a 60 kg dancer applies a horizontal force of -800 n on the dance floor. the dancer's acceleration will be

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Answer 1

The acceleration of the dancer who applies a horizontal force of -800 N on the dance floor will be 13.33 m/s².

The formula used to calculate acceleration is as follows:F = m × a

where,F is the force,m is the mass, and,a is the acceleration

Substituting the given values in the above formula, we get:

-800 N = 60 kg × a

We can solve this equation for a, which will give us the acceleration of the dancer.

a = (-800 N) / (60 kg) = -13.33 m/s²

Therefore, the acceleration of the dancer will be 13.33 m/s².

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Related Questions

a tired worker pushes a heavy (100-kg) crate that is resting on a thick pile carpet. the coefficients of static and kinetic friction are 0.6 and 0.4, respectively. the worker pushes with a force of 600 n. the frictional force exerted by the surface is

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When a tired worker pushes a heavy (100-kg) crate that is resting on a thick pile carpet, the frictional force exerted by the surface on the crate is 588 N.

When a tired worker pushes a heavy (100-kg) crate that is resting on a thick pile carpet, the frictional force exerted by the surface can be calculated as follows:

The weight of the crate = m × g = 100 kg × 9.8 m/s² = 980 N

Force applied by the worker = F = 600 N

The force of friction acting on the crate is given by the following formula:

Ff = μF

Where, μ is the coefficient of friction, F is the normal force acting on the crate.

Notes: The normal force is equal and opposite to the weight of the crate. i.e., N = 980 N1. The frictional force exerted by the surface on the crate is the static frictional force initially. Hence, we use the coefficient of static friction for our calculation.

2. If the force applied by the worker is not enough to overcome the static frictional force, then the crate will not move and the frictional force will remain static friction.

3. Once the crate starts moving, the static friction will convert to kinetic friction. Hence, we will use the coefficient of kinetic friction if the force applied by the worker is greater than the force of static friction. Initially, the force applied by the worker is less than the force of static friction, hence the frictional force exerted on the crate will be the static frictional force.

Frictional force = Ff = μN

The normal force acting on the crate = Weight of the crate = 980 N

Frictional force =

Ff = μN

= 0.6 × 980 N

= 588 N

Therefore, the frictional force exerted by the surface on the crate is 588 N.

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the intensity of the sound of a television commercial is 10 times greater than the intensity of the television program it follows. by how many decibels does the loudness increase?

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The television commercial loudness increases by 10 decibels.

Increase in the Intensity of sound

The decibel (dB) scale is a logarithmic measure of sound intensity. The intensity of a sound is measured in watts per square meter and the decibel scale is a way to express the relative loudness of a sound, compared to a reference level.

A 10 dB increase in intensity is a 10-fold increase in sound power. This means that a sound with an intensity of 10 watts per square meter is 10 times louder than a sound with an intensity of 1 watt per square meter.

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a ball of mass is dropped. what is the formula for the impulse exerted on the ball from the instant it is dropped to an arbitrary time later?

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The formula for the impulse exerted on the ball from the instant it is dropped to an arbitrary time later is:

Impulse = (Final momentum - Initial momentum)

What is impulse?

Impulse is a vector quantity having both magnitude and direction, whereas momentum is a vector quantity, but the impulse is not equal to momentum. The impulse is the change in momentum.

If a ball of mass m is dropped from rest, then its initial momentum is zero.

The final momentum of the ball after falling for time t is:

Final momentum = mv

Where v is the velocity of the ball after falling for time t.

Therefore, the impulse exerted on the ball from the instant it is dropped to an arbitrary time later is:

Impulse = (mv - 0) = mv

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calculate the average force on the person if he is stopped by a padded dashboard that compresses an average of 1.00 cm. calculate the average force on the person if he is stopped by an air bag that compresses an average of 15.0 cm.

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The average force on the person if they are stopped by an airbag that compresses an average of 15.0 cm is approximately 70,000 N.

To calculate the average force on a person,

Average force = (change in momentum) / (time interval)

Assuming that the person's initial velocity is constant, we can simplify the formula to,

Average force = (mass of the person) x (change in velocity) / (time interval)

Now, let's consider the two scenarios,

Stopped by a padded dashboard that compresses an average of 1.00 cm:

Assuming the person's initial velocity is known and constant, we need to know the time interval it takes for the person to stop after hitting the dashboard. Without this information, we cannot calculate the average force.

