A football player runs from his own goal line to the opposing team's goal line, returning to his twenty-yard line, all in 27.0 s. Calculate his average speed and the magnitude of his average velocity. (Enter your answers in yards/s.)HINTApply the definitions of average speed and average velocity.Click the hint button again to remove this hint.(a) Calculate his average speed. ____yards/s(b) Calculate the magnitude of his average velocity. ____yards/s

A Football Player Runs From His Own Goal Line To The Opposing Team's Goal Line, Returning To His Twenty-yard

Answers

Answer 1

time = 27 s

d = 20 yard

a) speed = distance / time

d1 = 100 yard ( own goal to opposing team's goal line)

d2 = 80 yard ( returning to 20 yard line)

d= d1+d2

d= 100 + 80 = 180 yards

Speed = 180 y / 27s = 6.667 y/s

b) velocity = displacement / time

d = 100 - 80 = 20 y

Velocity = 20 / 27 = 0.74 y/s


Related Questions

Timothy wants to know how far his math class is from the orange tree across the street from the school. His feet are ideal feet (meaning they are 1 foot long. 1 foot is 12 inches). Timothy finds that the orange tree is 159 feet from the door of the math classroom. He wants to know that distance in kilometers (km).a. Convert from feet to inches (1 ft =12 in)b. Convert from inches to centimeters (1 in =2.54c. Conver from centimeters to meters (1m = 100cm)d. Convert from meters to kilometers (1km=1000m)

Answers

a) 1 foot = 12 inches

159 feet = 159 x 12 = 1908

The distance in inches is 1908 inches

b) 1 inch = 2.54 cm

1908 inches = 1908 x 2.54 = 4846.32

The distance in centimeters is 4846.32 cm

c) 100 cm = 1 m

4846.32 cm = 4846.32/100 = 48.4632

The distance in meters is 48.4632 m

d) 1000m = 1 km

48.4632 m = 48.4632/1000 = 0.0484632

The distance in kilometers is 0.0484632 km

Writing Simple ExpressionsChoose all of the TRUE statement(s).Add 6 and 5, then multiply by 4 is the same as 4(6 + 5).4 times greater than 80 + 25 is the same as 4 x (80 + 25).Subtract 15 from 42 is the same as 15 − 42.9 times greater than 11 + 12 is the same as 9 + 11 + 12.8 times greater than 21 + 15 is the same as 8(21 + 15).

Answers

Add 6 and 5, then multiply by 4 is the same as 4(6 + 5). TRUE

4 times greater than 80 + 25 is the same as 4 x (80 + 25). TRUE

Subtract 15 from 42 is the same as 15 − 42. TRUE

9 times greater than 11 + 12 is the same as 9 + 11 + 12. FALSE

9 (11+12)

8 times greater than 21 + 15 is the same as 8(21 + 15). TRUE

The critical angle for a certain liquid-air surface is 20°. What is the index of refraction of this liquid?

Answers

ANSWER

[tex]\begin{equation*} 2.92 \end{equation*}[/tex]

EXPLANATION

To find the index of refraction of the liquid, we have to apply the formula for critical angle:

[tex]\theta=\sin^{-1}(\frac{n_r}{n_i})[/tex]

where nr = refractive index of air = 1

ni = refractive index of liquid

Hence, by substituting the given values into the equation, we have that the index of refraction of the liquid is:

[tex]\begin{gathered} 20=\sin^{-1}(\frac{1}{n_i}) \\ \sin20=\frac{1}{n_i} \\ n_i=\frac{1}{\sin20} \\ n_i=2.92 \end{gathered}[/tex]

That is the answer.

A bus is travelling along straight road at 100km/hr and the bus conductor walks a 6km/hr on the floor of the bus and in the same direction as the bus. Find the speed of the conductor relative to the road and relative to the bus. If the bus conductor now walks at the same rate but in opposite direction as the bus, find his new speed relative to the road.

Answers

Given data:

* The speed of the bus is 100 km/hr.

* The speed of the conductor is 6 km/hr.

Solution:

(a). If the bus and conductor are traveling in the same direction.

