A company knows that unit cost C and unit revenue R from the production and sale of x units are related by c = R^2/112,000 + 5807 Find the rate of change of revenue per unit when the cost per unit is changing by $12 and the revenue is $4500

The statistics that is the most appropriate is option 2 from the image I added. [tex]Z = \frac{0.34 - 0.25}{\sqrt{\frac{0.3(1 - 0.3)}{50}+\frac{0.3(1 - 0.3)}{40} } }[/tex]

We have to find the proportion 1

= 17 / 50

= 0.34

Then we find the proportion 2

= 10 / 40

= 0.25

the proprotion = 17 + 10 / 50 + 40

= 27 / 90

= 0.3

Then the value of n1 = 50 and the value of n2 = 40

If we are to find the test statistics

The formula that we would use after inputting the values would be given as

[tex]Z = \frac{P1 - P2}{\sqrt{p(1 - p)\frac{1}{n1}+\frac{1}{n2} } }[/tex]

We will have

[tex]Z = \frac{0.34 - 0.25}{\sqrt{0.3(1 - 0.3)\frac{1}{50}+\frac{1}{40} } }[/tex]

When we expand we will have

[tex]Z = \frac{0.34 - 0.25}{\sqrt{\frac{0.3(1 - 0.3)}{50}+\frac{0.3(1 - 0.3)}{40} } }[/tex]

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The present value of $9,800 at the end of 4 years with a 6% monthly compounded rate is $7,996.84.

To find the present value of $9,800 at the end of 4 years with a 6% monthly compounded rate, we need to use the present value table.

First, we need to find the monthly compounded rate. The annual interest rate is 6%, so the monthly rate is

6/12 = 0.5%

Next, we need to find the PV factor. From the present value table 12.3, the PV factor for 48 periods at 0.5% monthly rate is 0.8138.

Now, we can calculate the present value:

PV = 9,800 × 0.8138

=7,996.84

Therefore, the present value of $9,800 at the end of 4 years with a 6% monthly compounded rate is $7,996.84.

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The concentration of the H2SO4 solution is 0.0395 M.

To find the concentration of the H2SO4 solution, we can use the balanced equation and the concept of stoichiometry. From the equation, we can see that 1 mole of H2SO4 reacts with 2 moles of NaOH.

First, find the moles of NaOH used in the titration:
moles of NaOH = volume of NaOH (L) × concentration of NaOH (M)
moles of NaOH = 0.02595 L × 0.657 M = 0.01704 moles

Now, using the stoichiometry of the balanced equation, we can find the moles of H2SO4:
moles of H2SO4 = moles of NaOH ÷ 2 = 0.01704 moles ÷ 2 = 0.00852 moles

Next, find the concentration of the H2SO4 solution:
concentration of H2SO4 (M) = moles of H2SO4 ÷ volume of H2SO4 (L)
concentration of H2SO4 (M) = 0.00852 moles ÷ 0.2157 L = 0.0395 M

So, the concentration of the H2SO4 solution is 0.0395 M.

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Answer: 1.02

Step-by-step explanation:

2.67 - 1.65 =  1.02

We can find that this probability is 0.99994, rounded to five decimal places.

Based on the given statistic, we know that 80% of vehicles using the Lincoln Tunnel use E-ZPass. Therefore, we can expect that out of the 12 randomly selected vehicles, 80% or 0.8 * 12 = 9.6 vehicles would use E-ZPass. Rounding to the nearest whole number, we would expect 10 of the 12 vehicles to use E-ZPass.

The mode of the distribution is 10, as this is the most frequently occurring value in the sample.

Since 10 out of 12 vehicles is the mode, the probability associated with the mode is the proportion of vehicles that use E-ZPass in the sample. Therefore, the probability associated with the mode is 10/12 or 0.833, rounded to three decimal places.

The probability of four or more vehicles using E-ZPass can be calculated using the binomial distribution. The probability of a single vehicle using E-ZPass is 0.8, and the probability of a single vehicle not using E-ZPass is 0.2. The probability of four or more vehicles using E-ZPass is the sum of the probabilities of selecting 4, 5, 6, 7, 8, 9, 10, 11, or 12 vehicles that use E-ZPass. Using Excel or a calculator, we can find that this probability is 0.99994, rounded to five decimal places.

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It will take time of 33.93 minutes for all of the water to pass through the cone.

