researcher records the following scores for an Olympic gymnast following her routine: 9.9, 9.8, 9.6, 9.5, 9.7, 9.1, 8.9, and 9.8. What is the range for the scores?
1.0 (9.9 to 8.9)
0.3 (9.8 to 9.5)
0.5 (9.6 to 9.1)
It is not possible to compute a range with an even number of scores.
The range for the scores is 1.0 (from 9.9 to 8.9). The range is the difference between the highest and lowest numbers in a set of numbers. In this case, the highest score is 9.9 and the lowest score is 8.9, so the range is 1.0.
In mathematics, the range of a function can refer to one of two similar terms:
the common area of the function
The image of the function
Given two groups X and Y, the binary relation f between X and Y is a (exact) function (X to Y), if there is a y in Y for every x in X, so f is associated with y. The sets X and Y are called the area of f and the common domain, respectively.
The range is a measure of dispersion in a set of numbers. To find the range, you need to subtract the lowest score from the highest score. In this case, the scores for the Olympic gymnast are: 9.9, 9.8, 9.6, 9.5, 9.7, 9.1, 8.9, and 9.8.
First, identify the highest and lowest scores:
Highest score: 9.9
Lowest score: 8.9
Next, subtract the lowest score from the highest score:
Range = 9.9 - 8.9
The range for the scores is 1.0 (9.9 to 8.9).
Your answer: 1.0 (9.9 to 8.9)
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a put option is a security that gives its holder the opportunity either to sell something, such as 100 shares of common stock at a certain price, or to do nothing and therefore not transact. 1. True 2. False
The statement is true. A put option is a financial contract that provides the holder with the right, but not the obligation, to sell an underlying asset, such as 100 shares of common stock, at a predetermined price, known as the strike price, before or at the expiration date of the option. If the price of the asset decreases below the strike price, the holder of the put option can sell the asset at the higher strike price and make a profit. However, if the price of the asset increases above the strike price, the holder can simply do nothing and let the option expire, without any obligation to sell the asset.
The price of a put option is influenced by various factors, such as the price of the underlying asset, the strike price, the time until expiration, and the volatility of the asset's price. Generally, the higher the volatility and the longer the time until expiration, the higher the price of the put option.
Selling a put option involves taking on the obligation to buy the underlying asset at the strike price, if the holder decides to exercise the option. Selling put options can be a strategy for generating income, but it also involves risks, such as potential losses if the price of the asset decreases significantly.
In summary, a put option is a security that provides the holder with the right to sell an underlying asset at a predetermined price, but not the obligation to do so. The price of a put option is influenced by various factors, and selling a put option involves taking on the obligation to buy the asset.
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HELP PLEASE 100 POINTS!!!
Answer:
56.52 units³-------------------------------
Volume of cylinder formula:
V = πr²hWe are given values:
π = 3.14, r = 3 units,h = 2 units.Substitute and calculate the volume:
V = 3.14*3²*2 = 56.52 units³Let xx,x2,..., Xn be a random Sample from normal distribution, Xin N10,0). Is the MLE of o is an unbiased estimators?
Answer:
Ya
Step-by-step explanation:
Yes, the maximum likelihood estimator (MLE) of the standard deviation (sigma) in a normal distribution is an unbiased estimator. This means that on average, the MLE will provide an estimate of the true standard deviation that is equal to the true value. However, it's important to note that the MLE is not always the most efficient estimator, meaning that there may be other estimators that have lower variance and are therefore more precise.
Yes, the Maximum Likelihood Estimator (MLE) of σ (the standard deviation) is an unbiased estimator for a random sample from a normal distribution with mean 0 and standard deviation 10. The reason is that the MLE of σ is based on the sample variance, which is an unbiased estimator of the population variance. Since the population variance is σ^2, the MLE of σ is also an unbiased estimator of σ.
