A sample of krypton gas in a container of volume 1.90 L exerts a pressure of 0.553 atm at 21°C. How many moles of gas are present?

[tex] \mathbb{ANSWER:}[/tex]

Solvents can also be solid and gas not only liquid.

Answer: working on it

Explanation:

Answer:

a. 4 moles aluminum chloride = 8 moles chlorine (since each mole of aluminum chloride contains 2 moles of chlorine)

b. 1 mole aluminum chloride = 1 mole aluminum (since each mole of aluminum chloride contains 1 mole of aluminum)

c. It is not possible to determine the number of moles of chlorine from the given information.

please make me brainalist and keep smiling dude

CaCl 2(aq)→Ca 2+(aq)+2Cl −(aq) is a dissοciatiοn equatiοn fοr hοw calcium chlοride dissοciates in water.

A chemical reactiοn is the transfοrmatiοn οf οne οr mοre chemicals, knοwn as reactants, intο οne οr mοre new cοmpοunds, knοwn as prοducts. The change in cοncentratiοn οf any οf the reactants οr prοducts per unit οf time can be used tο determine the rate οr speed οf a reactiοn. It is determined by the equatiοn rate=time + cοncentratiοn.

When dissοlved in water, the lattice οf an iοnic crystal disintegrates. When an iοnic sοlid substance dissοlves, dissοciatiοn—the separatiοn οf iοns—οccurs. Iοnic substances that are placed in water will break apart intο a pοsitive iοn and a negative iοn, a prοcess knοwn as electrοlytic dissοciatiοn οr iοnic dissοciatiοn. Iοnizatiοn is a term used tο describe this kind οf dissοciatiοn respοnse. Iοnizatiοn is the name οf the reactiοn, while electrοlytic sοlutiοns are the results.

Therefοre,

CaCl 2(aq)→Ca 2+(aq)+2Cl −(aq) is a dissοciatiοn equatiοn fοr hοw calcium chlοride dissοciates in water.

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The solvents that are not suitable for liquid-liquid extraction of an aqueous layer are 1. n-pentane, 3. hexanes, and 6. isopropanol.

Liquid-liquid extraction (LLE) is a separation process that is commonly used in the laboratory to separate and purify a solvent-containing dissolved solute mixture. Liquid-liquid extraction may be utilized to segregate an aqueous solution containing one or more organic solutes from a complex mixture of organic solutes or to remove a neutral substance from an acidic or basic aqueous solution. The process entails dissolving a compound or compounds from one solvent into another and then separating the newly formed two-phase system.

The solvents that are not suitable for liquid-liquid extraction of an aqueous layer are as follows:

1. n-pentane 3. hexanes 6. isopropanol

The following solvents are suitable for liquid-liquid extraction of an aqueous layer:

2. dimethyl sulfoxide 4. dichloromethane 5. toluene

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Answer:

we need 1.605 grams of AgNO3 to prepare 237.3 mL of 0.0312 M solution.

Explanation:

First, let's write down the formula for calculating the mass of a solute:

mass = molarity x volume x molar mass

We are given the volume and molarity of the solution, so we just need to find the molar mass of AgNO3.

AgNO3 has a molar mass of 169.87 g/mol.

Now we can substitute into the formula:

mass = 0.0312 mol/L x 0.2373 L x 169.87 g/mol

mass = 1.605 g

Therefore, we need 1.605 grams of AgNO3 to prepare 237.3 mL of 0.0312 M solution.

Answer:

A the volume of the ballon will decrease

Explanation:

This is because the temperature decreased so the particles slowed down and need less room or volume to move around and collide in

Answer:

Inversely proportional.

Explanation:

The density and temperature relationship for ideal gases is mathematically written as- Density and Temperature Relationship The density and temperature relation are proportionate. That is, the density is inversely proportional to temperature.

chemical isotope analysis is particularly useful for considering ancient diets because it provides information that cannot be obtained from other sources.