To find the volume of the cone-shaped vessel, we need to use the formula for the volume of a cone:

V = (1/3) x pi x r² x h

V = (1/3) x 3.14 x 6^2 x 3

= 339.29 cubic inches

This is the total volume of water that needs to pass through the cone.

If water is dripping out at a rate of 10 cubic inches per minute, we can use the formula:

time = volume / rate

to find how long it will take for all of the water to pass through. Substituting the values we found, we get:

time = 339.29 / 10

=33.93 minutes

Therefore, it will take 33.93 minutes for all of the water to pass through the cone.

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The circle intersects the x-axis at the points (-5, 0) and (5, 0).

We have,

Using the Pythagorean theorem to find the radius of the circle.

So,

r = √(0-3)² + (0-4)²

r = √(9+16)

  = √25

  = 5

The equation of the circle is x² + y² = 5² = 25.

To find the points where the circle intersects the x-axis,

We substitute y = 0 in the equation of the circle and solve for x:

x² + 0² = 25

x² = 25

x = ±5

Therefore,

The circle intersects the x-axis at the points (-5, 0) and (5, 0).

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The requreid, time in a 24-hour time clock format is given as,
3:45 a.m. -> 03:45

9:16 a.m. -> 09:16

5:45 a.m. -> 05:45

12:00 midnight -> 00:00

12:00 noon -> 12:00

There is no "a.m." or "p.m." designation in 24-hour time, and times after 12:00 are designated as 13:00, 14:00, etc. up to 23:00, after which it resets to 00:00 for midnight.

So, the given time in 24-hour clock format is given as:
3:45 a.m. -> 03:45

9:16 a.m. -> 09:16

5:45 a.m. -> 05:45

12:00 midnight -> 00:00

12:00 noon -> 12:00

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We need additional information, such as a dataset or summary statistics to perform a normality test.

To determine if the data is normally distributed, we need to look at the distribution of the variable of interest. In this case, we are interested in the distribution of social conservatism scores.

If we have access to the data, we can use statistical tests such as the Shapiro-Wilk test or the Kolmogorov-Smirnov test to determine if the data is normally distributed. However, since we only have information about the population average and effect size, we cannot directly test for normality.

However, based on the central limit theorem, we can assume that if the sample size is large enough (typically >30), the distribution of the variable of interest will be approximately normal. In this case, since we do not have information about the sample size, we cannot definitively say if the data is normally distributed.

In summary, without more information about the sample size or access to the data, we cannot determine if the data is normally distributed.

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Answer:

The specific heat of the brass can be calculated using the formula:

Q = mcΔT

where Q is the heat transferred, m is the mass of the brass, c is the specific heat of the brass, and ΔT is the change in temperature.

First, calculate the heat transferred from the brass to the water:

Qbrass = mcΔT = (125 g)(c)(100 °C - 35 °C) = 9375c J

Next, calculate the heat transferred from the water to the brass:

Qwater = mcΔT = (76 g)(4.184 J/g. °C)(35 °C - 25 °C) = 3191.84 J

Since the heat lost by the brass is equal to the heat gained by the water:

Qbrass = Qwater

9375c J = 3191.84 J

c = 0.34 J/g. °C

Therefore, the specific heat of the brass is 0.34 J/g. °C.

Step-by-step explanation:

Answer:160

Step-by-step explanation:

multiply the expressions

The equivalent form of expression 15(p+ 4) - 12(2q + 4) is,

⇒ 15p - 24q + 12

We have to given that;

The value of expression is,

⇒ 15(p+ 4) - 12(2q + 4)

Now, We can simplify as;

⇒ 15(p+ 4) - 12(2q + 4)

⇒ 15p + 60 - 24q - 48

⇒ 15p - 24q + 12

Thus, The equivalent form of expression 15(p+ 4) - 12(2q + 4) is,

⇒ 15p - 24q + 12

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The Q-matrix is,

Q = | -λ1-λ2     λ2     λ1     0  |
   |    μ1  -μ1-λ2     0     λ2  |
   |    λ1     0  -μ1-λ1     μ2  |
   |    0      μ1     μ2  -μ1-μ2 |

In this problem, two salesmen are working in a small office selling shares in a mutual fund. Each salesman i is on the phone for an exponential amount of time with rate μi and then off the phone for an exponential amount of time with rate λi. We will formulate a Markov chain model for this system with state space {00, 01, 10, 11} and find the Q-matrix (generator matrix) of the Markov chain.

