Although you inherited one chromosome of each pair from your mother and your father, you have inherited a group of genes from your mother only. What genes are these?

Our primary weapon against infectious diseases is vaccines. Vaccines are a type of medical intervention that can help prevent the spread of infectious diseases by triggering an immune response in the body that protects against future infections.

When a vaccine is administered, it typically contains a weakened or inactivated form of the virus or bacteria that causes the disease. This allows the body's immune system to recognize and build immunity to the disease, without causing illness.

English physician Edward Jenner invented the first vaccine in 1796. He noticed that milkmaids who had the comparatively mild sickness known as cowpox appeared to be immune to the far more serious and fatal disease known as smallpox. An 8-year-old youngster was given the cowpox virus by Jenner after he collected a sample from a milkmaid. The youngster experienced a slight case of cowpox but rapidly recovered. The boy was then exposed to smallpox by Jenner, but he escaped infection. The first vaccine and the idea of vaccination were both developed as a result of this experiment.

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Answer:

Explanation:

To calculate the environmental variance, genetic variance, and broad-sense heritability, we can use the following formulas:

Vp = Vg + Ve (where Vp is the phenotypic variance, Vg is the genetic variance, and Ve is the environmental variance)

H^2 = Vg/Vp (where H^2 is the broad-sense heritability)

Given that the mean number of abdominal bristles in the F1 generation is 20, and the standard deviation is 2, we can calculate the phenotypic variance as:

Vp = (2^2) = 4

Since the F1 generation is a result of a cross between two inbred lines, we can assume that all of the genetic variation in the F1 generation is due to dominance effects, and the genetic variance in the F1 generation is zero.

Therefore,

Vp = Vg + Ve

4 = 0 + Ve

Ve = 4

To calculate the broad-sense heritability, we can use the formula:

H^2 = Vg/Vp

Since Vg is zero in the F1 generation, the broad-sense heritability for this generation is also zero.

Moving on to the F2 generation, we are given that the mean number of abdominal bristles is 20, and the standard deviation is 3. We can calculate the phenotypic variance as:

Vp = (3^2) = 9

To calculate the genetic variance, we can use the formula:

Vg = Vp - Ve

We know that Ve is 4, so:

Vg = 9 - 4 = 5

To calculate the broad-sense heritability, we can use the formula:

H^2 = Vg/Vp

H^2 = 5/9

H^2 = 0.56 (rounded to two decimal places)

Therefore, the environmental variance is 4, the genetic variance is 5, and the broad-sense heritability is 0.56 for bristle number in this population.

Model 1 illustrates an inducible operon. The lac operon consists of three genes which are lacZ, lacY, and lacA.

It is also known as the lac operon, which is involved in the metabolism of lactose in prokaryotes. , that encode for proteins involved in the breakdown of lactose. In addition to the three genes, the lac operon contains regulatory elements, including the promoter, operator, and regulatory gene.

Other than the regulatory gene, the lac operon contains three structural genes, lacZ, lacY, and lacA, which are involved in the metabolism of lactose.

In Model 1, RNA polymerase binds to the promoter region, which is located upstream of the lac operon. The operator region, located downstream of the promoter and upstream of the structural genes, serves as a binding site for the repressor protein that inhibits the transcription of the lac operon. The terminator region, located downstream of the structural genes, serves as a signal for the termination of transcription.

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The approximate population size of raccoons in the neighborhood, using the Lincoln-Petersen Index formula, is 48.

To estimate the approximate population size of raccoons in your neighborhood using the catch-and-release method, we need to follow these steps:

Step 1: Record the number of raccoons marked in the first sample. In this case, you marked 12 raccoons.

Step 2: Record the total number of raccoons caught in the second sample. In this case, you caught 16 raccoons.

Step 3: Record the number of marked raccoons in the second sample. In this case, there are 4 marked raccoons.

Step 4: Use the Lincoln-Petersen Index formula to estimate the population size. The formula is:

Population Size = (Number of raccoons marked in the first sample * Total number of raccoons caught in the second sample) / Number of marked raccoons in the second sample

Step 5: Plug the numbers into the formula:

Population Size = (12 * 16) / 4

Step 6: Calculate the population size:

Population Size = 192 / 4

Population Size = 48

Therefore, the approximate population size of raccoons in the neighborhood is 48.

