The sphere has to be launched 4 times the initial height, h, to hit the same target.
What is the time of motion of the first sphere?The time taken for the first sphere to hit the target is calculated as follows;
d = V₀t₁
where;
V₀ is the initial horizontal velocityd is the horizontal distance travelled by the spheret is the time of motiont₁ = d/V₀
The height travelled by the ball;
h = ¹/₂gt₁²
t₁² = 2h/g
t₁ = √(2h/g)
The time of motion of the second sphere when it is launched at a speed of 2V₀.
t₂ = d/2V₀
t₂ = ¹/₂(d/V₀)
t₂ = ¹/₂(t₁)
The height of fall of the second sphere;
¹/₂(t₁) = √(2h/g)
[¹/₂(t₁)]² = 2h/g
t₁²/4 = 2h/g
t₁² = 4(2h/g)
Thus, the height the sphere need to be launched in order to hit the same target is determined by applying kinematic equation.
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a 95 kg man lying on a surface of negligible friction shoves a 74 g stone away from himself, giving it a speed of 4.0 m/s. what speed does the man acquire as a result?
As a result of the law of conservation of momentum, the man will acquire a speed of 3 . 10⁻³ m/s
The law of conservation of momentum states thta:
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Where:
u₁ , u₂ = initial velocity of object 1 and object 2
v₁ , v₂ = final velocity of object 1 and object 2
Since both the man and the shove are initially at rest, hence u₁ , u₂ = 0.
Therefore,
m₁v₁ + m₂v₂ = 0
Parameters given:
m₁ = 95 kg
m₂ = 74 gram = 74 . 10⁻³ kg
v₂ = 4 m/s
Plug these parameters into the equation:
95 . v₁ + 74 . 10⁻³ . 4 = 0
v₁ = 3 . 10⁻³ m/s
Hence, the man acquire a speed of 3 . 10⁻³ m/s, which is very small.
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a fish looking straight up toward the smooth surface of a pond receives a cone of rays and sees a circle of light filled with the images of sky and birds and whatever else is up there. this bright circular field is surrounded by darkness. explain what is happening and compute the cone angle.
The phenomenon that occurs here is known as the snell's window, and the cone angle is 98 degrees.
To calculate the cone angle,
The cone angle is equal to two times the critical angle which is say, Ф
To calculate the critical angle Ф take the equation sinФ = n1÷n2 where
n1 is the refractive index of air, and n2 is the refractive index of water.
The refractive index of air, n1 = 1,
The refractive index of water, n2 = 1.33,
Substituting these values in the equation sinФ = n1÷n2, the equation becomes
sinФ = 1÷1.33
solving for Ф
Ф = [tex]sin^{-1}[/tex](1÷1.33)
Ф = 49°
Cone angle = 2×Ф
Cone angle = 2×49
Cone angle = 98°.
The phenomenon taking place here is known as snell's window. In this phenomenon, the person under the water sees everything above the surface through a cone of light whose width is about 96°-98°. Whatever is outside this cone appears dark to the person who is under the water. This is caused due to the refraction of light in different mediums.
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Arthur walks 3 km north, and then turns east and walks 4 km. What is distance traveled and his displacement?
The distance travelled by Arthur is 7 km and his displacement is 5 km.
What is the distance covered by Arthur?
The distance travelled by Arthur during the entire motion is determined by summing the entire path covered during the motion.
Distance = 3 km + 4 km
Distance = 7 km
The displacement of Arthur during the entire motion is obtained by calculating the length of the shortest path between the initial and final position.
d = √(a² + b)
where;
a is the northward motionb is the eastward motiond = √(3² + 4²)
d = 5 km
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A rock hits the ground with a speed of 6.2m/s and a kinetic energy of 113.J. What is the rock’s mass in Kilograms?
The mass of the rock with a kinetic energy of 113J and a speed of 6.2m/s is approximately 5.88 kilograms.
What is the mass of the rock?Kinetic energy is simply the energy a body possesses due to its motion;
It is expressed as;
K.E = 1/2 × m × v²
Given the data in the question;
Kinetic energy K.E = 113J = 113kgm²/s²Velocity of the rock v = 6.2m/sMass of the rock = ?To determine the mass of the rock, plug the given values into the Kinetic energy formular and solve for m.
