The height of the projectile is 69.7 meters when air resistance can be ignored.
The initial speed (u) of the projectile is = 37 m/s
The final speed (v) is 0 because, at a high point, the projectiles come at the rest condition.
The acceleration is negative when the project is thrown in an upward direction. Therefore, the acceleration is, a = -g
Or, a = -9.81 m/s²
Now, by using the kinematics equation, we can find the height of the projectile.
v² = u² + 2gh
(0 m/s)² = (37 m/s)² + 2(-9.81 m/s²)h
2(9.81 m/s²)h = (37 m/s)²
Or, h = (37 m/s)²/ 2(9.81 m/s²)
Or, h = 69.7 m
Therefore, the height of the projectile is 69.7 meters.
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Consider the electronic transition from n = 7 to n = 4 in the hydrogen atom. is light absorbed or emitted? calculate the energy, the frequency and wavelength (nm) of the photon involved.
Energy for this electronic transition is ΔE=0.572eV frequency is ν=1.38×[tex]10^{14}[/tex] [tex]s^{-1}[/tex] and wavelength is 2.17×[tex]10^{-6}[/tex] m
The Bohr Model for the energy of an electron in a hydrogen atom gives us:
E=−[tex]\frac{13.6}{n^{2} }[/tex] eV
Where n is the principle quantum no
For the transition 7→4 the difference in energy is given by:
ΔE= -[tex]\frac{13.6}{49}[/tex]+[tex]\frac{13.6}{16}[/tex] eV
ΔE=0.85-0.277
ΔE=0.572eV
To convert this to Joules we multiply by the electronic charge:
ΔE=0.572×1.6×[tex]10^{-19}[/tex]=9.16×[tex]10^{-20}[/tex]J
(b)
To find the frequency of the emitted photon we use the Planck expression:
ΔE=hν
∴ν=ΔE/h=(9.16×[tex]10^{-20}[/tex])÷(6.626×[tex]10^{-34}[/tex])[tex]s^{-1}[/tex]
ν=1.38×[tex]10^{14}[/tex] [tex]s^{-1}[/tex]
To find the wavelength
λ=c/ν
(3×[tex]10^{8}[/tex])/(1.38×[tex]10^{14}[/tex]) m
=2.17×[tex]10^{-6}[/tex] m
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find the strength of the net force produced by a 34-n force and a 21-n force in each of these cases.
The net force is in the first case is 13 N and in the second case is 55 N.
What is gravitational force?All mass-bearing objects are attracted by gravitational force. Because it consistently attempts to bring masses together rather than push them apart, the gravitational force is referred to as attractive.
As we know, the gravitational force is given by:
[tex]\rm F = \dfrac{Gm_1m_2}{r^2}[/tex]
Where G is the gravitational constant.
m1 and m2 are masses.
r is the distance between the masses.
It is given that:
Two forces are given:
The two forces act in opposite directions:
= 34 - 21
= 13 N
Both forces act in the same direction:
= 34 + 21
= 55 N
Thus, the net force is in the first case is 13 N and in the second case is 55 N.
The question is incomplete the complete question is:
find the strength of the net force produced by a 34-n force and a 21-n force in each of these cases.
The two forces act in opposite directions.
Both forces act in the same direction.
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A boat`s speed in still water is 20 km/h . If the boat is to travel directly across a river whose current has a speed of 12 km/h, at what upstream angle must the boat head ?
The sine components of the velocity of the boat will balance out the velocity of the river making an angle of 37° with the vertical.
What are the components of vectors?Every vector can be broken into some components, these components on vector addition would again give the resultant vector.
The components of the vector act independently.
Given:
Velocity of the boat in still water = 20km/h
Velocity of the river stream= 12km/h
We want the boat to go directly opposite to the starting point without any drift. For this one component of the boat's speed should be acting parallel to the speed of the stream and cancelling its effect in the motion of the boat.
Therefore preventing the drift of the boat now with the other perpendicular speed vector component the boat will cross the river.