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The aldehyde substrate derivative that specifically inhibits elastase forms a covalent bond with a serine residue in the active site of elastase.

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Answer: plasma

Explanation:

Answer:

A substitution mutation is a type of genetic mutation where one base pair in the DNA sequence is replaced with a different base pair. This can result in a change in the amino acid sequence of the protein that is translated from the DNA sequence. If the substitution mutation occurs in a non-coding region of the DNA, it may not have any effect on the organism.

On the other hand, a frameshift mutation is a type of genetic mutation where one or more base pairs are inserted or deleted from the DNA sequence. This can shift the reading frame of the DNA sequence, changing the way that the sequence is translated into amino acids. This can result in a completely different protein being produced, or a protein that is missing critical parts or has extra parts that don't function properly.

In general, frameshift mutations are likely to be more dangerous to an organism than substitution mutations. This is because frameshift mutations can result in a completely different protein being produced, or a protein that is missing critical parts or has extra parts that don't function properly. This can have a significant impact on the function of the protein, which can in turn impact the health and survival of the organism. Substitution mutations, on the other hand, may result in a change to a single amino acid in the protein, which may or may not have a significant impact on its function.

However, it is important to note that the impact of a mutation on an organism depends on a variety of factors, including the location of the mutation, the function of the protein that is affected, and the specific genetic and environmental context in which the organism exists. Therefore, it is not always the case that frameshift mutations are more dangerous than substitution mutations, and the impact of a particular mutation must be evaluated on a case-by-case basis.

Rigor mortis is the stiffening of a body after death that occurs when myosin binds to actin but cannot unbind. What prevents myosin from unbinding is the lack of energy required to separate the two molecules.

Rigor mortis is the stiffening of a body after death that occurs when myosin binds to actin but cannot unbind. The process of rigor mortis is due to the lack of energy. This lack of energy is due to the depletion of adenosine triphosphate (ATP) in the body after death.

ATP is necessary for the energy production needed to separate the molecules. Without ATP, the myosin heads cannot detach from the actin filaments, leading to stiffness. In muscles, energy is required for muscle contraction, which is usually provided by ATP. When the person dies, their cells no longer produce ATP, causing the muscles to become locked up and immobile.

Thus, it can be concluded that the lack of ATP is what prevents myosin from unbinding.

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Gastrulation in echinoderms, amphibians, and birds is accomplished through the invagination of different cells.

In general, gastrulation is the process that reorganizes cells to form the three germ layers, which are necessary for the further development of an organism.

Gastrulation is the process in which cells rearrange to form the three germ layers: the ectoderm, mesoderm, and endoderm.

In echinoderms, gastrulation is accomplished through the process of archenteron formation, which is when the mesoderm forms from the invagination of cells from the surface of the embryo.

In amphibians, gastrulation is accomplished through blastopore closure, which is when the opening at the blastula stage of the embryo closes.

In birds, gastrulation is accomplished through the formation of the primitive streak, which is when the ectoderm folds and inwards to form a groove-like structure.

In summary, gastrulation is the first step of morphogenesis, the development of form and structure, which will determine the shape of the organism. The three germ layers will further differentiate and develop into the organs, tissues, and cells that make up the organism.

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The general architecture of RNA-dependent RNA polymerase (RdRp) supports the specific polymerization of nucleotide triphosphates (NTPs) to a growing RNA chain through its structural and functional properties. RdRp is an enzyme that catalyzes the synthesis of RNA from an RNA template, playing a crucial role in the replication of RNA viruses.

The architecture of RdRp consists of a conserved structure resembling a right hand, with three domains: fingers, palm, and thumb. The fingers and thumb domains hold the RNA template, while the active site is located within the palm domain. This active site is responsible for the polymerization of NTPs.

RdRp recognizes and binds to specific sequences on the RNA template, ensuring the correct positioning of NTPs for polymerization. The enzyme undergoes conformational changes upon binding the RNA template, facilitating the formation of a catalytically active complex.

The specificity of RdRp for NTPs is primarily determined by the shape and electrostatic properties of the active site. The enzyme has a unique mechanism to discriminate between NTPs, allowing the incorporation of only the correct complementary NTPs into the growing RNA chain. The enzyme's fidelity is crucial for maintaining the integrity of the synthesized RNA.

