A net force of 10 N acts on the rock when it is halfway to the top of its path.
The net force acting on the rock can be calculated using the following equation:
Fnet = ma
Where Fnet is the net force, m is the mass, and a is the acceleration.
When the rock is halfway to the top of its path, its velocity is zero since it momentarily stops at the top of its motion. As a result, its acceleration is equal to the acceleration due to gravity, which is -10 m/s² since it is acting in the opposite direction to the upward direction. This is the gravitational force acting on the rock.
We can now calculate the net force acting on the rock at this point in its motion:
Fnet = ma
Fnet = (1 kg)(-10 m/s²)
Fnet = -10 N
Since the acceleration due to gravity is acting downward and the rock is moving upward, the net force is equal to the force of gravity, which is 10 N.
Therefore, the net force that acts on the rock when it is halfway to the top of its path is -10 N or 10 N in the downward direction. This net force is equal in magnitude to the weight of the rock.
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HELP ME PLEASE!!!
Which 2 statements are true about this chemical reaction that forms acid rain?
However, in general, acid rain is formed when sulphur dioxide (SO2) and nitrogen oxides (NOx) are emitted into the atmosphere by human activities, such as burning fossil fuels.
Which of the following is incorrect about the main cause of acid rain?The erroneous statement among the following is : Acid rain is largely because to oxides of nitrogen and sulphur The greenhouse effect is to blame for the world's warming. Infrared radiation from the sun cannot reach earth due to the ozone layer.
What does acid rain consist of ?Nitric and sulphuric acids are created when the gases nitrogen oxides and sulphur dioxide interact with the minute droplets of water in clouds. The rain from these clouds falls as very weak acid known as 'Acid rain'.
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Question:
"Which two of the following statements are true about the chemical reaction that forms acid rain?
a. Sulfur dioxide and nitrogen oxides react with water to form sulfuric acid and nitric acid.
b. Acid rain can cause damage to buildings and statues made of limestone or marble.
c. Acid rain is only a problem in areas with a high population density.
d. Acid rain has no effect on freshwater ecosystems."
find the net force on a 30.0 nc charge located at the origin by two other charges. one is -50.0 nc located at (-5.0 m, 2.0 m) and 40.0 nc located at (3.0 m, 1.0 m).
The net force on a 30.0 nc charge located at the origin by two other charges is the vector sum of the forces exerted by the two other charges. The force exerted by the first charge, -50.0 nC located at (-5.0 m, 2.0 m), is given by:
F1 = (k*q1*q2)/r2, where
k = 8.99 x 109 N m2/C2q1 = -50.0 ncq2 = 30.0 ncr = square root of (5.02 + 2.02) = 5.385Therefore,
F1 = (8.99 x 109 N m2/C2)*(-50.0 nc)*(30.0 nc)/(5.3852) = 2.38 x 10-2 N
Similarly, the force exerted by the second charge, 40.0 nc located at (3.0 m, 1.0 m), is given by:
F2 = (k*q1*q2)/r2, where
k = 8.99 x 109 N m2/C2q1 = 40.0 ncq2 = 30.0 ncr = square root of (3.02 + 1.02) = 3.162Therefore,
F2 = (8.99 x 109 N m2/C2)*(40.0 nc)*(30.0 nc)/(3.1622) = 4.58 x 10-2 N
The net force is the vector sum of F1 and F2 and can be calculated as follows:
F net = F1 + F2 = 2.38 x 10-2 N + 4.58 x 10-2 N = 7.00 x 10-2 N
Therefore, the net force on a 30.0 nc charge located at the origin by two other charges is 7.00 x 10-2 N.
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A resistor and a capacitor are connected in series across an ideal battery. At the moment contact is made with the battery the voltage across the capacitor is
a. equal to the battery's terminal voltage. b. less than the battery's terminal voltage, but greater than zero. c. zero.
When a resistor and a capacitor are connected in series across an ideal battery, the voltage across the capacitor is zero at the moment contact is made with the battery.
