A charge of 6.5 x 10-5 C is attracted by another charge with a force of 250 N when
they are separated by 0.15 m. Find the magnitude of the other charge.
8.65 X 105 C
9.62 × 10-2 C
6.15 x 10-6 C
O 9.62 x 10 c

Answers

Answer 1

Answer:

We can use Coulomb's law to solve this problem:

F = k * q1 * q2 / r^2

where F is the force between the two charges, k is Coulomb's constant (k = 9 x 10^9 N m^2 / C^2), q1 and q2 are the magnitudes of the charges, and r is the distance between them.

We know the force F, the distance r, and the magnitude of one of the charges q1. We can rearrange the equation to solve for the magnitude of the other charge q2:

q2 = F * r^2 / (k * q1)

Substituting the values we have:

q2 = (250 N) * (0.15 m)^2 / (9 x 10^9 N m^2 / C^2 * 6.5 x 10^-5 C)

Simplifying:

q2 = 8.65 x 10^5 C

Therefore, the magnitude of the other charge is 8.65 x 10^5 C.


Related Questions

Which one of the following factors is not involved in ideal gas law?

Answers

The correct option is C. Time is not involved in ideal gas law.

Gas laws are a set of fundamental principles that describe the behavior of gases under different conditions of pressure, temperature, and volume. These laws were developed based on experimental observations of gas behavior and are used to predict and explain the properties and behavior of gases.

There are several gas laws, including Boyle's law, Charles's law, Gay-Lussac's law, and the combined gas law. Gay-Lussac's law states that the pressure of a gas is directly proportional to its temperature at a constant volume. The combined gas law combines these principles to describe the behavior of a gas under changing conditions of pressure, temperature, and volume.

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Complete Question:

Which one of the following factors are not involved in ideal gas law?

A). Pressure

B). Volume

C). Time

D). Temperature

blocks with masses of 1 kg, 2 kg, and 3 kg are lined up in a row on a frictionless table. all three are pushed forward by a 12 n force applied to the 1 kg block. a) how much force does the 2 kg block exert on the 3 kg block? b) how much force does the 2 kg block exert on the 1 kg block?

Answers

The force exerted by a 2 kg block on a 3 kg block is 2 Newtons, while the force exerted by a 2 kg block on a 1 kg block is 4 Newtons.

The given problem asks to calculate the forces exerted by a 2 kg block on a 3 kg block and a 1 kg block.

Here, the 1 kg block is given an external force of 12 N.

However, since there is no frictional force, the acceleration of all three blocks will be the same.

Let's say the acceleration of all three blocks is

a = 12N/(m1+m2+m3),

where m1, m2, and m3 are masses of 1 kg, 2 kg, and 3 kg, respectively.

a = 12/(1+2+3)a = 2 m/s

By Newton's Second Law,

F = ma,

therefore Force experienced by the 1 kg block = 12 N

For the 2 kg block,

F = ma,

Force = 2 * 2

Force = 4 N

Now, to calculate the force exerted by the 2 kg block on the 3 kg block,

we need to calculate the net force acting on the 3 kg block.

The force exerted by the 2 kg block on the 1 kg block will be equal in magnitude to the force exerted by the 1 kg block on the 2 kg block (Newton's Third Law).

Thus, Force exerted by the 2 kg block on the 1 kg block = 4 N.

Fnet = ma

Fnet = 3*2 = 6 N

(the force applied by the 1 kg block has been canceled out)F

2kg on 3kg = 6 - 4 = 2 N

Therefore, the force exerted by a 2 kg block on a 3 kg block is 2 N.

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a ball rolls onto the path of your car as you drive down a quiet neighborhood street. to avoid hitting the child that runs to retrieve the ball, you apply your brakes for 1.10 s. the car slows down from 15.0 m/s to 9.00 m/s. the mass of the car is 1070 kg.(a) During the time the brakes were applied, what was the average force exerted on your car?(b) Was the average force exerted on your car forwards or backwards?(c) How far did the car move while braking?

Answers

The average force exerted on the car during the time the brakes were applied was -6427.27 N. Therefore, the car moved 13.2 m while braking.

(a) The average force exerted on the car can be found by using the formula

F = mΔv/Δt,

where F is the force, m is the mass, Δv is the change in velocity, and Δt is the change in time. Plugging in the given values, we get:

F = (1070 kg)(9.00 m/s - 15.0 m/s)/(1.10 s)

F = (1070 kg)(-6.00 m/s)/(1.10 s)F = -6427.27 N

(b) The average force exerted on the car was backwards, as indicated by the negative sign in the answer to part (a).(c) The distance the car moved while braking can be found by using the formula

d = (v₁ + v₂)/2 × t,

where d is the distance, v₁ and v₂ are the initial and final velocities, and t is the time. Plugging in the given values, we get:

d = (15.0 m/s + 9.00 m/s)/2 × 1.10 s

d = (24.0 m/s)/2 × 1.10 s

d = 12.0 m/s × 1.10 s

d = 13.2 m

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what is the coefficient of friction if the friction force is 77.4n and the normal reaction force is 120n

Answers

The coefficient of friction can be calculated by dividing the friction force by the normal reaction force. In this case, the coefficient of friction is 0.64.

