a rope passing through a capstan on a dock is attached to a boat offshore. the rope is pulled in at a constant rate of 6 ft/s and the capstan is 5 ft vertically above the water. how fast is the boat traveling when it is 12 ft from the dock?

Answers

Answer 1

Answer:The boat is traveling at a rate of 3 ft/s.

Step-by-step explanation:


Related Questions

a bike that goes from 6m/s to 16m/s in 20 seconds.

Answers

The initial velocity = vi = 6m/s

The final velocity = vf = 16 m/s

The total time = t = 20 seconds

The rate of change in velocity is called acceleration (a) that can be written as:

[tex]a\text{ = }\frac{Change\text{ in velocity}}{time}[/tex]

or

[tex]a\text{ = }\frac{vf-vi}{t}[/tex]

Put the values in the equation to get the value of 'a'.

[tex]a\text{ = }\frac{16\text{ - 6}}{20}[/tex][tex]a\text{ = }\frac{10}{20}[/tex]

or

[tex]a\text{ = }\frac{1}{2}[/tex]

hence, the value of a is 1/2.

Using the numbers 8, 6, 4, and 2, write an expression that equals 6.

Answers

Answer:

6+4,8-6, 4x2,8-2

Step-by-step explanation:

3. Your boss asks you to compare three phone plans. Identify the cheapest plan when an average of 190 text messages are sent each month. • Plan A costs a basic fee of $29.95 per month and 13 cents per text message • Plan B costs a basic fee of $53.00 per month and has unlimited text messages. • Plan C has no basic fee, but charges $0.28 per text message. 2021 Illuminate Education. Inc

Answers

Analyze each plan according to the given specifications.

Plan A:

The basic fee must be added to the product of 0.13 and the average messages sent.

[tex]29.95+190\cdot0.13=54.65[/tex]

Plan B:

It already includes the cost for unlimited messages.

[tex]53.00[/tex]

Plan C:

The plan costs the product of 0.28 and the average messages sent.

[tex]190\cdot0.28=53.2[/tex]

When comparing these plans, the cheapest one is Plan B, which only costs $53.00.

Trenton’s scouting group made 100 T-shirts for a charity fundraiser. The circle graph below compares how many of each different-colored T-shirt they made.

If the angle measure of the section for purple is 54°, how many purple T-shirts did Trenton’s scouting group make?
(Get it right, I will give you brainliest, thanks and 5* rating)

Answers

Trenton’s scouting group make 15 purple T-shirts.

How to find how much percent 'a' is of 'b'?

Suppose a number is 'a'. Suppose another number is 'b'. We want to know how much percent of 'b' is 'a'. Then, it is calculated as:

[tex]\dfrac{a}{b} \times 100[/tex]

We have been given that Trenton’s scouting group made 100 T-shirts for a charity fundraiser.

Also the angle measure of the section for purple is 54°, then;

54 / 360 = percent /100

percent = 15

Therefore, 15 percent of 100 T shirt would be;

15/100 x 100

15

Hence, Trenton’s scouting group make 15 purple T-shirts.

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solve (2x-3)²= 4x using the quadratic formula

Answers

Answer:

[tex]x = 2 \pm \frac12\sqrt7[/tex]

Step-by-step explanation:

Hello!

Expand the left-hand side of the equation:

(2x - 3)²(2x-3)(2x-3)(2x-3)(2x) +(2x-3)(-3)4x² - 6x - 6x + 94x² - 12x + 9

Create the Equation:

4x² - 12x + 9 = 4x4x² - 16x + 9 = 0Solve using the quadratic formula:[tex]x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}[/tex][tex]x = \frac{-(-16) \pm \sqrt{(-16)^2 - 4(4)(9)}}{2(4)}[/tex][tex]x = \frac{16 \pm \sqrt{256 - 144}}{8}[/tex][tex]x = \frac{16 \pm \sqrt{112}}{8}[/tex][tex]x = \frac{16 \pm 4\sqrt7}{8}[/tex][tex]x = 2 \pm \frac12\sqrt7[/tex]

The roots of the equation are [tex]x = 2 \pm \frac12\sqrt7[/tex]

Jasmine, multiply your age by 3 and add 6. Thenmultiply this sum by 2. James, multiply your age by 2and add 4. Then multiply this sum by 3. I predict youwill both get the same number!») B. Choose 4 whole numbers for the twins' age and test eachexpression. Make a table to show the numbers you tried and theresults.

