A __ is a polynomial with one term.

Answers

Answer 1

ANSWER

Monomial

EXPLANATION

A polynomial is a expression that contains variables, coefficients and sometimes constants.

These terms relate with one another by the use of mathematical signs like addition, subtraction, multiplication, etc

A polynomial with just one term is called monomial.

An example of a polynomial is:

[tex]x^2\text{ + x + 1}[/tex]

An example of a monomial is:

[tex]\begin{gathered} x^2 \\ or\text{ } \\ \frac{x}{2} \end{gathered}[/tex]

Answer 2

Answer:

monomial

Step-by-step explanation:


Related Questions

Translate the following word phrases to an algebraic expression and simplify: “8 times the difference of 6 times a number and 3”

Answers

SOLUTION:

Step 1:

In this question, we are meant to:

Translate the following word phrases to an algebraic expression and simplify:



“8 times the difference of 6 times a number and 3”

Step 2:

Assuming the unknown number be y, we have that:

[tex]\begin{gathered} 8\text{ ( 6y - 3 )} \\ =\text{ 48 y - 24} \end{gathered}[/tex]

CONCLUSION:

The final answer is:

[tex]48y\text{ - 24}[/tex]

Hey need your help it’s the one about the %

Answers

Answer:

[tex]\text{\$}$219.27$[/tex]

Explanation:

We were given that:

Pamela bought an electric drill at 85% off the original price (she bought it at 15% of the original price)

She paid $32.89 for the drill

The regular price is calculated using simple proportion as shown below:

[tex]\begin{gathered} 15\text{\%}=\text{\$}32.89 \\ 100\text{\%}=\text{\$}x \\ \text{Cross multiply, we have:} \\ x\cdot15\text{\%}=\text{\$}32.89\cdot100\text{\%} \\ x=\frac{\text{\$}32.89\cdot100\text{\%}}{15\text{\%}} \\ x=\text{\$}219.27 \\ \\ \therefore x=\text{\$}219.27 \end{gathered}[/tex]

Therefore, the regular price was $219.27

OA.y> -22² +10z - 8OB. y<-2x² +102-8OC. y2-22² +10r - 8OD. y ≤-22² +10z - 8

Answers

Solution:

Using a graph plotter,

The correct answer that satisfies the graph is OPTION C.

9Which is the best name for a quadrilateral with vertices at A(5,-2), B(2,2), C(1,-5), and D(-2,-1)?A parallelogramB squarerhombusD rectangle

Answers

Answer:

Parallelogram. Option A is correct

Explanations:

In order to determine the best name for a quadrilateral with the given vertices, we will find the measure of the distance AB, BC, CD, and AD using the distance formula as shown;

[tex]D=\sqrt[]{(x_2-x_1)^2+(y_2-y^{}_1)^2}[/tex]

For the measure of AB with coordinates A(5,-2), B(2,2);

[tex]\begin{gathered} AB=\sqrt[]{(5-2)^2+(-2-2^{}_{})^2} \\ AB=\sqrt[]{3^2+(-4)^2} \\ AB=\sqrt[]{9+16} \\ AB=\sqrt[]{25} \\ AB=5 \end{gathered}[/tex]

For the measure of BC with coordinates B(2,2) and C(1, -5)

[tex]\begin{gathered} BC=\sqrt[]{(2-1)^2+(2-(-5^{}_{}))^2} \\ BC=\sqrt[]{1^2+7^2} \\ BC=\sqrt[]{50} \\ BC=5\sqrt[]{2} \end{gathered}[/tex]

For the measure of CD with coordinates C(1,-5), and D(-2,-1);

[tex]\begin{gathered} CD=\sqrt[]{(1-(-2))^2+(-5-(-1^{}_{}))^2} \\ CD=\sqrt[]{3^2+(-4)^2} \\ CD=\sqrt[]{9+16} \\ CD=\sqrt[]{25} \\ CD=5 \end{gathered}[/tex]

For the measure of AD with coordinates A(5, -2), and D(-2,-1);

