A new planet is discovered orbiting a star with a mass of [tex]3.5\times 10^{31}[/tex] kg at a distance of [tex]1.2\times10^{11}[/tex] m. Assume that the orbit is circular. What is the orbital speed of the planet? What is the orbital period of the planet?

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Answer 1

The orbital speed of the planet is [tex]4.41 * 10^3 m/s[/tex] and the orbital period of the planet is 22.608s when its mass is [tex]3.5 * 10^{31}kg.[/tex]

The mass of the planet (m) = [tex]3.5 * 10^{31}kg[/tex]

The distance of star from the planet (r) = [tex]1.2 * 10^{11}m[/tex]

The planet is moving in circular shape around the star.

The orbital speed of the planet = v

The orbital speed of the planet can be calculated using the equation for the orbital speed, which is given by [tex]v = \sqrt{(GM/r)}[/tex], where G is the gravitational constant = [tex]6.67 * 10^{-11} m^3/(kg*s^2)[/tex]

[tex]v = \sqrt{6.67 * 10^{-11} m^3/(kg*s^2) * 3.5 * 10^{31}kg/1.2 * 10^{11}m}[/tex]

[tex]v = \sqrt{23.345 * 10^{20}/1.2 * 10^{11}} = \sqrt{19.45 * 10^9}[/tex]

[tex]v = 4.41 * 10^3 m/s[/tex]

the orbital speed of the planet is = [tex]4.41 * 10^3 m/s[/tex]

The orbital time period of the planet can be calculated using the equation for the orbital period, which is given by [tex]T = 2 * \pi * \sqrt{(r^3/GM)}[/tex]

[tex]T = 2 * \pi * \sqrt{(1.2 * 10^{11})^3/6.67 * 10^{-11} m^3/(kg*s^2) * 3.5 * 10^{31}kg}[/tex]

[tex]T = 2 * \pi * \sqrt{(1.2 * 10^{11})^3/23.345 * 10^{20}}[/tex]

[tex]T = 2 * \pi * \sqrt{0.07 * 10^{13}}[/tex]

[tex]T = 2 * \pi * 0.26 * 3.9[/tex]

T = 22.608s

Hence the orbital period of the planet is 22.608s

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Related Questions

alston and thana discuss the electric force, and thana challenges alston to think of a force that is not fundamentally an electric force. which of alston's responses is correct?

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The electric force is the force that exists between two electrically charged objects or particles. The force is either repulsive or attractive depending on whether the objects have the same or opposite charges, respectively. Electric force can be calculated using Coulomb's law.

Alston answered that gravity is a force that is not fundamentally an electric force. This statement is correct because gravity is a fundamental force that acts between two massive objects. It does not depend on electric charges. The force of gravity is always attractive and can be calculated using Newton's law of universal gravitation.

The other fundamental forces in the universe are the strong nuclear force and the weak nuclear force. These forces are responsible for holding the nucleus of an atom together and are not electric in nature.    

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what is the distance between your eye and the image of the butterfly in the mirror? explain your answer.

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The distance between your eye and the image of the butterfly in the mirror is: the same as the distance between your eye and the actual butterfly

The distance between your eye and the image of the butterfly in the mirror is the same as the distance between your eye and the actual butterfly, which is the sum of the distance from your eye to the mirror and the distance from the mirror to the butterfly.

To calculate this, we need to measure the distance from your eye to the mirror, which can be done using a ruler or tape measure, and then measure the distance from the mirror to the butterfly, which can be done using a ruler or tape measure as well. Once we have these two measurements, we can simply add them together to get the total distance between your eye and the image of the butterfly in the mirror.

To clarify further, let's use an example. If your eye is 10 cm away from the mirror and the butterfly is 30 cm away from the mirror, then the total distance between your eye and the image of the butterfly in the mirror is 40 cm. This is because 10 cm (from your eye to the mirror) + 30 cm (from the mirror to the butterfly) = 40 cm.

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jacob asks imad to explain to jacob how the number of field lines and the magnitude of the charge are related. which response is correct?

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To explain to Jacob how the number of field lines and the magnitude of the charge are related, Imad should mention that the number of field lines is proportional to the magnitude of the charge.

There is a relationship between the number of field lines and the magnitude of the charge. The magnitude of the charge is directly proportional to the number of field lines that pass through the surface that is perpendicular to the field lines. The number of field lines created by a charge or charges is proportional to the charge or charges' magnitude.