The correct option is c.
An ideal battery is a voltage source that delivers a constant voltage regardless of the load resistance or current drawn from it.
An ideal battery can maintain a steady voltage regardless of the amount of current being drawn from it.
In real-life batteries, there is always some internal resistance, which causes the voltage to drop as the current increases.
A resistor is an electrical component that opposes or limits the flow of electrical current. It has two terminals and can be made of various materials like carbon, metal, and ceramic. It is used in various applications, including voltage dividers, current limiting, and biasing.
A capacitor is an electronic component that stores energy in an electric field between two charged conductors. It has two terminals and is made of two conducting plates separated by an insulating material called a dielectric.
Capacitors are used in various applications, including energy storage, timing circuits, and power conditioning.
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if you hold a 1.85 kg k g package by a light vertical string, what will be the tension in this string when the elevator accelerates as in the previous part?
The tension in the string of a 1.85 kg package held by a light vertical string will depend on the acceleration of the elevator. When the elevator accelerates, the force of acceleration on the package will be equal and opposite to the tension in the string, causing the tension to increase.
The equation for tension in a string is:
Tension = Mass x Acceleration
Therefore, in this case, the tension in the string is equal to 1.85 kg x Acceleration.
If we assume that the acceleration of the elevator is a constant rate, then the tension in the string can be calculated by multiplying the mass of the package by the acceleration of the elevator.
To sum up, the tension in the string of a 1.85 kg package held by a light vertical string will depend on the acceleration of the elevator. If the acceleration of the elevator is a constant rate, then the tension in the string can be calculated by multiplying the mass of the package by the acceleration of the elevator.
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a weight hanging from a spring will remain hanging until the weight is pulled down and released. when the weight is released the spring will bounce up and down. which of newton's laws explains why the spring will bounce?
This principle can be observed in other everyday scenarios, such as jumping on a trampoline or the recoil of a gun after firing. Newton's Third Law of Motion is a fundamental principle in classical mechanics and explains why the spring will bounce when the weight is released.
The bouncing of the weight when released is explained by Newton's Third Law of Motion, which states that for every action there is an equal and opposite reaction. When the weight is released, the spring exerts an equal and opposite force on the weight, propelling it upwards and causing it to bounce. This is because when the weight is pulled down, it compresses the spring, storing potential energy. When the weight is released, the spring decompresses and the potential energy is released, propelling the weight in the opposite direction.
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pry on the power steering reservoir to adjust the tension of the power steering belt. true or false?
The statement "pry on the power steering reservoir to adjust the tension of the power steering belt" is: false.
The tension of the power steering belt is adjusted by adjusting the position of the power steering pump. There is a tension adjustment bolt on the power steering pump that is used to adjust the tension of the power steering belt. The adjustment bolt should be turned clockwise or counterclockwise to adjust the tension of the belt.
A belt tension gauge may be used to ensure that the belt is properly tensioned. A pry bar should not be used on the power steering reservoir to adjust the tension of the power steering belt. This could cause damage to the reservoir or other components of the power steering system. The reservoir should be inspected for damage or leaks, but it should not be used to adjust the tension of the belt.
In summary, the tension of the power steering belt should be adjusted by adjusting the position of the power steering pump, not by prying on the power steering reservoir.
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two stationary point charges q1 and q2 are shown in the figure along with a sketch of some field linesrepresenting the electric field produced by them. what can you deduce from the sketch?
From the sketch, we can deduce that the two charges q1 and q2 are of opposite signs, as field lines start at the positive charge q1 and end at the negative charge q2. The field lines also indicate that the magnitude of the electric field produced by q1 is larger than that of q2.
