Given:
The mass of the first ball is,
[tex]m_1=4\text{ kg}[/tex]The initial velocity of the first ball towards West is,
[tex]u_1=25\text{ m/s}[/tex]The mass of thr second ball is,
[tex]m_2=15\text{ kg}[/tex]the second object is initially at rest.
The final velocity of the first ball is,
[tex]v_1=-8.0\text{ m/s}[/tex]we are taking West as positive.
Applying momentum conservation principle we can write,
[tex]m_1u_1+m_2\times0=m_1v_1+m_2v_2[/tex]Substituting the values we get,
[tex]\begin{gathered} 4\times25+0=4\times(-8.0)+15\times v_2 \\ v_2=\frac{100+32}{15} \\ v_2=8.8\text{ m/s} \end{gathered}[/tex]THe final velocity of the second ball is towards East and the magnitude is 8.8 m/s.
The impulse of the Second ball is,
[tex]\begin{gathered} I=m_2v_2-m_2\times0 \\ =15\times8.8 \\ =132\text{ kg.m/s} \end{gathered}[/tex]what do fusion and fission have in common
Answer:
Explanation:
they both involve nuclear reactions that produce energy, but the application are not the same
A heart defibrillator passes 10.3 A through a patient's torso for 5.00 ms in an attempt to restore normal beating.(a) How much charge passed?(b) What voltage was applied if 492 J of energy was dissipated?KV(c) What was the path's resistance?ΚΩ(d) Find the temperature increase caused in the 8.00 kg of affected tissue. The specific heat of tissue is 3500 J/(kg. °C).°C
a) The formula for calculating the quantity of charge is expressed as
Q = IT
where
Q is the quantity of charge
I is the current
T is the time
From the information given,
I = 10.3
T = 5 ms = 5 x 10^-3 s
Q = 10.3 x 5 x 10^-3
Q = 51.5 x 10^- 5 C
The quantity of charge passed is 51.5 x 10^- 5 C
b) The formula for calculating the energy is expressed as
E = I^2RT
where
R is the resistance
E is the energy
From the information given,
E = 492 J
Thus,
492 = 10.3^2 x R x 5 x 10^-3
R = 492/(5 x 10^-3 x 10.3^2)
R = 927.514 ohms
Voltage, V = IR
Voltage = 10.3 x 927.514
Voltage = 9553.398 V
We would divide by 1000. It becomes
Voltage = 9.553 KV
c) From the calculations,
Resistance = 927.514 ohms
We would divide by 1000. It becomes
Resistance = 0.93 ΚΩ
d) Let the temperature increase be t
mass of tissue, m = 8 kg
Specific heat of tissue = 3500 J/(kg. °C).
°C
The formula for calculating the quantity of heat is
H = mcθ
where
H is the quantity of heat
From the informtaion given,
H = 492
θ = t
Thus,
492 = 8 x 3500 x t
t = 492/(8 x 3500)
t = 0.018
The temperature increase is 0.018 degrees
A 2.0 m long frictionless pendulum of mass 1.6 kg is released from point A at an angle & of
15 degrees. What is the speed of the pendulum at Point C.
The speed of pendulum at point C would be 0.47 m/sec when a 2 meter long frictionless pendulum of mass 1.6 kg is released from point A.
What is speed and how it is calculated out to be 0.47 meter/second?Speed is a quantity used to measure the distance travelled per unit time of the given time period.Here is given the length of rope be 2 meter and the mass of pendulum 1.6 kg released from point A.Using L cos theta = L ( 1 - cos theta) , we can write v^2/2g and putting all the numerical values we will get the speed be 0.47 m/s.Putting the angle that is theta be 15 degrees and getting the v the speed be 0.47 m/s.Hence the speed of the pendulum at point C would be 0.47 m/s.To know more about speed visit:
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I need help on this science homework I forgot on what to do through number 4-7 including a,b,c,d, and e.
