a. find a length of segment DF . use decimal rotation _______ unitsb. find the length of segment DF. use decimal rotation _______ units

A. Find A Length Of Segment DF . Use Decimal Rotation _______ Unitsb. Find The Length Of Segment DF.

Answers

Answer 1
[tex]\text{ Since the triangles are similar, we will use the Thales' theorem!}[/tex][tex]\begin{gathered} \text{ By thales' theorem, we have that } \\ \\ \frac{AB}{AC}=\frac{DE}{DF} \\ \frac{2}{4}=\frac{1.2}{DF} \\ \frac{DF}{4}=\frac{1.2}{2} \\ \frac{DF}{4}=0.6 \\ DF=0.6\cdot4 \\ DF=2.4 \end{gathered}[/tex][tex]\begin{gathered} \text{And again, by thales' theorem, we have} \\ \frac{AB}{BC}=\frac{DE}{EF} \\ \frac{2}{3}=\frac{1.2}{EF} \\ \frac{EF}{3}=\frac{1.2}{2} \\ \frac{EF}{3}=0.6 \\ EF=0.6\cdot3 \\ EF=1.8 \end{gathered}[/tex]


Related Questions

A yogurt stand gave out 200 free samples of frozen yogurt, one free sample per person. The three sample choices were vanilla, chocolate, or chocolate & vanilla twist. 115 people tasted the vanilla and 137 people tasted the chocolate, some of those people tasted both because they chose the chocolate and vanilla twist. How many people chose chocolate and vanilla twist?

Answers

GivenA yogurt stand gave out 200 free samples of frozen yogurt, one free sample per person. The three sample choices were vanilla, chocolate, or chocolate & vanilla twist. 115 people tasted the vanilla and 137 people tasted the chocolate, some of those people tasted both because they chose the chocolate and vanilla twist. How many people chose chocolate and vanilla twist?

So we are to find x

[tex]137-x+x+115-x=200[/tex][tex]\begin{gathered} 137+115-x=200 \\ 252-x=200 \\ -x=200-252 \\ -x=-52 \\ x=52 \end{gathered}[/tex]The final answer52 people chose chocolate and vanilla twist

The floor of a shed has an area of 80 square feet. The floor is in the shape of a rectangle whose length is 6 feet less than twice the width. Find the length and the width of the floor of the shed. use the formula, area= length× width The width of the floor of the shed is____ ft.

Answers

Given:

The area of the rectangular floor is, A = 8- square feet.

The length of the rectangular floor is 6 feet less than twice the width.

The objective is to find the measure of length and breadth of the floor.

Consider the width of the rectangular floor as w, then twice the width is 2w.

Since, the length is given as 6 feet less than twice the width. The length can be represented as,

[tex]l=2w-6[/tex]

The general formula of area of a rectangle is,

[tex]A=l\times w[/tex]

By substituting the values of length l and width w, we get,

[tex]\begin{gathered} 80=(2w-6)\times w \\ 80=2w^2-6w \\ 2w^2-6w-80=0 \end{gathered}[/tex]

On factorizinng the above equation,

[tex]\begin{gathered} 2w^2-16w+10w-80=0 \\ 2w(w-8)+10(w-8)=0 \\ (2w+10)(w-8)=0 \end{gathered}[/tex]

On solving the above equation,

[tex]\begin{gathered} 2w+10=0 \\ 2w=-10 \\ w=\frac{-10}{2} \\ w=-5 \end{gathered}[/tex]

Similarly,

[tex]\begin{gathered} w-8=0 \\ w=8 \end{gathered}[/tex]

Since, the magnitude of a side cannot be negative. So take the value of width of the rectangle as 8 feet.

Substitute the value of w in area formula to find length l.

[tex]\begin{gathered} A=l\times w \\ 80=l\times8 \\ l=\frac{80}{8} \\ l=10\text{ f}eet. \end{gathered}[/tex]

Hence, the width of the floor of the shed is 8 ft.

Find the y-intercept of the line represented by the equation: -5x+3y=30

Answers

We need to find the y-intercept of the equation.

For this, we need to use the slope-intercept form:

[tex]y=mx+b[/tex]

Where m represents the slope and b the y-intercept.