[tex]\begin{gathered} AD=\sqrt[]{(5-(-2))^2+(-2-(-1^{}_{}))^2} \\ AD=\sqrt[]{(5+2)^2+(-2+1)^2} \\ AD=\sqrt[]{7^2+(-1)^2} \\ AD=\sqrt[]{50} \\ AD=5\sqrt[]{2} \end{gathered}[/tex]

For the slopes;

Check if the length AB is perpendicular to AD

[tex]\begin{gathered} m_{AB}=\frac{2+2}{2-5} \\ m_{AB}=-\frac{4}{3} \end{gathered}[/tex]

For the slope of AD

[tex]\begin{gathered} m_{AD}=\frac{-1+2}{-2-5} \\ m_{AD}=-\frac{1}{7} \end{gathered}[/tex]

Since AB is not perpendicular to AD, hence the quadrilateral is not a rectangle and also not a square or rhombus since all the sides are not equal.

From the given distances, you can see that opposite sides are equal (AB = CD and BC = AD ), hence the best name for a quadrilateral is a parallelogram.

Plot the x-intercept(s), y-intercept, vertex, and axis of symmetry of this function:h(x) = (x − 1)^2− 9.

Answers

The function is

[tex]h(x)=(x-1)^2-9[/tex]

1) x-intercept(s)

The x-intercepts refer to the points on which the function intercepts with the x-axis, in other words, when y=h(x)=0

So, given that condition, we get

[tex]\begin{gathered} h(x)=0 \\ \Rightarrow(x-1)^2-9=0 \\ \Rightarrow x^2-2x+1^{}-9=0 \\ \Rightarrow x^2-2x-8=0 \\ \Rightarrow(x-4)(x+2)=0 \end{gathered}[/tex]

Therefore, there are two x-intercepts, and those are the points

[tex](4,0),(-2,0)[/tex]

2) y-intercepts

The y-intercepts happen when x=0. So,

[tex]\begin{gathered} x=0 \\ \Rightarrow h(0)=(0-1)^2-9=1-9=-8 \end{gathered}[/tex]

So, there is only one y-intercept and it's on the point (0,-8)

3) Vertex

The general equation of a parabola is

[tex]y=f(x)=a^{}x^2+bx+c[/tex]

There is another way to express the same function, which is called the 'vertex form':

[tex]\begin{gathered} y=f(x)=a(x-h)^2+k \\ \Rightarrow y=ax^2-2ahx+ah^2+k \end{gathered}[/tex]

What is particularly useful of this vertex form is that the vertex is the point (h,k)

So, transforming h(x) into vertex form:

[tex]\begin{gathered} h(x)=(x-1)^2-9=a(x-h)^2+k \\ \Rightarrow\begin{cases}a=1 \\ h=1 \\ k=-9\end{cases} \end{gathered}[/tex]

Therefore, the vertex is the point (h,k)=(1,-9)

4) Axis of symmetry

In general, the equation of the axis of symmetry is given by

[tex]x=-\frac{b}{2a};y=f(x)=ax^2+bx+c[/tex]

Therefore, in our particular problem,

[tex]\begin{gathered} h(x)=x^2-2x-8=ax^2+bx+c \\ \Rightarrow\begin{cases}a=1 \\ b=-2 \\ c=-8\end{cases} \\ \end{gathered}[/tex]

Thus, the equation of the line that is the axis of symmetry is

[tex]x=-\frac{b}{2a}=-\frac{(-2)}{2\cdot1}=-\frac{(-2)}{2}=1[/tex]

Then, the axis of symmetry is the line x=1.

Summing up the information in the four previous steps, we get

passes through (1,3) and parallel to y=-x

Answers

The equation of a line parallel to y=-x and passes through (1,3) is x+y=4

What is the relationship between coordinates and the equation of a line?

The coordinates of a line pass through the equation of a line.

What is the relationship between two parallel lines?  

Two parallel lines make the same angle with respect to the x-axis ie. make the same slope.

We have been given that the line is parallel to y=-x or x+y=0

Thus, they will be having the same slope which is -1.

