The acceleration due to gravity in m/s² at that altitude of 744 km is 9.797.
To find out what the acceleration due to gravity is in m/s² at an altitude of 744 km above the surface of earth, use the formula `g = Gm/r²`.
Given,The altitude of the satellite, h = 744 km,The radius of the earth, r = 6371 km, Formula for acceleration due to gravity:
g = Gm/r²
Here, the value of G, the universal gravitational constant, is 6.67 x 10^-11 Nm²/kg².Mass of the Earth, m = 5.97 x 10^24 kg.Let's calculate the radius of the orbit, R.Radius of the orbit = r + h= 6371 + 744 = 7115 km = 7.115 x 10^6 m.So, we have,
g = Gm/R²= 6.67 x 10^-11 x 5.97 x 10^24 / (7.115 x 10^6)²= 9.797 m/s².Therefore, the acceleration due to gravity in m/s² at that altitude is 9.797.
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a variable speed motor with an unbalanced is observed to have a displacement of 0.6 inches at resonance and 0.15 at a very high rpm. what is the damping ratio of the system?
The damping ratio of the system can be calculated as 0.13.
What is displacement?
Displacement at resonance, Xn = 0.6 inches
Displacement at very high RPM, Xv = 0.15 inches
Natural frequency of a system is:
f = (1/2π) * √(k/m)
where k is the stiffness of the system and m is its mass.
Let's assume the mass of the system as m and k is the stiffness of the system.
When the motor is at resonance, the frequency of the system is: n = f
where n is the frequency of the system.
When the motor is running at very high rpm, the frequency of the system is given as:v = f
where v is the frequency of the system.
Now, let's assume the damping coefficient of the system as c.
The displacement of the system:
X = [Xn * exp(-ζωnt)] * sin(ωdt)
where X is the displacement of the system, ζ is the damping ratio of the system, ωn is the natural frequency of the system and ωd is the frequency of the applied force.
The maximum value of the displacement is:
Xmax = Xn / (2ζ * √(1 - ζ²))
Here, Xmax = 0.6 inches when the motor is at resonance Xmax = 0.15 inches
when the motor is running at very high RPM, putting the given values of Xmax in the above equation, we can find the value of the damping ratio, ζ.
For resonance:0.6 = Xn / (2ζ * √(1 - ζ²))
=> 2ζ * √(1 - ζ²)
= Xn / 0.6=> 4ζ² * (1 - ζ²)
= Xn² / 0.36=> 4ζ⁴ - 4ζ² + 0.26244
= 0
Solving this quadratic equation gives us the value of ζ as 0.32.
For high RPM:
0.15 = Xn / (2ζ * √(1 - ζ²))
=> 2ζ * √(1 - ζ²)
= Xn / 0.15=> 4ζ² * (1 - ζ²)
= Xn² / 0.0225
=> 4ζ⁴ - 4ζ² + 1.728 = 0
Solving this quadratic equation gives us the value of ζ as 0.13.
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a 2.0 m tall man is 10 m in front of a camera with a 25 mm focal length lens. how tall is his image on the detector?
A 2.0 m tall man is 10 m in front of a camera with a 25 mm focal length lens, the height of the image on the detector is approximately 5.01 mm.
To determine the height of the image of a 2.0 m tall man who is 10 m in front of a camera with a 25 mm focal length lens, we will use the lens formula and magnification formula.
First, let's use the lens formula: 1/f = 1/u + 1/v
Here, f is the focal length, u is the object distance, and v is the image distance. We have f = 25 mm, and u = 10 m (which we need to convert to millimeters, so u = 10,000 mm).
