The force particle b exerts on a is -2.72 N to the left.
The force particle b exerts on a can be determined by using Coulomb's law, which states that the force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
Since the charges of the particles are the same, we can assume that the force is proportional to the inverse of the distance squared. By increasing the distance between the particles from 13.0 mm to 18.5 mm, we can assume that the force has decreased.
Using the formula F = k(q1*q2)/r^2, we can calculate the new force by substituting the new distance and assuming the charges are equal. Since the force was 2.72 N to the right, and the distance has increased, the force particle b now exerts on a would-be -2.72 N to the left.
This is because the force is inversely proportional to the distance squared, and since the distance has increased the force has decreased.
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atoms join to form chemical groups called ______, which in turn join to form ______
Atoms join to form chemical groups called molecules, which in turn join to form compounds.
What are Molecules?A molecule is a group of two or more atoms that are chemically bonded together. The bonding is achieved through the sharing or exchange of electrons between the atoms. The atoms in a molecule can be the same or different elements and can be arranged in various ways to form different types of molecules.
Molecules can be either simple or complex, depending on the number of atoms and the types of chemical bonds that hold the atoms together. Simple molecules, such as H2 and O2, are composed of only a few atoms, while complex molecules, such as proteins and DNA, can contain hundreds or even thousands of atoms.
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A ball freely falling at 20 m/s will in the next second have a speed of ______. 30 m/s. What two units of measurement are necessary for describing speed?
Two units of measurement are necessary to describe the speed, are meter and second.
Speed of an object is nothing but the distance travelled by the object in unit time. A freely falling ball experience the acceleration due to gravity in the downward direction. The value of acceleration due to gravity of the earth is roughly taken as 10 m/s². If the initial speed is 20 m/s. and Time, t = 1 sec. Then speed in the next second will be v = u + at
v = 20 + 10 × 1
v = 30 m/s
Meter is the SI unit of length or distance and second is the SI unit of time.
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Two balls of unequal mass traveling at different speeds collide head-on and rebound in opposite
directions.
1) How does the force that ball A exerts on ball B compare to the force that ball B exerts on ball A?
2) How do the impulses received by both balls compare?
3) How do the sums of the momenta of the balls before and after the collision compare?
Can someone please answers these for me i need help.
Answer: 3
Explanation: i think
for each of the following cases, indicate whether the work done is positive or negative. explain your answers. a) work done by an applied force in lifting a bucket of water upward. fa mg b) work done by the weight of the bucket c) work done by the applied force and mg if the bucket were lowered.
The work done in case a) is positive, in case b) is negative and in case c) is positive.
Work is said to be done when the displacement is occur in the direction of the applied force.
W = F×d×cosθ
Where F is the force, d is the displacement and θ is the angle between the displacement and the direction of the force.
In case a) as the work is done against the direction of the gravity so the work is positive. In case b) the weight of the buckets acts in downwards direction, that is the direction of the acceleration due to gravity. So the work is negative. In case c) the bucket were lowered, it means the displacement is in the direction of the applied force. Hence the work done is positive.
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Sc 1.1 Two forces act on an object. The first is a horizontal 50 N force. The second is a 40 N force acting at an angle to the horizontal. Use a graphical method drawn to a scale of 1 mm : 1 N to find the resultant if the 40 N force is inclined at: 1.1.1 30° to the horizontal 1.1.2 60° to the horizontal.
1.1.1: The force, which is 61.4 N and inclined at a 34.4° angle to the horizontal,
1.1.2: The resultant force is 30.8° inclined to the horizontal and is 66.9 N in magnitude.
How does vector addition work?
The process of adding vectors together to determine the resulting force is known as vector addition.
Vector addition is the theory that was applied in this question
The steps involved in adding vectors are as follows:
First, use the two provided vectors and the resulting vector to scale up a vector diagram.
Step 2: Apply the Pythagorean theorem to determine the magnitude of each vector.
