Given,
The initial length of the spring, l=9.7 m
The length of the spring after stretching, L=9.8 m
The mass, m=0.4 kg
The magnitude of the restoring force of the spring due to the stretching from the mass will be equal to the force applied by the mass, which is nothing but the weight of the mass.
Thus,
[tex]\begin{gathered} mg=k\Delta x \\ =k(L-l) \end{gathered}[/tex]Where g is the acceleration due to gravity, k is the spring constant, and Δx is the stretch in the length of the spring.
On substituting the known values,
[tex]\begin{gathered} k=\frac{mg}{(L-l)_{}} \\ =\frac{0.4\times9.8}{9.8-9.7} \\ =\frac{3.92}{0.1} \\ =39.2\text{ N/m} \end{gathered}[/tex]Thus the spring constant is 39.2 m
A 60.0 kg skier with an initial speed of 14 m/s coasts up a 2.50 m high rise
Find her final speed right at the top, in meters per second, given that the coefficient of friction between her skis and the snow is 0.38?
The final speed (in meters per second), given that the coefficient of friction between her skis and the snow is 0.38 is 14.65 m/s
How do I determine the final velocity?First, we shall obtain the force. This can be obatined as follow:
Mass (m) = 60 KgAcceleration due to gravity (g) = 9.8 m/s²Normal reaction (N) = mg = 60 × 9.8 = 588 NCoefficient of kinetic friction (μK) = 0.38Force (F) = ?F = μKN
F = 0.38 × 588
F = 223.44 N
Next, we shall obtain the acceleration of the skier. This can be obtained as follow:
Mass (m) = 60Force (F) = 223.44 NAcceleration (a) = ?a = F / m
a = 223.44 / 61
a = 3.724 m/s²
Finally, we shall determine the final velocity. This can be obtained as follow:
Initial speed (u) = 14 m/sDistance (s) = 2.5 mDeceleration (a) = 3.724 m/s²Final speed (v) =?v² = u² + 2as
v² = 14² + (2 × 3.724 × 50)
v² = 196 + 18.62
v² = 214.62
Take the square root of both sides
v = √214.62
v = 14.65 m/s
Thus, the the final speed is 14.65 m/s
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The final speed right at the top will be 14.65 m/s and the coefficient of friction between her skis and the snow is 0.38.
What is velocity?The ratio between displacement to time is referred to as the velocity of the object. It is a vector quantity with SI unit meter per second (m/s).
According to the question, the given information is :
Skier's mass, m = 60 kg
The acceleration due to gravity, g = 9.8 m/s²
Initial Speed, u = 14 m/s
Distance, s = 2.5 m
Deceleration is given as, a = 3.724 m/s².
Normal reaction force (N) will be equal to mg.
N = 60 × 9.8
N = 588 N
The coefficient of kinetic friction is given as, μ = 0.38
By using the formula,
F = μKN
F = 0.38 × 588
F = 223.44 N
Now, let's calculate the acceleration of the skier :
f = ma
a = f/m
a = 223.44/60
a = 3.724 m/s².
Now, calculate the velocity,
v² = u² + 2as
v² = 14² + 2 (3.724) (50)
v² = 196 + 18.62
v² = 214.62
v = 14.65 m/s.
Hence, the final speed right at the top will be 14.65 m/s.
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Moments after making the dreaded decision to jump out the door of the airplane, Darin's 75.5-kg body experiences +128 N of air resistance upward. Determine Darin's acceleration (in m/s^2) at this instant in time.Hint: Your answer will be negative since he is falling (i.e., his acceleration is still in the down direction). Answer: ________ m/s^2
Given:
The mass of the Darin is m = 75.5 kg
The air resistance is
[tex]F_a=128\text{ N}[/tex]Required: Darin's acceleration.
Explanation:
According to Newton's second law, the downward force will be
[tex]F_g=\text{ mg}[/tex]Here, g = -9.8 m/s^2 is the acceleration due to gravity.
