An electric motor delivers a shaft torque of 15 lb. ft at 1800 rpm. what is the motor power?

Answers

Answer 1

The power of the motor is 3.82 kilowatt.

Shaft torque of the electric motor = 15 lb-ft = 20.3 Nm

Revolution per minute made by the electric motor = 1800 revolutions per minutes

The angular velocity of the electric motor is,

[tex]Angular \: velocity = \frac{ 2 \times π \times revolutions}{60} [/tex]

[tex]w = \frac{2 \times \pi \times r}{60}[/tex]

[tex]w = \frac{2 \times 22 \times 1800}{ 7 \times 60}[/tex]

[tex]w = 188.5 \: rad/s[/tex]

The angular velocity of the electric motor is 188.5 rad/s.

The power of the motor is,

[tex]Power = torque \times angular \: velocity[/tex]

[tex]P = τ \times w[/tex]

[tex]P = 20.3 \times 188.5[/tex]

[tex]P = 3826.5 \: watt[/tex]

[tex]P = 3.82 \: kilowatt[/tex]

Therefore, the power of the motor is 3.82 kilowatt.

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Related Questions

inside out and upside-down: the roles of gas cooling and dynamical heating in shaping the stellar age-velocity relation

Answers

The formation and evolution of discs can be better understood by performing kinematic studies of disc galaxies utilizing specific Milky Way stars or statistical analyses of global disc kinematics across time.

The study of Gas Cooling and Dynamical Heating

Older stars are kinematically hotter at birth and get hotter as they grow older (the disc settles over time in an “upside-down” formation scenario).

The disc also expands from the inside out, and radial mixing has resulted in the presence of many of the older stars in the current solar neighborhood.

We show that the model used to explain the general decrease in velocity dispersion observed in disc galaxies from z 2-3 to the present day, in which the disc evolves in quasi-stable equilibrium and the ISM velocity dispersion decreases over time due to a decreasing gas fraction, can also be used to explain the evolution of birth in h277.

Our findings connect local measurements of the Milky Way’s AVR with those of high-z disc galaxies’ observed kinematics.

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you drive in a straight line at 16.0 m/sm/s for 10.0 minmin, then at 28.0 m/sm/s for another 10.0 minmin.

Answers

The average speed is 22 m/s. so, the value is less than 23.0 m/s.

Given:

Time  T1 = 16.0 m/s, 10.0 min

Time  T2 = 28.0 m/s, 10.0 min.

Average speed = distance / time ;

v =  [  16×10 ×60  + 28×10×60  ]  /  [ 10×60 + 10×60  ]

v = 22 m /s

What is a real speed?

The Actual Speed is the calculated velocity at which the axis is presently moving, as computed from the alternate within side the Transducer Counts repute register. The Actual Speed is in function devices according to second.

Speed has the dimensions of distance divided via way of means of time. The SI unit of velocity is the metre in keeping with the second (m/s), however, the maximum not unusual place unit of velocity in regular utilization is the kilometre in keeping with the hour (km/h) or, within side the US and the UK, miles in keeping with the hour (mph). For air and marine travel, the knot is normally used.

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Select all of the following that are vector quantities.
A acceleration
B. force
C. mass
D. speed
E. velocity
F. volume ​

Answers

Scalar(only magnitude, no direction): Volume, mass, speed, density, number of moles, angular frequency.
Vector(both magnitude and direction) : Acceleration, velocity, displacement, angular velocity.