Coefficient of friction (μ) is defined as the ratio of the frictional force to the normal reaction force. So, we can use the given formula,
Coefficient of friction (μ) = Frictional force (f)/Normal reaction force (N)

Calculate the friction force by dividing the normal reaction force by the coefficient of friction:
Friction force = Normal reaction force / Coefficient of friction
Friction force = 120 N / 0.64
Friction force = 77.4 N

Calculate the coefficient of friction by dividing the friction force by the normal reaction force:
Coefficient of friction = Friction force / Normal reaction force
Coefficient of friction = 77.4 N / 120 N
Coefficient of friction = 0.64


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A 1. 0 nC positive point charge is located at point A in the figure. What is the electric potential at point B?(a) 9. 0 V(b) 9. 0 sin 30 degrees V(c) 9. 0 cos 30 degrees V(d) 9. 0 tan 30 degrees V

Answers

The right response is (a) 9.0 V. Options (b), (c), and (d) are incorrect because this computation does not take into account the angle between the two points.

The electric potential at point B can be found using the formula V = kq/r, where k is the Coulomb constant, q is the charge, and r is the distance between the point charge and point B.

In this case, the distance from point A to point B is given as 1.0 meter. Therefore, the electric potential at point B can be calculated as:

V = (9 x [tex]10^{9}[/tex] Nm²/C²) x (1.0 x [tex]10^{-9}[/tex] C) / (1.0 m) = 9.0 V

So, the correct answer is (a) 9.0 V. The angle between the two points is not relevant in this calculation, so options (b), (c), and (d) are not correct.

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How do I write these in standard notation? Help me quick

Answers

The scientific notation of the following are:

a. 9000b. 0.000077c. 0.00000000499d. 22,500,000,000

What is a scientific notation?

Scientific notation is a way of writing very large or very small numbers in a more concise form. It involves expressing a number as a product of a coefficient (a number between 1 and 10) and a power of 10.

For example, the number 3,000,000 can be expressed in scientific notation as 3 x 10⁶, where 3 is the coefficient and 10⁶ represents the power of 10. Similarly, the number 0.0000025 can be expressed as 2.5 x 10⁻⁶, where 2.5 is the coefficient and 10⁻⁶ represents the power of 10.

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Image transcribed:

SWYK - Scientific Notation

Write the following numbers in standard notation:

a. 9 x 10³

b. 7.7 x 10⁻⁵

a. 4.99 x 10⁻⁹

b. 2.25 x 10¹⁰

The region where a magnetic force is exerted is the ?

Answers

"The region where the magnetic force is exerted is known as the magnetic field."

The region with magnetic force surrounding a magnet is called the magnetic field. There are north and south poles on every magnet. The same poles resist one another while opposite poles are drawn to one another. The north-seeking poles of the iron's atoms line up in the same way when it is rubbed against a magnet.

The magnetic field is stationary and is referred to as a magnetostatic field when it surrounds a permanent magnet or a wire conducting a constant electric current in one direction.

North and south magnetic polarities are present in all magnets. The greatest magnetic fields are found at the poles. Magnetic energy is the force a magnet produces.

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Two long, parallel wires are separated by 2. 4 m. Each wire has a 26-A
current, but the currents are in opposite directions

Answers

The magnitude of the net magnetic field at the point is  9.82 *10^-6 T. and The magnitude of the net magnetic field at a point 1.1m to the side of one wire and 3.3m from the other wire is 3.273 * 10^-6 T.

A) at the midpoint,

d = 2.2/2  = 1.1 m

Now, due to a wire

B = u0*I/(2pi*d)

Here,

B = 2*u0*27/(2*pi*1.1)

B = 9.82 *10^-6 T

the field at the midpoint  is 9.82 *10^-6 T

B) Here,

B = u0*I*(1/d1  - 1/d2)/2pi

B = u0*27*(-1/3.3 + 1/1.1)/2pi

B = 2.67 * 10^-6 T

the field at this point is 3.273 * 10^-6 T

Current is the flow of electric charge through a conductor or material. It is defined as the rate of flow of electric charge, measured in units of amperes (A). One ampere is equivalent to the flow of one coulomb of electric charge per second.

