The software engineers can be seated on a round table with no two civil engineers sitting together is 9!×10!/4!
Given, a company has 10 software engineers and 6 civil engineers.
we need to determine in how many ways can they be seated around a round table so that no two civil engineers will sit together.
10 software engineers can be arranged around a round table in :
=(10-1)!
= 9! ways .... eq(A)
Now, we must arrange the civil engineers so that no two can sit next to one another. In other words, we can place 6 civil engineers in any of the 10 *-designated roles listed below.
This can be done in ¹⁰P₆ ways ...(B)
From A and B,
required number of ways = 9!×¹⁰P₆
= 9! × 10!/4!
Hence the number of ways the engineers can be seated is 9! × 10!/4!.
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Nora has a job where she has a take home salary each month of $2400. if Nora wants to spend no more than 15% of her monthly take home salary on her car payment, how much can she afford?
Her take home salary is $2400 and she wants to spend no more than 15% on her car payment. Therefore, she can afford no more than 0.15*2400 = $360 on her car payment.
The perimeter of the rectangle is 19.4 centimeters.What is the width in centimeters,of the rectangle Length is 6cm
SOLUTION
From the question, the Perimeter of the rectangle is 19.4 cm and we want to find the width. The perimeter of a rectangle is given by
[tex]\begin{gathered} P=2\left(l+w\right) \\ where\text{ P =perimeter = 19.4} \\ l=length\text{ of rectangle = 6 cm} \\ w=width=? \end{gathered}[/tex]Applying this, we have
[tex]\begin{gathered} P=2\left(l+w\right) \\ 19.4=2\left(6+w\right) \\ 19.4=12+2w \\ 2w=19.4-12 \\ 2w=7.4 \\ w=\frac{7.4}{2} \\ w=3.7 \end{gathered}[/tex]Hence the width is 3.7 cm, option C
In the diagram below, GD = 10.1,EF 28.1, and EG 16.9. Find the length==of FC. Round your answer to the nearest tenthif necessary.
Solution:
In the figure;
[tex]\begin{gathered} \frac{EG}{EF}=\frac{ED}{EC} \\ \\ EG=16.9,ED=27,EF=28.1 \end{gathered}[/tex]Thus;
[tex]\begin{gathered} \frac{16.9}{28.1}=\frac{27}{EC} \\ \\ EC=44.9 \end{gathered}[/tex]Thus;
[tex]\begin{gathered} FC=EC-EF \\ \\ FC=44.9-28.1 \\ \\ FC=16.8 \end{gathered}[/tex]the double number line shows the price of one cupcake complete the table and show the same information as a double number line 5 to blank blank to 18 and 18 to blank
From the first diagram shown, we can see that 1 cupcake costs $1.5
To get the price of 5 cupcakes
Since 1cupcake = $1.5
5 cupcakes = $x
cross multiply
1 * x = 5 * 1.5
x = $7.5
Hence 5 cupcakes will cost $7.5
Since 1cupcake = $1.5
18 cupcakes = $x
cross multiply
1 * x = 18 * 1.5
x = $27
Hence 5 cupcakes will cost $27
To get the number of cupcakes priced $18
Since 1cupcake = $1.5
x cupcake = $18
1.5x = 18
divide both sides by 1.5
1.5x/1.5 = 18/1.5
x =
Irlene has just returned from a business trip in Britain with £200 of uncashed traveller's cheques. How much would she receive from the bank when she converts the currency back to Canadian dollars, assuming that the bank offers an exchange rate of C$1.00 = £0.5544 and charges a 0.65% fee to convert the traveller's cheques to Canadian funds? For full marks your answer(s) should be rounded to the nearest cent.
The converted money in Canadian dollars is $111.6.
Given that, Irlene has just returned from a business trip in Britain with £200 of uncashed traveler's cheques.
What is an equation?In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.
Let the converted Canadian dollars be x.
x = 200 × 0.5544 + 0.65% of 200 × 0.5544
= 110.88 + 0.0065 × 110.88
= 111.60072
≈ 111.6
Therefore, the converted money in Canadian dollars is $111.6.
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3.2 x 104 bacteria are measured to be in a dirt sample that weighs 1 gram. Usescientific notation to express the number of bacteria that would be in a sampleweighing 21 grams.
The number of bacteria that weighs 1 gram are,
[tex]3.2\times10^4[/tex]Determine the number of bacteria in a sample that weighs 21 grams.
[tex]\begin{gathered} 21\cdot3.2\times10^4=67.2\times10^4 \\ =6.72\times10^5 \end{gathered}[/tex]So answer is,
[tex]6.72\times10^5[/tex]Hi, can you help me answer this question please, thank you!