Stopped by an airbag that compresses an average of 15.0 cm:

The time interval for an airbag to deploy and cushion the person's impact is typically very short (about 0.03 seconds), so we can assume that the time interval is negligible in this case. Therefore, we can use the simplified formula above.

Let's assume the mass of the person is 70 kg and their initial velocity is 30 m/s. The change in velocity is the final velocity (0 m/s) minus the initial velocity (30 m/s), which is -30 m/s. The negative sign indicates that the person's velocity is decreasing.

Using the formula,

Average force = (mass of the person) x (change in velocity) / (time interval)

= (70 kg) x (-30 m/s) / (0.03 s)

= -70,000 N

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A skydiver of mass 95kg ,before opening his parachute, falls at t1 with V1= 11m/s and at t2 with t2 v2=27m/s; supposing friction is zero, find the distance covered between t1 and t2

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The skydiver covered a distance of approximately 94.9 meters before opening his parachute between t1 and t2, assuming no air resistance or friction.

v = final velocity = v2 = 27 m/s

u = initial velocity = v1 = 11 m/s

a = acceleration = g = 9.8 m/[tex]s^2[/tex]

s = (v² - u²) / 2a

s = (27² - 11²) / (2 x 9.8) = 94.9 meters

Resistance measures an item's potential to impede the drift of electrical present-day through it. it's far measured in ohms (Ω). Resistance is decided by way of the bodily residences of an item, along with its dimensions, material, and temperature. while electric-powered present-day flows thru a conductor, it encounters resistance that slows down its float. This resistance is as a result of the collisions among electrons and the atoms inside the conductor.

Resistance can be laid low with changes inside the bodily properties of the conductor, such as duration, cross-sectional region, or temperature. an extended or narrower conductor may have higher resistance, even as a much broader conductor could have decreased resistance. understanding resistance is critical for designing and working electrical circuits. with the aid of controlling the resistance of a circuit, engineers can make sure that the appropriate amount of current flows to electricity the devices linked to it.

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if you hold a 1.85 kg k g package by a light vertical string, what will be the tension in this string when the elevator accelerates as in the previous part?

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The tension in the string of a 1.85 kg package held by a light vertical string will depend on the acceleration of the elevator. When the elevator accelerates, the force of acceleration on the package will be equal and opposite to the tension in the string, causing the tension to increase.

The equation for tension in a string is:

Tension = Mass x Acceleration

Therefore, in this case, the tension in the string is equal to 1.85 kg x Acceleration.

If we assume that the acceleration of the elevator is a constant rate, then the tension in the string can be calculated by multiplying the mass of the package by the acceleration of the elevator.

To sum up, the tension in the string of a 1.85 kg package held by a light vertical string will depend on the acceleration of the elevator. If the acceleration of the elevator is a constant rate, then the tension in the string can be calculated by multiplying the mass of the package by the acceleration of the elevator.

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a brick is falling from the roof of a three-story building. how many force vectors would be shown on a free-body diagram? name them

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A brick is falling from the roof of three story building then free-body diagram would show only one force vector, which is the force of gravity acting on the brick.

A free-body diagram is used to graphically represent the forces acting on an object. It shows all of the forces acting on an object and can be used to analyze the motion of an object.

A free-body diagram for a falling brick would include two force vectors: Gravity or Weight.

If we consider only the brick and neglect air resistance, then there are two force vectors that would be shown on a free-body diagram of the brick:Force of gravity: The force of gravity, which pulls the brick downwards with a magnitude of its weight. This force is always present and directed downwards towards the center of the Earth. Normal Force: The normal force, which is the force exerted by the roof or any surface in contact with the brick that prevents it from falling through the surface. As the brick is falling, there is no contact force from the roof, so the normal force is zero.

So, in this scenario, the free-body diagram would show only one force vector, which is the force of gravity acting on the brick.

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What would you expect the force to be if the distance was 30 meters? How did you come up with your answer?

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The force would be 6 Newtons for a distance of 30 metres.

What connection exists between distance and force?

A force is defined as any influence that results in a change in an object. Distance is the amount of distance that an object moves over time. A force is applied to an item, and the more force is applied, the farther the thing will move.