Calculate each vector's angle with respect to the horizontal in step three.
4th step: Apply the Use the law of cosines to find the magnitude of the resultant vector
Step 5: Use the law of sines to find the angle of the resultant vector with respect to the horizontal.
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a boat can move at 30 km/h in still water. how long will it take to move 12 km upstream in a river flowing 6.0 km/h?
A boat can move at 30 km/h in still water, so to move 12 km upstream in a river flowing 6.0 km/h, it will take 20 minutes.
Water is referred to as still water when its motion is zero, or when it is still. Motionless water is defined as water that remains still, not flowing, and has no current, such as in rivers and streams. Therefore, a boat's relative speed on calm water is equal to 12 (a + b) km/hr. The stream is moving at a pace of 1/2 (a - b) km/hr.
Moving upstream, or against the flow of water, refers to a boat going against the current. The distinction when speaking about water in rivers and streams is that upstream is in opposition to the water flow and in the direction of the water's original source (where the river originates).
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what is the magnitude of the force exerted by the biceps fbiceps ? what is the magnitude of the force exerted by the elbow felbow ? express your answers in newtons separated by a comma.
The force exerted by the biceps and the elbow is 239.9 N and 215.89 N respectively.
When we use only your forearms to lift an object, assume that your biceps are the main muscle that lifts your arm. Suppose the weight of the forearm he is 1.50 kg. If the biceps is attached to the forearm 2.50cm from the elbow, with the forearm parallel to the floor, flex the biceps to hold a 950g ball on the end of the elbow at a distance of 36.0cm from the elbow.
Against this background,
forearm mass = 1.50 kg
forearm length = 2.50 cm
The weight of the ball is 950 g.
36.0 cm ball spacing
Forearm strength needs to be calculated. Balance Elbow Using
Torque,
Fb x Db = Wf x Df/2 + Wball x Dball
Putting Value,
Fb x .025 = 1.5 x 9.8 x .36/2 + 0
95 x 9.8 x 0.36
Fb = 239.9 N
Now elbow force,
Fb = Fl + Wf + Wb
Fl = Fb - Wf - Wb
Putting value,
Fl = 239 .9 - (1.5 x 9.8 ) - (0.95×9.8)
Fl = 215.89 N.
Therefore the force on the elbow is 215.89 N.
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nitrogen is contained in a 5-m3 rigid vessel at a pressure of 2200 kpa. (a) determine the mass if the temperature is 25oc. (b) determine the mass if the temperature is 250oc. (c) what would be the height of a column of mercury (in mm) in a manometer for this pressure? the density for mercury is 13600 kg/m3.
Barometric column, barometer column, etc. mercury barometer: a device that uses a mercury column to measure the height of the column (in inches of mercury) to determine atmospheric pressure.
How tall a column does a mercury have vertically?As a result, less than 76 cm of mercury can be held vertically in space by a basic barometer at sea level.Indicators of atmospheric pressure include the mercury column's height. The mercury column rises to a height of roughly 30 inches (76 centimeters) at sea level at a temperature of 0 degrees Celsius (C). This is equivalent to about 14.7 psia of pressure.Ytop minus YBot in HcolumnBarometric column, barometer column, etc. mercury barometer: a device that uses a mercury column to measure the height of the column (in inches of mercury) to determine atmospheric pressure.To learn more about Barometric column refer to:
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CAR A is travelling at 27 meters/second and is following closely behind CARB at a distance of 9 meters. The driver of CAR A
has a reaction time of 0. 5 seconds (the time it takes between seeing the brake lights of CAR B flash and the driver of CARA
hitting the brake).
How far will his car travel during the reaction time?
Will the driver of CAR A hit the driver of CAR B during the time it takes the driver of CAR A to react?
How do you know? Explain your evidence, reasoning, and any calculations you may have performed.
The car A will hit the car B during the reaction time of 0.5 seconds, and the distance the car will travel during the reaction time is 13.5 meters.