Assumption:
The boat goes at an angle p with the vertical or perpendicular to the river stream.
v is the resultant speed of the boat
u is the velocity of the stream
According to the question:
v × sin(p) = u
Sin(p) = 0.6
p = 37°
Therefore, The sine components of the velocity of the boat will balance out the velocity of the river making an angle of 37° with the vertical.
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In a standard deck of cards, what is the probability of drawing a black card followed by drawing a heart? answer choices are in the form of a percentage, rounded to the nearest whole number.
Percentage of probability of drawing a black card followed by drawing a heart = 13%
Total cards in a deck of cards = 52
Total black cards in a deck of cards = 26
Probability of drawing a black card = (26/52) = (1/2)
Percentage of probability of drawing a black card = (1/2) × 100 = 50 %
Total hearts in a deck of cards = 13
There are 26 black card in a deck of 52 cards . Once the black card is drawn we are left with total of 51 cards. So, we can write
Probability of then drawing a heart = (13/51)
To get the probability of drawing a black card followed by drawing a heart we need to multiply the fractions together, so we can write
Probability of drawing a black card followed by drawing a heart = (1/2) × (13/51) = (13/102)
Percentage of probability of drawing a black card followed by drawing a heart = (13/102) × 100 = 12.74% = 13% (after round off)
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Lab 2 uniform velocity why do you think it necessary to cut off the first few dots?
It is necessary to cut off the first few dots because a small distance between dots means the object was moving slow during that time interval.
What is Uniform velocity?Uniform velocity is the state in which a body travels the same distance in the same amount of time.
The average velocity of a body is represented by the variable v in the equation (d = v t). If the magnitude and direction of the velocity do not change over time, the body is said to be moving at a uniform speed.
An example of constant velocity, or when a body moves with increasing speed at regular intervals, is the rotation of the Earth.
Uniform velocity is the state in which a body travels the same distance in the same amount of time. The average velocity of a body is given in the equation (d = v t), and its magnitude and direction are constant across time.
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True or false: Scientific study can always be categorized as belonging to only one of the three major categories of sciences.
True false question.
It is a false statement that Scientific study can always be categorized as belonging to only one of the three major categories of sciences.
What is a scientific study?A scientific study involves an investigation into issues that has to do a scientific topic. There are three main branches of science which are physics, chemistry and biology. However most of the research in science is interdisciplinary. It involves a synergy between the various fields of science.
Thus, it is a false statement that Scientific study can always be categorized as belonging to only one of the three major categories of sciences.
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When two or more atoms combine into a chemical compound, the force of attraction holding the atoms together is known as a ______. A. charge B. electric current C. bond D. magnetic pole
Answer:
rgg3ge4gg434g4g4g4g44g
Explanation:
grg4g4g4y44h44h
the electric field midway between two equal but opposite point charges is 573 n/c , and the distance between the charges is 16.0 cm
The charge will be equal to 4.07 x 10⁻¹⁰ coulombs.
What is an electric field?The term "electric field" refers to the physical field that surrounds electrically charged particles and pulls or attracts all other charged particles nearby.
Use the following formula E = Kq / r² Since the electric field is 573 N/C
The distance of the midpoint of the charge.
r = 1/2 x 16 = 8 cm = 0.08m.
573 = (8.998 x 10⁹) x q) / (0.08)²
573 x 0.0064 = 8.998 x 10⁹ x q
q = (573 x 0.0064)/ 8.998 x 10^(9)
q =3.6672 / 8.998 x 10⁹
q = 4.07 x 10⁻¹⁰ coulombs
Therefore, the charge will be equal to 4.07 x 10⁻¹⁰ coulombs.
The complete question is given below:-
The electric field midway between two equal but opposite point charges is 573 n/c , and the distance between the charges is 16.0 cm. Calculate the magnitude of the charge.
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numerical study on transient airflows and air exchange induced by door motion in thermally stratified environment
The correct answer is transient airflows under the combined motion of a door and the force of buoyancy.