What is distance-based force?

Action-at-a-distance forces are those that develop even when the two interacting objects are not in close proximity to one another but are nevertheless able to push or pull against one another despite this physical gap.

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a series circuit is a current divider and a parallel circuit is a voltage divider circuit. select one: a. true b. false

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The given statement " A series circuit is a current divider and a parallel circuit is a voltage divider circuit " is True

In a series circuit, the electric current is the same through each component, and the total current is equal to the sum of the currents through each component. Therefore, the current is divided among the components.

In a parallel circuit, the potential voltage across each component is the same, and the total voltage is equal to the sum of the voltages across each component. Therefore, the voltage is divided among the components.

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the generation of multiple forecasts of future conditions followed by an analysis of how to respond effectively to each of those conditions is

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The process described in the question is known as scenario planning. It is a strategic planning method that involves generating multiple plausible scenarios of future conditions and analyzing the potential impact of each scenario on an organization or a system.

Scenario planning is a useful tool for decision-making, risk management, and identifying opportunities in an uncertain or rapidly changing environment.

By developing a range of scenarios, decision-makers can anticipate potential challenges and opportunities and develop strategies to respond effectively to each situation.

This approach allows organizations to be better prepared and more resilient in the face of future uncertainties. Scenario planning can be applied to various fields, including business, economics, environmental planning, and public policy.

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We were just introduced to electricity in physics and I have some questions:


1. Since electrons can be transferred from our hair to the balloon, can electrons also be transferred from the balloon to our hair? (Do questions always say whether an object is positive or negative charge)

2. Do electrons stay in place since balloons are rubber insulators?

3. What point do neutrons serve? Are they just there?

4. Are objects in constant exchange of energy with one another? Whenever they come in contact they exchange electrons until equal?

Answers

1 - Since electrοns can be transferred frοm οur hair tο the ballοοn , electrοns cannοt be transferred frοm ballοοn tο οur hair because. This is an illustratiοn οf  charging by cοnductiοn.

2 - Since the rubber οn the ballοοn is significantly less cοnductive than the hair, electrοns will nοt easily escape the ballοοn because οf this.

3 - Neutrοns are electrically neutral , neutrοns dοesn't participate in this prοcess.

What is charging by cοnductiοn?  

A charged οbject must cοme intο cοntact with a neutral οbject tο cοnduct electricity. As a result, when twο charged cοnductοrs cοme intο cοntact, the charge is split between the twο cοnductοrs, charging the uncharged cοnductοr.

When twο neutral οbjects are rubbed against οne anοther, electrοns are transferred. The οbject that has a strοnger affinity fοr electrοns will take electrοns frοm the οther οbject, and the twο becοme charged in οppοsitiοn. In this instance, the electrοns frοm the hair are taken up by the ballοοn , which nοw has an excess οf electrοns and a negative charge cοmpared tο the hair's current electrοn shοrtage and pοsitive charge.

2- Since the rubber οn the ballοοn is significantly less cοnductive than the hair, electrοns will nοt easily escape the ballοοn because οf this.

3- Neutrοns are electrically neutral , neutrοns dοesn't participate in this prοcess.

4-Insulating materials may becοme electrically charged when they cοme intο cοntact with οne anοther. Negatively charged electrοns can "rub οff" οne material and "rub οn" tο anοther. After bοth things have the same quantity οf οppοsite charges, the substance that gets electrοns becοmes negatively charged, and the material that lοses electrοns becοmes pοsitively charged.

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use the impulse-momentum theorem to find how long a falling object takes to increase its speed from 4.23 m/s to 10.47 m/s?

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The time it takes the object to fall through the change in speed using the impulse-momentum theorem is 0.62 seconds.

What is impilse-momentum theorem?

The impulse-momentum theorem states that the change in momentum of an object is equal to the impulse exerted on it.

To calculate the time it takes the object to increase it speed using the  impulse-momentum theorem, we use the formula below.

Formula:

Ft = m(v-u)Ft/m = (v-u)

Recall that F/m = acceleration. Therefore,

at = v-ua = (v-u)/t.......................... Equation 1

Where:

a = Acceleration due to gravityv = Final velocityu = Initial velocityt = Time

From the question,

Given:

v = 10.47 m/su = 4.23 m/sg = 9.8 m/s²

Substitute these values into equation 1 and solve for t

9.8 = (10.27-4.23)/tt = (10.27-4.23)/9.8t = 6.04/9.8t = 0.62 seconds

Hence, the time it takes the object to fall is 0.62 seconds.