Chemical isotope analysis is particularly useful for considering ancient diets because it can reveal the types of foods that were consumed by ancient people. This type of analysis is based on the fact that different isotopes of elements such as carbon, nitrogen, and oxygen are found in different types of foods.

For example, the isotopes of carbon found in wheat and barley are different from those found in meat and dairy products. By analyzing the isotopes of carbon, nitrogen, and oxygen in the bones and teeth of ancient people, researchers can determine what types of foods were consumed by these people.

This information can help researchers to understand how ancient people lived, what types of foods they ate, and how their diets may have affected their health and well-being. It can also provide insight into how food production and consumption patterns have changed over time.

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A closed network of blood vessels, comprising arteries, veins, and capillaries, transports blood throughout the body.

These are some examples of the route blood takes:

The largest artery in the body, the aorta, is used to push blood out of the heart.

The aorta divides into smaller arteries that supply blood to the body's many organs and tissues.

The arteries gradually shrink to the size of arterioles, which are tiny channels that can assist control blood pressure and flow.

The tiniest blood veins in the body, known as capillaries, are then reached via arterioles. The blood and cells of the organism exchange nutrients and gases through capillaries.

Then, blood exits the capillaries and enters the tiny veins called venules.

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Answer:

Igneous and metamorphic rocks are two of the three major types of rocks found on Earth, with the third being sedimentary rocks. Igneous rocks are formed from the solidification of molten magma or lava, while metamorphic rocks are formed from the transformation of existing rocks due to high temperature and pressure.

The formation of igneous rocks begins when magma or lava cools and solidifies. Magma is molten rock that is located beneath the Earth's surface, while lava is magma that has erupted onto the surface. When magma or lava cools and solidifies, it forms igneous rocks. There are two types of igneous rocks: intrusive and extrusive. Intrusive igneous rocks form when magma cools and solidifies slowly beneath the Earth's surface, while extrusive igneous rocks form when lava cools and solidifies quickly on the Earth's surface. Examples of igneous rocks include granite, basalt, and pumice.

In contrast, the formation of metamorphic rocks occurs when existing rocks are transformed due to high temperature and pressure. Metamorphism can occur when rocks are buried deep within the Earth's crust, or when they are subjected to high pressure and temperature due to tectonic activity. The transformation of existing rocks can result in the formation of new minerals, textures, and structures within the rocks. Examples of metamorphic rocks include marble, slate, and gneiss.

In conclusion, the formation of igneous and metamorphic rocks differ in terms of their origin and formation process. Igneous rocks are formed from the solidification of molten magma or lava, while metamorphic rocks are formed from the transformation of existing rocks due to high temperature and pressure. While both types of rocks can be found in various locations around the world, they differ in their properties, appearance, and composition.

Explanation:

Clouds form behind a cold front and ahead of a warm front because of the difference in temperature and moisture between the two air masses.

When a cold front, which is an area of colder air, meets a warm front, which is an area of warmer air, the colder air forces the warmer air to rise. As the warmer air rises, it cools and the moisture in the air condenses to form clouds. This process is called adiabatic cooling.

Similarly, when a warm front meets a cold front, the warmer air rises over the colder air and cools, forming clouds. However, because the warm air is less dense than the cold air, it rises more slowly and the clouds that form are typically less dense and less likely to produce precipitation.

In both cases, the difference in temperature and moisture between the two air masses leads to the formation of clouds. This is why we often see clouds forming behind a cold front and ahead of a warm front.

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The motion of the red ball over the same time period | 20 | 100 | Red ball continues to travel 25 meters in 5 seconds.