However, the combined airflow characteristics generated by door motion, ventilation airflow, and thermal impacts have not yet been thoroughly defined. Door motion has been acknowledged as playing a part in the confined conveyance between indoor and outdoor regions. This study employed dynamic CFD simulation to look at the transient airflow characteristics and amount of air exchange generated by door motions in a thermally stratified environment with displacement ventilation. The results show that at a door angle of 30°, there is a 40% air exchange even though only 15% of the overall door motion process is used during the initial phase. Two important contributing factors are the temperature difference between the air inside and outside, as well as the rotational speed of the door.
The thermal convective flow may have a considerable impact on the airflow pattern through the doorway when the door motion is slow enough and the temperature difference is greater than 3 °C. The amount of air exchange rises linearly with door motion speed when there is no difference in temperature between the internal and exterior spaces. When buoyant force and door motion are coupled, a modest door speed yields minimal air exchange. Only the air temperatures close to the door are impacted by door movement. In the displacement ventilated room, a single door open and close cycle does not considerably reduce the overall temperature stratification. The research findings may help to improve knowledge of the consequences of dynamic disturbances in thermally stratified environments as well as offer recommendations for decreasing door motion-induced pollutant movement.
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What’s an example of potential energy? I WILL CROWN YOU PLS HELP
A
Water behind a dam
B
A dart stuck in a dartboard
C
Plants using photosynthesis
D
A cow chewing grass
Answer:
I think it's A
Explanation:
potential energy is energy waiting to move right?
What is the correct name, number of protons, neutrons, and electrons for the
following
41
19
K
O Potassium -19, 19 protons, 19 electrons, 22 neutrons
O Potassium-41, 19 protons, 19 electrons, 22 neutrons
O Potassium-19, 41 protons, 41 electrons, 19 neutrons
O Potassium-41, 41 protons, 41 electrons, 19 neutrons
Potassium-41, 19 protons, 19 electrons, 22 neutrons is the correct name, number of protons, neutrons, and electrons for the following ₁₉⁴¹K.
The correct option is B.
What does potassium mean?The chemical element with the atomic number 19 and the letter K is potassium. Potassium is a silvery - white metal that may be cut with a knife quickly and painlessly. After only a few seconds of exposure, atmospheric oxygen and potassium metal combine to form flaky, white potassium peroxide.
How is low potassium treated?Your potassium level may be affected by a medicine you're taking, or it may be brought on by a medical problem that needs to be treated. The underlying cause of low potassium is treated, which may entail potassium supplementation.
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The complete question is -
What is the correct name, number of protons, neutrons, and electrons for the following ₁₉⁴¹K.
A- Potassium -19, 19 protons, 19 electrons, 22 neutrons
B- Potassium-41, 19 protons, 19 electrons, 22 neutrons
C- Potassium-19, 41 protons, 41 electrons, 19 neutrons
D- Potassium-41, 41 protons, 41 electrons, 19 neutrons
If the precessional frequency of the protons net magnetization is approximately 21.3 mhz, what would be the magnetic strength used to spatial localize a slice?
The correct option is (c) 0.5 .
The magnetic field experienced by the patient's protons is 0.5 Tesla.
What is a magnetic field in simple terms?
The area in which the force of magnetism acts around a magnetic material or a moving electric charge is known as the magnetic field. A diagram that shows the magnetic field and how a magnetic force is distributed inside and outside of a magnetic substance.
What causes a magnetic field?While opposite poles (north and south) are drawn to one another, the same poles repel one another. The north-seeking poles of the iron's atoms line up in the same direction when it is rubbed against a magnet. A magnetic field is produced by the force that the aligned atoms produce.
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The complete question is:
"If the precessional frequency of the protons net magnetization is approximately 21 MHz, a ____ Tesla magnetic field is being experienced by the patient's protons?
(a) 2.0
(b) 1.5
(c) 0.5
(d) 0.3"
What potential difference is needed to give a helium nucleus (q=2e) 75.0 kev of kinetic energy?
The potential difference is needed to give a helium nucleus (q=2e) 75.0 keV of kinetic energy is 37.5kV.
What is potential difference?Potential difference is the difference in amount of energy that charge carriers have between two points in a circuit.