We can now solve for v: 1/25 = 1/10,000 + 1/v
To isolate v, let's first subtract 1/10,000 from both sides: 1/25 - 1/10,000 = 1/v Now,
find the least common denominator (LCD) and subtract: (400 - 1)/10,000 = 1/v 399/10,000 = 1/v
Now, take the reciprocal of both sides to solve for v: v = 10,000/399
Now that we have the image distance (v), we can use the magnification formula to find the height of the image: magnification (m) = image height (h') / object height (h) = v / u
We want to find h', so we can rearrange the formula: h' = h * (v / u)
Plug in the known values (h = 2.0 m, u = 10,000 mm, and v = 10,000/399 mm), and convert h to mm (2.0 m = 2,000 mm): h' = 2,000 * (10,000 / 399) / 10,000 Simplify the expression: h' = 2,000 / 399
So, the height of the image on the detector when the man is 2.0m tall, 10 m in front of a camera with a 25 mm focal length lens is approximately 5.01 mm.
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A billiard ball of mass m = 0.150 kg hits the cushion of a billiard table at an angle of θ1 = 60.0 degrees at a speed of v1 = 2.50 m/s. It bounces off at an angle of θ2 = 47.0 degrees and a speed of v2 = 2.20 m/s.
a) What is the magnitude of the change in the momentum of the billiard ball?
b) In which direction does the change of momentum vector point? (Take the x-axis along the cushion and specify your answer in degrees.)
The magnitude of the change in the momentum of the billiard ball is 0.268 kg⋅m/s. The direction of the change of momentum vector points at 59.6 degrees, measured counterclockwise from the x-axis along the cushion.
This result can be found by using the equation for conservation of momentum, which states that both the magnitude and the direction of the momentum before and after the collision must be the same.
Since the mass and the speed of the ball changed, the direction of the vector must have changed as well. In this case, the vector changed direction from 60 degrees to 47 degrees, a difference of 13 degrees.
This means that the vector must have rotated counterclockwise by 13 degrees, or in other words, the change of momentum vector points at 59.6 degrees, measured counterclockwise from the x-axis along the cushion.
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g what is the ideal banking angle (in degrees) for a gentle turn of 1.40 km radius on a highway with a 105 km/h speed limit (about 65 mi/h), assuming everyone travels at the limit?
To calculate the ideal banking angle for a gentle turn
The ideal banking angle for a gentle turn of radius R, with velocity v, and coefficient of friction µ between the road and the tires can be calculated by the formula:
Tan(θ) = (v^2) / (gR)
where g is the acceleration due to gravity = 9.81 m/s²
θ is the banking angleIn this problem,
the radius of the gentle turn is R = 1.40 km = 1400 m
The speed limit is v = 105 km/h = 29.1667 m/s
Applying the formula,
Tan(θ) = (29.1667 m/s)^2 / (9.81 m/s² x 1400 m)
= Tan(θ) = 0.41435θ
= Tan^-1(0.41435)θ = 21.25°
Therefore, the ideal banking angle (in degrees) for a gentle turn of 1.40 km radius on a highway with a 105 km/h speed limit (about 65 mi/h), assuming everyone travels at the limit is 21.25 degrees.
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imagine you have a sensitive radio telescope and you would like to look at the sun. is it reasonable to expect that you would see it?
Yes, it is reasonable to expect that you would see the Sun with a sensitive radio telescope.
Radio waves can penetrate through the clouds and the atmosphere, so with a powerful radio telescope you can observe the Sun even on a cloudy day.
Gather the necessary components of the radio telescope, such as a dish and receiver. Point the radio telescope towards the Sun. Tune the receiver to the proper frequency. Take a look at the results from the telescope and observe the Sun.
Therefore, you can expect that you would see the Sun with a sensitive radio telescope.
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A sound wave has a frequency of 687 Hz in air and a wavelength of 0.49 m. What is the temperature of the air? Relate the speed of sound in air to temperature in units of Kelvin, but answer in units of Celsius. Assume the velocity of sound at 0◦C is 333 m/s.
Answer in units of deg C.
The temperature of the sound air is approximately 17.57°C.
Soundwave calculation.
We can use the formula for the speed of sound in air to relate it to temperature:
v = 331.5 * sqrt(T/273.15)
where v is the velocity of sound in air, T is the temperature in Kelvin, and 273.15 K is the temperature in Kelvin at 0◦C.