1. Test statistic:
To find the test statistic, we use the formula:
[tex]\begin{gathered} Z=\frac{\bar{X_d}-\mu_d}{\frac{s_d}{\sqrt[]{n}}} \\ \text{where,} \\ \bar{X}_d=sample\text{ difference} \\ \mu_d=\text{population difference} \\ s_d=\text{standard deviation of the differences } \\ n=\text{ number of people in the survey.} \\ \\ \text{ We use Z statistic because the number of people are more than 30} \end{gathered}[/tex]Solving for Z, we have:
[tex]\begin{gathered} \bar{X}-\mu_d=3.1\text{ (Average difference given in the question)} \\ \\ \therefore Z=\frac{3.1}{\frac{13.8}{\sqrt[]{40}}}=1.4207\approx1.421\text{ (To 3 decimal places} \end{gathered}[/tex]Thus, the test statistic is 1.421
2. P-value:
To find the p-value, we check the Z-distribution table.
The value for the p-value is
[tex]2\times0.077658=0.15532\approx0.1553\text{ (To 4 decimal places)}[/tex](We multiply by 2 because it is a two-tailed test.
3. Comparison:
The alpha level is 0.001.
Thus, the p-value is greater than the alpha level
Bryce drew a rectangle and labeled five of the angles, as shown. He knew these factsWHOabout the angles:• The measurements of angles 1 and 3 are the same.The measurement of angle 2 equals 110°.• The measurements of angles 3 and 5 are the same.Part A Based on these facts, what is the sum of the measurements of angle 1and angle 2? Show your work or explain your answer.Part B What is the measurement of angle 4? Show your work or explain your answer.
The given figure is;
It is given that :
The measurements of angles 1 and 3 are the same.
The measurement of angle 2 equals 110°.
PART A:
Since, angle 1 , 2 and 3 are lie at the same point on the same line
Thus, from the property of angle on a line
Sum of all angles on a strainght line at a point is equal to 180 degree
thus;
Angle1 + Angle2 + Angle 3 = 180
Angle 1 + Angle 2 + Angle1 = 180 {Angle1 = Angle 3, given}
2(Angle 1) + Angle 2 = 180
2 (angle 1) + 110 = 180 {Angle 2 = 110, given}
2(Angle 1) = 180 -110
2(Angle 1) = 70
Angle 1 = 70/2
Angle 1 = 35
Since, angle 2 = 110
The sum of angle 1 and 2 is 110 + 35
Sum of angle 1 and 2 = 145
PART B:
From the properties of the rectangle;
All the angles of a rectangle are 90°
In the given rectangle;
Thus, in the triangle form by the angle3, 4 and the right angle
Sum of all angles in a triangle is equal to 180
Angle 3 + Angle 4 + 90 = 180
35 + Angle 4 + 90 = 180
Angle 4 + 125 = 180
Angle 4 = 180 - 125
Angle 4 = 55
.....
What is the factorization of496^4-9
The given expression is
[tex]496^4-9[/tex]To factorize this, we find the square root of each term.
[tex]\begin{gathered} \sqrt[]{496^4}=496^2 \\ \sqrt[]{9}=3 \end{gathered}[/tex]Then, we use the difference of perfect square which states
[tex]a^2-b^2=(a+b)(a-b)[/tex]So, we have
[tex]496^4-9=(496^2+3)(496^2-3)[/tex]HELP PLEASE!!!!!!!!!!! ILL MARK BRAINLIEST
the rational number :
-1 ³/₄ is located as point 1
14/8 is located as point 5
1.125 is located as point 6
-0.875 is located as point 4
What is number line ?
Number line is virtual representation of numbers along with coordinates axis with number equally spaced with equal number of interval.
Here,
the rational number -1 ³/₄ is located as point 1, as -1 ³/₄ is greater then -1 and less then -2 on number line and is 3/4 of the gap between -1 and -2.
the rational number 14/8 is located as point 5, as 14/8 is greater then 0 and less then 1 on number line and is 3/4 of the gap between 0 and 1.
the rational number 1.125 is located as point 6, as 1.125 is greater then 1 and less then 2 on number line and is 1/8th of the gap between 1 and 2.
the rational number -0.875 is located as point 4, as -0.875 is greater then 0 and less then -1 on number line and is 1/8 th of the gap between -1 and 0.