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Identify each variable as either relevant or not relevant to the research question; further classify the relevant variable(s) as either quantitative or categorical.Group of answer choicesThe research question:Based on a recent study, roughly 80% of college students in the U.S. own a smartphone. Is the proportion of smartphone owners lower at this university?Math[ Choose ] Not relevant to the question Relevant; Categorical Relevant; QuantitativeVerbal[ Choose ] Not relevant to the question Relevant; Categorical Relevant; QuantitativeCredits[ Choose ] Not relevant to the question Relevant; Categorical Relevant; QuantitativeYear[ Choose ] Not relevant to the question Relevant; Categorical Relevant; QuantitativeExercise[ Choose ] Not relevant to the question Relevant; Categorical Relevant; QuantitativeSleep[ Choose ] Not relevant to the question Relevant; Categorical Relevant; QuantitativeVeg[ Choose ] Not relevant to the question Relevant; Categorical Relevant; QuantitativeCell[ Choose ] Not relevant to the question Relevant; Categorical Relevant; Quantitative
Math is not relevant to the research question as it is not directly related to smartphone ownership. Verbal, Credits, Year, Exercise, Sleep, Veg, and Cell are also not relevant to the research question as they do not provide information on smartphone ownership or the proportion of smartphone owners at a specific university. The relevant variable in this research question is smartphone ownership.
The relevant variable in this research question is smartphone ownership. This variable is quantitative as it involves measuring the proportion of smartphone owners at a specific university. The proportion of smartphone owners can be expressed as a percentage or a decimal value, which are both quantitative measurements.
Categorical variables are not relevant to this research question as they do not provide information on the proportion of smartphone owners. Categorical variables involve categorizing data into groups or categories, such as gender or race, which are not directly related to smartphone ownership.
In summary, the only relevant variable in this research question is smartphone ownership, which is a quantitative variable.
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A biotechnology company produced 203 doses of somatropin, including 10 which were defective. Quality control test 13 samples at random, and rejects the batch if any of the random samples are found defective. What is the probability that the batch gets rejected? Probability =
The probability that the batch gets rejected is 0.445 or 44.5%.
The probability that the batch gets rejected can be calculated using the binomial distribution. Let's define the following terms:
n = number of samples tested = 13
p = proportion of defective doses in the batch = 10/203
q = proportion of good doses in the batch = 1 - p
Now we can calculate the probability of finding k defective doses in a sample of size n as:
P(k defective doses)[tex]= (n choose k)(p^k)q^{(n-k)}[/tex]
To calculate the probability that the batch gets rejected, we need to find the probability of finding at least one defective dose in the sample:
P(rejecting the batch) = P(1 or more defective doses) = 1 - P(0 defective doses)
P(0 defective doses) [tex]= (13 choose 0)(p^0)q^{13}= q^{13} = (\frac{193}{203})^{13}[/tex]
P(rejecting the batch) = [tex]1 - (\frac{193}{203})^{13} =[/tex]=0.445 or 44.5%
Therefore, the probability that the batch gets rejected is 0.445 or 44.5%.
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Parker has 9 gallons of water. How many quarts of water does he have?
Answer: 36 quarts
Step-by-step explanation:
pretty much just do 9 * 4 qts
hope this helped!!
Answer: Parker has 36 Quarts of water.
We are given the following:
Parker has 9 gallons of water.We are asked to find:
How many Quarts of Water does he have.This question strictly revolves the around the conversion of units. In other words, in order to answer this question, we must know how many quarts are in a gallon.
Fortunately, we know that 4 quarts = 1 gallon.
Since Parker possesses 9 gallons of water, we would do [tex]4*9=36[/tex]. Arriving us at our answer of 36 quarts of water.
Parker has 36 quarts of water.
What is the area of the base of this right triangular prism?
hellp me pls
Step-by-step explanation:
Area of a triangle = 1/2 base leg * height
area = 1/2 * 9 * 6 = 27 cm^2
Answer: 27 cm²
Step-by-step explanation:
To find the area of the base of this right triangular prism we can use the area formula for a triangle. Make sure you are using the correct base (b) and height (H) in the formula that apply to the base triangle.
