With the use of the formula, the pressure on the bottom of the pool due to the water is 29400 Pascal
Given that a swimming pool of width 9.0 m and length 12.0 m is filled with water to a depth of 3.0 m.
Volume = Length x Width x Height
Volume = 9 x 12 x 3
Volume = 324 [tex]m^{3}[/tex]
Since 1 m^3 of water has a mass of 1000 kg,
Mass = 324 x 1000
mass = 324000 kg
To calculate the pressure on the bottom of the pool due to the water, let us use the pressure formula below
P = δgh
where
P = pressure
δ = density of the water = 1000 kg/[tex]m^{3}[/tex]
g = Acceleration due to gravity = 9.8 m/[tex]s^{2}[/tex]
h = height = 3m
Substitute all the parameters into the formula
P = 1000 x 9.8 x 3
P = 29400 Pascal
Therefore, the pressure on the bottom of the pool due to the water is 29400 Pascal
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Why is saving important to the economy.......and to you?
Answer: Saving is important to the economic progress of a country because of its relation to investment. If there is to be an increase in productive wealth, some individuals must be willing to abstain from consuming their entire income.
Explanation:
Savings is important to the economy because it enables growth and development of a nation.
Importance of savings
The importance of savings to the economy in general can not be over emphasized.
The following are some importance of savings to the economy;
Growth in the economy: when people save money the economy grows.Development: The increase in the economy due to savings can help in the development of a nation.Thus, savings is important to the economy because it enables growth and development of a nation.
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Match the definition with the appropriate word.
temperature
part of internal energy that can be
transferred
heat
measure of the average kinetic energy of a
substance
thermal energy
total potential and kinetic energies of the
particles in a substance
internal energy
thermal energy that flows from one
substance to another
Answer:
Temperature: measure of the average kinetic energy of a substance
Internal energy: total potential and kinetic energies of the particles in a substance
Heat: thermal energy that flows from one substance to another
Thermal energy: part of internal energy that can be transferred
Explanation:
Proof for correct answers on edge :)
Can you see people on puppies not to do stairs exercise when it is very hot and humid what is the reason for this warning Ate it makes muscles Louis loser in Punta do you speak it can you spell ate the whole way too unhealthy levels see it needs to be cool outside for exercise to be effective date it is really uncomfortable to exercise when it is really hot
Answer:
Exercising is not only good for their physical and mental health, but also helps them to socialise with other dogs and puppies, which is crucial to their ...
Explanation:
which distance indicator can be used to measure the most distant objects?
The distance indicator can be used to measure the most distant objects among all indicators stated above is Type Ia supernovae
In the field of Astronomy, there are different kind of distance indicators that can be used to measure the distance objects.
Few among them are :
Cepheids Type Ia supernovae Parallax Main-sequence fittingCepheid variables can be measured up to 18 million light years.
The expansion rate of the universe can also be measured by trying to measure the apparent brightness of the Type Ia supernovae
Parallax means illusory state of an object when viewed from different points
Main sequence fitting makes use of a H-R diagram of the cluster to determine the distance to a stellar cluster.
The distance indicator can be used to measure the most distant objects among all indicators stated above is Type Ia supernovae
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Write a summary paragraph discussing this experiment and the results. Use the following questions and topics to help
guide the content of your paragraph.
1. According to your data, was your hypothesis for each experiment correct? (Be sure to refer to your data and graphs
when answering this question.)
2. Summarize the conclusions that you can draw from this experiment. Use the questions above to gulde your ideas.
3. Summarize any difficulties or problems you had in performing the experiment that might have affected the results.
Describe how you might change the procedure to avoid these problems.
4. Give at least one more example from real life where the principles demonstrated in this lab are evident.
Answer:
Sample answer: part 1:
What was your hypothesis?
This is what you wanted to prove or study with the experiment. Reading the question I can see that the experiment seems to study the relation between the viscosity of honey and the temperature, so the hypothesis may be something like:
"The viscosity of honey decreases as temperature increases".
According to your data, do you think your hypothesis was correct?
Here you need to see your experimental data, probably, you found that yes, as you increase the temperature the viscosity decreases.
The last thing we need to do here is to summarize difficulties and problems that you had in the experiment, and propose how you could solve them in order to have a better experiment.
