a 24/7 calling center works as follows: every agent works 5 days in a row and has two days rest, e.g., every week works tuesday-saturday and rests on sunday and monday. the numbers of agents working every day of a week should be at least given numbers d1; :::; d7. the manager wants to meet this requirement with the minimal possible total number of agents employed, by deciding what will be the days o of the agents. assuming that di are large, so that we can ignore integrality restrictions, formulate manager's problem as an lo program.

120 table spoons of lemon juice.

15 cups of olive oil.

The question 4 groups of 3 can be calculated to be a total of 12 objects across all groups.

The total number of groups are 4 in number

Each of the 4 groups have 3 objects in it.

That is 3 in 4 places

This can be solved by 4 * 3 = 12

Hence we can say that the solution for the questions that says 4 groups of 3 is 12

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Answer:

The equation for the area of a rectangle is length*width. For this problem, it says the length is 8 and the width is (3n+2). All you have to do is multiply 8 by (3n+2).

8(3n+2)=A

24n+16=A

Option A is correct

f(x) = 7x - 1, which is a linear equation with a positive leading coefficient, making f(x) > 0 for all x.

Set 1: {f(x) = x + 1, f(x) = x - 1}

Function f(x) = x^2 + 2 can be found in the span of the two given functions. This can be seen by expanding the equation:

f(x) = x^2 + 2 = (x + 1) + (x - 1) = 2x;

thus, f(x) = 2x + 2, which is a quadratic equation with a positive leading coefficient, making f(x) > 0 for all x.

Set 2: {f(x) = 4x - 2, f(x) = 3x + 1}

Function f(x) = 7x - 1 can be found in the span of the two given functions. This can be seen by expanding the equation:

f(x) = 7x - 1 = (4x - 2) + (3x + 1) = 7x;

thus, f(x) = 7x - 1, which is a linear equation with a positive leading coefficient, making f(x) > 0 for all x.

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Complete question:Find a function f(x) in the span of the functions f1(x) = x and f2(x) = -x such that f(x) > 0 for all x.

For the value of x = 4, the inequality equation that is true is option C: x/2 < 3.

What is an inequality?

In Algebra, an inequality is a mathematical statement that uses the inequality symbol to illustrate the relationship between two expressions. An inequality symbol has non-equal expressions on both sides. It indicates that the phrase on the left should be bigger or smaller than the expression on the right, or vice versa.

The first inequality equation is - x + 5 < 3

Substitute the value of x = 4 in the equation.

4 + 5 < 3

Now, simplify the equation -

9 < 3

It is known that 9 is not less than 3, but greater than 3.

Therefore, this inequality is false.

The second inequality equation is - 9x > 36

Substitute the value of x = 4 in the equation.

9(4) > 36

Now, simplify the equation -

36 < 36

It is known that 36 is not less than 36, but equal 36.

Therefore, this inequality is false.

The third inequality equation is - x/2 < 3

Substitute the value of x = 4 in the equation.

4/2 < 3

Now, simplify the equation -

2 < 3

It is known that 2 is less than 3.

Therefore, this inequality is true.

The fourth inequality equation is - 18 < x + 8

Substitute the value of x = 4 in the equation.

18 < 4 + 8

Now, simplify the equation -

18 < 12

It is known that 18 is not less than 12, but greater than 12.

Therefore, this inequality is false.

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Which inequality is true when x = 4?

A. x + 5 < 3

B. 9x > 36

C. ×/2 < 3

D. 18 < x + 8

Quadrilateral DEFG is similar to quadrilateral HIJK The measure of side JK is 8.

Since quadrilateral DEFG is similar to quadrilateral HIJK, we know that the ratio of corresponding side lengths is equal. This means that if we know the length of one side of one of the quadrilaterals, we can use that ratio to find the length of the corresponding side in the other quadrilateral.

For example, if we know that side DE is 8 units long, we can use the ratio of side JK to side DE (x/8) to find the length of side JK. We can also use the same ratio of side IJ to side DF which is x/4.

Let's assume that the length of side DE is 8 units. We can use the ratio of side JK to side DE (x/8) to find the length of side JK.