Given:
A = [tex]\frac{bH}{2}[/tex]
Substitute known values:
A = [tex]\frac{(9\;cm)(6\;cm)}{2}[/tex]
Multiply:
A = [tex]\frac{54\;cm^2}{2}[/tex]
Divide:
A = 27 cm²
A study was conducted to determine the percent of children that want to grow up work in the same career as a parent. In a sample of 200 children, it was calculated that 43% wanted to eventually work in the same career as a parent. Construct the 95% confidence interval for the population proportion. Proposed Solution: phạt = 0.43/200 = 0.00215 phat - qnorm(1.95/2)*sqrt(phat*(1-phat)/200) = -0.00426926 phat + qnorm(1.95/2)*sqrt(phat*(1-phat)/200) = 0.00856926 [-0.0043, 0.0086) What is wrong with the proposed solution? A. phat was already provided, so dividing that value by the sample size is incorrect B. For a 95% confidence level, the z* is calculated by qnorm(0.95). C. You cannot use "phat" in an R Studio command. The decimal must be written D. You cannot have negative values as one of the limits on your interval. This should be made positive. E. The proposed solution is correct.
Previous question
The correct answer is B. For a 95% confidence level, the z* value should be calculated using qnorm(0.975).
The proposed solution to construct a 95% confidence interval for the population proportion has several errors. Let's review each of them in detail:
A. phat was already provided, so dividing that value by the sample size is incorrect:
This is incorrect because phat represents the sample proportion, which is the point estimate of the population proportion. The sample proportion alone is not enough to estimate the variability of the sample proportion, which is required to construct a confidence interval. Therefore, we need to divide phat by the sample size to obtain the standard error of the sample proportion.
B. For a 95% confidence level, the z* is calculated by qnorm(0.95):
This is incorrect because a 95% confidence level corresponds to a 1.96 standard error for a two-tailed test, not a 1.645 standard error. Therefore, we need to use qnorm(0.975) or qnorm(1 - 0.025) to find the z* value.
C. You cannot use "phat" in an R Studio command. The decimal must be written:
This is incorrect because "phat" is a valid R Studio command that represents the sample proportion. However, it is important to define this variable beforehand to avoid any errors.
D. You cannot have negative values as one of the limits on your interval. This should be made positive:
This is correct. A confidence interval cannot have negative values as limits since proportions must be between 0 and 1. Therefore, we need to take the absolute value of the lower limit.
E. The proposed solution is correct:
This is incorrect, as discussed above. The correct solution should use the formula:
phat +/- z* * sqrt(phat*(1-phat)/n)
where phat = 0.43, n = 200, and z* is the critical value of the standard normal distribution corresponding to a 95% confidence level, which is approximately 1.96. Therefore, the correct 95% confidence interval is:
0.43 +/- 1.96 * sqrt(0.43*(1-0.43)/200) = (0.369, 0.491).
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Michelle started her retirement plan early by saving $200 per month since she was 20 years old. During that time, she has earned an average annual rate of 5.2% compounded monthly. Her twin brother Michael, now 40 years old, would like to catch-up with his twin sister by contributing a monthly payment for the next 20 years. How much should Michael contribute monthly, assuming that both he and his twin sister will continue to earn an annual rate of 5.2% interest, compounded monthly?
The PMT or monthly contribution is pegged at $764.57
What is a Retirement Plan?
Individuals employ a financial tactic known as a retirement plan to accumulate and invest funds, which will enable them to have access to revenue during their retirement period.
The aim of this approach is to certitude that these individuals possess ample income to maintain their standard of living and fulfil any additional monetary requirements once they terminate employment.
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It is important that face masks used by firefighters be able to withstand high temperatures because firefighters commonly work in temperatures of 200–500°F. In a test of one type of mask, 11 of 55 masks had lenses pop out at 250°. Construct a 90% CI for the true proportion of masks of this type whose lenses would pop out at 250°.
Means that we are 90% confident that the true proportion of masks with lenses that pop out at 250° is between 7.6% and 32.4%.
We can use the formula for a confidence interval for a proportion:
CI = p ± z*sqrt(p(1-p)/n)
where:
p = sample proportion = 11/55 = 0.2
z = the z-score for a 90% confidence level, which is 1.645
n = sample size = 55
Plugging in the values, we get:
CI = 0.2 ± 1.645*sqrt(0.2(1-0.2)/55)
CI = 0.2 ± 0.124
Therefore, the 90% confidence interval for the true proportion of masks of this type whose lenses would pop out at 250° is (0.076, 0.324). This means that we are 90% confident that the true proportion of masks with lenses that pop out at 250° is between 7.6% and 32.4%.