Additionally, the field lines show that the electric field lines near the charges are denser, indicating a stronger electric field intensity near the charges. The direction of the electric field points from q1 to q2, which is consistent with the direction of the force that a positive test charge would experience if placed in the field. The field lines also show that the electric field is radial, i.e., the field lines point directly away from or towards each charge in a straight line, which is a characteristic of the electric field produced by a point charge. Finally, the density of the field lines decreases with distance from the charges, indicating that the electric field strength decreases with distance from the charges, following an inverse-square law.Learn more about electric field at: https://brainly.com/question/14372859
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A skydiver of mass 95kg ,before opening his parachute, falls at t1 with V1= 11m/s and at t2 with t2 v2=27m/s; supposing friction is zero, find the distance covered between t1 and t2
The skydiver covered a distance of approximately 94.9 meters before opening his parachute between t1 and t2, assuming no air resistance or friction.
v = final velocity = v2 = 27 m/s
u = initial velocity = v1 = 11 m/s
a = acceleration = g = 9.8 m/[tex]s^2[/tex]
s = (v² - u²) / 2a
s = (27² - 11²) / (2 x 9.8) = 94.9 meters
Resistance measures an item's potential to impede the drift of electrical present-day through it. it's far measured in ohms (Ω). Resistance is decided by way of the bodily residences of an item, along with its dimensions, material, and temperature. while electric-powered present-day flows thru a conductor, it encounters resistance that slows down its float. This resistance is as a result of the collisions among electrons and the atoms inside the conductor.
Resistance can be laid low with changes inside the bodily properties of the conductor, such as duration, cross-sectional region, or temperature. an extended or narrower conductor may have higher resistance, even as a much broader conductor could have decreased resistance. understanding resistance is critical for designing and working electrical circuits. with the aid of controlling the resistance of a circuit, engineers can make sure that the appropriate amount of current flows to electricity the devices linked to it.
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a spherical capacitor has vacuum between its conducting shells and a capacitance of 125 pf . the outer shell has inner radius 9.00 cm . what is the outer radius of the inner shell? express your answer with the appropriate units.
For a spherical capacitor with a capacitance of 125 and a vacuum between its conducting shells, the outer radius of the inner shell is around 5.60 cm.
The capacitance of a spherical capacitor is given by:
C = 4πε₀[(r₁r₂)/(r₂-r₁)]
where C is the capacitance, ε₀ is the electric constant (8.85 x [tex]10^{-12}[/tex] F/m), r₁ is the radius of the inner shell, and r₂ is the radius of the outer shell.
In this case, we know that the capacitance C = 125 pF (picoFarads), r₂ = 9.00 cm, and we want to find r₁.
We can rearrange the equation to solve for r₁:
r₁ = (C × r₂)/(4πε₀ + C)
Substituting the values:
r₁ = (125 x [tex]10^{-12}[/tex] F × 0.09 m) / (4π × 8.85 x [tex]10^{-12}[/tex] F/m + 125 x [tex]10^{-12}[/tex] F)
r₁ ≈ 5.60 cm
Therefore, the outer radius of the inner shell is approximately 5.60 cm.
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how to find the minimum thickness of a film such that reflected light undergo constructive interference
The minimum thickness of the film for constructive interference of reflected light would be t = 3*600/(2*1.4) = 850 nm.
The minimum thickness of a film required for constructive interference of reflected light can be calculated using the formula t = m*λ/(2*n),
where t is the minimum thickness of the film, m is the order of interference, λ is the wavelength of the light, and n is the index of refraction of the film.
For example, if the order of interference is 3, the wavelength of the light is 600 nm, and the index of refraction is 1.4,
the minimum thickness of the film for constructive interference of reflected light would be t = 3*600/(2*1.4) = 850 nm.
Constructive interference of reflected light occurs when the phase difference between the two waves is equal to an integral multiple of 2π.
This can be determined using the formula Δφ = (2π*m)/(λ*n), where Δφ is the phase difference, m is the order of interference, λ is the wavelength of the light, and n is the index of refraction of the film.
To achieve constructive interference, the minimum thickness of the film can be determined by ensuring that the phase difference is equal to an integral multiple of 2π.
The minimum thickness of a film required for constructive interference of reflected light can be calculated using the formula t = m*λ/(2*n),
where t is the minimum thickness of the film, m is the order of interference, λ is the wavelength of the light, and n is the index of refraction of the film.