[tex]x/8 = x/4[/tex]

Cross-multiplying and simplifying the equation we get

[tex]4x = 8x[/tex]

[tex]x = 8[/tex]

Therefore, the measure of side JK is 8 units.

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The transformation applied is the one in option D, a vertical dilation of scale factor of 5, and a shift of 10 units up.

Here we start with the parent quadratic function:

f(x) = x²

And we have the transformed function:

h(x) = 5x² + 10

We can write this as:

A vertical dilation of a scale factor 5, which will give:

h(x) = 5*f(x)

And then a translation of 10 units upwards, which gives:

h(x) = 5*f(x) + 10

Replacing the function f(x) we will get:

h(x) = 5*x² + 10

Then the correct option is D.

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The image of quadratic function f(x) = x² is equal to g(x) = 6 · x².

In this question we see the representation of quadratic equation f(x) = x², from which we need to generate the image of this function, this can be done by a rigid transformation known as vertical dilation:

g(x) = k · f(x), k > 1

Where:

If we know that f(x) = x² and k = 6, then the image of function is:

g(x) = 6 · x²

Whose representation on Cartesian plane is shown in the image attached below.

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Answer:

9.5

Step-by-step explanation:

Distance (d) = [tex]\sqrt{(2-(-7.5)^2)+(-11-(-11)^2)}\\ \sqrt{(9.5)^2+(0)^2}\\ \sqrt{90.25} \\9.5[/tex]

The equation y is 2x - 3 describes the line with a slope of 2 and a Y-intercept of -3.

Use m is used to show the slope of a line.

m = 2

c is used to signify the line's y-intercept. c = -3

For the line's equation, the slope-intercept is: y = mx + c

In the equation above, replace c = -3 with m = 2 ,y = 2x - 3

Consequently, the equation of the line with a Y-intercept of -3 and a slope of 2 is as follows: y = 2x - 3.

For the line's equation, the slope-intercept is: y = mx + c

In the equation above, replace c = -3 with m = 2 ,y = 2x - 3

Consequently, the equation of the line with a Y-intercept of -3 and a slope of 2 is as follows: y = 2x - 3.

The complete question is,

The line with a -3 Y-intercept and a 2 slope has what equation?

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Answer:

less than or equal to N7500

Step-by-step explanation:

N2x - N5000 =  N2500

N2x = N7500

Simple equation when u break it down: 33 x 24=792 apartments

A building, or edifice, is an enclosed structure with a roof and walls that is standing in one location more or less permanently, such as a house or factory (although there are also portable buildings). Buildings come in a variety of sizes, shapes, and uses, and they have been modified throughout history for a wide range of reasons, including the availability of building materials, weather, land prices, ground conditions, particular uses, prestige, and aesthetic considerations.

given:

new apartments' building =33 floor

apartments on each =24 floor

33*24=792

792 apartments are in the building

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Answer:

Yesterday I have received amount of be with you i need to pay

The interval on which the profit function is increasing is [0, 25).

Given that:

The cost function is, C(x) = 1.2x - 0.012x²

The revenue function is, R(x) = 3.6x - 0.06x²

Here, x i is the number of units sold, and 0 ≤ x ≤ 150.

The profit function is:

P(x) = R(x) - C(x)

      = (3.6x - 0.06x²) - (1.2x - 0.012x²)

      = 2.4x - 0.048x²

Find P'(x).

P'(x) = 2.4 - 0.096x

The profit function is increasing when P'(x) > 0.

2.4 - 0.096x > 0

2.4 > 0.096x

25 > x

That is x < 25.

Hence the function is increasing in the interval [0, 25).

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If the relation is represented by the equation y = 2x + 1, the domain would be all real numbers (-infinity, +infinity) and the range would be all real numbers greater than or equal to 1 (1, +infinity).

A relation is a function if for every input (x) there is exactly one output (y). To determine if a relation is a function, we can use the vertical line test, which states that if a vertical line can be drawn through the graph and intersects the relation more than once, then the relation is not a function.