Reaction time is the time taken by the driver between seeing the scenario in front of his/her eye and the instant of applying the break. It is derived by the PIEV theory. The PIEV theory includes the time durations which drivers see, recognize, analyze and react to apply the brake for avoiding objects on the roads. The PIEV time on highway design engineering is taken as 2.5 seconds.
Given the speed of the car A is 27 m/s
Reaction time = 0.5 sec
Distance travelled, d = 27 × 0.5 = 13.5 meters
As the distance travelled by the car A is more than the distance between car A and car B, so the car will surely hit the car B.
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An object starts from rest and accelerates uniformly in a straight line in the positive x direction.
After 11 seconds, its speed is 70.0 m/s.
a. Determine the acceleration of the object.
b. How far does the object travel during the first 11 seconds?
c. What is the average velocity of the object during the first 11 seconds?
d. The object continues to accelerate with the acceleration computed in 1.a. for another 5 seconds. Determine the final velocity at this time.
e. What was the objects displacement at this time?
a. The acceleration of the object is calculated to be 6.36 m/s².
b. During the first 11 seconds, the object travels 385 m.
c. The average velocity of the object during the first 11 seconds is 70 m/s.
d. The final velocity is 31.8 m/s.
e. The object's displacement at this time is 79.5 m.
Speed of the object = 70 m/s
Time = 11 sec
The acceleration of the object is described to be the rate of change of speed.
So, acceleration = 70/11= 6.36 m/s²
From the equations of motion, we know, s = ut + 1/2 a t²
As, u = 0 here, s = 1/2 a t²
s = 1/2 (70/11) 11² = 385 m
The following formula is used to determine the object's initial displacement,
s₀ = ut
s₀ = 0
After the first 11 seconds, the object's displacement is determined as follows,
s₁ = v t
s₁ = 70 × 11 = 770 m
The object's average velocity is computed as follows:
v = (s₁ - s₀)/t = (770-0)/11 = 70 m/s
Hence, the average velocity of the object is 70 m/s.
Relation between initial, final velocity, acceleration is
v = u + a t
v = 0 + 6.36 × 5 = 31.8 m/s
To find displacement, let us use the equation, v² - u² = 2 a s
Making s as subject, we have, s = (v² - u²)/2 a = (31.8² - 0)/(2 × 6.36) = 79.5 m
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Does the frequency distribution appear to have a normal distribution using a strict interpretation of the relevant​ criteria?
No, it doesn't seem like the distribution is normal. A data set must (when graphed) follow a bell-shaped, symmetrical curve that is centered around the mean in order to be regarded as having a normal distribution.
The best way to determine whether a frequency distribution looks to have a normal distribution is to look at a histogram. Plot a histogram and study the bar shapes. The distribution is generally regularly distributed if the bars have the shape of a bell or a hill, as in the figure below. A theoretical continuous, symmetrical bell-shaped distribution function represents a normal frequency distribution. The bell curve's mean, mode, and median are all the same, and both of its tails are indefinitely long.
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complete question: Does the frequency distribution appear to have a normal distribution using a strict interpretation of the relevant criteria. Temperature (degreesF) 35 - 39, 40 - 44, 45 - 49, 50 - 54, 55 - 59, 60 - 64, 65 - 9 frequency 3, 0, 6, 12, 8, 6, 1.
(a) No, the distribution does not appear to be normal.
(b) Yes, all the requirements are met.
(c) No, the frequencies do not decrease from the maximum frequency to a low frequency.
A bob of mass m is suspended from a fixed point with a massless string of length L (i. E. , it is a pendulum). You are to investigate the motion in which the string moves in a cone with half-angle θ. What tangential speed, v, must the bob have so that it moves in a horizontal circle with the string always maintaining an angle θ from the vertical? Express your answer in terms of some or all of the variables m, L, and θ and the acceleration due to gravity, g
The tangential speed, v, must the bob have so that it moves in a horizontal circle with the string always maintaining an angle θ from the vertical is √mgLsinθtanθ.