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a mass-spring oscillating system undergoes shm with a period t. what is the period of the system if the amplitude is doubled?

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The period of a mass-spring oscillating system undergoing SHM with a period t, when the amplitude is doubled, is still t.

The period of a mass-spring oscillating system undergoing simple harmonic motion (SHM) is determined by the spring constant and mass of the system.

When the amplitude of the system is doubled, the period of the system remains the same, regardless of the amplitude. This means that the period of a mass-spring oscillating system undergoing SHM with a period t, when the amplitude is doubled, is still t.
To understand why the period remains the same, consider the equation for simple harmonic motion:

x(t) = A cos (2πft).

This equation describes the displacement of an object over time and is based on the principle that any system undergoing SHM oscillates about a fixed point at a constant frequency.

The frequency of the system is inversely proportional to the period, and is determined by the spring constant and mass of the system.

Increasing the amplitude of the system does not affect the frequency or period of the oscillations.

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find the net force on a 30.0 nc charge located at the origin by two other charges. one is -50.0 nc located at (-5.0 m, 2.0 m) and 40.0 nc located at (3.0 m, 1.0 m).

Answers

The net force on a 30.0 nc charge located at the origin by two other charges is the vector sum of the forces exerted by the two other charges. The force exerted by the first charge, -50.0 nC located at (-5.0 m, 2.0 m), is given by:

F1 = (k*q1*q2)/r2, where

k = 8.99 x 109 N m2/C2q1 = -50.0 ncq2 = 30.0 ncr = square root of (5.02 + 2.02) = 5.385

Therefore,

F1 = (8.99 x 109 N m2/C2)*(-50.0 nc)*(30.0 nc)/(5.3852) = 2.38 x 10-2 N

Similarly, the force exerted by the second charge, 40.0 nc located at (3.0 m, 1.0 m), is given by:

F2 = (k*q1*q2)/r2, where

k = 8.99 x 109 N m2/C2q1 = 40.0 ncq2 = 30.0 ncr = square root of (3.02 + 1.02) = 3.162

Therefore,

F2 = (8.99 x 109 N m2/C2)*(40.0 nc)*(30.0 nc)/(3.1622) = 4.58 x 10-2 N

The net force is the vector sum of F1 and F2 and can be calculated as follows:

F net = F1 + F2 = 2.38 x 10-2 N + 4.58 x 10-2 N = 7.00 x 10-2 N

Therefore, the net force on a 30.0 nc charge located at the origin by two other charges is 7.00 x 10-2 N.

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You're designing an external defibrillator that discharges a capacitor through the patient's body, providing a pulse that stops ventricular fibrillation. Specifications call for a capacitor storing 250 J of energy; when discharged through a body with R = 48 Ω transthoracic resistance, the capacitor voltage is to drop to half its initial value in 10 ms.
A) Determine the capacitance (to the nearest ) 10 μF).
B) Determine initial capacitor voltage (to the nearest 100 V) that meet these specs.
I need both correct answers to 2 significant figures.

Answers

a..... 1.04 x 10⁻⁴ Vi

b.... 9500 V

A) Determine the capacitance (to the nearest 10 μF).

First, we should identify the formula that we will use to solve the problem.

The formula that relates to capacitance is:

C = 2E / V². Where C is the capacitance in farads, E is the energy stored in joules, and V is the voltage across the capacitor in volts.

Converting the energy to joules, we have: E = 250J.

Now we know that the voltage needs to drop to half of its initial value in 10 ms. We can use the following formula to calculate the capacitance: C = R x t / ln(Vi / Vf) where R is the resistance in ohms, t is the time in seconds, Vi is the initial voltage, and Vf is the final voltage, which is half of the initial voltage.

B) Plugging in the given values, we get:

C = 48 x 0.01 / ln(Vi / (Vi / 2))Simplifying and solving for capacitance, we get:

C = 1.04 x 10⁻⁴ ViNow we can use the energy formula to solve for Vi:Vi = √(2E / C)

Plugging in the given values, we get:Vi = √(2 x 250 / 1.04 x 10⁻⁴)Simplifying and solving for Vi, we get:Vi = 9469 V

Therefore, the capacitance that meets these specifications is 100 μF and the initial capacitor voltage that meets these specifications is 9500 V, to the nearest 100 V.

