The reading on the scale is 838.29 N.
To determine the reading on the scale, use the following formula:
F = ma
where F is force, m is mass, and a is acceleration.
The weight of the individual can be determined using the formula:
W = mg
where W is weight, m is mass, and g is the acceleration due to gravity, which is 9.81 m/s².
The given acceleration is 0.47 m/s². The weight of the individual is W = mg,
where m = 799 N / 9.81 m/s² = 81.38 kg
W = 81.38 kg x 9.81 m/s² = 798.11 N.
To calculate the reading on the scale, we'll have to add the force the scale must apply to support the individual's weight to the weight of the person's mass multiplied by the acceleration:
Reading on the scale = 798.11 N + 81.38 kg x 0.47 m/s² = 838.29 N, rounded to three digits.
Therefore, the reading on the scale is 838.29 N to at least three digits.
Learn more about acceleration here: https://brainly.com/question/460763.
#SPJ11
a 1000kg car moving at 19.6 m/s on a flat road slams on the brakes and skids to a stop. the coefficient of kinetic friction between the road and car tires is 0.694. how many meters does the car go before it comes to a complete stop? (hint: think of work-energy theorem, and friction equation)
If the coefficient of kinetic friction between the road and car tires is 0.694, the car will travel approximately 57.4 meters before it comes to a complete stop.
In this case, the net work done on the car is equal to the work done by friction, which is equal to the force of friction times the distance the car travels.
Therefore:
W_net = W_friction = f_friction x d
where f_friction is the force of friction and d is the distance the car travels.
The force of friction is given by:
f_friction = μ_k x N
where μ_k is the coefficient of kinetic friction and N is the normal force.
Since the car is on a flat road, the normal force is equal to the weight of the car, which is given by:
N = m x g
where m is the mass of the car and g is the acceleration due to gravity.
Substituting the given values, we get:
N = m x g = 1000 kg x 9.81 m/s² = 9810 N
f_friction = μ_k x N = 0.694 x 9810 N ≈ 6808.14 N
Now we can use the work-energy theorem to find the distance the car travels:
W_net = ΔK = 0 - 1/2 x m x v²
where ΔK is the change in kinetic energy, which is equal to the initial kinetic energy of the car (1/2 x m x v²) since the car comes to a complete stop.
Substituting the values, we get:
W_net = f_friction x d = -1/2 x m x v²
6808.14 N x d = -1/2 x 1000 kg x (19.6 m/s)²
d = -1/2 x 1000 kg x (19.6 m/s)² / 6808.14 N
d ≈ 57.4 m
Therefore, the car distance before it stops = 57.4 meters.
Learn more about friction here:
https://brainly.com/question/25050131
#SPJ11
the earliest telescopes used by astronomers were: a. used late at night to look into the neighbors' windows b. about the aperture of the telescope on mount palomar c. reflectors d. refractors e. radio telescopes
The earliest telescopes used by astronomers were refractors. The correct option is (d) refractors.
A telescope is an instrument used for observing distant objects or to magnify the size of the observed objects.
Telescopes were invented in the early 17th century, and the earliest ones were refractors, which used lenses to gather and focus light.Refractors are telescopes that use lenses to gather and focus light.
A lens is made up of one or more pieces of glass, and it bends light as it passes through it. A refracting telescope has a long tube that holds the lens at one end and an eyepiece at the other end.
The lens collects the light, and the eyepiece magnifies the image, allowing the viewer to see distant objects in greater detail.Refracting telescopes use lenses to bend and focus light, much like a magnifying glass does.
The objective lens is positioned at one end of the telescope tube, and it collects light from a distant object. The lens bends the light and focuses it at a point in space.
The eyepiece, located at the other end of the tube, magnifies the image created by the objective lens, making it appear larger and more detailed.
The earliest telescopes used by astronomers were refractors. The refracting telescope, also known as a refractor, is a type of telescope that uses lenses to collect and focus light.
The lens gathers the light and focuses it on an eyepiece, which magnifies the image, allowing the viewer to see distant objects in greater detail.
to know more about refractors refer here:
https://brainly.com/question/30657265#
#SPJ11
isolated/insulated equipment grounding circuits must include how many equipment grounding conductors to meet the requirements of the nec?
Isolated/insulated equipment grounding circuits must include one equipment grounding conductor to meet the requirements of the National Electrical Code (NEC). These grounding conductors play a crucial role in ensuring the safety and proper functioning of electrical systems.
The NEC sets the standards for the safe installation of electrical wiring and equipment in the United States. An isolated equipment grounding circuit is designed to maintain electrical safety by providing a dedicated path for grounding equipment. This prevents unwanted electrical noise or interference from affecting the performance of sensitive electronic devices.
A single equipment grounding conductor is sufficient for an isolated grounding circuit, as it is meant to carry the fault current back to the source of power, protecting people and equipment from electrical hazards. The conductor is usually made of copper or aluminum and is sized according to the size of the circuit conductors.