We know the frequency and wavelength of the sound wave in air, and we can use the formula for the speed of sound to find the velocity of sound:
v = f * λ
where f is the frequency of the sound wave λ is the wavelength.
Plugging in the given values, we get:
v = 687 Hz * 0.49 m
v = 336.63 m/s
Now we can use the formula for the speed of sound to find the temperature:
336.63 m/s = 331.5 * sqrt(T/273.15)
Solving for T, we get:
T = (336.63/331.5)^2 * 273.15
T = 290.72 K
Converting from Kelvin to Celsius, we get:
T = 290.72 - 273.15
T ≈ 17.57°C
Therefore, the temperature of the air is approximately 17.57°C.
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if a test point is marked 5 volts and a sedond test point is marked -3.3 volts. what voltage would you expect to read between the two points if the refernece lead is on the lowest voltage
The 5-volt reading we can expect between the two test points if the reference lead is on the lowest voltage.
The given data is as follows:
The first test marked voltage = 5 volts
The second test marked voltage = -3.3 volts
Let us assume that the two test points are there is a conductive track between them, the voltage between the two points can be calculated using the voltage difference between the two test points.
The voltage difference between the two test points is calculated as:
5 volts - (-3.3 volts) = 8.3 volts
If the reference lead is on the lowest voltage, It means that the negative side of the voltmeter is attached to the test point with the lower voltage which is -3.3 volts.
The voltage difference between the two test points is
8.3 volts - 3.3 volts = 5 volts
Therefore we can conclude that the 5-volt reading we can expect between the two test points.
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explain the use of air bags and seat belts in terms of momentum and impulse. please provide examples (and calculations) to elaborate your concepts.
Answer:
Explanation:
A seatbelt is designed to stretch a bit when the car decelerates rapidly. You travel forward a little while being stopped - you do not stop sharply as you would if you hit the dashboard. The seatbelt stretching increases the time over which your momentum is changed, thereby decreasing the force experienced by your body.
Airbags are made from a strong coated fabric. They are stored in a module mounted on the steering wheel and dashboard and side panels of the car. The inflation of them is initiated by crash sensors that activate upon impact at speeds of more than 10-15 miles per hour. They are mounted in several locations on the car body. In a crash, the sensor sends an electrical signal to the airbag which then causes the airbag to deploy. It ignites a chemical propellant which produces nitrogen gas, which then inflates the bag itself.
an asteroid orbits the sun in a highly elliptical orbit. as the asteroid gets closer to the sun, how are the total mechanical energy and gravitational potential energy of the asteroid-sun system changing, if at all?
The total mechanical energy and gravitational potential energy of the asteroid-sun system will change.
Asteroid-sun systemAs the asteroid gets closer to the sun in its highly elliptical orbit, both the total mechanical energy and gravitational potential energy of the asteroid-sun system will change.
The total mechanical energy of the asteroid-sun system is the sum of its kinetic energy and gravitational potential energy. As the asteroid moves closer to the sun, its kinetic energy will increase due to the increase in speed, but its gravitational potential energy will decrease due to the decrease in distance from the sun. Therefore, the total mechanical energy of the asteroid-sun system will remain constant, according to the law of conservation of energy.
However, if the asteroid encounters any gravitational forces or other external forces, such as a collision with another object or a thrust from a spacecraft, its mechanical energy can change.
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A 23.3 kg boy is moving along a circular path with the constant speed of 2.7 m/s. What is the magnitude of the centripetal force acting on the boy if the radius of the circle is 12.9 m. Note : Calculate the answer to 3 (three) significant figures by presenting it in normal ( decimal) form. Don't forget to include the unit.
The centripetal force for the given question would be 16.3 N.
Explanation:
The magnitude of the centripetal force acting on a 23.3 kg boy moving along a circular path with a constant speed of 2.7 m/s and the radius of the circle is 12.9 m is 16.3 N (newton).
What is centripetal force?
Centripetal force is the net force acting on an object moving in a circular path toward the center of the circle. It always points towards the center of the circle, hence the name "center-seeking force".
What is the formula for centripetal force?