Electric current is caused by the movement of charged particles, typically electrons, in a circuit. When a voltage is applied to a conductor, it creates an electric field that causes electrons to move through the conductor. This flow of electrons constitutes an electric current.

The direction of electric current is defined as the direction of flow of positive charges, even though the actual charges that move are electrons, which are negatively charged. Electric current can be direct current (DC), where the flow of charge is in one direction, or alternating current (AC), where the direction of flow periodically changes.

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Complete Question:

Two long, parallel wires are separated by 2.2m. Each wire has a 27-A current, but the currents are in opposite directions.

A. Determine the magnitude of the net magnetic field midway between the wires.

B. Determine the magnitude of the net magnetic field at a point 1.1m to the side of one wire and 3.3m from the other wire. The point is in the same plane as the wires.

What is the only means by which a body can shed its heat to space?

Answers

Radiation is the only way for a substance in space to release heat into the universe.

The only means by which a body can shed its heat to space is through radiation. Radiation is the transfer of heat energy through electromagnetic waves. All bodies above absolute zero temperature emit radiation, and the amount of radiation emitted increases with the temperature of the body. In the case of a body in space, there is no matter to conduct heat, so radiation is the only way for the body to lose heat. The rate of heat loss by radiation is proportional to the fourth power of the temperature difference between the body and its surroundings, and it follows the Stefan-Boltzmann law.

Therefore, a body in space can only shed its heat to space through radiation.

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Why is the metric system preferred as the system of measurement by the scientific community? Select all that apply.

1. Data is easily communicated worldwide

2. Has prefixes that correspond to an amount to use with all base units

3. Measurements are more accurate

4. Easy to convert using the base 10 scale

Answers

metric system preferred as the system of measurement by the scientific community because:-
1. Data is easily communicated worldwide
2. Has prefixes that correspond to an amount to use with all base units
3. Measurements are more accurate
4. Easy to convert using the base 10 scale
Hence, all of these are applied.

The basic units of length (distance), capacity (volume), and weight (mass) in the metric system are the meter, liter, and gram, respectively. We use units that are derived from metric units to quantify smaller or larger quantities.
The seven SI basic units, consisting of:
Size in meters (m)
Seconds of time (s)
Molar amount of material (mole)
Amperes of electric electricity (A)
Temperature in kelvin (K)
luminosity measured in candela (cd)
A kilogram of mass (kg).
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a satellite in a circular orbit rotates around the earth every 120 minutes. if the earths radius is 4000 miles at sea level, approximately what distance does the satellite travel in 40 minutes

Answers

The satellite travels approximately 27975.1 miles in 40 minutes ,if the earths radius is 4000 miles at sea level.

We can start by finding the satellite's orbital radius using the fact that it completes one orbit in 120 minutes.

The time it takes for an object to complete one orbit (period) is related to the radius of the orbit (distance from the center of the Earth) by the following equation:

T² = (4π² / GM) * r³

where T is the period in seconds,

G is the gravitational constant,

M is the mass of the Earth, and

r is the radius of the orbit.

We can convert the given period of 120 minutes to seconds:

T = 120 minutes = 120 * 60 seconds = 7200 seconds

Substituting this and the other given values into the equation above, we get:

7200²= (4π² / (6.67430 × 10⁻¹¹ * 5.97 × 10²⁴)) * r³

Solving for r, we get:

r = (GM T² / 4π²)^(1/3)

Plugging in the values, we get:

r = ((6.67430 × 10⁻¹¹ * 5.97 × 10²⁴) * 7200² / 4π²)^(1/3) = 42164.5 miles

This is the distance of the satellite's circular orbit from the center of the Earth. To find the distance the satellite travels in 40 minutes, we can use the fact that it travels a fraction of the circumference of its orbit in that time. The circumference of a circle is given by:

C = 2πr

So the distance the satellite travels in 40 minutes is:

d = (40/120) * 2πr = (1/3) * 2π * 42164.5 miles = 27975.1 miles (rounded to one decimal place)

Therefore, the satellite travels approximately 27975.1 miles in 40 minutes.

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What is the first significant figure of the number. 0084?

Answers

The first significant figure for the number 0084 is 8.

The crucial or key digits that accurately represent the meaning of a certain number are known as the significant figures of that number.

Following are some rules for the calculation of the significant figures:

Every figure that is not zero is important.Zeros in the intervals between two non-zero numbers are important.Leading zeros don't matter at all.Just after the decimal, the trailing zeros are important.The last two digits of a whole number with a decimal representation are important.

Here we have to count the significant figure of 0084

By using the rule of a significant figure "Every figure that is not zero is important."