In conclusion, the general architecture of RdRp enables the specific polymerization of NTPs to a growing RNA chain through its conserved structural domains, recognition of the RNA template, and active site properties. This ensures the accurate and efficient synthesis of RNA, critical for the replication of RNA viruses.

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If pure water and a solution containing a nonpenetrating solute are separated by a membrane that is permeable only to water, osmosis will occur.

Osmosis is the movement of water molecules across a membrane in order to equalize the solute concentration on either side. As the solute molecules are unable to pass through the membrane, only the water molecules are allowed to pass. This results in the transfer of water molecules from the pure water to the solution containing a nonpenetrating solute, thus increasing the solute concentration on the pure water side and decreasing the concentration on the other side. In the end, equilibrium is achieved and the water molecules will stop moving.

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The red portion of the human lip is known as the mucous membrane. It does not have any facial markings and must be treated by hypodermic tissue building in every case.

The mucous membrane is a layer of tissue that lines various parts of the body's openings and cavities that are in contact with the outside environment. It is a moist membrane that secretes mucus, a slimy substance that assists in trapping germs and other foreign substances, as well as keeping the surface moist.

The red portion of the human lip: Mucous membrane. The red portion of the human lip is the mucous membrane. The mucous membrane of the lips is often known as the vermilion zone. It is a transition zone between the skin and the mucous membrane.

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DNA contains the code for making proteins. The code in DNA is found in the structure of the double helix in several different ways.

The double helix structure is composed of two strands of nucleotides that are linked together by hydrogen bonds. The code is found in the sequence of nucleotides along each strand of the double helix. The sequence of nucleotides is what determines the genetic code. The genetic code is read in groups of three nucleotides called codons. Each codon codes for a specific amino acid, which is then used to build proteins. In addition to the sequence of nucleotides, the code is also found in the way that the double helix is folded and coiled. The three-dimensional structure of the double helix determines which parts of the DNA are accessible and which parts are not. This, in turn, determines which genes are expressed and which are not. The double helix structure of DNA is a complex structure that contains the code for making proteins in many different ways.

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>> We know that, the he Sensory neurons conduct signals from sensory organs to the CNS.

>> The Sensory Neurons arise from the dorsal root ganglion which are specialized clusters present at the dorsal roots of the spinal cord.

>> The Sensory neurons lack distinct axons and dendrites.

>> The soma of the sensory neurons possesses a nucleus and other cell organelles.

>> A synaptic junction with second-order sensory neurons is formed as the central branch extends from soma to the posterior horn of the spinal cord.

The functions of sensory neurons are :

>> Its the Controlling the Heartbeat and Blood Circulation

>> The sensory receptors in the blood vessels are responsible for registering blood pressure.

>> The Sensory neurons can be found in the aorta carotid arteries pulmonary artery capillaries in the adrenal gland and the tissues of the heart itself from where the signals are sent to the medulla and thus the help in controlling BP and blood circulation.

>> The Taste receptor cells on our tongues form a group of 50 to 150.

>> These cells respond to the chemicals present in the food and thus the form taste buds which help us in differentiating among the food items of different tastes.

Answer:

Interneurons

Explanation:

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These are environments found in water, either freshwater or marine. Examples include lakes, rivers, estuaries, and coral reefs.

What kind of environment found in water?

As I cannot view the specific textbook or table you are using, I will provide general information about the similarities and differences between land biomes and aquatic ecosystems. Please refer to your textbook and adjust the information accordingly.

Land biomes: These are large regions defined by their climate, vegetation, and animal life. Some examples include forests, grasslands, and deserts.

Similarities: Land biomes share features such as soil type, precipitation levels, and temperature ranges. They also contain diverse plant and animal life adapted to the specific conditions.
- Differences: Land biomes differ in climate, vegetation, and animal life. For example, forests are characterized by a high density of trees, while grasslands have predominantly grasses and deserts have little vegetation.

Aquatic ecosystems: These are environments found in water, either freshwater or marine. Examples include lakes, rivers, estuaries, and coral reefs.

Similarities: Aquatic ecosystems share features such as water depth, salinity, and temperature. They also contain diverse aquatic plants and animal life adapted to the specific conditions.

Differences: Aquatic ecosystems differ in the type of water (freshwater or marine), water movement, and available sunlight. For example, lakes are still bodies of freshwater, while rivers have flowing freshwater. Estuaries are where freshwater meets marine water, and coral reefs are marine ecosystems with high biodiversity.

