Answer:
48 minutes
Explanation:
60 divided by 25 equals 2.4 then you times 2.4 by 20
3. 135 g of ice is placed in a beaker of water. The water temperature in the beaker is 67 °C. After all the icemelts, the final water temperature in the beaker is 19.7 °C. 4 ptsHeat of fusion for water = 334 J/g. Specific heat of water = 4.184 J/g °C. T2-T1 = 47.3 °C.Note there are a couple different ways to solve this problems to sove this por(a) Determine the initial volume of water in the beaker (before the ice was added).(b) Determine the final volume of water in the beaker (after all the ice has melted).
Answer:
Explanation:
Answer to the 1st one. I have my doubts for the second one so didn't post :)
How do I write the Empirical Formula for: A compound composed of: 9.93% carbon, 58.6% chlorine, and 31.4% fluorine
The empirical formula for a compound composed of 9.93% carbon, 58.6% chlorine, and 31.4% fluorine is CCl₂F₂.
To write the empirical formula, let us assume that total mass of the compound is 100 g, then-
Mass of carbon = 9.93 g
Mass of chlorine = 58.6 g
Mass of fluorine = 31.4 g
We know that,
Molar mass of Carbon = 12.0 g/mol
Molar mass of Chlorine = 35.5 g/mol
Molar mass of Fluorine = 18.9 g/mol
Now, we will calculate the number of moles of each using the formula -
Number of moles = Given mass
Molar mass
Moles of Carbon = 9.93 g = 0.82 mol
12.01 g/mol
Moles of Chlorine = 58.6 g = 1.65 mol
35.5 g/mol
Moles of fluorine = 31.4 g = 1.66 mol
18.9 g/mol
Now, divide each value with the smallest amount of mole we got,
carbon = 0.82 = 1
0.82
chlorine = 1.65 = 2
0.82
fluorine = 1.66 = 2
0.82
Therefore, the empirical formula of the compound can be written as - CCl₂F₂
To learn more about empirical formula,
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number of litres of gas in 4.51 mol Xe
First, we assume STP conditions and Ideal gas conditions.
In STP conditions, we say that:
1 mol of any gas = 22.4 L (liters)
Procedure:
1 mol Xe ------ 22.4 L (STP)
4.51 moles Xe ------- X
X = 101 L
Answer: 101 L