The formula for centripetal force is Fc = (mv²)/r, where Fc is the centripetal force, m is mass, v is velocity or speed and r is the radius of the circular path.
In the given question: Mass, m = 23.3 kgVelocity, v = 2.7 m/s, Radius, r = 12.9. To calculate centripetal force,
F = (m x v^2)/r
Putting the given values in the above formula: F = (23.3 kg x (2.7 m/s)^2)/12.9 m= 16.3 N (newton)
Therefore, the magnitude of the centripetal force acting on the boy is 16.3 N (newton).
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determine the limit on the series resistance so the energy remaining after one hour is at least 85 percent of the initial energy.
The limit on the series resistance so that the energy remaining after one hour is at least 85 percent of the initial energy, is initial energy into 85% by the voltage.
Ohm's Law states that the current in a circuit is directly proportional to the voltage and inversely proportional to the resistance.
Therefore, the total resistance in a circuit can be calculated using the formula: R = V/I
The energy remaining after one hour must be at least 85 percent of the initial energy, we can calculate the resistance by rearranging the formula.
The total resistance can be determined by multiplying the initial energy by 85 percent and dividing it by the voltage. Thus, the limit on the series resistance is [tex]R = (Initial Energy *0.85) / V[/tex].
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An ice skater is spinning about a vertical axis with arms fully extended. If the arms are pulled in closer to the body, in which of the following ways are the angular momentum and kinetic energy of the skater affected?
Angular Momentum Kinetic Energy
(A) Increases Increases
(B) Increases Remains Constant
(C) Remains Constant Increases
(D) Remains Constant Remains Constant
(E) Decreases Remains Constant
An ice skater is spinning about a vertical axis with arms fully extended. If the arms are pulled closer to the body, the angular momentum of the skater will remain constant while the kinetic energy of the skater increases. The correct option is C.
The angular momentum of the skater is given by
[tex]L = I\omega[/tex],
where I is the moment of inertia of the skater and ω is the angular velocity.
When the skater pulls their arms in, their moment of inertia decreases due to the decreased distance between their body and the axis of rotation.
According to the conservation of angular momentum, the product of the moment of inertia and angular velocity must remain constant. Therefore, if the moment of inertia decreases, the angular velocity must increase to keep the angular momentum constant.
The kinetic energy of the skater is given by
[tex]K = (1/2)I\omega^2[/tex]
As the moment of inertia decreases and the angular velocity increases, the kinetic energy of the skater also increases because it is proportional to the square of the angular velocity.
Therefore, the correct answer is: (C) Remains Constant Increases. The angular momentum remains constant, while the kinetic energy increases due to the increased angular velocity.
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find the force between charges of +10.0 x 10*C and -50.0 x 10*C located 20>0cm apart
20 cm apart, the charges of +1.0 x 10⁻⁶ C and –1.0 x 10⁻⁶ C exert a force of 449.5 N on one another. This force is directed from the negative charge to the positive charge.
How can the force between two charges be determined?According to Coulomb's law, the force F between two point charges, q1 and q2, that are separated by a distance r, is computed as F=k|q1q2|r2.
It is possible to determine the force between two point charges using Coulomb's law:
F = k*(q1*q2)/r²
In this case, we have[tex]q1 = +10.0 x 10^-6 C, q2 = -50.0 x 10^-6 C, and r = 20 cm = 0.2 m.[/tex]
Plugging in these values, we get:
[tex]F = (8.99 x 10^9 N m^2/C^2) * [(+10.0 x 10^-6 C) * (-50.0 x 10^-6 C)] / (0.2 m)^2[/tex]
Simplifying, we get:
F = -449.5 N.
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a heat pump with a cop of 4.0 supplies heat to a building at a rate of 100 kw. determine the power input to the heat pump.
The power input to the heat pump is 25 kW.
The COP (coefficient of performance) of the heat pump is 4.0. This means that for every unit of power consumed by the heat pump, it supplies four units of heat to the building.
The rate at which the heat pump supplies heat to the building is 100 kW.
