answer: 3057.44 m^3
Explanation:
This is Charles Law which is V1/T1=V2/T2 and temp must be in kelvin
So v2=V1 x T2/T1
v2= 3100 X 359.15 / 364.15 = 3057.44 m^3
t1= 91 +273.15 = 364.15
t2=86+273.15 =359.15
What type of intermolecular force will for between H2O AND CH3OH? Draw and label a picture of this bond. Explain in words how this bond forms.
Hydrogen bonding, which is unquestionably what we have, will occur from the intermolecular force between the molecules of H2O and CH3OH. Atoms trade or exchange valence electrons to create bonds.
How come we create bonds?Trust and self-esteem are developed in children and adolescents through strong emotional ties. After that, they can leave the family and establish wholesome friendships and other types of social ties. Healthy relationships consequently lower a child's chances of emotional discomfort or antisocial behaviour.
What exactly is a bonds, for example?The government of a country issues government bonds, a sort of fixed-interest bond. These bonds are thought of as low-risk investments. Examples of different kinds of government bonds include T - bills, Municipality Bond, Zero-Coupon Bonds, and others.
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How many moles of MgS are in 1.00g MgS?
Answer:
24.31 g/mol.
Explanation:
moles =mass/molar mass
n=w/m
42 grams of nitrogen gas react with
13 grams of hydrogen gas. What is the
limiting reactant and how many grams of
ammonia will be produced?
N2 + 3H22NH3
A) H2; 74 grams NH3 produced
B) H2; 4.3 grams NH3 produced
C) N2; 3.0 grams NH3 produced
D) N2; 51 grams NH3 produced
Answer:
d
Explanation:
Nitrogen is the limiting reactant.
42 g N2x (1mole N2/28 g N2) X (2 moles NH3/ 1mole N2) X (17 grams NH3/1mole NH3) = 51 g
13 g H2 x (1 mole H2/2 g H2) X (2 moles NH3/3moles H2) X (17 g NH3/1mole NH3) =73.66g
since 51 is smaller than 73.66 and it started with N2 that is why N2 is the limiting reactant)
A 25.0 kg iron weight lifting plate has a volume of 3180 cm3 . what is the density of the iron plate in g/cm3?
Answer:
The density of a substance is given by dividing the mass by the volume.
The S.I units of density are kg/m³, but can be measured by other units such as g/cm³
The mass of the iron is 29 kg or 29000 g
Therefore; Density = 29000 g/ 3680 cm³
= 7.880 g/cm³
Hence, the density of the iron plate is 7.880 g/cm³
Explanation:
When 25 mL of 1.0M H₂SO4 is added to 50 mL of 1.0 M NaOH at 25°C in a calorimeter,
the temperature of the aqueous solution increases to 33.9 °C. Assuming that the specific
heat of the solution is 4.18 J/g°C, that its density is 1.00/mL, and that the calorimeter
itself absorbs a negligible amount of heat, calculate the amount of heat absorbed for the
reaction.
Answer: The amount of heat absorbed for the reaction of 25 mL of 1.0 M H₂SO4 and 50 mL of 1.0 M NaOH, resulting in a temperature increase from 25°C to 33.9°C, is 10.14 kJ.
Explanation:
Ten years ago, a vacant lot in a subdivision was purchased for $30,500. The owner hired a general contractor to build a home on the lot. The contractor charged $375,000. The homeowner is planning to refinance the mortgage. The bank recently appraised the home at $410,000. What is the value of the property?
The value of the property at the end of the given time period is determined as $410,000.
What is the value of the property?The value of the property is the sum of the purchase price of the lot and the cost of building the home, which is:
$30,500 (purchase price of the lot) + $375,000 (cost of building the home) = $405,500
However, the bank has appraised the home at $410,000, which means that the value of the property has increased by $4,500.
Therefore, the value of the property is:
$405,500 (original value) + $4,500 (increase in value) = $410,000.
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L 4.4.2 Test (CST): Electricity and Energy Resources
Question 11 of 25
What happens to the field lines of two positive charges as the charges are
brought close together?
A. The field lines are attracted to the other charge.
B. The field lines cross together.
C. It would depend on what kind of positive charges they are.
D. The field lines bend away from the other charge.
SUBMIT
Answer:
D
Explanation:
because replusive force is much more
A helium filled balloon had a volume of 30.2 L on the ground at 28°C and a pressure of 745 torr. After the balloon was released, it rose to an altitude where the temperature was -8°C and the pressure was 495 torr. What was the volume of the gas in the balloon at this altitude?
Answer:
The final volume of gas in the balloon is 40.0 L (nearest tenth).