Constructive interference can be achieved by ensuring that the phase difference between the two waves is equal to an integral multiple of 2π.
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To determine the location of her center of mass, a physics student lies on a lightweight plank supported by two scales 2.50m apart, as indicated in the figure . If the left scale reads 290 N, and the right scale reads 112 N. What is the student's mass and find the distance from the student's head to her center of mass.
The location of her centre of mass, a physics student lies on a lightweight plank supported by two scales 2.50m apart, as indicated in the figure. If the left scale reads 290 N and the right scale reads 112 N The student's mass is approximately 41 kg, and the distance from her head to her centre of mass is approximately 0.696 m.
To determine the student's mass, we can sum up the readings from both scales, which are measures of force (Newtons) and then convert it to mass using the gravitational acceleration (g = 9.81 m/s²).
Step 1: Calculate the total force acting on the plank:
Total Force = Force_left_scale + Force_right_scale
Total Force = 290 N + 112 N
Total Force = 402 N
Step 2: Convert the total force to mass using gravitational acceleration:
Mass = Total Force / g
Mass = 402 N / 9.81 m/s²
Mass ≈ 41 kg
Now, to find the distance from the student's head to her centre of mass, we'll use the principle of torque equilibrium.
Step 3: Set up the torque equation:
Torque_left_scale = Torque_right_scale
Force_left_scale × Distance_left_scale = Force_right_scale × Distance_right_scale
Let x be the distance from the student's head to her centre of mass. Then, the distance from the left scale to the centre of mass is x, and the distance from the right scale to the centre of mass is (2.50 - x).
Step 4: Plug in the known values and solve for x:
290 N × x = 112 N × (2.50 - x)
Step 5: Simplify the equation and solve for x:
290x = 112(2.50) - 112x
290x + 112x = 112(2.50)
402x = 280
x ≈ 0.696 m
The student's mass is approximately 41 kg, and the distance from her head to her centre of mass is approximately 0.696 m.
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logs sometimes float vertically in a lake because one end has become water-logged and denser than the other. what is the average density of a uniform-diameter log that floats with 20.0% of its length above water?
Uneven-diameter logs that float with 20.0% of their length above water have an average density of 0.8g/cm3. The density is the proportion of weight to capacity.
An item it's far less compact that liquid may be supported up liquid water, and hence it floats. More dense objects can sink when submerged in water. Less dense logs float whereas more thick logs sink. A body can change its condition of rest or motion by the application of force
Instead of obliquely reading from either the side, read the scale stick straight from of the end of both the log. → The diameter of a log is only ever calculated within the bark. Employ a log measuring rod to determine the log's small end's "diameter from within bark," also known as "d.i.b."
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5. does it take the same amount of work to speed your car up from 25 m/s to 30 m/s as it does to speed it up from 30 m/s to 35 m/s? if not, which situation requires more work? why? use the cer framework to answer the question.
The same amount of work to speed up a car from 25 m/s to 30 m/s as it does from 30 m/s to 35 m/s is different because it requires more work to speed up a car from 30 m/s to 35 m/s than it does to speed it up from 25 m/s to 30 m/s.
Thus, the correct answer is "No, it doesn't".
The CER framework is a tool that can be used to answer questions that involve scientific principles. CER stands for Claim, Evidence, and Reasoning.
1. Claim: It does not take the same amount of work to speed up a car from 25 m/s to 30 m/s as it does to speed it up from 30 m/s to 35 m/s.
2. Evidence: Work is equal to force times distance, which means that the amount of work required to accelerate an object depends on the distance over which the force is applied. If the distance is shorter, less work will be done.
The distance over which the force is applied to speed up a car from 30 m/s to 35 m/s is shorter than the distance over which the force is applied to speed it up from 25 m/s to 30 m/s. This implies that more work is required to speed up a car from 30 m/s to 35 m/s than it does to speed it up from 25 m/s to 30 m/s. The equation for calculating work is W = F x D, where W is work, F is force, and D is distance.