In the absence of any other charges or objects, the field lines emanating from a charge with magnitude q will terminate on another charge with magnitude q of opposite polarity, according to Coulomb's law. Therefore, Jacob should be told that the number of field lines is proportional to the magnitude of the charge, meaning that if the charge's magnitude increases, the number of field lines will increase as well.

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10. does the vertical speed of a segment of a horizontal taut string through which a sinusoidal, transverse wave is propagating depend on the wave speed of the transverse wave?

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The vertical speed of a segment of a horizontal taut string through which a sinusoidal, transverse wave is propagating depends on both the wave speed and the amplitude of the transverse wave.

The transverse wave and wave speed for vertical speed of a segment also depends on factors like:

The wave speed of a transverse wave on a string is determined by the tension in the string and the mass per unit length of the string, as well as the properties of the medium through which the wave is propagating. This wave speed does not directly determine the vertical speed of a segment of the string.However, the amplitude of the transverse wave does affect the vertical speed of a segment of the string. The greater the amplitude of the wave, the greater the maximum vertical displacement of the string from its rest position, and thus the greater the vertical speed of a segment of the string at that point.The vertical speed (v) of a segment of a horizontal taut string through which a sinusoidal, transverse wave is propagating can be expressed mathematically as: v = Aωcos(ωt)

        where 'A' is the amplitude of the transverse wave,

        'ω' is the angular frequency of the wave,

         't' is the time, and

        'cos' is the cosine function.

The wave speed [tex](v_w)[/tex]of a transverse wave on a string is given by: [tex]v_w[/tex] = [tex]\sqrt{(T/u)[/tex]

        where 'T' is the tension in the string and

         'u' is the mass per unit length of the string.

So while the wave speed does not directly determine the vertical speed of a segment of the string, it does affect the angular frequency of the wave (which is related to the wave speed) and thus indirectly affects the vertical speed of a segment of the string through the amplitude of the wave.

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how are thew avelength, freequency, and speed of a wave realted? how do they depend on the medium through which the wave is passing and the type of wave

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Wavelength, frequency, and speed of wave are related by the following formula:v = fλ

where v is the speed of the wave, f is the frequency of the wave, and λ is the wavelength of the wave.

In terms of the medium through which the wave is passing, the speed of the wave depends on the properties of the medium. The speed of a wave traveling through a medium depends on the medium's elasticity and density. The type of wave, such as sound or light, will also determine the speed of the wave.In terms of wavelength and frequency, they are inversely proportional. This means that if the wavelength increases, the frequency decreases, and if the wavelength decreases, the frequency increases. This is expressed by the formula:f = v/λSo, as the speed of the wave increases, the wavelength increases, and the frequency decreases. Conversely, as the speed of the wave decreases, the wavelength decreases, and the frequency increases.

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how much charge, in micro-coulombs, must be transferred from the negatively charged to the positively charged plate to increase the potential difference between them by 77 v?

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77 x 10⁶ micro-coulombs of charge must be transferred from the negatively charged to the positively charged plate to increase the potential difference between them by 77 V.

To increase the potential difference between a negatively charged plate and a positively charged plate by 77 V, you must transfer 77 x 10⁶ micro-coulombs of charge. This can be calculated using the equation:

Q = V * (10⁶)

where Q is the charge in micro-coulombs and V is the potential difference in Volts.

Plugging in 77 V for V, you get:

Q = 77 V * (10⁶)

Q = 77 x 10⁶ micro-coulombs.

Therefore, 77 x 10⁶ micro-coulombs of charge must be transferred from the negatively charged to the positively charged plate to increase the potential difference between them by 77 V.

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a plane is moving due north, directly towards its destination. its airspeed is 210 mph. a constant breeze is blowing from west to east at 20.0 mph. at what rate is the plane moving north?

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The rate at which the plane is moving north is 210 mph.

We can use vector addition to solve this problem. Let's denote the speed of the plane with respect to the ground as V, and the speed of the wind as W. We can break down the speed of the plane into two components: one component due north, denoted as Vn, and one component due east, denoted as Ve. Similarly, we can break down the speed of the wind into two components: one component due north, denoted as Wn, and one component due east, denoted as We.