Period, also known as the menstrual cycle, is the regular natural change that occurs in the reproductive system of women. It is a cycle of physical changes that happens to a female's body each month, usually lasting about 28 days. During this time, the uterus sheds its lining and a woman may experience bleeding from her. The period usually starts at puberty and ends when a woman reaches menopause.

| Time (s) | Position (m) | Explanation |

| - | - | - |

| 0 | 0 | Red ball starts at position 0 |

| 5 | 25 | Red ball travels 25 meters in 5 seconds |

| 10 | 50 | Red ball continues to travel 25 meters in 5 seconds |

| 15 | 75 | Red ball continues to travel 25 meters in 5 seconds |

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A horizontal line on a position-time graph indicates that the object is not moving; its position is not changing.

A position-time graph is a type of graph used to show the change in the position of an object over time. It is typically a line graph with the x-axis representing time and the y-axis representing position.

The slope of the line corresponds to the speed of the object, while the area under the line represents the total distance traveled by the object.

Furthermore, the velocity of an object is represented by the slope of a location graph. Hence, the slope's value at a given instant corresponds to the object's velocity at that precise moment.

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Particle splitting can occur through various mechanisms, such as nuclear fission, radioactive decay, and particle collisions.

Nuclear fission involves the splitting of an atomic nucleus into two or more smaller nuclei, releasing a significant amount of energy in the process. Radioactive decay is the natural process by which unstable atomic nuclei emit particles or radiation to become more stable. Particle collisions can also lead to the splitting of particles, as high-energy particles can break apart atomic nuclei or other particles.

These smaller particles may be subatomic particles such as protons, neutrons, and electrons, or even smaller particles like quarks and leptons.

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The percent composition by mass of sodium chloride and potassium chloride in the mixture is 90.4% sodium chloride and 9.6% potassium chloride.

The percent composition by mass of sodium chloride and potassium chloride in the mixture can be calculated using the following equation:

%Mass Sodium Chloride = (Mass of Sodium Chloride / (Mass of Sodium Chloride + Mass of Potassium Chloride)) x 100

%Mass Potassium Chloride = (Mass of Potassium Chloride / (Mass of Sodium Chloride + Mass of Potassium Chloride)) x 100

Mass of Sodium Chloride = (32.8mL)(0.384M)(58.44g/mol) / 1000mL = 0.73 g

Mass of Potassium Chloride = 0.807 g - 0.73 g = 0.077 g

%Mass Sodium Chloride = (0.73 g / (0.73 g + 0.077 g)) x 100 = 90.4%

%Mass Potassium Chloride = (0.077 g / (0.73 g + 0.077 g)) x 100 = 9.6%
Therefore, the percent composition by mass of sodium chloride and potassium chloride in the mixture is 90.4% sodium chloride and 9.6% potassium chloride.

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Answer:

21.58 mL

Explanation:

this is Charles' law

V1/T1 = V2/T2

Temperature must be in Kelvin

V2= V1 X T2 / T1

32.2  x203.15 / 303.15

dont need pressure since its the same.

Answer:

524.21 g/mol

Explanation:

The molar mass of a compound is the sum of the atomic masses of all the atoms in its chemical formula. The molecular formula of Prussian Blue is Fe(CN)18.

The atomic mass of iron (Fe) is 55.85 g/mol. The atomic mass of carbon is 12.01 g/mol and the atomic mass of nitrogen (N) is 14.01 g/mol. So the molar mass of the CN group is 12.01 g/mol + 14.01 g/mol = 26.02 g/mol.

Since there are 18 CN groups in one molecule of Prussian Blue, the total contribution of the CN groups to the molar mass of Prussian Blue is 18 × 26.02 g/mol = 468.36 g/mol.

So the molar mass of Prussian Blue is 55.85 g/mol + 468.36 g/mol = 524.21 g/mol.

Answer:

It's the type of radiation that lower frequency waves (such as visible light, microwaves, or radio waves) emit. Non-ionizing radiation is the kind that humans are typically exposed to when using electromagnetic wave-emitting technology, such as mobile phones, TVs, computers, powerlines, or microwaves.

Explanation:

hope this helps

TRNA binds to mRNA codon 5'-AUG-3' through complementary base pairing, carrying methionine.