This grounding conductor is connected to a grounding electrode system, which includes grounding electrodes such as ground rods, metallic water pipes, or concrete-encased electrodes. These electrodes create a connection to the earth, ensuring that any fault current is safely dispersed into the ground.
By complying with the NEC requirements, you ensure that your electrical systems are designed and installed in a manner that reduces the risk of electrical shock, fire hazards, and other potential dangers. A properly grounded electrical system promotes safety, performance, and reliability in any electrical installation.
Know more about National Electrical Code (NEC) here:
https://brainly.com/question/14507799
#SPJ11
what is the magnitude and direction of the force on the vertical wire segment on the left side of the square? the magnitude should be written in terms of i, l, and b, or could be zero, and the choices of direction are: left, right, up, down, in, out.
The magnitude of the force on the vertical wire segment on the left side of the square is F = (b * i * l) / 2, and the direction is out by Fleming's left-hand rule.
This is calculated by applying the equation for the force on a wire in a uniform magnetic field: F = (B * I * l) / 2. Here, B is the magnitude of the magnetic field, I is the current running through the wire, and l is the length of the wire.
The magnitude and direction of the force on the vertical wire segment on the left side of the square are as follows. Magnitude of force
The magnetic force on the wire can be calculated using the equation
F = BILsinθ
Where, F is the magnetic force, B is the magnetic field, I is the current in the wire, L is the length of the wireθ is the angle between the direction of the magnetic field and the direction of the current. In this case, the angle between the direction of the magnetic field and the direction of the current is 90°.
Hence, sin 90° = 1.So,F = BIL
Direction of force The direction of the magnetic force can be determined by Fleming's left-hand rule, which states that if you point your forefinger in the direction of the magnetic field and your middle finger in the direction of the current, your thumb will point in the direction of the force.
In this case, the magnetic field is pointing into the page, and the current is flowing from top to bottom. So, if you point your forefinger into the page and your middle finger downwards, your thumb will point towards the left side of the square. Therefore, the direction of the force is left.
For more such questions on Fleming's left-hand rule , Visit:
https://brainly.com/question/29054378
#SPJ11
an unbelted victim in a car accident will continue to move in the same direction and with the same speed until the dashboard causes a change in motion. this best exemplifies
According to Newton's first law, an unbelted victim in a car accident will continue to move in the same direction and with the same speed until the dashboard causes a change in motion.
Inertia is the tendency of an object to remain in motion in the absence of an unbalanced force. It is the property of an object to resist any change in motion unless acted upon by an external force.
The dashboard applies an external force that changes the direction and speed of the victim. This is because the person has no external forces acting on them to cause them to stop. Since they were in motion at the time of the accident, they will continue in that motion unless acted upon by another force, such as the dashboard, until they come to a stop or another force acts upon them.
Therefore, the best exemplifies the law of inertia. The law of inertia states that an object at rest will remain at rest, and an object in motion will remain in motion at a constant velocity unless acted upon by an external unbalanced force.
Learn more about the speed at
brainly.com/question/24091038
#SPJ11
a system releases 690 kj of heat and does 110 kj of work on the surroundings. part a what is the change in internal energy of the system?
A system releases 690 kj of heat and does 110 kj of work on the surroundings then part a what i the change in internal energy of the system -800 kJ.
The change in internal energy of the system can be calculated using the formula
ΔU = Q - W,
where ΔU is the change in internal energy, Q is the heat exchanged, and W is the work done.
In this case, the system releases 690 kJ of heat (Q = -690 kJ) and does 110 kJ of work on the surroundings (W = 110 kJ).
So, ΔU = -690 kJ - 110 kJ = -800 kJ.
The change in internal energy of the system is -800 kJ.
Know more about internal energy here:
https://brainly.com/question/30207866
#SPJ11
pry on the power steering reservoir to adjust the tension of the power steering belt. true or false?
The statement "pry on the power steering reservoir to adjust the tension of the power steering belt" is: false.
The tension of the power steering belt is adjusted by adjusting the position of the power steering pump. There is a tension adjustment bolt on the power steering pump that is used to adjust the tension of the power steering belt. The adjustment bolt should be turned clockwise or counterclockwise to adjust the tension of the belt.
A belt tension gauge may be used to ensure that the belt is properly tensioned. A pry bar should not be used on the power steering reservoir to adjust the tension of the power steering belt. This could cause damage to the reservoir or other components of the power steering system. The reservoir should be inspected for damage or leaks, but it should not be used to adjust the tension of the belt.
In summary, the tension of the power steering belt should be adjusted by adjusting the position of the power steering pump, not by prying on the power steering reservoir.
To know more about tension refer here:
https://brainly.com/question/29869473#
#SPJ11
radio waves are diffracted by large objects such as buildings, whereas light is not noticeably diffracted. why is this?
The reason why radio waves are diffracted by large objects, whereas light is not noticeably diffracted is the wavelength of light is much smaller than the wavelength of radio waves.
Thus, the correct answer is the wavelength of light is much smaller than the wavelength of radio waves (B).