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Determine if u is a solution to 1 - 9u = 19u= -2, 7, 0, 6
-2
Replace u by -2, and check if the equality remains
1-9u = 19
1-9(-2) = 19
1-(-18)=19
1+18 = 19
19=19
-2 YES
7
1- 9(7) = 19
1-63 = 19
-62=19
NO
0
1-9(0) = 19
1= 19
NO
6
1-9(6) = 19
1-54=19
-53=19
NO
How can a greatest common factor be separated from an expression
Answer: divide each term from the original expression (3x3+27x2+9x ) by the GCF (3x), then write it in the parenthesis
Step-by-step explanation:
Answer:
You take it out and place it as a multiple.
Step-by-step explanation:
5x+15
GCF = 5
5(x+3)
Hope that helps
# 8 Write an equation in slope-intercept form to represent the line parallel to y = -3/4 x + 1/4 passing through the point (4, -2). O y = -3/4x + 1 O y y = 4/3x + 20/3 O y = -3/4 - 2 O y=-3x - 2
If the line is parallel to y = -3/4 x + 1/4 then the slope is -3/4
the form of an equation is y = mx +b
In this case m = -3/4
Using the point given (4, -2) we will find the value of b:
y = mx + b
y = -3/4 x + b
Using the values of the point (4, -2).... x = 4 and y = -2
-2 = (-3/4)(4) + b
Solving for b:
-2 = -3 + b
-2 + 3 = b
1 = b
b = 1
Therefore the equation would be:
y = (-3/4)x + 1
Answer:
y = (-3/4)x + 1
A rectangular sheet of metal is 40 inches wide and 100 inches long. What is its perimeter?
Explanation
We are given the following:
[tex]Rectangle\begin{cases}width={\text{ }40inches} \\ length={\text{ }100inches}\end{cases}[/tex]We are required to determine the perimeter of the rectangular sheet.
This is achieved thus:
We know that the perimeter of a rectangle is given as:
[tex]P=2(l+w)[/tex]Therefore, we have:
[tex]\begin{gathered} P=2(100+40) \\ P=2(140) \\ P=280inches \end{gathered}[/tex]Hence, the answer is:
[tex]280inches[/tex]1 1 10 1 b. What fraction of the whole square is shaded? Explain how you know.
1/100
Explanation:To get the fraction of the square shaded we would use the rows and columns
For the row:
The total on the 1st row = 1
The first row is divided into 10. This means each box in the first row: 1/10
One of the box is shaded. This implies the fraction shaded in the first row is 1/10
For the column:
The total on the 1st column = 1
The column is also divided into 10 box which means each box represent 1/10
Since one of the box in the column is shaded, it represent 1/10
Fraction of the whole square shaded = fraction shaded in the row × fraction shaded in the column
Fraction of the whole square shaded = 1/10 × 1/10
Fraction of the whole square shaded = 1/100
Alisa walks 3.5 miles in 30 minutes. At this rate, how many miles can she walk in 45 minutes?385.7 miles5 miles386 miles5.25 miles
Given:
Alisa walks 3.5 miles in 30 minutes.
To find:
The number of miles if she walks 45 mins.
Explanation:
The unit rate for speed is,
[tex]\begin{gathered} Speed=\frac{Distance}{Time} \\ =\frac{3.5}{30} \end{gathered}[/tex]The distance covered when she walks 45mins,
[tex]\begin{gathered} Distance=Speed\times Time \\ =\frac{3.5}{30}\times45 \\ =5.25miles \end{gathered}[/tex]Final answer:
The number of miles she walks in 45mins is 5.25miles.
How many times larger is 3 x 10⁹ than 3 x 10⁷ ?
Answer:
100 times
Step-by-step explanation:
[tex]\frac{10^{9} }{10^{7} }[/tex] = [tex]10^{2}[/tex] = 100
When you are dividing exponents with the same bases, you subtract the exponents.
Answer:
3 x 10^9 is larger than 3 x 10^7 by 2,970,000,000
Step-by-step explanation:
Find the next two numbers in the pattern -243, 81, -27, 9
Find the next two numbers in the pattern -243, 81, -27, 9
Notice that all the values in the series are value of 3 raise to the power of a number.
-243 =
Find an equation of line L. Write your answer using fractions or integers.The equation of line L is y =
Find slope m, in equation y= mx + b
m = Y/X =( y - y')/ (x - x')
m= (5 - -5 )/ (-3 -3) = 10/-6 = -5/3
Now find b
b = y - mx
= 5 - (-5/3)•-3
. = 5 - 5 = 0
b = 0
Then answer is, equation is
y = (-5/3)x
Given g=(1+2a)/a, solve for the variable a.