Answers

Same age

See explanation below

Explanation:

Let the age of Jasmine = y

Multiplying Jasmine age by 3 and adding 6:

= (y × 3) + 6

= 3y + 6

Multiplyng the sum by 2:

2 × the sum = 2 × (3y + 6)

= 6y + 12

Let James age = z

Multiplying the age by 2 and adding 4:

James age × 2 = z × 2 = 2z

adding 4 = 2z + 4

Multiplying the sum y 3:

3 × the sum = 3 × (2z + 4)

= 6z + 12

Now since they are twins, they ae most likely same age

This means:

6y + 12 = 6z + 12

subtracting 12 from both sides:

6y = 6z

dividing both sides by 6:

y = z

Hence, Jasmine age is the same as James age

B) The expression for Jasmine = 2(3y + 6) = 6y + 12

The expression for James = 3(2z + 4) = 6z + 12

let the twin's age = 2, 3, 4, 5

when twin's age = 2

6y + 12 = 6(2) + 12 = 12 + 12 = 24

6z + 12 = 6(2) + 12 = 12 + 12 = 24

when twin's age = 3

6y + 12 = 6(3) + 12 = 18 + 12 = 30

6z + 12 = 6(3) + 12 = 18 + 12 = 30

when twin's age = 4

6y + 12 = 6(4) + 12 = 24 + 12 = 36

6z + 12 = 6(4) + 12 = 24 + 12 = 36

when twin's age = 5

6y + 12 = 6(5) + 12 = 30 + 12 = 42

6z + 12 = 6(5) + 12 = 30 + 12 = 42

Plotting the table:

how to find n(A-B)


q no 9 ii

sure branliest ​

Answers

Answer: 11

Step-by-step explanation:

[tex]A-B=\{2\}[/tex].

Since there is 1 element in this set, the answer is 1.

just tell me the slope of the line and where to plot the segments on the graph

Answers

Answer:

The slope is 2

Step-by-step explanation:

Take any two points on the line.  I am going to use the points (0,-8) and (4,0)  Points are in the form (x,y)  The y values form the two points is 0 and -8.  The x values are 4 and 0.

The slope is the change in y over the change in x.

[tex]\frac{0- -8}{4-0}[/tex] = [tex]\frac{8}{4}[/tex] = 2

A wedding planner placed two orders with a flower shop. The first order was for 13 bunches of roses and 4 palms, totaling $487. The second was for 6 bunches of roses and 2 palms, totaling $232. The receipts do not list the item per price. What is the cost of one bunch of roses and one palm?

Answers

Let's call X the cost of one bunch of roses and Y the cost of one palm.

Then, the first order was for 13 bunches of roses and 4 palms, totaling $487, so:

13X + 4Y = 487

Additionally, the second order was for 6 bunches of roses and 2 palms, totaling $232, so:

6X + 2Y = 232

Then, solving for Y on the first equation, we get:

[tex]\begin{gathered} 13X+4Y=487 \\ 4Y=487-13X \\ Y=\frac{487-13X}{4} \\ Y=\frac{487}{4}-\frac{13}{4}X \\ Y=121.75-3.25X \end{gathered}[/tex]

Replacing on the second and solving for X, we get:

[tex]\begin{gathered} 6X+2Y=232 \\ 6X+2(121.75-3.25X)=232 \\ 6X+2\cdot121.75-2\cdot3.25X=232 \\ 6X+243.5-6.5X=232 \\ -0.5X+243.5=232 \\ -0.5X=232-243.5 \\ -0.5X=-11.5 \\ X=\frac{-11.5}{-0.5} \\ X=23 \end{gathered}[/tex]

Then, we can replace the value of X and calculated the value of Y as:

[tex]\begin{gathered} Y=121.75-3.25X \\ Y=121.75-3.25\cdot23 \\ Y=121.75-74.75 \\ Y=47 \end{gathered}[/tex]

Answer: The cost of one bunch of roses is $23 and the cost of one palm is $47

please help solve the attatched question pleasee

Answers

Using complementary angles, the numerical value of the given expression is as follows:

2.