To record your work in the table, you can list each biome and aquatic ecosystem, then note their similarities and differences based on the features mentioned above. Please refer to your textbook for specific examples and more detailed information.

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The epiphyseal plate, also known as the growth plate, is composed of four zones: the resting zone, the proliferative zone, the hypertrophic zone, and the calcified zone. The epiphyseal line, or growth line, is the division between the epiphyseal plate and the diaphysis and is where all growth stops.

The resting zone is the first zone in the epiphyseal plate and is located at the epiphyseal side of the plate. It contains cells that are inactive but can divide to form more chondrocytes, which are essential for the formation of bone and cartilage.

The proliferative zone is the second zone and is the site of cell division and growth.

The hypertrophic zone is the third zone and is the site of most growth. It is also the site of most of the extracellular matrix mineralization, as chondrocytes in this zone produce high levels of collagen and other matrix proteins.

The calcified zone is the fourth and last zone and is composed of cells that are no longer able to divide or grow. It contains mature, mineralized cartilage.

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Which type of cloud is very close to the earth's surface?

The altostartus clouds are found in the upper troposphere

The cirrus clouds are found in the troposphere

The cumulonimbus clouds are found in the lower troposphere...

Transport of a solute across a membrane where the solute is going up its concentration gradient and using protein carriers driven by the expenditure of chemical energy is known as active transport.

Active transport is the movement of molecules against the concentration gradient, which means moving from lower to higher concentrations. It involves a direct energy source (ATP) to drive the movement of molecules. The active transport method involves the use of protein pumps to move molecules across the cell membrane. These pumps can help move molecules, including sodium, calcium, and potassium, against the concentration gradient, which allows the cell to regulate what enters and exits. During active transport, the cell must use energy in the form of ATP to transport the molecules.

In summary, the transport of a solute across a membrane, where the solute is going up its concentration gradient and using protein carriers driven by the expenditure of chemical energy, is known as active transport. Active transport requires energy, which is provided by the hydrolysis of ATP. Active transport is necessary because it allows the cell to maintain its internal environment despite the external environment's changes.

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If the vessels between the lungs and body tissues were permeable to oxygen, there will be a decrease in the oxygen supply to the body tissues.

Normally, oxygen-poor blood from the body tissues flows into the right side of the heart, and is then pumped to the lungs where it picks up oxygen and releases carbon dioxide. The oxygen-rich blood then flows back to the left side of the heart, where it is pumped out to the body tissues to supply oxygen to the cells.

If the vessels between the lungs and body tissues were permeable to oxygen, oxygen-rich blood from the lungs would flow into the right side of the heart, mix with oxygen-poor blood from the body tissues, and then be pumped out to the body tissues.

This would result in a reduced delivery of oxygen to the tissues, as some of the oxygen-rich blood from the lungs would bypass the body tissues and flow back to the lungs.

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Hearing, Balance and equilibrium: The ear is also very important for keeping your balance and equilibrium, which is important for your posture, movement, and sense of where you are in space.

Pressure regulation: The Eustachian tube, which connects the middle ear to the back of the throat, is opened and closed by the ear. This helps keep the pressure in the middle ear at the right level.

Protection: Hair and wax line the ear canal, which helps keep dust, dirt, and other foreign particles from getting into the ear's delicate structures.

Temperature regulation: When the temperature outside changes, the ear responds by widening or narrowing the blood vessels in the ear.

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Some of the age-related changes in the articular cartilage that contribute to osteoarthritis include increased stiffness and decreased elasticity, reduced water content and a decrease in proteoglycan content within the matrix, and loss of structural integrity.

Osteoarthritis (OA) is a chronic degenerative joint disease that affects both the cartilage and the underlying bone, with a growing prevalence and a major impact on people's lives.

The articular cartilage, which is the cartilage that covers the ends of bones in a joint, deteriorates in OA, causing joint pain, stiffness, and disability.

As the population ages, OA is projected to become a leading cause of disability, making it a significant public health concern.

The age-related changes in the articular cartilage that contribute to osteoarthritis include the following:

Increased stiffness and decreased elasticity. The articular cartilage, like other body tissues, loses its elasticity and becomes stiffer as we age.

This loss of elasticity and increased stiffness causes the joint to become less mobile, limiting motion and leading to joint pain and discomfort.

