A strong weightless rope has a mass, m, hanging from the middle of it. The tension force on each rope is 25 N, and the rope droops at an angle of 20.0 degrees. How much mass is hanging from the rope?​

Answers

Answer 1

By using Lami's theorem, Mass m = 1.75 kg approximately

Given that a strong weightless rope has a mass, m, hanging from the middle of it. If the tension force on each rope is 25 N, and the rope droops at an angle of 20.0 degrees to the horizontal.

By using Lami's theorem, we can get how much mass is hanging from the rope.

Let the angle between the rope = α = 180 - 40

α = 140 degrees

The angle between one of the rope and mass = β = 20 + 90

β = 110 degrees

The angle between the mass and the other rope = γ = 360 - (140 + 110)

γ = 360 - 250

γ = 110 degrees

W/ sinα = T/ sinβ = T/sinγ

W/ sinα = T/ sinβ

Substitute all the necessary parameters

W/sin140 = 25/sin 110

W / 0.643 = 25 / 0.939

W = 17.1 N

Weight W = mg

17.1 = 9.8m

mass m = 17.1/9.8

Mass m = 1.7455 kg

Mass m = 1.75 kg approximately

Therefore, 1.75 kg mass is hanging from the rope.

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Related Questions

How does production and possibilities curve show efficiency grouth and opportunity cost

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Answer:

The Production Possibilities Curve (PPC) is a model that captures scarcity and the opportunity costs of choices when faced with the possibility of producing two goods or services. Points on the interior of the PPC are inefficient, points on the PPC are efficient, and points beyond the PPC are unattainable.

Explanation:

what is the unit of measurement for expressing the intensity of sound

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Decibel - the decibel is a relative unit of measurement equal to one 10th of a bel

Send right answers plzzzz plz

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Answer:

I think A

Explanation:

A pail of water of mass 2000 gm is rotated in a vertical circle of radius 1.00 m. What is the pail’s minimum speed at the top of the circle if no water is to spill out and the tension exerted by the string is 25 N?

Answers

The pail’s minimum speed at the top of the vertical circle is 4.72 m/s.

The given parameters:

Mass of the water, m = 2000 g = 2 kgRadius of the circle, r = 1 mTension on the string, T = 25 N

The net force on the pail of water at the top of the vertical circle is calculated as follows;

[tex]T = ma - mg\\\\T = \frac{mv^2}{r} - mg\\\\T + mg = \frac{mv^2}{r} \\\\mv^2 = r(T + mg)\\\\v^2 = \frac{r(T + mg)}{m} \\\\v= \sqrt{\frac{r(T + mg)}{m}} \\\\v = \sqrt{\frac{1 (25\ + \ 2 \times 9.8)}{2}} \\\\v = 4.72 \ m/s[/tex]

Thus, the pail’s minimum speed at the top of the vertical circle is 4.72 m/s.

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The pail’s minimum speed at the top of the circle if no water is to spill out is; v = 4.722 m/s

We are given;

Mass of the pail of water; m = 2000 g = 2kg

Radius of the circle; r = 1 m

Tension exerted by string; T = 25 N

To calculate the net force on the pail of water at the top of the vertical circle, let us take equilibrium of forces to give;

W - T = ma

Where;

W is weight = mg

T is tension on the string

Now, in circular motion, we know that;

Acceleration is; a = v²/r

Thus;

mg - T = m(v²/r)

Making v the subject of the formula gives us;

v = √[(r(T + mg)/m)

Plugging in the relevant values gives;

v = √[(1(25 + (2 * 9.8))/2)

v = 4.722 m/s

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what two properties change when light is refracted

Answers

Answer:

Refraction is merely one of several possible boundary behaviors by which a light wave could behave when it encounters a new medium or an obstacle in its path. The transmission of light across a boundary between two media is accompanied by a change in both the speed and wavelength of the wave.

Explanation:


A 100kg diver jumps off a 40m cliff. Ignoring the affects of air resistance, determine the
time it would take for the diver to reach the water.

Answers

Answer:2.86seconds

Explanation:

H=gt^2/2

t=2h/g

If a nonzero net force is acting on an object, then the object is definitely _____.

a. at rest
b. being accelerated
c. moving with a constant velocity
d. losing mass.

Answers

An object is definitely being accelerated when a nonzero net force is acting on it: Option B.

A net force refer to the vector sum of all the forces that are acting on an object or physical body. Thus, a net force is a single force that substitutes the effect of all the forces acting on an object or physical body.

According to Newton's Second Law of Motion, the acceleration of an object is directly proportional to the net force acting on the object and inversely proportional to its mass.