Therefore, the power input to the heat pump can be calculated as:
Power input = Power output / COP
Power input = 100 kW / 4.0
Power input = 25 kW
Hence, the power input to the heat pump is 25 kW.
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in an alternating current circuit that contains a resistor a inductor and a capacitor with 120v how do you find current
In an alternating current circuit that contains a resistor, an inductor, and a capacitor with 120V, you can find the current by using Ohm's Law.
Ohm's Law states that the current is equal to the voltage divided by the resistance.
To calculate the resistance in an alternating current circuit, you must take into account the resistor, inductor, and capacitor.
For example, if the resistor has a resistance of 10 ohms, the inductor has a resistance of 5 ohms, and the capacitor has a resistance of 20 ohms, then the total resistance would be 35 ohms.
Therefore, the current in the circuit would be 120V/35 ohms = 3.43A.
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a 1-kg rock that weighs 10 n is thrown straight upward at 20 m/s. neglecting air resistance, the net force that acts on it when it is half way to the top of its path is
A net force of 10 N acts on the rock when it is halfway to the top of its path.
The net force acting on the rock can be calculated using the following equation:
Fnet = ma
Where Fnet is the net force, m is the mass, and a is the acceleration.
When the rock is halfway to the top of its path, its velocity is zero since it momentarily stops at the top of its motion. As a result, its acceleration is equal to the acceleration due to gravity, which is -10 m/s² since it is acting in the opposite direction to the upward direction. This is the gravitational force acting on the rock.
We can now calculate the net force acting on the rock at this point in its motion:
Fnet = ma
Fnet = (1 kg)(-10 m/s²)
Fnet = -10 N
Since the acceleration due to gravity is acting downward and the rock is moving upward, the net force is equal to the force of gravity, which is 10 N.
Therefore, the net force that acts on the rock when it is halfway to the top of its path is -10 N or 10 N in the downward direction. This net force is equal in magnitude to the weight of the rock.
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while the general equations for the first and second law are written in terms of how the universe changes, dr. laude's preference is that we quickly rewrite them to reflect changes in what?
This is due to the fact that the first and second laws of thermodynamics are universally applicable fundamental principles that can be utilised to examine particular systems and processes.
How do chemical processes relate to the first and second laws of thermodynamics?The part of thermodynamics that deals with chemical reactions is called chemical thermodynamics. The first law states that energy is conserved and cannot be created or destroyed. Second law: When natural processes in a closed system result in a rise in entropy, they are spontaneous.
The second law of thermodynamics is what?According to the second rule of thermodynamics, an isolated system that is out of equilibrium over time must increase in entropy until it reaches the ultimate equilibrium value.
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if the frequency of the incoming light is decreased, will the energy of the ejected electrons increase, decrease, or stay the same?
If the frequency of the incoming light is decreased, the energy of the ejected electrons will decrease.
The frequency of the incoming light will affect the energy of the ejected electrons. This is because the energy of the ejected electrons is proportional to the frequency of the incoming light.
The energy of the electrons can be determined using the equation:
E = h * f,
where E is the energy, h is Planck’s constant, and f is the frequency of the incoming light. This equation shows that the energy of the electrons is directly proportional to the frequency of the incoming light.
Therefore, if the frequency of the incoming light is decreased, the energy of the ejected electrons will also decrease.
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if the rate of internal energy dissipation in a battery is 1.0 watt, and the current produced by the battery is 0.50 amps, what is the internal resistance of the battery?
If the rate of internal energy dissipation in a battery is 1.0 watt, and the current produced by the battery is 0.50 amps, the internal resistance of the battery can be calculated using Ohm's law. Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points. The proportionality constant is called the resistance of the conductor, which is expressed mathematically as V = IR, where V is the voltage, I is the current, and R is the resistance.
The power dissipated by the internal resistance of a battery is given by P = I2R, where P is the power, I is the current, and R is the internal resistance. The rate of internal energy dissipation in the battery is given as 1.0 watt, and the current produced by the battery is given as 0.50 amps.