The net speed of the conductor relative to the road is,

[tex]v_1=v_b+v_c_{}[/tex]

where v_1 is the velocity of the conductor relative to the road, v_b is the velocity of the bus, and v_c is the velocity of the conductor inside the bus,

Substituting the known values,

[tex]\begin{gathered} v_1=100+6 \\ v_1=106\text{ km/hr} \end{gathered}[/tex]

Thus, the speed of the conductor relative to the road is 106 km/hr.

(b). The speed of the conductor relative to the bus is the speed of the conductor on the bus,

Thus, the speed of the conductor relative to the bus is 6 km/hr.

An electric oven has a resistance of 50.0 Ω and a voltage of 220 V. How much current does it draw?

Answers

Given

Resistance of the oven, R=50.0 ohm,

Voltage is V=220 V

To find

The current drawn

Explanation

Let the current be I

By Ohm's law,

[tex]V=RI[/tex]

Putting the values,

[tex]\begin{gathered} 220=50I \\ \Rightarrow I=4.4A \end{gathered}[/tex]

Conclusion

The current drawn is 4.4 A

Two Styrofoam blocks are brought near each other and are observed to repel each other. Each block has the same amount of charge on it. Which statement is true about this situation? A)the charge on each block must be positive B)the charge on each block must be negative C)the blocks are creating magnetic fields from non moving electric charges D)each block has the same kind of charge but we don't' know what kind it is

Answers

ANSWER:

D)each block has the same kind of charge but we don't' know what kind it is

STEP-BY-STEP EXPLANATION:

Two charges of the same type always repel each other.

In this case, it is not possible to know what type of load they are, only that they are the same.

Therefore, the correct answer is:

D)each block has the same kind of charge but we don't' know what kind it is

find an equation of the line with y intercept (0,7) and the slope of 1/2

Answers

Consider that a general way of writing a line equation is:

y = mx + b

where m is the slope of the line and b is the y coordinate of the y-intercept of the line.

Then, by using the given information:

m = 1/2

b = 7

You have the following equation of line:

y = 1/2*x + 7

How much work does Scott do to push a 74 kg sofa 2.1 m across the floor at a constant speed? The coefficient of kinetic friction between the sofa and the floor is 0.23.

Answers

Work does Scott do to push a 74 kg sofa 2.1 m across the floor at a constant speed. The coefficient of kinetic friction between the sofa and the floor is 0.23 is 349 Nm.

given that :

mass = 74 kg

distance d = 2.1 m

coefficient of kinetic friction , μk  = 0.23

work done is given as :

w = fd

f = μk m g

f = 0.23 × 74 × 9.8

f = 166 N

therefore ,

work = fd

w = 168 × 2.1

w = 349 Nm

Work does Scott do to push a 74 kg sofa 2.1 m across the floor at a constant speed. The coefficient of kinetic friction between the sofa and the floor is 0.23 is 349 Nm.

To learn more about Work here

https://brainly.com/question/13662169

#SPJ1

Grant jumps 1.10 m straight up into the air to slam-dunk a basketball into the net. With what speed did he leave the floor?

Answers

Grant jumps 1.10 m straight up into the air to slam-dunk a basketball into the net, the speed from which he would have left the floor would be 4.64 m / s .

What are the three equations of motion?

There are three equations of motion given by  Newton

v = u + at

S = ut + 1/2 × a × t²

v² - u² = 2 × a × s

As given in the problem grant jumps 1.10 m straight up into the air to slam-dunk a basketball into the net.

By using the third equation of the motion,

v² - u² = 2 × a × s

0 - u² = 2 × -9.81 × 1.10

u = 4.64 m / s

Thus,  the speed from which he would have left the floor would be 4.64 m / s .

To learn more about equations of motion here, refer to the link given below;

brainly.com/question/5955789

#SPJ1

A sled of mass 26 kg has an 18 kg child on it. If big brother is pulling with a 30 N force to the right and 10 N up, and big sister is pushing with a 40 N force to the right and 16 N down, what is the normal force?

Answers

Given data:

* The mass of the sled is m_1 = 26 kg.

* The mass of the child is m_2 = 18 kg.

* The force in the upwards direction by the big brother is F_1 = 10 N.

* The force in the downwards direction by the big sister is F_2 = 16 N.