What are complementary angles?

Complementary angles are angles whose sum of the measures is of 90º.

The relevance of complementary angles in the context of this problem is that if a and b are complementary angles, then the sine of one angle is the cosine of the other angle, as follows:

sin(a) = cos(b).

Considering the angles of 40º and 50º in this problem, we have that:

sin(40º) = cos(50º).sin(50º) = cos(40º).

Hence these following simplifications are applied:

sin²(40º) + sin²(50º) = sin²(40º) + cos²(40º) = 1.cos²(40º) + cos²(50º) = sin²(50º) + cos²(50º) = 1.sin(40º)cos(50º) = sin(40º)sin(40º) = sin²(40º).cos(40º)sin(50º) = cos(40º)cos(40º) = cos²(40º).

Then the numerical value of the expression is given as follows:

1/1 + sin²(40º) + cos²(40º) = 1 + 1 = 2.

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Find the unit rate of gallon to mile:
1/4 of a gallon to 3/10 mile

Answers

The unit rate of gallon to mile is calculated as: 5/6 gallon per mile.

How to Find the Unit Rate Between Two Variables?

The unit rate between two variables is simply the ratio of the quantity of one variable to the quantity of the other variable, such that the the denominator of the will be equal to exactly 1.

We are given the variables gallons and miles, where 1/4 of a gallon is to 3/10 mile.

The unit rate between these two variables would be an amount of gallons per mile.

Thus, find the unit rate by dividing 1/4 by 3/10:

1/4 ÷ 3/10

= 1/4 × 10/3

= 10/12

= 5/6

The unit rate is therefore, 5/6 gallon per mile.

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What’s the answer plsss

Answers

Answer:

8.5 cm

Step-by-step explanation:

See attached worksheet.

Opposite 63 is ML (we are not after that)

Adjacent is MN

Hypotenuse is 18.8

Choose adjacent + Hypotenuse to find MN

AH - CAH, cos

Cos63 = A/18.8

x18. 8

18.8 x Cos63 = A

8.535.... = A

So, MN = 8.5cm

Ans: C

Hope this helps!

What number should be the exponent on the 10 so that the two numbers are equivalent? 75.6 - 10% = 0.00756 y = -3 C y = 3 c y y = 4 y = 4 =

Answers

Answer:

y = -4

Explanation:

Given the equation:

[tex]75.6\times10^y=0.00756[/tex][tex]\begin{gathered} 0.00756=7.56\times10^{-3} \\ =75.6\times10^{-4} \end{gathered}[/tex]

Thus, the number is -4.

How many students age 15 and above take a car to school? Show work
A. 18
B. 38
C. 87

Answers

im pretty sure its B or most likeley C

b:38

98 (total amt of students who take cars) - 60 (amount of students under 15 who take cars) = 38

Convert 41°F to degrees Celsius.
if necessary, round your answer to the nearest tenth of a degree.
Here are the formulas.
C=5/9(F-32)
F=9/5C+32

Answers

Answer:

5°C

Step-by-step explanation:

hope this helps, i used your formula :D

The width of a classroom is 4m less than the length.its area is 45m raised to power of two .find the dimensions of the class room​

Answers

Length =9 , second-order polynomial equation in a single variable. a 0. It has at least one solution because it is a second-order polynomial equation, which is guaranteed by the algebraic fundamental theorem.

What is quadratic equation?

x ax2 + bx + c = 0 is a quadratic equation, which is a second-order polynomial equation in a single variable. a 0. It has at least one solution because it is a second-order polynomial equation, which is guaranteed by the algebraic fundamental theorem. The answer could be simple or complicated.