Since the plane is moving directly towards its destination, we know that the component of its velocity due east, Ve, is zero. Therefore:

V = [tex]\sqrt{(Vn^2 + Ve^2) }[/tex]= Vn

We also know that the speed of the wind due north, Wn, is zero (since the wind is blowing from west to east). Therefore:

W = [tex]\sqrt{(Wn^2 + We^2)}[/tex] = We

Now, we can use vector addition to find the speed of the plane due north. The northward component of the plane's velocity is given by:

Vn = V * cos(theta)

where theta is the angle between the velocity vector and the northward direction. Since the plane is moving due north, theta is 0 degrees. Therefore:

Vn = V * cos(0) = V

The northward component of the wind's velocity is given by:

Wn = W * sin(theta)

where theta is the angle between the velocity vector and the northward direction. Since the wind is blowing from west to east, theta is 90 degrees. Therefore:

Wn = W * sin(90) = W

Now, we can add the northward components of the plane's and the wind's velocities to find the northward component of the resultant velocity:

Vn + Wn = V + W * sin(90)

Simplifying this equation, we get:

Vn = V + Wn = V + W * sin(90) = 210 + 0 * sin(90) = 210 mph

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a 0.105-kg hockey puck moving at 30 m/s is caught and held by a 61-kg goalie at rest. with what speed does the goalie slide on the ice?

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A 0.105-kg hockey puck moving at 30 m/s is caught and held by a 61-kg goalie at rest. The Speed at which the goalie slide on the ice is  0.0517 m/s.

A 0.105-kg hockey puck moving at 30 m/s is caught and held by a 61-kg goalie at rest.

The velocity of the goalie is given. In the problem, the momentum of the hockey puck is defined as 0.105 kg x 30 m/s = 3.15 kg*m/s.

The law of conservation of momentum claims that the sum of the momenta of two objects is conserved throughout the collision.

Momentum is always conserved, but the total energy in the system is not (since some energy is lost as sound, heat, and deformation of the objects during a collision).

This is given as the initial momentum of the puck, and since the total momentum of the system is conserved, the momentum of the puck after the collision is zero since the goalie is at rest.

The total momentum of the system is calculated using conservation of momentum principles.

Using the conservation of momentum law, the velocity of the goalie can be calculated, which is given by:

[tex]$$\begin{aligned} 0.105 \text{ kg}\times 30 \text{ m/s} &= (0.105 \text{ kg}+61 \text{ kg}) \times v \\ 3.15 \text{ kg}\cdot \text{m/s} &= 61.105 \text{ kg}\times v \\ \frac{3.15 \text{ kg}\cdot \text{m/s}}{61.105 \text{ kg}} &= v \approx 0.0517 \text{ m/s} \end{aligned}$$.[/tex]

The goalie's velocity is 0.0517 m/s, which is a very modest speed.

 

Thus, the answer to the given problem is 0.0517 m/s, which is the velocity of the goalie.

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A 2000 kg car traveling at a speed of 37 m/s skids to a halt on wet concrete where μk
= 0.50.

Answers

Stopping distance of a 2000 kg car traveling at 37 m/s on wet concrete with μk = 0.50 is 141.95 meters.

How to calculate stopping distance?

To solve this problem, we need to use the formula for the stopping distance of a car on a slippery surface:

d = (v² / 2μk g)

where:

v - is the car's initial velocity.

d - is the stopping distance

μk - is the coefficient of kinetic friction between the car's tires and the road surface

g - is the acceleration due to gravity (9.81 m/s²)

Substituting the given values, we get:

d = (37² / (2 * 0.50 * 9.81)) = 141.95 meters

Therefore, the stopping distance of the car is 141.95 meters.

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Complete question:

A 2000 kg car traveling at a speed of 37 m/s skids to a halt on wet concrete where μk = 0.50. What is Stopping distance?

the first simple electric motor and the first dynamo for generating electricity were both invented by

Answers

Answer: The first simple electric motor and the first dynamo for generating electricity were both invented by Michael Faraday.

Michael Faraday was a British physicist and chemist who lived from 1791 to 1867. In 1821, he created the first basic electric motor, which utilized a wire carrying a current placed inside a magnetic field, resulting in a rotary motion.

Faraday discovered electromagnetic induction in 1831 and developed the first electric dynamo, which used electromagnetic induction to transform mechanical energy into electrical energy. Faraday's findings laid the groundwork for modern electrical engineering and power generation.