3. Reasoning: Therefore, it requires more work to speed up a car from 30 m/s to 35 m/s than it does to speed it up from 25 m/s to 30 m/s. This is because the distance over which the force is applied to speed up a car from 30 m/s to 35 m/s is shorter than the distance over which the force is applied to speed it up from 25 m/s to 30 m/s. The work done on an object is a measure of the energy transferred to it. When more work is done on an object, more energy is transferred to it.
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an n-type piece of silicon experiences an electric field equal to 0.1v/m. (a) calculate the velocity of electrons and holes in this material
In an n-type piece of silicon, the electric field causes the electrons to accelerate due to the attractive force between the negatively charged electrons and the positively charged electric field. This acceleration causes the electrons to reach a velocity of V = E/μ, where E is the electric field (0.1V/m) and μ is the mobility of electrons in silicon (1350 cm2/V⋅s). Therefore, the velocity of electrons in this material would be equal to 0.1V/m/1350cm2/V⋅s = 0.0741 cm/s.
The holes, on the other hand, experience a repulsive force due to the positive electric field. This causes the holes to decelerate, with a velocity of V = -E/μ. Therefore, the velocity of holes in this material would be equal to -0.1V/m/1350cm2/V⋅s = -0.0741 cm/s.
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when rotating the platform, the hanging mass should be removed from the platform. question 2 options: true false
The given statement, while the platform is rotating, the hanging mass remains attached to the test mass and is not removed from the platform is true, if the purpose of the experiment or test is to determine the effect of the hanging mass on the rotation or stability of the platform.
In this case, the hanging mass must remain attached to the test mass during the rotation to observe the behavior of the system under the specified conditions. If the purpose of the experiment or test is to study the effect of the hanging mass on the platform's rotation or stability, the hanging mass must remain attached to the test mass during the rotation. This is because the presence of the hanging mass affects the overall weight and center of gravity of the system. Removing the hanging mass would alter the system's behavior and prevent accurate observations of the phenomenon under investigation. Therefore, if the experiment requires the hanging mass to be present, it must remain attached to the test mass while the platform is rotating.
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--The complete question is, While the platform is rotating, the hanging mass remains attached to the test mass and is not removed from the platform. State true/false.--
a system releases 690 kj of heat and does 110 kj of work on the surroundings. part a what is the change in internal energy of the system?
A system releases 690 kj of heat and does 110 kj of work on the surroundings then part a what i the change in internal energy of the system -800 kJ.
The change in internal energy of the system can be calculated using the formula
ΔU = Q - W,
where ΔU is the change in internal energy, Q is the heat exchanged, and W is the work done.
In this case, the system releases 690 kJ of heat (Q = -690 kJ) and does 110 kJ of work on the surroundings (W = 110 kJ).
So, ΔU = -690 kJ - 110 kJ = -800 kJ.
The change in internal energy of the system is -800 kJ.
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a brick is falling from the roof of a three-story building. how many force vectors would be shown on a free-body diagram? name them
A brick is falling from the roof of three story building then free-body diagram would show only one force vector, which is the force of gravity acting on the brick.
A free-body diagram is used to graphically represent the forces acting on an object. It shows all of the forces acting on an object and can be used to analyze the motion of an object.
A free-body diagram for a falling brick would include two force vectors: Gravity or Weight.
If we consider only the brick and neglect air resistance, then there are two force vectors that would be shown on a free-body diagram of the brick:Force of gravity: The force of gravity, which pulls the brick downwards with a magnitude of its weight. This force is always present and directed downwards towards the center of the Earth. Normal Force: The normal force, which is the force exerted by the roof or any surface in contact with the brick that prevents it from falling through the surface. As the brick is falling, there is no contact force from the roof, so the normal force is zero.So, in this scenario, the free-body diagram would show only one force vector, which is the force of gravity acting on the brick.