Explanation : Vector quantities have both magnitude and direction.
Scalar quantities have only magnitude.
Distance is a scalar quantity. It refers only to how far an object has traveled. For example, 4 feet is a distance; it gives no information about direction. To say an object traveled 4 feet is somewhat ambiguous. To say the object traveled 4 feet west, for example, would be a displacement, and would then be a vector quantity. It gives a more complete picture of what happened.
Mass is a scalar quantity. Simply put, it refers to how much matter an object is made up of. It has magnitude but gives no indication of direction in any sense. The vector counterpart to mass is weight.
Weight is a vector quantity. Weight is a force, and forces are vectors, i.e. having both magnitude and direction. Perceived weight of an object at rest on earth is given by
W=→Fg=mg
, the product of the mass of the object and the free-fall acceleration constant, g
, or simply equal to the force of gravity acting on the object. The force of gravity acts downward.
Time is a scalar quantity (as far as we are concerned at this level). It gives information about magnitude, i.e. how much time, but no information about direction.
Volume is a scalar quantity. It refers to the amount of space that an object occupies and therefore has magnitude, but gives no information about direction.
Density is a scalar quantity, having only magnitude and giving no information about direction. We can also reason that, because density is equal to mass divided by volume and both mass and volume are scalar quantities, density must also be a scalar quantity.
Speed is a scalar quantity, having only magnitude and giving no information about direction. For example,
40ms
is a speed, it tells us how fast an object is traveling, but nothing abut which direction the object is traveling in. The vector counterpart to speed is velocity.
Velocity is a vector quantity. Velocities have both magnitude and direction. For example,
40ms
NE is a velocity.
Acceleration is a vector quantity. Acceleration has both magnitude and direction. For example,
9.8ms2 downward or −9.8ms2
vertically is an acceleration.
Force is a vector quantity. Force has both magnitude and direction. Weight is an example of force given above. Another is the force of friction, which has some magnitude and acts in the direction opposite that of motion.
Temperature is a scalar quantity. A measurement of temperature has magnitude, but gives no information about direction.
Energy is a scalar quantity. It gives information about magnitude, e.g. how much energy an object has, but none about direction.
Note that certain quantities which are alone scalars can be represented as vectors when we discuss intervals or how the quantities change (e.g. measure of increase or decrease).

Person of weight 80 kg jumped off a platform of height 1 m and safely landed on their feet. what is the magnitude of the momentum change during the collision?

Answers

The momentum change is 125440 kg.m/s.

We need to know about momentum to solve this problem. Momentum can be defined as the degree of difficulty to stop a moving object. It can be determined by

P = m . v

where P is momentum, m is mass and v is velocity.

Momentum also can be defined by kinetic energy

KE = 1/2 . m . v²

KE = P² / 2m

where KE is kinetic energy

From the question above, we know that:

m = 80 kg

h = 1 m

g = 9.8 m/s²

By conservation of energy, the initial kinetic energy is zero because of the person is in static condition. Hence, the initial momentum is

KEo = Po² / 2m

Po = 0 kgm/s

After the jump, the person will have maximum kinetic energy before landing which can be written

KE = PE

P² / 2m = m . g . h

P² = 2m² . 9.8 . 1

P² = 2.80² . 9.8 . 1

P² = 125440 kg.m/s

The momentum change is

ΔP = P - Po

ΔP = 125440 - 0

ΔP = 125440 kgm/s

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A body is thrown upwards vertically with a velocity of 60m/s. Calculate it’s velocity the height attained after 3 seconds the maximum height attained

Answers

The velocity of the body will be 30.6 m/s.

The object's highest vertical point during its trajectory is at its maximum height. Before it reaches the highest point, the item is flying upward; once it reaches that point, it is falling.

The velocity of the body is 60 m/s when thrown vertically upwards.

The maximum height attained by the body after 3 seconds.

Then, the initial velocity of the body is :

u = 60 m/s

t = 3 seconds

Then, using the equation of motion:

v = u - gt , the negative sign indicates that the body is moving opposite to gravity.

Therefore,

v = 60 - (9.8)(3)

v = 60 - 29.4

v = 30.6 m/s

Hence, the final velocity of the body when thrown upwards before it comes to stop is 30.6 m/s.

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a bicyclist traveled from 15.6 m/s to 21.1 m/s over a distance of 30 meters

a) what is the acceleration of the bicyclist?

b) How much time does it take the bicyclist to travel the 30 meters

Answers

The acceleration of the bicyclist is 3.35 m / s². It takes the bicyclist 1.64 s to travel the 30 meters

We know that,

a = ( v - u ) / t

s = ut + 1 / 2 at²

where,

a = Acceleration

v = Final velocity

u = Initial velocity

t = Time taken

s = Distance travelled

Given that,

u = 15.6 m / s

v = 21.1 m / s

s = 30 m

a = ( 21.1 - 15.6 ) / t = 5.5 / t

s = ut + 1 / 2 at²

30 = 15.6 t + 1 / 2 ( 5.5 t )

30 = 15.6 t + 2.75 t

t = 30 / 18.35

t = 1.64 s

a = 5.5 / t = 5.5 / 1.64

a = 3.35 m / s²

Equations of motion are used to describe the position of an object using the motion of the object with respect to time. It is done using speed, acceleration, distance and time.

