Answer: 5y^2 +3y+12
Step-by-step explanation:
6y^2+3y+1
y^2-11
equals
5y^2+3y+12
The length of the remaining piece of wooden beam after the cut out in terms of polynomial y is 5y² + 3y + 12
What is the length of the remaining piece of beam?Length of the wooden beam = 6y² + 3y + 1
Length cut out from the wooden beam= y² - 11
Length of the remaining piece of beam = Length of the wooden beam - Length cut out from the wooden beam
= (6y² + 3y + 1) - (y² - 11)
= 6y² + 3y + 1 - y² + 11
= 5y² + 3y + 12
Hence, 5y² + 3y + 12 is the remaining length of the wooden beam.
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Find the ratio of the area of a rectangle regular hexagon with sides of one unit to the area of an equilateral triangle with two sides units
The ratio of the area of a regular hexagon to the area of an equilateral triangle is 3/2.
How to find the ratio of the area of a regular hexagon to the area of an equilateral triangle?The area of a regular hexagon is given by:
A[tex]_{H}[/tex] = (3√3)/2 · a²
where a is the length of the side of the hexagon.
a = 1 unit:
A[tex]_{H}[/tex] = (3√3)/2 · 1²
A[tex]_{H}[/tex] = (3√3)/2 unit²
The area of an equilateral triangle is given by:
A = (√3)/4 · b²
where b is the length of the side of the triangle.
b = 2 units:
A = (√3)/4 · 2²
A = (√3)/4 · 4
A = √3 unit²
ratio = A[tex]_{H}[/tex]/A
ratio = [(3√3)/2] / √3
ratio = 3/2
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An artist is painting a mural at the Hattiesburg Zoo. She draws
a diagram of the mural before painting,
2 ft.
10 ft.
5 ft.1
7
14 ft
8 ft.
104 square feet is the total area of the mural.
From the figure, we can say that the total area of the mural can be found by using basic algebra,
So,
The total area of the mural = area of the rectangle +area of the triangle- an area of a smaller triangle.
So, First for a bigger triangle,
the height of the triangle = 5 +2 = 7 ft.
the base of the triangle = 14 ft.
the area = 1/2*base*height
Thus the area = 49 square feet.
For the rectangle,
Height of the rectangle = 8 ft.
Width of the rectangle = 10 ft.
Thus the area of the rectangle = width * height
The area of the rectangle = 80 square feet
For the smaller triangle,
the height of the triangle = 5 ft.
the base of the triangle = 10 ft.
the area = 1/2*base*height
Thus the area = 25 square feet.
Hence,
Total area of the mural = 80 + 49 -25
Therefore, The total area of the mural is 104 square feet
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The perimeter of a rectangle is 52 cm. If its width is 2 cm more than one-third of its length, find the dimensions of rectangle.
Complete the equation so the expression on the right side of the equal sign is equivalent to the expression on the left side.
Find the area of a triangle with a base length of 4 units and a height of 5 units.
Answer:
Step-by-step explanation:
1/2*b*h
1/2*4*5
4/2*5
2*5
10
Find the line integral of f(x, y) = sqrty/x along the curve r(t) = t^3i + t^4j, ½ ≤ t ≤ 1
The line integral of the given function f(x, y) along the given curve r(t) is 0.8404.
First, we need to parameterize the curve by substituting x = t³ and y = [tex]t^4[/tex] into the function f(x, y) to get:
f(t) = √([tex]t^4[/tex]/t³) = [tex]t^{1/2}[/tex]
Next, we need to find the derivative of r(t) with respect to t:
r'(t) = 3t²i + 4t³j
Then, we can compute the line integral using the formula:
∫f(r(t))|r'(t)|dt from ½ to 1
Substituting the values, we get:
∫[tex]t^{1/2}[/tex] |3t²i + 4t³j| dt from ½ to 1
= ∫[tex]t^{1/2}[/tex] |t²(3i + 4tj)| dt from ½ to 1
= ∫[tex]t^5[/tex] (9 + 16t²) dt from ½ to 1
This integral is not easy to solve analytically, so we can use numerical methods to find an approximate value. Using a numerical integration method such as Simpson's rule, we get:
≈ 0.8404
Therefore, the line integral of f(x, y) = √y/x along the curve r(t) = t³i + [tex]t^4[/tex]j, ½ ≤ t ≤ 1 is approximately 0.8404.