This ultimately implies that, an object is definitely being accelerated when a nonzero net force is acting on it.

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how many types Of Ornital does the atomic orbital have ?​

Answers

Answer:

There are four types of orbitals that you should be familiar with s, p, d and f (sharp, principle, diffuse and fundamental). Within each shell of an atom there are some combinations of orbitals

3) A 14 kg object is sitting at the top of a hill that is 100 m high. What is the potential energy of the
object?

Answers

Answer:

13,720 joules

Explanation:

Epotential = mgh

mass x gravity x height

Ep= 14 x 9.8 x 100

Ep=13,720 joules

A 30.4-newton force is used to slide a 40.0-newton crate a distance of 6.00 meters at constant speed along an incline to a vertical height of 3.00 meters. Calculate the work done by a friction force on the crate as it slides 6.00 m along the incline.

Answers

Hi there!

Since the crate is being slid at a constant speed, the forces sum to 0 N. In this instance, the following forces occur in the axis of interest:

Wsinθ = downward acceleration along incline due to gravity (N)

Fκ = kinetic friction force along incline (N)

A = applied force (N)

The acceleration due to gravity and friction force act in the same direction, so:

Wsinθ + Fκ = A

Solve for sinθ using right triangle trigonometry:

sinθ = O/H = 3/6 = 0.5

Rearrange the equation for the force of kinetic friction and solve:

Fκ = A - 0.5W

Fκ = 30.4 - 20 = 10.4 N

Now, recall that:

Work = Force × displacement (W = F × d)

Since the box's displacement is in the same axis as the force but OPPOSITE direction, we must use:

W = Fdcosθ

Angle between displacement and friction force is 180°.

cos(180) = -1

Work done by friction = -Fd = -10.4(6) = -62.4 J

help omg
An object, moving with a constant velocity, travels 400 m in 25 s. What is its velocity?

Answers

52.4934 meters per second
It would be 52.4934

When traveling north from the United States into Canada, you'll see the North Star (Polaris) getting _________. lower in the sky higher in the sky dimmer brighter

Answers

When traveling north from the United States into Canada, you'll see the

North Star (Polaris) getting higher in the sky .

This is because the polaris which is also known as North Star is located

very close to the north celestial pole. When an objects moves towards the

north , the polaris gets higher due to its upward northern location.

This is the major reason why when traveling north from the United States

into Canada, you'll see the North Star (Polaris) getting higher.

Read more about Polaris on https://brainly.com/question/1130377

Answer:

Higher

Explanation:

As you go further north, the Star Polaris rises in the sky. This is due to it being circumpolar meaning that the star doesn't move in the night sky (Often)

A rocket consists of a shuttle and a fuel tank. The rocket flies through the air with a momentum of 180000kgm/s at a velocity of 120m/s. If the fuel tank has a mass of 500kg, what is the mass of the shuttle?

Answers

Answer:

Answer is 1000kg

Hope it help

write the resistivity of gold, iron ,Mercury, silver,copper? which is bad conductor?​

Answers

Answer:

Mercury is a bad conductor of heat but a fair conductor of electricity

By the way PURE SILVER is the best conductor of electricity

Please Mark as brainliest

find the quotient 3^15 × 3^3

Answers

Answer:

3^15 / 3^3 = 3^12 * 3^3 / 3^3 = 3^12

The Law of Exponents applies here

3^15 x 3^3 is a product, not a quotient

3^15 x 3^3 = 3^18

Anyone please.??????​

Answers

Answer:

468.42572 Wavelength In Metres

Explanation:

Answer:

[tex]\huge\boxed{\sf Wavelength= 470\ m}[/tex]

Explanation:

Given Data:

Speed of light = c = 3 × 10⁸ m/s (Constant)

Frequency = f = 640 kHz = 6.4 × 10² × 10³ Hz = 6.4 × 10⁵ Hz

Required:

Wavelength = λ = ?

Formula:

λ = c / f

Solution:

λ = 3 × 10⁸ / 6.4 × 10⁵

λ = 0.47 × 10³

λ = 4.7 × 10² m

λ = 470 m

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

~AH1807

A balloon is rubbed against a sweater. Which of the following describes the result of this interaction?(1 point)
The outer shell electrons move from the balloon to the sweater.

The fibers of the sweater lose electrons.

The balloon becomes positively charged.

The free electrons in the balloon decreases.

Answers

Answer:

The fibers of the sweater lose electrons.