Answer:
[tex]\begin{gathered} (a)\Rightarrow v=2ms^{-1} \\ (b)\Rightarrow v=1ms^{-1} \\ (c)\Rightarrow v=6.67ms^{-1}_{} \\ (d)\Rightarrow v=1.2ms^{-1} \\ (e)\Rightarrow v=0ms^{-1} \end{gathered}[/tex]Explanation: We need to calculate the speed on intervals a b c d and e, the speed can be calculated with the following formula:
[tex]v=\frac{\Delta S}{\Delta t}\Rightarrow(1)[/tex](a) 0-5 seconds Interval:
[tex]\begin{gathered} v=\frac{\Delta S}{\Delta t}\Rightarrow v=\frac{(10m-0m)}{(5s-0s)}=\frac{10m}{5s}=2ms^{-1} \\ v=2ms^{-1} \end{gathered}[/tex](b) 5-15 seconds Interval:
[tex]\begin{gathered} v=\frac{\Delta S}{\Delta t}\Rightarrow v=\frac{(20m-10m)}{(15s-5s)}=\frac{10m}{10s}=1ms^{-1} \\ v=1ms^{-1} \end{gathered}[/tex](c) 15-18 seconds Interval:
[tex]\begin{gathered} v=\frac{\Delta S}{\Delta t}\Rightarrow v=\frac{(40m-20m)}{(18s-15s)}=\frac{20m}{3s}=6.67ms^{-1} \\ v=6.67ms^{-1} \end{gathered}[/tex](d) 18-23 seconds Interval:
[tex]\begin{gathered} v=\frac{\Delta S}{\Delta t}\Rightarrow v=\frac{(46m-40m)}{(23s-18s)}=\frac{6m}{5s}=1.2ms^{-1} \\ v=1.2ms^{-1} \end{gathered}[/tex](e) 23-25 seconds Intervals:
[tex]\begin{gathered} v=\frac{\Delta S}{\Delta t}\Rightarrow v=\frac{(40m-40m)}{(25s-23s)}=\frac{0m}{2s}=0ms^{-1} \\ v=0ms^{-1} \end{gathered}[/tex]Moving a charge from point A, where the potential is 369.53 V, to point B, where the potential is 217.85 V, takes 0.55 milliJ of work. What is the value of the charge, in micro-Coulombs?
Given:
The potential of point A is
[tex]V_A=369.53\text{ V}[/tex]The potential of point B is
[tex]V_B=\text{ 217.85 V}[/tex]The work done is W = 0.55 milli Joule.
To find the value of charge in micro Coulomb.
Explanation:
The charge can be calculated as
[tex]\begin{gathered} Q=\frac{W}{V_B-V_A} \\ =\frac{0.55\times10^3\text{ J}}{217.85-369.53} \\ =-3.63\text{ C} \\ =\text{ -3.63 C}\times\frac{10^6\text{ }\mu C}{1\text{ C}} \\ =-3.63\times10^6\text{ }\mu C\text{ } \end{gathered}[/tex]
Imagine that you are on board a ship that was struck by a rogue wave.
Tell your story, from the calm before the wave hit to its aftermath.
The possibility of a wave toppling cruise liner is extremely low. They are made wide and have enough ballast on the lower decks to be heavy enough rogue waves. On the side, the crew's neglect also be necessary.
What are rogue waves?A wave that is double the region's major wave height is typically considered a rogue wave. The highest one-third of waves on average over a period of time make up the noteworthy wave height. Even the biggest ships and oil rigs can be rendered useless and sunk by rogue waves.
Have rogue waves ever struck a cruise ship?Rogue waves have occasionally hit cruise ships, although it is not frequently. Four cruise ships have collided with rogue waves since rogue wave records were first kept in 1995. All sustained damage, and some people reported injuries, but there have been no confirmed fatalities on cruise ships due to rogue waves.
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person pulls a toboggan for a distance of 35.0 m along the snow with a rope directed 32.0o above the snow. The tension in the rope is 105.0 N. How much work is done on the toboggan by the tension force?
