Adeline had a box full of notebooks. If she gives 13 notebooks to each

Given the set 5, 8, 8, 8, 8, 9, 9, 9,  10, & 10. Calculate the mean which is the average of a given data set.

[tex]\bold{Mean}=\frac{Sum \ of \ all \ Data \ Points }{The \ Amount \ of \ Data \ Points \ you \ have}[/tex]

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

[tex]\bold{Mean}=\frac{5+8+8+8+8+9+9+10+10 }{10}[/tex]

[tex]\Longrightarrow \bold{Mean}=\frac{75 }{10}[/tex]

[tex]\Longrightarrow \bold{Mean}=7.5[/tex]

[tex]\Longrightarrow \boxed{\bold{Mean} \approx 8} \therefore Sol.[/tex]

The surface area of the prism is determined as 300 yd².

The surface area of the prism is calculated as follows;

S.A = bh + (s₁ + s₂ + s₃)L

where;

The surface area of the prism is calculated as;

S.A = 5 (12) + (5 + 12 + 13) x 8

S.A = 60 yd² + 240 yd²

S.A = 300 yd²

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Answer:

y = 3x - 3

Step-by-step explanation:

(You should write this down just in case)

Write the slope formula:

m = [tex]\frac{y2 - y1}{x2 - x1}[/tex]

Substitute and Calculate:

[tex]x_{1}[/tex] = 3

[tex]x_{2}[/tex] = -1

[tex]y_{1}[/tex] = 6

[tex]y_{2}[/tex] = -6

^ Substitution

m = [tex]\frac{-6 - 6}{-1 - 3}[/tex]

m = [tex]\frac{-12}{-4}[/tex]

m = [tex]\frac{12}{4}[/tex]

m = 3

^ Calculation

Substitute and Calculate:

m = 3

x = 3       <<into y = mx + b

y = 6

6 = 9 + b

-b = 9 - 6

-b = 3

b = -3

^ Calculation

Substitute:

y = 3x - 3

m = 3

^Into y = mx + b

y = 3x - b

The distance from the zebra habitat to the giraffe habitat is approximately 77.2 meters.

The similarity of triangles states that the ratio of the two sides of the triangles will be constant.

Since the triangles are similar, apply the proportional theorem and calculate the distance d from the Zebra habitat to the Giraffe.

Using the values from the figure:

(d + 386) / d = 360 / 60

Simplify the equation written below,

d + 386 = 6d

5d = 386

d = 77.2

Therefore, the distance from the zebra habitat to the giraffe habitat is approximately 77.2 meters, rounded to the nearest tenth.

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The probability of a standard normal variable being less than -2.65 is 0.0040. Therefore, P(x < 979) = 0.0040.

To solve this problem, we use the central limit theorem since we have a large enough sample size.

a) Probability that a single randomly selected value is less than 979 dollars

To find the probability that a single randomly selected value is less than 979 dollars, we standardize the value and use the standard normal distribution:

z = (979 - 1046) / 206 = -0.3233

Using a standard normal distribution table or calculator, we find that the probability of a standard normal variable being less than -0.3233 is 0.3736. Therefore, P(X < 979) = 0.3736.

b) Probability that a sample of size n = 66 is randomly selected with a mean less than 979 dollars

To find the probability that a sample of size n = 66 is randomly selected with a mean less than 979 dollars, we use the central limit theorem.

The mean of the sampling distribution of the sample means is the same as the population mean, which is 1046 dollars. The standard deviation of the sampling distribution of the sample means is the standard error, which is:

SE = σ / sqrt(n) = 206 / sqrt(66) = 25.23

To standardize the sample mean, we use the formula:

z = (x - μ) / SE = (979 - 1046) / 25.23 = -2.65

Using a standard normal distribution table or calculator, we find that the probability of a standard normal variable being less than -2.65 is 0.0040. Therefore, P(x < 979) = 0.0040.

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The Intermediate Value Theorem does not conclude the value of the function at any specific point within the interval. It only guarantees the existence of at least one point where the function takes on a certain value within the given interval.