Since, in the equation Ax+By+C=0, the slope is equal to -A/B

So putting the values in the equation y=mx+c where m is the slope and c is the constant

y=-x+c

Now we know that the equation passes through (1,3)

So, putting values 1=-3+c which gives c=4

Therefore, the equation of the line is y=-x+4 or x+y=4.

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Suppose A and B are points on the number line. If AB=10 and B lies at -6, where could A be located?

Answers

Answer: 16 or 4

Step-by-step explanation:

-6-10=-16

10-6=4

Question : Suppose A and B are points on the number line. If AB=10 and B lies at -6, where could A be located?

Answer: 16

A family eats at a restaurant. The bill is $42. The family leaves a tip and spends $49.77. How much was the tip as a percentage of the bill?

Answers

[tex]\begin{gathered} \text{tip}=49.77-42=7.77 \\ \text{Percentage of the bill=}\frac{7.77}{42}=0.185 \end{gathered}[/tex]

Percentage of the bill = 0.185*100=18.5%

The proof below may or may not be correct. If the proof is incorrect, determine the first step number that is not justified and the reason it is not justified.

Answers

The first step number that is not justified and the reason it is not justified:

From the attached image

[tex]<\text{ECF}\cong

Step 1: is said to be correct cause all the range are equivalent and parallel

Step 2: is said to be correct AECF is a parrelologram because it is a quadilateral with two opposite equal sides

Step 3: is correct

[tex]\begin{gathered} \Delta BEC\cong\Delta\text{ECF}\ldots\text{..} \\ \text{parallel lines cut by a transverse form congruent alternate interior angle.} \end{gathered}[/tex]

Step 4: is correct

[tex]<\text{BEC}\congStep 5: is correct [tex]<\text{BEC}\cong

Step 6 : is not correct , because corresponding parts of the congruent triangle are not congruent.

Step 7: is correct , because its a rhombus.

How do we determine the strength of a correlation?
OA. The more closely two variables follow the general trend, the stronger the correlation (which may be positive or negative).
GB. Negative correlation is stronger than no correlation. Positive correlation is stronger than negative correlation.
OC. The more closely two variables follow the general trend, the weaker the correlation (which may be positive or negative).
OD. No correlation is stronger than negative correlation. Positive correlation is stronger than no correlation

Answers

We can determine the strength of a correlation by A. The more closely two variables follow the general trend, the stronger the correlation (which may be positive or negative).

What is correlation?

Correlation is a statistical term that reflects how closely two or more variables are related to one another. Correlation is measured on a scale of -1 to +1, with 0 indicating a negative correlation and > 0 indicating a positive correlation. A value of 0 implies that there is no association.

A positive correlation is a two-variable association in which both variables move in lockstep. A positive correlation exists when one variable declines while the other increases, or when one variable increases while the other falls. The number one represents a perfect positive association.

If there is an increase or decrease in one variable results in increase or decrease in the other then there is correlation. If the value of correlation is close to either extremities (+1 or +1) then there is strong correlation.

Learn more about correlation on:

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Tj earns a 20% commission on all sales plus a base salary of 40k. his total income last year was at least 70k. which inequality can be used to calculate the minimum of Tj sales.

Answers

Let x be the all sale for individual.

Determine the expression for total income of individual.

[tex]\frac{20}{100}x+40000=0.2x+40000[/tex]

The total income was at least 70000. So last year income is 70000 or more than 70000.

Setermine the inequality for the sales.

[tex]\begin{gathered} 0.2x+40000-40000\ge70000-40000 \\ \frac{0.2x}{0.2}\ge\frac{30000}{0.2} \\ x\ge150000 \end{gathered}[/tex]

Americans who are 65 years of age or older make up 13.2% of the total population. If there at 30.3 million american in this age group, find the total u.s. population

Answers

Given:

Americans who are 65 years of age or older make up 13.2% of the total population.

Required:

The total u.s. population

Explanation:

Let the total population of u.s be x.

According to the given condition.