Using Ohm's law, we can calculate the voltage across the battery as V = IR = 0.50 x R. Therefore, the power dissipated by the internal resistance of the battery is P = I2R = (0.50)2 x R = 0.25R.
Equating the power dissipated by the internal resistance of the battery to the rate of internal energy dissipation, we get:
0.25R = 1.0
Solving for R, we get:
R = 1.0/0.25 = 4 ohms.
Therefore, the internal resistance of the battery is 4 ohms.
Internal energy dissipation is the energy that is lost due to friction or resistance in a system. In the case of a battery, internal energy dissipation refers to the energy that is lost due to the internal resistance of the battery. The internal resistance of a battery is a measure of how much energy is lost due to the resistance of the battery's internal components. The higher the internal resistance of the battery, the more energy is lost as heat, which reduces the battery's efficiency.
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the period of oscillation of a nonlinear oscillator depends on the mass m, with dimensions of m; a restoring force constant k with dimensions of ml2t2 , and the amplitude a, with dimensions of l. dimensional analysis shows that the period of oscillation should be proportional to
The correct option is C, The period of oscillation should be proportional to A^-1 square root of m/k.
mass m, with dimensions of M
force constant k with dimensions of ML^-2T^-2
amplitude A, with dimensions of L
To find the relation for period of oscillation with dimension T
To get the dimension T from m,k and A
[tex]1/A*\sqrt{(m/k)} = 1/L*\sqrt{(M/ML^{-2}T^{-2}) }= 1/L*LT = T[/tex]
Oscillation refers to the repetitive variation of a physical quantity around a central value or equilibrium position. It is a common phenomenon in many natural and man-made systems, ringing from simple pendulums and springs to complex electrical circuits and biological processes.
In an oscillating system, the physical quantity, such as displacement, velocity, or current, continuously changes between maximum and minimum values with a fixed frequency and amplitude. The frequency of oscillation is the number of cycles per unit time, usually measured in Hertz (Hz), while the amplitude is the maximum deviation from the equilibrium position. Oscillations can be periodic, where the motion repeats itself exactly over a fixed time interval, or non-periodic, where the motion is irregular and unpredictable.
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Complete Question: -
The period of oscillation of a nonlinear oscillator depends on the mass m, with dimensions of M; a restoring force constant k with dimensions of ML^-2T^-2 and the amplitude A, with dimensions of L. Dimensional analysis shows that the period of oscillation should be proportional to
a) A square root of m/k b) A^2 m/k c) A^-1 square root of m/k d) (A^2k^3)/m
horses that move with the fastest linear speed on a merry-go-round are located anywhere, because they all move at the same speed. near the center. near the outside.
Horses that move with the fastest linear speed on a merry-go-round are located near the outside.
A merry-go-round is an amusement park ride that comprises a rotating circular platform equipped with seats or mounts for people to ride on. When the ride is operating, the circular platform rotates around a fixed central axis at a constant velocity, while the people on it rotate with the platform. Linear speed refers to the velocity of the object in a straight line path, regardless of its direction of movement.
Therefore, the linear speed of the mounts on the merry-go-round depends on the radius of the circular path they move on. The closer the horse is to the center, the shorter the path it has to cover during one rotation of the platform, meaning it has a slower linear speed. Conversely, the farther the horse is from the center, the longer the path it has to cover, hence it has a faster linear speed. As a result, the mounts located near the outside of the merry-go-round move with the fastest linear speed.
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an electric eel can generate a 278-v, 0.8-a shock for stunning its prey. what is the eel's power output?
The electric eel's power output is 222.4 Watts
Given voltage (V) = 278 V
Current (I) = 0.8 A
To find the electric eel's power output, we have to use the formula
P = IV,
Where P is the power output, I is current, and V is the voltage.
So, we can calculate the electric eel's power output as follows:
Power Output (P) = IVP
⇒278 × 0.8
Power Output (P) = 222.4 Watts
Hence, The power output of the electric eel is 222.4 Watts.
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a rising parcel of unstable air a rising parcel of unstable air can rise well into the mesosphere. cannot rise very far above the tropopause. can eventually escape into space. will not be slowed by entrainment.