Now, to get the form, we need to solve the equation for y:

Then:

[tex]-5x+3y=30[/tex]

Solving for y:

Add both sides 5x:

[tex]-5x+5x+3y=30+5x[/tex][tex]3y=30+5x[/tex]

Divide both sides by 3

[tex]\frac{3y}{3}=\frac{30+5x}{3}[/tex][tex]\frac{3y}{3}=\frac{30}{3}+\frac{5x}{3}[/tex][tex]y=10+\frac{5}{3}x[/tex]

We can rewrite the expression as:

[tex]y=\frac{5}{3}x+10[/tex]

Where 5/3x represents the slope and 10 represents the y-intercept.

The y-intercept represents when the graph of the equations intersects with the y-axis, therefore, it can be written as the ordered pair (0,10).

Dante is arranging 11 cans of food in a row on a shelf. He has 7 cans of beans, 3 cans of peas, and 1 can of carrots. In how many distinct orders can the cans be arranged if two cans of the same food are considered identical (not distinct)?

Answers

Given:

The number of cans of food =11

The number of cans of beans=7

the number of cans of peas=3

the number of cans of carrots=1

Condition : two cans of the same food are considered identical.

To arrange the n objects in order,

[tex]\begin{gathered} \text{Number of ways= }\frac{n!}{r_1!r_2!r_3!} \\ =\frac{11!}{7!3!1!} \\ =\frac{39916800}{30240} \\ =1320 \end{gathered}[/tex]

Answer: the number of ways are 1320.

There are 3 consecutive even integers that have a sum of 6. What is the value of the least integer?

Answers

We can express this question as follows:

[tex]n+(n+2)+(n+4)=6[/tex]

Now, we can sum the like terms (n's) and the integers in the previous expression. Then, we have:

[tex](n+n+n)+(2+4)=6=3n+6\Rightarrow3n+6=6[/tex]

Then, to solve the equation for n, we need to subtract 6 to both sides of the equation, and then divide by 3 to both sides too:

[tex]3n+6-6=6-6\Rightarrow3n=0\Rightarrow n=\frac{3}{3}n=\frac{0}{3}\Rightarrow n=0_{}[/tex]

Then, we have that the three consecutive even integers are:

[tex]0+2+4=6[/tex]

Therefore, the least integer is 0.

Graph the reflection of the polygon in the given line

Answers

Let:

[tex]\begin{gathered} A=(-3,2) \\ B=(1,-1) \\ C=(-2,-2) \\ D=(-4,-1) \end{gathered}[/tex]

After the reflection over y = -x:

[tex]\begin{gathered} A->(-y,-x)->A^{\prime}=(-2,3) \\ B->(-y,-x)->B^{\prime}=(1,-1) \\ C->(-y,-x)->C^{\prime}=(2,2) \\ D->(-y,-x)->D^{\prime}=(1,4) \end{gathered}[/tex]

a. Draw any obtuse angle and label it angle AXB. Then draw ray XY so that it bisects < AXB.b. if m AXB = 140°, then what is m ZYXB?

Answers

The obtuse angle is shown in the diagram below:

The word, "bisect" means to divide an angle into 2 equal parts. Given that ray XY bisects angle AXB, it mean that it divides it into two equal halves. Theregfore, angle YXB is 140/2 = 70 degrees

Use the graph to answer the question.Find the interval(s) over which the function is decreasing.A. (-infinity,-2)U(5,infinity)B. (-infinity,-2)U(-2,1)U(5,infinity)C.infinity,-2)U(-2,-1)U(-1,1)U(5,infinity )D. (1,5)

Answers

Okay, here we have this:

Considering the provided graph, and that a function is decreasing when as x increases, "y" decreases, we obtain the following:

The intervals over which the function is decreasing are:

(infinity,-2)U(-2,-1)U(-1,1)U(5,infinity )

Finally we obtain that the correct answer is the option C.

Transform y f(x) by translating it right 2 units. Label the new functiong(x). Compare the coordinates of the corresponding points that makeup the 2 functions. Which coordinate changes. x or y?

Answers

If we translate y = f(x) 2 units to the right, we would have to sum and get g(x) =f(x+2).

That means the x-coordinates of g(x) are going to have 2 extra units than f(x).

[tex](x,y)\rightarrow(x+2,y)[/tex]

Therefore, with the given transformation (2 units rightwards) the function changes its x-coordinates.