Transfer RNA, also known by the acronym tRNA and formerly known as soluble RNA (sRNA), is an adaptor molecule made of RNA that, in eukaryotes, usually has a length of 76 to 90 nucleotides[2]. It acts as the physical connection between the mRNA and the amino acid sequence of proteins. tRNAs from bacteria usually have shorter genomes (mean = 77.6 bp) than those from archaea and eukaryotes (mean = 83.1 bp and 84.7 bp, respectively).

The mature tRNA exhibits the reverse trend, with eukaryotes having the smallest mature tRNAs (median = 74.5 nt), while tRNAs from bacteria are typically longer (median = 77.6 nt) than tRNAs from archaea (median = 76.8 nt).

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Answer:

Explanation:

1) 1; 1; 2

2) 2; 6; 2; 3

Answer: NH4NO3 ⟶ 2N2O + 4H2O (balanced equation)

Coefficients: 1, 2, 4

2Fe + 6HCl ⟶ 2FeCl3 + 3H2 (balanced equation)

Coefficients: 2, 6, 2, 3

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Modern chemical fertilizers include one or more of the three elements that are most important in plant nutrition: nitrogen, phosphorus, and potassium. Of secondary importance are the elements sulfur, magnesium, and calcium.

Answer: The most common useful element in fertilizer is mostly nitrogen since it is also found in air

The pKa of [tex]NH^{4+[/tex] would be 9.51.

To solve the problem, we can use the equation for the ionization constant of a weak base, Kb:

Since NH3 is a weak base, we can assume that the concentration of OH- ions produced by water is negligible. Thus, we can simplify the equation to:

The equilibrium expression for the ionization of NH3 can be written as:

The equilibrium constant for this reaction is:

Since the concentration of OH- is negligible, we can assume that:

Substituting Kb and Kw into the equation above, we get:

Since NH3 is only 1.1% ionized, we can assume that [NH4+] ≈ [OH-] = 5.6 x 10^-10

Using the equation for the ionization constant of NH4+, we get:

Since NH3 is a weak base, we can assume that [H3O+] ≈ [OH-] = 5.6 x 10^-10

Substituting the values into the equation, we get:

Ka = (0.15 x 0.011)/(5.6 x 10^-10) = 3.1 x 10^-10

Finally, we can use the relationship between Ka and pKa:

pKa = -log(Ka) = -log(3.1 x 10^-10) = 9.51

Therefore, the pKa of NH4+ is 9.51.

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After 11 years, a tritium sample will contain about 41.6% of the original amount.

A hydrogen isotope with a half-life of 12.3 years, tritium (also known as T or 3H) decays to 3He through beta decay.

Applying the formula for the half-life:N(t) = N₀(1/2)^(t/T)

where N(t) is the quantity still present at time t, N0 is the starting quantity, t is the time since the beginning of time, and T is the half-life.

For tritium, we have T = 12.3 years, and t = 11 years.

Substituting these values, we get:

N(11) = N₀(1/2)^(11/12.3)

We can multiply by 100 and divide N(11) by N0 to determine how much is left:

% remaining = (N(11) / N₀) * 100

% remaining = (1/2)^(11/12.3) * 100

% remaining = 41.6%

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Here are the number of unpaired electrons for each of the given atoms:

Y: 0, Br: 1 , Ca: 0, Sn: 2, Br: 1

In order to determine the number of unpaired electrons for each of the given atoms, we need to look at the electron configuration for each atom.

Y (yttrium): Y has an electron configuration of [Kr] 4d¹⁰ 5s². This means that Y has a completely filled 4d subshell and no unpaired electrons.

Br (bromine): Br has an electron configuration of [Ar] 3d¹⁰ 4s² 4p⁵. This means that Br has seven electrons in its outermost energy level (4p⁵), and one of these electrons is unpaired.

Ca (calcium): Ca has an electron configuration of [Ar] 4s². This means that Ca has two electrons in its outermost energy level (4s²), and both of these electrons are paired.