Explanation:
To solve this problem we can use the Combined Gas Law.
Combined Gas Law[tex]\boxed{\sf \dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}}[/tex]
where:
P₁ is the initial pressure.V₁ is the initial volume.T₁ is the initial temperature (measured in kelvin).P₂ is the final pressure.V₂ is the final volume.T₂ is the final temperature (measured in kelvin).Convert the temperatures given in Celsius to kelvin by adding 273.15:
[tex]\implies \sf 28^{\circ}C=28+273.15=301.15\;K[/tex]
[tex]\implies \sf -8^{\circ}C=-8+273.15=265.15\;K[/tex]
Therefore, the values to substitute into the formula are:
P₁ = 745 torrV₁ = 30.2 LT₁ = 301.15 KP₂ = 495 torrT₂ = 265.15 KSubstitute the values into the formula and solve for V₂:
[tex]\implies \sf \dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}[/tex]
[tex]\implies \sf \dfrac{745 \cdot 30.2}{301.15}=\dfrac{495 \cdot V_2}{265.15}[/tex]
[tex]\implies \sf V_2=\dfrac{745 \cdot 30.2 \cdot 265.15}{301.15 \cdot 495}[/tex]
[tex]\implies \sf V_2=40.01905...[/tex]
[tex]\implies \sf V_2=40.0\;L\;(nearest\;tenth)[/tex]
Therefore, the final volume of gas in the balloon is 40.0 L (nearest tenth).
In the reaction NH3(g) + O2(g) → NO(g) + H₂O(g) How many grams of H₂0 are generated when 1.54 moles of NH3 react?
Answer: 2.31 mole H2O
Explanation: blance the equation first
4 NH3 + 5O2 --> 4 NO + 6 H20
1.54 moles NH3 x ( 6 mole H20/ 4 moles NH3) X (18 g H20/1mole H20)
2.31 mole H20
Which of the following could be a useful IPM monitoring strategy to reduce crop damage from pests?
A.mating disruption devices B.noisemakers C.pesticides D.forecasting software
Answer:
C. pesticides
Explanation:
hope it helps :)
5. Use the formula that states the mass-to-volume ratio of a substance to solve the following:
(a) what is the density of a substance that has a mass of 7.9 g and a volume of 4.3 cm³?
(b) what is the mass of a substance that has a density of 8.9 g/cm³ and a volume of 5 cm³?
(c) what is the volume of a substance that has a density of 1.25 g/mL and a mass of 150 g?
Answer:
Explanation:
Part A
Density equals mass divided by volume. The units for density are g/cm³ or g/mL. Note that 1 cm³ = 1 mL.
d = m/v
Substitute the mass and the volume into the equation and then divide the bottom number into the top number.
d = 7.9 g/4.3 cm³ = 1.8 g/cm³
Part B
The density of a substance can be used as a conversion factor to find either the mass of the substance or the volume of the substance.
5 cm³ x 8.9 g/cm³ = 45 g
Note that cm³ units cancel and you are left with grams.
Part C
We will use the density of the substance to find the volume of the substance.
150 g x 1 mL/1.25 g = 120 mL
Note that you can invert density so the units of g cancel and you are left with mL.
The pressure of compressed air that occupies 2 L is 30.0 atm. What will be the new volume of the gas if the pressure is reduced to 10.0 atm if the temperature is not allowed to change? Ty in advance!
Answer:
To solve this problem, we can use the Boyle's Law equation, which states that the pressure and volume of a gas are inversely proportional at constant temperature.
Boyle's Law: P1V1 = P2V2
where P1 and V1 are the initial pressure and volume, and P2 and V2 are the new pressure and volume.
Using the given values:
P1 = 30.0 atm
V1 = 2 L
P2 = 10.0 atm
Substituting these values into the Boyle's Law equation, we get:
30.0 atm x 2 L = 10.0 atm x V2
Simplifying and solving for V2, we get:
V2 = (30.0 atm x 2 L) / 10.0 atm
V2 = 6 L
Therefore, the new volume of the gas will be 6 L if the pressure is reduced to 10.0 atm, assuming the temperature remains constant.
I Hope This Helps!