Solution:

The net mass on the sled along with the child is,

[tex]\begin{gathered} m=m_1+m_2 \\ m=26+18 \\ m=44\text{ kg} \end{gathered}[/tex]

The net weight of the sled along with the child is,

[tex]\begin{gathered} w=mg \\ w=44\times9.8 \\ w=431.2\text{ N} \end{gathered}[/tex]

The weight of the sled along the child is acting on the sled in the downwards direction.

Thus, the normal force acting on the sled (taking upward force as negative and downward force as positive) is,

[tex]\begin{gathered} N=w+F_2-F_1 \\ N=431.2+16-10 \\ N=437.2\text{ newton} \end{gathered}[/tex]

Thus, the normal force acting on the sled is 437.2 N.

Tsunami waves generally carry a mass (m) of 770 kg of water, travel at a velocity (v) of approximately 10 m/s and have a height (h) of 10 m at landfall. The colony structures can withstand a total energy (TE) 135,000 J before catastrophic damage occurs.ANSWER (a) AND (b)(a) Using your answers from #4 and #5 calculate the total energy (TE) of a tsunami wave. TE = KE + PE (b) Using your calculations and the provided data, explain to the colonizing council whether this crash site can be used to start a colony.

Answers

ANSWER:

(a)

Potential energy = 75460 J

Kinetic energy = 38500 J

Total energy = 113960 J

(b)

The site can be used to start a colony.

STEP-BY-STEP EXPLANATION:

Given:

Mass (m) = 770 kg

Velocity (v) = 10m/s

Height (h) = 10 m

(a)

We calculate in each case the kinetic and potential energy by means of their formulas

[tex]\begin{gathered} E_k=\frac{1}{2}m\cdot v^2=\frac{1}{2}\cdot770\cdot10^2=38500\text{ J} \\ E_p=m\cdot g\cdot h=770\cdot9.8\cdot10=75460\text{ J} \end{gathered}[/tex]

The total energy is the sum of both calculated energies:

[tex]\begin{gathered} E_T=38500+75460 \\ E_T=113960\text{ J} \end{gathered}[/tex]

(b)

Since the tsunami energy is less than the energy that can destroy the colony, then the site can support a permanent colony.

The source of the Sun’s heat and light energy is:A. combustion of helium gas.B. fusion of hydrogen nuclei.C. gravitational pressure.D. burning of fossil fuels.

Answers

To find

The source of the Sun’s heat and light energy is:

Explanation

The sun's core is very hot. So under pressure nuclear fusion takes place. Here hydrogen is changed to helium.

Conclusion

The correct option is

B. fusion of hydrogen nuclei.

A 65.0-kg basketball player jumps vertically and leaves the floor with a velocity of 1.80 m/s upward. (a) What impulse does the player experience? (b) What force does the floor exert on the player before the jump? (c) What is the total average force exerted by the floor on the player if the player is in contact with the floor for 0.450 s during the jump?

Answers

(a) The impulse experienced by the player is 117 Ns.

(b) The force the floor exert on the player before the jump is 637 N.

(c) The total average force exerted by the floor on the player if the player is in contact with the floor for 0.450 s during the jump is 260 N.

What impulse does the player experience?

The impulse experienced by the player is the change in the momentum of the player.

J = ΔP

J = m(v - u)

where;

m is the mass of the playerv is the final velocity of the player = 0u is the initial velocity of the player = - 1.8 m/s (negative because of upward direction)

J = 65 x (0 + 1.8)

J = 117 Ns

The force the floor exert on the player before the jump is calculated as;

F = mg

where;

g is acceleration is due to gravity

F = 65 x 9.8

F = 637 N

The total average force exerted by the floor on the player if the player is in contact with the floor for 0.450 s during the jump is calculated as;

F = ma

F = m(v/t)

F = (mv)/t

F = (65 x 1.8) / 0.45

F = 260 N

Learn more about impulse here: https://brainly.com/question/25700778

#SPJ1

Mass/energy equivalence is expressed mathematically in which of the following expressions?

Answers

Check each option to see how it relates to different concepts.

Option 1: E=hf

This equation tells the energy carried by an electromagnetic wave with frequency f.

Option 2: E=mc

This equation is not correct, since the left member is measured in units of energy and the right member does not.