Obviously, this depends on how you performed the experiment, but for example, if you saw that the temperature of the honey increased too fast, you could say:
"one problem was that the temperature of the honey increased too fast"
And one way to solve that would be submerging the honey in a water bath so the temperature increases a bit slower.
part 2:
Viscosity depends strongly on temperature, but this relation depends also on the given material.
Generally, we would see that the viscosity decays exponentially as the temperature increases.
So for the first question:
What effect did the temperature have on the viscosity of the honey?
You should have seen that, as the temperature increased, the viscosity decreased.
Now, we need to give some practical examples where knowledge of viscosity is important.
The first one is for cleaning: We know that if we increase the temperature, the viscosity decreases. Thus if we have some object with some viscous thing on it, increasing the temperature will cause it to be easier to clean.
Another example is to store/transport viscous things, for example, honey, it is actually a lot easier to pour honey in bottles if you first heat it a little, so it becomes less viscous.
So there you have two examples where knowing about viscosity (and how it relates to temperature) may be important.
Explanation:
What’s 5.1 cm in Newton’s?
What is the relationship between transit duration and orbital period?
Answer:
The length of time between each transit is the planet's "orbital period", or the length of a year on that particular planet. Not all planets have years as long as a year on the Earth! Some planets discovered by Kepler orbit around their stars so quickly that their years only last about four hours!
I hope it helps.
Answer:
lenght of year poExplanation:
hope it helpsA block of mass M is attached to a spring of negligible mass and can slide on a horizontal surface along the x-direction, as shown above. There is friction present between the block and the surface. The spring exerts no force on the block when the center of the block is located at x=0. At the instant shown above, the block is located at x=0 and moving toward the right with speed v=v0. (a) For the instant shown above, with the block located at x=0 and moving to the right, predict the direction of the net force on the block. If the net force is zero, select “The net force is zero.”
_ To the left _ The net force is zero _ To the right
Briefly justify your prediction.
Answer:
Because of the frictional force, the net force will oppose direction of the block and be directed towards the left even tho the spring exerts no force at this point
Describe the way that distance is changing in relation to tiMe
Answer:
DistaNcE chanGes iN relAtiOn tO TiMe Bc ThE fuRthEr yOu Go ThE mOrE TiMe goeS bY
Dan is working as a family resources coordinator. Which of these statements are true about him?
Dan is responsible for overseeing the administrative functions and daily operations of a childcare center. He also helps families with children
who have special needs to uphold the rights of the children. He assists daycare teachers in carrying out their everyday duties. He also helps
families make use of early intervention services.
Reset
Next
rights reserved
The true statement about Dan is that "he also helps families make use of early intervention services."
Family resource coordinators are experts whose job it is to help families to ensure that children get along in early intervention services. They always work with families and school age children.
If Dan is working as a family resources coordinator, then a true statement about him is that "he also helps families make use of early intervention services."
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Answer:
-He also helps families make use of early intervention services.
-He also helps families with children who have special needs to uphold the rights of the children
Explanation:
Got it right on plato.
A strong weightless rope has a mass, m, hanging from the middle of it. The tension force on each rope is 25 N, and the rope droops at an angle of 20.0 degrees. How much mass is hanging from the rope?
By using Lami's theorem, Mass m = 1.75 kg approximately
Given that a strong weightless rope has a mass, m, hanging from the middle of it. If the tension force on each rope is 25 N, and the rope droops at an angle of 20.0 degrees to the horizontal.
By using Lami's theorem, we can get how much mass is hanging from the rope.
Let the angle between the rope = α = 180 - 40
α = 140 degrees
The angle between one of the rope and mass = β = 20 + 90
β = 110 degrees
The angle between the mass and the other rope = γ = 360 - (140 + 110)
γ = 360 - 250
γ = 110 degrees
W/ sinα = T/ sinβ = T/sinγ
W/ sinα = T/ sinβ
Substitute all the necessary parameters
W/sin140 = 25/sin 110
W / 0.643 = 25 / 0.939
W = 17.1 N
Weight W = mg
17.1 = 9.8m
mass m = 17.1/9.8
Mass m = 1.7455 kg
Mass m = 1.75 kg approximately
Therefore, 1.75 kg mass is hanging from the rope.