Zinc reacts with hydrochloric acid according to the reaction equation
Zn(s) + 2 HCl(aq) → ZnCl₂(aq) + H₂(g)
How many milliliters of 1.50 M HCl(aq) are required to react with 5.05 g Zn(s)?
volume: ___ mL
Answer:
many milliliters of 1.50 M HCl(aq) are required to react with 5.05 g Zn(s)?
volume: 16 mL
First, we need to calculate the number of moles of Zn:
m(Zn) = 5.05 g
M(Zn) = 65.38 g/mol (molar mass of Zn)
n(Zn) = m(Zn) / M(Zn) = 5.05 g / 65.38 g/mol = 0.0773 mol
According to the balanced chemical equation, 1 mole of Zn reacts with 2 moles of HCl. Therefore, the number of moles of HCl needed is:
n(HCl) = 2 × n(Zn) = 2 × 0.0773 mol = 0.1546 mol
Now we can use the molarity of the HCl solution to calculate the volume needed:
M(HCl) = 1.50 mol/L
n(HCl) = V(HCl) × M(HCl)
V(HCl) = n(HCl) / M(HCl) = 0.1546 mol / 1.50 mol/L = 0.103 L = 103 mL
Therefore, we need 103 mL of 1.50 M HCl(aq) to react with 5.05 g Zn(s).
A buffer solution is made using weak acid, HA, with a pKa of 6.98. If the ratio of [A-] to [HA] is 1.0 x 10^3, what is the pH of the buffer
Among the methods you researched, do you think there's one method that's effective in all situations? Explain your answer.
will give brainliest if answer quickly and CORRECT!!
Explanation:
I don't have a personal opinion, but I can say that there is no single research method that is effective in all situations.
Different research methods are appropriate for different types of research questions and situations. For example, if the research question is focused on understanding the relationship between two variables, a correlational research method may be appropriate. However, if the research question is focused on understanding the cause-and-effect relationship between variables, an experimental research method may be necessary.
In addition, some research methods may be more appropriate for certain types of data or populations, such as qualitative research methods for exploring subjective experiences or quantitative research methods for analyzing numerical data.
Therefore, researchers need to carefully consider their research question and choose the research method that is most appropriate for their specific situation.
The most standard and widely used research methods
Survey research
This method involves collecting data from a sample of individuals through questionnaires, interviews, or online surveys.
Experimental research
This method involves manipulating one variable (the independent variable) to observe its effect on another variable (the dependent variable) while controlling for other variables.
Observational research
This method involves observing and recording behavior in natural settings without any intervention or manipulation of variables.
Case study research
This method involves in-depth examination and analysis of a single case or a small group of cases to understand a particular phenomenon or situation.
Content analysis
This method involves analyzing and interpreting the content of documents, media, or other communication sources to identify patterns, themes, and trends.
These methods are commonly used across various fields of research, including social sciences, psychology, education, business, and healthcare. However, the choice of research method depends on the research question, the type of data needed, and the availability of resources.
Number 5 please.
Show work.
Mr Clink has the genotype IOIO
Mrs Clink has genotype IOIA
The child can not belong to them because the IAIB genotype is not in the Punnet square shown
What is genotype?Genotype refers to the genetic makeup of an organism, specifically the combination of alleles (different versions of genes) inherited from its parents. It determines the traits that an organism will express, including physical characteristics, behavioral traits, and susceptibility to certain diseases.
The mother's genotype in question 2 is IOIO
The father's genotype is IAIB
The baby belongs to them because it is possible from the Punnet square shown
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What is the percent of O in
Ca(С2H302)2?
(Ca = 40.08 g/mol, C = 12.01 g/mol,
H= 1.01 g/mol, O = 16.00 g/mol)
40.5%
Explanation:
Ca×1 = 40
C×4 = 48
H×6 = 6
O×4 = 64
64÷158×100% = 40.5%
. An IV solution contains 0.0175% of Drug Z, how much of this IV solution should we infuse, if the patient needs 100 mg of Drug Z?
If this solution is infusing at 50 ml/hr, how long will it take take to complete the infusion? Hint: 1mg = 0.001g or ml.
The infusion will be finished in 114.286 hours.
We need to infuse 100 mg of Drug Z. Since the IV solution contains 0.0175% of Drug Z, we can calculate the amount of IV solution needed for the infusion.
To do this, we need to use the following formula:
Amount of IV solution = [tex]\frac{(Amount of Drug Z * 100) }{ Concentration of Drug Z}[/tex]
Amount of IV solution = [tex]\frac{(100 mg * 100) }{0.0175 \% }[/tex]
Amount of IV solution = 5,714.286 ml
To calculate how long it will take to complete the infusion, we need to use the following formula:
Time to complete infusion =[tex]\frac{Amount of IV solution }{ Rate of infusion }[/tex]
Time to complete infusion =[tex]\frac{ 5,714.286 ml }{ 50 ml/hr }[/tex]
Time to complete infusion = 114.286 hr
Therefore, it will take 114.286 hours to complete the infusion.
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What happens to the solubility of gases in water as pressure increases?