**Measured in Volts: **Potential difference is measured in volts (V) and is also called voltage. The energy is transferred to the electrical components in a circuit when charge carriers pass through them. We use a voltmeter to measure the potential difference (or voltage).
The potential Difference formula:** V = I x R**
The potential difference (which is the same as voltage) is equal to amount of current multiplied by the resistance. A potential difference of one Volt is equal to the one Joule of energy being used by one Coulomb of charge when it flows between two points in a circuit.
For the above question:
The kinetic energy K given to helium nucleus is equal to its potential energy, which is
E=q ∆ V
where q=2e is the charge of helium nucleus, and is the potential difference applied to it.
Since we know kinetic energy, we have
E= K= 75 keV= q ∆ V
and from this we can find potential difference:
∆V= K/q= 75keV/2e= 37.5 kV
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At+what+speed,+as+a+fraction+of+c,+will+a+moving+rod+have+a+length+80+%+that+of+an+identical+rod+at+rest?
At the speed of 0.44 c as a fraction of c, the moving rod will have a length of 80% that of an identical rod at rest.
The speed of the light is c.
c = 3.0 × 10⁸ m/a
Let the length of the moving rod be L.
Let the length of the rod at rest be l.
Length contraction of the rod is,
[tex]L= \sqrt{ 1 - \frac{ v ^{2} }{c ^{2} } \times l} [/tex]
The length of the moving rod is,
Length of moving road = 80% of the length of the rod at rest.
L = 80 % of the l.
[tex] = \frac{80}{100} [/tex]
= 0.80 l
The moving rod will have a length 80% that of an identical rod at rest at the speed of,
[tex]L ^{2} = (1 - \frac{ v ^{2} }{c ^{2} } )\times l ^{2} [/tex]
[tex] \frac{L ^{2}}{l ^{2} }= (1 - \frac{ v ^{2} }{c ^{2} } )[/tex]
[tex]v ^{2} = (1 - \frac{L ^{2}}{l ^{2} }) \: {c^{2} } [/tex]
[tex]v ^{2} = ( \sqrt{1 - \frac{L ^{2}}{l ^{2} }}) \: {c^{2} } [/tex]
[tex]= ( \sqrt{ 1 - \ \frac{0.80 \: l^{2}}{l ^{2} }}) \: {c^{2} } [/tex]
[tex] = \sqrt{( 1 - 0.80) } c[/tex]
v = 0.44 c
Therefore, at the speed of 0.44 c as a fraction of c, the moving rod will have a length of 80% that of an identical rod at rest.
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if we break the acceleration of this missile into two components, in the vertical and horizontal direction, what statement correctly characterizes the source of the acceleration?
Both horizontal and vertical acceleration is produced by the jet engines. While it does contribute to vertical acceleration, gravity has no effect on horizontal acceleration.
there's a particular value or velocity for the horizontal component. with out accounting for air resistance, the horizontal factor is regular for the duration of the flight.
Horizontal velocity affects the variety however not the period of an airborne object. Gravity reasons a downward vertical acceleration that has a price of 9.8 m/s/s.
This vertical acceleration reasons a downward projectile's vertical velocity to vary by 9.8 m/s in keeping with 2nd. The movement of a projectile's horizontal axis is unrelated to its vertical axis.
A projectile's trajectory is determined by using pace in two dimensions. The x and y components of the projectile, respectively, describe its horizontal and vertical pace. Meters are the devices used to signify each horizontal and vertical distances (m).
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What happens to a satellite not moving fast enough to stay in orbit 
Answer:
It would crash into the thing it's orbiting.
Explanation:
Since it's not going fast enough to counter the pull of gravity.