Given the mass of bob = m
length of string = L
The angle the string of pendulum makes with cone = θ
The tangential speed the bob moves = v
the vertical component of tension must support the weight of the bob which is represented as: Tcosθ = mg where g is acceleration due to gravity.
the horizontal component of tension must equal the centripetal force acting on the bob which is: Tsinθ = v^2/r where r is the radius of orbit.
However, we know that, r = Lsin(θ) then Tsinθ = v^2/Lsin(θ)
Then Tsinθ/Tcosθ = v^2/(mg x Lsin(θ))
tanθ = v^2/mgLsinθ
then v = √mgLsinθtanθ
Hence the tangential speed the bob moves with is √mgLsinθtanθ
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Please help me by 8:30 thank you!!
The statement which correctly describes the all of these given blood cell types is option C. They perform functions that air in maintaining homeostasis.
What is homeostasis ?Any self-regulating mechanism called homeostasis helps biological systems to maintain stability while responding to environmental factors that are best for survival. If homeostasis is achieved, life goes on; if it is not, catastrophe or death result.
The stability obtained is actually a dynamic equilibrium, where circumstances are mostly uniform yet change is constant. All the bodily systems must be in a condition of equilibrium for the body to live and work properly.
When the body is in homeostasis, its levels of acid, blood pressure, blood sugar, electrolytes, energy, hormones, oxygen, proteins, and temperature are maintained at a normal level by being continually adjusted in response to changes both inside and outside the body. Hence, option C is correct.
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A 68.5 kg rocket is to be launched upwards with an acceleration of 3.65 m/s^2. What is the size of the gravitational force acting on the rocket?
Answer:
671,3 Newtons
Explanation:
Fg=mass×g
1. Mr. Gewanter, whose mass is 60 kg, is doing a physics demonstration in the front of the classroom.
A. How much gravitational force does he exert on 55 kg Martha in the front row, 1.5 m away?
B. How much force does he exert on 65 kg Lester in the back row, 4.0 m away?
2. A 400 kg weather satellite is about to launched into orbit.
A. When the satellite is still on Earth, what is the gravitational force on it? (The mass of the Earth is 5.98x1024 kg and the radius of the Earth is 6.37x106 m)
B. What radius of orbit does the satellite need to experience half this force?
By performing a physics demonstration in front of the students. F is 9.79 x 108 newtons.
Given,
Mr. Gewanter weighs 60 kilograms (kg).
The weight of Martha is 55 kg.
d = 1.5 meters separates them.
The equation F = GMm/d2 newton determines the gravitational force between them.
changing the given values in the equation above
F = (6.673 x 1011 x 60 x 55)/1.52 = 9.79 x 108 newtons.
As a result, F = 9.79 x 108 newton is the gravitational pull Mr. Gewanter has on Martha.
A geostationary satellite travels in a circular path around the planet with a 36,000 km radius. The orbital period of a spy satellite will then be roughly (Re = 6400 km), orbiting a few hundred kilometers above the surface of the planet.
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Cathode ray tubes (CRTs) used in old-style televisions have been replaced by modern LCD and LED screens. Part of the CRT included a set of accelerating plates separated by a distance of about 1. 40 cm. If the potential difference across the plates was 28. 5 kV, find the magnitude of the electric field (in V/m) in the region between the plates
The magnitude of the electric field (in V/m) in the region between the plates is 20.35x10^5V/m.
Given the distance between the plates (d) = 1.4cm = 1.4x10^-2m
The potential difference across the plates is (V) = 28.5kV = 28.5x10^3V
The electric field between two parallel conducting plates is dependent on the voltage or potential difference between the two plates as well as their separation from one another. The two charged parallel plates would carry their total charges since an electric insulator separates them. Because the two parallel charged plates are kept apart from one another, a homogenous electric field is created there.