K.E = 1/2 × m × v²
113kgm²/s² = 1/2 × m × ( 6.2m/s )²
113kgm²/s² = 1/2 × m × 38.44m²/s²
113kgm²/s² = m × 19.22m²/s²
m = 113kgm²/s² / 19.22m²/s²
m = 5.88kg
Therefore, the mass of the rock is 5.88 kilograms.
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__ is the rate at which an object changes position
Velocity is the rate at which an object changes position.
___________________________________________
"What is velocity?"Velocity is a vector quantity that refers to "the rate at which an object changes its position."
Hope this helps!
Want to learn more? Visit below for more information about velocity.
Look up "Speed versus Velocity" at The Physics Classroom.com
_______ energy is defined as stored energy.
Answer:
Potential energy
Explanation: Potential energy is represented as a stored energy.
pls the answer.........................................................................................................................
a) The motion of the motorcyclist is a uniform motion
b) The distance is 600 m
c) The speed is 20 m/s.
What is the motion?We now that motion has to do with the change in the position of an object with time. In this case, we have the graph that described the motion of the motorcyclist . It is clear that the distance is increasing in equal amounts, in equal time intervals thus this is a uniform motion.
Looking at the graph, we can see that the motorcyclist covers 600 meters of distance within 30 seconds.
We can obtain the speed as the ratio of the distance to the time or the slope of the graph. Hence the speed is obtained from;
Speed = distance / time
Using the slope concept;
[tex]y_{2} - y_{1} /x_{2} - x_{1}[/tex]
= 600 - 0/30 - 0
= 20 m/s
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he radius of a circular oil slick expands at a rate of 4 m/min. (a) how fast is the area of the oil slick increasing when the radius is 58 m? (use symbolic notation and fractions where needed.)
It is 24 pi fast area of oil sick increasing when the radius is 60m.
This question we are given the rate of change is the radius T. R. D. T. Is equal to two m per minute. And we know that the area since we're talking about the radius theory of the seco which is pi R squared. And our D A t. R. Would be the first derivative of A. That will be two pi R. And our D A D. T. Would be equal to T. A. T. R. Multiplied by the era T. T. And already we can plug in our numbers. Here we have two pi R. A. Multiplied by two and we get four pi hi and this season meters squared per minute.
Now we want to find the value of our rate of change of area with time At R. A. is equal to 56. And therefore our D. A. T. T. At our escort 56 is equal to four pi my play by 56. And here we get 224 pi square meters per minute. This is our answer to part A no for part B. We are giving that At time is equal to zero is equal to zero. And our rate of change of radius the time is still equal to two meters per minute and Therefore from 0 to 3 we have a tiara Is equal to two d. T. And we integrate Both sides from 0 to 3. So on the left hand side we have our era on the right hand side we have to t From 0 to 3 and here we get six So our radius is six m.
Therefore our D a t t will be a quarter full pie. Sarah it R is equal to six and Plugging. In our 6th year. We have four pay And our era is six. We get 24 pi in this season square meters per minute. That's it. We had them.
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Question 6:A particle of mass 0.2 kg is moving in a straight line at speed 2.5ms, a constant force of magnitude FN is applied to it in the direction in which it is moving. The speed of the particle 5 seconds later is 4.5ms Find the value of F, magnitude of the force applied.
First, let's calculate the particle acceleration, using the formula below:
[tex]\begin{gathered} V=V_0+a\cdot t \\ 4.5=2.5+a\cdot5 \\ 5a=4.5-2.5 \\ 5a=2 \\ a=\frac{2}{5}=0.4\text{ m/s}^2 \end{gathered}[/tex]Now, to find the force applied, let's use the second law of Newton:
[tex]\begin{gathered} F=m\cdot a \\ F=0.2\cdot0.4 \\ F=0.08\text{ N} \end{gathered}[/tex]Therefore the value of F is 0.08 N.
A forklift raises a crate weighing 8.35 × 102 newtons to a height of 6.0 meters. What amount of work does the forklift do?
Answer:5110.2 joule
Explanation:Weight of the crate:- 8.35 x 102 N
Height to which the forklift lift the crate:- 6.0 M
Work done by the forklift=F.d
F=Gravitational Force =m.g
d=height=h
Work w=m.g.h
m.g=8.35 x 102 N
h=6.0 M
w=8.35x102N x 6.0M
w=5110.2NM
w=5110.2joule
How can we simplify the analysis of the state of motion of an object?
Answer:
The speed and direction of motion can be changed by applying force on an object and thus a force can bring a change in the state of motion of an object.
A cosmic-ray electron moves at 7. 5 × 10^6 m/s perpendicular to earth’s magnetic field at an altitude where the field strength is 1. 0 × 10^-5t. What is the radius of the circular path the electron follows?.
4.266 m is the radius of the circular path the electron follows
Electron's speed = 7.50 × 10⁶ m/s
Magnetic field, B = 1 × 10⁻⁵ T
Electron's mass. m = 9.11 × 10⁻³¹
Charge of electron, q = 1.6 × 10⁻¹⁹
We know the relation of radius of curvature, = 4.266 m
What is a circle's radius of curvature?Every point on a circle has a curvature that is equal to the reciprocal of the radius; for other curves (and straight lines, which can be thought of as circles of infinite radius), the curvature is equal to the reciprocal of the radius of the circle that at that point most closely approximates the curve.
The curvature's reciprocal, R, is the radius of curvature in differential geometry. It is equal to the radius of the circular arc that, at that moment, most closely resembles the curve for a curve. The radius of curvature for surfaces is the diameter of a circle that, individually or in combination, best fits a normal section.
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What number should be placed in front of HCI balance this chemical equation?
Zn + ___HCI ZnCI2 + H2
A. 1
B. 4
C. 2
D. 3
Coefficient 2 should be placed in front of HCl to balance the given chemical equation.
What is chemical equation?
Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.
A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .
The first chemical equation was put forth by Jean Beguin in 1615.By making use of chemical equations the direction of reaction ,state of reactants and products can be stated. In the chemical equations even the temperature to be maintained and catalyst can be mentioned.
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A force of 30.ON is acted on a block of mass 15.0kg placed on a horizontal surface but the boxdoes not move. Calculate the magnitude of the frictional force between the surfaces when theapplied force is along the horizontal and when it makes angle 60° with the horizontal.
We will have the following:
1. In the first case, we will calculate the normal force:
[tex]N=(15\operatorname{kg}\cdot9.8m/s^2)\Rightarrow N=147N[/tex]Then, we will have that the fricion coefficient will be:
[tex]\mu_f=\frac{30.0N}{147N}\Rightarrow\mu_f=\frac{10}{49}\Rightarrow\mu_f\approx0.20[/tex]So the magnitude of the friccional force when applied horizontally will be of 30.0N.
2. And the magnitude when applied horizontal but the block is on an inclined surface of 60°, we will have that:
[tex]F=(10/49)(15.0\operatorname{kg}\cdot9.8m/s^2)\cos (60)\Rightarrow F=15N[/tex]So, the friction force when the force is applied, is 15N.
suppose you observe a small star orbiting a much larger star. you observe that the small star is orbiting at a distance of 20 au (in terms of the semi-major axis of its orbit), and with an orbital period of 2 years. how massive is the large star? (hint: for this problem you can assume that the small star has a much smaller mass than the large star.)
The mass of the large star based on orbital period is 6912 x 10³⁰ kg.
We need to know about the orbital period to solve this problem. The orbital period depends on the semi-major axis, gravitational constant, and the mass of the massive object. It can be written as
T² = 4π².a³ / GM
where T is the orbital period, a is the semi-major axis, G is the gravitational constant and M is the mass.
From the question above, the given parameters are
a = 24 au = 24 . ³√(G.Msun yr²/ 4π²)
T = 2 years
Msun = 2 x 10³⁰ kg
By substituting the given parameters, we get
T² = 4π².a³ / GM
2² = 4π². (24 . ³√(G.Msun yr²/ 4π²))³ / GM
4 = 13824 Msun / M
M = 6912 x 10³⁰ kg
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its hard it have time help
Answer:
i think it's a
Explanation:
What is the speed of a rocket that starts with a speed of 120m/s and slows down at a rate of 22m/s2 for 4 seconds?
The final speed of the rocket, given it started with a speed of 120 m/s and slows down at a rate of 22 m/s² for 4 seconds is 208 m/s
How do I determine the final speed?From the question given above, the following parameters were obtained:
Initial speed (u) = 120 m/sAcceleration (a) = 22 m/s²Time (t) = 4 secondsFinal speed (v) =?The final speed of the rocket can be obtained as follow:
v = u + at
v = 120 + (22 × 4)
Clear bracket
v = 120 + 88
v = 208 m/s
Thus, we can conclude from the calculation above that the final speed of the rocket is 208 m/s
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a parallel-plate capacitor is connected to a battery. the energy of the capacitor is u0 . the capacitor is then disconnected from the battery and the plates are slowly pulled apart until the plate separation doubles. the new energy of the capacitor is u . find the ratio u/u0 .
The ratio u/u0 : 1/2
As the distance is doubled and the battery is connected, we know that Capacitance is given by: [tex]C= \frac{\epsilon_0 A}{d}[/tex]
As the distance between the plate is doubled, C will become: [tex]C= \frac{\epsilon_0 A}{2d} = \frac{C}{2}[/tex]
Now, as the battery is connected, Voltage will remain constant, therefore Charge Q will become: [tex]Q=\frac{CV}{2}[/tex]
The energy before doubling the distance between the plates was, U0 :
[tex]U_0 = \frac{1}{2}QV = \frac{1}{2}CV^2[/tex]
After doubling the distance, the Energy will become U:
[tex]U = \frac{1}{2}QV = \frac{1}{4}CV^2[/tex]
Therefore, the ratio will be:
[tex]\frac{U}{U_0} = \frac{\frac{1}{2}CV^2}{\frac{1}{4}CV^2} = \frac{1}{2}[/tex]
What is capacitor ?A capacitor is a bipolar electrical device that can store energy in the form of an electrical charge. It consists of two electrical conductors separated by a distance. The space between the conductors can be filled with a vacuum or an insulating material known as a dielectric. The ability of a capacitor to store charges is called capacitance. Capacitors store energy by keeping opposite charges away from each other. The simplest model of a capacitor is a parallel plate, which consists of two metal plates with a gap between them. However, different types of capacitors are manufactured in different shapes, styles, lengths, circumferences and materials.
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Two students, Jenny and Cho, are investigating motion.
Jenny walks in a straight line.
Cho measures the distance Jenny has walked at 10 s intervals.
State two measuring instruments the students should use.
Answer:
1: a measuring instruments the students should use for time is a stopwatch
2: a measuring instruments the students should use for distance is a measuring tape
Explanation:
pls mark brainliest
how to sketch the following:Sketch a ray diagram for a spherical convex lens with an object at Do = 2f. (Submit a file with a maximum size of 1 MB.)
Do = 2f means that object distance is 2 x focal length.
2 x focal length = radius of curvature
When an object is placed at the radius of curvature, a real, inverted image is formed at the other radius of curvature. The sizes of the image and the object are the same. The sketch is shown below
. overdriving your headlights is a. driving with only your parking lights on. b. driving at a speed that makes your stopping distance longer than the distance illuminated by your headlights. c. having your headlights aimed improperly. d. driving with your high-beam headlights on.
Overdriving is driving at a speed making the stopping distance longer than the distance illuminated by headlights.
Typically, one can utilize their headlights to schedule stops in dimly lit or low visibility locations. Typically, one can measure their stopping distance using the visible light cone in the headlights. Exceeding the stopping distance that the headlights highlight is overdriving. Thus, driving too fast and leaving little room to stop in an emergency is known as overdriving the headlights.
When the lights are far enough ahead of a person to illuminate the road, one should often stop so that they can see any approaching impediments. When one is traveling at a rate of speed that prevents them from stopping in that lit region, that rate of speed is taken into account.
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n sussex county, delaware, a post-halloween tradition is punkin chunkin, a competition in which contestants build cannons, catapults, trebuchets, and other devices to launch pumpkins to the greatest distance they can. tough hard to believe, pumpkins have been projected a distance of 1245 m (over 3 4 mi) in this contest. what is the minimum initial speed needed for such a shot?
110.53m/s is the minimum initial speed or initial velocity needed for such a shot.
The lowest speed at which a particular range is attained is determined. It is stated the distance that the pumpkins were hurled. By inserting the range of the pumpkin and the acceleration owing to gravity, the minimal velocity at which they were launched to go this distance was determined.
[tex]R=u_m^2/g[/tex]
[tex]1245.41m=(u_m^2/9.80m/s^2[/tex]
[tex]u_m^2=12217.47[/tex]
[tex]u_m=110.53m/s[/tex]
Any object susceptible to forces will move more quickly. This acceleration causes a change in the object's velocity. The speed of the item prior to the change brought on by acceleration is therefore known as the initial velocity. The speed will be the final speed once the object has been accelerating for some time.