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Given two independent random samples with the following results: n_1 = 561 n_2=741 p_1 =0.72 p_2 = 0.82 Can it be concluded that the proportion found in Population 2 exceeds the proportion found in Population 1? Use a significance level of alpha = 0.05 for the test. Step 1 of 5: State the null and alternative hypotheses for the test.
H0: p1 = p2 (the proportions are equal)
Ha: p2 > p1 (the proportion in Population 2 exceeds that in Population 1)
Hypothesis testing involves making a statement about a population parameter (such as a mean or a proportion) based on a sample of data. The statement is made in the form of two hypotheses: the null hypothesis (H0) and the alternative hypothesis (Ha).
The null hypothesis is the default assumption that there is no significant difference between the two populations being compared. In this case, the null hypothesis would be that the proportion found in Population 2 is not significantly different from the proportion found in Population 1.
The alternative hypothesis is the statement we are trying to support with our evidence. In this case, the alternative hypothesis would be that the proportion found in Population 2 exceeds the proportion found in Population 1.
So, in step 1 of hypothesis testing, we would state the null and alternative hypotheses as follows:
H0: p1 = p2 (the proportions are equal)
Ha: p2 > p1 (the proportion in Population 2 exceeds that in Population 1)
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Mr. Tukey's class is taking a field trip on a bus. While traveling, students count the number of cars with out-of-state license plates. The students' data are given. Use the data to make a cumulative frequency table.
10, 30, 25, 31, 17, 25, 36, 20, 34, 14, 35, 24, 22, 19, 37
Answer:
The graph shown is the answer
Step-by-step explanation:
It says why and how its the answer
Let β and γ be ordered bases of a vector space V. Let T : V → V be a linear transformation. Prove that [T]β and [T]γ, are similar.
The matrices [T]β and [T]γ, which represent a linear transformation T with respect to ordered bases β and γ in vector space V, are similar.
To prove that [T]β and [T]γ are similar, we need to show that there exists an invertible matrix P such that [T]γ = P⁻¹ [T]β P.
Since β and γ are ordered bases of V, there exists an invertible change of basis matrix Q such that γ = βQ.
Then, we can write [T]γ = [T]βQ(Q⁻¹) = P⁻¹[T]β P where P = Q^(-1).
Therefore, [T]β and [T]γ are similar, and the matrix P is the change of basis matrix from β to γ.
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The height in feet of an arrow is modeled by the equation h(t) = (1+2r)(18-81),
where is seconds after the arrow is shot.
a. When does the arrow hit the ground? Explain or show your reasoning.
b. From what height is the arrow shot? Explain or show your reasoning.
The arrow would hit the ground after 2.25 seconds.
The height from which this arrow was shot is 18 feet.
How to determine the time when the arrow would hit the ground?Based on the information provided, we can logically deduce that the height (h) in feet, of this arrow above the ground is related to time by the following quadratic function:
h(t) = (1 + 2t)(18 - 8t)
Generally speaking, the height of this arrow would be equal to zero (0) when it hits the ground. Therefore, we would equate the height function to zero (0) as follows:
0 = (1 + 2t)(18 - 8t)
(18 - 8t) = 0
8t = 18
By dividing both sides of the equation by 8, we have:
Time, t = 18/8
Time, t = 2.25 seconds.
Next, we would determine the height from which this arrow was shot by substituting time (t) with zero;
h(0) = (1 + 2(0))(18 - 8(0))
h(0) = 1(18)
h(0) = 18 feet.
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Complete Question:
The height in feet of an arrow is modeled by the equation h(t) = (1+2t)(18-8t),
where t is seconds after the arrow is shot.
a. When does the arrow hit the ground? Explain or show your reasoning.
b. From what height is the arrow shot? Explain or show your reasoning.