According to Coulombs law E = V/d such that
E = 28.5x10^3V/1.4x10^-2m = 20.35x10^5V/m
Hence the required magnitude of the electric field is 20.35x10^5V/m
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the visual phenomenon whereby an elongated object protruding toward or away from a viewer appears shorter than its actual length, as though compressed, is known as:
The visual phenomenon in which an elongated object moving towards or away from the viewer appears compressed and shorter than its actual length is called linear perspective.
Linear perspective is based on a fixed point of view. A visual phenomenon in which an elongated object projected toward or away from the viewer appears to be compressed shorter than it actually is. Linear perspective is a system that creates the illusion of depth on a flat surface. All parallel (perpendicular) lines in a painting or drawing using this system converge at a single vanishing point on the horizontal line of the composition. An example of linear perspective is the obvious convergence of two parallel lines, especially when viewing a long two-lane highway.
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you are traveling west on the highway. At 1:00 you pass kilometer marker 485. At 4:30 you pass kilometer marker 154. What has your average velocity been.
Technically a question for physical science but i didn't know what to label it.
Your average velocity for the journey has been 94.57 km/h.
What is the average velocity of an object?The average velocity of an object is the ratio of total displacement to the total time of motion of an object.
V = ( total displacement ) / ( total time )
The total displacement of your journey is calculated as;
x = 485 km - 154 km
x = 331 km
The total time of the motion is calculated as;
t = 4:30 - 1:00 = 3:30 = 3.5 hours
v = x / t
v = ( 331 km ) / ( 3.5 hr )
v = 94.57 km/h
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4. 77 Augment the rectifier circuit of Problem 4. 70 with a capacitor chosen to provide a peak-to-peak ripple voltage of (i) 10% of the peak output and (ii) 1% of the peak output. In each case: (a) What average output voltage results? (b) What fraction of the cycle does the diode conduct? (c) What is the average diode current? (d) What is the peak diode current?
You may calculate the average load current—the average diode current—by dividing the average load voltage by the average load resistance.
What is the diode's typical forward current?Vavg = 15.45 V
Diode conduction is 7.11 percent.
Iavg = 0.232 A
Ip = 0.449 A
Case (ii) (ii)
Vavg = 16.18 V
Diode conduction is 2.25 percent.
Iavg = 0.735 A
Ip = 1.453 A
The transformer's secondary side has a voltage of
= Vpri/turn ratio
Vrms = 120/10 = 12 V
Peak voltage and rms voltage have the following relationship:
Vp = Vrms / 2.
Vp = 12√2 = 16.97 V
Vd = 0.7 V
We will first determine all the necessary variables for the ripple voltage of 10%, and then for the ripple voltage of 1%.
10% of the highest output in scenario I
What average output voltage is produced?
Vavg = Vp - Vd - 0.5Vr is the average output voltage.
Vp is the maximum output voltage.
Diode voltage drop is denoted by Vd, while ripple voltage is denoted by Vr, which is expressed as a percentage of Vp.
Vavg = 0.5Vr + Vp - Vd
Vavg = 16.97 - 0.7 - 0.5[0.1(16.97 - 0.7)]
Vavg = 15.45 V
(b) The diode conducts what percentage of the cycle?
= Vd - 2Vr/Vp
Vp- Vd = 2*0.1 (Vp-Vd)/Vp
ω = √2*0.1(16.97-0.7)/16.97 - 0.7
ω = 0.447 rad
Diode conductance equals (/2)*100
Diode conductance is (0.447/2)*100
Diode conduction is 7.11 percent.
The typical diode current is (c).
Iavg = Vavg/R[1 + (2(Vp - Vd)/0.1(Vp-Vd))] is the formula for average current.
Average current is equal to Iavg, which is 15.45/1000[1 + (2(16.97 - 0.7)/0.1(16.97-0.7)]
Iavg, or average current, is 0.232 A.
(d) How much diode current peaks at?