If the relation is a function, we can find the domain and range by analyzing the relation. The domain is the set of all x-values and the range is the set of all y-values. In interval notation, the domain is written as (a, b) and the range is written as (c, d).

So, the domain and range answers depend on the relation which is given and it should be specified.

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The hypothesis of the conditional statement is;

Option A: we walk home from school

A hypothesis is defined as an educated guess while using reasonable thought patterns, about the answer to a scientific question.  Now, the hypothesis can either be supported or not supported at all, but then it depends on the data gathered.

A conditional statement is defined as a set of rules performed provided a certain condition is met. Thus, it is sometimes referred to as If-Then statement because if a condition is said to be met, then an action is said to have been performed " .

Thus, the conditional statement here is: " we walk home from school ".

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A population of bacteria growing exponentially can be modeled as P(t)= P0e kt, where is the time in hours and P0 is the initial population. if the population has a doubling time of 3 hours, the growth constant  is k = ln(2) / 3 = 0.231049.

The growth constant (k) can be calculated by taking the natural log of 2 (ln(2)) and dividing it by the doubling time (3 hours). Therefore, the growth constant is 0.231049.  This equation models exponential growth, which is a type of growth where the rate of increase is proportional to the population size. In this case, the population doubles every 3 hours.

This exponential growth is modeled using the equation P(t)= P0e^kt, where P(t) is the population size at a given time, P0 is the initial population size, and k is the growth constant.  By finding the growth constant, we can predict the population size at any given time. The growth constant is found by taking the natural log of 2 (ln(2)) and dividing it by the doubling time (3 hours).

This equation is used to find the amount of growth per unit time and is the same regardless of the population size. This equation can be used to predict the population size at any given time, allowing us to estimate the population size in the future.

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Part (a)

The two limit statements tell us that this an exponential decay function.

The curve goes up forever when heading to the left (negative infinity) as indicated by the notation [tex]\displaystyle \lim_{\text{x}\to-\infty}f(x) = \infty[/tex]

At the same time, the curve slowly approaches the horizontal asymptote y = -2, when moving to the right, because of this notation [tex]\displaystyle \lim_{\text{x}\to\infty}f(x) = -2[/tex]

An exponential decay function like [tex]\text{y} = (0.5)^{\text{x}}[/tex] has a horizontal asymptote of y = 0, aka the x axis. The y value approaches 0 but never gets there. Each output is positive.

Shift everything down 2 units to arrive at [tex]\text{y} = (0.5)^{\text{x}}-2[/tex] and this will move the horizontal asymptote down the same amount.

There's nothing really special about the 0.5; you can replace it with any value in the interval 0 < b < 1.

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====================================================

Part (b)

I'll use this template

[tex]\text{y} = ab^{\text{x}}+c[/tex]

Plugging in x = 0 leads to y = a+c which is the y intercept. Set this equal to the stated y intercept 7 and we get a+c = 7.

We want the [tex]ab^{\text{x}}[/tex] portion to approach zero, which leads to c = 4 so we approach the stated horizontal asymptote.

So,

a+c = 7

a+4 = 7

a = 7-4

a = 3

We go from this

[tex]\text{y} = ab^{\text{x}}+c[/tex]

to this

[tex]\text{y} = 3b^{\text{x}}+4[/tex]

The value of b doesn't matter.

I'll go for b = 0.7 so we get to [tex]\text{f(x)} = 3(0.7)^{\text{x}}+4[/tex]

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====================================================

Part (c)

The parent function [tex]\text{y} = \log(\text{x}})[/tex] has a domain of [tex](0, \infty)[/tex]. In other words it is the interval [tex]0 < \text{x} < \infty[/tex]

If we replaced each input x with x-5, then we shift the xy axis 5 units to the left. It gives the illusion the log curve moves 5 units to the right.

The vertical asymptote also moves 5 units to the right. We go from a domain of [tex](0, \infty)[/tex] to a domain of [tex](5, \infty)[/tex]

The base of the log doesn't matter.

---------

Check out the graphs below. I used GeoGebra, but Desmos is another good option.

The required blueberries Ben has 6 5/12 pounds.