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two stationary point charges q1 and q2 are shown in the figure along with a sketch of some field linesrepresenting the electric field produced by them. what can you deduce from the sketch?

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From the sketch, we can deduce that the two charges q1 and q2 are of opposite signs, as field lines start at the positive charge q1 and end at the negative charge q2. The field lines also indicate that the magnitude of the electric field produced by q1 is larger than that of q2.

Additionally, the field lines show that the electric field lines near the charges are denser, indicating a stronger electric field intensity near the charges. The direction of the electric field points from q1 to q2, which is consistent with the direction of the force that a positive test charge would experience if placed in the field. The field lines also show that the electric field is radial, i.e., the field lines point directly away from or towards each charge in a straight line, which is a characteristic of the electric field produced by a point charge. Finally, the density of the field lines decreases with distance from the charges, indicating that the electric field strength decreases with distance from the charges, following an inverse-square law.

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how to find the minimum thickness of a film such that reflected light undergo constructive interference

Answers

The minimum thickness of the film for constructive interference of reflected light would be t = 3*600/(2*1.4) = 850 nm.

The minimum thickness of a film required for constructive interference of reflected light can be calculated using the formula t = m*λ/(2*n),

where t is the minimum thickness of the film, m is the order of interference, λ is the wavelength of the light, and n is the index of refraction of the film.

For example, if the order of interference is 3, the wavelength of the light is 600 nm, and the index of refraction is 1.4,

the minimum thickness of the film for constructive interference of reflected light would be t = 3*600/(2*1.4) = 850 nm.

Constructive interference of reflected light occurs when the phase difference between the two waves is equal to an integral multiple of 2π.

This can be determined using the formula Δφ = (2π*m)/(λ*n), where Δφ is the phase difference, m is the order of interference, λ is the wavelength of the light, and n is the index of refraction of the film.

To achieve constructive interference, the minimum thickness of the film can be determined by ensuring that the phase difference is equal to an integral multiple of 2π.

The minimum thickness of a film required for constructive interference of reflected light can be calculated using the formula t = m*λ/(2*n),

where t is the minimum thickness of the film, m is the order of interference, λ is the wavelength of the light, and n is the index of refraction of the film.

Constructive interference can be achieved by ensuring that the phase difference between the two waves is equal to an integral multiple of 2π.

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A dog can hear sounds in the range from 15
to 50,000 Hz.
What wavelength corresponds to the lower
cut-off point of the sounds at 20◦C where the
sound speed is 344 m/s?
Answer in units of m.

Answers

Explanation:

Speed of sound is 344

The frequency corresponding to the lower cut-off point is the lowest frequency which his 15Hz

F=15Hz

The relationship between the wavelength, speed and frequency is given as

v=fλ

Then,

λ=v/f

λ=v/f

λ=344/15

λ=22.93m

a spherical capacitor has vacuum between its conducting shells and a capacitance of 125 pf . the outer shell has inner radius 9.00 cm . what is the outer radius of the inner shell? express your answer with the appropriate units.

Answers

For a spherical capacitor with a capacitance of 125 and a vacuum between its conducting shells, the outer radius of the inner shell is around 5.60 cm.

The capacitance of a spherical capacitor is given by:

C = 4πε₀[(r₁r₂)/(r₂-r₁)]

where C is the capacitance, ε₀ is the electric constant (8.85 x [tex]10^{-12}[/tex] F/m), r₁ is the radius of the inner shell, and r₂ is the radius of the outer shell.

In this case, we know that the capacitance C = 125 pF (picoFarads), r₂ = 9.00 cm, and we want to find r₁.

We can rearrange the equation to solve for r₁:

r₁ = (C × r₂)/(4πε₀ + C)

Substituting the values:

r₁ = (125 x [tex]10^{-12}[/tex] F × 0.09 m) / (4π × 8.85 x [tex]10^{-12}[/tex] F/m + 125 x [tex]10^{-12}[/tex] F)

r₁ ≈ 5.60 cm

Therefore, the outer radius of the inner shell is approximately 5.60 cm.