Peak current is defined as Ip = Vavg/R[1 + 2(2(Vp - Vd)/0.1(Vp-Vd)]
Peak current is expressed as Ip = 15.45/1000[1 + 2](2(16.97 - 0.7)/0.1(16.97-0.7)]
Peak current is 0.449 A, or Ip.
What average output voltage is produced?
Vavg = 16.97 - 0.7 - 0.5[0.01(16.97 - 0.7)]
Vavg = 16.18 V
(b) The diode conducts what percentage of the cycle?
Vp - Vd = 2*0.01(Vp-Vd)
ω = √2*0.01(16.97-0.7)/16.97 - 0.7
ω = 0.1417 rad
Diode conductance is (0.1417/2)*100
Diode conduction is 2.25 percent.
The typical diode current is (c).
Average current is equal to Iavg, which is 16.18/1000[1 + (2(16.97 - 0.7)/0.01(16.97-0.7)]].
Average current is 0.735 A (Iavg).
(d) How much diode current peaks at?
Peak current is expressed as Ip = 16.18/1000[1 + 2](2(16.97 - 0.7)/0.01(16.97-0.7)]
Peak current is 1.453 A, or Ip.
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an airplane starts from a brakes locked position and accelerates down the runway at 11 ft/s2. it reaches takeoff airspeed at 275 ft/s. what is the time for the airplane to reach takeoff speed?
The aircraft takes off from the runway with its brakes locked. At such a speed of 200 fps, the aircraft takes off. Find out when the plane will arrive.
How quickly do airplanes take off and land?
The ground run can be a little bit longer if a decreased power takeoff is being performed. Prior to takeoff, a typical commercial aircraft accelerates to a speed of 120–140 knots. It will need a strong sustained acceleration to complete it in 30 to 35 seconds. Pilots watch for this as they roll out for takeoff.
What is the total vertical force acting on the aircraft when it takes off?
When a result, there is no net vertical force acting on the aircraft as it takes off. When a result, there is no net vertical force acting on the aircraft as it takes off. The net vertical force acting on the aircraft as it ascends is therefore 65000 Newton.
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the coriolis effect describes the . multiple choice question. wobble of air masses resulting from a titled earth apparent deflection from straight-line movement of air and water masses condensation of water vapor on rotating aerosols expansion of air and water masses due to heating and cooling
The Coriolis effect describes the deflection pattern experienced by an object that is not firmly anchored to the ground as it travels long distances around the Earth. Many large-scale weather patterns are caused by the Coriolis effect.
The rotation of the Earth is important for the Coriolis effect. In particular, the Earth rotates faster at the equator than at the poles. Because the Earth is wider at the equator, the equatorial region must travel about 1,000 kilometers (1,000 miles) per hour to make one revolution of her in 24 hours. The Earth rotates slowly near the poles at 0.00008 kilometers (0.00005 miles) per hour. If you play catch anywhere in the northern hemisphere, the ball will curve to the right.
Apparent deflection is due to the Coriolis effect.
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maximum current problem. if the current on your power supply exceeds 500 ma it can damage the supply. suppose the supply is set for 37 v. what is the smallest resistance you can measure? please write your answer with integer value.
The smallest value of resistance that we can measure is 74 Ω(ohm), if the maximum power supply is 500 ma and the supply voltage is 37 V.
According to Ohm's law, the current in a conductor is directly proportional to the potential difference between its two ends. In other words, the ratio of the potential difference(V) and the electric current(I) is a constant in a conductor. This constant is called "resistance(R)". its unit is Ω(ohm). Mathematically,
V = IR
R = V/I
The maximum current, I = 500 ma = 500 × 10⁻³ A
Voltage supply, V = 37 Volts
R = 37/ (500 × 10⁻³) = 74 Ω
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50) at the taking of a direct free kick, the ball accidentally bounces off the referee and enters the goal. what decision should the referee make?