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What is the density of a substance that has a volume of 30ml and a mass of 20g?
Answer:
0.67 g/mLExplanation:
The density of a substance can be found by using the formula
[tex]d = \frac{m}{v} \\ [/tex]
m is the mass
v is the volume
From the question
m = 20 g
v = 30 mL
We have
[tex]d = \frac{20}{30} = \frac{2}{3} \\ = 0.66666...[/tex]
We have the final answer as
0.67 g/mLHope this helps you
which term is equal to velocity change per second?
Answer:
Acceleration is measured in meters per second squared (m/s²) change in velocity is measured in meters per second (m/s) time taken
A dart is thrown at a target that is supported by a wooden backstop. It strikes the backstop with an initial velocity of 350 m/s [E] The dart comes to rest in 0.0050 s.
a. What is the acceleration of the dart?
b. How far does the dart penetrate into the backstop?
Answer:u=350m/sec
v=0m/sec
t=0.005sec
a=v-u/t
=0-350/0.005
= -350/0.005
= -350×1000/5
= -70×1000
= -70000 m/sec^2
Explanation: i think this will help you thankyou
HELP!!!
Which of the following statements is true about magnets?
A. The molecules of the atom are unaligned
B. The orientation of atoms does not affect a magnet
C. The north pole is stronger than the south pole
D. The molecules of the atom are all aligned
Giving brainliest to the correct answer! (If both are correct I'll give whoever answered correctly 1st brainliest!)
Answer:
Explanation:
A is not correct. That means that D is since they offer exactly the opposite meanings.
C is rubbish. One pole could not be stronger than the other. Heaven help us if touched the stronger pole.
B the very point of a magnet is that it does matter how the atoms are orientated.
Two Magnets are placed near each other on the space station orbiting earth. The south poles are facing each other which statement explains what what happen to the magnets.
A. They will be repelled because they are in each others magnetic field
B. They will be attracted because they’re magnetic fields will add together
C. They will not move because they are not in earths gravitational field.
D. They will not move because they do not have electric fields.
Explanation: A) They will be repelled because they are in each others magnetic field
Using a balance, determine the mass of the ball and basket of the ballistic pendulum. Fire the ballistic pendulum
and measure the maximum height the pendulum reaches. Use the conservation of energy (initial KE + initial GPE =
final KE + final GPE; KE = 12mv2; GPE = mgh) to calculate the initial speed of the pendulum after the ball has
collided with the pendulum basket. Next, use the conservation of momentum (total initial p = total final p; p = mv)
to determine the initial speed of the ball before it collided with the pendulum basket.
=
=
The conservation of energy and moment allows to find the results for the velocity of the pendulum and the bullet in the system are:
The velocity of the pendulum (bullet + basket) is: v₀ = 1.98 m The speed of the bullet, depending on the mass are:m (kg) v (m / s)
0.05 41.58
0.10 21.78
0.15 15.18
0.20 11.88
0.25 9.90
The conservation of mechanical energy is one of the most important principles of physics, it establishes that if there is no friction force, the energy is constant at all points. Mechanical energy is the sum of the kinetic energy plus the potential energies.
In the attachment we can see a diagram of the system, let's start by finding the speed of the pendulum when it leaves, for this we use the conservation of energy.
Starting point. In the lowest part of the movement.
Em₀ = K = ½ (m + M) v₀²
Final point. At the top of the movement.
Em_f = U = (m + M) g y
Energy is conserved because there is no friction.
Em₀ = Em_f
½ (m + M) v₀² = (m + M) g y
[tex]v_o = \sqrt{2gy}[/tex]
They indicate a table with several measurements of the masses and the period, let's use the relationship of the simple harmonic motion.
y = y₀ cos wt
The period and the angular velocity are related.
w = 2π / T
we substitute
y = y₀ cos ( [tex]2 \pi \frac{t}{T}[/tex] )
Let's analyze how long it takes to reach the point of maximum height, the period is the time of a complete oscillation, therefore from the lowest point to the highest point we have ¼ of oscillation, consequently the time to the highest point.
t = T / 4
y = y₀ cos ( [tex]2 \pi 4[/tex])
y = y₀
Therefore the point of maximum amplitude coincides with the maximum height and must be average by the student, suppose that the height is
y₀ = 20 cm = 0.20 m
Let's calculate the initial velocity.
v₀ = [tex]\sqrt{2 \ 9.8 \ 0.20 }[/tex]
v₀ = 1.98 m / s
They ask for the speed of the bullet before striking the basket of mass
M = 1 Kg.