On substituting the values, the downward force will be
[tex]\begin{gathered} F_g=75.5\times(-9.8) \\ =\text{ -739.9 N} \end{gathered}[/tex]The net force will be
[tex]\begin{gathered} F_{net}=\text{ F}_g+F_a \\ =-739.9+128 \\ =-611.9\text{ N} \end{gathered}[/tex]Final Answer: Darin's acceleration is -611.9 N
Choose all the answers that apply.Asteroids:only orbit planetsonly orbit the sunare made of frozen gas and icetake millions of years to orbit the sun sometimes come very close to Earth
ANSWER:
5th option: sometimes come very close to Earth
STEP-BY-STEP EXPLANATION:
Asteroids are small rocky objects that orbit the Sun. Although asteroids orbit the Sun like planets, they are much smaller.
Therefore, of the options the only totally true option is "sometimes come very close to Earth"
So the correct answer is 5th option: sometimes come very close to Earth
If you see an object following a curve path, you can safely assume:There is a net force being applied The net force is zero
If an object is following a curve, it means that it is changing direction. This change in direction will cause a change in velocity. Change in velocity causes acceleration. Since the velocity keeps changing, the acceleration is not zero. This also means that the net force is not zero. Therefore, you can safely assume:
There is a net force being applied
Identify the following examples of forces as either a contact force or a non-contact force:
Given:
Different kinds of forces
To find:
Identify the contact forces and non-contact forces
Explanation:
A force that acts between two surfaces in contact is a contact force, while the force that acts between the two surfaces, not in contact, is a non-contact force.
The contact forces here are:
Sitting on a chair (friction)
Skateboard slows down on a rough surface (friction)
Slamming the door (friction)
Non-contact forces:
Magnet attracting paper clips (magnetic force)
Two like charges repel each other (electrostatic force)
When A peach falls from a tree (gravitational force)
WILL MARK AS BRAINLIST!⚠️
Find the direction of this vector -22.2m, 12.6m
Answer:
Angle:
α = - 62°
Explanation:
Given:
Nₓ = 12.6 m
Ny = - 22.2 m
_________
α - ?
The direction of vector:
tg α = Ny / Nₓ
tg α = ( - 22.2 ) / 12.0 ≈ - 1.85
Angle:
α = arctg ( - 1.85) ≈ - 62°
The direction of the vector is [tex]\alpha=-62^o[/tex]. Given Components: Nₓ = 12.6 m and Ny = -22.2 m. The negative sign indicates that the angle is measured clockwise from the positive x-axis.
Finding the Tangent of Angle α:
- The tangent of an angle α can be calculated using the formula: tan(α) = opposite/adjacent. In this case, the opposite side is Ny, and the adjacent side is Nₓ. So, you have:
tan(α) = Ny / Nₓ
tan(α) = (-22.2) / 12.6 ≈ -1.85
Finding the Angle α:
- To find the angle α, you need to take the arctangent (inverse tangent) of the value you calculated above. This will give you the angle whose tangent is approximately -1.85:
α = arctan(-1.85)
α ≈ -62°
So, based on the given vector components Nₓ and Ny, the angle α is approximately -62 degrees.
The negative sign indicates that the angle is measured clockwise from the positive x-axis.
The angle obtained is in degrees. If you need the angle in radians, you could convert it using the relationship: radians = degrees × (π / 180).
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What is the shortest distance in which you can stop, after the brakes are applied, without the groceries sliding off the seat? The static and kinetic coefficients of friction are, respectively, 0.65 and 0.45. Assume that the surface of the seat is horizontal.
The shortest distance in which you can stop, after the breaks are applied is 80.38 m.
What is the shortest distance you can stop?The shortest distance in which you can stop is calculated by applying the principle of conservation of energy and work energy principle.
K.E = ¹/₂mv²
where;
K.E is your kinetic energy
m is your mass
v is your speed
The work done by force of friction before you stop is calculated as follows;
W = Ffx
where;
Ff is the frictional forcex is the shortest distance you can stopW = (μmg)x
where;
μ is coefficient of kinetic frictionW = K.E
(μmg)x = ¹/₂mv²
(μg)x = ¹/₂v²
x = (v²) / (2μg)
x = (32²) / (2 x 0.65 x 9.8)
x = 80.38 m
Thus, the shortest distance in which you can stop, after the breaks are applied is determined by applying the principle of conservation of energy.