A dropped ball is given if the ball hits the referee or another match official and goes into the goal, team possession changes, or a potential attack or a promising offensive begins.
The note of the following additional modifications to the dropped ball procedure The ball will be dropped for the goalie if play is stopped inside the penalty area. If the game is stopped outside of the penalty area, one player from the team that last touched the ball at the last touch will receive the ball. All other players from both teams must always be at least 4 metres or 4.5 yards away.
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jason drives due west with a speed of 35.0 mi/hr for 30.0 min, continues in the same direction with a speed if 60.0 mi/h for 2.00 h, and then drives still farther west at 25.0 mi/h for 10 min. what is jason's average velocity for the entire trip? (units of mi/h)\
The average velocity is 47.96 mi/h with which Jason can drive
on average.
Well, there are many ways to calculate the average velocity, but the most complete one would be the following.
With the equations of Uniform Rectelinear Movement we can obtain the distance Jason has driven. We will use the same equation for each step.
where x is the position, is the initial position (which we can pick as zero to simplify), v is the velocity, t is time and is the initial time (also picked as zero). In order to get the right answer we must use the same units, so we will change the minutes to hours, where 30 minutes are half an hour and 12 minutes are 0.2 hours
So, the distance will be Now that we have the partial distances, we use the formula for average velocity which is where is the final position (the sum of the distances) and is the total time Jason took.
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a teacher sends her students on a treasure hunt. she gives the following instructions: 1. walk 300 m north 2. walk 400 m northwest 3. walk 700 m east-southeast and the treasure is buried there. as all the other students walk off following the instructions, joe physics student quickly adds the displacements and walks in a straight line to find the treasure. how far and in what direction does joe need to walk?
The directions she gives are as follows: 1. Move 400 meters to the northwest. 3. The wealth is hidden there, 700 meters to the east-southeast.
What is a displacement example?Change inside an object's position in relation to a reference frame is known as displacement. For instance, a billiards ball moves of one spot to another when one player strikes it. It is alleged to have moved. A vector quantity with both size and direction is displacement.
What is another name for displacement?The spacing between two specified points is represented by the one-dimensional quantity of displacement (symbolized as d or s), commonly known as length or distance. The meter serves as the standard displacement unit in the International Unit System (SI) (m).
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A force of 45 n is exerted on an object, resulting in an acceleration of 5 m/s² for the object. what will the object's acceleration be if the force doubles? question 9 options: a. 2.5 m/s² b. 5 m/s² c. 10 m/s² d. 20 m/s²
Answer:
Option C. 10 m/s²
Explanation:
First we need to find the mass of the object.
We can use Newton's second law to evaluate the mass of the object.
Newton's second law says that the net force of is equal to the mass times it acceleration.
[tex]F_{net} =ma[/tex]
Lets solve for [tex]m[/tex].
Divide each side by [tex]a[/tex].
[tex]m=\frac{F_{net} }{a}[/tex]
We are given
[tex]F_{net} =45\\a=5[/tex]
Lets evaluate [tex]m[/tex].
[tex]m=\frac{45}{5}[/tex]
[tex]m=9[/tex]
Now we can find the object's acceleration if the force doubles.
[tex]F_{net} =ma[/tex]
Lets solve for [tex]a[/tex].
Divide each side by [tex]m[/tex].
[tex]a=\frac{F_{net} }{m}[/tex]
Doubling the force of 45 N leaves us with a force of 90 N.
[tex]a=\frac{90}{9}[/tex]
[tex]a=10[/tex]
We can see that the object's acceleration is directly proportional to the net force and inversely proportional to the object's mass.
these fringe shifts occur because the wavelength of the light changes inside the gas filled tube. assume that 502 nm light is used, the tube is 3.99 cm long, and that 221 fringe shifts occur as the pressure of the gas in the tube increases to atmospheric pressure. calculate ngas, the index of refraction of the gas
The index of refraction of gas will be 1.008 units.