The wаvelength of rаdio wаves being much lаrger thаn light, hаs а size compаrаble to those of buildings, hence diffrаct from them. Both rаdio аnd light wаves аre electromаgnetic wаves, just in different wаvelength rаnges. The wаvelength of visible light is typicаlly аround the 400-700 nm rаnge. Rаdio wаves on the other hаnd, often wаve wаvelengths of а few meters long.
For а wаve to diffrаct аround аn object, the size of the object must be on the sаme order of the wаvelength of the wаve. Hence, rаdio wаves diffrаct through buildings becаuse rаdio wаves hаve much lаrger wаvelength thаn light wаves.
Your question is incomplete, but most probably your options were
a. Radio waves are unpolarized, whereas light is plane polarized.
b. The wavelength of light is much smaller than the wavelength of radio waves.
c. Light is coherent and radio waves are usually not coherent.
d. Radio waves are coherent and light is usually not coherent.
Thus, the correct option is B.
For more information about radio waves refer to the link: https://brainly.com/question/28874040
#SPJ11
the centripetal force in a collapsing cloud of gas and dust is strongest at the poles question 9 options: true false
The given statement "centripetal force in a collapsing cloud of gas and dust is strongest at the poles" is - True.
Centripetal force refers to a force that drives an object toward a fixed point, which is the center of a circular path. For example, if you tie a ball to a string and whirl it around in a circle, the string exerts a centripetal force on the ball that keeps it moving in a circle.
The force of gravity is the most common centripetal force that we encounter in nature, and it is what drives the movement of planets, moons, and other celestial objects.
During the formation of a star, a cloud of gas and dust collapses inwards due to gravity. The cloud starts to rotate as it shrinks due to the law of conservation of momentum. The centripetal force in this situation is the gravitational force that holds the cloud together.
The gravitational force, on the other hand, is stronger at the poles of the cloud. The gravitational force increases as the distance between the particles in the cloud decreases. Because the poles of the cloud are closer together, the gravitational force is stronger, and the centripetal force is also stronger.
As a result, the centripetal force in a collapsing cloud of gas and dust is strongest at the poles.
To know more about centripetal force click here:
https://brainly.com/question/14249440
#SPJ11
HELP ME PLEASE!!!
Which 2 statements are true about this chemical reaction that forms acid rain?
However, in general, acid rain is formed when sulphur dioxide (SO2) and nitrogen oxides (NOx) are emitted into the atmosphere by human activities, such as burning fossil fuels.
Which of the following is incorrect about the main cause of acid rain?The erroneous statement among the following is : Acid rain is largely because to oxides of nitrogen and sulphur The greenhouse effect is to blame for the world's warming. Infrared radiation from the sun cannot reach earth due to the ozone layer.
What does acid rain consist of ?Nitric and sulphuric acids are created when the gases nitrogen oxides and sulphur dioxide interact with the minute droplets of water in clouds. The rain from these clouds falls as very weak acid known as 'Acid rain'.
To know more about radiation visit:-
https://brainly.com/question/28202771
#SPJ1
Question:
"Which two of the following statements are true about the chemical reaction that forms acid rain?
a. Sulfur dioxide and nitrogen oxides react with water to form sulfuric acid and nitric acid.
b. Acid rain can cause damage to buildings and statues made of limestone or marble.
c. Acid rain is only a problem in areas with a high population density.
d. Acid rain has no effect on freshwater ecosystems."
bob is pushing a box across the floor at a constant speed of 1.4m/s m / s , applying a horizontal force whose magnitude is 55n n . alice is pushing an identical box across the floor at a constant speed of 2.8m/s m / s , applying a horizontal force. a) what is the magnitude of the force that alice is applying to the box?
The magnitude of the force that Alice is applying to the box is 110 N.
To calculate the force that Alice is applying, we need to use the equation F = ma. In this equation, F is the force applied, m is the mass of the box, and a is the acceleration of the box.
Since Alice is pushing the box at a constant speed of 2.8 m/s, the acceleration is 0, and the equation simplifies to F = 0 x m. Since the force must equal 0 when the acceleration is 0, the magnitude of the force that Alice is applying to the box is 0.
However, since Bob is pushing an identical box across the floor at a constant speed of 1.4 m/s, the acceleration is 0 and the equation simplifies to F = m x a. In this case, a is the acceleration of the box, which is 1.4 m/s.
Since we know that the magnitude of the force Bob is applying is 55 N, we can use the equation to calculate the force Alice is applying. 55 N = m x 1.4 m/s, which simplifies to m = 39.286.
We then substitute m back into the equation F = ma, so F = 39.286 x 1.4 m/s. This simplifies to F = 55.0 N, so the magnitude of the force Alice is applying is 55.0 N.
To know more about constant speed click on below link:
https://brainly.com/question/30151073#
#SPJ11
a physics student wants to construct a model of an electric motor. The student creates a chart for the steps in the process. the chart shows what the student recorded so far:
what is the correct ordering of these cards to model how an electric motor works?
An electric motor is a device that transforms electrical energy into mechanical energy. Most electric motors create force in the form of torque imparted to the motor's shaft by interacting between the magnetic field of the motor and electric current in a wire winding.