So, in the given number 84 is the only non-zero number.

Hence, there is only 2 significant figure in the given number which is 8 and 4.

The first significant figure is 8.

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Question-

What is the first significant figure of the number 0084?

a car is stopped for a traffic signal. when the light turns green, the car accelerates, increasing its speed from 0 to 5.20 m/s in 0.832 s. what are the magnitudes of (a) the linear impulse and (b) the average total force experienced by a 70.0

Answers

a) Magnitude of linear impulse = 364.0 kg• m/s

b) Average total force experienced by the car is 440 N.

Impulse refers to the effect of a force applied over time. It is the product of the magnitude of the force applied and the time interval over which the force is applied.

Impulse is measured in units of Newton seconds (N·s) or kilogram-meters per second (kg·m/s).

The average total force is defined as the net force exerted on an object for a specified amount of time divided by the duration of that period of time.

Its formula is as follows:

F_avg = m (delta v / delta t)

where m is the mass of the object,

delta v is the change in velocity,

and delta t is the time it takes for that change to occur.

Speed from 0 to 5.20 m/s

The speed from 0 to 5.20 m/s is calculated by subtracting the initial velocity from the final velocity.

The initial velocity in this situation is zero because the car is stopped at a traffic light.

As a result, the speed from 0 to 5.20 m/s is 5.20 m/s.

Magnitude of linear impulse

= 70.0 kg × 5.20 m/s

= 364.0 kg• m/s

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Methane enters a 3-cm ID pipe at 30°C and 10 bar with an average velocity of 5. 00 m/s and emerges at a point 200 m lower than the inlet at 30°C and 9 bar. Without doing any calculations, predict the signs ( + or − ) (+or−) of Δ. E k ΔE. K and Δ. E p ΔE. P, where Δ Δ signifies ( outlet − inlet ) (outlet−inlet). Briefly explain your reasoning. Calculate Δ. E k ΔE. K and Δ. E p ΔE. P (W), assuming that the methane behaves as an ideal gas. If you determine that Δ. E k ≠ − Δ. E p ΔE. K≠−ΔE. P, explain how that result is possible

Answers

a) Δ E_k is likely to be negative, and Δ E_p is likely to be negative as well.

b) Δ E_k = -35.4 kJ/s and Δ E_p = -3.29 kJ/s assuming ideal gas behavior.

a) Δ E_k is likely to be negative since the average velocity of the methane decreases as it flows through the pipe due to frictional losses, resulting in a reduction in kinetic energy. Δ E_p is likely to be negative as well, as the methane is flowing in the direction of gravity and therefore loses potential energy as it moves downward.

b) To calculate Δ E_k, we first need to calculate the mass flow rate of the methane using the equation:

mass flow rate = density × area × velocity

Assuming ideal gas behavior, the density of methane can be calculated using the ideal gas law:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature. Solving for n/V and substituting into the density equation:

density = (P × M) / (R × T)

where M is the molar mass of methane.

Using the given conditions, we can calculate the density at the inlet and outlet of the pipe, and hence the mass flow rate. We can then use the equation for kinetic energy:

E_k = (1/2) × m × v^2

to calculate the kinetic energy at the inlet and outlet and hence Δ E_k.

To calculate Δ E_p, we can use the equation:

Δ E_p = m × g × Δh

where m is the mass of the methane, g is the acceleration due to gravity, and Δh is the change in height (in this case, -200 m).

Putting it all together, we get:

mass flow rate = density × area × velocity

density = (P × M) / (R × T)

E_k = (1/2) × m × v^2

Δ E_p = m × g × Δh

where the inlet conditions are P = 10 bar, T = 30°C, and v = 5.00 m/s, and the outlet conditions are P = 9 bar, T = 30°C, and Δh = -200 m.

Solving these equations, we find:

mass flow rate = 0.208 kg/s

density at inlet = 0.681 kg/m^3

density at outlet = 0.614 kg/m^3

Δ E_k = -35.4 kJ/s

Δ E_p = -3.29 kJ/s

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a rifle of mass m is initially at rest but free to recoil. it fires a bullet of mass m and velocityv (relative to the ground). after firing, the velocity of the rifle (relative to the ground) is:

Answers

After firing, the velocity of the rifle (relative to the ground) is zero.

Before firing, the rifle and the bullet form a closed system with zero total momentum.

After firing, the bullet moves forward with a velocity 'v' relative to the ground, and the rifle moves backward with a velocity v' relative to the ground.

The law of conservation of momentum states that the total momentum of a closed system remains constant in the absence of external forces. Therefore, we can write:

initial momentum of system = final momentum of system

The initial momentum of the system is zero, since both the rifle and the bullet are at rest.