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if a current of 5.5 a is used, what is the force generated per unit field strength on the 20.0 cm wide section of the loop? use units of newtons per tesla.

Answers

The force generated per unit field strength on a 20.0 cm wide section of the loop with a current of 5.5 A is: 0.001 newtons per tesla

The force generated per unit field strength on a 20.0 cm wide section of the loop with a current of 5.5 A is given by the formula F = (μI) / 2πr,

where μ is the permeability of free space, (4π x 10-7 N/A²)

I is current, and r is the radius of the loop.

In this case, the force is (4π x 10-7 x 5.5) / (2π x 0.1) = 0.001 N/T.

In other words, the force generated per unit field strength on a 20.0 cm wide section of the loop with a current of 5.5 A is 0.001 newtons per tesla.

The formula for the force generated per unit field strength on a loop is derived from the fact that the force is a result of the magnetic field generated by the current flowing in the loop.

The magnitude of the magnetic field generated is proportional to the current and inversely proportional to the radius of the loop. Since the force is a product of the current and the magnetic field, it is proportional to the square of the current and inversely proportional to the square of the radius of the loop.

In summary, the force generated per unit field strength on a 20.0 cm wide section of the loop with a current of 5.5 A is 0.001 newtons per tesla, given by the formula F = (μI) / 2πr, where μ is the permeability of free space (4π x 10-7 N/A²), I is current, and r is the radius of the loop.

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Two aircraft are flying toward each other at the same speed. They each emit a 800 HZ whine. what speed (km/hr) must each aircraft have an order that pitch they both hear is 2 times the emitted frequency. Hint: the speed of sound is 343m/s

Answers

Each aircraft must be moving at a speed of 85.75 km/hr towards each other to hear a pitch that is 2 times the emitted frequency.

What is frequency ?

Frequency is a physical quantity that describes the number of occurrences of a repeating event per unit of time. It is often measured in Hertz (Hz), which represents the number of cycles or vibrations per second.

In the context of waves, such as sound waves or electromagnetic waves, frequency refers to the number of complete cycles of the wave that occur in one second. A high frequency wave has more cycles per second than a low frequency wave.

Frequency is also an important concept in physics, particularly in the study of oscillations and waves. It is used to describe the behavior of systems that oscillate or vibrate, such as a simple pendulum or a guitar string. In these cases, the frequency of the oscillation is related to the natural frequency of the system, which is determined by its mass, stiffness, and other properties.

When two aircraft are moving towards each other, the sound waves from each aircraft are compressed, leading to a higher pitch than the emitted frequency. The pitch heard by the pilots of the aircraft can be calculated using the following formula:

Pitch heard = Emitted frequency * (Speed of sound + Speed of observer) / (Speed of sound - Speed of source)

Since the two aircraft are flying towards each other at the same speed, we can assume that the speed of one aircraft is x km/hr, and the speed of the other aircraft is also x km/hr. Therefore, the relative speed between the two aircraft is 2x km/hr.

Substituting the values given in the formula, we get:

2 * Emitted frequency = Emitted frequency * (343 + 2x) / (343 - x)

Simplifying this equation, we get:

686 - 2x = 343 + 2x

4x = 343

x = 85.75 km/hr

Therefore, each aircraft must be moving at a speed of 85.75 km/hr towards each other to hear a pitch that is 2 times the emitted frequency.

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the intensity of sound in a typical classroom is approxiamtely 10^-7 w/m2. what is the sound level for this noise/

Answers

The sound level for this noise is approximately 50 decibels.

Sound level is a logarithmic measure of the ratio between the sound pressure level of a particular sound wave and a reference level. The reference level is typically set at the threshold of human hearing, which corresponds to an intensity of 10^-12 W/m^2. The sound level (measured in decibels, dB) of a sound wave is given by,

L = 10 log10(I/I0)

where I is the intensity of the sound wave and I0 is the reference intensity, which is typically set at 10^-12 W/m^2.

So, for an intensity of 10^-7 W/m^2 in a typical classroom, we can calculate the sound level as,

L = 10 log10(I/I0) = 10 log10(10^-7/10^-12) = 10 log10(10^5) = 50 dB

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A resistor and a capacitor are connected in series across an ideal battery. At the moment contact is made with the battery the voltage across the capacitor is
a. equal to the battery's terminal voltage. b. less than the battery's terminal voltage, but greater than zero. c. zero.