L= 4 + W

Area is 45, so

L times W = 45

substituting the value of L, we get (4+W)*W=45, after simplifying this we get

4W+W2=45

W2+4W-45=0, this is a quadratic equation and after solving this we get the factors 9 and -5

( W+9) and (W-5) = 0

we get W=-9 or W=5, since width cannot be negative, so width = 5

substituting the value of W=5 in L = 4 +5, we get length = 9

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Second-order polynomial equation in one variable, length = 9. a 0. Since it is a second-order polynomial equation, which is ensured by the algebraic fundamental theorem, it must have at least one solution.

What is quadratic equation?

A quadratic equation, or second-order polynomial equation with a single variable, is x ax2 + bx + c = 0. a 0. Since it is a second-order polynomial equation, which is ensured by the algebraic fundamental theorem, it must have at least one solution. The solution might be straightforward or difficult.

L= 4 + W

Since the area is 45, L times W = 45. Substituting the value of L, we get (4+W)*W=45. Simplifying this, we get 4W+W2=45. W2+4W-45. = 0. This is a quadratic equation, and after solving it, we get the factors 9 and -5. Since width cannot be negative, we get W=-9 or W=5. Substituting the value of W=5 in L = 4 + 5,

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Assume that each circle shown below represents one unit. Express the shaded amount as a single fraction and as a mixed number. One Fraction: Mixed Number: Submit Answer attempt

Answers

The shaded amount can be express as a single fraction and mixed fraction below

[tex]\begin{gathered} \text{each circle=1 unit} \\ 2\text{ circle= 2 unit} \\ \text{each circle was divided into 12 parts} \\ \text{the shaded parts in the 24 parts =14} \\ Therefore, \\ 1\frac{2}{12}=\frac{14}{12}=1\frac{1}{6} \end{gathered}[/tex]

how many bit strings of length five either start with two zeros or end with two zeros? how many bit strings of length six either do not start with two zeros or do not end with two zeros? how many bit strings of length seven either start with four ones or end with four ones? how many bit strings of length eight do not start with a one or do not end with a one?

Answers

16 bit strings of length five either start with two zeros or end with two zeros are there; 32 bit strings of length six either do not start with two zeros or do not end with two zeros are there; 16 bit strings of length seven either start with four ones or end with four ones are there and 256

bit strings of length eight do not start with a one or do not end with a one are there.

A string is a combination which is made up of only two characters, either 1 or 0.

So, the combinations of the string can be found,

If the length of the bit string is 5, it means it will have 5 characters.

If this string either start with two zeroes or end with two zeroes. It mean there are only three positions are remaining which have two choices available for each place.

So, the total bit strings possible are,

= 2×(1×1×2×2×2)

= 16

16 such bit strings are possible.

If the length of the bit string is 6, it means it will have 6 characters.

If this string either do not start with two zeroes or do not end with two zeroes. It mean there are only four positions are remaining which have two choices available for each place.

So, the total bit strings possible are,

= 2×(1×1×2×2×2×2)

= 32

So, 32 such strings are possible.

Now, If the length of the bit string is 7, it means it will have 7 characters.

If this string either start with four ones or end with four ones. It mean there are only three positions are remaining which have two choices available for each place.

So, the total bit strings possible are,

= 2×(1×1×1×1×2×2×2)

= 16

So, 16 such strings are possible.

If the length of the bit string is 8, it means it will have 8 characters.

If this string either do not start with one and do not end with one. It mean there are only seven positions are remaining which have two choices available for each place.

So, the total bit strings possible are,

= 2×(1×2×2×2×2×2×2×2)

= 256

So, 256 such strings are possible.

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A restaurant uses four pounds of potatoes for a party of 12 people They are cooking potatoes for a party of 60 people what should I do

Answers

I think that the answer is 5

(c) Which is more unusual - an actress who receives an Oscar at 22 or an actor who
receives an Oscar at 55? Explain you answer using the percentages you calculated in
parts (a) and (b).
(d) Which is more unusual an actress who receives an Oscar at 55 or an actor who
receives an Oscar at 55? Calculate the standard score for the 55 year old actress.
Calculate the standard score for the 55 year old actor. Then answer the question and
explain your answer.

Answers

Which is more unusual – anactress who receives an Oscar at 22or

complete the two-column proof.
pleasee

Answers

∠2 ≅ ∠4 and m∠2 = 110°, and proved  m<3 = 70⁰.