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An explanation for planetary differentiation is_____________. question 5 options: all the planets are different colors and some have life, while others do not different scientist are chosen to explore planet similarities is the separation of different constituents of planetary materials resulting in the formation of distinct compositional layers. denser material tends to sink into the center and less dense material rises toward the surface. planets have different orbits around the sun and therefore consist of varying elements
One hypothesis for planetary differentiation is the process through which various layers with diverse chemical and/or physical features arise.
A planet's trajectory around a star, a natural satellite's path around a planet, or an artificial satellite's course around a space object or place, such as a planet, moon, asteroid, or Lagrange point, are examples of orbits in celestial mechanics.
A spacecraft, planet, moon, star, or other object travels on a curved route called an orbit when it is dragged by the gravity of another object.
The force of gravity is what pulls objects with mass in space. An orbit is a path an object follows as it travels around a certain location in space, such as the Moon's orbit of the Earth.
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a car with a mass of 1,060.0 kg accelerates from 0 to 88.0 km/h in 10.0 s. the driver applies the brakes when the car is moving at 88.0 km/h, and the car comes to rest after traveling 46.0 m. what is the net force (in n) on the car during its deceleration? (assume the car is traveling in the positive direction. indicate the direction with the sign of your answer.)
A car with a mass of 1,060.0 kg accelerates from 0 to 88.0 km/h in 10.0 sec .The net force (in n) on the car during its deceleration is F = 7812.5 N.
Given
m= 1000 kg
u= 0 m/s
V = 90 km/h = 25m/s
t = 10 sec
a)by equation of motion :
v = u+at
25 = 0+ ax10
a = 2.5 m/c2
( b )By newton's law;
F= m*a
F=100X 2.5
F =2500N
( C )
u= 25m/s
V = 0
S = 40m
by equation of motion ;
v² = u²+2as
0=25²+80a
a=-7.8125 m/s²
by newton's law
F= m*a
F= 1000X 7.8125
F = 7812. 5N
A higher level motion control operation than velocity control is the control of acceleration and deceleration. Given that torque is the result of inertia and rate of altered speed, the system's forces will be affected by the rate of acceleration or deceleration. Any force calculation of this kind must take into account the actuator's or motor's inertia because it can significantly affect the torque needed. Control performance will also be impacted by the acceleration or deceleration profiles used. A motor needs linear acceleration in order to transition smoothly from one velocity to the next until the desired speed is reached. The rates of change, on the other hand, depend on both position and velocity when acceleration follows a non-linear, curved profile.
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Compare and contrast oxygen-16 and
oxygen-17.
Answer:
oxygen 16 has 8 protons and 8 neutrons, oxygen 17 has 8 protons and 9 neutrons
Explanation:
isotope's number is equal to the sum of its protons and neutrons
Answer:Oxygen 16 is number 16 while oxygen 17 is number 17 and oxygen 16 is also oxygen like oxygen 17.
Explanation: Common Knowledge in my brain....
a small container of water is placed on a carousel inside a microwave oven, at a radius of 12.5 cm from the center. the turntable rotates steadily, turning through one revolution each 7.45 s. what angle does the water surface make with the horizontal?
θ = 0.0090 degree is the angle does the water surface make with the horizontal
At a radius of 12.5 cm from the center, or r = 13.5 cm, a tiny container of water is positioned on a rotating carousel within a microwave oven.
Time for every rotation is 7.15 seconds.
Fc=mrω^2
Fc=mr(2 π/T^2)^2
Fc=m12.5x10^-2(2 π/7.45)^2.....(1)
Gravitational force is caused by:
Fg=mg
Fg=mx9.8........(2)
Letθ is the angle between the water's surface and the horizontal be. Equations (1) and (2) can be used to compute it as follows:
tanθ=Fc/Fg
tanθ=m12.5x10^-2(2 π/7.45)^2/mx9.8
tanθ=0.0090
θ=0.0090 degree
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Answer: The angle between the water's surface and the horizontal is = 0.0090 degrees.
Explanation: The angle between the water's surface and the horizontal is = 0.0090 degrees.
A little container of water is placed on a revolving carousel within a microwave oven at a radius of 12.5 cm from the center, or r = 13.5 cm.
7.15 seconds pass throughout each revolution.