Answers

When a resistor and a capacitor are connected in series across an ideal battery, the voltage across the capacitor is zero at the moment contact is made with the battery.

The correct option is c.

An ideal battery is a voltage source that delivers a constant voltage regardless of the load resistance or current drawn from it.

An ideal battery can maintain a steady voltage regardless of the amount of current being drawn from it.

In real-life batteries, there is always some internal resistance, which causes the voltage to drop as the current increases.

A resistor is an electrical component that opposes or limits the flow of electrical current. It has two terminals and can be made of various materials like carbon, metal, and ceramic. It is used in various applications, including voltage dividers, current limiting, and biasing.

A capacitor is an electronic component that stores energy in an electric field between two charged conductors. It has two terminals and is made of two conducting plates separated by an insulating material called a dielectric.

Capacitors are used in various applications, including energy storage, timing circuits, and power conditioning.

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Explain how a book can have energy even if it’s not moving.

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Even though a book appears to be stationary and not moving, it nevertheless contains energy in the form of potential energy, thermal energy, electromagnetic energy, and gravitational potential energy.

Energy is a system's ability to accomplish work or produce change. Even though a book appears to be motionless and not moving, it nonetheless contains energy in numerous ways.

The book has potential energy inside its molecular connections. Because of the arrangement of atoms inside their molecules, the paper and ink used in the book possess potential energy.

This energy may be released by chemical processes like combustion, which turn potential energy into other types of energy like heat and light.

The book also possesses thermal energy, which is the energy of its constituent molecules as a result of their motion and temperature.

The energy of the molecules within the book determines the temperature of the book, and this energy may be transmitted to other things or turned into other kinds of energy via numerous processes.

The book might potentially contain electromagnetic energy, which is the energy released by its constituent atoms and molecules as a result of electromagnetic interactions.

Depending on the state of the book and the energy of its constituent particles, this energy can emerge in a variety of ways, such as visible light or radio waves.

Lastly, due to its position inside a gravitational field, the book may have gravitational potential energy. As the book falls or is moved, this energy can be turned into other types of energy, such as kinetic energy.

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an electron is each placed at rest in an electric field of 490 n/c. calculate the speed, mega m/s, 53.0 ns after being released.

Answers

The final speed of the electron placed at rest in an electric field of 490 N/C, after being released is -4.558 mega m/s.


Electric field = E = 490 N/C

The force acting on an electron in the electric field is:

F = qE, where q is the charge of the electron and E is the electric field strength.

q = -1.6 x 10⁻¹⁹ C (the negative sign indicates that the charge is negative).

F = qE = (-1.6 x 10⁻¹⁹ C) (490 N/C) = -7.84 x 10⁻¹⁷N.

The acceleration of the electron due to the electric field:

a = F/m = (-7.84 x 10⁻¹⁷N)/(9.11 x 10⁻³¹kg) = -8.6 x 10¹³ m/s².

According to the third law of motion, for every action, there is an equal and opposite reaction. This reaction force is the force of the electron on the source of the electric field, which is positive. Since the force is negative, the electron is accelerating in the opposite direction to the electric field direction.

The velocity can be found from the equation of motion, v = u + at

v = 0 + (-8.6 x 10¹³)(53.0 x 10⁻⁹) = 4.55 x 10⁶ m/s = 4.55 mega m/s.

The final speed of the electron is therefore -4.558 mega m/s.

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a square loop 5 cm on each side carries a 500 ma current. the loop is within a uniform magnetic field of 1.2t. the axis of the loop, perpendicular to the plane of the loop, makes an angle of 30 degrees with the b field. what is the magnitude of the torque on the current loop?

Answers

The magnitude of the torque on the current loop is calculated using the formula τ=BIA sinθ, where B is the magnitude of the magnetic field, I is the current, A is the area of the loop, and θ is the angle between the magnetic field and the loop's plane. In this case, the magnitude of the torque is τ = (1.2 T)(0.5 A)(5 cm x 5 cm)sin(30°) = 7.5 x 10-3 Nm.

The torque is the rotational force that causes the loop to rotate. This is due to the fact that a force is exerted on the loop by the magnetic field when there is a current running through it. This force generates a torque on the loop, which will cause it to rotate until the angle between the plane of the loop and the magnetic field is 0°.