4) What is the kinetic energy of a 5 kg object moving ot a velocity of 25 m/s?
Help me please I’m confused

Answers

Kinetic Energy (KE)
Mass(m)
Velocity(V)

KE= 1/2 (m) (V^2)
KE=(.5)(5kg)(25^2m/s)
KE= (.5)(5kg)(625m/s^2)
KE= (.5)(3125kgm/s^2)
KE=1562.5 (kgm/(s^2))

Please I need help with this ❤️ ?

Answers

Answer:

Compound 'A' C5H12 does not react with phenyl hydrazine. Oxidation of 'A' with K2Cr2o7,/H" gives B' (c5H10o). Compound 'B' reacts with phenyl hydrazine but does not give Tollen's test. The

moving east with a constant velocity of 30 m/s for 5 seconds. What is the object's
acceleration?
a. O m/s/s
C. 30 m/s/s
b. 6 m/s/s
d. 150 m/s/s

Answers

Ok, so you multiply them so it would be 30x5 so you will get 150.

on what factors does the quantity of heat of an object depend​

Answers

Answer:

The quantity of heat given to body depends on: (i) The mass of the body, (ii) The rise (or fall) in the temperature of the body, and (iii) Nature of the material of the body.

Explanation:

Hope this helps

have a great day

~Zero

a galaxy that is a featureless spherical ball of stars would be called a type

Answers

Answer:

E0

Explanation:

Yes. The "0" indicates that it is spherical

A car starts with a velocity of 16 m/s and slows at a constant rate of -2m/s2, what is its velocity after 3 s?

Answers

After 3 seconds, the car slows down to

16 m/s + (-2 m/s²) (3 s) = 16 m/s - 6 m/s = 10 m/s

An eagle flying at a constant 120 km/h and has kinetic energy of 2,800 J. What is the mass of the eagle?

Answers

Answer:

The mass of the eagle is about 5 Kg

Explanation:

1/2 M= Ke/V^2

120 km/h = 33.3333m/s

1/2 M = 2,800/33.3333^2

1/2 M = 2,800/ 1111.10888889

1/2 M = 2.52000504001

(2) 1/2 M = (2) 2.52000504h001

= M = 5.04001008002

About 5 Kilograms

Say you were at mission control on
Earth. You use radio waves to say "Hello" to an
astronaut on Mars when Mars is 84,000,000
km from Earth. The astronaut hears your "Hello"
280 seconds after you spoke the word. How do
you explain this time lag?

Answers

Answer:

because mars is far

Explanation:

so if he shouts louder than he will hear it quicker

define the unit of work​

Answers

[tex]\text{The unit of work is same as energy. Newton-meters(Nm) or Joules(J).}\\[/tex]

What is an example of bad energy efficiency but good energy conservation?

Answers

Answer:

Energy conservation relies on people cutting back on activities that consume energy—by turning off lights or driving less or using appliances less often.

Explanation:

hope this helps

batman recharges his bat taser with 2500 joules of energy in 15 minutes. how much power does it draw from the mains

Answers

The power P in watts (W) is equal to the energy E in joules (J), divided by the time period t in seconds (s):
P(W) = E(J) / t(s)

2.78 Watts

effect of looping the loop​

Answers

Answer:

What does this mean? please provide more explanation when asking for help

From one point on the ground, the
angle of elevation of the peak of a
mountain is 10.38°, and from a
point 15,860 ft closer to the
mountain, the angle of elevation is
14.67º. Both points are due south of
the mountain. Find the height of the
mountain.
10.38°
一企一
14.67°
15,860 ft

Answers

Trigonometry allows to find the result for the question about the height of the mountain is:

The height mountain  is:  y = 9674.4 ft

Trigonometry allows finding relationships between the angles of a right triangle.

         [tex]tan \theta = \frac{y}{x}[/tex]  

Where θ is the angle, y the opposite leg (height) and x the adjacent leg (horizontal distance).

In the attachment we can see a diagram of the system. They indicate that for x  distance the angle is 14.67º  

         tan 14.67 = [tex]\frac{y}{x}[/tex]  

At the other point the angle is 10.38º.

        tan 10.38 = [tex]\frac{y}{x+15860}[/tex]

We look for the horizontal distance (x) with these equations.

        x tan 14.67 = (x + 15860) tan 10.38

        x tan 14.67 / tan 10.38 = x + 15860

        x 1,429 = x + 15860

        x 0.429 = 15860

        x = [tex]\frac{15680}{0.429}[/tex]

        x = 36955.3 ft

We calculate for the height.

        y = x tan 14.67

        y = 36955.3 tan 14.67

        y = 9674.4 ft

In conclusion using trigonometry we can find the result for the height of the mountain is:

The height is y = 9674.4 ft

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