Option 3: E=(1/2)mv^2

This equation relates the energy of a moving object with its mass and its velocity. It is known as kinetic energy.

Option 4: E=mc^2

Since c is a constant (the speed of light), this equation relates the energy of an object with its mass.

Therefore, the mass/energy equivalence is expressed mathematically in the equation:

[tex]E=mc^2[/tex]

Four wires running through the corners of a square with sides of length 16.166 cm carry equal currents, 3.684 A. Calculate the magnetic field at the center of the square.

Answers

For practical reasons, we can consider each side of the square as an infinite wire. This can be seen on the following drawing:

This way, the field on the center will be the sum of the contribution of each wire. We can calculate the contribution of a single wire as:

[tex]B=\frac{\mu_0i}{2\pi d}=\frac{4\pi *10^{-7}*3.684}{2\pi(\frac{16.166*10^{-2}}{2})}=9.115*10^{-6}T[/tex]

Then, the total field will be this, multiplied by the number of wires:

[tex]B_t=4*9.115*10^{-6}=36.46\mu T[/tex]

Then, the resulting field will be Bt=36.46uT

if i put my spoon in the microwave what will happen

Answers

If you put your spoon in the microwave, nothing will happen to it as long as it has round edges and it is not touching any sides of the microwave.

Putting a spoon in the microwave

Spoons are generally made from stainless steel. Stainless steels are iron and chromium. In some cases, other metals such as nickel are thrown into the mix.

Thus, being made of metals, these stainless steels are good conductors of heat and electricity.

A microwave works by heating foods put into it using electromagnetic radiation in the microwave frequency range. Electromagnetic radiation causes the molecules of food to rotate and produce thermal energy.

If the spoon touches the side of the microwave, sparks may result. Otherwise, it is totally fine because spoons usually have round edges. With rough edges,  the waves may be reflected back and forth and create sparks.

More on microwaves can be found here: https://brainly.com/question/1593533

#SPJ1

Two identical point charges exert a repulsive force of 0.500 N on one another when separated by 1.5 m. What is the magnitude of the net charge of either point charge?

Answers

Given,

The repulsive force exerted by the charges, F=0.500 N

The distance between the charges, d=1.5 m

From Coulomb's law,

[tex]F=\frac{\text{kqq}}{r^2}[/tex]

Where q is the magnitude of the charge of each point charge and k is the coulomb's constant.

On rearranging the above equation,

[tex]\begin{gathered} F=\frac{kq^2}{r^2} \\ \Rightarrow q=\sqrt[]{\frac{F}{k}}r \end{gathered}[/tex]

On substituting the known values,

[tex]\begin{gathered} q=\sqrt[]{\frac{0.5}{9\times10^9}}\times1.5 \\ =1.1\times10^{-5}\text{ C} \end{gathered}[/tex]

Thus the magnitude of the charge of each point charge is 1.1×10⁻⁵ C

Therefore the correct answer is option B.

The position of a particle is F(t) = 4.01²î - 3.0ĵ +2.03 km. (a) What is the velocity of the particle at 0 s and at 1.0 s? (b) What is the average velocity between 0 s and 1.0

Answers

The velocity of the particle at 0 s and at 1.0 and the average velocity between 0 s and 1.0

a)[tex]\vec{V}(0)=0 m / s[/tex]

[tex]\vec{V}(1)=(8 \hat{\imath}+6 \hat{k}) m / s[/tex]

b)[tex](4 \hat{\imath}+2 \hat{k}) \mathrm{m} / \mathrm{s}[/tex]

This is further explained below.

What is the average velocity?

Generally, the equation for the Position is mathematically given as

F(t) = 4.01²î - 3.0ĵ +2.03 km.