Reduced water content. The cartilage matrix has a high water content, which provides cushioning and shock absorption, particularly during joint movement. However, with age, the water content of the matrix reduces, leading to a loss of this cushioning effect.

Loss of proteoglycan content within the matrix. Proteoglycans are large molecules found in the cartilage matrix that help to maintain the structural integrity of the cartilage. The age-related loss of proteoglycans weakens the cartilage matrix and makes it more prone to damage and deterioration.

Loss of structural integrity, Age-related changes, such as changes in the joint shape or the alignment of the bones, can lead to uneven distribution of weight within the joint, causing additional stress on the cartilage.

This uneven weight distribution, combined with the age-related changes in the cartilage matrix, contributes to the loss of structural integrity of the articular cartilage, which is a hallmark of osteoarthritis.

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The reactants side consists of three different types of atoms: carbon, hydrogen and oxygen. There are 6 carbon atoms, 12 hydrogen atoms and 18 oxygen atoms.

The reactants side consists of three different types of atoms: carbon, hydrogen and oxygen. There are 6 carbon atoms, 12 hydrogen atoms and 18 oxygen atoms.

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If a gardener wants to grow a lemon tree from a lemon, the first thing he should do is to remove the seeds from the lemon to germinate.

A gardener who wants to grow a lemon tree from a lemon should follow a series of steps. These steps are as follows:

Step 1: Remove the seeds from the lemon. The seeds should be washed and cleaned with water. The gardener should be careful not to damage the seeds.

Step 2: Prepare the soil. The soil should be well-draining, rich in nutrients, and have a pH of 5.5 to 6.5. The gardener can mix sand, perlite, and vermiculite to the soil to increase its drainage.

Step 3: Plant the seeds. The gardener should plant the seeds about 1 inch deep into the soil. The soil should be moist but not waterlogged.

Step 4: Cover the pot with a plastic bag or a plastic wrap to create a greenhouse effect.

Step 5: Place the pot in a warm and sunny location. The temperature should be around 70 degrees Fahrenheit.

Step 6: Water the soil regularly. The soil should be kept moist but not waterlogged.

Step 7: Wait for the seeds to germinate. It may take a few weeks to a few months for the seeds to germinate.

Step 8: Once the seedlings have grown big enough, they can be transplanted into a bigger pot. The plant should be kept in a warm and sunny location. The soil should be kept moist but not waterlogged.

Step 9: The lemon tree should be fertilized with a citrus fertilizer every two weeks during the growing season.

Step 10: The lemon tree should be pruned regularly to remove dead, damaged, or diseased branches.

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In an ecological study involving killifish and pike-cichlid pools, the control group is the source population in the pike-cichlid pools as it did not receive any intervention in the study.

In a study, the control group refers to the group that does not receive any treatment or intervention and is used as a comparison to the experimental group. In this scenario, the source population in the pike-cichlid pools is the control group as it did not receive any intervention in the study. The study is not mentioned in the question, but based on the options provided, it is likely an ecological study involving killifish and pike-cichlid pools. The transplanted population is most likely the experimental group. The source population in the killifish pools and the source population in the pike-cichlid pools are both control groups that did not receive any intervention in the study.

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The new organelle that you discovered with a highly hydrophobic compartment will most likely contain lipids, such as fatty acids and phospholipids, as they are hydrophobic molecules.

There are a number of molecules that will most certainly be abundant in an organelle that contains a highly hydrophobic compartment. In the context of biochemistry, the most abundant molecule is usually the one that is most soluble in the organelle's environment.

According to a number of theories, lipids are most likely to be the most abundant molecules in an organelle containing a highly hydrophobic compartment. Lipids are a diverse class of molecules that are primarily defined by their solubility characteristics. Lipids are soluble in organic solvents and insoluble in water, which means they are ideal for forming membranes, which are hydrophobic compartments.

Therefore, lipids will most certainly be abundant in an organelle that contains a highly hydrophobic compartment.

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Answer:

The birds may initially be frightened by the rubber snakes due to the sudden presence of a new stimulus. However, if they do not encounter any negative effects, such as being attacked or injured by the snakes, they may quickly habituate to their presence and no longer see them as a threat. This means that the birds may learn that the rubber snakes are not a danger and may continue to build their nests on the sign, ignoring the presence of the snakes. Therefore, the use of rubber snakes may have no positive effects in deterring the birds from building their nests, but rather may be ineffective or even have negative effects if the birds become habituated to them.