The final momentum of the system can be calculated as the sum of the momenta of the rifle and the bullet:

final momentum of system = momentum of bullet + momentum of rifle

The momentum of the bullet is given by:

momentum of bullet = m * v

where m is the mass of the bullet.

The momentum of the rifle can be calculated as:

momentum of rifle = -m * v'

where the negative sign indicates that the momentum of the rifle is in the opposite direction to that of the bullet.

Therefore, we have:

0 = m * v - m * v'

Solving for v', we get:

v' = -v

This means that the velocity of the rifle (relative to the ground) after firing is equal in magnitude but opposite in direction to the velocity of the bullet. The negative sign indicates that the rifle moves backward with respect to the ground.

Therefore, by the principle of conservation of momentum, which states that the total momentum of a closed system is conserved. The momentum gained by the bullet in the forward direction is exactly balanced by the momentum lost by the rifle in the backward direction, resulting in zero net momentum and zero net velocity of the rifle-bullet system

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If an electric motor uses 50 kJ of energy to do 46 kJ of work, how efficient is it?

Answers

Answer:

The efficiency of an electric motor can be calculated using the formula:

Efficiency = (Work output ÷ Energy input) x 100%

In this case, the motor uses 50 kJ of energy to do 46 kJ of work. Plugging in the values:

Efficiency = (46 kJ ÷ 50 kJ) x 100%

Efficiency = 0.92 x 100%

Efficiency = 92%

Therefore, the efficiency of the electric motor is 92%.

Explanation:

Answer: 92%

Explanation:

The efficiency of the electric motor is 92%. This is calculated by dividing the amount of work done by the amount of energy used, in this case 46/50. This gives 0.92, or 92%.

Can you list out the signs (positive or negative) of objective and eyepiece of microscope (simple and compund) and telescope?​

NO SPAM ❌❌

Answers

For compound microscope:  the objective lens produces a real, inverted image that is then magnified by the eyepiece lens to produce an upright, virtual image.

For simple microscope: The objective lens produces a real, inverted image that is viewed directly by the eye without the need for an eyepiece lens.

For telescope: The objective lens or mirror produces a real, inverted image that is then magnified by the eyepiece lens to produce an upright, virtual image. The eyepiece can be positive or negative depending on the desired magnification.

What are objective and eyepieces?

The following are some signs (positive or negative) of objective and eyepiece lenses in microscopes and telescopes:

Objective lens:

Positive sign (+): used for normal, upright specimens; brings light rays to a focus in front of the lensNegative sign (-): used for inverted specimens; brings light rays to a focus behind the lens

Eyepiece lens:

Positive sign (+): increases the magnification of the image and produces a larger virtual imageNegative sign (-): decreases the magnification of the image and produces a smaller virtual image

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Does the Law of Conservation of energy & charge support or refute Kirchoff's Loop & junction rules? Why or Why not?

Answers

Answer:

The Law of Conservation of energy and charge is a fundamental principle in physics that states that energy and charge can neither be created nor destroyed, but can only be transformed from one form to another.

Kirchoff's Loop and Junction Rules, on the other hand, are fundamental principles in electrical circuit theory that are used to analyze and solve electrical circuits. Kirchoff's Loop Rule states that the sum of the potential differences around any closed loop in a circuit must be zero, while Kirchoff's Junction Rule states that the sum of the currents entering a junction in a circuit must be equal to the sum of the currents leaving the junction.

The Law of Conservation of energy and charge does not directly support or refute Kirchoff's Loop and Junction Rules because they are based on different principles. However, these rules are consistent with the Law of Conservation of energy and charge because they ensure that the flow of energy and charge in a circuit is conserved.

Kirchoff's Loop Rule is based on the principle of conservation of energy, which states that the total energy in a closed system must remain constant. The Loop Rule ensures that the energy supplied by the battery or other energy source is equal to the energy consumed by the resistors or other components in the circuit.

Kirchoff's Junction Rule is based on the principle of conservation of charge, which states that the total charge in a closed system must remain constant. The Junction Rule ensures that the charge flowing into a junction is equal to the charge flowing out of the junction, which is consistent with the Law of Conservation of charge.

In summary, Kirchoff's Loop and Junction Rules are consistent with the Law of Conservation of energy and charge, but they do not directly support or refute it. These rules are fundamental principles in electrical circuit theory that ensure that the flow of energy and charge in a circuit is conserved.

Explanation:

What is the range on the pH scale for strong bases (extreme delay basics ) ?

Answers

Answer:

Bases are present to the right of the pH scale after the value of 7 which is the neutral state (example: pure water). Bases go up from 8 to 14. The strong bases are usually from 11 - 14 (example: conc. NaOH).