The amount of work done on the toboggan by the tension force of 105 N with a rope directed 32° above the snow is 3.12 KJ
W = F d cos θ
W = Work done
F = Force
d = Distance
θ = Angle between force and displacement vector
d = 35 m
F = 105 N
θ = 32°
W = 105 * 35 * cos 35°
W = 105 * 35 * 0.85
W = 3123.75 N m
W = 3.12 KJ
Work done is energy transferred to make an object move to a distance. Its unit is Joules which is denoted as J. It is the amount of work done by a force of 1 Newton to move a distance of 1 meter.
Therefore, the amount of work done on the toboggan by the tension force is 3.12 KJ
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Tritium has a half-life of 12.3 years. How many years will have elapsed when the radioactivity of a tritium sample has decreased to 10 percent of its original value?
Given
Half life of tritium is
[tex]t_{\frac{1}{2}}=12.3\text{ years}[/tex]The sample is reduced to 10% of its original value.
To find
How many years will have elapsed when the radioactivity of a tritium sample has decreased to 10 percent of its original value?
Explanation
The activity is given by
[tex]\begin{gathered} A=A_oe^{-\lambda t} \\ \Rightarrow0.1A_o=A_oe^{-\frac{0.693}{t_{\frac{1}{2}}}t} \\ \Rightarrow ln(0.1)=-\frac{0.693}{1.23}t \\ \Rightarrow-2.302=-\frac{0.693}{1.23}t \\ \Rightarrow t=4.08 \end{gathered}[/tex]Conclusion
The time taken is 4.08 years
You place a box weighing 276 N on an inclined plane that makes a 44.5° angle with the horizontal.
Compute the component of the gravitational force acting down the inclined plane.
Answer in units of N.
Answer:
this is the answer
Explanation:
hope it helps
which are neutrally charged, are found in thenucleus of the atom.
Given:
Nucleus of the atom
Required:
Neutra
Ahmed wants to measure the weight of an object. What instrument should he use?
Answer:
a scale
Explanation:
you use it to weigh things
Answer:
its not a scale
Explanation:
given q= 10^-6 c, v= (3i + 4j )m/(s) , b=1i tesla find magnetic force
Lorentz magnetic force is the force exerted on a charged particle 'q' which moves with a velocity 'v' through a magnetic field B. The Lorentz forces exerted by moving charges on one another are not equal and opposite.
Given:
Charge, q = [tex]10^{-6}[/tex] C
Velocity, v = (3i + 4j) m/s
Magnetic field, B = 1i T.
To find: Magnetic force, F.
From Lorentz force law, the magnetic force is given by,
F = q × (v × B)
Substituting the given values,
F = [tex]10^{-6}[/tex] × ((3i + 4j) × 1i)
Since i×i = 0, and j×i = k,
F = [tex]10^{-6}[/tex] × 4k
∴ F = 4 × [tex]10^{-6}[/tex] k newtons.
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On a fishing trip Justin rides in a boat 12 km south. The fish aren't biting so they go 4 km west. They then follow a school of fish 1 km north. What is his total displacement?
ANSWER:
The displacement is 11.7 km
STEP-BY-STEP EXPLANATION:
The displacement is the vector sum from the start point to the end point. Vector addition is applying the formula of the distance between two points.. We will use this formula:
[tex]d=\sqrt[]{(x_2-x^{^{}}_1)^2+(y_2-y_1)^2^{}}[/tex]To better understand the exercise, we will draw a picture of the situation, it would look like this:
Replacing the points (-4, -11) and (0, 0)
[tex]\begin{gathered} d=\sqrt[]{(-4-0^{}^{}_{})^2+(-11_{}-0_{})^2} \\ d=\sqrt[]{16+121^{}} \\ d=\sqrt[]{137} \\ d=11.7 \end{gathered}[/tex]state the dimension of energy in physics
hint: Energy = force × distance
Force = Mass * Acceleration = kg* m/s^2= MLT^-2
Distance = metres= L
Energy = MLT^-2 * L =ML^2T^-2
A duck is paddling due East at 1.1 m/s across the river while it flows due South at 0.55 m/s What is her resultant velocity?