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The complete question is below:
Your are driving at 32 m/s, what is the shortest distance in which you can stop, after the brakes are applied, without the groceries sliding off the seat? The static and kinetic coefficients of friction are, respectively, 0.65 and 0.45. Assume that the surface of the seat is horizontal.
A 22-pound force that makes an angle of 12° with an inclined plane is pulling a box up the plane. The inclined plane makes a 25° angle with the horizontal. What is the magnitude of the effective force pulling the box up the plane?
We will ave that the effective force is:
[tex]\begin{gathered} F=(22Lb)cos(12)\Rightarrow F=21.51924722...Lb \\ \\ \Rightarrow F\approx21.52Lb \end{gathered}[/tex]So, the effective force is 21.52 Pounds.
What is the mass of 12 m3 of methylated spirit whose relative density is 0.8 ? ( Hint the density of water = 1000 kgm-3 ) A. 9600 kg B.9400 kg C. 8600 kg
ANSWER
A. 9600 kg
EXPLANATION
Given:
• The volume of the substance, V = 12m³
,• The relative density of the substance, 0.8
,• The density of water, 1000 kg/m³
Unknown:
• The mass of the substance, m
The relative density of a substance is defined as,
[tex]\rho_{relative}=\frac{\rho_{substance}}{\rho_{water}}[/tex]And the density of a substance is,
[tex]\rho=\frac{m}{V}[/tex]Let's solve the first formula for the density of the substance,
[tex]\rho_{substance}=\rho_{relative}\cdot\rho_{water}=0.8\cdot1000\operatorname{kg}/m^3=800\operatorname{kg}/m^3[/tex]Then, solve the second formula for m,
[tex]m=\rho\cdot V=800\operatorname{kg}/m^3\cdot12m^3=9600\operatorname{kg}[/tex]Hence, the mass of this substance is 9600 kg
Imagine that someone is looking out of the top floor window of a skyscraper with a brick in his hand at the same instant someone else is looking out if the window on the floor below also holding a brick if both bricks were dropped at the same instant would the distance between them increase decrease or remain the same over time why
The distance between them remain the same over time both of them are accelerating - because of gravity
What is acceleration ?
acceleration: the rate at which the speed and direction of a moving object vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting. Both effects contribute to the acceleration for all other motions.
Both of them are accelerating - because of gravity - and the one that you dropped first has been accelerating for longer - and is therefore going faster than they one that you dropped later.
Until the two objects both reach their terminal velocities - assuming the objects are identical - their speeds will eventually be the same - and from that point onwards - the distance between them won’t change
The distance between them remain the same over time both of them are accelerating - because of gravity
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A 1 kg apple and a 2 kg grapefruit are 2 m apart. What is the force of gravity between each fruit?
According to Newton's law of gravitation, any particle of matter in the universe attracts any other with a force varying directly as the product of their masses and inversely as the square of the distance between them. It is expressed as
F = Gm1m2/r^2
where
G = gravitational constant and its value is G = 6.673 x 10^-11 Nm^2/kg^2
m1 and m2 are the masses of the bodies
r is the distance between the bodies
From the information given,
m1 = 1
m2 = 2
r = 2
By substituting these values into the formula,
F = (6.7 x 10^-11 x 1 x 2)/2^2
F = 33.5 x 10^- 12
F = 3.35 x 10^-11
The second option is correct
Which of the following scientists discovered that atoms contain electrons?a. Daltonb. RutherfordC. Thomsond. Bohr
Until 1897, atom was thought as the fundemental particle. But in 1897 J.J Thompson discovered that the atoms contains electrons. He discovered during his experiment with cathod ray tube.
Thus the correct answer is option C.
