A car is on a Ferris wheel with a radius of 20 ft. To the nearest foot, how far does the car travel over an angle of
π
3
radians?

Answers

Answer 1

The car on a Ferris wheel with a radius of 20 feet. travels a distance of 125.6 feet.

In order to determine the distance that the car has travelled, we will use the formula for calculating the circumference of a circle.

How to calculate Circumference of a circle

C = 2πr

where

r = radius

Therefore,

r is the radius of the fairy wheel

r = 20 ft

C = 2 × 3.14 × 20

C = 40 × 3.14

C = 125.6 ft

This shows that the car on a Ferris wheel with a radius of 20 feet. travels a distance of 125.6 feet

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Related Questions

Ben is going on a 380-mile trip. If he drives for 2 hours at an average speed of 50 miles per hour, how many miles will he still have left to go on on his trip?

Answers

Answer:

19000

Step-by-step explanation:

1 hour = 50 miles

2 hour = 100 miles

50×380 = 19000

write the fractions in least to greatest
1/5 3/4 1/3 2/4 6/24

Answers

Answer: 1/5 6/24 1/3 2/4 3/4

Step-by-step explanation: bigger the denominator smaller the value.

write a function that transforms f(x)=2^3+4 in the following way: stretch vertically by a factor of 6 and shift 5 units left.

Answers

Answer:

f(x) = 2x3 + 4

Stretch vertically be a factor of 2:

f(x) = 2*2x3 + 4 = 4x3 + 4

Shift 5 units to the left:

f(x) = 4(x+5)3 + 4

Figure ABCD is a parallelogram.

Parallelogram A B C D is shown. A diagonal is drawn from point A to point C.

Which sequence could be used to prove that AD = BC?

First prove TriangleABC is congruent to TriangleCDA, and then state AD and BC are corresponding sides of the triangles.
First prove TriangleABC is similar to TriangleCDA, and then state AD and BC are opposite sides of the parallelograms.
First prove ParallelogramABCD is congruent to ParallelogramCDAB, and then state AD and BC are corresponding sides of two parallelograms.
First prove ParallelogramABCD is similar to ParallelogramCDAB, and then state AD and BC are opposite sides of the parallelograms.

Answers

Answer:

A

First prove Triangle ABC is congruent to Triangle CDA, and then state AD and BC are corresponding sides of the triangles.

Hope this helps!

Please Mark Brainleast!!!

The sequence to prove that AD = BC is; First prove ABC is similar to CDA, and then state AD and BC are opposite sides of the parallelograms.

How to prove Quadrilateral Theorems?

From the question, we see that the parallelogram ABCD has a diagonal AC. Thus; AB║ CD and AD║BC.

Now, the parallelogram is divided into two triangles ΔABC and ΔADC by its diagonal AC.

Thus;

∠ACB = ∠DAC  and ∠CAB = ∠ACD  because they are alternate interior angles.

Also, AC = AC  (Reflexive property)

Thus; by ASA congruence postulate, we can say that; ΔABC ≅  ΔADC

Also, by corresponding sides of the congruent triangles are congruent we can say that AD = BC.

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evaluate the expression 4 3x when x is 2

Answers

4 times 3(2) = 24
24 would be the answer

In a certain year, 26% of people aged 65–69 worked. Suppose that a recent report claimed that the percentage of people aged 65–69 who work has increased since that year.

Answers

Considering the situation described, the appropriate hypotheses set is given by:

[tex]H_0: p = 0.26[/tex]

[tex]H_1: p > 0.26[/tex]

What are the hypotheses test?


At the null hypotheses, we test if there is not enough evidence that the percentage has increased, that is, it still is of 26%, hence:

[tex]H_0: p = 0.26[/tex]

At the alternative hypotheses, we test if there is evidence that it has increased, hence:

[tex]H_1: p > 0.26[/tex]

More can be learned about hypothesis tests at https://brainly.com/question/26454209

can someone please help me

Answers

Answer:

x = 49

Step-by-step explanation:

corner point b = 41

d = right angle ( 90 )

90 + 41 = 131

180- 131 = 49

x = 49

p.s

im not sure if d is a right angle if it is not please inform me.

A prize is divided in the ratio 5:1 if the larger share is £65 what is the total prize?

Answers

Answer:

£78

Step-by-step explanation:

65 divided by 5= £13

13+65=£78

Answer:

£78

Step-by-step explanation:

Let the total value be T.

£65/T = 5/(5 + 1)£65/T = 5/6T = 65 x 6 / 5T = 13 x 6T = £78


How much of a radioactive kind of promethium will be left after 20 days if you start with
9,056 grams and the half-life is 5 days?