The diagram representing this scenario is shown below
A right angle triangle is formed. R represents the resultant velocity. To find R, we would apply the pythagorean theorem which is expressed as
hypotenuse^2 = one leg^2 + other leg^2
From the diagram,
hypotenuse = R
one leg = 1.1
other leg = 0.55
Thus,
R^2 = 1.1^2 + 0.55^2 = 1.5125
Taking square root of both sides,
R = square root of 1.5125
R = 1.23
The resultant velocity is 1.23 m/s
Consider the graph shown. Which of the motions is consistent with the graph?a) The object has a constant velocity in the negative direction.b) The object is moving in the negative direction with a changing speed.c) The object is moving in the positive direction and slowing down.
Given:
The graph of velocity vs time of an object
To find:
Which of the motions is consistent with the graph?
Explanation:
We see here that the object's initial velocity is positive, and the final velocity is zero. So, the object is slowing down. as the initial velocity is positive, the object's direction of movement is positive.
Hence, The object is moving in a positive direction and slowing down.
Atmospheric pressure is about 1.00 × 105 Pa on average.A. What is the downward force of the air on a desktop with surface area 2.59 m2?B. Convert the downward force of the air on a desktop with surface area 2.59 m2 to pounds to help others understand how large it is.
A)
The formula for calculating pressure is expressed as
pressure = force/area
From the information given,
pressure = 1.0 x 10^5 pa
Recall, 1 pa = 1 N/m^2
This means that
pressure = 1.0 x 10^5 N/m^2
surface area = 2.59 m^2
Force = pressure x area
Force = 1.0 x 10^5 x 2.59 = 259000 N
Recall,
B)
1 newton = 0.224808943 pounds
259000 newtons = 259000 x 0.224808943
= 58226 pounds
A kid is on a stationary sled, onsnowy ground with fls 0.105.It takes 71.2 N of force to setthe sled moving. How muchnormal force is acting?(Unit = N)
ANSWER
[tex]678.10N[/tex]EXPLANATION
Parameters given:
Coefficient of static friction, μs = 0.105
Force, F = 71.2 N
The minimum force required to set the sled moving must be equal to the frictional force acting on the sled.
The frictional force is given mathematically as:
[tex]F_f=\mu_sN[/tex]where N = normal force
Since the force required is equal to the frictional force, we have that:
[tex]F=F_f[/tex]Therefore:
[tex]F=\mu_sN[/tex]Solve for N:
[tex]\begin{gathered} N=\frac{F}{\mu_s} \\ N=\frac{71.2}{0.105} \\ N=678.10N \end{gathered}[/tex]That is the normal force.
3. An object of mass 8 kg is sliding down a friction lessinclined plane of length 11 m that makes an angleof 70 deg with the horizontal. Calculate thework done by gravitational force as the objectslides from the top of the inclined plane to theground. (1 point)A. 099.045 JB. O1135.872 JC.810.391 JD.499.917
Given
Mass of the object, m=8 kg
Length of the inclined plane, l=11 m
Angle of inclination,
[tex]\theta=70^o[/tex]To find
Calculate the work done by gravitational force as the object slides from the top of the inclined plane to the
ground.
Explanation
The height of the ramp
[tex]h=lsin\theta=11sin70^o[/tex]The work done by gravitational force,
[tex]\begin{gathered} W=mgh \\ \Rightarrow W=8\times9.8\times11sin70^o \\ \Rightarrow W=810.390J \end{gathered}[/tex]Conclusion
The work done is C.810.391
What is the resistance in a circuit that has a current of 2.5A and a voltage of 40v
16 ohms
Explanation
Ohm's law relates the strength of a direct current is directly proportional to the potential difference and inversely proportional to the resistance of the circuit,it is given by the expresssion
[tex]\begin{gathered} V=IR \\ if\text{ we isolate R} \\ R=\frac{V}{I} \end{gathered}[/tex]then
Step 1
a) Let
[tex]\begin{gathered} I=2.5\text{ A} \\ V=40\text{ V} \end{gathered}[/tex]b)replace in the formula
[tex]\begin{gathered} R=\frac{V}{I} \\ R=\frac{40V}{2.5A} \\ R=16\text{ ohms} \end{gathered}[/tex]therefore, the answer is 16 ohm
I hope this helps you
REWRITE THIS SENTENCE ON THE LINES PROVIDED.