Therefore

[tex]\begin{aligned}&\vec{r}(t)=\left(4 t^2 \hat{l}-3 \hat{\jmath}+2 t^3 \hat{k}\right) m \\&\vec{V}(t)=\frac{d \vec{r}(t)}{d t}=\left(8 t \hat{\imath}+6 t^2 \hat{k}\right) m / s\end{aligned}[/tex]

For A

[tex]\begin{aligned}&\vec{V}(0)=0 m / s \\&\vec{V}(1)=(8 \hat{\imath}+6 \hat{k}) m / s\end{aligned}[/tex]

For B

[tex]\text { Average velocity } &=\frac{\text { Total displacement }}{\text { time interval }} \\[/tex]

[tex]=\frac{\vec{r}(1)-\vec{r}(0)}{1} \\&=4 \hat{\imath}-3 \hat{\jmath}+2 \hat{k}-\left(-3 \hat{\jmath}^{\prime}\right) \\&=(4 \hat{\imath}+2 \hat{k}) \mathrm{m} / \mathrm{s}\end{aligned}[/tex]

In conclusion, The speed of the particle at 0 seconds and at 1.0 seconds, as well as the average speed between 0 seconds and 1.0 seconds

a)[tex]\vec{V}(0)=0 m / s[/tex]

[tex]\vec{V}(1)=(8 \hat{\imath}+6 \hat{k}) m / s[/tex]

b)[tex](4 \hat{\imath}+2 \hat{k}) \mathrm{m} / \mathrm{s}[/tex]

Read more about average velocity

https://brainly.com/question/862972

#SPJ1

Peter is trying to ignite the hotplate by turning the gas knob. Suppose thatthe minimum moment of couple about the center of the gas knob requiredto ignite the hotplate is 0.3 N m. Calculate the minimum force (F, and F2)that required to exert. Given that the diameter of gas knob is 5 cm.

Answers

the minimum force is 6 Newtons

Explanation

A moment of a force, or a torque, is a measure of a force's tendency to cause a body to rotate. The moment depends on both the force, and on the position at which the force acts, it is given by the expression

[tex]M=F\cdot d\text{ }[/tex]

where F is the exerted force and d is the distance

Step 1

then, let

[tex]\begin{gathered} M=\text{0}.3\text{ Nm} \\ F=F \\ \text{distance}=\text{ 5 cm= }\frac{5}{100}m=0.05\text{ m} \\ \end{gathered}[/tex]

now, replace in the formula

[tex]\begin{gathered} M=F\cdot d\text{ } \\ 0.3\text{ Nm=F}\cdot0.05\text{ m} \\ \text{divide both sides by 0.05 m} \\ \frac{0.3\text{ Nm}}{0.05\text{ m}}\text{=}\frac{\text{F}\cdot0.05\text{ m}}{0.05\text{ m}} \\ 6N=F \end{gathered}[/tex]

therefore, the minimum force is 6 Newtons

I hope this helps you

You and some friends are duck pin bowling. You’re up and you roll your bowling ball (m = 1.6kg) down the lane. It collided with one pin (0.68kg) on the end in a perfectly elastic one dimensional collision. If the ball was moving at a velocity of 6 m/s just before it hits the pin, what is the velocity of the bowling pin after the collision?

Answers

Given:

The mass of the bowling ball is m1 = 1.6 kg

The mass of the pin is m2 = 0.68 kg

The initial velocity of the ball is

[tex]v_i=\text{ 6 m/s}[/tex]

Required: Velocity of the bowling pin after the collision.

Explanation:

According to the conservation of momentum, the velocity after the collision will be

[tex]\begin{gathered} m1v_i+m2\times0\text{ =\lparen m1+m2\rparen v}_f \\ v_f=\frac{m1v_i}{m1+m2} \\ =\frac{1.6\times6}{1.6+0.68} \\ =4.21\text{ m/s} \end{gathered}[/tex]

Final Answer: The velocity of the bowling pin after the collision is 4.21 m/s

A rock sample has a mass of 6 kg and a volume of 0.002 m3. Calculate the density of this rock sample.

Answers

Density = mass / volume

So 6/0.002=3,000 kg/m3.

The density of the rock sample is 3000 kg/m³.

Density is an important property of matter because it can be used to determine the weight of an object. For example, if you know the density of a rock sample and its volume, you can calculate its weight by multiplying the density by the volume. Density can also be used to determine the composition of a material. For example, if you know the densities of different materials, you can identify the material of a rock sample by measuring its density.

Density is a measure of how much mass is contained in a given volume.. The calculation of the density of the rock sample:

Density = Mass / Volume

Density = 6 kg / 0.002 m³

Density = 3000 kg/m³

As a result, the rock sample has a density of 3000 kg/m³.