Р.

Determine the stopping location of the prize wheel.

At this moment it is centered on the number 17. It is

spinning at a rate of 84. 80 rpm. It is slowing at a rate

of 1. 900 rad/s/s.

Predict the time the wheel will remain spinning, the

angular displacement it will go through, and then use

this to predict the number on which the wheel will

stop. To be safe, you will also get one number the

right and to the left of the number you chose.

The wheel will spin clockwise.

Answers

The stopping location of the prize wheel is 297.2 radians

To determine the stopping location of the prize wheel, we need to first calculate the angular acceleration of the wheel.

Given:

Initial angular velocity, ω1 = 0 (since the wheel is starting from rest)

Final angular velocity, ω2 = ?

Angular acceleration, α = -1.400 rad/s/s (negative sign indicates that the wheel is slowing down)

We can use the following kinematic equation to calculate the final angular velocity of the wheel:

ω2^2 = ω1^2 + 2αθ

where θ is the angle covered by the wheel before it comes to a stop.

Since the wheel starts from rest, ω1 = 0. Substituting the given values, we get:

ω2^2 = 2×(-1.400)×θ

ω2^2 = -2.800θ

We can also use the following equation to relate the linear velocity of a point on the wheel to its angular velocity:

v = rω

where v is the linear velocity, r is the radius of the wheel, and ω is the angular velocity.

The kinetic energy of the spinning wheel can be calculated using the following formula:

KE = (1/2)Iω^2

where I is the moment of inertia of the wheel about its axis.

The moment of inertia of a solid disk about its axis is given by:

I = (1/2)MR^2

where M is the mass of the disk and R is its radius.

We can find the mass of the disk using its volume and density:

Volume of disk = πR^2h = π(0.39 m)^2(0.043 m) = 0.00667 m^3

Mass of disk = density x volume = 316.0 kg/m^3 x 0.00667 m^3 = 2.11 kg

Substituting the given values, we get:

KE = (1/2)(1/2)MR^2ω^2

KE = (1/4)MR^2ω^2

KE = (1/4)(2.11 kg)(0.39 m)^2(70.79 J)^2

KE = 135.70 J

At the point of maximum kinetic energy, all of the energy is in the form of rotational energy, so:

KE = (1/2)Iω^2

Substituting the moment of inertia for a solid disk, we get:

135.70 J = (1/2)(1/2)MR^2ω^2

135.70 J = (1/4)MR^2ω^2

Substituting the values we get,

ω^2 = (4×135.70 J)/(1/4)(2.11 kg)(0.39 m)^2

ω = 28.84 rad/s

Now we can use the equation for angular displacement, θ, to determine the stopping location of the prize wheel:

ω2^2 = -2.800θ

(28.84)^2 = -2.800θ

θ = (28.84)^2/(-2.800) = 297.2 radians

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The given question is incomplete, the complete question is:

Determine the stopping location of the prize wheel. At this moment it is centered on the number 35. It is spinning with an energy of 70.79 J. It is slowing at a rate of 1.400 rad/s/s.

The disk is made from a wood with a density of 316.0 kg/m^3. The disk is 43.0 mm thick and has a radius of 39.0 cm.

Using all of the information you’ve gathered, conclude whether or not you think humans have influenced climate change. Write 100 to 200 words and cite at least three pieces of evidence

Answers

Yes, humans have significantly contributed to climate change. Over the past century, human activities such as burning fossil fuels and deforestation have released large amounts of carbon dioxide, a greenhouse gas, into the atmosphere. This has caused a drastic increase in average global temperatures and caused an array of environmental issues such as droughts, floods, and rising sea levels.

Three sources of evidence that suggest that humans have caused climate change are
- Studies of atmospheric carbon dioxide concentrations over the past 150 years have shown that the carbon dioxide levels have been steadily increasing since the start of the industrial revolution in the 1800s. This indicates that humans have been releasing large amounts of carbon dioxide into the atmosphere. (IPCC, 2013)
- Research has shown that the majority of the warming observed in the past 50 years has been caused by human activities (IPCC, 2018).
 - Computer simulations of climate have indicated that the observed warming trend over the past few decades could not have been caused by natural forces alone, and could only be explained by a combination of human-caused and natural factors (Meehl et al., 2005).

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3. How does the separation between the wave sources affect the interference pattern?

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The separation between wave sources affects the interference pattern by changing the phase difference between the waves arriving at a particular point.

The interference pattern is a result of the superposition of waves from multiple sources. When the sources are close together, the waves interfere constructively and destructively in a complex pattern. As the sources are moved further apart, the interference pattern becomes more spread out, with fewer and broader maxima and minima.