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the air in an organ pipe is replaced by helium (which has a lower molar mass than air) at the same temperature. how does this affect the normal-mode wavelengths of the pipe?

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The normal-mode wavelengths decrease when the air in an organ pipe is replaced by helium, at the same temperature. This is because helium has a lower molar mass than air, and therefore a lower speed of sound, which causes the normal-mode wavelengths to decrease.

The normal-mode
wavelengths are determined by the length of the pipe L and the speed of sound in the pipe

V.λn = 2L/nVn is the index of the mode, which can be any integer.

When helium is used instead of air, the speed of sound in the pipe rises because the mass of the helium molecules is smaller than that of the air molecules, so the gas molecules must travel quicker to achieve the same speed. Because the wavelength of a standing wave must fit into the pipe precisely, the increase in velocity causes the wavelength to decrease. The normal-mode wavelengths will be lowered as a result of this.

Thus, the answer is the normal-mode wavelengths decrease.

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a 500-w device is connected to a 120-v ac power source. what is the peak voltage across this device?

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The peak voltage across a 500-w device connected to a 120-v ac power source is 120 V. This is because the voltage rating of the device is determined by the voltage of the power source.

To calculate the peak voltage across the device, we can use Ohm's Law:

V = I x R.

This equation states that the voltage is equal to the current multiplied by the resistance.

We know that the voltage of the power source is 120 V and the current is 4 A (I = P/V, where P is the power rating of the device). Therefore, the resistance is 30 ohms (R = V/I).

We can then use Ohm's Law to calculate the peak voltage across the device.

V = I x R
V = 4 A x 30 ohms
V = 120 V

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what is the relationship between index of refraction and the speed of the light in the medium of the index of refraction?

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The relationship between the index of refraction and the speed of light in a medium is that the higher the index of refraction is: the slower the speed of light in that medium

The index of refraction is a measure of how much a light ray is bent, or refracted, as it enters a material or medium. The amount of refraction increases as the index of refraction increases, which in turn causes light to travel slower in the medium.

The index of refraction is related to the speed of light in the medium because the amount of refraction affects the speed of light in that medium. The index of refraction is a ratio between the speed of light in a vacuum and the speed of light in a medium.

This is calculated as the speed of light in a vacuum (c) divided by the speed of light in the medium (v). This ratio is usually represented as n, and so the formula for the index of refraction is: n = c/v. As the index of refraction increases, the speed of light in the medium decreases.


In a medium with a low index of refraction, the speed of light is higher than in a medium with a higher index of refraction. This is because a low index of refraction means that the light ray is not being refracted very much, so it is able to travel faster.

A higher index of refraction means that the light ray is being refracted more, so it is forced to travel slower. This explains the relationship between the index of refraction and the speed of light in a medium; the higher the index of refraction, the slower the speed of light in that medium.

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if the current in a 190 mh coil changes steadily from 22.0 a to 12.0 a in 450 ms , what is the magnitude of the induced emf?

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The magnitude of the induced emf by the coil is  -0.63 V.

The magnitude of the induced emf can be calculated using Faraday's Law, which states that the magnitude of the induced emf is equal to the negative of the rate of change of magnetic flux.

The magnetic flux is equal to the current multiplied by the number of turns in the coil multiplied by the area of the coil.

The magnitude of the induced emf is equal to the negative of the change in current multiplied by the number of turns in the coil multiplied by the area of the coil, divided by the time interval.

The magnitude of the induced emf is equal to the negative of (22.0 A - 12.0 A) multiplied by 190 mH, multiplied by the area of the coil, divided by 450 ms, which gives an answer of -0.63 V.

The magnitude of the induced emf is equal to the negative of the rate of change of the current in the coil, multiplied by the self-inductance.

Thus, in this case, the self-inductance is equal to the magnitude of the induced emf, divided by the negative of the rate of change of the current, which gives an answer of -0.63 V.

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what happens to the energy waves as they pass through the valley and reach the mountain? what type of material do you expect to find in valleys

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When energy waves pass through the valley and reach the mountain, the waves will be reflected back, the material that you can expect to find in valleys are generally soil and rock formations.