We are given the equality
[tex]g=\frac{1+2a}{a}[/tex]and told to solve for a. That is, we should apply mathematical operations on both sides of the equality so we "isolate" variable a on one side of the equality. We start by multiplying both sides by a, so we get
[tex]a\cdot g=1+2a[/tex]Now, we subtract 2a from both sides. We get
[tex]a\cdot g-2a=1[/tex]We can factor on the left side a as a common factor, so we get
[tex]a\cdot(g-2)=1[/tex]Finally, we divide by (g-2) on both sides, so we get
[tex]a=\frac{1}{g-2}[/tex]which statement is true?
This is the graph of the function
The answer is (8,0)
Mai made $192 for 12 hours of work at the same rate how many hours would she have to work to make $128? Please help
We were told that Mai made $192 for 12 hours of work. This means that the amount that she made per hour is
192/12 = $16
Given that her constant rate is $16 per hour,
let x = the number of hours would she have to work to make $128. Then, we have the following equations
1 = 16
x = 128
By crossmultiplying, we have
16x = 128
x = 128/16
x = 8
She has to work for 8 hours
H D 2 cm 4 cm The two rectangles below are similar. What is the ratio of the perimeters of rectangle ABCD to rectangle EFGH? B А 4 cm E 8 cm F 2:1 8:1 1:4 1:2 2
In order to determine the ratio of the perimeters for the given rectangles, first calcualte their perimeters. Use the following formula:
P = 2w + 2l
w: width
l: length
For the smaller rectangle you have:
w = 2cm
l = 4 cm
P = 2(2cm) + 2(4cm) = 4cm + 8cm = 12cm
For the bigger triangle you have:
w' = 4cm
l' = 8cm
P' = 2(4cm) + 2(8cm) = 8cm + 16cm = 24cm
Then, you have:
P/P' = 12cm/24cm = 1/2
Hence, the ratio is 1:2
^3 sq root of 1+x+sq root of 1+2x =2
The given equation is
[tex]\sqrt[3]{1+x+\sqrt{1+2x}}=2[/tex]First, we need to elevate each side to the third power.
[tex]\begin{gathered} (\sqrt[3]{1+x+\sqrt{1+2x}})^3=(2)^3 \\ 1+x+\sqrt{1+2x}=8 \end{gathered}[/tex]Second, subtract x and 1 on both sides.
[tex]\begin{gathered} 1+x+\sqrt{1+2x}-x-1=8-x-1 \\ \sqrt{1+2x}=7-x \end{gathered}[/tex]Third, we elevate the equation to the square power to eliminate the root
[tex]\begin{gathered} (\sqrt{1+2x})^2=(7-x)^2 \\ 1+2x=(7-x)^2 \end{gathered}[/tex]Now, we use the formula to solve the squared binomial.
[tex](a-b)=a^2-2ab+b^2[/tex][tex]\begin{gathered} 1+2x=7^2-2(7)(x)+x^2 \\ 1+2x=49-14x+x^2 \end{gathered}[/tex]Now, we solve this quadratic equation
[tex]\begin{gathered} 0=49-14x+x^2-2x-1 \\ x^2-16x-48=0 \end{gathered}[/tex]We need to find two number which product is 48 and which difference is 16. Those numbers are 12 and 4, we write them down as factors.
[tex]x^2-16x-48=(x-12)(x+4)[/tex]So, the possible solutions are
[tex]\begin{gathered} x-12=0\rightarrow x=12 \\ x+4=0\rightarrow x=-4 \end{gathered}[/tex]However, we need to verify each solution to ensure that each of them satisfies the given equation. We just need to evaluate it with those two solutions.
[tex]\begin{gathered} \sqrt[3]{1+x+\sqrt{1+2x}}=2\rightarrow\sqrt[3]{1+12+\sqrt{1+2(12)}}=2 \\ \sqrt[3]{13+\sqrt{1+24}}=2 \\ \sqrt[3]{13+\sqrt{25}}=2 \\ \sqrt[3]{13+5}=2 \\ \sqrt[3]{18}=2 \\ 2.62=2 \end{gathered}[/tex]As you can observe, the solution 12 doesn't satisfy the given equation.
Therefore, the only solution is -4.$85000 is invested at 7.5% per annum simple interest for 5 years. Calculate the simple interest.
From the statement of the problem we know that:
• the principal amount of money invested is P = $85000,
,• the rate per year is 7.5%, in decimals r = 0.075,
,• the time is t = 5 years.