To know more about the Density, here

https://brainly.com/question/32293567

#SPJ2

A wooden sphere of mass 4.0 kg is completely immersed in water. A pushing force of 20. N is
applied.
21°
20 N
4.2 ms²
19⁰
At the moment shown in the diagram, the sphere is stationary and it experiences an
acceleration upwards and to the right as shown.
Calculate the size of the upwards force due to the water (upthrust) acting on the sphere.

Answers

The size of the upwards force due to the water (upthrust) acting on the sphere is 12.64 N.

What is upthrust?

Buoyancy or upthrust, is an upward force exerted by a fluid on an object immersed in the fluid due to the weight of the object

Thus, upthrust is the upward force acting on an object immersed in a liquid.

Fu - Df = F(net_u)

where;

Fu is the upward forceDf is the downward force applied on the objectF(net_u) is the net upward force

Fu - F x sin(21) = ma x sin(19)

where;

m is the mass of the wooden spherea is the upward acceleration of the wooden sphere

Fu -  20 x sin(21) = (4 x 4.2) x sin(19)

Fu - 7.17 = 5.47

Fu = 12.64 N

Learn more about upthrust here: https://brainly.com/question/23931817

#SPJ1

44) Find the x coordinate of the center of mass of the bricks shown.

Answers

We are asked to determine the x-coordinate of the center of mass of the given bricks. To do that, we will use the following formula:

[tex]\bar{x}=\frac{\Sigma x_im_i}{\Sigma m_i}[/tex]

Where:

[tex]\begin{gathered} x_i=\text{ x-coordinate of the center of mass of each brick} \\ m_i=\text{ mass of each brick} \end{gathered}[/tex]

Since we have three bricks, the formula expands to:

[tex]\bar{x}=\frac{x_1m_1+x_2m_2_{}+x_3m_3}{m_1+m_2+m_3}[/tex]

Since we have three bricks with the same characteristics we will assume the three of them have the same mass:

[tex]\bar{x}=\frac{x_1m_{}+x_2m+x_3m_{}}{m_{}+m_{}+m_{}}[/tex]

Taking "m" as a common factor and adding like terms in the denominator we get:

[tex]\bar{x}=\frac{m(x_1+x_2+x_3)}{3m}[/tex]

Now we cancel out the "m":

[tex]\bar{x}=\frac{x_1+x_2+x_3}{3}[/tex]

Now we determine the x-coordinates of each brick. Each brick is a parallelepiped, therefore, the x-coordinate is in the middle. Since each brick measures L, this means that the x-coordinate of the first brick is:

[tex]x_1=\frac{L}{2}[/tex]

For the second brick, we have the L/2 of the separation from the first plus the L/2 of its length, therefore:

[tex]x_2=\frac{L}{2}+\frac{L}{2}=L[/tex]

Now, for the third brick we have the L/4 of the separation from the second brick plus the L/2 of the separation of the second brick and the first brick and the L/2 of the length of the third brick, therefore:

[tex]x_3=\frac{L}{2}+\frac{L}{4}+\frac{L}{2}=\frac{5L}{4}[/tex]

Now we substitute in the formula for the x-coordinate:

[tex]\bar{x}=\frac{(\frac{L}{2})+(L)+(\frac{5L}{4})}{3}[/tex]

Adding like terms in the numerator:

[tex]\bar{x}=\frac{\frac{11L}{2}}{3}[/tex]

Simplifying:

[tex]\bar{x}=\frac{11L}{6}[/tex]

Therefore, the x-coordinate of the center of mass is located at 11L/6 from the origin.

some more disconnectiob

Answers

let the student report the tutor and check

answer is updated

answer is updated olalalala

olalalala 2

olalalala 3

Using the work energy theorem, what is the final velocity of a roller coaster at the bottom of the hill. The coaster has a mass of 839 kg and starts at rest from the top of a hill that is 75 meters tall.

Answers

ANSWER

38.34 m/s

EXPLANATION

Given:

• The mass of the coaster, m = 839 kg

,

• The initial height of the coaster, h = 75 m

,

• The acceleration due to gravity, g = 9.8 m/s²

Find:

• The final velocity of the roller coaster at the bottom of the hill, v.