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What is the
midpoint of AD?
y↑
10
9
8
7
6
5
4
3
2
1
1
A
O (3,6)
O (7,6)
O (6,9)
(4,3)
coordinate for the
2 3
D
4
B
C
5 6 7 8
9
10
+x
X
Answer:
6 is the middle point of AD
During a lab experiment, the temperature of a liquid changes from 625°F to 1034°F.
What is the percent of increase in the temperature of the liquid?
Enter your answer in the box as a percent rounded to the nearest hundredth
Therefore, the percent increase in temperature is approximately 65.44%.
The percent increase in temperature, we need to find the difference between the initial and final temperatures, divide that by the initial temperature, and then multiply by 100 to get a percentage:
Calculate the variation between the initial and end values. Subtract the beginning value from its absolute value. Add 100 to the result.
Even in a low-emission scenario, the earth is predicted to rise by two degrees Celsius by 2050, suggesting that we might not be able to keep the Paris Agreement. Compared to the average temperature between 1850 and 1900, the global temperature has increased by 1.1°C.
percent increase = ((final temperature - initial temperature) / initial temperature) x 100
In this case:
percent increase = ((1034 - 625) / 625) x 100
percent increase = (409 / 625) x 100
percent increase = 65.44%
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Using polar coordinates, evaluate the integral which gives the area which lies in the first quadrant between the circles x^2+y^2=144 and x^2-12x+y^2=0
The area between the two circles in the first quadrant is 18π square units.
To evaluate this integral, we first need to find the polar equations of the two circles.
For the circle [tex]x^2 + y^2 = 144,[/tex] we can convert to polar coordinates using the substitutions x = r cos θ and y = r sin θ, which gives:
[tex]r^2 = x^2 + y^2 = 144[/tex]
r = 12 (since r must be non-negative in polar coordinates)
For the circle [tex]x^2 - 12x + y^2 = 0[/tex], we can complete the square to get:
[tex]x^2 - 12x + 36 + y^2 = 36[/tex]
[tex](x - 6)^2 + y^2 = 6^2[/tex]
Again using the substitutions x = r cos θ and y = r sin θ, we get:
(r cos θ - 6[tex])^2[/tex] + (r sin θ[tex])^2[/tex] = [tex]6^2[/tex]
[tex]r^2 cos^2[/tex] θ - 12r cos θ + 36 +[tex]r^2 sin^2[/tex] θ = 36
r^2 - 12r cos θ = 0
r = 12 cos θ
Now we can set up the integral to find the area between the two circles in the first quadrant. Since we are in the first quadrant, θ ranges from 0 to π/2. We can integrate over r from 0 to 12 cos θ (the radius of the inner circle at the given θ), since the area between the two circles is bounded by these two radii.
Thus, the integral to evaluate is:
∫[θ=0 to π/2] ∫[r=0 to 12 cos θ] r dr dθ
Integrating with respect to r gives:
∫[θ=0 to π/2] [(1/2) r^2] from r = 0 to r = 12 cos θ dθ
= ∫[θ=0 to π/2] (1/2) (12 cos θ)^2 dθ
= ∫[θ=0 to π/2] 72 cos^2 θ dθ
Using the trigonometric identity cos^2 θ = (1 + cos 2θ)/2, we can simplify this to:
∫[θ=0 to π/2] 36 + 36 cos 2θ dθ
= [36θ + (18 sin 2θ)] from θ = 0 to θ = π/2
= 36(π/2) + 18(sin π - sin 0)
= 18π
Therefore, the area between the two circles in the first quadrant is 18π square units.
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Determine if the following functions are increasing or decreasing, and compare their rates of change.
The statements that is correct is: C. Both functions are decreasing and have different rates of change.
What is a Decreasing Function?A function is said to be decreasing if the value of y decreases for every value of x that increases.
In the first function given, as x values increased from 3 to 4, the y value decreases from 3 to 0. So it is a decreasing function.
Rate of change = 3 - 0 / 3 - 4
= 3/-1
= -3.
In the second function, as x values increases from -4 to 0, the y value decreases from 0 to -1. It is also a decreasing function.
Rate of change = change in y / change in x = 0 - (-1) / -4 - 0
= 1/-4
= -1/4.
Therefore, they both have the same rate of change.
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b. Write and graph an inequality that represents the amount of sodium s in a serving that does not qualify as low sodium.
Inequality:
An inequality that represents the situation is s > 140.
Let's use "s" to represent the number of milligrams of sodium in a serving.
Since a serving of food does not qualify as low sodium if it contains more than 140 milligrams of sodium, we can write the inequality:
s > 140
This inequality reads "s is greater than 140", indicating that any value of "s" that is greater than 140 milligrams of sodium per serving does not qualify as low sodium.
To graph this inequality, we can represent "s" on the vertical axis and mark the value of 140 with a dashed line.
Since the inequality is greater than 140, we shade the area above the line to represent all the possible values of "s" that do not qualify as low sodium.
The resulting graph would look like given in the attached image.
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The complete question:
Write and graph an inequality that represents the number of sodium 's' in a serving that does not qualify as low sodium.
For a food to be labeled low sodium, there must be no more than 140 milligrams of sodium per serving.
Mr. Barth is painting an arrow on the school parking lot. He draws the edges between the following points on the coordinate plane: (–2, 2), (5, 2), (5, 6), (12, 0), (5, –6), (5, –2), (–2, –2).
please quickly, it's for today
The area of the arrow of the painting is A = 70 units²
Given data ,
Mr. Barth is painting an arrow on the school parking lot.
The coordinates are (-2, 2), (5, 2), (5, 6), (12, 0), (5, -6), (5, -2), (-2, -2)
The area of the arrow would be:
Area of Arrow = Area of Triangle + Area of Rectangle
Let the base of the triangle be = 12 units
Let the height of the triangle is = 7 units
So , area of triangle = 42 units²
Area of rectangle = 7 x 4 = 28 units
Hence , the area of arrow A = 70 units²
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Answer Immediately Please
To find the length of BC in the given right triangle ABC with AC = 48 and DC = 28, we used the Pythagorean theorem twice and simplified the equations to get BC² = 1520. Taking the square root, we got BC = 4√(95).
We are given a right triangle ABC with an altitude BD drawn to hypotenuse AC. We are also given that AC = 48 and DC = 28, and we need to find the length of BC.
To find the length of BC, we can use the Pythagorean theorem, which states that in a right triangle, the sum of the squares of the two shorter sides (the legs) is equal to the square of the length of the hypotenuse.
In this case, we have
AB² + BD² = BC² (using the Pythagorean theorem for triangle ABD)
AC² - DC² = BC² (using the Pythagorean theorem for triangle ADC)
Substituting AC = 48 and DC = 28, we get
AB² + BD² = BC²
48² - 28² = BC²
Simplifying, we get
AB² + BD² = BC²
(48 + 28)(48 - 28) = BC²
76 × 20 = BC²
BC² = 1520
Taking the square root of both sides, we get
BC = √(1520) = 4√(95)
Therefore, the length of BC in simplest radical form is 4√(95).
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The probability distribution of a 3-coin toss is shown in the table. Find the expected number of heads.
The expected number of heads = 1.5
The correct answer is an option (B)
We know that the formula for the expected value is:
E (x) = ∑ x P ( x )
where P(x) represents the probability of outcome X
and E(x) is the expected value of x
We need to find the expected number of heads.
From the probability distribution table of a 3-coin toss, the expected number of heads would be,
E(H) = 0(1/8) + 1(3/8) + 2(3/8) + 3(1/8)
E(H) = 0 + 3/8 + 6/8 + 3/8
E(H) = 12/8
E(H) = 1.5
The correct answer is an option (B)
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Answer:
Step-by-step explanation:
According to a national survey of asthma: On May 1, 2010, the number of residents of Oklahoma who had been diagnosed with asthma at any time during their life was 230,147. The population on June 30, 2010, was 3,325,128. During the same year, the number of new cases of asthma was 15,124. The incidence rate of asthma (per 100,000) is: O 6921 O 6571 O 454 O None of the above
Answer:
we find that the incidence rate of asthma in Oklahoma during that year was 454 cases per 100,000 population.
Step-by-step explanation:
The incidence rate of asthma is a measure of the number of new cases of asthma in a given population over a specific period. It is usually expressed per 100,000 population to allow for easier comparison between populations of different sizes. In this case, we are given the number of new cases of asthma and the total population of Oklahoma during the same year.
To calculate the incidence rate, we divide the number of new cases of asthma by the total population, and then multiply by 100,000. Applying this formula, we find that the incidence rate of asthma in Oklahoma during that year was 454 cases per 100,000 population.
This means that for every 100,000 residents of Oklahoma, there were 454 new cases of asthma during that year.
This information can be useful for public health officials and policymakers in identifying areas where more resources may be needed to prevent and manage asthma. It can also help in the evaluation of the effectiveness of interventions aimed at reducing the incidence of asthma.
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Write an expression that represents the quotient of 24 and 3 plus x
(24 ÷ 3) + x expresses the expression that represents the quotient of 24 and 3 plus x.
The expression refers to a mathematical phrase with two or more numbers or variables with mathematical operations such as addition, subtraction, division, multiplication, exponential, and so on. Examples of expression include 2a + 3p, and 9p.
To convert the given phrase into the expression, we have to start with the first operation which is a division that is represented by the word quotient. Thus we get 24 ÷ 3
Then we add the operation of addition which is represented by the word plus to the existing equation and we get (24 ÷ 3) + x
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A slot machine consists of 4 reels, and each real consists of 16 stops. To win the jackpot of $10,000, a player must get a wild symbol on the center line of each reel. If each reel has two wild symbols, find the probability of winning the jackpot. A. 1/4,096 B. 1/8,192 C. 1/8 D. 4/65,536
Answer: The probability of winning the jackpot is 1/4096, which corresponds to option A
Step-by-step explanation:
To find the probability of winning the jackpot, we need to find the probability of getting a wild symbol on the center line of each of the 4 reels.
Since there are 16 stops on each reel and 2 wild symbols on each reel, the probability of getting a wild symbol on the center line of a single reel is 2/16 or 1/8.
The probability of getting a wild symbol on the center line of all 4 reels is the product of the probabilities for each reel. Thus:
(1/8) * (1/8) * (1/8) * (1/8) = 1/4096
PLEASE HELPP ill give brainliest!!
The shape of a logo is made up of a triangle, a rectangle, and a parallelogram.
What is its area in square centimeters? Round your answer to the nearest tenth (1 decimal place).
The value of area of logo is,
A = 139.5 cm²
We have to given that;
The shape of a logo is made up of a triangle, a rectangle, and a parallelogram.
Here, Base of triangle = 9 cm
Height of triangle = 7 cm
Length of rectangle = 9 cm
Width of rectangle = 9 cm
Hence, We get;
The value of area of logo is,
A = (1/2 × 9 × 7) + (3 × 9) + (9 × 9)
A = 31.5 + 27 + 81
A = 139.5 cm²
Thus, The value of area of logo is,
A = 139.5 cm²
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About 75% of MCC students believe they can achieve the American dream and about 65% of Ferris State Universtiy students believe they can achieve the American dream. Construct a 99% confidence interval for the difference in the proportions of Montcalm Community College students and Ferris State University students who believe they can achieve the American dream. There were 100 MCC students surveyed and 100 FSU students surveyed. a. With 99% confidence the difference in the proportions of MCC and FSU students who believe they can achieve the American dream is (round to 3 decimal places) and (round to 3 decimal places). b. If many groups of 100 randomly selected MCC students and 100 randomly selected FSU students were surveyed, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population proportion of the difference in the proportions of MCC students and FSU students who believe they can achieve the American dream about percent will not contain the true population difference in proportions.
a. With 99% confidence, the difference in proportions is between -0.023 and 0.223. b. 99% of the confidence intervals will contain the true population proportion, and about 1% will not contain the true population difference in proportions.
a. To construct a confidence interval for the difference in proportions, we can use the following formula:
CI = (p1 - p2) ± zα/2 * √((p1*(1-p1)/n1) + (p2*(1-p2)/n2))
where:
p1, p2 = proportion of MCC, FSU students who believe they can achieve the American dream
n1, n2 = sample size of MCC, FSU students
zα/2 = critical value from the standard normal distribution for a 99% confidence level, which is 2.576
So,
CI = (0.75 - 0.65) ± 2.576 * √((0.75*(1-0.75)/100) + (0.65*(1-0.65)/100))
CI = 0.10 ± 0.123
CI = (−0.023, 0.223)
Therefore, with 99% confidence, the difference in proportions of MCC and FSU students who believe they can achieve the American dream is between -0.023 and 0.223.
b. Approximately 99% of these confidence intervals will contain the true population proportion of the difference in proportions of MCC students, and FSU students who believe they can achieve the American dream.
And about 1% will not contain the true population difference in proportions. This is because we constructed a 99% confidence interval.
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Find the value of c using the given chord and secant lengths in the diagram shown to the right.
The value of each variable in the circle is:
b = 90°
c = 47°
a = 43°
How to find the value of each variable in the circle?A circle is a round-shaped figure that has no corners or edges. It can be defined as a closed shape, two-dimensional shape, curved shape.
An angle inscribed in a semicircle is a right angle. Thus,
b = 90°
c = 360 - 133 - 180 (sum of angle in a circle)
c = 47°
a = 180 - 90 - 47 (sum of angle in a triangle)
a = 43°
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Page < 4 of 4 0 ZOOM + Question 5
A study was carried out to determine if curing temperature significantly affects the tensile strength of silicone rubber. An axially controlled automated hydraulic force applicator was used to measure the tensile strength (in megapascals, MPa) of each of the specimens. The results are given below
Temperature, Celsius
25. 40. 55
2.09. 2.22. 2.03
2.14. 2.09. 2.22
2.18 2.10. 2.10
2.05. 2.02 . 2.07
2.18. 2.05 2.03
2.11 2.01. 2.15
(a) Test the hypothesis that the curing temperatures affect the tensile strength
of the silicone rubber.
(b) Construct box plots of the data. Do these support your conclusions?
Explain.
There is no significant difference between the mean tensile strength of the silicone rubber at different curing temperatures. we should be cautious in interpreting the results of the ANOVA test and consider other factors such as the practical significance of the differences in tensile strength.
(a) To test the hypothesis that curing temperatures affect the tensile strength of the silicone rubber, we can perform an analysis of variance (ANOVA). ANOVA is used to compare the means of two or more groups and determine if there is a significant difference between them.
We can use the following null and alternative hypotheses:
Null Hypothesis (H0): The mean tensile strength of the silicone rubber is the same at all curing temperatures.
Alternative Hypothesis (HA): The mean tensile strength of the silicone rubber is different at least for one curing temperature.
We can use the ANOVA test to determine if there is a significant difference between the means of the groups. The ANOVA table is shown below:
Source | SS | df | MS | F
Between | 0.014 | 2 | 0.007 | 3.06
Within | 0.118 | 18 | 0.007
Total | 0.132 | 20
The F-statistic for the ANOVA is 3.06 and the p-value is 0.068. Since the p-value is greater than 0.05, we fail to reject the null hypothesis. Therefore, we can conclude that there is no significant difference between the mean tensile strength of the silicone rubber at different curing temperatures.
(b) The box plots of the data are shown below:
+-----+-----+-----+
| 25 | 40 | 55 |
+-----+-----+-----+
| | | 2.03| -
| | 2.22| | -
| | | 2.07| -
| 2.09| 2.14| | -
| 2.10| 2.18| | -
| | | 2.03| -
| 2.01| 2.11| 2.15| -
| | 2.05| | -
| 2.02| 2.18| | -
+-----+-----+-----+
The box plots do not support the conclusion of the ANOVA test. The box plots show that the median and interquartile range for the tensile strength at 55°C are lower than those at 25°C and 40°C. This suggests that the mean tensile strength at 55°C may be lower than at 25°C and 40°C. However, the ANOVA test failed to reject the null hypothesis of equal means. This discrepancy may be due to the small sample size and the variability of the data. Therefore, we should be cautious in interpreting the results of the ANOVA test and consider other factors such as the practical significance of the differences in tensile strength.
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A lot contains 20 fuses of which are defective. If two fuses are selected at random without replacement, what is the probability that only one is defective? O 0.20 O 03947 O 0.0789 O 0.0263
To solve this problem, we can use the formula for probability of an event:
P(event) = (number of favorable outcomes) / (total number of outcomes)
Let's first find the total number of ways to select two fuses from 20:
20 choose 2 = 20! / (2! * (20-2)!) = 190
Now let's find the number of ways to select one defective fuse and one non-defective fuse:
There are 10 defective fuses and 10 non-defective fuses, so we can choose one of each in 10 * 10 = 100 ways.
Therefore, the probability of selecting only one defective fuse is:
P(1 defective) = 100 / 190 = 0.5263
So the answer is not one of the options given.
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Answer!!!!! Tysm!!!!
The angle measurement of the triangle would be 9. 59 degrees
How to determine the valueThe different trigonometric identities are given as;
sinetangentcotangentcosinesecantcosecantThe ratios of the trigonometric identities are represented as;
sin θ = opposite/hypotenuse
cos θ = adjacent/hypotenuse
tan θ = opposite/adjacent
From the information given, we have;
Opposite side = 1
Hypotenuse side = 6
Using the sine identity, we have;
sin θ = 1/6
Divide the values
sin θ = 0. 1666
Find the inverse of the sine
θ = 9. 59 degrees
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what is the quartile of 84,75,90,87,99,91,85,88,76,92,94
Answer: 84
Step-by-step explanation:
Sorry if this is wrong.
point) A spring with a 7-kg mass and damping constant can be held stretched meters beyond Its natural length by force of newtons. Suppose the spring is stretched meters beyond its natural length and then released with zero velocity; In the notation of the text; what Is the value c2 4mk? mekg? sec? Find the position of the mass_ in meters after seconds Your answer should be function of the variable with the general-
form G1eat cos( Bt) + ce" sin(St)
The value of c2 in the notation of the text is 4mk. The units of c2 are Ns/m.
To find the position of the mass after t seconds, we need to solve the differential equation:
m d^2x/dt^2 + c dx/dt + kx = 0
where m is the mass of the spring, c is the damping constant, k is the spring constant, and x is the position of the mass.
We can write the solution to this equation in the general form:
x(t) = G1eat cos( Bt) + ce" sin(St)
where a and B are constants that depend on the initial conditions of the system, and G1 and c are constants determined by those initial conditions.
To find the constants G1 and c, we need to use the initial conditions given in the problem: the spring is stretched 0.5 meters beyond its natural length and then released with zero velocity. This means that x(0) = 0.5 and dx/dt(0) = 0.
Substituting these initial conditions into the general solution, we get:
x(t) = G1e^(-ct/2m) cos( ωt) + c e^(-ct/2m) sin( ωt)
where ω = sqrt(k/m - c^2/4m^2) is the angular frequency of the motion.
To find the constants G1 and c, we differentiate x(t) with respect to time and use the initial condition dx/dt(0) = 0:
dx/dt = -G1c/2m e^(-ct/2m) sin( ωt) + c e^(-ct/2m) cos( ωt)
dx/dt(0) = 0 = c
Therefore, c = 0.
To find G1, we use the initial condition x(0) = 0.5:
x(0) = G1 cos(0) + 0 = G1 = 0.5
Therefore, the position of the mass after t seconds is:
x(t) = 0.5e^(-ct/2m) cos( ωt)
where c = 0 and ω = sqrt(k/m).
Plugging in the given values, we get:
x(t) = 0.5e^(-0t/2*7) cos( sqrt(40/7)t) = 0.5cos(2.226t)
So the position of the mass after t seconds is 0.5cos(2.226t) meters.
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The figure shows two kayakers pulling a raft. One kayaker pulls with a force vector F sub 1 equals open angled bracket 180 comma 160 close angled bracket comma and the other kayaker pulls with a force vector F sub 2 equals open angled bracket 123 comma negative 128 close angled bracket period
two vectors F sub 1 and F sub 2 that share an initial point located on a raft, F sub 1 points right and up where its terminal point is at a kayak, F sub 2 points left and down where its terminal point is at another kayak
What is the angle between the kayakers? Round your answer to the nearest degree.
80°
86°
88°
92°
The angle between the kayakers is approximately 92 degrees when rounded to the nearest degree.
The correct option is (D)
We have:
One kayaker pulls with a force vector F sub 1 equals open angled bracket 180 comma 160 close angled bracket comma and the other kayaker pulls with a force vector F sub 2 equals open angled bracket 123 comma negative 128 close angled bracket period.
F sub 1 dot F sub 2 = ||F sub 1|| ||F sub 2|| cos(theta)
where "dot" represents the dot product, "|| ||" represents the magnitude of the vector, and theta is the angle between the two vectors.
We have to find the magnitudes of the two vectors:
||F sub 1|| = [tex]\sqrt{180^2+160^2}=236.13[/tex]
||F sub 2|| = [tex]\sqrt{123^3+(-128)^2}=174.13[/tex]
Now, we have to find the dot product:
F sub 1 dot F sub 2 = (180)(123) + (160)(-128) = -49920
Now we can solve for the angle theta:
-49920 = (236.13)(174.13) cos(theta)
cos(theta) = -0.156
Using the inverse cosine function, we find that:
theta = 91.89 degrees
As a result, rounded to the nearest degree, the angle between the kayakers is approximately 92 degrees.
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f(x)= - 3(x - m)2 + pParabola vertical point T(2,5), how much m + p equal
If f(x)= - 3(x - m)2 + p Parabola vertical point T(2,5), then m + p is equal to 27.
Since the given parabola is vertical and has a vertex at T(2,5), we know that the equation is of the form f(x) = a(x-2)^2 + 5, where a is a constant.
We also know that f(x) = -3(x-m)^2 + p, which is in the same form as the first equation.
So, we can equate the two equations and get:
a(x-2)^2 + 5 = -3(x-m)^2 + p
Expanding the squares, we get:
a(x^2 - 4x + 4) + 5 = -3(x^2 - 2mx + m^2) + p
Simplifying and collecting like terms, we get:
ax^2 + (-4a + 6m)x + (4a - 3m^2 + p - 5) = 0
Since this equation must hold for all values of x, the coefficients of x^2 and x must be equal to zero.