How does an electric motor work?Electric motors generate motion by transferring electrical energy to mechanical energy. The interaction of a magnetic field and winding alternating (AC) or direct (DC) current generates force within the motor.
The basic motor constructed in class employs a coil that serves as a temporary electromagnet. The electrical current supplied by the battery provides the push for this coil to assist produce torque. The doughnut magnet utilized in the motor is a permanent magnet, which means it has a fixed north and south pole.
Learn more about electric motor
https://brainly.com/question/20317436
#SPJ1
when rotating the platform, the hanging mass should be removed from the platform. question 2 options: true false
The given statement, while the platform is rotating, the hanging mass remains attached to the test mass and is not removed from the platform is true, if the purpose of the experiment or test is to determine the effect of the hanging mass on the rotation or stability of the platform.
In this case, the hanging mass must remain attached to the test mass during the rotation to observe the behavior of the system under the specified conditions. If the purpose of the experiment or test is to study the effect of the hanging mass on the platform's rotation or stability, the hanging mass must remain attached to the test mass during the rotation. This is because the presence of the hanging mass affects the overall weight and center of gravity of the system. Removing the hanging mass would alter the system's behavior and prevent accurate observations of the phenomenon under investigation. Therefore, if the experiment requires the hanging mass to be present, it must remain attached to the test mass while the platform is rotating.
To know more about platform, here
brainly.com/question/22850608
#SPJ4
--The complete question is, While the platform is rotating, the hanging mass remains attached to the test mass and is not removed from the platform. State true/false.--
a raindrop has a mass of 5.2 x 10-7 kg and is falling near the surface of earth. (a) calculate the magnitude of the gravitational force exerted on the raindrop by earth. (b) calculate the magnitude of the gravitational force exerted on earth by the raindrop.
The magnitude of the gravitational force exerted on the raindrop by the earth is: 4.86 x 10-5 N
and the magnitude of the gravitational force exerted on earth by the raindrop is: 4.86 x 10-5 N
(a) The gravitational force on a 5.2 x 10-7 kg raindrop falling close to the surface of Earth is calculated in this question. We can use Newton's law of universal gravitation to determine the gravitational force between two objects. The force between two objects is proportional to the product of their masses and inversely proportional to the square of the distance between them.
The formula is as follows: F = G(m1m2 / r2)Where F is the gravitational force, G is the gravitational constant, m1, and m2 are the masses of the two objects, and r is the distance between them. The mass of the Earth is approximately 5.97 x 1024 kg, and its radius is approximately 6.38 x 106 m.
The gravitational constant is 6.67 x 10-11 Nm2/kg2. If we substitute the given values in the formula, F = (6.67 x 10-11 Nm2/kg2) x (5.2 x 10-7 kg x 5.97 x 1024 kg) / (6.38 x 106 m)2 = 4.86 x 10-5 N
(b) We can use Newton's third law to determine the magnitude of the gravitational force exerted by the raindrop on Earth. According to the third law, for every action, there is an equal and opposite reaction.
As a result, the magnitude of the gravitational force exerted on Earth by the raindrop is the same as the magnitude of the gravitational force exerted on the raindrop by Earth. The magnitude of the gravitational force is 4.86 x 10-5 N, according to the previous calculation. So the gravitational force exerted on Earth by the raindrop is 4.86 x 10-5 N.
According to Newton's law of universal gravitation, the gravitational force between two objects is proportional to the product of their masses and inversely proportional to the square of the distance between them. The gravitational force on a raindrop falling close to Earth's surface can be calculated using this law.
The gravitational force exerted by the raindrop on Earth is equal in magnitude to the gravitational force exerted on the raindrop by Earth, according to Newton's third law.
To know more about gravitational force refer here:
https://brainly.com/question/12528243#
#SPJ11
the total change in the internal energy of a system is the sum of the energy transferred as and/or .
The total change in the internal energy of a system is the sum of the energy transferred as heat and/or work.
The internal energy of a system is the sum of the kinetic and potential energies of the particles that make up the system. Heat is a form of energy that is transferred from a body at a higher temperature to a body at a lower temperature. The transfer of heat is always accompanied by a change in the internal energy of the system. If heat is absorbed by the system, the internal energy of the system increases, and if heat is lost by the system, the internal energy of the system decreases.
Work, on the other hand, is the product of force and distance, and it is a form of energy that is transferred when a force is applied to an object to move it a certain distance. If work is done on a system, the internal energy of the system increases, and if work is done by the system, the internal energy of the system decreases.
The first law of thermodynamics, also known as the law of conservation of energy, states that the total energy of an isolated system is constant. This means that the change in the internal energy of a system is equal to the heat added to the system minus the work done by the system.
Thus, the sum of the energy transferred as heat and/or work is the total change in the internal energy of a system.
To know more about internal energy, refer here:
https://brainly.com/question/14668303#
#SPJ4
1. Which graphic organizer best compares the energy inputs and outputs of cellular respiration and photosynthesis? Chemical energy. Cellular respiration. Thermal energy. Photosynthesis. Light energy. Light energy. Photosynthesis. Chemical energy. Cellular respiration. Chemical energy. Chemical energy. Photosynthesis. Thermal energy. Cellular respiration. Chemical energy. Light energy. Cellular respiration. Chemical energy. Photosynthesis. Thermal energy.
The best sources of energy are light, photosynthesis, chemicals, cellular respiration, and chemicals. the energy inputs and outputs of photosynthesis and cellular respiration are compared.
What exactly does energy mean?The capability to do tasks is how energy is most frequently defined. In other words, energy is a property of everything that can accomplish work. Making or producing change is another name for conducting work in the context of energy. With every act of labor, energy is either changed or transferred.
Why does energy exist?Energy is a word that denotes a property of matter & non-matter fields; it is not a substance in and of itself. For instance, it is argued that matter has kinetic energy when it moves quickly. Potential energy can take many different forms.
To know more about Energy visit:
https://brainly.com/question/1932868
#SPJ1
a body weighs 0.5kg in air 0.3kg in water and 0.2kg in a liquid. what is the relative density of the liquid
Answer:
The relative density of the liquid is 1.5
Explanation:
The relative density of a liquid is defined as the ratio of the density of the liquid to the density of water. We can use the principle of buoyancy to find the relative density of the liquid.
When the body is immersed in water, it experiences an upthrust equal to the weight of water displaced. Therefore, the weight of water displaced = weight of the body in air - weight of the body in water = 0.5 kg - 0.3 kg = 0.2 kg.
Similarly, when the body is immersed in the liquid, it experiences an upthrust equal to the weight of liquid displaced. Therefore, the weight of liquid displaced = weight of the body in air - weight of the body in the liquid = 0.5 kg - 0.2 kg = 0.3 kg.
The relative density of the liquid can be found as follows,
Relative density of liquid = Density of liquid / Density of water
= (Weight of liquid displaced / Volume of liquid) / (Weight of water displaced / Volume of water)
= (0.3 kg / Volume of liquid) / (0.2 kg / Volume of water)
= (0.3 kg / Volume of liquid) / (0.2 kg / 0.2 L) [since the density of water is 1 g/mL or 1 kg/L]
= 1.5 / Volume of liquid
Therefore, the relative density of the liquid is 1.5 divided by the volume of the liquid in liters.
the tilt of the moon's orbit shifts a little bit each year, which changes the dates eclipses occur each year. this shift of the orbital plane is called
The shift of the Moon's orbit is called precession and it occurs over a period of 18.6 years.
During precession, the tilt of the Moon's orbit changes by up to 5° from its current inclination to the Earth's orbit. This change in the Moon's orbit causes the dates and times of eclipses to shift each year. Solar eclipses occur when the Moon's shadow crosses the Earth, and this requires the Moon to be in a specific position in relation to the Earth. Precession of the Moon's orbit shifts that position, which shifts when and where on the Earth's surface eclipses occur.
Precession also affects the visibility of lunar eclipses. During a lunar eclipse, the Earth's shadow covers the Moon, which means the Moon must be in the Earth's shadow in the first place. As the Moon's orbital inclination changes over time, it affects which parts of the Earth's shadow the Moon will pass through and be visible from, meaning that not all lunar eclipses are visible from the same places.
Precession is an important factor in predicting when and where solar and lunar eclipses will occur. As the Moon's orbital inclination changes, it affects where on Earth an eclipse will be visible from and when it will occur. It's important for astronomers to consider precession when making predictions about eclipses.
For more such questions on Precession.
https://brainly.com/question/30352256#
#SPJ11
jasmin, a cyclist, accelerates from rest. after 8 s, the wheels have made 3 revolutions. (a) what is the angular acceleration of the wheels? (b) what is the angular velocity of the wheels after 8 s?
a. The angular acceleration of the wheels is 0.2945 rad/s². b. The angular velocity of the wheels after 8 seconds is 2.3560 rad/s.
Calculation:
a. The formula for angular acceleration is: α = (ω2 - ω1) / (t2 - t1) Whereα is angular acceleration, ω2 is final angular velocity, ω1 is initial angular velocity, t2 is final time, t1 is initial time. To calculate the angular acceleration, we can use the formula:α = (ω2 - ω1) / (t2 - t1)
The initial angular velocity of the wheels is zero since Jasmin starts from rest, soω1 = 0. We know that the wheels make 3 revolutions after 8 seconds, so the final angular velocity can be calculated as follows: ω2 = (3 revolutions / 8 s) x (2π radians / 1 revolution) = 2.3562 rad/s
Therefore,α = (2.3562 rad/s - 0 rad/s) / (8 s - 0 s) = 0.2945 rad/s². The angular acceleration of the wheels is 0.2945 rad/s².
b. To calculate the angular velocity of the wheels after 8 seconds, we can use the formula:ω = ω1 + αtWhereω is angular velocity,ω1 is initial angular velocity,α is angular acceleration, t is time. The initial angular velocity of the wheels is zero since Jasmin starts from rest, so ω1 = 0
We have already calculated the angular acceleration to be 0.2945 rad/s², and we know that the time is 8 seconds, soω = ω1 + αt = 0 + (0.2945 rad/s²) x (8 s) = 2.3560 rad/s. Therefore, the angular velocity of the wheels after 8 seconds is 2.3560 rad/s.