The Energy waves are also formed by

Energy waves passing through valleys and reaching mountains undergo diffraction, causing them to curve and spread outwards.Valleys are formed by erosion and typically consist of dense materials like rocks, soil, and water, which can scatter, reflect or absorb the passing waves.The behavior of waves passing through valleys and mountains depends on various factors like wave type, angle of incidence, and material properties

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as a percentage of their total volumes, how do the cores of uranus and neptune compare with those of saturn and jupiter?

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As a percentage of their total volumes, the cores of Uranus and Neptune are smaller than the cores of Saturn and Jupiter.

Uranus, Neptune, Saturn, and Jupiter are all gas giant planets with a layered structure consisting of a core, mantle, and atmosphere. The size of the core relative to the rest of the planet is determined by the planet's formation and evolution history.

Jupiter and Saturn are known to have relatively large cores compared to their overall size, while Uranus and Neptune are believed to have smaller cores.

However, the exact sizes and compositions of the cores of these planets are still a subject of research and debate. As a result, it is difficult to provide a precise comparison of the sizes of the cores of these planets as a percentage of their total volumes.

Based on current knowledge, it is generally accepted that the cores of Uranus and Neptune are smaller than the cores of Saturn and Jupiter as a percentage of their total volumes.

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masswhat is the relationship between energy in joules versus ev. if you have a proton at 10 mev, how fast is it going?

Answers

The speed of the proton can be calculated as:v = p/m = (1.08 × 10⁻¹⁸ kg m/s)/(1.67 × 10⁻²⁷ kg) = 6.46 × 10⁸ m/s. So, the speed of the proton at 10 MeV is 6.46 × 10⁸ m/s.

Relationship between energy in joules versus eV. The relationship between energy in joules and electron volts (eV) is defined by the conversion factor 1 eV = 1.6 × 10⁻¹⁹ joules. This factor is used to convert energy measurements from one unit to the other. If a proton has an energy of 10 MeV, we can use this conversion factor to determine its energy in joules.10 MeV = 10 × 10⁶ eV = 1.6 × 10⁻¹⁹ J/eV × 10 × 10⁶ eV = 1.6 × 10⁻¹³ J. Speed of a proton at 10 MeV.

The speed of a proton at 10 MeV can be calculated using the relativistic equation: E² = (mc²)² + (pc)², where E is the energy of the proton, m is its mass, c is the speed of light, and p is the momentum of the proton. Let's assume that the mass of the proton is 1.67 × 10⁻²⁷ kg. Then, the momentum of the proton can be calculated as follows:p = √(E² - (mc²)²)/c = √((10 × 10⁶ eV)² - (1.67 × 10⁻²⁷ kg × (2.998 × 10⁸ m/s)²)²)/2.998 × 10⁸ m/s = 1.08 × 10⁻¹⁸ kg m/s. The speed of the proton can be calculated as:v = p/m = (1.08 × 10⁻¹⁸ kg m/s)/(1.67 × 10⁻²⁷ kg) = 6.46 × 10⁸ m/s. Therefore, the answer is 10 MeV is 6.46 × 10⁸ m/s.

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calculate the efficiency of an electric motor which uses 7.4kJ of energy to lift a 34kg object 11m​

Answers

The electric motor's efficiency is 51.06%.

What is the electric motor's efficiency?

The majority of electric motors are made to operate between 50% and 100% of rated load. Typically, maximum efficiency is within 75% of rated load. Hence, the allowable load range for a 10-horsepower (hp) motor is between 5 and 10 hp; its peak efficiency is at 7.5 hp. Below roughly 50% load, a motor's efficiency tends to decline significantly.

To calculate the effort required to raise the object, use the formula:

Work = Force x Distance

= m x g x h (where m is the mass of the object, g is the acceleration due to gravity, and h is the height lifted)

= 34 kg x 9.81 m/s² x 11 m

= 3,769.34 J

The energy consumed by the electric motor is given as 7.4 kJ.

Therefore, the input power is:

Input power = Energy consumed / time taken

= 7.4 kJ / t

Efficiency=(Output power/Input power) x 100%

Output power = Work done/time taken

= 3,769.34 J / t

As a result, the electric motor's efficiency is:

Efficiency=(Output power/Input power)x 100%

= [(3,769.34 J / t) / (7.4 kJ / t)] x 100%

= 51.06%.