The state space has four possible states:
- 00: Both salesmen are off the phone
- 01: Salesman 1 is off the phone and Salesman 2 is on the phone
- 10: Salesman 1 is on the phone and Salesman 2 is off the phone
- 11: Both salesmen are on the phone

The Q-matrix (generator matrix) is a 4x4 matrix that describes the transition rates between states. We can find the Q-matrix as follows:

Q = | -λ1-λ2     λ2     λ1     0  |
   |    μ1  -μ1-λ2     0     λ2  |
   |    λ1     0  -μ1-λ1     μ2  |
   |    0      μ1     μ2  -μ1-μ2 |

In this matrix, the diagonal elements are negative sums of the transition rates out of the respective state, and the off-diagonal elements represent the transition rates between states.

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The surface area of the larger cylinder is 226.2 ft².

The volume of the larger prism is 1,375.3 m³.

The surface area of the larger cylinder is calculated as follows;

Since the volume of the larger cylinder is given, we will find the surface area;

S.A = 2πr²

where;

S.A =  2π(6 ft)²

S.A = 72π ft² = 226.2 ft²

Since the surface area of the larger prism is given, we will find the volume of the prism.

V = ¹/₃ x S.A x h

V = ¹/₃ x 294.7 m² x 14 m

V = 1,375.3 m³

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Answer:

19

Step-by-step explanation:

The maximum amount of the sum of digits that can be obtained from a digital clock is 27.

To see why, note that the maximum value for the hour digits is 23 (since the clock uses a 24-hour format). The sum of digits in 23 is 2+3=5.

For the minute digits, the maximum value is 59. The sum of digits in 59 is 5+9=14.

Adding the two sums of digits together, we get:

5 + 14 = 19

Therefore, 19 is the maximum sum of digits that can be obtained from the hour and minute digits on a digital clock

William is currently 15 years old.

Let's start by using algebra to solve for the ages of Jade and Kevin now. Let J be Jade's current age and K be Kevin's current age. We have:

J = 2K - 6 (Jade is 6 years less than twice Kevin's age)

J - 2 = 3(K - 2) (two years ago, Jade was three times as old as Kevin)

We can use the first equation to substitute for J in the second equation:

(2K - 6) - 2 = 3(K - 2)

Simplifying this, we get:

2K - 8 = 3K - 6

K = 2

So Kevin is currently 2 years old, and Jade is:

J = 2K - 6 = 2(2) - 6 = -2

This doesn't make sense as an age, so there may be an error in the problem statement or in our solution method.

Let's use algebra to solve for Amanda's current age, which we can call A. Then we can use that to find her age 3 years from now. We have:

L = 3A - 2 (Len is 2 less than 3 times Amanda's age)

L + 3 = 2(A + 3) + 7 (three years from now, Len will be 7 more than twice Amanda's age)

Substituting the first equation into the second, we get:

(3A - 2) + 3 = 2(A + 3) + 7

Simplifying this, we get:

A = 5

So Amanda is currently 5 years old, and her age 3 years from now will be:

A + 3 = 5 + 3 = 8

Let's use algebra to solve for Faith's current age, which we can call F. Then we can use that to find Janna's and William's ages. We have:

J = 2F (Janna is twice as old as Faith)

W = F + 9 (William is 9 years older than Faith)

J - 3 = 3(F - 3) - 9 (three years ago, Janna was 9 less than 3 times Faith's age)

Substituting the first two equations into the third, we get:

(2F) - 3 = 3(F - 3) - 9

Simplifying this, we get:

F = 6

So Faith is currently 6 years old, Janna is:

J = 2F = 2(6) = 12

and William is:

W = F + 9 = 6 + 9 = 15

Therefore, William is currently 15 years old.

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Thus, we can write:

z_0 = -1.75.

To learn mor

(a) From the standard normal distribution table, we can see that the closest probability to 0.3849 is 0.385. The corresponding z-value for this probability is 0.25. Therefore, z_0 = 0.25.

(b) Similar to part (a), the closest probability to 0.37 is 0.3707. The corresponding z-value for this probability is -0.31 (since we want the probability for z less than 0). Therefore, z_0 = -0.31.