The interest earnt I is equal to the difference between the total accrued amount A and the principal amount P:
[tex]I=A-P=P(1+r\cdot t)-P=P\cdot r\cdot t.[/tex]Replacing by the data of the problem we find that the simple interest is:
[tex]I=85000\cdot0.075\cdot5=31875.[/tex]Answer
The simple interest is $31875.
use accounting principles to find the number of outcomes: How many ways can Mark create a 4-digitcode for his garage door opener?
To creat a 4 - digit code, we need to consider that for each digit we have 10 options:
0, 1, 2, 3, 4, 5, 6, 7, 8, 9 -----> 10 options for each digit.
Next, we multiply the number of options we have for each digit. In this case, since we need the code to have 4 digits:
[tex]10\times10\times10\times10[/tex]We multiply 4 times 10.
And the result is:
[tex]10\times10\times10\times10=10,000[/tex]He has 10,000 ways to create a 4-digit code.
Canvas that costs 3/4 cents/in squared is used to make golf bags. Find the cost (in dollars) of 200 rectangular pieces of canvas, each 6.0 in. by 4.0 in.
The cost of 200 rectangular pieces of canvas given its dimensions is $36.
What is the cost?The first step is to determine the area of one of the rectangular pieces. A rectangle is a two-dimensional quadrilateral with four right angles.
Area of a rectangle = length x width
6 X 4 = 24 in²
The next step is to determine the area of the 200 rectangular pieces.
Area of the 200 rectangular pieces = 200 x 24in² = 4,800 in²
The last step is to determine the cost of the 200 rectangular pieces.
Total cost = total area x cost per squared inches
3 / 4 x 4800 = 3600 cents = $36
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45. For customers generating their own solar power, ZG&E charges them $3 per month per kilowatt (kWh) for excess electricity they export to the grid. Ready Edison charges customers a flat rate of $20 per month and credits them $0.06 per kWh for excess electricity they export to the grid. Determine the monthly bills for customers of both companies for each of the following:(A) Customer owns a 3-kW system and exports 120 kWh monthly to the grid.(B) Customer owns a 5-kW system and export 300 kWh monthly to the grid.
(A) The customer that owns a 3-kW system exports 120 kWh monthly to the grid will have the following bills for both companies:
For ZG&E that collects $3 per kWh on a monthly basis, the monthly bill will be
[tex]120kWh\times\frac{\$3}{1kWh}=\$360[/tex]For Ready Edison that collects $0.06 per kWh exported energy monthly, the computation of bill will be
[tex]\$20+(120kWh\times\frac{\$0.06}{1kWh})=\$27.2[/tex](B) The customer that owns a 5-kW system exports 300 kWh monthly to the grid will have the following bills for both companies:
For ZG&E that collects $3 per kWh on a monthly basis, the monthly bill will be
[tex]300kWh\times\frac{\$3}{1kWh}=\$900[/tex]For Ready Edison that collects $0.06 per kWh exported energy monthly, the computation of bill will be
[tex]\$20+(300kWh\times\frac{\$0.06}{1kWh})=\$38[/tex]Suppose the purr of a cat has a sound intensity that is 320 times greater than the threshold level. Find the decibel value for this cats purr. Round to the nearest decibel.
The decibel value for this cats purr round to the nearest decibel is; 25
How to calculate the decibel level?Decibel (dB) is a unit for expressing the ratio between two physical quantities, such as measuring the relative loudness of sounds. One decibel (0.1 bel) is equal to 10 times the common logarithm of the power ratio.
Decibels are a unit of measure used to describe how loud a sound is. Now, I₀ is the intensity of threshold sound, which is sound that can barely be perceived by the human ear.
The loudness of a sound, in decibels, with intensity I is given by;
dB = 10 log₁₀(I/I₀)
We are given the intensity of a cat’s purr as I = 320I₀
Thus;
dB = 10 log₁₀(320I₀/I₀)
dB = 10 log₁₀(320)
dB = 25.05 ≈ 25
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Ben works at a mobile phone store, where he earns a flat $80 for each 8-hour shift. He also earns a commission of $20 for each phone that he sells. If e stands for Ben's earnings and m is the number of mobile phones he sells, which of the following equations describes the amount of money that he earns in one shift?Question 5 options:A) e = m + 80B) e = m + 100C) e = –20m + 80D) e = 20m + 80
fixed earnings = $80 ( for 8 hour shift)
Number of mobile phones he sells = m
Commision for each mobile phone sold = $20
Amount he earns in 1 shift (e) = flat + number of phones* commision
e = 80 + 20m
e= 20m + 80 (D)