To know more about angular acceleration, refer here:
https://brainly.com/question/29428475#
#SPJ11
To determine the location of her center of mass, a physics student lies on a lightweight plank supported by two scales 2.50m apart, as indicated in the figure . If the left scale reads 290 N, and the right scale reads 112 N. What is the student's mass and find the distance from the student's head to her center of mass.
The location of her centre of mass, a physics student lies on a lightweight plank supported by two scales 2.50m apart, as indicated in the figure. If the left scale reads 290 N and the right scale reads 112 N The student's mass is approximately 41 kg, and the distance from her head to her centre of mass is approximately 0.696 m.
To determine the student's mass, we can sum up the readings from both scales, which are measures of force (Newtons) and then convert it to mass using the gravitational acceleration (g = 9.81 m/s²).
Step 1: Calculate the total force acting on the plank:
Total Force = Force_left_scale + Force_right_scale
Total Force = 290 N + 112 N
Total Force = 402 N
Step 2: Convert the total force to mass using gravitational acceleration:
Mass = Total Force / g
Mass = 402 N / 9.81 m/s²
Mass ≈ 41 kg
Now, to find the distance from the student's head to her centre of mass, we'll use the principle of torque equilibrium.
Step 3: Set up the torque equation:
Torque_left_scale = Torque_right_scale
Force_left_scale × Distance_left_scale = Force_right_scale × Distance_right_scale
Let x be the distance from the student's head to her centre of mass. Then, the distance from the left scale to the centre of mass is x, and the distance from the right scale to the centre of mass is (2.50 - x).
Step 4: Plug in the known values and solve for x:
290 N × x = 112 N × (2.50 - x)
Step 5: Simplify the equation and solve for x:
290x = 112(2.50) - 112x
290x + 112x = 112(2.50)
402x = 280
x ≈ 0.696 m
The student's mass is approximately 41 kg, and the distance from her head to her centre of mass is approximately 0.696 m.
For more such questions on centre of mass
brainly.com/question/28021242
#SPJ11
a 6 mf capacitor, a 10 mf capacitor, and a 16 mf capacitor are connected in parallel. what is their equivalent capacitance?
The equivalent capacitance of a 6 mF capacitor, a 10 mF capacitor, and a 16 mF capacitor connected in parallel is: 32 mF
This is because when capacitors are connected in parallel, their total capacitance is equal to the sum of their individual capacitances. The formula for calculating the equivalent capacitance (C) of capacitors connected in parallel is: C = C1 + C2 + C3 + ... In this example, C = 6 mF + 10 mF + 16 mF = 32 mF.
Capacitors are electrical components that store energy in the form of an electric field between two conductors (plates). When capacitors are connected in parallel, the electric field between the plates of each capacitor is the same, but the overall capacitance is increased due to the combined plate area of all the capacitors.
This increase in plate area is why the equivalent capacitance of the three capacitors in this example is 32 mF, which is larger than any of the individual capacitances.
To know more about capacitors refer here:
https://brainly.com/question/17176550#
#SPJ11
Which of the following is an example of the law of acceleration?
A - Sitting in your chair and breaking it.
B - Changing your force to accelerate a baseball different distances
C - A train traveling at constant speed.
D - Throwing a ball in space and it goes on FOREVER.
The correct answer is B - Changing your force to accelerate a baseball different distances.
Newton's second law of motion is also called the law of acceleration. It tells us that if we push or pull an object, it will move in the direction of the push or pull, and the harder we push or pull it, the faster it will move. The law also says that heavier objects will move more slowly than lighter objects when the same amount of force is applied.
In the example given in option B, the force applied to the baseball is changing, which means that the acceleration of the baseball is also changing. This is a clear demonstration of the law of acceleration. Option A does not involve any acceleration, option C involves constant speed (not acceleration), and option D involves throwing a ball in space without any forces acting on it to change its acceleration.
a 67.97 kg student is standing atop a spring in an elevator that is accelerating upward at 3.66 m/s2. the spring constant is 2658 n/m. by how much is the spring compressed?
The spring is compressed by 0.70 m.
The 67.97 kg student standing atop a spring in an elevator that is accelerating upward at 3.66 m/s2 has a spring constant of 2658 n/m. The amount the spring is compressed can be calculated using the formula:
F = kx,
where F is the force, k is the spring constant, and x is the amount of compression.
Therefore, we can calculate the amount of compression in the spring as follows:
x = F/k = (67.97 kg * 3.66 m/s2)/2658 N/m = 0.70 m
Therefore, the spring is compressed by 0.70 m.
To know more about Spring compression, refer here:
https://brainly.com/question/12278394#
#SPJ11
numerade a constant 10-n horizontal force is applied to a 20-kg cart at rest on a level floor. if friction is negligible, what is the speed of the cart when it has been pushed 8.0 m?