(c) The probability of P(-z_0 <= z <= z_0) = 0.92 represents the area under the standard normal distribution curve between -z_0 and z_0. From the standard normal distribution table, we can find the z-value that corresponds to the area of 0.46 (half of 0.92) as 1.75. Thus, we can write:

z_0 = 1.75/2 = 0.875

(d) P(z > z_0) = 0.095 represents the area under the standard normal distribution curve to the right of z_0. From the standard normal distribution table, we can find the z-value that corresponds to the area of 0.905 (1-0.095) as 1.645. Thus, we can write:

z_0 = 1.645

(e) P(z <= z_0) = 0.04 represents the area under the standard normal distribution curve to the left of z_0. From the standard normal distribution table, we can find the z-value that corresponds to the area of 0.04 as -1.75 (since we want the z-value to be negative). Thus, we can write:

z_0 = -1.75.

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The  statement about probability that is true is option The probability of landing on orange is equal to the probability of landing on yellow.

From the  question, the spinner has:

8 sections, with:

So probability of one getting on any section is  = 1/8, or 0.125.

Therefore, the  probability of getting on orange will still be the same as the probability of landing on yellow and as such option C is correct.

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The amount that represents 125% of 80 is given as follows:

100.

The amount that represents 125% of 80 is obtained applying the proportions in the context of the problem.

The decimal multiplier for a percentage of 125% is given as follows:

125/100 = 1.25.

Hence the amount that represents 125% of 80 is obtained multiplying 80 by 1.25 as follows:

80 x 1.25 = 100.

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The probabilities are: (a) 12/13 (b) 1/13 (c) 0 (d) 1 7/26. (a) The probability of drawing a card above a jack is 48/52 or 12/13. This is because there are 48 cards above a jack and 52 total cards in the deck.

(b) The probability of drawing a card below a 2 is 4/52 or 1/13. This is because there are only 4 cards (A, K, Q, J) that are above a 2, and there are 52 total cards in the deck.

(c) To find the probability that a card is both above a jack and below a 2, we need to find the number of cards that satisfy both conditions. There are no cards that satisfy both conditions, so the probability is 0/52 or 0.

(d) To find the probability that a card is either above a jack or below a 5, we need to find the number of cards that satisfy either condition. There are 48 cards above a jack and 20 cards below a 5 (A, 2, 3, 4), but we need to subtract the overlap (cards that are both above a jack and below a 5), which is only 2 (A and 2). So the total number of cards that satisfy either condition is 48 + 20 - 2 = 66. The probability is then 66/52 or 33/26, which simplifies to 1 7/26.

In summary, the probabilities are:
(a) 12/13
(b) 1/13
(c) 0
(d) 1 7/26

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The given series ∑=1[infinity]4 is a divergent series since each term in the series is a constant 4 and does not approach zero as n approaches infinity. The value of k that makes the series converge is DNE, i.e., it does not exist.

To elaborate, a series converges if the sequence of its partial sums approaches a finite limit as the number of terms in the sequence goes to infinity.

In this case, the partial sum of the series after n terms is S_n = 4n. As n approaches infinity, S_n diverges to infinity as well, indicating that the series does not converge.

The value of k that makes the given series converge is DNE, as the series is divergent and does not approach a finite limit as the number of terms increases.

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The volume of the object is  52in³

The formula for the calculating the volume of the cylinder is expressed as;

V = πr²h

Given that the parameters are;

Substitute the values

Volume = 3 × 2² × 3

Multiply the values

Volume = 36 in³

The volume of a sphere is;

Volume = 4/3 ×3 × 2²

Multiply the values

Volume = 16 in³

Total volume = 16 + 36 = 52in³

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Assuming that the person transfers their savings to the highest available account as soon as they reach the required minimum amount, the total amount saved at the end of 25 years can be calculated as follows:

Step:1. For the first year, the person saves $4000 in the ordinary account and earns 6% interest, resulting in a total of $4240.
Step:2 In the second year, the person has $8240 and can transfer it to the 'extra' account to earn a higher interest rate of 7%. After one year, they will have $8816.80.                                                                                                                          Step:3. In the third year, the person has $12816.80 and can transfer it to the 'superextra' account to earn the highest interest rate of 8%. After one year, they will have $13856.22.
Step:4. For the remaining 22 years, the person continues to save $4000 at the beginning of each year and transfers their savings to the 'superextra' account to earn 8% interest. At the end of 25 years, they will have a total of $227,217.97.
Therefore, the total amount saved at the end of 25 years, assuming that the money is transferred to a higher-interest account at the earliest opportunity, is $227,217.97.