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The top view below shows a record that is spinning counterclockwise at a constant rate. Which of the following statements are true? Choose all that apply.
-A and B have the same linear velocity
-A has a greater linear velocity than B
-B has a greater linear velocity than A
-A and B have the same angular velocity
-A has a greater angular velocity than B
-B has a greater angular velocity than A

Answers

From the top view of the spinning record, we can see that points A and B are at different distances from the center of rotation. Therefore, they have different linear velocities.

A has a greater linear velocity than B: True

B has a greater linear velocity than A: False

A and B have the same linear velocity: False

However, both points A and B are at the same distance from the center of rotation. Therefore, they have the same angular velocity.

A and B have the same angular velocity: True

A has a greater angular velocity than B: False

B has a greater angular velocity than A: False

In summary,

A has a greater linear velocity than B

A and B have the same angular velocity.

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The average wavelength in a series of ocean waves is 15. 0 meters. A wave crest arrives at the shore an average of every 10. 0 seconds, so the frequency is 0. 100 Hz. What is the average speed of the waves?

Answers

A wave crest arrives on the shore a median of every 10. zero seconds, so the frequency is 0. one hundred Hz. The average speed of the waves is 1.five m/s.

We are to decide the common pace of the waves.

Using the formula

v = fλ

Where

v is the speed

f is the frequency

and λ is the wavelength

From the given information

f = 0.1 Hz

λ = 15.0 m

∴ Speed of the wave = 0.1 × 15.0

Speed of the wave = 1.5 m/s

Average speed is defined as the total distance traveled by an object divided by the time taken to cover that distance. It is the measure of the average rate at which an object covers a certain distance in a given amount of time. Mathematically, the average speed is expressed as: Average speed = Total distance traveled / Time taken

It is important to note that average speed is not the same as instantaneous speed, which refers to the speed of an object at a particular instant in time. Average speed takes into consideration the entire adventure, while instant velocity only reflects the velocity at a unmarried moment. The unit of measurement for average speed is meters per second (m/s) or kilometers per hour (km/h), depending on the system of measurement used.

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these two resistors are in series. first, stop and trace the current flowing from the battery through the complete circuit. now, what is the current flowing through resistor r1?

Answers

The current flowing through resistor R1 since resistors in series have the same current running through them is the current flowing from the battery through the complete circuit.

To find the current flowing through resistor R1, first we need to trаce the current flowing from the bаttery through the complete circuit. The given resistors аre in series, which meаns they аre connected end-to-end, so the sаme current flows through both of them. Thus, the current flowing through the complete circuit is:

I = V/Rtotаl

where I is the current, V is the voltаge of the bаttery, аnd Rtotаl is the totаl resistаnce of the circuit.To find the totаl resistаnce of the circuit, we need to аdd the resistаnces of both resistors in series:

Rtotаl = R1 + R2

Thus, the current flowing through the complete circuit is:

I = V / (R1 + R2)

Now, to find the current flowing through resistor R1, we use Ohm's Lаw, which stаtes thаt the current through а resistor is proportionаl to the voltаge аcross it аnd inversely proportionаl to its resistаnce. Thus:

I1 = V/R1

where I1 is the current flowing through resistor R1. Substituting the vаlue of V from the previous equаtion, we get:

I1 = I * R1 / (R1 + R2)

Therefore, the current flowing through resistor R1 is I1 = I * R1 / (R1 + R2)

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a baseball has a mass of 145 g. a pitcher throws the baseball so that it accelerates at a rate of 80 m/s2. how much force did the pitcher apply to the baseball?(1 point)

Answers

The amount of force that the pitcher applies to the baseball is 11.6N.

How to calculate force?

Force is a physical quantity that denotes ability to push, pull, twist or accelerate a body. It can be calculated by multiplying the mass of the object by its acceleration as follows;

Force = mass × acceleration

According to this question, a baseball has a mass of 145 g. A pitcher throws the baseball so that it accelerates at a rate of 80 m/s². The force applied on the baseball can be calculated as follows:

Force = 145/1000 kg × 80m/s²

Force = 11.6N

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in a radio telescope, the role that the mirror plays in visible-light telescopes is played by: a. a spectrometer b. an interferometer c. a special kind of lens d. computer software e. a large metal dish (antenna)

Answers

In a radio telescope, the role that the mirror plays in visible-light telescopes is played by a large metal dish (antenna).