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A dog can hear sounds in the range from 15
to 50,000 Hz.
What wavelength corresponds to the lower
cut-off point of the sounds at 20◦C where the
sound speed is 344 m/s?
Answer in units of m.
Explanation:
Speed of sound is 344
The frequency corresponding to the lower cut-off point is the lowest frequency which his 15Hz
F=15Hz
The relationship between the wavelength, speed and frequency is given as
v=fλ
Then,
λ=v/f
λ=v/f
λ=344/15
λ=22.93m
A 23.3 kg boy is moving along a circular path with the constant speed of 2.7 m/s. What is the magnitude of the centripetal force acting on the boy if the radius of the circle is 12.9 m. Note : Calculate the answer to 3 (three) significant figures by presenting it in normal ( decimal) form. Don't forget to include the unit.
The centripetal force for the given question would be 16.3 N.
Explanation:
The magnitude of the centripetal force acting on a 23.3 kg boy moving along a circular path with a constant speed of 2.7 m/s and the radius of the circle is 12.9 m is 16.3 N (newton).
What is centripetal force?
Centripetal force is the net force acting on an object moving in a circular path toward the center of the circle. It always points towards the center of the circle, hence the name "center-seeking force".
What is the formula for centripetal force?
The formula for centripetal force is Fc = (mv²)/r, where Fc is the centripetal force, m is mass, v is velocity or speed and r is the radius of the circular path.
In the given question: Mass, m = 23.3 kgVelocity, v = 2.7 m/s, Radius, r = 12.9. To calculate centripetal force,
F = (m x v^2)/r
Putting the given values in the above formula: F = (23.3 kg x (2.7 m/s)^2)/12.9 m= 16.3 N (newton)
Therefore, the magnitude of the centripetal force acting on the boy is 16.3 N (newton).
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We were just introduced to electricity in physics and I have some questions:
1. Since electrons can be transferred from our hair to the balloon, can electrons also be transferred from the balloon to our hair? (Do questions always say whether an object is positive or negative charge)
2. Do electrons stay in place since balloons are rubber insulators?
3. What point do neutrons serve? Are they just there?
4. Are objects in constant exchange of energy with one another? Whenever they come in contact they exchange electrons until equal?
1 - Since electrοns can be transferred frοm οur hair tο the ballοοn , electrοns cannοt be transferred frοm ballοοn tο οur hair because. This is an illustratiοn οf charging by cοnductiοn.
2 - Since the rubber οn the ballοοn is significantly less cοnductive than the hair, electrοns will nοt easily escape the ballοοn because οf this.
3 - Neutrοns are electrically neutral , neutrοns dοesn't participate in this prοcess.
What is charging by cοnductiοn?A charged οbject must cοme intο cοntact with a neutral οbject tο cοnduct electricity. As a result, when twο charged cοnductοrs cοme intο cοntact, the charge is split between the twο cοnductοrs, charging the uncharged cοnductοr.
When twο neutral οbjects are rubbed against οne anοther, electrοns are transferred. The οbject that has a strοnger affinity fοr electrοns will take electrοns frοm the οther οbject, and the twο becοme charged in οppοsitiοn. In this instance, the electrοns frοm the hair are taken up by the ballοοn , which nοw has an excess οf electrοns and a negative charge cοmpared tο the hair's current electrοn shοrtage and pοsitive charge.
2- Since the rubber οn the ballοοn is significantly less cοnductive than the hair, electrοns will nοt easily escape the ballοοn because οf this.
3- Neutrοns are electrically neutral , neutrοns dοesn't participate in this prοcess.
4-Insulating materials may becοme electrically charged when they cοme intο cοntact with οne anοther. Negatively charged electrοns can "rub οff" οne material and "rub οn" tο anοther. After bοth things have the same quantity οf οppοsite charges, the substance that gets electrοns becοmes negatively charged, and the material that lοses electrοns becοmes pοsitively charged.