The Intermediate Value Theorem (IVT) states that if a continuous function, f(x), is defined on a closed interval [a, b] and k is a value between f(a) and f(b), then there exists at least one value c in the interval (a, b) such that f(c) = k.

However, the Intermediate Value Theorem does not conclude the following:

1. The existence of a unique value c: There may be multiple values in the interval (a, b) that satisfy f(c) = k.

2. That the function is differentiable or continuous outside the interval [a, b].

3. That the function has a local maximum or minimum value within the interval [a, b].

In summary, the Intermediate Value Theorem only guarantees the existence of at least one point where the function equals a specified value within a given interval, but it does not provide information about the uniqueness of that point, differentiability, or the presence of local extrema.

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The correct option is D. 1/4 of the distance from A to B.

D. 1/4 of distance from A to B.

The potential energy of a spring varies with the displacement of the object from its equilibrium position. At the equilibrium position, the potential energy is at a minimum, and the kinetic energy is at its maximum. As the object moves away from the equilibrium position, the potential energy increases and the kinetic energy decreases until the object reaches the maximum displacement point, where the potential energy is at a maximum and the kinetic energy is at a minimum.

In the case of a vertical spring, the equilibrium position is the midpoint between the two extreme points, A and B. At this point, the object has zero potential energy and maximum kinetic energy. As the object moves away from the equilibrium position towards point A, its potential energy increases and its kinetic energy decreases until it reaches point A, where the potential energy is at a maximum and the kinetic energy is at a minimum. Therefore, the object is located at point A when the kinetic energy is at a minimum.

Since the spring is ideal and massless, the potential energy is proportional to the square of the displacement from the equilibrium position. The kinetic energy is proportional to the square of the velocity of the object. At point A, the velocity of the object is zero, and hence the kinetic energy is at a minimum. Therefore, the object is located at point A when the kinetic energy is a minimum.

The distance from A to B is divided into four equal parts, and the object is located at the first quarter point from A to B, which is 1/4 of the distance from A to B. Therefore, the correct option is D. 1/4 of the distance from A to B.

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The five-number summary for the data set is:

Minimum value = 10

Q1 = 14

Median = 18.5

Q3 = 24

Maximum value = 28.

The box and whisker plot is given.

We have,

To find the five-number summary, we need to first sort the data set in ascending order:

10, 12, 14, 15, 16, 18, 22, 24, 25, 28

Minimum value:

The smallest value in the data set is 10, so this is the minimum value.

Q1 (first quartile):

This is the value that separates the bottom 25% of the data from the top 75%.

To find Q1, we need to find the median of the lower half of the data.

The lower half of the data consists of the values 10, 12, 14, 15, and 16.

The median of these values is 14, so Q1 is 14.

Median (Q2):

This is the value that separates the bottom 50% of the data from the top 50%.

To find the median, we take the average of the two middle values.

The middle values are 18 and 19, so the median is (18+19)/2 = 18.5.

Q3 (third quartile):

This is the value that separates the bottom 75% of the data from the top 25%.

To find Q3, we need to find the median of the upper half of the data.

The upper half of the data consists of the values 22, 24, 25, and 28.

The median of these values is 24, so Q3 is 24.

Maximum value:

The largest value in the data set is 28, so this is the maximum value.

Therefore,

The five-number summary for the data set are minimum value = 10,

Q1 = 14, median = 18.5, Q3 = 24, maximum value = 28.

The box and whisker plot is given.

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The equation when solved for x gives x = √3 - 5y

It is important to note that the subject of formula in an equation is the variable that is being worked out.

This variable is made to stand alone on one end of the equality sign.

From the information given, we have the equation;

y = 3√(x²+3)÷15

cross multiply the values

15y = 3√(x²+3)

Divide both sides by the coefficient of √(x²+3)

15y/3 = √(x²+3)

Divide the values

5y = √(x²+3)

Find the square of both sides

25y² = x² + 3

collect terms

x² = 3 - 25y²

Find the square root

x = √3 - 5y

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The length of the line segment AC is 25.5 cm.

A line segment in geometry is a section of a line that has two clearly defined ends as its boundaries. It may be compared to a straight line that has two points where it begins and ends. Letters or points on the line, such as A and B, are frequently used to represent the two ends of a line segment. In contrast to a line, which extends forever in both directions, a line segment has a limited length. A ruler or other measuring device can be used to determine the length of a line segment.

To find the length of segment AC, we can use the fact that the sum of the lengths of two segments on a line is equal to the length of the entire line. That is:

AB + BC = AC

Substituting the given values, we get:

12 cm + 13.5 cm = AC

Simplifying:

AC = 25.5 cm

Therefore, the length of segment AC is 25.5 cm.

There is only one possible answer for the length of segment AC since it is uniquely determined by the lengths of segments AB and BC.

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The function for the area of the campsite in terms of x only is A(x) = 60x - x^2.

1. We need to find the equation for the area and the length of the caution tape in terms of x:
a. The area of the campsite can be represented by the equation A = xy, where A is the area, and x and y are the dimensions of the campsite.
b. The length of the yellow caution tape can be represented by the equation L = 2x + 2y, where L is the length of the tape, and x and y are the dimensions of the campsite. In this case, L = 120 feet.

2. The constraint equation is L = 2x + 2y = 120 feet. This is because without this constraint, the dimensions x and y could be infinitely large, resulting in an infinitely large campsite.

3. To generate a new equation for the area of the campsite in terms of x only, we can solve the constraint equation for y and substitute it into the area equation:
L = 2x + 2y = 120
2y = 120 - 2x
y = (120 - 2x)/2 = 60 - x

Now substitute this expression for y into the area equation:
A(x) = x(60 - x) = 60x - x^2

So, the function for the area of the campsite in terms of x only is A(x) = 60x - x^2.

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The producers' surplus if the market price is set at the equilibrium price is $38.33.

The producers' surplus is calculated from the quantity supplied at equilibrium as shown below;

-0.01x² − 0.2x + 11 = 0.01x² + 0.3x + 4

-0.02x² - 0.5x + 7 = 0

solve the quadratic equation using formula method as follows;

x = -35 or 10

So we take only the positive quantity supplied.

Integrate the function from 0 to 10;

∫-0.02x² − 0.5x + 7 = [-0.00667x³ - 0.25x² + 7x]

= [-0.00667(10)³ - 0.25(10)² + 7(10)] - [-0.00667(0)³ - 0.25(0)² + 7(0)]

= -6.67 - 25 + 70

= $38.33

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The first function is the correct option, it is:

f(x) = (x² - 36)/(x - 6)

We know that the domain of the function f(x) is (-∞, ∞).

So our function has no jumps, meaning that the denominator never is equal to zero.

So any of the options where the denominator can't be removed can be igonerd.

the first function is:

f(x) = (x² - 36)/(x - 6)

You can rewrite the numerator as:

(x - 6)*(x + 6)

REplacing that you will get.

f(x) = [(x - 6)*(x + 6)]/(x -6) = x + 6

So the denominator was removed, then the domain is (-∞, ∞).

This is the correct option.

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The component form of vector v is ((9√6+3√2)/2, (9√6-3√2)/2).

To get the component form of a vector given its magnitude and direction angle, we can use the following formulas:
v = ||v|| [cos(Ɵ)i + sin(Ɵ)j]
where v is the vector in component form, ||v|| is the magnitude of the vector, Ɵ is the direction angle in degrees, and i and j are the unit vectors in the x and y directions, respectively.
Step:1. For |v|=20 and Ɵ = 60o, we have:
v = 20 [cos(60o)i + sin(60o)j]
 = 20 [(1/2)i + (√3/2)j]
 = 10i + 10√3j
Therefore, the component form of vector v is (10, 10√3).
Step:2. For |v|=12 and Ɵ = 125o, we have:
v = 12 [cos(125o)i + sin(125o)j]
 = 12 [(-√2/2)i + (√2/2)j]
 = -6√2i + 6√2j
Therefore, the component form of vector v is (-6√2, 6√2).
Step:3. For |v|=18 and Ɵ = 75o, we have:
v = 18 [cos(75o)i + sin(75o)j]
 = 18 [(√6+√2)/4)i + (√6-√2)/4)j]
 = (9√6+3√2)/2)i + (9√6-3√2)/2)j
Therefore, the component form of vector v is ((9√6+3√2)/2, (9√6-3√2)/2).

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The area of the rectangle is 3/8 square units.

Multiplying 1/2 by 3/4 gives us: (1/2) x (3/4) = 3/8. This means that if we have a rectangle with a length of 1/2 and a width of 3/4, the area of the rectangle is 3/8.

To calculate the area of a rectangle, we use the formula A = lw, where A represents the area, l represents the length, and w represents the width. So, if we plug in the values for length and width, we get:

A = (1/2) x (3/4) = 3/8

Area = (1/2) x (3/4) = 3/8 square units.

Therefore, the area of the rectangle is 3/8 square units.

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Complete Question:

Multiply 1/2 and 3/4 and figure out the area of the rectangle.

When applying the multiplication and division rules for exponents, it is important to remember that the rules apply only when the bases of the exponents are equivalent. So, correct option is C.

In other words, the bases must be the same number or variable. The multiplication rule for exponents states that when you multiply two numbers with the same base, you can add their exponents. For example, if you have 2² × 2³, you can simplify it to 2²⁺³ = 2⁵ = 32. However, if the bases are different, you cannot apply this rule.

The division rule for exponents states that when you divide two numbers with the same base, you can subtract their exponents. For example, if you have 5⁴ ÷ 5², you can simplify it to 5⁴⁻² = 5² = 25. Again, this rule can only be applied when the bases are the same.

In summary, when applying the multiplication and division rules for exponents, you must ensure that the bases are equivalent. If the bases are different, the rules cannot be applied.

Therefore, option c is the correct answer.

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The bush is 26.4 inches tall after 2 weeks. This means it has grown by 14.4 inches since it was first planted and the percentage increase is 120%

To calculate the height of the bush after 2 weeks, we can use the following formula:

New height = initial height + (percent increase/100) * initial height

In this case, the initial height of the bush is 12 inches, and the percent increase is 120%. Plugging in these values, we get:

New height = 12 + (120/100) * 12

New height = 12 + 14.4

New height = 26.4 inches

Therefore, the bush is 26.4 inches tall after 2 weeks. This means it has grown by 14.4 inches since it was first planted.

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Based on the information provided, 90% of wildfires being "human caused" means that these wildfires are initiated or influenced by human activities, rather than natural causes. This does not necessarily imply arson, as there are various other ways in which humans can unintentionally start or contribute to wildfires.

Some specific examples of human-caused wildfires include:

1. Unattended campfires: When people leave campfires without properly extinguishing them, the fire can spread to nearby vegetation and ultimately result in a wildfire.
2. Burning debris: People may burn yard waste or other materials without proper safety measures, which can lead to wildfires if the fire is not contained or controlled.
3. Discarded cigarettes: Carelessly thrown cigarette butts can ignite dry vegetation and start a wildfire.
4. Equipment use: Sparks from power tools or vehicles, such as chainsaws, lawnmowers, or off-road vehicles, can ignite dry vegetation and cause wildfires.
5. Power lines: Falling or damaged power lines can spark and ignite a wildfire.

While arson is one potential cause of human-caused wildfires, it is important to recognize that there are many other factors and activities that contribute to the majority of these fires. By understanding these causes, we can take preventive measures and reduce the occurrence of wildfires.

For more information and support, you can refer to this National Park Service article on human-caused wildfires: [Human-Caused Wildland Fires](https://www.nps.gov/articles/human-caused-wildland-fires.htm).

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The answer is (b) x+y=C.

The given equation is [tex]xdy + ydx = 0.[/tex]

We can rewrite this equation as:

dy/dx = -y/x

This is a first-order linear differential equation that can be solved using separation of variables.

We can write it as:

dy/y = -dx/x

Integrating both sides, we get:

ln|y| = -ln|x| + ln|C|

where C is the constant of integration.

Simplifying this expression, we get:

ln|y| = ln|C/x|

Taking the exponential of both sides, we get:

|y| = |C/x|

Since |C| is a constant, we can replace it with another constant, say k, giving:

|y| = k/|x|

where k is a non-zero constant.

Now, we can rewrite this expression as:

y = ± k/x

where the ± sign depends on the sign of y.

Therefore, the solution to the differential equation xdy + ydx = 0 is y = ± k/x.

We can rewrite this solution in different forms:

a) y = Cx, where C = ± k

b) x + y = C, where C = k/2

c) xy = C, where C = ± k^2

d) x = Cy, where C = ± k

Therefore, the answer is (b) x+y=C.

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The approximate distance between Earth and the Andromeda galaxy is 2,500,000 x 365 x 24 x 3,600 x 300,000 km.

To calculate the approximate distance between Earth and the Andromeda galaxy, you should use the given distance in light years, the number of days in a year, the speed of light, and the conversion from days to seconds. Here's the step-by-step explanation:

1. You know that the distance is 2.5 million light years or 2,500,000 light years.
2. One year has 365 days.
3. The speed of light is 300,000 km/second.
4. One day has 24 hours, and one hour has 3,600 seconds.

Now, you can calculate the distance:

Distance = (2,500,000 light years) x (365 days/year) x (24 hours/day) x (3,600 seconds/hour) x (300,000 km/second)
This matches option D.

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The complex number can be written in polar form as 2 + ((2+m) + 3i) = √(m² + 6m + 25)∠tan⁻¹(3/(2+m)).

What is complex number?

A complex number is obtained by adding real and imaginary numbers. Complex numbers have the formula a + ib and are usually symbolized by the symbol z. Here the numbers a and real are both. The value "a" is known as the real component and is denoted Re(z), while "b" is known as the imaginary part and is denoted Im(z). Also known as imaginary number, ib. Hero of Alexandria, a Greek mathematician, first used the idea of complex numbers in the first century when he tried to calculate the square root of a negative integer.

a. A complex number is a number that consists of a real part and an imaginary part, where the imaginary part is the real number multiplied by the imaginary unit "i", defined as the square root of -1. The modulus of a complex number is the distance between the starting point and the point representing the complex number on the complex plane. This can be calculated using the Pythagorean theorem. For example, the real part of the complex number z = 3 + 4i is 3 and the imaginary part is 4, and its modulus is √(3²+4²)=5.

b. Let z = a + bi be a complex number, where a and b are real numbers. The modulus of z is defined as |z| = √(a² + b²). Therefore, for the complex number z = 1 + 2i, the modulus is |z| = √(1² + 2²) = √5.

c. To write the complex number 2 = ((2+ m) + 3i) in polar form, we need to find the modulus and argument of the complex number. The modulus is |2 + ((2+m) + 3i)| = |4 + mi + 3i| = √(4² + (m+3)²) = √(m² + 6m + 25). The argument is given by tan⁻¹(Im/Re) = tan⁻¹(3/(2+m)), which gives us the angle that the complex number makes with the positive real axis. Therefore, the complex number can be written in polar form as 2 + ((2+m) + 3i) = √(m² + 6m + 25)∠tan⁻¹(3/(2+m)).

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The value of b as shown from the steps below is -21.

An equation is an expression that can be used to show the relationship between two or more numbers and variables using mathematical operators.

Given the equation:

4(b + 5) = 3b - 1

Opening the parenthesis:

4b + 20 = 3b - 1

Subtracting 3b from both sides:

b + 20 = -1

Subtracting 20 from both sides:

b = -21

The value of b is -21.

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y = -4 (1+x)^1.5 * cos[log(1+x)] + 6 (1+x)^1.5 * sin[log(1+x)] / e

To solve the differential equation:

(1+x) * dy/dx + y = 4 sin[log(1+x)]

We first need to find the integrating factor, which is given by:

μ(x) = e^(∫(1+x)dx) = e^(x + 0.5x^2)

Multiplying both sides of the differential equation by the integrating factor, we get:

e^(x+0.5x^2) * (1+x) * dy/dx + e^(x+0.5x^2) * y = 4 e^(x+0.5x^2) * sin[log(1+x)]

The left-hand side can be simplified using the product rule:

d/dx [e^(x+0.5x^2) * y] = e^(x+0.5x^2) * (1+x) * dy/dx + e^(x+0.5x^2) * y'

Substituting this into the differential equation and rearranging, we get:

d/dx [e^(x+0.5x^2) * y] = 4 sin[log(1+x)] * e^(x+0.5x^2)

Integrating both sides with respect to x, we get:

e^(x+0.5x^2) * y = ∫ 4 sin[log(1+x)] * e^(x+0.5x^2) dx

We can evaluate the integral on the right-hand side using substitution, letting u = log(1+x), du/dx = 1/(1+x), and dx = e^u du:

∫ 4 sin[log(1+x)] * e^(x+0.5x^2) dx = ∫ 4 sin(u) * e^(u-0.5u^2+u) du

= ∫ 4 sin(u) * e^(1.5u-0.5u^2) du

We can now use integration by parts, letting u = sin(u), dv = e^(1.5u-0.5u^2) du:

∫ 4 sin(u) * e^(1.5u-0.5u^2) du = -4 e^(1.5u-0.5u^2) cos(u) + 6 ∫ e^(1.5u-0.5u^2) cos(u) du

Using integration by parts again, letting u = cos(u), dv = e^(1.5u-0.5u^2) du:

∫ e^(1.5u-0.5u^2) cos(u) du = e^(1.5u-0.5u^2) sin(u) + ∫ e^(1.5u-0.5u^2) sin(u) du

Using these results to evaluate the integral on the right-hand side of the differential equation, we get:

e^(x+0.5x^2) * y = -4 e^(1.5log(1+x)-0.5log^2(1+x)) * cos[log(1+x)]

+ 6 e^(1.5log(1+x)-0.5log^2(1+x)) * sin[log(1+x)]

+ C

where C is the constant of integration. Simplifying, we get:

y = -4 (1+x)^1.5 * cos[log(1+x)] + 6 (1+x)^1.5 * sin[log(1+x)] / e

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The area of the circles are calculated below.

The area of a circle is given by the formula:

A = πr²

Where r is the radius of the circle

No. 1

r = 0.7 in

A = π * 0.7² = 0.49π in²

No. 2

r = 1.0/2 = 0.5 in

A = π * 0.5² = 0.25π in²

No. 3

r = 1.6/2 = 0.8 in

A = π * 0.8² = 0.64π in²

No. 4

r = 0.4/2 = 0.2 in

A = π * 0.2² = 0.04π in²

No. 5

r = 0.3 yd

A = π * 0.3² = 0.09π yd²

No. 6

r = 0.9 ft

A = π * 0.9² = 0.81π ft²

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From the two column proof below we have been able to show that:

WZ bisects ∠YWX

A two-column proof uses a table to present a logical argument and assigns each column to do one job, and then the two columns work in lock-step to take a reader from premise to conclusion.

The two column proof here is:

Statement 1: WY ≅ WX, zy ≅ zx

Reason 1: Given

Statement 2: ∠WYX ≅ ∠WXY, ∠3 ≅ ∠4

Reason 2: Base angles of Isosceles triangles are congruent

Statement 3: m∠WYX = m∠WXY

Reason 3: Measures of congruent angles are equal

Statement 4: m∠WYX = m∠6 + m∠3: m∠WXY = m∠5 + m∠4

Reason 4: Angle Addition Postulate

Statement 5: m∠6 + m∠3 = m∠5 + m∠4

Reason 5: Substitution

Statement 6: m∠6 + m∠3 = m∠5 + m∠3

Reason 6: Substitution

Statement 7: m∠6 = m∠5

Reason 7: Subtraction Property of equality

Statement 8: ΔWYZ ≅ ΔWXZ

Reason 8: SAS

Statement 9: ∠YWZ ≅ ∠XWZ

Reason 9: Corresponding parts of congruent triangles are congruent.

Statement 10: WZ bisects ∠YWX

Reason 10: Definition of angle bisector

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The measure of CFE is 28^o.

When the measures of two or more angles add up to the sum of angle on a straight line i.e. 180^o, then the set of angles are said to be supplementary.

Given point F on line CD in the question, we have;

<CFE + <DFE = 180^o  (definition of supplementary angles)

So that;

<CFE + 152 = 180

<CFE = 180 - 152

         = 28

<CFE = 28^o

Therefore, the measure of <CFE is 28^o.

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a)  The bias does not approach zero as A approaches infinity, e^-X is not asymptotically unbiased.

b)  if Y₁ is the best unbiased estimator of P(X=0), we need to compare its MSE with the MSE of any other unbiased estimator.

c) in terms of MSE, Y₁ is better than e^-X with n = 10 and λ = 1.

(a) To check if e^-X is an unbiased estimator of P(X=0), we need to calculate its expected value and check if it is equal to P(X=0).

The moment generating function of Poi(A) is M(t) = exp(A(e^t -1)), and the moment generating function of -X is M(-t) = exp(A(1 - e^t)).

Using the moment generating function of -X, we can calculate the expected value of e^-X as follows:

E(e^-X) = E(exp(-X log(e))) = M(-log(e)) = exp(A(1 - e^-1))

Now, we need to check if E(e^-X) = P(X=0). Since P(X=0) = exp(-A), we can see that the estimator e^-X is biased. The bias is given by B(e^-X) = E(e^-X) - P(X=0) = exp(A(1-e^-1)) - exp(-A).

To check if the bias is asymptotically unbiased, we need to take the limit as A approaches infinity.

lim(A → ∞) B(e^-X) = lim(A → ∞) exp(A(1-e^-1)) - exp(-A) = ∞

Since the bias does not approach zero as A approaches infinity, e^-X is not asymptotically unbiased.

To check if e^-X is the best unbiased estimator of P(X=0), we need to compare its mean squared error (MSE) with the MSE of any other unbiased estimator.

(b) Y₁ is an unbiased estimator of P(X=0) if P(Y₁ = 1) = P(X=0) and P(Y₁ = 0) = 1 - P(X=0). Since Y₁ Ber(P(X=0)), we have

P(Y₁ = 1) = P(X=0) and P(Y₁ = 0) = 1 - P(X=0), which means that Y₁ is an unbiased estimator of P(X=0).

The bias of Y₁ is zero, so it is unbiased and there is no need to check if it is asymptotically unbiased. To check if Y₁ is the best unbiased estimator of P(X=0), we need to compare its MSE with the MSE of any other unbiased estimator.

(c) Using the fact that E(Xi) = λ and Var(Xi) = λ, we can calculate the MSE of e^-X and Y₁ as follows:

MSE(e^-X) = E((e^-X - P(X=0))^2) = Var(e^-X) + B(e^-X)^2 = exp(A(e^-1 - 2)) + (exp(A(1-e^-1)) - exp(-A))^2 - exp(-2A)

MSE(Y₁) = E((Y₁ - P(X=0))^2) = Var(Y₁) = P(X=0)(1-P(X=0)) = exp(-λ)(1-exp(-λ))

Substituting n = 10 and λ = 1, we get:

MSE(e^-X) ≈ 0.1381 + (exp(9)(1-e^-9))^2 - exp(-2) ≈ 1.3869

MSE(Y₁) ≈ exp(-1)(1-exp(-1)) ≈ 0.3935

Therefore, in terms of MSE, Y₁ is better than e^-X with n = 10 and λ = 1.

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The probability of selecting an even number card is: 50%

The number of the cards are given as:

4, 5, 6 and 7

Now, an even number are defined as any number that can be exactly divided by 2. Even numbers always end up with the last digit as 0, 2, 4, 6 or 8. Some examples of even numbers are 2, 4, 6, 8, 10, 12, 14, 16.

A number which is not divisible by “2” is called an odd number. An odd number always ends in 1, 3, 5, 7, or 9. Examples of odd numbers: 51 , − 543 , 8765 , − 97 , 9 , etc.

Thus, we have 4 cards and the even number are 2. Thus:

P(even) = 2/4 = 0.5

= 50%

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