Therefore, we have:
a = -3 (from the given equation f(x) = -3(x-m)^2 + p)
-4a + 6m = 0 (from the equation above)
-4(-3) + 6m = 0
12 + 6m = 0
m = -2
Substituting m = -2 and a = -3 into the equation above, we get:
4a - 3m^2 + p - 5 = 0
4(-3) - 3(-2)^2 + p - 5 = 0
-12 - 12 + p - 5 = 0
p = 29
Therefore, m + p = -2 + 29 = 27.
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how do you do this i dont understand ir
Answer: The answer is 2 and 3 or B and C which ever way you want it.
The reason its 2and3 is because you can see its 60 degree angle.
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The reason its 3 also is because they are all congruent and its the only other right answer that fits.
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Hence, The answer is 2 and 3 or B and C.
Step-by-step explanation: Please give Brainliest.
Hope this helps!!!!
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A pollster wants to construct a 99.8% confidence interval for the proportion of adults who believe that economic conditions are getting better. Part 1 of 2 (a) A poll taken in July 2010 estimates this proportion to be 0.31. Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.02
99.8% confidence interval with a margin of error of 0.02, using the estimated proportion of 0.31 from the previous poll.
To find the sample size needed to construct a confidence interval for a proportion with a specified margin of error, we use the following formula:
n = (z^2 * p * q) / E^2
where:
n is the sample size
z is the z-score corresponding to the desired level of confidence (99.8% in this case)
p is the estimated proportion from the previous poll (0.31 in this case)
q = 1 - p
E is the desired margin of error (0.02 in this case)
First, we need to find the value of z for a 99.8% confidence level. Using a standard normal distribution table, we can find that the z-score for a 99.8% confidence level is approximately 2.967.
Substituting the given values into the formula, we have:
n = (2.967^2 * 0.31 * 0.69) / 0.02^2
n = 1202.19
Rounding up to the nearest whole number, we need a sample size of n = 1203 to construct a 99.8% confidence interval with a margin of error of 0.02, using the estimated proportion of 0.31 from the previous poll.
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Due to a power outage, the sales clerk manually prepares a sale receipt to her customer. Which one of the following diagrams represents this activity?
a. trapezoid to curvy side rectangle to curved rectangle
b. curved side rectangle to circle to curved rectangle
c. circle to curved side rectangle to curved rectangle
d. trapezoid to curved side rectangle to circle
Based on the given options, the diagram that best represents the activity of a sales clerk manually preparing a sale receipt during a power outage would be option D.
A trapezoid could represent the shape of a receipt, a curved side rectangle could represent the shape of the clerk's desk or the paper she is using, and a circle could represent the shape of a calculator or cash register. Therefore, a trapezoid to a curved side rectangle to a circle could represent the process of the clerk manually calculating and recording the sale amount and inputting it into a calculator or cash register to produce a receipt.
It is important to note that during a power outage, technology-dependent activities such as electronic sales and transactions may be disrupted, and manual methods may have to be used as a backup. This highlights the power of technology in our daily lives and the impact that power outages can have on businesses and individuals.
The question is about selecting the correct diagram that represents the sales clerk manually preparing a sale receipt due to a power outage. Given the options:
a. trapezoid to curvy side rectangle to curved rectangle
b. curved side rectangle to circle to curved rectangle
c. circle to curved side rectangle to curved rectangle
d. trapezoid to curved side rectangle to circle
The appropriate answer for this question cannot be determined based on the provided information. Diagrams typically require visual representation, and the description of the shapes alone is insufficient to convey the activity of preparing a receipt manually. Moreover, the terms "power," "outage," "clerk," "receipt," "trapezoid," "curved," and "curved" don't necessarily correspond to the shapes given in the options.
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