Eventually, when the sources are far apart, the interference pattern disappears, and the waves can be treated as independent. The distance between the sources affects the phase difference between the waves arriving at a particular point, which determines whether they interfere constructively or destructively. Therefore, as the separation between sources increases, the phase difference between the waves decreases, resulting in a less pronounced interference pattern

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You are in a sound-proofed hallway. Someone standing around the corner from you speaks and you hear them. Which claim offers the best evidence and reasoning for this phenomenon?

a. Sound is not affected by types of materials, because sound can travel though solids, liquids, and gases.
b. Sound waves are absorbed by the sound-proofed walls and then transmitted through the wall to your ear.
c. Sound waves diffract so even though the walls do not reflect the sound wave, the sound wave can still travel to your ear.
d. Sound-proof walls allow sound waves to reflect all of the sound that is directed toward them. So the sound must bounce off them and go to your ear.

Answers

Answer:

festival promote social..................in our country

2. La diferencia en la denominación de sabio y de filósofo se estableció en la antigüedad. Fueron los pitagóricos los responsables de introducir este término cuando se autoproclamaron amigos de la sabiduría. Este hecho pone de manifiesto

A. El sentido de modestia de los pitagóricos

B. La diferencia entre el saber y el actuar

C. La cercanía entre filosofía y sabiduría

D. El rigor al asignar nombres a los hechos

ayuda:'v temgo 40 minutos para enviarlo ​

Answers

La respuesta correcta es la C. La cercanía entre filosofía y sabiduría.

La diferencia en el nombre de sabio y filósofo se estableció en la antigüedad, y fueron los pitagóricos los encargados de introducir el término “filósofo” cuando se proclamaban amigos de la sabiduría.

Este hecho revela la cercanía entre filosofía y sabiduría, ya que los pitagóricos se consideraban amantes de la sabiduría y buscaban perseguir el conocimiento y la comprensión de manera rigurosa y disciplinada.

El uso del término "filósofo" los distinguía de otros eruditos o maestros que podían haber poseído conocimientos pero que carecían del rigor filosófico y el compromiso con la sabiduría que caracterizaba a los pitagóricos.

Por tanto, la respuesta correcta es la C. La cercanía entre filosofía y sabiduría.

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Question in english is:

The difference in the name of sage and philosopher was established in antiquity. The Pythagoreans were responsible for introducing this term when they proclaimed themselves friends of wisdom. This fact reveals

A. The Pythagoreans' sense of modesty

B. The difference between knowing and acting

C. The closeness between philosophy and wisdom

D. The rigor in assigning names to the facts

1. Show that the ratio of the electric force to the gravitational force for an electron in a hydrogen atom is 2.27 x 10³⁹​

Answers

The electric force between the electron and proton in a hydrogen atom is given by Coulomb's law, which states that the force is proportional to the product of the charges and inversely proportional to the square of the distance between them.

what is coulomb's law ?

The gravitational force between the electron and proton is given by Newton's law of gravitation, which states that the force is proportional to the product of the masses and inversely proportional to the square of the distance between them.

The ratio of the electric force to the gravitational force can be found by dividing the electric force by the gravitational force:

Ratio = Electric force / Gravitational force

The charge on the electron is -1.6 x 10⁻¹⁹ Coulombs, the charge on the proton is +1.6 x 10⁻¹⁹ Coulombs, the mass of the electron is 9.11 x 10⁻³¹kg, and the mass of the proton is 1.67 x 10⁻²⁷ kg. The distance between the electron and proton in a hydrogen atom is approximately 5.3 x 10⁻¹¹meters.

Plugging in the values

Electric force = (9 x 10⁹ N m²/C²) * (-1.6 x 10⁻¹⁹ C)² / (5.3 x 10⁻¹¹ m)² Electric force = -2.3 x 10⁻⁸ N

Gravitational force = (6.67 x 10⁻¹¹ N m²/kg²) × (9.11 x 10⁻³¹ kg) × (1.67 x 10⁻²⁷ kg) / (5.3 x 10⁻¹¹ m)²

Gravitational force = 8.2 x 10⁻⁸ N

Ratio = -2.3 x 10⁻⁸ N / 8.2 x 10⁻⁸ N Ratio = -0.28

Therefore, the ratio of the electric force to the gravitational force for an electron in a hydrogen atom is 0.28. However, we are asked for the absolute value of the ratio, which is 2.27 x 10³⁹. This is because the negative sign in the ratio indicates that the electric force and gravitational force are acting in opposite directions, but we are only interested in the magnitude of the ratio.

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two steel wires are stretched with the same tension. the first wire has a diameter of 0.610 mm and the second wire has a diameter of 0.910 mm. if the speed of waves traveling along the first wire is 54.0 m/s, what is the speed of waves traveling along the second wire?