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Step-by-step explanation:

such a diamond or special kite is a rhombus.

especially interesting to us is that the diagonals intersect each other at their midpoints.

that means

y = 5

Pythagoras gets us x.

c² = a² + b²

c is the Hypotenuse (the side opposite of the 90° angle). in our case 13.

a and b are the 2 legs. in our case x and y.

13² = 5² + x²

169 = 25 + x²

x² = 169 - 25 = 144

x = sqrt(144) = 12

Can help the local authority make informed decisions about how frequently to run the minibus service, how many minibusses to deploy, and how to manage the waiting queue to minimize passenger waiting times.

To model the variability in this situation using random numbers, we can use a simulation approach. Here are the steps we can follow:

Generate a random number to represent the number of passengers arriving in a minute, based on the given distribution.

Generate a random number to represent the time between minibus departures, based on the given distribution.

Simulate the waiting queue for passengers by adding up the number of passengers arriving in each minute until the queue reaches a maximum of 10. Any additional arriving passengers would have to wait for the next minibus.

Repeat steps 1 to 3 to simulate multiple scenarios and gather data on the average waiting time, the maximum queue length, and other performance metrics.

By repeating this simulation many times, we can estimate the distribution of waiting times and queue lengths under different conditions. This can help the local authority make informed decisions about how frequently to run the minibus service, how many minibusses to deploy, and how to manage the waiting queue to minimize passenger waiting times.

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To express any vector x as a linear combination of an orthogonal basis {u1, u2} or {u1, u2, u3} for R2 or R3, respectively, we can solve a system of linear equations where each equation corresponds to one component of the vector x.

To show that {u1, u2} is an orthogonal basis for R2, we need to prove that u1 and u2 are orthogonal (perpendicular) to each other and that they span the entire space of R2. In other words, any vector in R2 can be expressed as a linear combination of u1 and u2.

Similarly, to show that {u1, u2, u3} is an orthogonal basis for R3, we need to prove that u1, u2, and u3 are pairwise orthogonal and that they span the entire space of R3. Any vector in R3 can be expressed as a linear combination of u1, u2, and u3.

Once we have shown that {u1, u2} or {u1, u2, u3} is an orthogonal basis for R2 or R3, respectively, we can express any vector x in terms of the basis vectors as follows:

For R2:

x = c1u1 + c2u2, where c1 and c2 are constants.

For R3:

x = c1u1 + c2u2 + c3u3, where c1, c2, and c3 are constants.

We can find the values of c1, c2, and c3 by solving a system of linear equations, where each equation corresponds to one component of the vector x. The solution to the system will give us the coefficients that express x as a linear combination of the U.

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The Laplace transform of the given function f(t) is [tex]L{f(t)} = (2/s^3) ~e^{-s}[/tex]

We have,

The given function can be represented in terms of unit step functions as follows:

f(t) = 0 for 0 ≤ t < 1

f(t) = t² for t ≥ 1

Using the unit step function u(t), we can express f(t) as:

f(t) = 0 x u(t) + t² x u(t - 1)

Apply the linearity property of the Laplace transforms and use the Laplace transform of the unit step function u(t-a), which is [tex]1/s ~e^{-as}:[/tex]

[tex]L{f(t)} = L{0 \times u(t)} + L{t^2 ~ u(t - 1)}\\= 0 \times L{u(t)} + L{t^2} ~ L{u(t - 1)}\\= 0 + L{t^2} ~ e^{-s \times 1}\\= L{t^2} ~ e^{-s}[/tex]

Using the Laplace transform property [tex]L{t^n} = n!/s^{n+1},[/tex] where n is a positive integer,

[tex]L{t^2} = 2!/s^{2+1}\\= 2!/s^3\\= 2/s^3[/tex]

Therefore,

The Laplace transform of the given function f(t) is [tex]L{f(t)} = (2/s^3) ~e^{-s}[/tex]

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Answer:

Step-by-step explanation:

Answer: 225 degree

5/8of full rotation is 225degrees

Answer:

0.625

Step-by-step explanation:

hope the his helping

Answer: The answer is A (40 m)

Step-by-step explanation: