we can write equations from the statements
a washer and dryer cost 1001 combined
[tex]w+d=1001[/tex]where w is the price of the washer and d the price of the dryer
the washer costs 51 more the than the dryer
[tex]w=51+d[/tex]then we can replace the value of w from the second equation to the first equation
[tex]\begin{gathered} (51+d)+d=1001 \\ 51+d+d=1001 \\ 51+2d=1001 \end{gathered}[/tex]and solve for d
[tex]\begin{gathered} 2d=1001-51 \\ 2d=950 \\ d=\frac{950}{2} \\ \\ d=475 \end{gathered}[/tex]the cost of the dryer was $475
Which point is part of the solution of the inequality y ≤ |x+2|-3A.(-1,-1)B.(1,0)C.(0,0)D.(0,1)
We are going to test all options to see which is true and false.
The one that is true will be the point that is part of the solution.
[tex]\begin{gathered} A) \\ (-1,-1) \\ y\leq\lvert x+2\rvert-3 \\ -1\leq\lvert-1+2\rvert-3 \\ -1\leq\lvert1\rvert-3 \\ -1\leq1-3 \\ -1\leq-2 \\ \text{Not true, so the point (-1,-1) is not a part of the solution} \end{gathered}[/tex]We will move to the next option and test:
[tex]\begin{gathered} B) \\ (1,0) \\ y\leq\lvert x+2\rvert-3 \\ 0\leq\lvert1+2\rvert-3 \\ 0\leq\lvert3\rvert-3 \\ 0\leq3-3 \\ 0\leq0 \\ \text{The above solution is true, so it is a point that is part of the solution.} \\ \text{The correct answer is option B.} \end{gathered}[/tex]what is 2 to the 6 power
3. Define and find the value of the central angle theinscribed angle, and the arc associated with both.Central angle:namemeasureInscribed angle:namedoYmeasureArc:namemeasure
Given
Answer
Central angle
Name XOY
Measure 90
Inscribed angle
name XZY
Measure 45
Arc
name XY
Measure = circumference of circle/4
Sand will be placed under the base of a circular pool with a diameter of 14 feet. 1 bag of sand covers about 5 square feet. How many bags of sand are needed? Use 3.14 for pi. Round bags up.
I am getting hung up on the last part of doing this problem.
Any help is greatly appreciated.
Sand will be placed under the base of a circular pool with a diameter of 14 feet. 1 bag of sand covers about 5 square feet. the number of bags of sand required is 30bags.
The area of the pool is
A = πr²
A = 3.14×(7 ft)² = 153.8 ft²
The number of bags of sand required is ...
(153.8 ft²)/(5 ft²/bag) ≈ 30.76bags
bags of sand are needed.
What is diameter?The diameter is defined as twice the length of the radius of the circle. The radius is measured from the centre of the circle to one endpoint on the boundary of the circle, while the diameter is the distance measured from one end of the circle to a point on the other end of the circle that passes through the centre. This is indicated by the letter D. The circumference of a circle has an infinite number of points, which means that the circle has an infinite number of diameters and each diameter of the circle is the same length.
Ø is the symbol used in the design to indicate the diameter. This symbol is often used in technical data and drawings.
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Select the graph for the solution of the open sentence. Click until the correct graph appears. Ix| + 3 > 3
Given the sentence;
[tex]\mleft|x\mright|+3>3[/tex]Subtracting 3 from both sides;
[tex]\begin{gathered} \mleft|x\mright|+3>3 \\ |x|+3-3>3-3 \\ \mleft|x\mright|>0 \end{gathered}[/tex]Given the absolute value of x to be greater than zero, the range of value of x is;
[tex]\begin{gathered} x>0 \\ or \\ x<0 \end{gathered}[/tex]Therefore, the correct graph of the solution is;
Marco states that 7.696696669...... is a rational numberbecause it is a repeating decimal. Is he correct? Justifyyour answer.Yes he is correct because it keeps going and going and it will go on forever and ever so that is my guess
The answer is NO, Marco is wrong.
The number 7.696696669.... has not a repeating decimal there is no a number that is repeating, like 0.6969696969... in the last number the 69 is repeating, in the Marco's number the decimal number change every time.
The following hyperbola has a horizontal transverse axis: (x + 2) (w+7)=11617
for the given hyperbola
[tex]\frac{(x+2)^2}{16}-\frac{(y+7)^2}{17}=1[/tex]We have the following graph. Visually we can see that this hyperbola does have a transverse axis, however you can do all the calculations to check it
[tex]\begin{gathered} \frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1 \\ h=-2 \\ k=-7 \\ a^2=16 \\ b^2=17 \\ c^2=16+17 \\ c=\sqrt[]{33}=5.7 \\ f_1=(h-c,k) \\ f_1=(-2-5.7,-7) \\ f_2=(-7.7,-7) \\ f_2=(3.7,-7) \\ y=-7\to\text{ is the ecuation of the transversal axis} \end{gathered}[/tex]As we can see y = -7 is a line parallel to the x axis, turning the transversal axis horizontal.
That is, this hyperbola does have a horizontal transverse axis and the answer is TRUE
Twenty-five randomly selected students were asked the number of movies they watched the previous week. The results are as follows.
Given the table that shows the number of movies and the corresponding frequency, you can determine that the total frequency is:
[tex]Total\text{ }Frequency=25[/tex]By definition:
[tex]Relative\text{ }Frequency=\frac{Frequency}{Total\text{ }Frequency}[/tex]By definition, the Cumulative Frequency can be obtained by adding the corresponding frequency with the previous frequencies and dividing the sum by the Total Frequency.
Therefore, you can determine that:
- For:
[tex]Frequency=3[/tex]You know:
[tex]Relative\text{ }Frequency=\frac{3}{25}[/tex]And:
[tex]Cummulative\text{ }Relative\text{ }Frequency=\frac{3}{25}[/tex]- Given:
[tex]Frequency=8[/tex]You get:
[tex]Relative\text{ }Frequency=\frac{8}{25}[/tex]And:
[tex]Cummulative\text{ }Relative\text{ }Frequency=\frac{3+8}{25}=\frac{11}{25}[/tex]- Given:
[tex]Frequency=9[/tex]You get:
[tex]Relative\text{ }Frequency=\frac{9}{25}[/tex]And:
[tex]Cummulative\text{ }Relative\text{ }Frequency=\frac{3+8+9}{25}=\frac{4}{5}[/tex]- Given:
[tex]Frequency=4[/tex]You get:
[tex]Relative\text{ }Frequency=\frac{4}{25}[/tex]And:
[tex]Cummulative\text{ }Relative\text{ }Frequency=\frac{3+8+9+4}{25}=\frac{24}{25}[/tex]- Given:
[tex]Frequency=1[/tex]You get:
[tex]Relative\text{ }Frequency=\frac{1}{25}[/tex]And:
[tex]Cummulative\text{ }Relative\text{ }Frequency=\frac{3+8+9+4+1}{25}=\frac{25}{25}=1[/tex]Hence, the answer is:
10)BONUSKelll walks into science class and they have 6 hershey kisses and 6 reese cups on a scale that reads82.4 ounces. She wants some chocolate so she eats 2 hersey kisses and 1 reese cup and now thescale reads 63.8 ounces.a) Define your variables and set up a system of equations.
Leah, this is the solution:
Variables:
Let x to represent the weight of one Hershey kiss
Let y to represent the weight of one Reese cup
System of equations:
6x + 6y = 82.4
4x + 5y = 63.8
______________
Let's multiply the second equation by - 3/2, therefore:
6x + 6y = 82.4
-6x - 15y/2 = -95.7
________________
-15/2 + 6 = -3/2
_________________
-3y/2 = -13.3
Dividing by -3/2 at both sides:
-3y/2 / -3/2 = -13.3 / -3/2
y = 8.87
______________
Replacing y in the first equation and solving for x:
6x + 6 * 8.87 = 82.4
6x + 53.22 = 82.4
Subtracting 53.22 at both sides:
6x +53.22 - 53.22= 82.4 - 53.22
6x = 29.18
Dividing by 6 at both sides:
6x/6 = 29.18/6
x = 4.86
_________________
In conclusion, one Hershey kiss weights 4.86 ounces and one Reese cup weights 8.87 ounces.