A rising parcel of unstable air is an air mass that is warmer than the surrounding air and is therefore buoyant. It can rise until it reaches an area where its temperature is the same as the surrounding air, the tropopause.
The tropopause is the boundary between the troposphere (the lowest part of the atmosphere) and the stratosphere (the next layer of the atmosphere).
At this level, the air is very stable and so the air parcel cannot rise any further.
The air parcel may eventually escape into space, however it will not be slowed by entrainment, the process by which the parcel loses energy and slows down due to friction.
As the parcel rises, the atmospheric pressure decreases and the temperature increases due to the decrease in air density.
As it rises further, the air pressure decreases until it reaches the tropopause, where it then plateaus.
Once the air reaches the tropopause, it has reached a level of equilibrium and can no longer rise further as the temperature and pressure remain constant.
The tropopause also acts as a barrier to air moving from the stratosphere to the troposphere.
This is due to the temperature inversion that occurs when the temperature in the troposphere decreases with altitude while the temperature in the stratosphere increases with altitude.
This inversion creates a strong stratospheric temperature gradient, making it difficult for air to move between the two layers.
A rising parcel of unstable air can rise well into the mesosphere but cannot rise very far above the tropopause.
The tropopause acts as a barrier to air moving between the troposphere and the stratosphere due to its temperature inversion, and the air parcel may eventually escape into space without being slowed by entrainment.
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I have no clue what im doing..
If work = 100J and time = 20 seconds, what is power
Answer:
5 J/s or 5 watt
Explanation:
Given,
Work (W) = 100 J
Time (t) = 20 s
To find : Power (P)
Formula :
P = W/t
P = 100/20
P = 5 J/s
P = 5 watt
Note : -
J/s and watt are units are power.
if a bag has a mass of 25 kg, how much force must you apply vertically to lift it off of a baggage cart?
A force of 245 N must be applied vertically to lift the bag off the baggage cart.
The force that must be applied vertically to lift a bag off a baggage cart, given that the bag has a mass of 25 kg, can be determined using the formula F = m*g
where F is force, m is mass, and g is acceleration due to gravity. The value of g is 9.8 m/s².So, F = 25 kg x 9.8 m/s² = 245 N. Therefore, a force of 245 N must be applied vertically to lift the bag off the baggage cart.
The mass of the bag = 25 kg.The formula used is, F = m*gwhereF = Force required to lift the bagm = Mass of the bagg = Acceleration due to gravityF = 25 kg x 9.8 m/s² = 245 N.
Therefore, a force of 245 N must be applied vertically to lift the bag off the baggage cart.
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a ball is dropped from a distance 5 m above the ground, and it hits the ground with a certain speed. if the same ball is dropped from a distance 10 m above the ground, its final speed will be
The final speed of the ball dropped from a distance of 10 meters will be 49 m/s.
The final speed of the ball dropped from a distance of 10 meters will be higher than the final speed of the ball dropped from a distance of 5 meters. This is because of the effect of gravity on the ball.
As the ball falls, gravity will pull it toward the ground, giving it a greater speed as it falls further. This increase in speed is known as the "acceleration due to gravity."
When the ball is dropped from 10 meters, the ball will fall faster because of the increased distance it has to travel, allowing gravity to pull it down more quickly.
By the time it reaches the ground, it will have reached a higher velocity.
The equation for this acceleration due to gravity is:
Vf = Vi + g × t
Where Vf is the final speed, Vi is the initial speed, g is the acceleration due to gravity and t is the time.
Therefore, in order to calculate the final speed of the ball dropped from 10 meters, we can use this equation. Assuming the initial speed of the ball is zero and the acceleration due to gravity is 9.8 m/s2, we get:
Vf = 0 + 9.8 × (10/2)
Vf = 49 m/s
So, the final speed of the ball dropped from a distance of 10 meters will be 49 m/s.
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how does matter affect your daily lives?
Matter affects our daily lives in the sense all is composed of matter and energy.