Question 9 options:
solubility increases so less solute dissolves
solubility decreases so more solute dissolves
solubility increases so more solute dissolves
solubility decreases so less solute dissolves
Answer: Solubility increases so more solute dissolves
Explanation:
The solubility is a measure of the concentration of the dissolved gas particles in the liquid and is a function of the gas pressure. As you increase the pressure of a gas, the collision frequency increases and thus the solubility goes up, as you decrease the pressure, the solubility goes down.
5. The average human requires .66 moles of glucose (C6H1206) per day. How many mole
of CO2 (in the photosynthesis reaction) are required for this amount of glucose? The
photosynthetic reaction is: 6 CO2 + 6 H₂O ---> C6H12O6 + 6 02
Answer: 3.96 moles of CO2 are required in the photosynthesis reaction.
Explanation: The balanced equation for photosynthesis tells us that for every mole of glucose produced, 6 moles of CO2 are required. Therefore, to determine how many moles of CO2 are required for 0.66 moles of glucose, we can set up a proportion:
6 moles CO2 / 1 mole glucose = x moles CO2 / 0.66 moles glucose
Solving for x, we get:
x = (6 moles CO2 / 1 mole glucose) x (0.66 moles glucose / 1) = 3.96 moles CO2
Therefore, to produce 0.66 moles of glucose, 3.96 moles of CO2 are required in the photosynthesis reaction.
What's absolute zero?
A. The temperature at which all liquids freeze
B. The temperature at which water freezes
C. The coldest temperature ever recorded in nature on Earth
D. The temperature at which all molecular motion is stopped
Answer:
D. The temperature at which all molecular motion is stopped.Explanation:Absolute zero is the theoretical temperature at which all matter would have zero thermal energy and all molecular motion would stop. This temperature is equal to -273.15 degrees Celsius or -459.67 degrees Fahrenheit. It is the lowest possible temperature in the universe and cannot be reached in practice, as it is impossible to completely eliminate all thermal energy from matter.
Calculate the decrease in temperature when 6.0 L at 21.0 °C is compressed to 3.0 L.
The decrease in temperature is 147.075 K. The SI unit for temperature is the kelvin (K), but it can also be measured in degrees Celsius (°C) or Fahrenheit (°F).
What is Temperature?
Temperature is a physical property that measures the degree of hotness or coldness of an object or system, as compared to a standard reference point. It is a measure of the average kinetic energy of the particles (atoms or molecules) in a substance or system.
To solve this problem, we need to use the Charles's law equation which states:
V1/T1 = V2/T2
where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature.
We can rearrange the equation to solve for T2:
T2 = (V2/T2) x T1
First, we need to convert the initial temperature from Celsius to Kelvin by adding 273.15:
T1 = 21.0°C + 273.15 = 294.15 K
The initial volume (V1) is 6.0 L, and the final volume (V2) is 3.0 L. Substituting these values into the equation, we get:
(6.0 L/294.15 K) = (3.0 L/T2)
Solving for T2, we get:
T2 = (3.0 L x 294.15 K) / 6.0 L
T2 = 147.075 K
Finally, we can find the decrease in temperature by subtracting the final temperature (T2) from the initial temperature (T1):
ΔT = T1 - T2
ΔT = 294.15 K - 147.075 K
ΔT = 147.075 K
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How many mL of 2.25M H2SO4 are needed to react completely with 69.9g BaO2
Answer:
4 millllllermeeters jb
How many moles of MgS are in 100.g MgS?
The number or amount of moles of magnesium sulfide in 100g of MgS is 1.774 moles.
How to calculate number of moles?The number of moles in a substance can be calculated by dividing the mass of the substance by its molar mass as follows:
Mole is the base unit of amount of substance i.e. the amount of substance of a system which contains exactly 6.02214076 × 10²³ elementary entities.
no of moles = mass ÷ molar mass
According to this question, 100g of magnesium sulfide is given. The molar mass of magnesium sulfide is 56.38 g/mol.
moles = 100g ÷ 56.38g/mol
moles = 1.774 moles
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How many liters of a 3.58 MK2SO4 solution are needed to provide 85.1 g of K2SO4 (molar mass 174.01g/mol)? Recall that M is equivalent to mol/L.
Explanation:
Which of the following is already in its empirical formula?
-C22H34O10
-C6H6
-C6H1203
-C5H1202
-none of these
These substances C6H1203 don't already exist in their empirical formula.
How can the empirical formula in MCQS be found?The empirical formula is CH for both C2H2 and C2H6, as it represents the simplest whole number ratio of the various atoms in a molecule. The compound's molar mass is 314 g/mol, and the empirical formula mass is (2 X 12) + 1 + 80 = 105g. Hence, C6H3Br3 is the molecular formula.