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a 100 cm diameter propeller blade, similar to the blade in example 4.15, is attached to a motor spinning at a constant rate. what is true about the radial (centripetal) acceleration and the tangential acceleration at the end of the blade?

Answers

The true statements about the radial (centripetal) acceleration and the tangential acceleration at the end of the blade are: the radial acceleration is non-zero the tangential acceleration is zero

The radial acceleration is non-zero and the tangential acceleration is zero. This is because, the radial acceleration is determined by the formula, ar = (v²)/r

where ar is the radial acceleration, v is the velocity and r is the radius. Thus, since the propeller blade is spinning at a constant rate, the velocity v is constant.

Therefore, the radial acceleration is constant and non-zero.

The tangential acceleration, on the other hand, is given by at = rα

where at is the tangential acceleration and α is the angular acceleration. Since the blade is spinning at a constant rate, the angular acceleration is zero. Therefore, the tangential acceleration is zero.

So, the correct option is the radial acceleration is non-zero and the tangential acceleration is zero.

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an n-type piece of silicon experiences an electric field equal to 0.1v/m. (a) calculate the velocity of electrons and holes in this material

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In an n-type piece of silicon, the electric field causes the electrons to accelerate due to the attractive force between the negatively charged electrons and the positively charged electric field. This acceleration causes the electrons to reach a velocity of V = E/μ, where E is the electric field (0.1V/m) and μ is the mobility of electrons in silicon (1350 cm2/V⋅s). Therefore, the velocity of electrons in this material would be equal to 0.1V/m/1350cm2/V⋅s = 0.0741 cm/s.

The holes, on the other hand, experience a repulsive force due to the positive electric field. This causes the holes to decelerate, with a velocity of V = -E/μ. Therefore, the velocity of holes in this material would be equal to -0.1V/m/1350cm2/V⋅s = -0.0741 cm/s.

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how fast is it moving when it reaches the top of its trajectory if the projectile is fired at a speed of 138 and an upward angle of 65 degrees?

Answers

The projectile will be moving at a speed of 57.21 m/s when it reaches the top of its trajectory.

When a projectile is fired at a speed of 138 and an upward angle of 65 degrees, the speed at the top of the trajectory can be calculated. To solve this problem, you need to understand some basic physics concepts. Here's how you can solve this problem:
1. First, identify the given values and write them down:
Initial velocity (u) = 138 m/s
Angle of projection (θ) = 65 degrees
Acceleration due to gravity (g) = 9.81 m/s²
2. Now, break down the initial velocity into its horizontal and vertical components:
Initial velocity in the horizontal direction = u cos θ
Initial velocity in the vertical direction = u sin θ
3. Use the equation of motion to calculate the time taken by the projectile to reach the top of its trajectory:
u sin θ = gt/2
t = 2u sin θ/g
4. Use the time obtained in step 3 to calculate the velocity at the top of the trajectory:
v = u cos θ
Where,
v = final velocity
u = initial velocity
θ = angle of projection
5. Substitute the given values in the equation to get the final answer:
v = u cos θ
v = 138 cos 65
v = 57.21 m/s
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(a) when a 9.00-v battery is connected to the plates of a capacitor, it stores a charge of 27.0 mc. what is the value of the capacitance? (b) if the same capacitor is connected to a 12.0-v battery, what charge is stored?

Answers

(a) The value of the capacitance when connected to a 9.00 V battery is 3.00 μF.(b) The charge stored in the capacitor when connected to a 12.0 V battery is 36.0 μC.

The formula for calculating capacitance is as follows:

C = Q/V

Where,

C = capacitance (Farads)

Q = charge (Coulombs)

V = voltage (Volts)

As given,

Q = 27.0 μC

V = 9.00 V

Substituting the given values in the above equation

C = 27.0 μC/9.00 V = 3.00 μF

Therefore, the value of capacitance is 3.00 μF.

The formula for calculating charge stored is as follows:

Q = CV

Where,

Q = charge (Coulombs)

C = capacitance (Farads)

V = voltage (Volts)

As given,

C = 3.00 μF

V = 12.0 V

Substituting the given values in the above equation,

Q = (3.00 × 10⁻⁶ F) × 12.0 V = 36.0 μC

Therefore, the charge stored is 36.0 μC.

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