Sn (tin): Sn has an electron configuration of [Kr] 4d¹⁰ 5s² 5p². This means that Sn has two electrons in its outermost energy level (5p²), and one of these electrons is unpaired.

Br (bromine): As above, Br has an electron configuration of [Ar] 3d¹⁰ 4s² 4p⁵. This means that Br has seven electrons in its outermost energy level (4p⁵), and one of these electrons is unpaired.

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correct form of question should be:

The mass of copper produced is  0.635 g from the question that has been asked here.

Stoichiometry is the study of the quantitative relationships between reactants and products in a chemical reaction. It involves the use of balanced chemical equations to determine the ratios of reactants and products in a reaction.

We can see that the reaction equation is;

Zn(s) + CuSO4(aq) → ZnSO4(aq) + Cu(s)

Number of moles of Zn = 1.2g/65 g/mol

= 0.018 moles

Number of moles CuSO4 = 50/1000 * 0.2

= 0.01 moles

Then;

Since the reaction is 1:1

0.01 moles of CuSO4 will produce

0.01 mol * 63.5 g.mol

= 0.635 g

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Explanation:

1 sodium must contain free eelctron cuz electricity is created due to flow of electron

2 suspension

1. To conduct electricity, a solution must contain ions and free electrons.

2. The particles in a suspension can be separated from heterogeneous mixtures by passing the mixture through a filter.

3. Solutions - Smaller than 1 nm

Colloids - 1 nm to 1000 nm

Suspensions - Larger than 1000 nm

In a solution, ions can be present when an ionic compound dissolves and dissociates into its constituent ions. These ions can move freely within the solution, allowing for the conduction of electricity.

Free electrons are not bound to any specific atom and are able to move through the material, facilitating the flow of electric current.

A suspension is a heterogeneous mixture in which solid particles are dispersed in a liquid or gas medium.

Solutions contain particles that are smaller than 1 nanometer (nm) in size. Colloids consist of particles that range in size from 1 nm to 1000 nm. Suspensions contain particles that are larger than 1000 nm in size.

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The equivalency solution has a pH of 2.624.

Nitrous acid is frequently created by adding a mineral acid to aqueous sodium nitrite solutions. Typically, acidification is carried out at ice-cold temperatures, and HNO2 is consumed on-site. Nitrous acid in its free form is unstable and breaks down quickly.

In a neutralization process, weak nitrous acid (HNO2) reacts with strong basic KOH.

HNO2 + KOH → KNO2 + H2O

Then, we determine how many moles of KOH were used:

volume KOH x concentration equals moles KOH. KOH

moles KOH = 0.190 L x 0.377 mol/L

moles KOH = 0.07153 mol

Next, we calculate the initial concentration of HNO2:

concentration HNO2 = moles HNO2 / volume HNO2

concentration HNO2 = 0.07153 mol / 0.190 L

concentration HNO2 = 0.3765 M

[HNO2] = 0.5 x 0.3765 M

[HNO2] = 0.1883 M

The following equation can be used to model how nitrous acid dissociates in water:

HNO2 + H2O ⇌ H3O+ + NO2-

The following equation relates the pKa to the acid dissociation constant, Ka, for this reaction:

pKa = -log Ka

So we can find the Ka value from the given pKa:

pKa = -log Ka

3.35 = -log Ka

Ka = 10⁻³

Ka = 4.47 x 10⁻⁴

The relationship shown below is true for the concentrations of the species involved at equilibrium:

Ka = [H3O+][NO2-] / [HNO2]

Ka = [H3O+][NO2-] / [HNO2]

Ka = [H3O+] [HNO2]

Solving for [H3O+], we get:

[H3O+] = Ka / [HNO2]

[H3O+] = (4.47 x 10⁻⁴) / (0.1883 M)

[H3O+] = 0.002374 M

Finally, we can calculate the pH of the solution:

pH = -log[H3O+]

pH = -log(0.002374)

pH = 2.624

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