Fc=mrω^2
Fc=mr(2 π/T^2)^2
Fc=m12.5x10^-2(2 π/7.45)^2....(1) (1)
There is a gravitational force because of:
Fg=mg
Fg=mx9.8........(2)
Take as an example the angle formed by the water's surface and the horizontal. It can be calculated using Equations (1) and (2) as follows:
tanθ=Fc/Fg
tan = (m12.5x10-2(2 /7.45)/mx9.8)
tanθ=0.0090
0.09 degrees.
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True or false? The period of an AC supply is equal to the time between an adjacent peak and trough on an oscilloscope trace.
Answer:
false
Explanation:
the time period is for a whole cycle of the wave, so peak-to-peak on an oscilloscope trace.
What is the equation for calculating the electrical force, Fe1, between two charges?
The equation for calculating the electrical force between two charges is: F = Kq₁q₂ / d²
How to determine the equationConsidering the options given in the question, we can obtain the equation for calculating electrical force as shown.
Coulomb's law states as follow:
F = Kq₁q₂ / d²
Where
F is the electrical force of attraction / repulsion K is the electrical constant q₁ and q₂ are two point charges d is the distance apartWith the above equation, we can easily determine the force between two charges.
For example find the force between two charges of charge 1 C and 2 C which are 1.5 m apart.
We can obtain the force as follow:
Charge 1 (q₁) = 1 CCharge 2 (q₂) = 2 CElectric constant (K) = 9×10⁹ Nm²/C²Distance apart (r) = 1.5 mForce (F) =?F = Kq₁q₂ / d²
F = (9×10⁹ × 1 × 2) / (1.5)²
F = 18×10⁹ / 2.25
F = 8×10⁹ N
Thus, we can see clearly that the equation F = Kq₁q₂ / d² can be use to calculate the force between t two charges.
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Two objects with the same mass have the same force applied to them. What can be said of their acceleration?
A. Their acceleration will be the same.
B. Their acceleration will be different.
C. Their acceleration will depend on their net force, which is not provided.
D. Their acceleration will depend on their weight, which is not provided.
A force of 30 N to the right is applied to an object. An opposite force of 20 N to the left is applied to the same object. What is the net force applied to the object?
A. 10 N to the left
B. 50 N to the right
C. 50 N to the left
D. 10 N to the right
Answer:
Explanation:
A. Their acceleration will be the same. F=ma, a = F/m. If F and m are the same, acceleration will be the same.
B. Their acceleration will be different.
C. Their acceleration will depend on their net force, which is not provided.
D. Their acceleration will depend on their weight, which is not provided.
======
A force of 30 N to the right is applied to an object. An opposite force of 20 N to the left is applied to the same object. What is the net force applied to the object?
A. 10 N to the left
B. 50 N to the right
C. 50 N to the left
D. 10 N to the right
Add the two vectors: 30R = +30, 20L = -20 Sum = +10 or 10R
The force acting on two bodies will be the same if they have same mass and same acceleration. But the acceleration is dependant on the net force of the body and thus option C is correct. The net force of the body is 10 N to the right.
What is force?Force is an external agent or factor which change an object from its state of rest or motion. The force to be applied depends on the mass and acceleration of the body by the equation F = ma.
Acceleration of a moving body is dependant on the direction and thus the direction of force and net force. Thus the two objects having the same mass and same force f applied to them, the acceleration may not be the same. Thus option C is correct.
The two force acting on a body in opposite direction will cancel each other in magnitude. Thus 20N of force to the right will be cancel by 20 N to the left. Remaining 10N will be there to the right direction. Hence, option D is correct.
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While in a park, you walk west for 52 m, then you walk 31.1° north of west for 40 m, and finally you walk due north for 25 m. Find the components of your final displacement (in m), from your initial to final point, along the north and west directions.
The components of the final displacement (in m), from the initial to final point, along the north and west directions is given as:
88m west and 50m north
What is displacement?The displacement of an object is a vector whose length is the shortest distance from the initial to the final position of a point P undergoing motion.
we will find the components of each vector in x and y:
For Vector 1:
Fx = 52m
Fy = 0m
for Vector 2:
Fx = 40m*cos31.1
Fy = 40m * cos 31.1
For Vector 3:
Fx = 0m
Fy = 25m
we will then find the components of the final displacement acting in x and y:
For west direction:
Rx = 52m + 40m*cos31.1 + 0
Rx = 90m
For north direction:
Ry = 0 + 40m*sin31.1 + 25m
Ry = 12m.
In conclusion, displacement is a vector quantity that refers to how far out of place an object is. Displacement is known to be the object's overall change in position.
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