A radio telescope works by collecting and analyzing radio waves emitted by celestial objects. To collect these radio waves, the radio telescope has a large metal dish, also known as an antenna.

This metal dish gathers radio waves from space and reflects them into the radio telescope's receiver.Spectrometer is a scientific instrument used to measure the intensity of different wavelengths of light in a spectrum.

It is an essential tool for astronomers as it helps to understand the nature of celestial objects by analyzing the light that they emit.Interferometer is a device used in radio telescopes to improve the resolution of images.

It is used to combine the signals from multiple telescopes, allowing astronomers to study more distant objects with greater accuracy.

Special lenses are used in visible-light telescopes to focus light onto the detector or camera. They help to produce clear images by reducing distortions caused by aberrations and other optical imperfections.

Computer software is used in all types of telescopes to process and analyze the data collected by the telescope.

It allows astronomers to create images, measure the intensity of different wavelengths of light, and make other calculations.

The role that the mirror plays in visible-light telescopes is replaced by a large metal dish in radio telescopes, which collects and reflects radio waves into the telescope's receiver.

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how many nuclear reactor incidents have been studied to determine the stoachasitc effects on the workers and exposed population

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Nuclear reactor incidents have been studied in hundreds to determine the stochastic effects on the workers and exposed population.

The stochastic effect refers to radiation-induced effects that may occur in tissues or cells and that are subject to probabilistic relationships between exposure and reaction. The probability of developing cancer increases as a result of exposure to radiation. The greater the exposure dose, the greater the likelihood of developing cancer.The stochastic effect can occur even at low radiation doses.

This is opposed to deterministic effects, which only occur when a particular radiation dose threshold is surpassed. Stochastic effects are also referred to as random or probabilistic effects. They can happen in any tissue or organ in the body, including reproductive cells, which can lead to heritable genetic mutations. The probability of developing cancer increases as the radiation dose rises.

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Part A Reflect on how you use electricity at home. Think about times when you might be wasting energy. For example, leaving on appliances, such as lights, wastes energy if you're not using them. Come up with a tip to address the problem you've identified.​

Answers

Answer:

at night unplug EVERYTHING

explanation

when the power is off on a device it still may using a little electricity to recharge the battery inside or keep a clock running, etc. usually there are a lot of things plugged in a home so even if each thing is not using a lot of electricity, ALL the things that plugged in, put together, maybe using A LOT.

A marble is travelling at 2.0 m/s along a table top. The top of the table is 1.5 m above the floor.
Find:
a. the time the marble will take to reach the floor.
b. the distance of the table that the marble will land.
c. the velocity of the marble just before it reaches the floor.

Answers

Answer

time of flight = 0.5533 seconds

horizontal range = 1.107 metres

final velocity is 5.779 m/s at 70° downwards

Step-by-Step Solution

initial horizontal velocity (ux) = 2.0 m/s

initial vertical velocity (uy) = 0

vertical displacement (sy) = -1.5 m

neglecting air friction (drag), acceleration due to gravity (g) in the vertical component, is constant (9.8 m/s²), and horizontal velocity is ALWAYS constant. i.e, acceleration=0. Now using the equations of motion for the x-component:

[tex]s=ut\\v^2=u^2\\v=u[/tex]

for the y-component:

[tex]v=u-gt\\v^2=u^2-2gs\\s=ut-\frac{1}{2}gt^2\\[/tex]

(a) the time the marble will take to reach the floor.

using an equation that we have all the data for,

[tex]s=ut-\frac{1}{2}gt^2[/tex]

-1.5 = 0 - 1/2(9.8)×t². Solving this to get t,

∴ time of flight = 0.5533 seconds

(b) the distance of the table that the marble will land.

similar to the previous question, we can use one of the equations of motion again, but this time, there's only one equation we can use:

[tex]s=ut[/tex]

s = 2×0.5533

∴ horizontal range = 1.107 metres

c. the velocity of the marble just before it reaches the floor.