[tex]13.2\text{ \% of x = 30.3 billion}[/tex]

Therefore,

[tex]\begin{gathered} \frac{13.2}{100}\text{ }\times\text{ x = 30.3} \\ x\text{ = }\frac{30.3\text{ }\times\text{ 100}}{13.2} \\ x\text{ = 229.55 billion} \end{gathered}[/tex]

Answer:

Thus the total population of u.s is 229.55 billion.

Which equation has the same solution as x2 + 8x – 17 = -8? Submit Answer (3-4)2 = -7 O (2+4)2 = 25 O (x – 4)2 = 25 (x - 1)² = -7 problem 3 out of max 6

Answers

Given

[tex]x^2+8x-17=-8[/tex]

Procedure

[tex]\begin{gathered} x^2+8x+16-16-17=-8 \\ (x+4)^2=16+17-8 \\ (x+4)^2=25 \end{gathered}[/tex]

The answer would be (x+4)^2 = 25

AABC - ADEF? Explain your reasoning. E 6 units C 40° 9 units 4 units 6 units er your answer and explanation.

Answers

Side-Angle-Side Theorem states that triangles are congruent if any pair of corresponding sides and their included angle are congruent.

How do we know that their sides are congruent, by similarity ratios, means a ratio of the lengths of the sides to see if they have the same ratio or scale factor:

[tex]\begin{gathered} \frac{9}{6}=1.5 \\ \frac{6}{4}=1.5 \end{gathered}[/tex]

Then, since their sides are congruent and they have the same angle, they are congruent by SAS.

triangle OPQ is similar to triangle RST. Find the measure of side RS. Round your answer to the nearest tent if necessary

Answers

To answer this question, we have that, if two triangles are similar, they maintain the same proportion on their corresponding sides.

We have that the corresponding sides are QP and TS, OP and RS, and QO and TR, so we can write:

[tex]\frac{TS}{QP}=\frac{RS}{OP}=\frac{TR}{QO}[/tex]

Then, since we have the values for QP, TS, and OP, we can find RS using the above proportion:

[tex]\frac{TS}{QP}=\frac{RS}{OP}\Rightarrow\frac{41.4}{11}=\frac{RS}{8}\Rightarrow RS=\frac{41.4\cdot8}{11}=\frac{331.2}{11}\Rightarrow RS=30.109090\ldots[/tex]

Then, we have that we can round this value to 30.11 units, and if we round the answer to the nearest tenth, we finally have that RS = 30.1 units.

Answer:

x = 30.1  (round 30)

Step-by-step explanation:

being similar we can solve with a simple equation

11 : 8 = 41.4 : x

x = 8 × 41.4 : 11

x = 331,2 : 11

x = 30.1  (round 30)

Find the area of the yellow region. Round to the nearest tenth. 7.53cm

Answers

The figure shows a square inscribed in a circle of radius r = 7.53 cm.

The yellow region corresponds to the area of the circle minus the area of the square.

The area of a circle of radius r is:

[tex]A_c=\pi r^2[/tex]

Calculating:

[tex]A_c=\pi(7.53\text{ cm})^2=178.13\text{ }cm^2[/tex]

The radius of the circle is half the diagonal of the square. The diagonal of the square is:

d = 2 x 7.53 cm = 15.06 cm

The area of a square, given the diagonal d, is calculated as follows:

[tex]A_s=\frac{d^2}{2}[/tex]

Calculating:

[tex]\begin{gathered} A_s=\frac{(15.06\text{ cm})^2}{2} \\ \\ A_s=113.40\text{ }cm^2 \end{gathered}[/tex]

The required area is:

A = 178.13 - 113.40 = 64.73 square cm

Sally deposits $2,500 at 8% interest for 3 years . How much can she withdraw at the end of that period

Answers

ANSWER

$3100

EXPLANATION

Sally deposits $2500 at 8% interest for 3 years.

We want to find the amount she can withdraw at the end of the period.

To know this, we have to first find the interest.