Every 5 seconds, the crest of a wave in the ocean travels 25 meters. What is the speed of the wave?
Given
Every 5 seconds
One wave travel 25m
Speed of waves
Explanation
[tex]\begin{gathered} v=\frac{25m}{5s} \\ v=5\text{ m/s} \end{gathered}[/tex]
The answer would be 5 m/s
Can you tell me the types of thermal processes and there meanings
Isothermal process: Temperature remains constant
Adiabatic process: No heat is exchanged to or from the system.
Isochoric process : Change in volume is zero.
ISobaric process : Pressure remains constant .
A child and sled with a combined mass of 25.2 kg slide down a frictionless hill, starting at the top. The sled starts from rest and acquires a speed of 6 m/s by the time it reaches the bottom of the hill. What is the height (in m) of the hill?Answer: _________ m (round to the nearest hundredth)
Given:
The mass of the child and the sled is,
[tex]m=25.2\text{ kg}[/tex]The child acquires a speed at the bottom of the hill is,
[tex]v=6\text{ m/s}[/tex]To find:
The height of the hill
Explanation:
The potential energy at the top of the hill will be converted to the potential energy at the bottom of the hill. So for the hill of height 'h', we can write, the potential energy as
[tex]PE=mgh[/tex]The kinetic energy is
[tex]KE=\frac{1}{2}mv^2[/tex]So,
[tex]\begin{gathered} mgh=\frac{1}{2}mv^2 \\ h=\frac{v^2}{2g} \\ h=\frac{6^2}{2\times9.8} \\ h=1.84\text{ m} \end{gathered}[/tex]Hence, the height of the hill is 1.84 m.
An 1,810 W toaster, a 1,340 W electric frying pan, and an 85 W lamp are plugged into the same outlet in a 15 A, 120 V circuit. (The three devices are in parallel when plugged into the same socket.)(a) What current (in A) is drawn by each device?Itoaster= AIpan= AIlamp= A
ANSWER
• I(toaster) = 15.08 A
,• I(pan) = 11.17 A
,• I(lamp) = 0.71 A
EXPLANATION
Given:
• The toaster's power, P(toaster) = 1810 W
,• The frying pan's power, P(pan) = 1340 W
,• The lamp's power, P(lamp) = 85 W
,• The total current supported by the circuit, I = 15 A
,• The voltage of the circuit, V = 120 V
Find:
• The current across each device
Power is the product of current and voltage,
[tex]P=I\cdot V[/tex]We know that all three devices are connected in parallel, which means that they all have the same voltage, 120 V.
Solving the equation above for I,
[tex]I=\frac{P}{V}[/tex]So, for each device,
[tex]I_{toaster}=\frac{P_{toaster}}{V}=\frac{1810W}{120V}\approx15.08A[/tex][tex]I_{pan}=\frac{P_{pan}}{V}=\frac{1340W}{120V}\approx11.17A[/tex][tex]I_{lamp}=\frac{P_{lamp}}{V}=\frac{85W}{120V}\approx0.71A[/tex]Hence, the current drawn by each device is:
• I(toaster) = 15.08 A
,• I(pan) = 11.17 A
,• I(lamp) = 0.71 A
Please read the photo, Skill practice; how can you classify different types of energy?
There are 3 types of energy:
Kinetic energy(KE): energy of moving objects
Potential energy(PE): energy that an object has stored, position energy
Mechanical energy: The sum of both. PE+KE
Given v = 145 sin (200πt + 3π/2), what is the period?Question 12 options:10 msec5 sec.03 sec.005 sec
For a sine or cosine function of the form:
[tex]A\sin (B(x+C))+D[/tex]the perfiod is given by:
[tex]\frac{2\pi}{B}[/tex]In this case we have that:
[tex]B=200\pi[/tex]Then we have:
[tex]\frac{2\pi}{200\pi}=\frac{1}{100}=0.01=10\times10^{-3}[/tex]Therefore, the period is 10 ms
Examine the heating curve for water below. Answer each question andcomplete the table to review your understanding of heating curves
Explanation:
When the temperature is increasing, the kinetic energy change, and when the graph is horizontal (the water is changing phases), the potential energy changes.