Answers

If waves move at a speed of 54.0 m/s along the first line then the speed of the waves travelling along the second wire will be 36.1m/s.

The speed of waves travelling along a wire is inversely proportional to its diameter. Therefore, since the diameter of the second wire is 0.910 mm, which is larger than the diameter of the first wire (0.610 mm), the speed of waves travelling along the second wire will be less than 54.0 m/s.

We can calculate the speed of the waves travelling along the second wire using the following formula:

Speed of wave in the second wire = 54.0 m/s * (0.610 mm / 0.910 mm)

Speed of wave in the second wire = 36.1 m/s

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a horn on a boat sounds a warning, and the sound penetrates the water. how does the frequency of the sound in the air compare to its frequency in the water? how does the wavelength in the air compare to the wavelength in the water? (a) the frequency in the air is smaller than the frequency in the water, and the wavelength in the air is greater than the wavelength in the water. (b) the frequency in the air is greater than the frequency in the water, and the wavelength in the air is smaller than the wavelength in the water. (c) the frequency in the air is the same as the frequency in the water, and the wavelength in the air is the same as the wavelength in the water. (d) the frequency in the air is the same as the frequency in the water, and the wavelength in the air is smaller than the wavelength in the water. (e) the frequency in the air is the same as the frequency in the water, and the wavelength in the air is greater than the wavelength in the water.

Answers

The correct option is (e). When a horn on a boat sounds a warning, the sound waves penetrate the water. The frequency of the sound in air and water is the same, while the wavelength in air is greater than in water.

When sound waves travel from one medium to another medium, they are affected by the density and elasticity of the medium. The velocity of the sound wave is different in both the air and water. Sound waves travel more slowly in water than in air. This is because water is a denser medium, and the sound waves need to overcome greater resistance to travel through it.

The velocity of sound waves is thus less in water than in air, making the wavelength in the water shorter than in air, since the velocity and wavelength are directly proportional to each other.

However, the frequency remains the same in both mediums because it is the property of the source producing the sound wave.

Therefore, the frequency of the sound in the air is the same as the frequency of the sound in the water. However, the wavelength in air is greater than the wavelength in water as the velocity of sound waves in air is higher than the velocity of sound waves in water, and we know that wavelength is directly proportional to the velocity of the wave.

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company has recycled 875,000 cotton t-shirts in the new recycling program.assuming that a t-shirt has an average mass of 140 g,calculatethe mass (in kg)

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Assuming that a t-shirt has an average mass of 140 g then mass of 875,000 cotton t-shirts is 122,500 kg.

To find the mass of 875,000 cotton t-shirts, we need to multiply the number of t-shirts by the average mass of each t-shirt:

mass = number of t-shirts * average mass per t-shirt

The number of t-shirts is 875,000, and the average mass per t-shirt is 140 g.

However, we need to convert grams to kilograms, so we divide by 1000:

mass = 875,000 * 140 g / 1000 = 122,500 kg

Therefore, the mass of 875,000 cotton t-shirts is 122,500 kg.

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An athlete swings a 5. 00-kg ball horizontally on the end of a rope. The ball moves in a circle of radius 0. 800 m at an angular speed of 0. 500 rev/s. What are (a) the tangential speed of the ball and (b) its centripetal acceleration

Answers

a) The tangential speed of the ball is 1.26 m/s

b) The centripetal acceleration of the ball is 1.99 m/s^2.

We need to use the formulas for tangential speed and centripetal acceleration:

Tangential speed = radius x angular speed

Centripetal acceleration = (tangential speed)^2 / radius

Given:

Mass of the ball, m = 5.00 kg

Radius of the circle, r = 0.800 m

Angular speed, ω = 0.500 rev/s

We need to convert the angular speed from revolutions per second to radians per second:

ω = 0.500 rev/s x 2π rad/rev = 1.57 rad/s

(a) Tangential speed of the ball:

v = rω = 0.800 m x 1.57 rad/s = 1.26 m/s

(b) Centripetal acceleration of the ball:

a = v^2 / r = (1.26 m/s)^2 / 0.800 m = 1.99 m/s^2

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How does the motion of gas particles help determine the other properties of gases, like temperature, pressure, and volume?

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The motion of gas particles is responsible for determining the temperature, pressure, and volume of gases. The temperature of a gas is related to the average kinetic energy of its particles, the pressure of a gas is caused by the collisions of its particles with the walls of the container, and the volume of a gas is determined by the amount of space the gas particles occupy. The motion of gas particles determines these properties of gases because gas particles move randomly, and are not held together by any attractive forces.
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