Solve the following system of equations graphically on the set of axes below. Plot two or more dotes on the graphy = 2x - 8 y = -x + 4
Given:-
[tex]y=2x-8,y=-x+4[/tex]To find the graphical representation.
So the graph of y=2x-8 is,
Also the graph of y=-x+4 is,
Combining we get the graph
So the point is (4,0).
Surface area of a cone: S = πr² + πrl;solve for l.
Answer:
[tex]l=\frac{S-\pi r^{2}}{\pi r}[/tex]Explanation:
The surface area of a cone is calculated using the formula:
[tex]S=πr^2+πrl[/tex]We want to solve for l.
First, subtract πr² from both sides of the equation:
[tex]\begin{gathered} S-\pi r^2=\pi r^2-\pi r^2+\pi rl \\ S-\pi r^2=\pi rl \end{gathered}[/tex]Next, divide both sides by πr:
[tex]\begin{gathered} \frac{S-\pi r^2}{\pi r}=\frac{\pi rl}{\pi r} \\ l=\frac{S-\pi r^{2}}{\pi r} \end{gathered}[/tex]The equation solved for l is:
[tex]l=\frac{S-\pi r^{2}}{\pi r}[/tex]The mayor of a town proposes to fence off a triangular area of a building that includes two sides of the building as shown below.Which distance, in feet could be the length of the proposed fence line?100280220130
Solution
Using triangle inequality
The triangle inequality states that the sum of the lengths of any two sides of a triangle is greater than the length of the remaining side.
The fence line is the longest size
100, 130 can't be the answer
[tex]200+70=270[/tex]280 can't be the answer be ause the triangle inequality says it should be less than the sum
[tex]Z<\text{ X +Y}[/tex]Therefore, the correct answer is 220
Find the distance d(P1, P2) between the given points P1 and P2: P1 =(0,0) P2 = (2,3)d(P1,P2) = (Simplify your answer using radical as needed)
Recall that given points (a,b) and (c,d) the distance between them would be
[tex]d=\sqrt[2]{(c\text{ -a\rparen}^2+(d\text{ -b\rparen}^2}[/tex]In our case we are given a=0,b=0,c=2,d=3. So the distance would be
[tex]d=\sqrt[2]{(2\text{ -0\rparen}^2+(3\text{ -0\rparen}^2}=\sqrt[2]{2^2+3^2}=\sqrt[2]{4+9}=\sqrt[2]{13}[/tex]so the distance between them is the square root of 13.
Which statements describe one of the transformations performed on f(x) = x?to create g(x) - 3(x + 5)2 - 2? Choose all that apply.DA. A translation of 2 units to the leftI B. A vertical stretch with a scale factor of 3O C. A vertical stretch with a scale factor of3O D. A translation of 5 units to the left
Solution:
The Function transformation of f(x) is:
[tex]g(x)=f(x+c)+d[/tex]If c > 0, then the graph shift left f(x+c).
If c<0, then the graph shift right f(x-c)
If d > 0, then the graph shift up f(x) +d
If d < 0, then the graph shift down f(x) -d
When the given equation is:
[tex]f(x)=x^2[/tex]The transformation equation is given:
[tex]g(x)=3(x+5)^2-2[/tex]Then, the graph shifts down 2 units and shifts left 5 units.
Also, the vertical stretch with a scale factor 3.
Therefore, the correct options are B and D.
Solve the following inequality: 6p - 15 < 33
WE are to solve an inequality, so we proceed to isolate the variable "p" on one side of the inequality symbol:
6 p - 15 < 33
we add 15 to both sides:
6 p < 33 + 15
6 p < 48
now divide both sides by 6 (notice that since 6 is a positive number, the division doesn't change the direction of the inequality)
p < 48/6
p < 8
So we need to highlight on the number line, the line that starts at "8" and goes all the way to the left (to minus infinity), and make sure that at the point "8" you draw an "empty" circle to indicate that the number 8 itself is NOT included in your set of solutions.
17. A moving company charges a flat rate of $85 plus and additional $0.17 per mile driven. How far must the company drive to earn at least $100? Round to thenearest mile.x2 84x2 78x2 80x2 88
ANSWER
88
EXPLANATION
Let x be the miles driven and y be the earnings of the company when they drive for x miles.
If the company charges $0.17 per mile driven plus a flat rate of $85, then the total cost for moving x miles away is,
[tex]y=85+0.17x[/tex]Now, we have to find for how many miles, x, the company must drive to earn $100 or more,
[tex]85+0.17x\ge100[/tex]Subtract 85 from both sides,
[tex]\begin{gathered} 85-85+0.17x\geq100-85 \\ \\ 0.17x\ge15 \end{gathered}[/tex]And divide both sides by 0.17,
[tex]\begin{gathered} \frac{0.17x}{0.17}\ge\frac{15}{0.17} \\ \\ x\ge88.24 \end{gathered}[/tex]Hence, the company must drive for at least 88 miles to earn at least $100, rounded to the nearest mile.
need help please 16x=-44-4y
-8x=28+4y
Answer: (x,y)= (-2/5,-43/5)
Step-by-step explanation:
At the park there is a pool shaped like a circle. A ring-shaped path goes around the pool. Its inner radius is 7 yd and its outer radius is 9 yd.We are going to give a new layer of coating to the path. If one gallon of coating can cover 5v * d ^ 2 how many gallons of coating do we need? Note that coating comes only by the gallon, so the number of gallons must be a whole number. (Use the value 3.14 for pi.)
in the graph below line k,y=-x makes a 45 degree angle with the x and y axescomplete the following
step 1
The equation of line k is y=-x
The rule of the reflection across the line y=-x is equal to
(x,y) -------> (-y,-x)
so
we have the point (2,5)
Apply the rule
(2,5) -----> (-5,-2)
step 2
Reflection across the x axis
The rule of the reflection across the x axis is
(x,y) ------> (x,-y)
so
Apply the rule to the point (-5,-2)
(-5,-2) ------> (-5,2)
therefore
the answer is
(-5,2)True or false the surface area of a sphere with a radius of 10 units is larger than the surface area of a cube with edge lengths of 10 units
The surface area of a sphere is given by
[tex]S_s=4\pi r^2[/tex]in our case r=10 units ( the radius). By substituting this value into the last formula, we have
[tex]S_s=4(3.1416)(10^2)[/tex]which gives
[tex]S_s=1256.64u^2[/tex]On the other hand, the surface area of a cube is given by
[tex]S_c=6L^2[/tex]where L is the length of one side, that is, L=10. Then, we have
[tex]\begin{gathered} S_c=6\cdot(10^2) \\ S_c=6\cdot100=600u^2 \\ S_c=600u^2 \end{gathered}[/tex]By comparing both results, we can see that the surface area of our sphere is larger than the surface area of the given cube. So the answer is TRUE.
The price of Stock A at 9 A.M. was $12.42. Since then, the price has been increasing at the rate of $0.12 each hour. At noon the price of Stock B was $12.92. It begins to decrease at the rate of $0.09 each hour. If the two rates continue, in how many hours will the prices of the two stocks be the same?
The hours when the prices of the two stocks be the same is 2.38 hours.
How to illustrate the information?From the information, the price of Stock A at 9 A.M. was $12.42 and the price has been increasing at the rate of $0.12 each hour. This will be the expressed as 12.42 + 0.12h.
At noon the price of Stock B was $12.92. It begins to decrease at the rate of $0.09 each hour. This will be:
= 12.92 - 0.09h
where h = number of hours
Equate both equations. This will be:
12.42 + 0.12h = 12.92 - 0.09h
Collect like terms
12.92 - 12.42 = 0.12h + 0.09h
0.21h = 0.50
h = 0.50 / 0.21
h = 2.38 hours.