What is index of refraction?Because of their low density, gases at atmospheric pressure have refractive indices close to one.The refractive index, also known as the index of refraction, is a measurement of the bending of a light ray as it passes through one medium and into another.The number of wavelengths originally in the cylinder is m1 = 2L/λ when light is counted in both directions.
It transforms into m2 = 2L/λ/n gas.
= 2ngasL/λ
As the cylinder is filled with gas,
If N is the number of bright fringes passing,
N = m2 - m1
= 2L/λ (ngas - 1) or,
The index of refraction of the gas is,
ngas =1 + Nλ/2L = 1+ (221)(502 x 10⁻⁹ m)/2(3.99 x 10⁻²)
= 1.008 units
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let the sign of q2 be changed from positive to negative. at which position can the point charge q be placed now so that the net electrostatic force on it is zero?
The position of the point charge q can be placed such that the net electrostatic force is -1.857 m.
To find the position where the net electrostatic force on the charge q is zero, we need to apply Coulomb's Law. Coulomb's law states that the electrostatic force between two charges is proportional to the product of the charges and inversely proportional to the square of the charges. distance between them.
In this case, we have two charges Q1 and Q2 at known positions and we need to find the position of the third charge q such that the net force is zero.
By equating the force due to Q1 with the force due to Q2, we can solve for the position of q. Changing the sign of Q2 changes the direction of the force on q and changes the position of q.
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The question is -
An electric point charge of Q1 = 7.43 nC is placed at the origin of the real axis. Another point charge of Q2 = 1.21 nC is placed at a position of p = 3.95 m on the real axis. At which position can a third point charge of q = -1.99 nC be placed so that the net electrostatic force on it is zero? Let the sign of Q2 be changed from positive to negative. At which position can the point charge q be placed now so that the net electrostatic force on it is zero?
Calculate the height gained by a 2kg mass has 100J of gravitational energy is transferred to it. (g=10N/kg)
Answer:
The mass has gained a height of 5 meters.
Explanation:
To calculate the height gained by a 2kg mass when 100J of gravitational energy is transferred to it, we can use the equation:Height (h) = Gravitational Potential Energy (GPE) / Weight (w)where GPE = mgh (mass x acceleration due to gravity x height)Therefore,h = (100 J) / (2 kg x 10 N/kg)h = 5 metersThe mass has gained a height of 5 meters.
a 90-kg fullback, running at 5.0 m/s attempts to dive across the goal line for a touchdown. just as he reaches the goal line, he is met head-on in midair by two 73-kg linebackers, one moving at 3.0 m/s and the other at 4.0 m/s. if they all become entangled as one mass, with what velocity do they travel?
The final velocity of the combined mass of the fullback and the two linebackers is 4.09 m/s.
To find the velocity of the combined mass of the fullback and the two linebackers, we need to use the principle of conservation of momentum. This principle states that the total momentum of an isolated system remains constant if no external forces act on it.
First, we need to find the initial momentum of the fullback by multiplying his mass (90 kg) by his velocity (5.0 m/s):
Initial momentum of fullback = 90 kg * 5.0 m/s = 450 kg m/s
Next, we need to find the initial momentum of the two linebackers by multiplying each of their masses by their velocities:
Initial momentum of first linebacker = 73 kg * 3.0 m/s = 219 kg m/s
Initial momentum of second linebacker = 73 kg * 4.0 m/s = 292 kg m/s
Now, we need to add the initial momentum of the three individuals to find the total initial momentum:
Total initial momentum = 450 kg m/s + 219 kg m/s + 292 kg m/s = 961 kg m/s
Since the final velocity of the combined mass is going to be the same as the initial momentum, we can say:
Final velocity = 961 kg m/s / (90 kg + 73 kg + 73 kg) = 961 kg m/s / 236 kg = 4.09 m/s
Therefore, the final velocity of the combined mass of the fullback and the two linebackers is 4.09 m/s.
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