Answer:
Null Hypothesis - True average compressive strength of mixture of pulverized fuel ash and Portland cement is more than 1300 KN/m2.
Type I error (false positive) - this occur when the True average compressive strength of mixture of pulverized fuel ash and Portland cement is not more than 1300 KN/m2 in actual scenario but the measurements shows an incorrect reading of True average compressive strength greater than 1300 KN/m2.
Type II error (false-negative)- his occur when the True average compressive strength of mixture of pulverized fuel ash and Portland cement is more than 1300 KN/m2 in actual scenario but the measurements show an incorrect reading of True average compressive strength less than 1300 KN/m2.
Explanation:
The hypothesis for this piece of information is as follows -
Null Hypothesis - True average compressive strength of mixture of pulverized fuel ash and Portland cement is more than 1300 KN/m2.
Alternate hypothesis - True average compressive strength of mixture of pulverized fuel ash and Portland cement is less than or equal to 1300 KN/m2
Type I error (false positive) - this occur when the True average compressive strength of mixture of pulverized fuel ash and Portland cement is not more than 1300 KN/m2 in actual scenario but the measurements shows an incorrect reading of True average compressive strength greater than 1300 KN/m2.
Type II error (false-negative)- his occur when the True average compressive strength of mixture of pulverized fuel ash and Portland cement is more than 1300 KN/m2 in actual scenario but the measurements show an incorrect reading of True average compressive strength less than 1300 KN/m2.
How do guest room hotel smoke alarms work and differ then regular home versions?
Answer: As to the more sophisticated way of detecting "smoke" from an object a human may use in hotel rooms, this sensor called a Fresh Air Sensor does not just detect and, and but alerts the management about a smoking incident in a hotel room
A resistor, inductor, and capacitor are in parallel in a circuit where the frequency of operation can vary. The R, L, and C values are such that at the frequency omega subscript 0, the magnitude of all the impedances are equal to each other. If the frequency of operation approaches zero, which element will dominate in determining the equivalent impedance of this parallel combination?
a. The inductor.
b. The capacitor.
c. The resistor.
d. Insufficient information provided.
Answer:
Option A is correct
Explanation:
As we know
Inductive Susceptance = ½(pi)*f*L
Or Inductive Susceptance is inversely proportional to the frequency
Likewise conductive Susceptance = 2 (pi)*f*C
Conductive Susceptance is directly proportional to the frequency
When the frequency will reach the value zero, then the Inductive Susceptance will become infinite
Hence, inductor will dominate in determining the equivalent impedance of this parallel combination
Option A
where can I find solved problems of advanced soil structure interaction?
The seismic response of nuclear power plant structures is often calculated using lumped parameter methods. A finite element model of the structure is coupled to the soil with a spring-dashpot system used to represent the interaction process. The parameters of the interaction model are based on analytic solutions to simple problems which are idealizations of the actual problems of interest. The objective of the work reported in this paper is to compare predicted responses using the standard lumped parameter models with experimental data. These comparisons are shown to be good for a fairly uniform soil system and for loadings that do not result in nonlinear interaction effects such as liftoff. 7 references, 7 figures.