5. (a) Calculate Earth's average speed relative to the Sun. (b) What is its average velocity over a period of one year?
a. The Earth's average speed relative to the Sun is 2970 m/s
b. The earth's average velocity over a period of one year is 0 m/s
(a) Calculate Earth's average speed relative to the Sun.The speed of the earth relative to the sun is given by v = √(GM/r) where
G = universal gravitational constant = 6.67 × 10⁻¹¹ Nm²/kg², M = mass of sun = 1.989 × 10³⁰ kg and r = distance of earth from sun = 1.5043 × 10¹¹ mSubstituting the values of the variables into the equation, we have
v = √(GM/r)
v = √(6.67 × 10⁻¹¹ Nm²/kg² × 1.989 × 10³⁰ kg/1.5043 × 10¹¹ m)
v = √(13.26663 × 10¹⁹ Nm²/kg/1.5043 × 10¹¹ m)
v = √(8.8191 × 10⁸ Nm²/kg)
v = 2.97 × 10⁴ m/s
v = 2970 m/s
So, the Earth's average speed relative to the Sun is 2970 m/s
(b) What is its average velocity over a period of one year?The average velocity of the Earth is v = ΔD/T where
ΔD = total dispalcement = D' - D where D = initial position of earth and D' = final position of earth and T = period of earth over one year = 365 days × 24 h/day × 60 min/h × 60 s/min = 31536000 s = 3.1536 × 10⁸ sNow, since the earth starts and stopps at the same position, D' = D.
So, ΔD = D' - D = 0
Substituting the values of the variables into the equation, we have
v = ΔD/T
v = 0 m/3.1536 × 10⁸ s
v = 0 m/s
So, the earth's average velocity over a period of one year is 0 m/s
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a pendulum of length 0.50 meters, mass 1.0 kilogram, and displacement angle 12 degrees has a period of 1.4 seconds. determine the period if the mass is doubled.
The period of pendulum is still the same at 1.4 seconds.
We need to know about pendulum experiment to solve this problem. The pendulum is a simple experiment to calculate gravitational acceleration. The gravitational acceleration can be calculated by
g = 4π² . L / T²
where g is gravitational acceleration, L is the length of the string and T is the period.
From the question above, we know that:
L = 0.5 meters
m1 = 1 kg
θ = 12⁰
m2 = 2 . m1
T1 = 1.4 seconds
Find the period of pendulum
g = 4π² . L / T²
T² = 4π² . L / g
T = √(4π² . L / g)
The period of a pendulum does not depend on the mass of the object, hence the period is still the same at 1.4 seconds.
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How much additional time will pass before the ball passes the tree branch on the way back down?
The additional time pass before the ball passes the tree branch on the way back down is 1.913 .
Consider the displacement equation
s(t) = (-g/2)t^2 + v(0)t + s(0)
where g = 9.8 m/s/s is the acceleration due to gravity,
v(0) = 15 m/s is the initial velocity, and
s(0) = 0 is the staring position (the ground).
We want to know when s(t) = 7 m. Thus,
7 = (-9.8/2)t^2 + 15t
We solve for t by solving the quadratic
(-9.8/2)t^2 + 15t - 7 = 0
Using the Quadratic Formula, we get the two roots
t1 = .574 seconds
t2 = 2.487 seconds
These two values represent the times when the ball passes the tree branch. Therefore, the total time between passing the branch is the difference between 2.49 seconds and 0.57 seconds.
Thus, the ball is at 7 meters at both times. The additional time after the first instance is
d = t2 - t1 = 2.487 - .574 = 1.913 seconds
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Convert 300 m/s to mi/hr
Answer:
671.22 mi/hr
Explanation:
[tex](\frac{300 m}{s} )(\frac{1mi}{1609m} )(\frac{3600s}{1hr} )=\frac{(300)(3600)}{1609} =671.22mi/hr[/tex]
Hope this helps
An artificial satellite moves at a steady 25,000 km/hr in a circular orbit around earth. is it accelerated?
Yes the motion is accelerated.
We have a artificial satellite that moves at a steady 25,000 km/hr in a circular orbit around earth.
We have to determine whether or not it is accelerated.
What is an Artificial Satellite ?An artificial Satellite is a man - made artificial body placed in orbit round the earth or moon or another planet in order to collect information or for communication.
According to the question -
v = 25000 km/hr
Now for the motion to be accelerated the velocity must change with respect to time. But, the velocity here is constant. It should be kept in mind that the velocity is a vector quantity, its magnitude is constant but its direction keeps on changing in circular motion, and hence, its acceleration also changes.