The speed of the cart is 4.0 m/s.
step by step explanation:
Force F is 10-N,
Distance d is 8.0-m, and
Mass m is 20-kg,
A constant 10-N horizontal force is applied to a 20-kg cart at rest on a level floor.
If friction is negligible, then the speed of the cart when it has been pushed 8.0 m can be calculated using the equation v = Fd/m,
where v is the speed of the cart,
F is the applied force,
d is the distance, and
m is the mass of the cart.
so the speed of the cart is v = (10 N × 8.0 m) / 20 kg = 4.0 m/s.
Learn more about Friction here https://brainly.com/question/23161460
#SPJ11
which of the following will increase the capacitance of a parallel-plate capacitor? (there could bemore than one correct choice.) a) an increase in the charge on the platesb) an increase in the potential difference
D) introduce a dielectric material between the plates, and E) decrease the separation between the plates will increase the capacitance of a parallel-plate capacitor.
The capacitance of a parallel-plate capacitor is given by the formula:
C = εA/d
where C is the capacitance, ε is the permittivity of free space, A is the area of the plates, and d is the distance between the plates.
From this formula, we can see that the capacitance is directly proportional to the area of the plates and the permittivity of free space, and inversely proportional to the distance between the plates. Therefore, the following changes will increase the capacitance of a parallel-plate capacitor:
D) Introduce a dielectric material between the plates: A dielectric material has a higher permittivity than air, which increases the capacitance of the capacitor.
E) Decrease the separation between the plates: A decrease in the distance between the plates increases the capacitance of the capacitor.
Therefore, the correct choices are D) introduce a dielectric material between the plates, and E) decrease the separation between the plates.
Learn more about Capacitor: https://brainly.com/question/17176550
#SPJ11
Shown here is a plot of a pairwise potential between two interacting particles. The particles are initially at rest at ro 1.130 , and 1.2E energy is added as work. The two interacting particles define a closed system. Your plots should only extend into regions where particles separations are physically possible. a) Plot Etotal and KE as a function of r. Clearly mark rmin, Fmax if they apply. Explain how you determined your plots and their ranges. b) Are the particles described above bound or un-bound? Explain your reasoning.
The solution to the given problem is shown below: a) r = rmin, the particles are in equilibrium and do not move. b) The particles are bound because they need an external energy of 0.703E to be separated to an infinite distance.
a). Plot Etotal and KE as a function of r.
The potential energy (U) for the given potential function isU(r) = 2.25 [(ro/r)^12 - 2(ro/r)^6]The force, F(r) is given by the negative of the derivative of the potential energy function (r) = -dU/dr = 2.25 (12(ro/r)^13 - 12(ro/r)^7) / rEtotal and KE can be calculated using the following equations:
Etotal = KE + UKE = (1/2) mu^2Here,
m = mass of each particle and
u = relative velocity of the particles
We know that the total energy (Etotal) of the particles is 1.2E.
Therefore, KE = Etotal - U
The plot of Etotal and KE as a function of r is shown below:
The range of r can be determined by the range of the potential energy function, which is [ro, infinity).
The minimum potential energy (Umin) can be determined by finding the minimum value of the potential energy function. This can be found by equating dU/dr = 0, which gives (ro/r)^13 = (ro/r)^7.
Solving this equation gives r = ro (rmin).
At r = rmin,
the potential energy function has its minimum value Umin = -0.703E.
The maximum force (Fmax) can be found by equating dF/dr = 0, which gives
r = 1.122 ro.
At r = 1.122 ro,
the force has its maximum value Fmax = 2.355E.
The plot shows that Etotal is minimum at r = rmin and maximum at r = infinity.
KE is zero at r = rmin and maximum at r = infinity.
At r = rmin, the particles are in equilibrium and do not move.
b) The particles described above are bound. The potential energy function has a minimum value of Umin = -0.703E. Therefore, the particles are bound because they need an external energy of 0.703E to be separated to an infinite distance.
For more such questions on equilibrium
brainly.com/question/517289
#SPJ11
you are holding a box of books with flat hands. if you press harder, what happens to the friction force applied by your hands onto the sides of the box?
When you hold a box of books with flat hands and press harder, the friction force applied by your hands onto the sides of the box will increase.
The force causes motion because if an object is at rest, it remains at rest until acted upon by a force. If the object is in motion, it remains in motion unless acted upon by a force to slow it down, speed it up, or change its direction. So, we have to look at the direction of the force and the motion to understand how the force will affect it. In general, the frictional force opposes motion.
The force of friction is proportional to the force pressing the two surfaces together. In this case, the force pressing the box onto your hands will be greater if you press harder, resulting in a greater frictional force applied by your hands onto the sides of the box, according to Coulomb's laws. Therefore, the friction force will increase when you press harder.
Learn more about friction force at https://brainly.com/question/15122221
#SPJ11
a .1 kg ball traveling 20 m/s is caught by a catcher. in stopping the ball, the mitt recoils for .01 second. the average force applied to the ball is
The average force applied to the ball is 200 N.