The equation model is defined as the model of the given situation in the form of an equation using variables and constants.

Here,
Let the amount of blueberries Ben has to be x,
According to the question,
Together, they have 9 2/3 pounds of blueberries.
x + 3 1/4 = 9 2/3
x = 9 2/3 - 3 1/4
x = 9 + 2/3 - 3 -1/4
x = 6 + 5/12
x = 6 5/12 pounds

Thus, the required blueberries Ben has 6 5/12 pounds.

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Using Moore's Law, which states that the number of transistors on a chip doubles approximately every two years, the estimated number of transistors per IC in 1992 would be 64,000.

The law claims that we can expect the speed and capability of our computers to increase every two years because of this, yet we will pay less for them. In more simple terms, the observation by Gordon Moore in 1965 that the number of transistors in a dense integrated circuit (IC) doubles roughly every two years is known as Moore's law.

This is calculated by doubling the estimate of 4,000 transistors every two years for a total of 8 doublings (16 years).

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The solution to the equation 10+4y=-4y+2 is -1 because the variable y represents the same value.

An equation is a formula in mathematics that expresses the equality of two expressions by connecting them with the equals sign =. In its most basic form, an equation is a mathematical statement that shows that two mathematical expressions are equal. 3x + 5 = 14, for example, is an equation in which 3x + 5 and 14 are two expressions separated by a 'equal' sign. A mathematical equation that depicts the relationship between two expressions on opposite sides of the sign. It mostly consists of one variable and one equal to symbol. 2x - 4 = 2 is an example.

Here,

10+4y=-4y+2

8y=-8

y=-1

The solution of equation 10+4y=-4y+2 is -1 as the variable y represents the same value.

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The required number of sheets cut from the stock are 9.

A mixed fraction is one that is represented by both its quotient and remainder. For example, 2 1/3 is a mixed fraction, where 2 is the quotient, 1 is the remainder. An amalgam of a whole number and a legal fraction is a mixed fraction.

We have,

We need sheets of length = 2 (3/4) in from 26 (1/8) in stock.

So, 2 (3/4) = 11/4 in

26 (1/8) = 209/8

Then,

Number of sheets =  209/8 / 11/4

Number of sheets = 836/88

Number of sheets = 9.5

So, 9 sheets can be cut.

Thus, required number of sheets are 9.

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Answer:

  5.2 square units

Step-by-step explanation:

You want the area of a triangle with sides 4 and 3, and the angle between them measuring 60°.

The formula for the area of a triangle is ...

  A = 1/2ab·sin(C)

Here, we have a=4, b=3, C=60°, so the area is ...

  A = 1/2·4·3·sin(60°) = 3√3 ≈ 5.2 . . . . square units

The area of the triangle is about 5.2 square units.

Answer:

48.53 = 49 feet

Step-by-step explanation:

sin 0 = opposite/hypotenuse

sin 68 = AB/AC = 45/x

x = 45/sin 68 = 45/0.9272 = 48.53

48.53 rounded = 49 feet

Answer:

You have let out 48.5 feet of string

Step-by-step explanation:

Attached is a sketch of the problem.

We can use SOH CAH TOA to find our answer.

In this acronym, O is the opposite side, A is the adjacent side, and H is the hypotenuse. S is for the SIN function. C is for the COS function. T is for the TAN function.

We can calculate the length of the string by using the SIN function.

So we can say the sine of angle x is the opposite side divided by the hypotenuse.

[tex]sin(x)=\frac{O}{H}[/tex]

Lets solve for [tex]H[/tex].

Multiply each term by [tex]H[/tex].

[tex]H*sin(x)=\frac{O}{H} *H[/tex]

Simplify the right side by cancelling the common factor of [tex]H[/tex].

[tex]H*sin(x)=O[/tex]

Divide both sides of the equation by [tex]sin(x)[/tex].

[tex]\frac{H*sin(x)}{sin(x)} =\frac{O}{sin(x)}[/tex]

Simplify the right side by cancelling the common factor of [tex]sin(x)[/tex].