Hence, yes the motion is accelerated.
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For an object in uniform circular motion, its velocity and acceleration vectors are always perpendicular to each other at every point in the path. True or false?.
For an object in uniform circular motion, its velocity and acceleration vectors are always perpendicular to each other at every point in the path is true.
What is circular motion?Circular motion refers to the movement of a body part around the perimeter of a circle or in a circular motion. It may rotate at a fixed speed and angular rate or it may rotate at a variable rate, making it either uniform or non-uniform. A three-dimensional body's components move in circles as it rotates around a fixed axis. The center of mass of a body moves according to the equations of motion. In circular motion, the distance between the body and a fixed point on the surface stays constant.
Examples of circular motion include an artificial satellite circling the Earth at a constant altitude, ceiling fan blades spinning around a hub, and a rotating disc.
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it is known that a vertical force of 200 lb is required to remove the nail at c from the board. as the nail first starts moving, determine (a) the moment about b of the force exerted on the nail, (b) the magnitude of the force p that creates the same moment about b if (c) the smallest force p that creates the same moment about b.
(a) The moment about B is 800 lb.in
(b) The magnitude of the force P is 51.3lb
(c) The smallest force P is 44.4lb
(a)
As we know,
[tex]M_{B} = r_{CIB}F_{N}[/tex]
[tex]M_{B}[/tex] = [tex]4[/tex] × [tex]200[/tex]
= 800 lb.in
The moment about B is 800 lb.in
(b)
By using the formula,
[tex]M_{B} =r_{AIB}Psin[/tex]θ
θ = 120°
Then, [tex]800[/tex] = [tex]18[/tex] × [tex]Psin120[/tex]°
P = 51.3lb
The magnitude of the force P is 51.3lb
(c)
P must be perpendicular to the line connecting points A and B in order for it to be minimal.
Using the formula,
[tex]M_{B} = dP_{min}[/tex]
[tex]800[/tex] = [tex]18[/tex] × [tex]P_{min}[/tex]
[tex]P_{min}[/tex] = 44.4lb
The smallest force P is 44.4lb
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a well-insulated rigid tank contains 3 kg of a saturated liquid–vapor mixture of water at 200 kpa. initially, threequarters of the mass is in the liquid phase. an electric resistance heater placed in the tank is now turned on and kept on until all the liquid in the tank is vaporized.
The correct answer is ΔS=11.16kJ/K.
m=3kg
p_1=200kPa
m_f1=3/4m=2.25kg
x_2=1
ΔS=?
x_1=m_g/m=(m-_f1)/m=(3-2.25)/3=0.25
p_1=200kPa
v_f1=0.001061m^3/k g
v_g1=0.88578m^3/k g
s_f1=1.5302k J/k gK
s_fg1=5.5968 k J/kgK
With these data, we may solve for particular entropy in state 1 using the following equation:
s_1=s_f1+x_1g=1.5302+(0.25)(5.5968)
=2.9294 kJ/kgK
Entropy will be obtained in stage 2, but in order to do so, we must first compute a particular volume in state 1 that is identical to the one in state 2, as this is a constant volume process.
The formula for a particular volume is:
v_1=v_f1+x_1v_fg=0.001061+0.25(0.88578-0.001061)=0.22m^3/kg=v_2
Now, we may get particular entropy in state 2 using the Molier diagram for water.
p_2=1/v_2=1/0.22=4.55 kg/m^3
x_2=1⇒s_2=6.65kJ/kgK
Final entropy change is:
ΔS=m(s_2-s_1)
=3(6.65-2.9294)
ΔS=11.16kJ/K
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A lightning bolt with 10 ka strikes an object for 15 s. how much charge is deposited on the object?
The charge deposited on the object is 150000 C.
What is charge?Charge can be defined as the product of current and time. The S.I unit of charge is coulombs (C.)
To calculate the charge deposited on the object, we use the formula below
Formula:
Q = it.................equation 1Where:
Q = Chargei = Currentt = TimeFrom the question,
Given:
i = 10 kA = 10000 At = 15 sSubstitute these values into equation 1\
Q = 10000×15Q = 150000 CHence, the charge deposited on the object is 150000 C.