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a 100 cm diameter propeller blade, similar to the blade in example 4.15, is attached to a motor spinning at a constant rate. what is true about the radial (centripetal) acceleration and the tangential acceleration at the end of the blade?
The true statements about the radial (centripetal) acceleration and the tangential acceleration at the end of the blade are: the radial acceleration is non-zero the tangential acceleration is zero
The radial acceleration is non-zero and the tangential acceleration is zero. This is because, the radial acceleration is determined by the formula, ar = (v²)/r
where ar is the radial acceleration, v is the velocity and r is the radius. Thus, since the propeller blade is spinning at a constant rate, the velocity v is constant.
Therefore, the radial acceleration is constant and non-zero.
The tangential acceleration, on the other hand, is given by at = rα
where at is the tangential acceleration and α is the angular acceleration. Since the blade is spinning at a constant rate, the angular acceleration is zero. Therefore, the tangential acceleration is zero.
So, the correct option is the radial acceleration is non-zero and the tangential acceleration is zero.
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a value of mass is given as 14.6 g to 15.2 g. a value of volume is given as 2.4 to 2.8 m3. state the density using reasonable outer limits.
The density using reasonable outer limits is the density of an object can be determined by dividing its mass (measured in grams, g) by its volume (measured in cubic metres, m3). To calculate the density using the given values of mass and volume, we can use the following formula: Density = Mass/Volume.
Therefore, the density of the given object can be calculated using the outer limits of mass and volume, which are 14.6 g to 15.2 g and 2.4 m3 to 2.8 m3, respectively. The calculated density of the given object is in the range of 5.75 g/m3 to 5.45 g/m3.
To calculate the density, the mass and volume of the object must be known. Mass is a measure of how much matter an object has, and is calculated in grams (g). Volume, on the other hand, is a measure of the amount of space an object takes up, and is calculated in cubic metres (m3).
When these two values are known, the density can be calculated using the formula: Density = Mass/Volume. In this case, the given values of mass and volume are 14.6 g to 15.2 g and 2.4 m3 to 2.8 m3, respectively. By substituting these values into the formula, the density of the object can be calculated as follows:
Density = Mass/Volume
Density = 14.6 g/2.4 m3 = 5.75 g/m3
Density = 15.2 g/2.8 m3 = 5.45 g/m3
Therefore, the density of the given object is in the range of 5.75 g/m3 to 5.45 g/m3.
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a heat pump with a cop of 4.0 supplies heat to a building at a rate of 100 kw. determine the power input to the heat pump.
The power input to the heat pump is 25 kW.
The COP (coefficient of performance) of the heat pump is 4.0. This means that for every unit of power consumed by the heat pump, it supplies four units of heat to the building.
The rate at which the heat pump supplies heat to the building is 100 kW.
Therefore, the power input to the heat pump can be calculated as:
Power input = Power output / COP
Power input = 100 kW / 4.0
Power input = 25 kW
Hence, the power input to the heat pump is 25 kW.
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I have no clue what im doing..
If work = 100J and time = 20 seconds, what is power
Answer:
5 J/s or 5 watt
Explanation:
Given,
Work (W) = 100 J
Time (t) = 20 s
To find : Power (P)
Formula :
P = W/t
P = 100/20
P = 5 J/s
P = 5 watt
Note : -
J/s and watt are units are power.
A 750-kg roller coaster car drops from rest at a height of 90.0 m along a frictionless track. If the coefficient of kinetic friction due to braking along a horizontal track at the end of the ride is 0.720, over what distance does the car need to brake to come to a complete stop?
a ball of mass is dropped. what is the formula for the impulse exerted on the ball from the instant it is dropped to an arbitrary time later?
The formula for the impulse exerted on the ball from the instant it is dropped to an arbitrary time later is:
Impulse = (Final momentum - Initial momentum)
What is impulse?Impulse is a vector quantity having both magnitude and direction, whereas momentum is a vector quantity, but the impulse is not equal to momentum. The impulse is the change in momentum.
If a ball of mass m is dropped from rest, then its initial momentum is zero.