What are matter and energy in the Universe and daily life?Matter and energy in the Universe and daily life are two basic elements that characterize the physic system and allow us to understand the world. In regard to matter, it is something that occupies space and has mass, while energy can perform work.
Therefore, with this data, we can see that matter and energy in the Universe and daily life are fundamental to understanding the universe.
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which term defines the distance from rest to crest, or from rest to trough?responsesamplitudeamplitudefrequencyfrequencyperiodperiodspeed
Amplitude is not measured from peak to trough, but from rest to peak or rest to trough.
The highest and lowest points on the surface of a wave are called crests and troughs respectively. The vertical distance between the peak and the trough is the height of the waves. The horizontal distance between two successive peaks or troughs is called the wavelength.
The amplitude of a wave is the maximum displacement of a particle on a medium with respect to its position of rest.
The amplitude can be thought of as the distance between rest and the peak. The amplitude from the rest position to the dip position can be measured in a similar manner.
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5. does it take the same amount of work to speed your car up from 25 m/s to 30 m/s as it does to speed it up from 30 m/s to 35 m/s? if not, which situation requires more work? why? use the cer framework to answer the question.
The same amount of work to speed up a car from 25 m/s to 30 m/s as it does from 30 m/s to 35 m/s is different because it requires more work to speed up a car from 30 m/s to 35 m/s than it does to speed it up from 25 m/s to 30 m/s.
Thus, the correct answer is "No, it doesn't".
The CER framework is a tool that can be used to answer questions that involve scientific principles. CER stands for Claim, Evidence, and Reasoning.
1. Claim: It does not take the same amount of work to speed up a car from 25 m/s to 30 m/s as it does to speed it up from 30 m/s to 35 m/s.
2. Evidence: Work is equal to force times distance, which means that the amount of work required to accelerate an object depends on the distance over which the force is applied. If the distance is shorter, less work will be done.
The distance over which the force is applied to speed up a car from 30 m/s to 35 m/s is shorter than the distance over which the force is applied to speed it up from 25 m/s to 30 m/s. This implies that more work is required to speed up a car from 30 m/s to 35 m/s than it does to speed it up from 25 m/s to 30 m/s. The equation for calculating work is W = F x D, where W is work, F is force, and D is distance.
3. Reasoning: Therefore, it requires more work to speed up a car from 30 m/s to 35 m/s than it does to speed it up from 25 m/s to 30 m/s. This is because the distance over which the force is applied to speed up a car from 30 m/s to 35 m/s is shorter than the distance over which the force is applied to speed it up from 25 m/s to 30 m/s. The work done on an object is a measure of the energy transferred to it. When more work is done on an object, more energy is transferred to it.
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a value of mass is given as 14.6 g to 15.2 g. a value of volume is given as 2.4 to 2.8 m3. state the density using reasonable outer limits.
The density using reasonable outer limits is the density of an object can be determined by dividing its mass (measured in grams, g) by its volume (measured in cubic metres, m3). To calculate the density using the given values of mass and volume, we can use the following formula: Density = Mass/Volume.
Therefore, the density of the given object can be calculated using the outer limits of mass and volume, which are 14.6 g to 15.2 g and 2.4 m3 to 2.8 m3, respectively. The calculated density of the given object is in the range of 5.75 g/m3 to 5.45 g/m3.
To calculate the density, the mass and volume of the object must be known. Mass is a measure of how much matter an object has, and is calculated in grams (g). Volume, on the other hand, is a measure of the amount of space an object takes up, and is calculated in cubic metres (m3).
When these two values are known, the density can be calculated using the formula: Density = Mass/Volume. In this case, the given values of mass and volume are 14.6 g to 15.2 g and 2.4 m3 to 2.8 m3, respectively. By substituting these values into the formula, the density of the object can be calculated as follows:
Density = Mass/Volume
Density = 14.6 g/2.4 m3 = 5.75 g/m3
Density = 15.2 g/2.8 m3 = 5.45 g/m3
Therefore, the density of the given object is in the range of 5.75 g/m3 to 5.45 g/m3.
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