Explanation:

This is what I think hope it helps.

Genetic changes in bacteria can be brought about by mutations, conjugation, transduction, transformation, and reproduction.

Genetic changes refer to alterations in the genetic material of an organism that occur naturally or due to external factors such as radiation or chemical exposure.

The most common causes of genetic change in bacteria are mutations, conjugation, transduction, transformation, and reproduction.' in second part of your answer.

Mutations

Mutations occur when changes in the DNA sequence of a bacterium occur due to errors during DNA replication or exposure to mutagenic agents such as UV light, chemicals, or radiation.

These changes can be beneficial, harmful, or neutral, depending on the type and location of the mutation in the bacterial genome.

Conjugation

Conjugation is the process by which bacteria exchange genetic material through direct cell-to-cell contact via a pilus. This mechanism allows the transfer of plasmids that can carry antibiotic resistance genes or other genes of interest from one bacterium to another.

Transduction

Transduction is the process by which bacteria transfer genetic material via a bacteriophage, which is a virus that infects bacteria. During transduction, bacterial DNA is incorporated into the viral genome and transferred to other bacteria during subsequent infection cycles.

Transformation

Transformation is the process by which bacteria take up DNA from their surroundings and incorporate it into their genome. This mechanism is important for bacterial adaptation to new environments and can lead to the acquisition of new genetic traits that provide a survival advantage.

Reproduction

Reproduction involves the production of offspring that inherit genetic material from their parents. Bacteria reproduce through a variety of mechanisms, including binary fission, budding, and sporulation, among others. These processes can lead to the accumulation of genetic changes over time that can result in the development of new bacterial strains with unique properties.

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Answer:

Natural selection drives evolution by preserving favorable variations and causing the extinction of unfavorable variations.

Explanation:

Natural selection is the process by which forms of life having traits that better enable them to adapt to specific environmental pressures, as predators, changes in climate, or competition for food or mates, will tend to survive and reproduce in greater numbers than other of their kind, thus ensuring the perpetuation of those favorable traits in succeeding generations. Evolution is the change of a gene pool of a population from generation to generation by such processes as mutation, natural selection, or genetic drift.

Carbohydrates are composed of monosaccharides, proteins are composed of amino acids, and nucleic acids are composed of nucleotides.

Carbohydrates, proteins, and nucleic acids are three major classes of biomolecules that are essential for life.

Here are the elements present and the building blocks of each:

Carbohydrates:

Carbohydrates are organic molecules that contain carbon, hydrogen, and oxygen in the ratio of 1:2:1. The building blocks of carbohydrates are monosaccharides, which are simple sugars that cannot be broken down into smaller molecules. Examples of monosaccharides include glucose, fructose, and galactose.

Proteins:

Proteins are complex molecules that are made up of amino acids. Amino acids contain carbon, hydrogen, oxygen, nitrogen, and sometimes sulfur. There are 20 different types of amino acids, and they are joined together by peptide bonds to form polypeptide chains, which fold into specific three-dimensional structures to form proteins.

Nucleic acids:

Nucleic acids are macromolecules that store and transmit genetic information. They are composed of nucleotides, which are made up of a nitrogenous base, a sugar, and a phosphate group. The four nitrogenous bases in DNA are adenine, guanine, cytosine, and thymine, while in RNA, uracil replaces thymine. The sugar in DNA is deoxyribose, while in RNA, it is ribose. The nucleotides are joined together by phosphodiester bonds to form a linear chain called a polynucleotide.

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Proteases enzyme is not found in saliva , hence option 'D' is correct

The natural execration occurs from salivary gland, thus it accounts for high concentration of urea and uric acid found in saliva. Since the amount of creatinine production is consonant in 24 hours , uric acid and urea -to- creatinine ratio are better to clarify the changes of this compound concentration in saliva . Therefore option A is incorrect.

The main inorganic components are sodium , potassium, chloride, calcium, phosphate , and bicarbonate , all contributing to the ionic strength of saliva. Therefore option B is incorrect.

As an important part of the non specific immune defense mechanism , lysozyme is an important component of antibacterial in saliva. Therefore option C is incorrect.

Proteases are released by pancreas into the proximal small intestine ,where the mix with proteins already denatured by gastric secretion's and break down into amino acids. Therefore option "D" is correct.

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