Answers

in 20 days 4 half life will be completed

so n = 4

formula :-

[tex] \frac{ A\degree}{ {2}^{n} } = \frac{9056}{ {2}^{4} } = \frac{9056}{16} = 566grams[/tex]

The radioactive kind of promethium will have 566 grams left after 20 days.

What is half-life?

Half-life is the time required for a quantity to reduce to half of its initial value.

Given, A radioactive kind of promethium with 9,056 grams and a half-life is 5 days.

∴ In the next 5 days, it'll have (9056/2) = 4528 grams.

Next 5 days it'll have (4528/2) = 2269 grams.

As it has a half-life in 5 days and 20 is multiple (4×5).

After 20 days the radioactive material will have (9056/2⁴) grams.

= 566 grams left.

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find measure of the missing angles and justify your answer with postulates and theorems.

Answers

Answer:

Step-by-step explanation:

I need step by step written answer for this​

Answers

Answer:

-1/2

Step-by-step explanation:

2/5 * - 3/7 - 1/14 - 3/7 * 3/5

= - 6/35 - 1/14 - 9/35

= - (6*2)/(35*2) - (1*5)/(15*5) - (9*2)/(35*2)

= - 12/70 - 5/70 - 18/70

= (-12 - 5 - 18)/70

=- 35/70

= - 1/2

2/5 * - 3/7 - 1/14 - 3/7 * 3/5
- 6/35 - 1/14 - 9/35
- (6*2)/(35*2) - (1*5)/(15*5) - (9*2)/(35*2)
- 12/70 - 5/70 - 18/70
= (-12 - 5 - 18) /70
=- 35/70
- 1/2

How many gallons is equal to 48 cups?

Answers

Answer:

3 US galloons

In the figure below, triangle QRT, triangle RSQ, and triangle QST are scalene triangles.

If mQRS = 37° and mTQS = 34°, what is mTQR?
A.
87°
B.
90°
C.
93°
D.
109°

Answers

mTQR = 87°

HOPE IT HELPS...!!!

Answer:

[tex] \sf m \angle TQR = 87 \degree[/tex]

Step-by-step explanation:

Given:

QRT, RSQ and QST are scalene traingle.

[tex]m \angle QRS = 37 \degree \\ m \angle TQS = 34 \degree \\ m \angle QST = 90 \degree[/tex]

To find:

[tex]m \angle TQR = ?[/tex]

Solution:

In ∆ QTS,

[tex] \sf \: m \angle TQS + m \angle QTS +m \angle QST = 180 \degree \: \\ \sf (properties \: of \: triangle)[/tex]

[tex] \sf \: 34 + m \angle QTS +90 = 180 \degree \: \\ \sf m \angle QTS = 180 - 90 - 34 \\ \sf \: m \angle QTS = 180 - 124 \\ \sf \: m \angle QTS = 56 \degree[/tex]

Now in ∆QTR,

[tex] \sf \: m \angle QTR + m \angle TQR + m \angle TRQ \: = 180 \degree \\ \sf (properties \: of \: triangle)[/tex]

[tex] \sf \: 56 + m \angle TQR + 37 \: = 180 \degree \\ \sf m \angle TQR = 180 - 56 - 37 \\ \sf m \angle TQR = 87 \degree[/tex]

Thanks for joining brainly community!

​4sin45 degrees cos 15degrees=1+square root 3

Answers

[tex]\text{R.H.S}\\\\=4\sin 45^{\circ} \cos 15^{\circ} \\\\=4\sin 45^{\circ} \cos (45^{\circ}-30^{\circ})\\ \\=4 \sin 45^{\circ} \left(\cos 45^{\circ} \cos 30^{\circ} +\sin 45^{\circ} \sin 30^{\circ} \right)\\\\=4 \left(\sin 45^{\circ} \cos 45^{\circ} \cos 30^{\circ} +\sin^2 45^{\circ} \sin 30^{\circ} \right)\\[/tex]

[tex]=4\left[\dfrac 1{\sqrt 2} \cdot \dfrac 1{\sqrt 2} \cdot \dfrac{\sqrt 3}2 +\left( \dfrac 1{\sqrt 2} \right)^2 \cdot \dfrac 12 \right]\\ \\=4\left(\dfrac{\sqrt 3}4 +\dfrac 14\right)\\\\=4\cdot \dfrac 14 \left(1+\sqrt 3\right)\\\\=1+\sqrt 3\\\\=\text{L.H.S}[/tex]

135.99 rounded to two significant figures

Answers

Answer:

1.3×10^1

Step-by-step explanation:

For this, you need to use scientific notation

First, let's round up the decimal points

135.99 = ~ 136

1.3 ×.10^1

A sample of bacteria is decaying according to a half-life model. If the sample begins with 500 bacteria,
and after 17 minutes there are 150 bacteria, after how many minutes will there be 10 bacteria
remaining?
When solving this problem, round the value of k to four decimal places and round your final answer to
the nearest whole number.