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the linear momentum of a bullet-gun system is zero before the gun fires. afterwards: i. the kinetic energy is zero ii. the momentum is zero group of answer choices i & ii i ii neither i nor ii
Answer:
Neither of the two options.
Explanation:
Before a bullet is fired, the momentum of the bullet-gun system is zero because of lack of velocity. After the gun is fired, both gun and bullet acquire velocity making them nonzero. Thus, it is impossible for the kinetic energy to be zero because both the bullet and the gun are in motion. Also, the momentum is nonzero momentum is the product of the mass of an object and its corresponding velocity. Once the bullet is fired, both the bullet and the gun gains momentum thus making it nonzero.
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ow many times as strong is the coulomb repulsion between two electrons than the gravitational attraction between the same two electrons? (the distance does not matter.)
Fe/Fg = 4.2 x 10⁴² is the gravitational attraction.
Gm²/r² the gravitational attraction between two electrons is given by, where G is the gravitational constant, m is the electron mass, and r is the distance between the two electrons.
r = the distance between two electrons the size of the charge on each electron, or q, is 1.6 x 1019 C.
The mass of one electron, or m, is 9.1 x 1031.
The Coulomb force of repulsion is expressed mathematically as
Fe equals (9 x 109) k q/r2 (1.6 x 10-19) ²/r²
Fg = Gm2/r2 = 6.67 x 1011 is the formula for the gravitational force of attraction. (9.1 x 10⁻³¹) ²/r²
The formula for calculating Fe/Fg is [(9 x 109) (1.6 x 1019) 2/r2] / [(6.67 x 1011). (9.1 x 10^-31) ⁻³/r²]
Fe/Fg = 4.2x10⁴²
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Suppose we want a satellite to revolve around the earth 6 times a day. what should the radius of its orbit be? (neglect the presence of the moon.)
We must use the principles of the balance of forces to resolve this exercise.
What is centrifugal force?
A hypothetical force called centrifugal force, which is unique to particles traveling in a circle, is a force that has the same strength and dimensions as the centripetal force, but acts in the opposite direction.
The force exerted on the satellite by the planet in this specific instance must be equal to the centrifugal force, that is
Fg =Fe
GMm/ r^2 = mw^2r
Where,
G = Gravitational Universal Constant
M = Mass of earth
m = mass of satellite
r = Distance/Orbit
By changing and rearranging the equation to find the orbit using the idea of Period through the Angular Velocity, we have,
r = 1.44 x 10^7 m
The orbit is 14400 kilometers
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what did edwin hubble discover about galaxies that allowed him to determine the expansion rate of the universe?
Edwin Hubble was an American astronomer who discovered a way to determine the rate of expansion of the universe through the relationship between the velocities of remote galaxies and their distances.
Mr. Hubble established what is known as Hubble's law, this law states that the greater the distance of a galaxy, the greater the speed at which it moves away from us, so both the law indicates that the large objects in the universe are moving away from each other steadily causing an unchanging expansion.
What is the Hubble constant?It is a mathematical constant that expresses the expansion velocity of the universe at a distance from a point in space. Its value is 69.8 km/s/Mpc.
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how far would it be from the milky way galaxy to the most distant galaxies in the observable universe on this scale?
The distance from the milky way galaxy to the most distant galaxies in the observable universe would be approximately 1.34 kilometers on a scale in which the MIlky Way Galaxy was the size of a marble(about 1 cm).
The MIlky Way is the galaxy that includes our solar system along with billions of stars.
To measure distances in space, we use the unit light year. One light year is the distance travelled by light in year. 1 light year is equal to 9.5 trillion km.
The size of MIlky Way is about 1,00,000 light years and the distance from the MIlky Way to the most distant galaxies in the observable is 13.4 billion light years.
Therefore, the distance from the milky way galaxy to the most distant galaxies in the observable universe would be approximately 1.34 kilometers on a scale in which the MIlky Way Galaxy was the size of a marble(about 1 cm).
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