The roller coaster starts from rest, so at the top of the hill, it only has gravitational potential energy and no kinetic energy. Then, at the bottom of the hill, the roller coaster is in motion, to it has kinetic energy, and, because the difference of height with the reference - which is the bottom of the hill, is zero, it has no potential energy,

By the work-energy theorem, we have the equation,

[tex]KE_i+PE_i+W_{nc}=KE_f+PE_f_{}[/tex]

As explained above, the initial kinetic energy is 0 and the final potential energy is also 0. If we assume that there is no friction, air resistance, or other external forces, then the work done by non-conservative forces is also 0,

[tex]PE_i=KE_f[/tex]

Replace each kind of energy with the expression to obtain them,

[tex]m\cdot g\cdot h=\frac{1}{2}\cdot m\cdot v^2[/tex]

The mass cancels out,

[tex]g\cdot h=\frac{1}{2}\cdot v^2[/tex]

Solving for v,

[tex]v=\sqrt[]{2\cdot g\cdot h}[/tex]

Replace with the known values and solve,

[tex]v=\sqrt[]{2\cdot9.8m/s^2\cdot75m}=\sqrt[]{1470m^2/s^2}\approx38.34m/s[/tex]

Hence, the velocity of the roller coaster at the bottom of the hill is 38.34 m/s, rounded to the nearest hundredth.

On a standard day the speed of sound is 345 meters per second. A whistle whose frequency is 725 Hz is movingtoward an observer at a speed of 25.2 meters per second. What is the wavelength of the sound at the observer?(a) 0.367 m(b) 0.441 m(c) 0.511 m(d) 0.623 m

Answers

Take into account that this is a situation where the source moves presenting the Doppler effect.

In order to determine the wavelength of the sound generatd by the whistle at the observer, first calculate the frequency at the observer by using the following formula:

[tex]f=\frac{v}{v-v_s}f_s[/tex]

where:

f: frequency at the observer = ?

fo: source frequency = 725 Hz

vs: source speed = 25.2 m/s

v: speed of sound = 345 m/s

replace the previous values of the parameters into the fomrula for f:

[tex]\begin{gathered} f=\frac{345m/s}{345m/s-25.2m/s}725Hz \\ f=782.1Hz \end{gathered}[/tex]

Next, use the following formula to determine the wavelength of the sound at observer, by using the previous result:

[tex]\lambda=\frac{v}{f_s}=\frac{345m/s}{782.1Hz}=0.441m[/tex]

Hence, the wavelength of the sound at the observer is 0.441 m

When a rubber band with a force constant of 58.7 N/m is stretched a certain distance,
there is 1.94 J of elastic potential NRG stored in it. How far has the band been stretched

Answers

According to the given statement the band has been stretched far  is  0.25 m.

What is the meaning of elastic potential?

The energy that is stored when a force is used to bend an elastic object is known as elastic potential energy. Until the force is released as well as the object springs returns to its original form, doing work in the process, the energy is retained. The object may be squeezed, stretched, or bent during the deformation.

What's an example of elastic potential energy?

For example, if you pull a spring, it will return to its initial form when you release it (energy input equals energy output.) Elastic potential energy is rendered possible by this.

Briefing:

U= 1.94 J

k  = 58.7  N/m

U = 1/2 kΔ x²

1.94 = 1/2 kΔ x²

3.88/58.7 = Δ x²

x = √(3.88 /58.7)

x = 0.25 m

To know more about Elastic potential visit:

https://brainly.com/question/14687790

#SPJ13

What is the momentum of a 934 kg car moving 10 m/s?

Answers

ANSWER:

9340 kg*m/s

STEP-BY-STEP EXPLANATION:

Given:

Mass (m) = 934 kg

Speed (v) = 10 m/s

The formula to calculate the momentum is as follows:

[tex]\begin{gathered} p=m\cdot v \\ \text{ we replacing} \\ p=934\cdot10 \\ p=9340\text{ kg*m/s} \end{gathered}[/tex]

The momentum of the car is 9340 kg*m/s.

Newton’s Second Law states “The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.” Explain how your observations in both a and b support this Law.

Answers

Newton’s Second Law states “The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.”

What is Newton's second law?

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

Force  = mass  × acceleration

Assuming the force constant the acceleration is inversely proportional to the mass of the object.