The time it takes for the moon to rotate once on its axis is the same amount of time it takes for
the moon to revolve around the Earth once. The result is that the SAME SIDE OF THE MOON
ALWAYS FACES THE EARTH.
The amount of time it takes for the moon to complete one full rotation around the Earth is the same as its period of one full rotation on its axis. Due to this, the EARTH ALWAYS SEE THE SAME SIDE OF THE MOON.
What does the earth's rotation entail?With an inclination of 23.45 degrees from the plane of its orbit around the sun, the Earth revolves on its axis in relation to the sun every 24.0 hours mean solar time. The differences brought on by the Earth's are averaged out to create mean solar time.
What occurs when the Earth rotates?Rotation causes the day-night cycle, which in turn induces a cycle of temperature and humidity. As the world spins, the sea level rises and falls twice each day. The tidal range is determined by the gravitational pull of the sun and moon together
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pls brainliest
Sports biomechanics looks at athletes to better understand how the body:
A. grows.
B. creates energy.
C. moves.
D. resists disease.
Answer:
The ans is C
Explanation:
In a sporting context, biomechanics examines an athlete in relation to his or her environment and equipment. Forces acting on the body (kinetics) and movements of the body (kinematics) are analysed prior to mapping out an exercise, performance or recovery plan.
A computer connected to a motion sensor creates velocity—time graph for a ball rolling down an incline. On the graph, the velocity increases by 0.3 m/s for every tenth of a second increment on the graph. What is the acceleration of the object? A. 0.3 m/s2. B. 1 m/s2. C. 3 m/s2. D. The acceleration cannot be determined from the given information.
We are asked to determine the acceleration of an object which speed changes by 0.3 m/s every 1/10 seconds. The definition of acceleration is the following:
[tex]a=\frac{\Delta v}{\Delta t}[/tex]Where:
[tex]\begin{gathered} \Delta v=\text{ change in velocity} \\ \Delta t=\text{ change in time} \end{gathered}[/tex]Substituting the given values we get:
[tex]a=\frac{0.3\frac{m}{s}}{\frac{1}{10}s}[/tex]Solving the operations we get:
[tex]a=3\frac{m}{s^2}[/tex]Therefore, the acceleration is option C.
Based on the periodic table why are He, Ne, Ar, Kr, and Xe the same
column/group/family?
The noble gases or inert gases helium (He), neon (Ne), argon (Ar), krypton (Kr), and radon (Rn) are found in group 8A of the periodic table. The name comes from little these elements react with other substances.
What is periodic table ?The periodic table is a tabular arrangement of chemical elements arranged according to number of protons, starting with hydrogen and going up to the element the with highest atomic number. The quantity of protons found in the nucleus of an element's atom is referred as the element's atomic number.
Why is the periodic table important?All known elements were grouped together in the periodic table of elements into groups with attributes. It becomes a crucial tool for chemists, nanotechnologists, and other scientists as a result. One can forecast what chemicals will react if you learn to use and understand the periodic table.
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A 6 kg object is being pulled by a horizontal force F=120 N on a friction-less horizontal surface. It moved a distance of 18 m. If its initial kinetic energy was 100 Joules, what is the final kinetic energy in Joules?
The final kinetic energy is 120m.
What is Work-Energy Theorem?
The Work-Energy Theorem states that the work done is equal to the change in the K.E. i.e Kinetic Energy of the object.
W = Δ(K.E.)