A manager of a service call center wants to estimate how long the average customer waits on the phone with an agent before a solution is reached to the customer's problem. The manager recorded the number of minutes 15 customer phone calls lasted before a solution was reached and the data is presented below. Please SHOW Excel Functions when doing the work respectively. Ex: "=Average(A6:A20), and etc."For reading purposes, A29 is Upper Bound and A30 is Lower Bound
The upper bound should be entered in cell A29 and the lower bound in cell A30.
Assuming the data is in cells A1 to A15, the Excel functions to calculate the required statistics are:
Mean (average) waiting time:
= AVERAGE(A1:A15)
Result: This will return the average waiting time of the 15 customer phone calls.
Median waiting time:
= MEDIAN(A1:A15)
Result: This will return the median waiting time of the 15 customer phone calls.
Standard deviation of waiting time:
= STDEV(A1:A15)
Result: This will return the standard deviation of the waiting time of the 15 customer phone calls.
95% Confidence Interval of the mean waiting time:
Lower bound: = AVERAGE(A1:A15) - (T.INV(0.05,14)*STDEV(A1:A15)/SQRT(15))
Upper bound: = AVERAGE(A1:A15) + (T.INV(0.05,14)*STDEV(A1:A15)/SQRT(15))
Result: This will return the lower and upper bounds of the 95% confidence interval of the mean waiting time of the 15 customer phone calls.
The upper bound should be entered in cell A29 and the lower bound in cell A30.
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Identifying,simplifying, setting up, and solving proportions 1-4
1. Circling non-ratio.
c. 6d. 12.52. Circling ratios that are fully simplified.
a. 7/3b. 1/2c. 2/13d. 3/1e. 21/5f. 44/1g. 1/8h. 10/3i. 2/6 or 1/3Variables in a proportion:
3. a. x = 43. b. y = 154. a. x = 34. b. y = 2How to find variable in each proportion?3. Solve for the variable in each proportion.
a. 3/9 = x/12
To solve for x, cross-multiply and simplify:
3/9 = x/12
(3)(12) = (9)(x)
36 = 9x
x = 4
Therefore, the solution is x = 4.
b. 20/y = 4/3
To solve for y, cross-multiply and simplify:
20/y = 4/3
(4)(y) = (20)(3)
4y = 60
y = 15
Therefore, the solution is y = 15.
4. Solve for the variable in each proportion.
a. 2/14 = (x+1)/28
To solve for x, cross-multiply and simplify:
2/14 = (x+1)/28
(2)(28) = (14)(x+1)
56 = 14x + 14
42 = 14x
x = 3
Therefore, the solution is x = 3.
b. 3/(2y-3) = 6/y
To solve for y, cross-multiply and simplify:
3/(2y-3) = 6/y
(3)(y) = (6)(2y-3)
3y = 12y - 18
-9y = -18
y = 2
Therefore, the solution is y = 2.
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You are building a greenhouse with walls that are 10' wide, 15' long, and 8' high. You want the wall
space to be used to hydroponically grow various types of lettuce. You also want to use the floor space to
start tomato seeds. The extension office recommends for only half of the floor space to be available for
the tomatoes.
Glass panels come in 5' x 4' sheets. You will use glass for all windows and doors as well as the walls. How
many glass panels will you need?
Answer:The answer is $911.68.
Step-by-step explanation:
Answer:
we will need 20 glass panels to cover the walls of the greenhouse with 5' x 4' glass panels.
Step-by-step explanation:
First, let's calculate the total wall area:
2 walls (10' x 8') = 160 sq. ft.
2 walls (15' x 8') = 240 sq. ft.
Total wall area = 400 sq. ft.
Next, let's calculate the total floor area:
15' x 5' = 75 sq. ft. (total floor area)
75 sq. ft. / 2 = 37.5 sq. ft. (floor area for tomatoes)
To cover the walls with glass panels, we need to divide the total wall area by the area of each glass panel:
Glass panel area = 5' x 4' = 20 sq. ft.
400 sq. ft. (total wall area) / 20 sq. ft. (area of each glass panel) = 20 glass panels
Therefore, we will need 20 glass panels to cover the walls of the greenhouse with 5' x 4' glass panels.
Find the area of the composite figure by matching the area of each part below.
Area of the semi-circle
Area of the triangle
Total area of figure
USE 3.14 for pi! Round to the nearest hundredth if necessary!