Use the distance formula to find the distance between the points given.(3,4), (4,5)

Answers

Solution:

To find the distance between two points, the formula is

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Where

[tex]\begin{gathered} (x_1,y_1)=(3,4) \\ (x_2,y_2)=(4,5) \end{gathered}[/tex]

Substitute the values of the variables into the formula above

[tex]d=\sqrt{(4-3)^2+(5-4)^2}=\sqrt{1^2+1^2}=\sqrt{1+1}=\sqrt{2}\text{ units}[/tex]

Hence, the answer is

[tex]\sqrt{2}\text{ units}[/tex]

Find the volume of each prism. Round your answers to the nearest tenth, if necessary. Do not include units (i.e. ft, in, cm, etc.). (FR)

Answers

EXPLANATION:

Given;

We are given the picture of an isosceles trapezoidal prism.

The dimensions are as follows;

[tex]\begin{gathered} Top\text{ }base=4 \\ Bottom\text{ }base=9 \\ Vertical\text{ }height=4.3 \\ Height\text{ }between\text{ }bases=6 \end{gathered}[/tex]

Required;

We are required to find the volume of this trapezoidal prism.

Step-by-step solution;

The area of the base of a trapezium is given as;

[tex]Area=\frac{1}{2}(a+b)\times h[/tex]

For the trapezium given and the values provided, we now have;

[tex]\begin{gathered} a=top\text{ }base \\ b=bottom\text{ }base \\ h=height \\ Therefore: \\ Area=\frac{1}{2}(4+9)\times4.3 \\ Area=\frac{1}{2}(13)\times4.3 \\ Area=6.5\times4.3 \\ Area=27.95 \end{gathered}[/tex]

The volume is now given as the base area multiplied by the length between both bases and we now have;

[tex]\begin{gathered} Volume=Area\times height\text{ }between\text{ }trapezoid\text{ }ends \\ Volume=27.95\times6 \\ Volume=167.7 \end{gathered}[/tex]

ANSWER:

The volume of the prism is 167.7

Write the following number as a fraction:

0.27

Answers

Step-by-step explanation:

27/100 is the fraction of 0.27

The length of a rectangle is 2 inches more than its width.If P represents the perimeter of the rectangle, then its width is:oAB.O4Ос. РOD.P-2 별O E, PA

Answers

Given:

a.) The length of a rectangle is 2 inches more than its width.

Since the length of a rectangle is 2 inches more than its width, we can say that,

Width = W

Length = L = W + 2

Determine the width with respect to its Perimeter, we get:

[tex]\text{ Perimeter = P}[/tex][tex]\text{ P = 2W + 2L}[/tex][tex]\text{ P = 2W + 2(W + 2)}[/tex][tex]\text{ P = 2W + 2W + }4[/tex][tex]\text{ P = 4W + }4[/tex][tex]\text{ P - 4 = 4W}[/tex][tex]\text{ }\frac{\text{P - 4}}{4}\text{ = }\frac{\text{4W}}{4}[/tex][tex]\text{ }\frac{\text{P - 4}}{4}\text{ = W}[/tex]

Therefore, the answer is D.

Identity the triangle congruence postulate (SSS,SAS,ASA,AAS, or HL) that proves the triangles are congruent. I will mark brainliest!!!

Answers

These are my old notes, I hope they can help.

SSS, or Side Side Side

SAS, or Side Angle Side

ASA, or Angle Side Side

AAS, or Angle Angle Side

HL, or Hypotenuse Leg, for right triangles only

Side Side Side Postulate

A postulate is a statement taken to be true without proof. The SSS Postulate tells us,

If three sides of one triangle are congruent to three sides of another triangle, then the two triangles are congruent.

Congruence of sides is shown with little hatch marks, like this: ∥. For two triangles, sides may be marked with one, two, and three hatch marks.

If △ACE has sides identical in measure to the three sides of △HUM, then the two triangles are congruent by SSS:

Side Angle Side Postulate

The SAS Postulate tells us,

If two sides and the included angle of a triangle are congruent to two sides and the included angle of another triangle, then the two triangles are congruent.

△HUG and △LAB each have one angle measuring exactly 63°. Corresponding sides g and b are congruent. Sides h and l are congruent.

A side, an included angle, and a side on △HUG and on △LAB are congruent. So, by SAS, the two triangles are congruent.

Angle Side Angle Postulate

This postulate says,

If two angles and the included side of a triangle are congruent to two angles and the included side of another triangle, then the two triangles are congruent.