Answers

contact +2348021312463, he can help you

after approximately 137 minutes, there will be 10 bacteria remaining.

To find the time at which there will be 10 bacteria remaining, we can use the half-life model for exponential decay, which is given by:

N(t) = N₀ * [tex](1/2)^{(t / t_{half})[/tex]

where:

N(t) = the number of bacteria at time t

N₀ = the initial number of bacteria

t = time (in minutes)

t_half = the half-life of the bacteria

We are given that the initial number of bacteria (N₀) is 500 and after 17 minutes there are 150 bacteria (N(17) = 150).

Let's use this information to find the value of k (the decay constant):

150 = 500 * [tex](1/2)^{(17 / t_{half})[/tex]

Divide both sides by 500:

[tex](1/2)^{(17 / t_{half})[/tex] = 150 / 500

[tex](1/2)^{(17 / t_{half})[/tex] = 0.3

Now, we can write the equation as an exponent:

17 / t_half = log base (1/2) of 0.3

Using logarithms:

t_half = 17 / log base (1/2) of 0.3

Now, calculate t_half:

t_half = 17 / log base 2 of 0.3 ≈ 38.555

Now, we can find the time at which there will be 10 bacteria remaining (N(t) = 10):

10 = 500 * [tex](1/2)^{(t / 38.555)[/tex]

Divide both sides by 500:

[tex](1/2)^{(t / 38.555)[/tex] = 10 / 500

[tex](1/2)^{(t / 38.555)[/tex] = 0.02

Write the equation as an exponent:

t / 38.555 = log base (1/2) of 0.02

Using logarithms:

t = 38.555 * log base 2 of 0.02 ≈ 137.08

Rounding to the nearest whole number:

t ≈ 137

So, after approximately 137 minutes, there will be 10 bacteria remaining.

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find the 39th term for the aritmethic sequence, 10,15,20

Answers

because you are increasing by 5, you multiply 39x5
this will equal 195.
because you didn’t start at 5, you have to add 10-5 to your answer.
this will make your answer 200.

The 39th term of the sequence is 200.

What is Arithmetic Sequence?

Arithmetic sequence or arithmetic progression is the set of numbers for which the difference of any two consecutive numbers in that set will be a constant.

The constant term which is the difference of the two consecutive numbers is called the common difference and is usually denoted by 'd'.

Arithmetic sequence is usually represented as

a, a + d, a + 2d, ........, a + (n - 1)d

The nth term of an arithmetic sequence, aₙ is given by the formula,

aₙ = a + (n - 1) d

where, a is the first term and d is the common difference.

The given sequence is 10, 15, 20, ......

a = 10

d = 15 - 10 = 5

Here, we have to find the 39th term of the sequence.

a₃₉ = 10 + (39 - 1) 5

     = 10 + (38 × 5)

     = 10 + 190

     = 200

Hence, the 39th term of the progression 10, 15, 20,..... is 200.

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The following data points represent the number of children in each household in Cam's neighborhood.
0, 0,6,3,1,5, 0, 2,0
How many households in Cam's neighborhood have 0 children?
households

Answers

Answer:

4

Step-by-step explanation:

We can see that 9 households are represented in the data, 4 of them are zeros. This means 4 households in Cam's neighborhood have 0 children.

can someone please help with this problem please

Answers

Answer:

1360 seats sold

Step-by-step explanation:

total seats = 1600

total seats sold = 85% of 1600

= 85/100 × 1600

= 85 × 16

= 1,360 seats sold

how do you solve 7/8+(4/8-2/4)

Answers

the answer is 7/8 find a common denominator or cross multiply

A picture frame measures 18 cm by 20 cm on the outside, and 168 cm?
of picture shows.
Find the width of the frame around the picture.
The width of the frame is
cm.

Answers

Answer:

hello

( 20 - 2 x ) ( 18 - 2 x )

= 360 - 40 x - 36 x + 4 x²

= 4 x² - 76 x + 360

Step-by-step explanation:

The graph shows the amount of caffeine left in the body after drinking a 20-ounce soft drink with 90 milligrams of caffeine. Which of the following exponential equations best fits the data?
y=90(2)^
y=2(90)^x
y=0.5(90)^x
y=90(0.5)^x

Answers

Answer:

y=90(0.5)^x

The y-intercept is (0,90), so when x=0, y should be 90.