Answer:
Area of the semi-circle:
(1/2)π(2^2) = 2π = 6.28 square centimeters
Area of the triangle:
(1/2)(4)(5.7) = 11.4 square centimeters
Total area:
6.28 + 11.4 = 17.68 square centimeters
There are 20 students in a class. Billy is one of them. Suppose we select 5 students in the class uniformly at random without replacement.
a.What is the probability that Billy is among the 5 selected students?
b.Bob is also one of the 20 students. What is the probability that Bob and Billy are chosen among the 5 students?
c.What is the probability that Bob or Billy is chosen among the 5 students?
d.What is the probability that Bob is not chosen and Billy is chosen among the 5 students?
Explain your answer.
In part (d), we had to calculate the probability of choosing 4 out of the 18 remaining students because we know that Bob is not chosen.
The probability that Billy is among the 5 selected students is given by the number of ways Billy can be selected out of 20 students, divided by the total number of ways to select 5 students out of 20:
P(Billy is selected) = 1/ C(20,5) = 1/15504
b. The probability that both Billy and Bob are chosen among the 5 students is given by the number of ways both Billy and Bob can be selected out of 20 students, divided by the total number of ways to select 5 students out of 20:
P(Billy and Bob are selected) = C(2,2) * C(18,3) / C(20,5) = 816/15504 = 0.0526
c. The probability that Bob or Billy is chosen among the 5 students is given by the sum of the probabilities of Billy being chosen and Bob being chosen, minus the probability of both Billy and Bob being chosen (to avoid double-counting):
P(Bob or Billy is selected) = P(Billy is selected) + P(Bob is selected) - P(Billy and Bob are selected)
= 1/ C(20,5) + 1/ C(20,5) - 816/15504
= 2/15504 + 2/15504 - 816/15504
= 168/15504 = 0.0108
d. The probability that Bob is not chosen and Billy is chosen among the 5 students is given by the number of ways to choose 4 students out of the 18 remaining students, multiplied by the number of ways to choose Billy from those 4 students, divided by the total number of ways to choose 5 students out of 20:
P(Bob is not chosen and Billy is chosen) = C(18,4) * C(1,1) / C(20,5) = 3060/15504 = 0.1971
Explanation: In order to calculate the probabilities, we used the formula for the probability of a combination, which is the number of favorable outcomes divided by the total number of possible outcomes. In part (c), we had to subtract the probability of both Billy and Bob being chosen to avoid double-counting. In part (d), we had to calculate the probability of choosing 4 out of the 18 remaining students because we know that Bob is not chosen.
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K
Find the area of the shaded region. Leave your answer in
terms of and in simplified radical form.
...
120°
18 cm
The area of the shaded region is
(Simplify your answer. Use integers or fractions for any numbers in the expression.
Type an exact answer in terms of x.)
The area of the sector is 305. 2 cm²
How to determine the areaThe area of the shaded part is equivalent to the area of the sector.
The formula for determining the area of a sector is expressed with the equation;
A = θ/360 × πr²
Given that the parameters of the equation are;
A is the area of the sectorθ is the angle subtendedr is the radiusFrom the diagram shown, we have;
Area = 120/360 × 3.14 × 18²
find the square values
Area = 0. 3 × 3. 14 × 324
multiply the values
Area = 305. 2 cm²
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the average age of community college students is 24.6 years. state the null and alternative hypothesis
The null hypothesis states that the average age of community college students is equal to 24.6 years. The alternative hypothesis states that the average age of community college students is not equal to 24.6 years.
In other words, the null hypothesis assumes that the given average age is accurate, and the alternative hypothesis suggests that the given average age is either higher or lower than 24.6 years. These hypotheses can be tested through statistical analysis to determine if there is sufficient evidence to reject the null hypothesis and accept the alternative hypothesis. This analysis can provide insights into the characteristics of the community college student population and inform decisions related to education policy and programs.
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Some people claim that psychology is common sense. A psychologist predicts that this is not true and that nonpsychology majors will do worse at predicting the outcomes of psychology experiments than psychology majors. Psychology students typically predict outcomes with 75% accuracy (population mean). A sample of 15 nonpsychology students predicted with 60% accuracy (sample mean). The estimated standard error of the mean = 2.696. What is the 95% confidence interval for nonpsychology students?
the 95% confidence interval for the mean prediction accuracy of nonpsychology students is (0.60 - 1.77, 0.60 + 1.77), which is approximately equal to (−1.17, 2.37).
To calculate the 95% confidence interval for the mean prediction accuracy of nonpsychology students, we can use the following formula:
CI = X ± t(α/2, df) × (SE)
where:
- X is the sample mean (0.60 in this case)
- t(α/2, df) is the t-value for the given level of significance (α), degrees of freedom (df) and two-tailed test. For a 95% confidence interval with df = n - 1 = 14, the t-value is 2.145
- SE is the estimated standard error of the mean (2.696 in this case)
Substituting the given values into the formula, we get:
CI = 0.60 ± 2.145 × (2.696/√15)
Simplifying the expression, we get:
CI = 0.60 ± 1.77
Therefore, the 95% confidence interval for the mean prediction accuracy of nonpsychology students is (0.60 - 1.77, 0.60 + 1.77), which is approximately equal to (−1.17, 2.37).
Note that the confidence interval includes the population mean of 75%, which suggests that the psychologist's prediction is correct - nonpsychology students are likely to do worse than psychology students at predicting the outcomes of psychology experiments. However, the confidence interval is quite wide, indicating that there is considerable uncertainty in our estimate of the mean accuracy for nonpsychology students based on this small sample size.
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Find the area of the composite figure. In neccesary, round your answer to the nearest hundredth.
The area of the circle is approximately 55.39 square inches.
The circumference of the circle is approximately 26.38 inches.
What is the Area and Circumference of a Circle?The area of a circle = πr²
The circumference of the circle = 2πr
Where, r is the radius of the circle, which is half of the diameter of the circle.
Therefore, we have:
radius (r) = 8.4/2 = 4.2 inches
π = 3.14
Thus:
The area of the circle = πr² = 3.14 * 4.2²
Area ≈ 55.39 square inches [nearest hundredth]
The circumference of the circle = 2πr = 2 * 3.14 * 4.2
Circumference ≈ 26.38 inches.
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mandy collected 80 stamps last year, and collected 140 stamps this year. what was the percentage increase in her stamp collection
Answer:
75%
Step-by-step explanation:
We Know
Mandy collected 80 stamps last year.
Collected 140 stamps this year.
What was the percentage increase in her stamp collection?
We Take
(140 ÷ 80) x 100 = 175%
Then We Take
175 - 100 = 75%
So, the stamp collection increase by 75%
An online poll asked: "Do you believe the Loch Ness monster exists?" Among 21,466 responses, 62% were "yes." Use a 0.10 significance level to test the claim that most people believe that the Loch Ness monster exists. How is the conclusion affected by the fact that Internet users who saw the question could decide whether to respond?
Identify the null and alternative hypotheses for this test. Choose the correct answer below.
OA H_{0} / p = 0.5 H_{1} / p > 0.5
OB. H_{0} / p = 0.5 H_{1} :p ne0.5
OC. H_{0} / p = 0.5 H_{1} / p < 0.5
OD. H_{0} / p > 0.5 H_{1} / D = 0.5
Who are more likely to respond to an online poll about the Loch Ness monster may not be representative of the general population, and may have different beliefs about its existence.
The correct answer is: H0: p <= 0.5, H1: p > 0.5
Explanation:
The null hypothesis (H0) is that the proportion of people who believe that the Loch Ness monster exists is less than or equal to 0.5. The alternative hypothesis (H1) is that the proportion is greater than 0.5.
This is a one-tailed test, since we are only interested in whether the proportion is greater than 0.5.
The fact that Internet users who saw the question could decide whether to respond may affect the conclusion of the test, as it introduces potential bias into the sample. Those who are more likely to respond to an online poll about the Loch Ness monster may not be representative of the general population, and may have different beliefs about its existence.