We have △MAC and △CHZ, with side m congruent to side c. ∠A is congruent to ∠H, while ∠C is congruent to ∠Z. By the ASA Postulate these two triangles are congruent.

Angle Angle Side Theorem

We are given two angles and the non-included side, the side opposite one of the angles. The Angle Angle Side Theorem says,

If two angles and the non-included side of one triangle are congruent to the corresponding parts of another triangle, the triangles are congruent.

Here are congruent △POT and △LID, with two measured angles of 56° and 52°, and a non-included side of 13 centimeters:

[construct as described]

By the AAS Theorem, these two triangles are congruent.

HL Postulate

Exclusively for right triangles, the HL Postulate tells us,

Two right triangles that have a congruent hypotenuse and a corresponding congruent leg are congruent.

The hypotenuse of a right triangle is the longest side. The other two sides are legs. Either leg can be congruent between the two triangles.

Here are right triangles △COW and △PIG, with hypotenuses of sides w and i congruent. Legs o and g are also congruent:

[insert congruent right triangles left-facing △COW and right facing △PIG]

So, by the HL Postulate, these two triangles are congruent, even if they are facing in different directions.

Proof Using Congruence

Proving Congruent Triangles 5

Given: △MAG and △ICG

MC ≅ AI

AG ≅ GI

Prove: △MAG ≅ △ICG

Statement Reason

MC ≅ AI Given

AG ≅ GI

∠MGA ≅ ∠ IGC Vertical Angles are Congruent

△MAG ≅ △ICG Side Angle Side

If two sides and the included angle of a triangle are congruent to two sides and the included angle of another triangle, then the two triangles are congruent.

how long will it take for $2700 to grow to $24500 at an interest rate of 2.2% if the interest is compounded quarterly? Round to the nearest hundredth.

Answers

Let n be the number of quarterlies.

Then

[tex]\begin{gathered} 24500=2700(1+0.022)^n \\ \Rightarrow1.022^n=\frac{245}{27} \\ \Rightarrow n=\frac{\log _{10}\frac{245}{27}}{\log _{10}1.022} \end{gathered}[/tex]

Hence the number of months = 3n = 304.04 months

and the number of years = n / 4 = 25.34 years

7n + 2 - 7n How can I simplify the expression by combining like terms

Answers

In order to simplify this expression, we can combine the terms with the variable n, like this:

[tex]\begin{gathered} 7n+2-7n \\ =(7n-7n)+2 \end{gathered}[/tex]

Since the terms with the variable n have opposite coefficients (+7 and -7), the sum will be equal to zero:

[tex]\begin{gathered} (7n-7n)+2 \\ =(0)+2 \\ =2 \end{gathered}[/tex]

Therefore the simplified result is 2.

Seventh gradeK.2 Write equations for proportional relationships from tables 66UTutorialVer en español1) Over the summer, Oak Grove Science Academy renovates its building. The academy'sprincipal hires Jack to lay new tile in the main hallway.3) There is a proportional relationship between the length (in feet) of hallway Jack coverswith tiles, x, and the number of tiles he needs, y.0)) (feet)y (tiles)3276547631199Write an equation for the relationship between x and y. Simplify any fractions.y =

Answers

Proportional Relationship

Two variables x and y have a proportional relationship it the following equation stands:

y = kx

Where k is the constant of proportionality.

The number of tiles needed by Jack (y) has a proportional relationship with the length in feet of the hallway (x).

The table gives us some values. We'll summarize them as ordered pairs (x,y) as follows:

(3,27) (6,54) (7,63) (11,99)

We can use any of those ordered pairs to find the value of k. For example, (3,27). Substituting into the equation:

27 = k.3

Solving for k:

k= 27/3 = 9

Thus the equation is:

y = 9x

Note: We could have used any other ordered pair and we would have obtained the very same value of k.