The conservation of the momentum that for an isolated system the momentum is constant in all the instants. Let's form the system by the bullet and the basket.
Initial instant. Before the crash
p₀ = m v
Final moment. Right after the crash.
P_f = (m + M) v₀
The momentum is conserved because the system is isolated.
p₀ = p_f
m v = (m + M) v₀
v = m + M / m v₀
they have tabulated various mass for the bullet, we calculate the speed of each bullet.
m = 0.05 kg
v = [tex]\frac{0.05+1}{0.05} \ 1.98[/tex]
v = 41.58 m / s
m = 0.10 kg
v = [tex]\frac{0.10+1}{0.10} \ 1.98[/tex]
v = 21.78 m / s
m = 0.15 kg
v = [tex]\frac{0.15+1}{0.15y}[/tex]
v = 15.18 m / s
m = 0.20 kg
v = 11.88 m / s
m = 0.25 kg
v = 9.9 m / s
In conclusion with the conservation of energy and the momentum we can find the results for the speed of the pendulum and the bullet in the system are:
The velocity of the pendulum (bullet + basket) is: v₀ = 1.98 m The speed of the bullet, depending on the mass are:m (kg) v (m / s)
0.05 41.58
0.10 21.78
0.15 15.18
0.20 11.88
0.25 9.90
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Twins Bo and Joe have a combined mass of 200 kg and are zooming along at 10 m/s in a 100 kg amusement park bumper car. They bump into Melinda’s car, which is sitting still. Melinda has a mass of 25 kg and is also in a 100 kg car. After the collision, the twins continue moving with a speed of 4.12 m/s.
a. What is the initial momentum of the system?
b. What must be the final momentum of the system?
c. How fast is Melinda’s car bumped across the floor?
The speed with which Melinda’s car is bumped across the floor is 14 ms-1.
Total mass of the twins and the car = 300 Kg
Initial velocity of the twins car = 10 m/s
Total mass of Melinda and her car = 125 Kg
Initial velocity of Melinda's car = 0 m/s (at rest)
Final velocity of the twins car = 4.12 m/s
Final velocity of Melinda's car = ?
Initial momentum of the system = (300 × 10) + (125 × 0) = 3000 Kgms-1
Final momentum of the system = (300 × 4.12) + (125 × x) = (1236 + 125x) Kgms-1
Using the principle of conservation of linear momentum;
Total momentum before collision = Total momentum after collision
m1u1 + m2u2 = m2v1 + m2v2
(300 × 10) + (125 × 0) = (300 × 4.12) + (125 × x)
3000 = 1236 + 125x
x = 3000 - 1236 /125
x = 14 ms-1
The speed with which Melinda’s car is bumped across the floor is 14 ms-1.
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A machine does 2500 J of work in 1 min. What is the power developed by the machine?
Answer:
41.7 watts
Explanation:
power=work done/time
2500/60seconds
=41.6666
if you immerse an object into a known mass of water, the measured mass of the water will _____, and will be equal to the mass of the water displaced by the immersed object.
Answer: decrease
Explanation: it does
Which statement best explains why a wet saw used to cut through a fine optical crystals is constantly lubricated with oil
The major reason why a wet saw that is used in cutting optical crystals is constantly lubricated with oil is largely due to friction, lubrication decreases friction and minimises the increase of internal energy.
Friction is basically the coming together of two parts that rubs against each other, it causes heat and lead to deterioration of surfaces, it can also lead to wear and tear.
Although, despite it down side, friction is desire-able in most applications
e.g the brake system of vehicles, and if not for friction, we humans cannot walk without falling
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The diagram shows a nephron.
A nephron. W points to branch of renal artery. X points to branch of renal vein. Y points to tubular point of nephron. Z points to collecting duct.
Where is the blood first filtered?