For this, we require both the x and y components of final velocity, and then we can calculate the resultant vector of the two velocities, as well as the direction/angle. Since u=v in x-component, we already have Vx. To find Vy, we can use:

[tex]v=u-gt[/tex]

v = 0 - 9.8×0.5533

∴ final vertical velocity = -5.4223 m/s

Therefore, final velocity = [tex]\sqrt{Vx^2+Vy^2}[/tex]

v = √(2.0² + (-5.4223)²) = 5.779 m/s

To find direction of velocity, tan∅ = Vy/Vx

∅ = tan⁻¹(5.4223/2.0) = 70°

Therefore, final velocity is 5.779 m/s at 70° downwards

if 22.5L of nitrogen at 748 mm Hg are compressed to 725 mm hg at constant temperature what is the new volume?

Answers

The new volume is approximately 23.16 L when the nitrogen gas is compressed from 748 mmHg to 725 mmHg at constant temperature.

Use the combined gas law to determine the relationship between a gas's pressure, volume, and temperature:

P1V1/T1 = P2V2/T2

where the gas's starting pressure, volume, and temperature are P1, V1, and T1, and its ultimate pressure, volume, and temperature are P2, V2, and T2.

The equation may be made simpler by saying: since the temperature is constant.

P1V1 = P2V2

Substituting the given values, we get:

725 mmHg × V2 = 748 mmHg × 22.5 L

Solving for V2, we get:

V2 = (748 mmHg × 22.5 L) / 725 mmHg

V2 = 23.16 L

A gas law known as the combined gas law connects a gas's pressure (P), volume (V), and temperature (T). It combines Boyle's law, Charles' law, and Gay-law, Lussac's three additional gas laws.

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when the light ray enters the air from the water, will the refracted light ray bend further from or closer to the normal?

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Yes, when a light ray enters from water to air, it will bend further from the normal. This phenomenon is known as refraction, and is caused by the difference in speed between light passing through the two different materials. The light ray will slow down when passing through water, so it will bend closer to the normal.

When a light ray enters the air from water, the light ray will refract closer to the normal. This is due to the fact that light travels faster through air than through water, so when the light enters the air, it bends towards the normal. The amount of refraction is determined by the index of refraction of each material. Since the index of refraction of air is lower than the index of refraction of water, the light ray will bend closer to the normal.

To better understand this, imagine a light ray traveling from a denser material (like water) to a less dense material (like air). As the light ray enters the air, the speed of the light increases, causing it to bend closer to the normal. This is due to the law of refraction, which states that the angle of refraction is inversely proportional to the speed of the light ray. In summary, when a light ray enters the air from water, it will refract closer to the normal. This is due to the fact that light travels faster through air than through water, so the light ray bends towards the normal. The amount of refraction is determined by the index of refraction of each material, with the lower index refraction material (air) resulting in the light ray bending closer to the normal.

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a 1000-kg automobile enters a freeway on-ramp at 20 m/s and accelerates uniformly up to 40 m/s in a time of 10 seconds. how far does the automobile travel during that time?

Answers

The automobile will travel for 300 m during that time. The result is obtained by using the formula for uniformly accelerated motion.

Uniformly Accelerated Motion

The equations apply in uniformly accelerated motion in horizontal dimension are

v₁ = v₀ + at

v₁² = v₀² + 2ax

x = v₀t + ½ at²

Where

v₀ = initial velocityv₁ = final velocitya = accelerationt = timex = distance

We have

m = 1000 kgv₀ = 20 m/sv₁ = 40 m/st = 10 s

Find the distance that the automobile travel during that time!

From that information, we can find the acceleration.

a = (v₁ - v₀)/t

a = (40 - 20)/10

a = 2 m/s²

The distance will be

x = v₀t + ½ at²

x = 20(10) + ½ (2)(10)²

x = 200 + 100

x = 300 m

Hence, that time the automobile will reach the distance of 300 m.

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consider a hypothetical planet with a radius of 162 million meters and a mass of 1027 kg. what is the density of this planet, in kg/m3? round to the nearest integer.

Answers

The density of the hypothetical planet, in kg/m3, is 6,246 kg/m3

Calculate the volume of the planet in m3

V = (4/3)πr3

V = (4/3)π(162 x 106 m)3

V = 9.30 x 1018 m3

The density of the planet in kg/m3

We know that Density is given as

D = Mass ÷ Volume

D = 1027 kg ÷ 9.30 x 1018 m3

D = 6,246 kg/m3

Density is a measure of mass per unit of volume. It is expressed in terms of mass per volume and is typically measured in kg/m3 or g/cm3. Density is an important physical property of matter as it allows us to compare the mass of different substances at the same volume.

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