Find the area of triangle ABC with the given parts. Round to the nearest tenth when necessary.a=47ftb=59ftc=65ft

Answers

Okay, here we have this:

Considering the provided measures, we are going to calculate the area of the triangle, so we obtain the following:

So to calculate the area of the triangle we are going to use Heron's formula. so, we have:

[tex]A_=\sqrt{S(S-a)(S-b)(S-c)}[/tex]

And S is equal to (a+b+c)/2, let's first calculate S and replace with the values in the formula:

S=(47+59+65)/2=171/2=85.5

Replacing:

[tex]\begin{gathered} A=\sqrt{85.5(85.5-47)(85.5-59)(85.5-65)} \\ A=\sqrt{85.5(38.5)(26.5)(20.5)} \\ A=\sqrt{1788243.1875} \\ A\approx1337.3ft^2 \end{gathered}[/tex]

Finally we obtain that the area of the triangle is approximately equal to 1337.3 ft^2

D. What is the change in temperature when the thermometer readingmoves from the first temperature to the second temperature? Write anequation for each part.1. 20°F to +10°F2. 20°F to 10°F3. 20°F to 10°F4. 10°F to +20°F

Answers

Given

What is the change in temperature when the thermometer reading

moves from the first temperature to the second temperature? Write an

equation for each part.

Solutiion

Lulu the Lucky puts chests of gems into her treasure vault.
Each chest holds the same number of gems. The table
below shows the number of gems Lulu received from
three different adventures and the number of chests she
needed to hold the gems.
Number of gems
Number of chests
Adventure A
600
2
Adventure B
1500
5
Adventure C
4800
16
Write an equation to describe the relationship between
g, the number of gems, and c, the number of chests.

Answers

The equation that represents the relationship of gems 'g' and chest 'c' is 300c = g.

What are equations?A mathematical statement that uses the word "equal to" between two expressions with the same value is called an equation. Like 3x + 5 = 15, for instance. Equations come in a wide variety of forms, including linear, quadratic, cubic, and others. Point-slope, standard, and slope-intercept equations are the three main types of linear equations.

So, the equation representing the relation of 'g' and 'c':

We can observe that:

600/2 = 3001500/5 = 3004800/16 = 300

So, we can conclude that:

g/c = 300300c = g

Therefore, the equation that represents the relationship of gems 'g' and chest 'c' is 300c = g.

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Solve the inequality
And how do I graph Graph the solution below:

Answers

Answer:

Step-by-step explanation:

to solve, divide both sides by -3/2 to isolate x

you'll get x>1.5

to graph, make a ray pointing right from 1.5 with an open dot

i need help with this question... it's about special right triangles. The answer should not be a decimal.

Answers

4) The given triangle is a right angle triangle. Taking 30 degrees as the reference angle,

hypotenuse = 34

adjacent side = x

opposite side = y

We would find x by applying the Cosine trigonometric ratio which is expressed as

Cos# = adjacent side/hypotenuse

Cos 30 = x/34

Recall,

[tex]\begin{gathered} \cos 30\text{ = }\frac{\sqrt[]{3}}{2} \\ \text{Thus, } \\ \frac{\sqrt[]{3}}{2}\text{ =}\frac{x}{34} \\ 2x=34\sqrt[]{3} \\ x\text{ = }\frac{34\sqrt[]{3}}{2} \\ x\text{ = 17}\sqrt[]{3} \end{gathered}[/tex]

To find y, we would apply the Sine trigonometric ratio. It is expressed as

Sin# = opposite side/hypotenuse

Sin30 y/34

Recall, Sin30 = 0.5. Thus

0.5 = y/34

y = 0.5 * 34

y = 17

the population of a town grows at a rate proportional to the population present at time t. the initial population of 500 increases by 15% in 10 years. what will be the pop ulation in 30 years? how fast is the population growing at t 30?

Answers

Using the differential equation, the population after 30 years is 760.44.

What is meant by differential equation?In mathematics, a differential equation is a relationship between the derivatives of one or more unknown functions. Applications frequently involve a function that represents a physical quantity, derivatives that show the rates at a differential equation that forms a relationship between the three, and a function that represents how those values change.A differential equation is one that has one or more functions and their derivatives. The derivatives of a function define how quickly it changes at a given location. It is frequently used in disciplines including physics, engineering, biology, and others.

The population P after t years obeys the differential equation:

dP / dt = kP

Where P(0) = 500 is the initial condition and k is a positive constant.

∫ 1/P dP = ∫ kdtln |P| = kt + C|P| = e^ce^kt

Using P(0) = 500 gives 500 = Ae⁰.

A = 500.Thus, P = 500e^kt

Furthermore,

P(10) = 500 × 115% = 575sO575 = 500e^10ke^10k = 1.1510 k = ln (1.15)k = In(1.15)/10 ≈ 0.0140Therefore, P = 500e^0.014t.

