting equal and opposite forces on each other according to Newton's Third Law of Motion.

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Answer:

Explanation:

Because by Wien's Law, they emit strongest in infrared and human eyes cannot see infrared radiation

The kinetic energy of the ball when hits the ground is 88.2 J

The formula for calculating kinetic energy is

KE = 1/2mv²

Where KE is kinetic energy, m is mass, and v is velocity.

We have, the mass of the bowling ball is 6 kg, and it is dropped from a height of 1.5 m, we can calculate its velocity just before it hits the ground as follows:

Potential energy = mgh

Where m = mass of the object = 6 kg

g = acceleration due to gravity (9.8 m/s²), and

h = height from which the object is dropped = 1.5 m

PE = mgh

= (6 kg)(9.8 m/s²)(1.5 m)

= 88.2 J

The potential energy of the bowling ball is 88.2 J.

This is equal to its kinetic energy just before it hits the ground.

Therefore, the kinetic energy of the ball is 88.2 J.

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