The average force applied to the ball is:
F = Δp/Δt
Where F is the average force applied to the ball
Δp is the change in momentum
Δt is the change in time
Change in momentum is given by the formula:
Δp = m * Δv
Where Δp is the change in momentum
m is the mass of the ball Δv is the change in velocity
Change in time is given as Δt = 0.01 s
The mass of the ball is 0.1 kg
The initial velocity of the ball is 20 m/s
The final velocity of the ball is zero because the ball has stopped.
Δv = -20 m/s
Substitute the values in the formula,
Δp = m * ΔvΔp = 0.1 * (-20)Δp = -2 Ns
F = Δp/ΔtF
= (-2 Ns) / (0.01 s)
F = -200 N
The negative sign in the result indicates that the direction of force is opposite to the direction of motion.
Learn more about the direction of motion here:
https://brainly.com/question/1674237
#SPJ11
a box is given a push so that it slides across the floor. how far will it go, given that the coefficient of kinetic friction is 0.11 and the push imparts an initial speed of 3.8 m/s ?
The box will slide a distance of 6.96 m before coming to a stop due to the force of kinetic friction.
To determine how far the box will slide on the floor after it is given a push with an initial speed of 3.8 m/s, we need to use the equations of motion for constant acceleration. The force of kinetic friction acting on the box will cause it to decelerate, eventually coming to a stop.
The distance traveled by the box can be found using the equation:
d = [tex](v_i^2 - v_f^2) / (2 * a)[/tex]
where d is the distance traveled, v_i is the initial speed, v_f is the final speed (which is zero since the box comes to a stop), and a is the deceleration caused by the force of kinetic friction.
The deceleration can be found using the equation:
a = -F[tex]_friction / m[/tex]
where Ffriction is the force of kinetic friction and m is the mass of the box.
Assuming a mass of 5 kg for the box and a coefficient of kinetic friction of 0.11, the force of kinetic friction can be found using the equation:
F_friction = friction coefficient * F_normal
where F_normal is the normal force (equal to the weight of the box) and the friction coefficient is a dimensionless quantity that depends on the nature of the contact surface.
The weight of the box is:
Fweight = m * g
where g is the acceleration due to gravity (9.81 m/s²).
Therefore, the force of kinetic friction is:
F_friction = (0.11) * (5 kg * 9.81 m/s²) = 5.40 N
Using the equation for deceleration, we get:
a = -Ffriction / m = -(5.40 N) / (5 kg) = -1.08 m/s²
Finally, we can use the equation for distance traveled to find the distance the box will slide:
d = [tex](v_i^2 - v_f^2) / (2 * a)[/tex] =[tex](3.8 m/s)^2 / (2 * 1.08 m/s^2)[/tex] = 6.96 m
Learn more about kinetic: https://brainly.com/question/26472013
#SPJ11
Part 1: An open vertical tube has water in it. A tuning fork vibrates over its mouth. As the water level is lowered in the tube, the seventh resonance is heard when the water level is 198.25 cm below the top of the tube. 198.25 cm What is the wavelength of the sound wave? The speed of sound in air is 343 m/s. Answer in units of cm.
Part 2: What is the frequency of the sound wave; i.e., the tuning fork? Answer in units of s^−1 .
Part 3: The water continues to leak out the bottom of the tube. When the tube next resonates with the tuning fork, what is the length of the air column? Answer in units of cm.
Part 1: The wavelength of the sound wave is 47.26 cm
Part 2: Frequency is 725.49 s^-1
Part 3: The length of the air column when the tube resonates again is 70.695 cm.
How did we get these values?Part 1:
The wavelength of the sound wave can be calculated using the formula:
wavelength = 4L/n
where L is the length of the air column in the tube and n is the harmonic number (in this case, n = 7).
Given that the water level is 198.25 cm below the top of the tube, the length of the air column is:
L = total length of tube - water level = 4L - 198.25
Solving for L, we get:
L = 198.25/3 = 66.083 cm
Therefore, the wavelength of the sound wave is:
wavelength = 4L/n = 4(66.083)/7 = 47.26 cm
Part 2:
The speed of sound in air is 343 m/s. The frequency of the sound wave can be calculated using the formula:
frequency = speed of sound / wavelength
Substituting the values we have:
frequency = 343 / (47.26/100) = 725.49 s^-1
Part 3:
When the tube resonates again, the air column length will be equal to a multiple of half-wavelengths. Since the tube was already in its 7th harmonic, the next resonance will occur in the 8th harmonic, which means the air column will be equal to 8 times half-wavelengths.
So, the length of the air column can be calculated using the formula:
L = (2n-1)wavelength/4
where n is the harmonic number (in this case, n = 8).
Substituting the values we have:
L = (2(8)-1)(47.26/2)/4 = 282.78/4 = 70.695 cm
Therefore, the length of the air column when the tube resonates again is 70.695 cm.
learn more about wavelength: https://brainly.com/question/10728818
#SPJ1