The population after 30 years is:

P = 500e^0.014(30) = 760.44

Therefore, using the differential equation, the population after 30 years is 760.44.

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Northeast Hospital’s Radiology Department is considering replacing an old inefficient X-ray machine with a state-of-the-art digital X-ray machine. The new machine would provide higher quality X-rays in less time and at a lower cost per X-ray. It would also require less power and would use a color laser printer to produce easily readable X-ray images. Instead of investing the funds in the new X-ray machine, the Laboratory Department is lobbying the hospital’s management to buy a new DNA analyzer.

Answers

The classification of each cost item as a differential cost, a sunk cost, an opportunity cost, or None, is as follows:

Cost                                                                  Classification

1. Cost of the old X-ray machine                                  Sunk cost

2. The salary of the head of the Radiology Dept.      None

3. The salary of the head of the Laboratory Dept.     None

4. Cost of the new color laser printer                          Differential cost

5. Rent on the space occupied by Radiology             None

6. The cost of maintaining the old machine               Differential cost

7. Benefits from a new DNA analyzer                         Opportunity cost

8. Cost of electricity to run the X-ray machines         Differential cost

9. Cost of X-ray film used in the old machine            Sunk cost

What are differential cost, sunk cost, and opportunity cost?

A differential cost is a cost that arises as the cost difference between two alternatives.

A sunk cost is an irrelevant cost in managerial decisions because it has been incurred already and future decisions cannot overturn it.

An opportunity cost is a benefit that is lost when an alternative is not chosen.

Thus, the above cost classifications depend on the decision to replace the old X-ray machine with a new machine (new X-ray or new DNA analyzer).

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Question Completion:

Required Classify each item as a differential cost, a sunk cost, or an opportunity cost in the decision to replace the old X-ray machine with a new machine. If none of the categories apply for a particular item, select "None".

1. Cost of the old X-ray machine

2. The salary of the head of the Radiology Department

3. The salary of the head of the Laboratory Department

4. Cost of the new color laser printer

5. Rent on the space occupied by Radiology

6. The cost of maintaining the old machine

7. Benefits from a new DNA analyzer

8. Cost of electricity to run the X-ray machines

9. Cost of X-ray film used in the old machine

Solve the equation for w.

4w + 2 + 0.6w = −3.4w − 6

No solution

w = 0

w = 1

w = −1

Answers

Answer:

w = -1

Step-by-step explanation:

Given equation:

[tex]4w + 2 + 0.6w=-3.4w-6[/tex]

Add 3.4w to both sides:

[tex]\implies 4w + 2 + 0.6w+3.4w=-3.4w-6+3.4w[/tex]

[tex]\implies 4w + 2 + 0.6w+3.4w=-6[/tex]

Subtract 2 from both sides:

[tex]\implies 4w + 2 + 0.6w+3.4w-2=-6-2[/tex]

[tex]\implies 4w +0.6w+3.4w=-6-2[/tex]

Combine the terms in w on the left side of the equation and subtract the numbers on the right side of the equation:

[tex]\implies 8w=-8[/tex]

Divide both sides by 8:

[tex]\implies \dfrac{8w}{8}=\dfrac{-8}{8}[/tex]

[tex]\implies w=-1[/tex]

Therefore, the solution to the given equation is:

[tex]\boxed{w=-1}[/tex]

Given that,

→ 4w + 2 + 0.6w = -3.4w - 6

Now the value of w will be,

→ 4w + 2 + 0.6w = -3.4w - 6

→ 4.6w + 2 = -3.4w - 6

→ 4.6w + 3.4w = -6 - 2

→ 8w = -8

→ w = -8/8

→ [ w = -1 ]

Hence, the value of w is -1.

For each ordered pair, determine whether it is a solution.

Answers

To determine which ordered pair is a solution to the equation we shall substitute the values of x and y in the ordered pair.

Taking the first ordered pair;

[tex]\begin{gathered} \text{For;} \\ 3x-5y=-13 \\ \text{Where;} \\ (x,y)\Rightarrow(9,8) \\ 3(9)-5(8)=-13 \\ 27-40=-13 \\ -13=-13 \end{gathered}[/tex]

This means the ordered pair (9, 8) is a solution.

We can also solve this graphically a follows;

Observe from the graph attached that the solution to the equation shown above is indicated at the point where x = 9 and y = 8.