By replacing x=0 in all equations you get;

1)

y=90(2)^0 =90 accepted

2)

y=2(90)^0 =2 rejected

3)

y=0.5(90)^0 =0.5 rejected

4)

y=90(0.5)^0 =90 accepted

Since this is an exponential decrease,

y=90(2)^x is rejected.

You want to know the average height of your three closest friends.
Should you survey the population or a sample?

Answers

Answer:

population

Step-by-step explanation:

A company makes chocolate candies in the shape of a solid sphere. Each piece of candy has a diameter of 9 cm . If a box contains 10 pieces of candy, how much chocolate does the box contain?
Use 3.14 for π, and do not round your answer.

Answers

Step-by-step explanation:

The Volume of a Sphere ( One piece of candy ) = 4/3πr³

r = diameter/2 = 9/2 = 4.5 cm

Volume = 4/3(3.14)(4.5³)

V = 381.51 cm³

the box contains 10 pieces so the box contains :

381.51 x 10 = 3815.1 cm³ of chocolate

What would you do if fear was not a factor and you could not fail?`

i know it's not a maths question but let's try

Answers

Answer:

Well, i would just say you just had to do your best in everything that you do. No pressure , no stress don't overwork yourself and simply take action. Then you will have a chance to get what you want because you tried your best to get to it. Although sometimes we don't get what we want, atleast we'll be closer. As they say, 'Aim for the sun to reach the moon"

Step-by-step explanation:

You're welcome

Which of the numbers below is greater than 36.785 Select all that apply

A) 36.78
B) 36.79
C) 41.2
D) 36.789

Answers

B. 36.79
C. 41.2
D. 36.789

Rewrite the equation by completing the square. X^2-14x+40=0

Answers

Answer:

(x – 7)² – 9

Step-by-step explanation:

I hope this helps

It’s from khan academy

B=10 H=8

Find the area of the parallelogram
Use the slider to help you remember the formula

Answers

Answer:

80

Step-by-step explanation:

area of parallelogram is b(vh)

Mike is buying a car for $24,300. He wants to make a maximum down payment of $3.000. TWo. deals are available, both for 48-month loans. In the first deal, with a factory rebate his down payment will be $1,000. His monthly loan payments would be $573 21 at 8.4% interest. In the second deal, he gets no rebate and makes a $3,000 down payment but his interest rate is 0.9% resulting in a $451.95 loan payment. a) What total amount will Mike pay with the first deal? b) What total amount will Mike pay with the second deal?

Answers

Answer:

1,000

Step-by-step explanation:

candy that costs 31 cents per pound is mixed with candy that costs 46 cents per pound to obtain 50 pounds of candy that costs 40 cents per pound. How many pounds of each of the two types of candy are in the mix?

Answers

Answer:

20 lb of 31 cent candy, 30 lb of 46 cent candy

Step-by-step explanation:

sorry don't have one

here is a smiley face for you

:D

The amount of each type of candy (in pounds) that are mixed for the considered condition is: 20 pounds of first type of candy and 30 pounds of second type of candy.

How to form mathematical expression from the given description?

You can represent the unknown amounts by the use of variables. Follow whatever the description is and convert it one by one mathematically. For example if it is asked to increase some item by 4 , then you can add 4 in that item to increase it by 4. If something is for example, doubled, then you can multiply that thing by 2 and so on methods can be used to convert description to mathematical expressions.

For this case, we can assume the separate weights of each type of candies to be represented by variables.

Let we have:

x = weight (in pounds) of first type of candy whose cost is 31 cents per pound.y = weight (in pounds)  of second type of candy whose cost is 46 cents per pound.

x pounds of first type of candy is mixed with y pounds of second candy.

The weight of the mixture = x + y = 50 pounds

The cost of the mixture = 40 cents per pound  = [tex]40 \times 50 = 2000[/tex] cents

Cost of the mixture = cost of x pounds of first candy+ cost of y pounds of second candy = [tex]31x + 46y[/tex]
Thus, we get [tex]31x + 46y =2000[/tex]

Therefore, we got a system of two linear equations as:

[tex]x +y = 50\\31x + 46y =2000[/tex]

From first equation, we get:

[tex]x = 50 -y[/tex]

Substituting this value in second equation, we get:

[tex]31(50-y) + 46y =2000\\1550 + 15y = 2000\\15y = 450\\\\y = 450/15 = 30[/tex]

Putting this value of y in equation for x, we get:

[tex]x = 50-y = 50-30 = 20[/tex]

Thus, the amount of each type of candy (in pounds) that are mixed for the considered condition is: 20 pounds of first type of candy and 30 pounds of second type of candy.

Learn more about solving system of linear equations here:

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