The answers of the blank lines are:

A . Vertically opposite angle.

B . Linear angle .

C . Hence proved  .

Solution:

Given ,

∠2 ≅ ∠4 and m∠2 = 110°.

We have to prove

m<3 = 70⁰

Here ,

m<2 = m<4 => They are vertically opposite angles.

And here ,

m<3 and m<4 are supplementary angles.

m∠3 + m∠4 = 180° => linear angle .

m<4 = 110⁰  => since  m<2 = m<4

By substituting m∠4  we get,

m∠3 + m∠4 = 180°

= m∠3 + 110 = 180

= 180 - 110

m∠3 = 70°

Hence proved.

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Which system of linear inequalities is represented by the graph? O y=x-2 and x-2y 4 O y=x + 2 and x + 2y = 4 O y=x-2 and x + 2y = 4 O y =x-2 and x + 2y =-4

Answers

The two inequalities are (option c) y > x - 2 and2y + x < 4

Given,

Let's start by locating the red-hued area.

If the shadow is visible to be over the line, then the situation will be as follows:

y > ax + b

Hence the equation for the line is ax + b.

The slope is a, and the y-intercept is b.

The line in the graph intersects the y-axis at y = -2, which results in:

b = -2

Two points on the line are required to determine the slope; these points are (0, -2), and (2, 0)

We are aware of the slope for a line passing through the points (x1, y1) and (x2, y2) as follows:

a = (y2 - y1)/(x2 - x1) (x2 - x1)

The slope for this line will then be:

a = (0 - (-2))/(2 - 0) = 2/2 = 1

Then this line's equation is:

1x - 2

And here's the inequality:

y > x - 2.

The shaded area of the blue one is below the line, thus we will have:

y < ax + b

The y-intercept in this situation is y = 2.

This line crosses through the points (0, 2) and, as can be seen (4, 0)

The slope is then:

a = (0 - 2)/(4 - 0) (4 - 0) = -2/4 = -1/2

This inequality is then:

y < (-1/2)x + 2

If we rewrite this using the choices, we get the following:

y < (-1/2)x + 2

2y < -x + 2 ×2

2y + x < 4

The two inequalities are (option c) y > x - 2 and2y + x < 4

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Answer: C

Step-by-step explanation:

Which of the following is NOT an expression?
A
3x + 1

B
4x^2
​2
​​ - 6

C
5b

D
6y + 1z = 7x - 3w

Answers

Answer:

they are all expressions except D) 6y + 1z = 7x - 3w which is an equation, B

4x ^ 2

2

- 6 it is not known because it is poorly written.

Step-by-step explanation:

Which of the following is NOT an expression?

A   3x + 1  (expression)

B  4x^2 2- 6 (unknow)

C) 5b (expeession)

D) 6y + 1z = 7x - 3w    (Equation)

pls help me super confused on inequality

Answers

The inequality to this problem is:

40.50d - 400(0.12) ≤ 210

_____________________
Step 1:
40.50×d - 48 ≤ 210

Step 2:
40.50×d ≤ 210 + 48

Step 3:
40.50×d ≤ 258

Step 4:
d ≤ 258÷ 40.50

Final step:
d ≤ 6.37

What is the equation, in slope-intercept form, of the line that is perpendicular to the given line and passes through the point (2, −1)? y = Negative one-thirdx − One-third y = Negative one-thirdx − Five-thirds y = 3x − 3 y = 3x − 7

Answers

1st , 3rd & 5th choices

Step-by-step explanation:

perpendicular line would have a slope that is a

negative reciprocal

so if the slope is 3 then a perpendicular line would have a slope of -1/3

y - 1 = 1/3 (x + 2)

make the line look like y = mx + b

y = 1/3 (x + 2) + 1

y = 1/3 (x + 2) + 3/3

y = 1/3x + 2/3 + 3/3

y = 1/3x + 5/3

m = 1/3

perpendicular line has a slope of

m = -3

Draw and label a figure that shows line z intersecting plane R at point M.