Simple Interest is given as:

[tex]\begin{gathered} SI\text{ = }\frac{P\cdot\text{ R }\cdot\text{ T}}{100} \\ \text{where P = principal = \$2500} \\ R\text{ = rate = 8\%} \\ T\text{ = 3 years} \end{gathered}[/tex]

Therefore:

[tex]\begin{gathered} SI\text{ = }\frac{2500\cdot\text{ 8 }\cdot\text{ 3}}{100} \\ SI\text{ = }\frac{60000}{100} \\ SI\text{ = \$600} \end{gathered}[/tex]

Therefore, after 3 years the interest will be $600.

The amount she can withdraw after this period is therefore the sum of the principal and the interest:

$2500 + $600 = $3100

She can withdraw $3100 at the end of the period.

Which cosine function has maximum of 2, a minimum of –2, and a period of 2pi/3 ?

Answers

Given:

maximum = 2, minimum = -2

period = 2π/3

Find: the cosine function having those attributes stated above

Solution:

Cosine equations follow the pattern below:

[tex]y=Acos(B(x-C))+D[/tex]

where A = amplitude, B = 2π/period, C = horizontal shift, and D = vertical shift.

Since the only given information is the period, let's calculate for the value of B.

[tex]B=\frac{2\pi}{period}\Rightarrow B=\frac{2\pi}{\frac{2\pi}{3}}=3[/tex]

Out of the choices, only y = 2cos 3θ has the value of B which is 3. Hence, y = 2cos 3θ is the cosine function that has a maximum of 2, a minimum of –2, and a period of 2pi/3. (Option 3)

Find d the side length of a square given the area of the square

Answers

Area of a square = side length ^2

Given: A= 20.25

Replacing:

20.25 = s^2

√20.25 = s

s = 4.5 m

Create a polynomial of degree 6 that has no real roots. Explain why it has no real roots.

Answers

Answer:

Explanation:

We're asked to create a polynomial of degree 6 that has no real roots.

Let's consider the below polynomial;

[tex]x^6+1=0[/tex]

To determine its roots, we'll follow the below steps;

Step 1: Subtract 1 from both sides of the equation;

[tex]undefined[/tex]

Calculate the determinant of this 2x2 matrix. Provide the numerical answer. |2 -1 | |4 -5|

Answers

Given the matrix

[tex]\begin{bmatrix}{a} & {b} & {} \\ {c} & {d} & {}{}\end{bmatrix}[/tex]

its determinant is computed as follows:

ad - cb

In this case, the matrix is

[tex]\begin{bmatrix}{2} & {-1} & \\ {4} & -5 & {}\end{bmatrix}[/tex]

and its determinant is

2(-5) - 4(-1) = -10 - (-4) = -10 + 4 = -6

Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.(14+3)(2 x 6)B▸ Math symbols▸ Relations▸ Geometry▸ Groups▸ TrigonometryStatistics▸ Greek

Answers

Given:

The given mathematical expression is,

[tex](14+3)-(2\times6)[/tex]

Required:

To solve the given expression.

Explanation:

Let us solve the given mathematical expression by using BODMAS rule.

Therefore, first, we calculate within brackets and then will perform subtraction.Thus, we get,

[tex]\begin{gathered} (14+3)-(2\times6) \\ =17-12 \\ =5 \end{gathered}[/tex]

Final Answer:

The solution of the given mathematical expression is, 5.

In the similaritytransformation of AABCto ADFE, AABC was dilated bya scale factor of 1/2, reflected4 across the x-axis, and movedthrough the translation [? ].

Answers

We have to identify the translation.

We can see that the green triangle represents the transformation of triangle ABC after a dilation with a scale factor of 1/2 and a reflection across the x-axis.

We can then find the translation in each axis from the image as:

Triangle is DEF is translated 3 units to the left (and none in the vertical axis).

We can express this translation as this rule:

[tex](x+3,y+0)[/tex]

Answer: (x+3, y+0)

ABCD is a rectangle. Find the length of AC and the measures of a and f.

Answers

SOLUTION

Consider the diagram

We need to obtain the value of length AC

Using the pythagoras rule, we have

[tex]undefined[/tex]

find the values of x y and z.The answers are in degrees.