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The smaller of two similar balloons has a diameter of 10 inches. If it takes 12 (same sized) breaths to blow up the smaller balloon and 40.5 to blow up the larger, what is the diameter of the larger balloon?
The smaller of two similar balloons has a diameter of 10 inches. If it takes 12 (same sized) breaths to blow up the smaller balloon and 40.5 to blow up the larger, what is the diameter of the larger balloon?
we have that
If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube.
so
Find the scale factor
ratio volumes=40.5/12=3.375
3.375=(scale factor)^3
[tex]\text{scale factor=}\sqrt[3]{3.375}[/tex]scale factor=1.5
To find out the diameter of the larger balloon multiply the scale factor by the diameter of the smaller balloon
so
1.5*(10)=15 inches
the answer is 15 inchesFor every 4 songs on Mary's playlist, 3 of the songs are longer than 5 minutes.
Complete the table of values to compare the total money spent to tickets purchased.
Total Number of Songs on Playlist
Number of Songs Longer Than 5 Minutes
8
32
40
136
we were told that in every 4 songs on the playlist, 3 of the songs are longer than 5
so if in for 4 songs, 3 is longer than 5
for 8 songs,
we divide the the number of songs in the playlist by 4 in other to get the numbers of 4 in it then muliply by the number of songs longer than 5
for 8 songs on the playlist:
= 8/4 X 3
= 2 X 3
= 6
For 32 songs on the playlist
= 32/4 X 3
= 8 X 3
= 24
For 40 songs on the playlist
= 40/4 X 3
= 10 X 3
= 30
For 136 number of songs on the playlist
= 136/4 X 3
= 34 X 3
= 102
so in completing the table:
Total Number of Songs on the Playlis Number of songs longer than 5min.
8 6
32 24
40 30
136 102
The following circle passes through the origin. Find the equation.
Answer
(x - 2)² + (y - 2)² = 8
Step-by-step explanation
The equation of the circle centered at (h, k) with radius r is:
[tex](x-h)^2+(y-k)^2=r^2[/tex]In this case, the center of the circle is the point (2, 2), then h = 2 and k = 2, that is,
[tex](x-2)^2+(y-2)^2=r^2[/tex]Given that the circle passes through the center, then the point (0, 0) satisfies the above equation. Substituting x = 0 and y = 0 into the equation and solving for r²:
[tex]\begin{gathered} (0-2)^2+(0-2)^2=r^2 \\ 4+4=r^2 \\ 8=r^2 \end{gathered}[/tex]Substituting r² = 8 into the equations, we get:
[tex](x-2)^2+(y-2)^2=8[/tex]1. Abby baked 2-dozen brownies. She took 1 dozen to her scout meeting. Her family ate 8, and she put the rest in a container in the refrigerator. How can Abby find the number of brownies left in the refrigerator?
In order to determine the amount of brownies left in the refrigerator, subtract 8 from 12.
How many brownies are left in the refrigerator?If Abby bakes 2 -dozen brownies, she baked 24 brownies. There are 12 pieces in 1 dozen, thus if she bakes two dozens, she baked 24 brownies ( 12 x 2).
The amount of brownies left after she takes one dozen to school = amount baked - amount taken for the meeting
24 - 12 = 12
Amount left in the refrigerator : amount left after she took a dozen for the meeting - amount eaten by her family
12 - 8 = 4
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Please help me come you just tell me the answer I don’t really need you to explain
Given:
[tex]\begin{gathered} \angle JKL=65 \\ \angle KJL=50 \end{gathered}[/tex]Sum of the angle of any triangle is 180
So:
[tex]\begin{gathered} \angle JKL+\angle KJL+\angle KLJ=180 \\ 65+50+\angle KLJ=180 \\ \angle KLJ=180-(65+50) \\ \angle KLJ=180-115 \\ \angle KLJ=65 \end{gathered}[/tex]Then two sides are also equal.