The final momentum of the ball after falling for time t is:
Final momentum = mv
Where v is the velocity of the ball after falling for time t.
Therefore, the impulse exerted on the ball from the instant it is dropped to an arbitrary time later is:
Impulse = (mv - 0) = mv
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calculate the average force on the person if he is stopped by a padded dashboard that compresses an average of 1.00 cm. calculate the average force on the person if he is stopped by an air bag that compresses an average of 15.0 cm.
The average force on the person if they are stopped by an airbag that compresses an average of 15.0 cm is approximately 70,000 N.
To calculate the average force on a person,
Average force = (change in momentum) / (time interval)
Assuming that the person's initial velocity is constant, we can simplify the formula to,
Average force = (mass of the person) x (change in velocity) / (time interval)
Now, let's consider the two scenarios,
Stopped by a padded dashboard that compresses an average of 1.00 cm:
Assuming the person's initial velocity is known and constant, we need to know the time interval it takes for the person to stop after hitting the dashboard. Without this information, we cannot calculate the average force.
Stopped by an airbag that compresses an average of 15.0 cm:
The time interval for an airbag to deploy and cushion the person's impact is typically very short (about 0.03 seconds), so we can assume that the time interval is negligible in this case. Therefore, we can use the simplified formula above.
Let's assume the mass of the person is 70 kg and their initial velocity is 30 m/s. The change in velocity is the final velocity (0 m/s) minus the initial velocity (30 m/s), which is -30 m/s. The negative sign indicates that the person's velocity is decreasing.
Using the formula,
Average force = (mass of the person) x (change in velocity) / (time interval)
= (70 kg) x (-30 m/s) / (0.03 s)
= -70,000 N
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a 6 mf capacitor, a 10 mf capacitor, and a 16 mf capacitor are connected in parallel. what is their equivalent capacitance?
The equivalent capacitance of a 6 mF capacitor, a 10 mF capacitor, and a 16 mF capacitor connected in parallel is: 32 mF
This is because when capacitors are connected in parallel, their total capacitance is equal to the sum of their individual capacitances. The formula for calculating the equivalent capacitance (C) of capacitors connected in parallel is: C = C1 + C2 + C3 + ... In this example, C = 6 mF + 10 mF + 16 mF = 32 mF.
Capacitors are electrical components that store energy in the form of an electric field between two conductors (plates). When capacitors are connected in parallel, the electric field between the plates of each capacitor is the same, but the overall capacitance is increased due to the combined plate area of all the capacitors.
This increase in plate area is why the equivalent capacitance of the three capacitors in this example is 32 mF, which is larger than any of the individual capacitances.
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how many electrons per second enter the positive end of the battery 2? answer in units of electrons/s.
The number of electrons per second that enter the positive end of a battery can be calculated by the current flowing through the circuit and the time for which it flows.
Therefore, The formula of current is as
I = Q/t
where I is the current,
Q is the charge passing through the circuit, and
t is the time for which the current flows.
Since one electron carries a charge of -1.6 x 10⁻¹⁹Coulombs, we can calculate the number of electrons passing through the circuit using the following formula:
n = Q/e
where n is the number of electrons and
e is the charge on an electron (-1.6 x 10⁻¹⁹ Coulombs).
If we know the current flowing through the circuit and the time for which it flows, we can calculate the number of electrons per second using the following formula:
n/s = I/e
where n/s is the number of electrons per second.
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the intensity of the sound of a television commercial is 10 times greater than the intensity of the television program it follows. by how many decibels does the loudness increase?
The television commercial loudness increases by 10 decibels.
Increase in the Intensity of soundThe decibel (dB) scale is a logarithmic measure of sound intensity. The intensity of a sound is measured in watts per square meter and the decibel scale is a way to express the relative loudness of a sound, compared to a reference level.
A 10 dB increase in intensity is a 10-fold increase in sound power. This means that a sound with an intensity of 10 watts per square meter is 10 times louder than a sound with an intensity of 1 watt per square meter.
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