The other ordered pairs in the answer options cannot be found on the line which simply mean they are not solutions to the equation given.

ANSWER:

The ordered pair (9, 8) is a solution to the equation 3x - 5y = -13

A quality control expert at glow tech computers wants to test their new monitors . The production manager claims that have a mean life of 93 months with the standard deviation of nine months. If the claim is true what is the probability that the mean monitor life will be greater than 91.4 months and a sample of 66 monitors? Round your answers to four decimal places

Answers

Given the following parameter:

[tex]\begin{gathered} \mu=93 \\ \sigma=9 \\ \bar{x}=91.4 \\ n=66 \end{gathered}[/tex]

Using z-score formula

[tex]z=\frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

Substitute the parameter provided in the formula above

[tex]z=\frac{91.4-93}{\frac{9}{\sqrt{66}}}[/tex][tex]z=-1.4443[/tex]

The probability that the mean monitor life will be greater than 91.4 is given as

[tex]\begin{gathered} P(z>-1.4443)=P(0\leq z)+P(0-1.4443)=0.5+0.4257 \\ P(z>-1.4443)=0.9257 \end{gathered}[/tex]

Hence, the probability that the mean monitor life will be greater than 91.4 months is 0.9257

currently, Yamir is twice as old as pato. in three years, the sum of their ages will be 30. if pathos current age is represented by a, what equation correctly solves for a?

Answers

The given situation can be written in an algebraic way.

If pathos age is a, and Yamir age is b. You have:

Yamir is twice as old as pato:

b = 2a

in three years, the sum of their ages will be 30:

(b + 3) + (a + 3) = 30

replace the b = 2a into the last equation, and solve for a, just as follow:

2a + 3 + a + 3 = 30 simplify like terms left side

3a + 6 = 30 subtract 6 both sides

3a = 30 - 6

3a = 24 divide by 3 both sides

a = 24/3

a = 8

Hence, the age of Pato is 8 years old.

What is the equation in slope-intercept form of the line that passes through the points (-4,8) and (12,4)?

Answers

ANSWER

y = -0.25 + 7

EXPLANATION

The line passes through the points (-4, 8) and (12, 4).

The slope-intercept form of a linear equation is written as:

y = mx + c

where m = slope

c = y intercept

First, we have to find the slope of the line.

We do that with formula:

[tex]\begin{gathered} m\text{ = }\frac{y_2-y_1}{x_2-x_1} \\ \text{where (x}_1,y_1)\text{ = (-4, 8) } \\ (x_2,y_2)\text{ = (12, 4)} \end{gathered}[/tex]

Therefore, the slope is:

[tex]\begin{gathered} m\text{ = }\frac{4\text{ - 8}}{12\text{ - (-4)}}\text{ = }\frac{-4}{12\text{ + 4}}\text{ = }\frac{-4}{16}\text{ = }\frac{-1}{4} \\ m\text{ = -0.25} \end{gathered}[/tex]

Now, we use the point-slope method to find the equation:

[tex]\begin{gathered} y-y_{1\text{ }}=m(x-x_1) \\ \Rightarrow\text{ y - 8 = -0.25(x - (-4))} \\ y\text{ - 8 = -0.25(x + 4)} \\ y\text{ - 8 = -0.25x - 1} \\ y\text{ = -0.25x - 1 + 8} \\ y\text{ = -0.25x + 7} \end{gathered}[/tex]

That is the equation of the line. It is not among the options.

need help finding the exact value of sec pi/3

Answers

Solution:

Given:

[tex]sec(\frac{\pi}{3})[/tex]

To find the exact value,

Step 1: Apply the trigonometri identieties.

From the trigonometric identities,

[tex]sec\text{ }\theta\text{ =}\frac{1}{cos\theta}[/tex]

This implies that

[tex]sec(\frac{\pi}{3})=\frac{1}{\cos(\frac{\pi}{3})}[/tex]

Step 2: Evaluate the exact value.

[tex]\begin{gathered} since \\ \cos(\frac{\pi}{3})=\frac{1}{2}, \\ we\text{ have} \\ sec(\frac{\pi}{3})=\frac{1}{\cos(\pi\/3)}=\frac{1}{\frac{1}{2}}=2 \end{gathered}[/tex]

Hence, te exact value of

[tex]sec(\frac{\pi}{3})[/tex]

is evaluated to be 2

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