What are C6H12O6 and C6H6's empirical formulas?Glucose has the chemical formula C6H12O6 = 6 x CH2O c.The molecular weight of glucose is 180 g/mol.. The empirical and molecular formulas are identical because it equals 6 x 30 g/mol.
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The temperature of an object increases by 38.1 °C when it absorbs 3647 J of heat. Calculate the heat capacity of the object.
The heat capacity of an object is defined as the amount of heat required to raise its temperature by 1 degree Celsius (or 1 Kelvin). It is denoted by the symbol "C" and has units of J/°C (Joules per degree Celsius) or J/K (Joules per Kelvin).
We can use the formula for heat capacity to calculate its value for the object:
[tex]C = \dfrac{Q}{\Delta T}[/tex]where:
Q is the amount of heat absorbed by the object andΔT is the change in temperature of the object.Substituting the given values, we get:
[tex]C = \dfrac{3647 \: J }{ 38.1\: ^{\circ}C}[/tex]Note that the units of temperature must match (either Celsius or Kelvin) in order for the calculation to be correct. Since the given change in temperature is in Celsius, we can use Celsius for the units of heat capacity as well.
Dividing, we get:
[tex]C = 95.8 \: J/^{\circ}C[/tex]Therefore, the heat capacity of the object is 95.8 J/°C. This means that it requires 95.8 Joules of heat to raise the temperature of the object by 1 degree Celsius (or Kelvin).
[tex]\rule{200pt}{5pt}[/tex]
Which emission spectrum represents the copper?
A.) Spectrum A
B.) Spectrum B
C.) Spectrum C
Answer:b
Explanation:i just did it
Consider the reaction for the formation of aluminum oxide from aluminum and oxygen.
4Al(s)+3O2(g)⟶2Al2O3(s)Δ1
Express the enthalpy of the following reaction, Δ2,
in terms of Δ1.
2Al2O3(s)⟶4Al(s)+3O2(g)Δ2
Express the enthalpy of the following reaction, Δ3,
in terms of Δ1.
12Al(s)+9O2(g)⟶6Al2O3(s)Δ3
Express the enthalpy of the following reaction, Δ4,
in terms of Δ1.
2Al(s)+32O2(g)⟶Al2O3(s)Δ4
To solve for Δ2, we need to reverse the reaction and change the sign of Δ1:
2Al2O3(s)⟶4Al(s)+3O2(g)Δ2 = -Δ1
Therefore, Δ2 = -Δ1.
To solve for Δ3, we need to add the reactions for the formation of two moles of Al2O3 from aluminum and oxygen:
4Al(s)+3O2(g)⟶2Al2O3(s)Δ1
2Al2O3(s)⟶4Al(s)+3O2(g)Δ3
Adding these equations gives:
12Al(s)+9O2(g)⟶6Al2O3(s)Δ3
Therefore, Δ3 = 2Δ1.
To solve for Δ4, we need to divide the reaction for the formation of two moles of Al2O3 by two:
2Al(s)+3O2(g)⟶Al2O3(s)Δ1/2
Multiplying this equation by 16 gives:
32Al(s)+48O2(g)⟶16Al2O3(s)8Δ1/2
We can then cancel out the formation of 14 moles of Al2O3:
2Al(s)+32O2(g)⟶Al2O3(s)Δ4 = 8Δ1/2 - 7Δ1
Therefore, Δ4 = 8Δ1/2 - 7Δ1.
calculate the mole fraction of HCl in a 9.8% (by mass) aqueous solution. the density of the solution is 1.03 g/mL
The mole fraction of HCl in the given solution is 0.051.
What is the mole fraction of the HCL?To calculate the mole fraction of HCl in the given solution, we need to first find the mass of HCl and water present in the solution.
Let's assume we have 100 g of the solution, so 9.8 g of it is HCl, and 90.2 g is water.
Next, we need to find the moles of HCl present in the solution.
To do this, we divide the mass of HCl by its molar mass.
The molar mass of HCl is 36.46 g/mol (1.01 g/mol for hydrogen + 35.45 g/mol for chlorine).
moles of HCl = 9.8 g / 36.46 g/mol = 0.269 mol
The moles of water can be calculated using its molar mass which is 18.015 g/mol.
moles of water = 90.2 g / 18.015 g/mol = 5.005 mol
The total number of moles in the solution is the sum of the moles of HCl and water.
total moles = 0.269 mol + 5.005 mol = 5.274 mol
The mole fraction of HCl can now be calculated by dividing the moles of HCl by the total number of moles.
mole fraction of HCl = 0.269 mol / 5.274 mol = 0.051
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