Answers

Answer

x = 35°

y = 145°

z = 25°

Explanation

We are told to solve for x, y and z.

Considering the first triangle with angles 55°, x° and the right angle (90°).

The sum of angles in a triangle is 180°.

So,

x° + 55° + 90° = 180° (Sum of angles in a triangle is 180°)

x° + 145° = 180°

x = 180° - 145° = 35°

Then, we can solve for y. Angles x and y are on the same straight line, and the sum of angles on a straight line is 180°

x° + y° = 180°

35° + y° = 180°

y° = 180° - 35°

y° = 145°

We can then solve for z°. The big triangle has angles (55° + 10°), z° and the right angle (90°).

The sum of angles in a triangle is 180°.

So,

55° + 10° + z° + 90° = 180°

z° + 155° = 180°

z = 180° - 155°

z° = 25°

Hope this Helps!!!

VIP at (-2,7) dropped her pass and moved to the right on a slope of -9. Where can you catch up to her to return her VIP pass? I know the answer is (-1 ,-2) my question is how do you solve to get the answer?

Answers

we are told that VIP is located at (-2,7) and then she drops her pass. Then she moves on a slope of -9. To determine where you can catch up, we simply analyze what would be the next position by incrementing x by 1.

In this case, we are told that the slope is -9.

Recall that given points (a,b) and (c,d) the slope of the line that joins this points is given by

[tex]m=\frac{d-b}{c-a}=\frac{b-d}{a-c}[/tex]

Lets call the next point (-1,y) . So using this, we have

[tex]\text{ -9=}\frac{y\text{ - 7}}{\text{ -1 -(-2)}}=\frac{y\text{ -7}}{2\text{ -1}}=y\text{ -7}[/tex]

So, by adding 7 on both sides, we get

[tex]y\text{ = -9+7 = -2}[/tex]

So, the next position, following a slope of -9 and starting at (-2,7) is (-1,-2)

what is the slope formula of (4,2) and (7, 6.5)

Answers

Suppose the given coordinates are represented as,

[tex]\begin{gathered} (x_1,y_1)=(4,2) \\ (x_2,y_2)=(7,6.5) \end{gathered}[/tex]

Then, the formula for slope can be expressed as,

[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{6.5-2}{7-4} \end{gathered}[/tex]

Solving it,

[tex]m=\frac{4.5}{3}=1.5[/tex]

The slope is 1.5.

The formula of (10, 8) anjd (-5,8) is

[tex]m=\frac{8-8}{-5-10}[/tex]

I'll send a pic of it

Answers

Solution:

Since the slope of the given function represents the rate at which the temperature changes, the answer is the slope of the equation, that is, the correct solution would be:

[tex]0.7[/tex]

I just want to go to sleep but I need the answer to this question

Answers

The average rate of change of a function f(x) from x1 to x2 is given by:

[tex]\frac{f(x_2)-f(x_1)}{x_2-x_1}[/tex]

In this case we need the first three seconds so x1=0 and x2=3.

Calculate the values of the function at x=0 and x=3 to get:

f(0)=150 and f(3)=0.

Substitute these values into the formula for average rate of change:

[tex]\begin{gathered} \frac{f(3)-f(0)}{3-0} \\ =\frac{0-150}{3} \\ =\frac{-150}{3} \\ =-50 \end{gathered}[/tex]

Hence the avearage rate of change of the function for the first three seconds is -50.

Note that the negative sign shows that the function is decreasing in the time interval (first three seconds).

what is the substitution for f7=3(x)^2+2(x)-9

Answers

Given a function f(x), whenever you want to evaluate the function, you simply change the variable for the value you where you want to evaluate the function at, and then perform the mathematical operations the function tells you to do.

In our case f(x) = 3x^2 + 2x -9

If we evaluate f(x) at x=7, then

[tex]f(7)=3(7)^2+2(7)\text{ -9 = 3 }\cdot\text{ 49 + 2}\cdot\text{ 7 - 9 = 152}[/tex]

So f(7) = 152.

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