Answer:
w
Explanation:
renal artery...the blood flow into the kidney via this blood vassles
and the filtration take place is called ultrafiltration
A 0.40 kg bead slides on a straight frictionless wire with a velocity of 3.50 cm/s to the right. The
bead collides elastically with a larger 0.60 kg bead initially at rest. After the collision the smaller
bead moves to the left with a velocity of 0.70 cm/s. Find the distance the larger bead moves along
the wire in the first 5.0 s following the collision?||
Answer:
Total momentum before collision
P1 =.4 * 3.5 = 1.4 ignoring units here
Total momentum after collision
P2 = .6 * V - .4 * .7 = .6 V - .28
.6 V = 1.4 + .28 momentum before = momentum after
V = 2.8 cm/sec
In 5 sec V moves 2.8 cm/sec * 5 sec = 14 cm
Simplicity of conducting the study is to ________ as ability to test large numbers of participants is to ________.
Simplicity of conducting the study is to archival research as ability to test large numbers of participants is to surveys.
What is Archival research?Archival research is a type of research which involves seeking out and extracting the evidence from archival records. These archival records may be held together either in the collection of institutions, such as libraries and museums, or in the custody of the organization that originally generated or accumulated them, or in that of a successor object.
Archival research can be contrasted with the secondary research, which involves identification and consulting the secondary sources related to the topic of enquiry; and with the other types of primary research and empirical investigation such as fieldwork and experiment.
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An object with a mass of 5 kg is accelerated from rest by a 60 N*s impulse. What is the change in the object's velocity?
Hi there!
Using the Impulse-Momentum theorem:
I = Δp = mΔv
Where:
I = Impulse (Ns)
m = mass of object (kg)
Δv = change in velocity (vf - vi, m/s)
Plug in the given values and solve:
60 = 5Δv
Δv = 12 m/s
The change in the momentum of an object is represented by the following formula:
Impulse = (Force)(time) = change in momentum
I = F • t = pfinal – pinitial
A 1.0 kg rabbit traveling east at 10 m/s spots a predator, turns around, and then begins to travel west at 21 m/s.
What is the change in momentum of the rabbit, and what is another term for this concept?
The rabbits change of momentum is
A. 31 kg•m/s east
B. 31 kg•m/s west
C. 15.5 kg•m/s, west
D. 15.5 kg•m/s, east
This value can also be referred to as
E. Collisions
F. Potential energy
G. Kinetic energy
H. Impulse
Please help will mark brainliest
Hi there!
Recall that:
Change in momentum = mass × change in velocity
Or:
Δp = mΔv = m(vf - vi)
Plug in the given values. We can assign east to be positive and west to be negative in this instance (Velocity is a vector with direction).
Thus:
Δp = (1)(-21 - 10) = -31 kgm/s OR 31 kgm/s WEST.
The correct answer is B.
Change in momentum is EQUIVALENT to the quantity of IMPULSE.
The correct answer is H.
The parking brake on a 1200kg automobile has broken, and the vehicle has reached a momentum of 7800kg.m/s. What is the velocity of the vehicle?
Answer:
Velocity of the vehicle (v) = 6.5 m/s
Explanation:
Mass of automobile (m) = 1200 kg
Momentum of vehicle (p) = 7800 kg m/s
By using formula of momentum:
[tex] \rm p = mv \\ \rm 7800 = 1200 \times v \\ \rm v = \frac{7800}{1200} \\ \rm v = 6.5 \: m {s}^{ - 1} [/tex]
Assertion: In domestic electric circuits, the metallic body is connected to the earth wire, which
provides a low-resistance conducting path for the current.
Reason: It ensures that any leakage of current to the metallic body of the appliance keeps its
potential to that of the earth, and the user may not get a severe electric shock. pls fast
Answer:
The answare is it ensures that any leakage of current to the metallic body of the appliance keeps its potential to that of the earth, and the user may not get a severe electric shock.
how many bears are witching the category of the
1. A student adds water and sugar to a jar and seals the jar so that nothing can get in or out. The
student then finds the mass of the jar containing the water and sugar. After some sugar dissolves, the
student finds the mass of the jar and its contents again.
Water
Sugar
and
Water
Sugar
Sugar
Before
After
Vhat will happen to the mass of the jar containing the water and sugar after some of the sugar
issolves?
a. The mass will stay the same
b. The mass will increase
c. The mass will decrease
The moon will donend on how much sunar dissolves
Answer:
The mass will stay the same throughout time