So at A, C, and E, there is a change in kinetic energy and at B and D there is a change in potential energy.
Then, we use a specific heat capacity of 4.2 J/g°C when the water is at A, C, and E. We use latent heat of 334 J/g for melting and latent heat of 2260 J/g for evaporation.
Answer:
Therefore, the complete table is
Round the answer for each problem to the correct number of significant figures.
a. (7.31 × 104) + (3.23 × 103)
b. (8.54 × 10–3) – (3.41 × 10–4)
c. 4.35 dm × 2.34 dm × 7.35 dm
d. 4.78 cm + 3.218 cm + 5.82 cm
e. 38,736 km ÷ 4784 km
After solving each problem to correct the number of significant figures :
(a) 76330
(b) 8199 × 10⁻³
(c) 74.81 dm.
(d) 13.8 cm
(e) 8.09 km
What is an Equation?Equations are mathematical expressions that have two algebraic expressions on either side of an equals (=) sign. The expressions on the left and right are shown to be equal to one another, demonstrating this relationship. L.H.S. = R.H.S. (left hand side = right hand side) is a fundamental mathematical formula.
According to the question,
(a) (7.31 × 10⁴) + (3.23 × 10³)
(73100) + (3230) = 76330
(b) (8.54 × 10⁻³) – (3.41 × 10⁻⁴)
= 8199 × 10⁻³
(c) 4.35 dm × 2.34 dm × 7.35 dm
= 74.81 dm.
(d) 4.78 cm+3.218 cm+5.82 cm
= 13.8 cm
(e) 38,736 km ÷ 4784 km
= 8.09 km
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The current in the circuit shown is 5.0 A, and the resistor is 2.0 Ω. What is the potential across the battery? A.8.0 VB.2.5 VC.10 VD.3.0 V
Given:
The current is,
[tex]i=5.0\text{ A}[/tex]The resistance is,
[tex]R=2.0\text{ ohm}[/tex]To find:
The potential across the battery
Explanation:
Using Ohm's law, we can write the potential across the battery is,
[tex]\begin{gathered} V=iR \\ =5.0\times2.0 \\ =10\text{ V} \end{gathered}[/tex]Hence, the potential across the battery is 10 V.
A wave traveling on a Slinky® that is stretched to 4 m takes 4.97 s to travel the length of the Slinky and back again.(a) What is the speed (in m/s) of the wave? m/s
ANSWER
1.61 m/s
EXPLANATION
Given:
• The distance the Slinky is stretched, d = 4 m
,• The time it takes for the wave to travel the length mentioned before and back, t = 4.97 s
Find:
• The speed of the wave, v
We know that the wave takes 4.97 seconds to travel the 4 meters the Slinky was stretched and back, so it travels a total of 8 meters in that time. This means that the speed of the wave is,
[tex]v=\frac{2d}{t}=\frac{8m}{4.97s}\approx1.61m/s[/tex]Hence, the speed of the wave is 1.61 m/s.
Calculate the potential energy of a roller coaster when the coaster is at the top of a 107.1 meter high hill and has a mass of 2,078.1 kg when fully loaded with passengers.
Given:
The mass when fully loaded with passengers is m =2078.1 kg
The height is h = 107.1 m
To find the potential energy of the roller coaster.
Explanation:
The potential energy of the roller coaster is given by the formula
[tex]P\mathrm{}E\text{. =mgh}[/tex]Here, g= 9.8 m/s^2 is the acceleration due to gravity.