Thus, acceleration is directly proportional to force and inversely proportional to the mass of the body.

Learn more about Newton's second law, here, refer to the link

brainly.com/question/13447525

#SPJ1

A flywheel with a moment of inertia of 3.45 kg·m2is initially rotating. In order to stopits rotation, a braking torque of -9.40 N·m is applied to the flywheel. Calculate the initialangular speed of the flywheel if it makes 1 complete revolution from the time the brake isapplied until it comes to rest

Answers

Given data

*The given moment of inertia is I = 3.45 kg.m^2

*The given braking torque is T = -9.40 N.m

*The angular distance traveled is

[tex]\theta=(1\times2\pi)rad_{}[/tex]

*The final angular speed is

[tex]\omega=0\text{ rad/s}[/tex]

The angular acceleration of the flywheel is calculated by using the torque and moment of inertia relation as

[tex]\begin{gathered} T=I\alpha \\ \alpha=\frac{T}{I} \\ =\frac{-9.4}{3.45} \\ =-2.72rad/s^2 \end{gathered}[/tex]

The formula for the initial angular speed of the flywheel is given by the rotational equation of motion as

[tex]\omega^2-\omega^2_0=2a\theta[/tex]

Substitute the known values in the above expression as

[tex]\begin{gathered} (0)^2-\omega^2_0=2\times(-2.72)(2\pi) \\ \omega_0=\sqrt[]{2\times2.72\times2\pi} \\ =5.88\text{ rad/s} \end{gathered}[/tex]

Hence, the initial angular speed of the flywheel is 5.88 rad/s

Other Questions
4. Consider the number of NARRATIVES in this report. Why do you thinkBader includes so many? What other kinds of WELL-RESEARCHEDINFORMATION does she include, if any? What additional kinds ofinformation might she have used to help accomplish her purpose? find the reference angle for -0.8pi on one side of the balance scale, Henry placed gram weight. on the other side of the scale, he placed a ballet slipper. how many milligrams does the slipper weigh? A growing number of thieves are using keylogging programs to steal passwords and other personal information from Internet users. The number of keyloggingprograms reported grew approximately exponentially from 0.3 thousand programs in 2001 to 11.0 thousand programs in 2008. Predict the number of keyloggingprograms that will be reported in 2013 How might Ida tarbell's position cause conflict in the women's movement for suffrage? what is the business strategy here (or competing dimensions) and what is the appropriate process type to match with the strategy (e.g., assembly line or batch or job shop, etc.)? 7^2 7^8. 7^a------------ = -------- = 7^b7^4 7^4 Write an exponential function in the form y = ab that goes through points (0,18) and (3,6174). A card is drawn from a standard deck of fifty-two cards. What is the probability of selecting Jack or a red card? I need help on number 14!!! Please help and justify your answer!! PLEASE To produce g, function f was reflected over the x-axis andFunction g can be defined as Which equation has no solution? Find the perimeter pf the regular polygon. 5 (x+2) 7x+4 Leila wrote an equation to represent the revenue of a parking lot for one day. She let x represent the number of cars that paid to park and y represent the number of trucks that paid to park. If a car costs $8 per day, a truck costs $10 per day, and the total revenue for the day was $830, which equation could Leila use to represent the number of cars and trucks that paid to park that day?8 x + 10 y = 1,66010 x + 8 y = 1,6608 x + 10 y = 830 a credit policy that is too tight results in: multiple choice question. decreased sales volume accompanied by a high level of losses a low level of losses accompanied by an decrease in sales volume increased sales volume accompanied by a high level of losses which is not true? the uncoupling protein group of answer choices inhibits the formation of atp in mitochondria. is important for small mammals in cold climates. is a channel for protons like the atp synthase without the turbine part. occurs in all fat cells. is important for human newborns. find the Medina number of campsites.9,11,12,15,17,18 reba and sly enter into a contract by which reba promises to deliver newly printed marketing brochures to sly. reba later transfers her duty under the contract to troy. reba is Which graph represents the reflection of AABC over the line y = 0?-54-3 -2 -1S ONCH-3LO*CA2 3AB12X A barge is being towed by two tugboats, using ropes with force vectors as shown.