[tex]\begin{gathered} 3x-2=x+10 \\ 3x-x=10+2 \\ 2x=12 \\ x=\frac{12}{2} \\ x=6 \end{gathered}[/tex]So the value of x is 6.
Finding the mode and range of a data set Each day, Kaitlin records the number of news articles she reads. Here are her results for the last eight days. 7, 3, 8, 5, 7,7,7,8 Find the mode and the range for the data. Mode: Range: X 5 ?
Explanation:
The set of values are given below as
[tex]7,3,8,5,7,7,7,8[/tex]Mode:
This the data that occurs highest or the dat that has the highest frequency
Range:
The is the difference between the lowest val and the highest value
[tex]Range=highest-lowest[/tex]Hence,
The final answers are
[tex]\begin{gathered} mode=7(it\text{ occurs 4 times\rparen} \\ range=8-3=5 \end{gathered}[/tex]Hence,
The final answer is
[tex]\begin{gathered} mode=7 \\ Range=5 \end{gathered}[/tex]Is Ari’s answer to the question, correct? If not, where did Ari make a mistake? If his answer is incorrect, explain what the correct answer is and why it is correct.
None of Ari's answer to the question is correct. The right application of the laws of exponents to get the correct answer is explained below.
What are the Laws of Exponents?Some of the laws of exponents can be summarized as follows.
The product law of exponents: This states that we are to add the exponents together if we are multiplying two numbers that have the same base. For example, [tex]x^m \times x^n = x^{m + n}[/tex].The division law of exponents: this states that when dividing two numbers that have the same base, we are to find the difference of their exponents. For example, [tex]\frac{x^m}{x^n} = x^{m - n}[/tex].The negative law of exponents: This state that, [tex]x^{-m} = \frac{1}{x^m}[/tex].Based on the above laws of exponents, none of Ari's answer is correct. Below are the correct way to solve the questions:
1. [tex]4^2 \times 4^5 = 4^{2 + 5} = 4^7[/tex]
2. [tex](2^{-5})^3 = 2^{-3 \times 5} = 2^{-15} = \frac{1}{2^{15}}[/tex]
3. [tex]\frac{(\frac{1}{4})^4 \times (\frac{1}{4})^5 }{(\frac{1}{4})^3} = \frac{(\frac{1}{4})^{4 + 5} }{(\frac{1}{4})^3} = \frac{(\frac{1}{4})^9 }{(\frac{1}{4})^3} = (\frac{1}{4})^{9 - 3}} = (\frac{1}{4})^6[/tex]
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match the function rule with the graph of the function (number 24)
It is given that the function is:
[tex]y=\frac{3}{4}\times4^x[/tex]Therefore y=0 then the value of x will be:
[tex]\begin{gathered} 0=4^x \\ x=-\infty \end{gathered}[/tex]Now at x=0, y will be:
[tex]y=\frac{3}{4}[/tex]at x=1, y will be:
[tex]y=\frac{3}{4}\times4=3[/tex]These 3 points that is (-inf,0),(0,3/4),(1,3) are on graph D.
Hence option D is coreect.
LaVelle is making a pitcher of caffe mocha. For each ounce of chocolate syrup, she uses 5 ounces of coffee. She wants to make 48 ounces of caffe mocha.
Let c represent the number of ounces of coffee, and let s represent the number of ounces of chocolate syrup used. Which of the following systems of equations models this situation?
The systems of equations which correctly models the situation as described is;
s = 5c ands + c = 48Which systems of equations correctly models the situation as described in the task content?It follows from the task content that the system of equations which models the production process of caffe mocha be determined.
As given in the task content;
Let c represent the number of ounces of coffee.Let s represent the number of ounces of chocolate syrup.Hence, since For each ounce of chocolate syrup, she uses 5 ounces of coffee, the situation can be represented algebraically as;
s = 5c.Also, since she wants to make 48 ounces of caffe mocha; we have;
s + c = 48.Therefore, the required system of equations is;
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