Substituting the values, the potential energy of the roller coaster will be
[tex]\begin{gathered} P\mathrm{}E\text{. = 2078.1}\times9.8\times107.1 \\ =2181132.198\text{ N} \end{gathered}[/tex]Final Answer: The potential energy of the roller coaster is 2181132.198 N
Three non-parallel forces which can be represented both in magnitude and direction by the three sides of a triangle, taken in order, can: A. make a body oscillate B. make a body rotate C. keep a body in equilibrium D. move a body in a straight line E. always produce vertical motion of body
Answer:
If the triangle representing the 3 non-colinear forces is closed
then then (C) the body is in equilibrium:
Adding vectors A + B + C = 0 means that the resultant of adding the three vectors A, B, and C is zero
Two sounds of 610Hz and 620Hz are played together. The frequency you hear will be ___. The beat frequency is ___
Explanation
The beat frequency is equal to the complete value of the alteration in the frequency of the two waves,it can be calculated by using the expression
[tex]f_{beat}=\lvert{{f_1}-f_2}\rvert[/tex]so
Step 1
a)let
[tex]\begin{gathered} f_1=610\text{ Hz} \\ f_2=620\text{ Hz} \end{gathered}[/tex]b) replace and calculate
[tex]\begin{gathered} f_{beat}=\lvert{{f_1}-f_2}\rvert \\ f_{beat}=\lvert610\text{ Hz-620Hz}\rvert \\ f_{beat}=10\text{ Hz} \end{gathered}[/tex]so
the beat frequency is 10 HZ
Step 2
the frequency yuo will detect is the difference of the frequency, so , teh frequency beat, so
the frequency you hear will be 10 Hz
I hope this helps you
A construction worker pushes a wheelbarrow 5.0 m with a horizontal force of 250.0 N. How much work is done by the worker on the wheelbarrow
Given data
*A construction worker pushes a wheelbarrow at a distance is d = 5.0 m
*The given horizontal force is F = 250.0 N
The formula for the work is done by the worker on the wheelbarrow is given as
[tex]W=F\times d[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} W=(250.0)(5.0) \\ =1250\text{ J} \end{gathered}[/tex]Hence, the work done by the worker on the wheelbarrow is W = 1250 J
The potential energy of two atoms in a diatomic molecule is approximated by U(r)=a/r12−b/r6, where r is the spacing between atoms and a and b are positive constants.
Find the force F(r) on one atom as a function of r .
Express your answer in terms of the variables a , b , and r .
The force (r) on one atom as a function of r is a/r¹³ - b/r⁷.
What is the electric force between charged molecules?
The electric force between charged molecules is determined by applying Coulomb's law, which states that the electric force between tow charged molecules is directly proportional to the product of their charges and inversely proportional to the square of their distance.
F = kq²/r²
where;
q is the magnitude of the chargesr is the distance between the chargesThe electric potential energy of the atoms is given as;
U = Fr
From the given parameters;
Fr = a/r¹² − b/r⁶
F = 1/r( a/r¹² − b/r⁶)
F = a/r¹³ - b/r⁷
Thus, the force on one atom as a function of r is determined by applying Coulomb's law of electrostatic force. The force is also expressed in terms of the variables a , b , and r .
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In which direction does the tension force on the pirate point when a gust of wind rises up?
Answer: For downwind sailing, with the sail oriented perpendicular to the wind direction, the pressure increase on the upwind side is greater than the pressure decrease.
Explanation: this is all i know
True/False: The only difference between how electricity is produced at a coal plant and at a nuclear reactor is the type of fuel used to heat the water to steam. Select one:TrueFalse
To determine whether the given statement is true/false.
Explanation:
In nuclear reactors, after nuclear fission, energy is generated in the form of heat. This heat is used convert water steam.
In coal plant, burning coal produces steam.
Thus, the statement is true.
How much time would it take a car to go from a speed of 10m/s to 30m/s if it acceleratesat a rate of 4.0m/s/s?
Given,
The initial velocity of the car, u=10 m/s
The final velocity of the car, v=30 m/s
The acceleration of the car, a= 4.0 m/s²
From one of the equations of the motion, we have
[tex]v=u+at[/tex]Where t is the time duration.
On rearranging the above equation,
[tex]t=\frac{v-u}{a}[/tex]On substituting the known values,
[tex]t=\frac{30-10}{4.0}=5\text{ s}[/tex]Therefore the time that the car takes to accelerate is 5 s