In the given question we had,
Mass = 6 kg,
Force = 120 N,
Distance = 18 m,
Initial Kinetic Energy ( KE1 ) = 100 Joules
According to Work-Energy Theorem,
W = Δ(K.E.)
W = KE2-KE1
F x S = KE2 - 100
120 x 18 = KE2 - 100
2160 + 100 = KE2
2260J = KE2
So, the final kinetic energy is 2260J.
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An object has 25 J of kinetic energy and 35 J of potential energy. What isthe total energy possessed by the object? *
The total energy possessed by the object is 60 J
Given:
The kinetic energy of the object, K=25 J
The potential energy of the object, P=35 J
To find:
The total energy possessed by the object.
Explanation:
The kinetic energy of an object is the energy possessed by it due to its motion. The kinetic energy is directly proportional to the square of the velocity of the object.
The potential energy of an object is the energy possessed by it due to its position. The gravitational potential energy of an object is directly proportioinal to the mass ofthe
Can you help me match these with the correct word
When an object is thrown up into the air the time up is equal to the time down.
When an object is thrown up into the air and reacher the apex, the velocity of the object is zero.
If you throw an object straight up the air the velocity of the object is decreasing on its way up.
Whats the percent of 10 of 20
In order to determine the associated percent of 10 related to 20, proceed as follow:
If x is the percentage, then, you can write:
[tex]\frac{x}{100}\cdot20=10[/tex]which means that x percentage of 20 is equal to 10. By solving for x, you get:
[tex]\begin{gathered} x=\frac{10}{20}\cdot100 \\ x=50 \end{gathered}[/tex]Hence, 10 is the 50% of 20
Answer:2
Explanation:multiply 0.20 times 10 you get it
Convert 500BTU/ft.s.F to g.cal/cm^2.s.°C
The requirement of the prompt is for 500 British Thermal Units /Calories (Cal) to be converted to Gram Calories. Hence, 500 BTU (cal) = 126,082cm²
What is a British Thermal Unit?A British thermal unit is a heat unit defined as the amount of heat needed to raise the temperature of one pound of water by one degree Fahrenheit. It is also one of the customary units used in the United States.
To covert 500 BTU, one must note that according to established scientific metrics.:
1 BTU = 252.164 Gram (Cal).
Hence,
500 BTU = 252.164 x 500
= 126,082 cm²
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A NASA probe is moving horizontally above the surface of the moon at a constant speed to the right, as depicted in the diagram below. It releases an instrument package when it is directly above Point P. As seen from the lunar surface, which path would the package likely follow after the release and why?
B, because the gravity of the moon will pull the instrument to the ground with constant acceleration and the lack of an atmosphere allows the package to fall straight down
D, because the gravity of the moon will pull the instrument to the ground with constant acceleration so that its vertical velocity increases as it falls, while the horizontal component of the velocity remains constant
C, because the reduced gravity of the moon pulls the package down vertically at a constant speed while the package travels horizontally at a constant speed resulting in a straight-line trajectory to the lunar surface.
A, because the gravity of the moon pulls the package down with constant acceleration, while the atmosphere of the moon creates horizontal drag on the package which reduces the horizontal component of the package’s velocity causing the package to be pulled backward as it falls
As seen from the lunar surface, the path followed by the package after the release is D, because the gravity of the moon will pull the instrument to the ground with constant a, so that its vertical velocity increases.
A is incorrect because there is no wind pushing the package backwards. B is incorrect because the package has an initial velocity. C is incorrect because vertical velocity is not constant due to the presence of gravity. E and F are incorrect because gravity acts immediately after the package is dropped.
D is correct because the horizontal component remains constant because there is no horizontal force acting on the package. This is because in outer space there is no atmosphere, so there will be no air resistance. The vertical component increases with respect to time because of constant acceleration due to gravitational pull on the package.
Therefore, as seen from the lunar surface, the path followed by the package after the release is D, because the gravity of the moon will pull the instrument to the ground with constant acceleration so that its vertical velocity increases as it falls, while the horizontal component of the velocity remains constant
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