Answers

A figure that shows line z intersecting plane R at point M could be like:

The plane is black, the line is red and the point is blue.

y
(1.3)
(5.b)
(a, 6)
(9.7)
All of the points in the graph are on the same line.
Find the slope of the line.
Submit and Explain

Answers

Answer is a= 7 b= 5

Slope is found with the formula

(y2 - y1) over (x2 - x1)

Starting with (1, 3) and (9, 7)

7-3 over 9-1
4 over 8
= 1/2 slope

Now to find our unknown b
(1, 3) and (5, b)

b - 3 over 5-1 (b=5)
5 - 3 over 5-1
2 over 4
= 1/2 slope

Now let’s find our unknown a

(a, 6) and (9, 7) (a = 7)
7 - 6 over 9 - 7
1 over 2
= 1/2 slope

I graphed the two given points, then graphed the one known point and found a and b on the line.
Answer is a= 7 b= 5

Slope is found with the formula

(y2 - y1) over (x2 - x1)

Starting with (1, 3) and (9, 7)

7-3 over 9-1
4 over 8
= 1/2 slope

Now to find our unknown b
(1, 3) and (5, b)

b - 3 over 5-1 (b=5)
5 - 3 over 5-1
2 over 4
= 1/2 slope

Now let’s find our unknown a

(a, 6) and (9, 7) (a = 7)
7 - 6 over 9 - 7
1 over 2
= 1/2 slope

I graphed the two given points, then graphed the one known point and found a and b on the line.

I need help with the question above. I took a pic.

Answers

Answer:

[tex]S=\frac{12}{5}[/tex]

Step-by-step explanation:

The common ratio of the following sequence is:

[tex]\frac{\frac{9}{16}}{\frac{3}{2}}=\frac{3}{8}[/tex]

If the common ratio is less than 1 or greater than -1 but not 0, we can use the following expression to determine the sum of the infinite geometric series:

[tex]S=\frac{a_1}{1-r}[/tex]

Therefore, if we have a common ratio of 3/8 or 0.375 and the first term of the series is 3/2.

The sum would be:

[tex]\begin{gathered} S=\frac{\frac{3}{2}}{1-\frac{3}{8}} \\ S=\frac{\frac{3}{2}}{\frac{5}{8}} \\ S=\frac{24}{10}=\frac{12}{5} \end{gathered}[/tex]

Can someone please help me

Answers

May's total profit given the revenue, fixed cost and variable cost is $250.

What is the total profit?

Profit is when the difference between revenue and total cost is positive. A loss is earned when the difference between revenue and total cost is negative.

Total cost is the sum of fixed cost and variable cost. Fixed cost is the cost that remains constant regardless of the level of output. Variable cost changes based on the level of output.

Total cost = variable cost + fixed cost

$9,000 + $300 = $9,300

Profit = revenue - total cost

$9,950 - $9,300 = $250

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Solve the equation b over 27 equals negative 3 for b.

81
9
−9
−81

Solve the equation 42 = v + 35 for v.

−77
77
−7
7

Solve the equation −128 = 4x for x.

−124
132
−32
32

Answers

The solution of the equation is as follows;

b = -81v = 7x = -32

How to solve equations?

An equation is a mathematical statement that is made up of two expressions connected by an equal sign.

In other words, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

The expression can be solved as follows:

b / 27 = - 3

cross multiply

b = -3 × 27

b = - 81

42 = v + 35

subtract 35 from both sides of the equations.

42  - 35 = v + 35 - 35

v = 42 - 35

v = 7

- 128 = 4x

divide both sides of the equations by 4

4x / 4 = - 128 / 4

x = - 32

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Answer:

b = -81v = 7 x = -32

Step-by-step explanation:

1) b/27 = -3, then b = ?

→ b/27 = -3

→ b = -3 × 27

→ [ b = -81 ]

Thus, value of b is -81.

2) 42 = v + 35, then v = ?

→ v + 35 = 42

→ v = 42 - 35

→ [ v = 7 ]

Thus, value of v is 7.

3) -128 = 4x, then x = ?

→ 4x = -128

→ x = -128/4

→ [ x = -32 ]

Thus, value of x is -32.

Other Questions
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