[tex]H=\frac{O}{sin(x)}[/tex]

Now lets evaluate the length of the string.

In this example we are given

[tex]x=68\\O=45[/tex]

[tex]H=\frac{45}{sin(68)}[/tex]

[tex]H=48.5341[/tex]

The volume of the cylinder is 3,714.62 cubic yards.

We know that the volume of a cylinder of radius R and height H is given by:

V = pi*R²*H

where pi = 3.14

In this case, we also know that:

H = 7yd

And the diameter is 26 yards, the radius is half of that, then:

R = 26yd/2 = 13yd

Then the volume is:

V = 3.14*(13 yd)²*7yd = 3,714.62 yd³

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Answer:

To find the result of 2.4 divided by -0.06, we need to use the following steps:

Step 1: Change the division problem into a multiplication problem by flipping the divisor and multiplying by its reciprocal.

-0.06 ÷ 2.4 = -0.06 x 1/(2.4)

Step 2: To find the reciprocal of 2.4, we need to divide 1 by 2.4

1/(2.4) = 0.416666666666667

Step 3: Multiply the original dividend (2.4) by the reciprocal of the divisor (0.416666666666667)

2.4 x 0.416666666666667 = -0.1

So, 2.4 divided by -0.06 is equal to -0.1

It's worth noting that -0.1 is a negative number which makes sense since the divisor is negative, hence the result is the opposite of the result when dividing by a positive number.

You cannot use the Hypotenuse-Leg congruence theorem to prove the similarity of triangles JKM and LKM, as they are not right triangles.

The Hypotenuse-Leg congruence theorem states that if the hypotenuse and one leg of two right triangles have the same measure then these two triangles are said to be congruent to each other.

The triangles JKM and LKM are not right triangles, as they do not have an angle of 90º, hence the HL congruence theorem cannot be used to prove their similarity.

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The relative order of the metric prefixes Milli- < Centi- < Micro- < Kilo-

The relative order of the metric prefixes of kilo-, micro-, centi-, and milli- is milli-, centi-, micro-, and kilo-. This order is determined by the exponential values of each prefix.

Milli- is equal to 10-3, centi- is equal to 10-2, micro- is equal to 10-6 and kilo- is equal to 103. The exponential values are used to determine the relative order of the prefixes. The lowest exponential value is milli-, making it the smallest metric prefix and the highest exponential value is kilo-, making it the largest metric prefix.

When the exponential values are compared, it is clear that the order of the prefixes is milli- < centi- < micro- < kilo-. This order is used to determine the relative size of the metric prefixes when measuring the same base unit.

For example, if the base unit is meter, then millimeter is the smallest measure and kilometer is the largest measure. The exponential values of the metric prefixes determine the relative order of the base unit.

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The probability of a score lower than three is given as follows:

0.38.

A probability is obtained as the division of the number of desired outcomes by the number of total outcomes.

As the table gives the probability distribution, we must just take the probabilities of the desired events from the table.

The probability of a score lower than three is given as follows:

P(X < 3) = P(X = 1) + P(X = 2).

Taking the values from the table, the probability is of:

P(X < 3) = 0.18 + 0.20

P(X < 3) = 0.38.

The problem is given by the image presented at the end of the answer.

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To show that the improper integral g(x)dx is divergent, but the average value of g on the interval 4, infinity is finite, we can consider a function g(x) = 1/x, which is mostly used as an example for a divergent integral.

The improper integral of g(x) from 4 to infinity is given by:

[tex]\int\limits {g(x)} \, dx = \int\limits {(1/x)} \, dx[/tex]  from 4 to infinity

= lim (upper limit -> infinity) [ln|x|] from 4 to x

= [ln|x|] from 4 to infinity

= ln(infinity) - ln(4) = infinity - ln(4) = infinity

As the limit of the integral is infinity, the integral is divergent.

However, the average value of g on the interval [4, ∞) is given by:

average value = (1/∞ - 4) * ∫(1/x)dx from 4 to infinity

= (1/∞ - 4) * (infinity - ln(4))

= -4 + ln(4)

= ln(4) - 4

which is a finite value when the integral is divergent

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