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The range of probability is _____,
a. any value larger than 0
b. 0 to 1, inclusive
c. any value between -1 to 1
d. any value between minus infinity to plus infinity
Answer: A
Step-by-step explanation:
which of the following will shift the production possibilities curve outward?i. an increase in the production of investment goodsii. an increase in the production of consumer goodsiii. technological progress
Answer:
If not choose all that apply, technological process will shift the PPC right (outwards)
Step-by-step explanation:
The production possibilities curve represents the maximum amount of goods and services that a country can produce with its limited resources. It is a graphical representation of the trade-offs a country must make between producing one good or service over another. Any factor that can increase production will shift the curve outward, indicating an increase in the maximum amount of goods and services that can be produced.
An increase in the production of investment goods will shift the curve outward because it will increase the amount of capital goods that can be used to produce other goods and services. Investment goods are items like machinery, equipment, and infrastructure that are used to produce other goods and services. By increasing the production of investment goods, a country can increase its productive capacity, allowing it to produce more goods and services in the future.
An increase in the production of consumer goods will not shift the curve outward because it does not increase the country's productive capacity. Consumer goods are items that are consumed immediately, like food, clothing, and electronics. While an increase in the production of consumer goods can lead to short-term economic growth, it will not increase the country's long-term productive capacity.
Technological progress, on the other hand, will shift the production possibilities curve outward. Technological progress refers to advancements in technology that increase productivity, reduce costs, and improve efficiency. By adopting new technologies, a country can produce more goods and services with its existing resources, allowing it to shift its production possibilities curve outward.
In conclusion, an increase in the production of investment goods and technological progress will shift the production possibilities curve outward, while an increase in the production of consumer goods will not.
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an auditorium can see 1800 and there's always a capacity for shells the owner wants to increase revenue by raising ticket prices tickets currently cost $6.00 and he estimates that for each $0.50 increase in price 100 few people were 10 what pressure he said it takes to make the most money based on this scenario
HELPP
Answer:
Step-by-step explanation:
To find the optimal ticket price that will maximize revenue, we need to determine the price point where the increase in revenue from selling each ticket at a higher price is greater than the decrease in revenue from selling fewer tickets due to the higher price.
Let's start by calculating the current revenue generated at the current ticket price of $6.00:
Current revenue = 1800 x $6.00 = $10,800
Now, we need to determine the effect of increasing ticket prices by $0.50 on the number of tickets sold:
For each $0.50 increase in ticket price, 100 fewer people will attend. So, for a $0.50 increase, the new ticket price will be $6.50, and the number of attendees will be:
1800 - 100 = 1700
For a $1.00 increase, the new ticket price will be $7.00, and the number of attendees will be:
1700 - 100 = 1600
And so on.
We can create a table to calculate the revenue at different price points:
Ticket Price Number of Tickets Sold Revenue
$6.00 1800 $10,800
$6.50 1700 $11,050
$7.00 1600 $11,200
$7.50 1500 $11,250
$8.00 1400 $11,200
$8.50 1300 $11,050
$9.00 1200 $10,800
As we can see from the table, the optimal ticket price that will maximize revenue is $7.50, where the revenue is $11,250. Beyond this point, the decrease in attendance outweighs the increase in ticket price, resulting in a decrease in revenue.
Therefore, the owner should increase the ticket price to $7.50 to maximize revenue.
Segment AB falls on line 6x + 3y = 12. Segment CD falls on line 4x+2y=8. What is true about segments AB and CD?
O They are parallel because they have the same slope of -2.
O They are parallel because they have the same slope of
2
O They are lines that lie exactly on top of one another because they have the same slope and the same y-intercept.
O They are lines that lie exactly on top of one another because they have the same slope and a different y-intercept
Answer:
(c) They are lines that lie exactly on top of one another because they have the same slope and the same y-intercept.
Step-by-step explanation:
You want to know the relation between the lines ...
6x +3y = 124x +2y = 8Standard formThese equations can be put into standard form by removing the common factor from the coefficients:
6x +3y = 12 ÷3 ⇒ 2x +y = 44x +2y = 8 ÷2 ⇒ 2x +y = 4We see that the equations give the same line. That is ...
(c) They are lines that lie exactly on top of one another because they have the same slope and the same y-intercept.
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