Therefore,

a) The acceleration of the bicyclist is 3.35 m / s²

b) Time taken by the bicyclist =

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Is there any difference between frame of reference and reference point in physics?​

Answers

Answer: A frame of reference is a reference point combined with a set of directions. A frame of reference is similar to the idea of a reference point. A frame of reference is defined as a reference point combined with a set of directions. For example, a boy is standing still inside a train as it pulls out of a station.

Explanation: hope this helps!!!!

a 60kg person walks from the ground to the roof of a 80m tall building. what is the person's potential energy once they get to the top?

Answers

The potential energy is 47040 joules.

We need to know about potential energy to solve this problem. The potential energy is the object's energy caused by its position. Potential energy can be determined as

PE = m . g . h

where PE is potential energy, m is mass, g is the gravitational acceleration (9.8 m/s²) and h is height.

From the question above, we know that

m = 60 kg

h = 80 m

By substituting the given parameters, we can calculate the potential energy

PE = m . g . h

PE = 60 . 9.8 . 80

PE = 47040 joules

Hence, the potential energy is 47040 joules.

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Please in complete sentences I already did the first slide but i put it there so you can i have an idea about what its asking

Answers

Answer:

The prospect of giving a presentation fills some people with dread, while others relish the experience. However you feel, presenting your work to an audience is a vital part of professional life for researchers and academics. Presentations are a great way to speak directly to people who are interested in your field of study, to gather ideas to push your projects forward, and to make valuable personal connections.

Find the caloric content of 100g of fruit salad containing 20g of apple, 25g of strawberry, 15g of grapes, 30g of banana, and 10g of honey.

Answers

90 caloric content of 100g of fruit salad containing 20g of apple, 25g of strawberry, 15g of grapes, 30g of banana, and 10g of honey.

energy are the strength that a meals or beverage includes.

On food merchandise, energy are normally noted, and wearables just like the first-class health trackers assist you to hold-song of how many calories you burn even as undertaking numerous sports. greater energy are usually found in positive ingredients, together with those which are fatty, fried, or processed. clean fruit and veggies, as an instance, have fewer calories on average than different foods. Conversely, low-calorie objects like food regimen soda don't have any dietary value while some nutritious culmination and vegetables might have a high-calorie content.

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drivers must slow down from 60 to 40 mph to negotiate a severe curve on a rural highway. a warning sign for the curve is clearly visible for a distance of 200’. how far in advance of the curve must the sign be located in order to ensure that vehicles have sufficient distance to safely decelerate? use the standard reaction time and deceleration rate recommended by aashto for basic braking maneuvers.

Answers

The sign needs to be placed 292.07 feet in advance of the curve in order to provide cars enough room to safely slow down.

Prior to putting up a sign board to slow down traffic, we first calculate the distance.

d is the safe stopping distance, Si is the initial speed (60 mph), t is the time reaction (2.5 seconds), Sf is the end speed (40 mph), and G is the grade (0).

Therefore, we replace d = (1.47 60 2.5) + [(602 - 402) / 30(0.348 0) = 220.5 + (2000/10.44) = 220.5 + 191.57 = 412.07 ft Now that we know that a warning sign is clearly visible at a distance of 120 ft, the ideal safe distance will be d = minimum distance - sign visible distance d = 412.07 ft.

d = 412.07 - 120

d = 292.07 ft

In order to ensure that vehicles have enough room to safely slow down, the sign must be placed 292.07 feet ahead of the bend.

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a jet fighter pilot wishes to accelerate from rest at 5 g to reach mach-3 (three times the speed of sound) as quickly as possible. experimental tests reveal that he will black out if this acceleration lasts for more than 4.9 s . use 331 m/s for the speed of sound.

Answers

The greatest speed pilot can reach with an acceleration of 5g before he blacks out is 240 m/s.

The acceleration due to gravity is g.

g = 9.8 m/s²

The acceleration of the jet is,

[tex]Acceleration = Mass \times Gravity[/tex]

[tex]a = m \times g[/tex]

[tex]a = 5 \times 9.8[/tex]

[tex]a = 49 \: m/s ^{2} [/tex]

The acceleration of the jet is 49 m/s².

Let the speed of sound be v.

[tex]v = 331 \: m/s[/tex]

Let the initial velocity of the jet be

[tex]Let \: the \: initial \: velocity \: of \: the \: jet \: [/tex]

[tex]be \: v _i.[/tex]

[tex]v _i = 0[/tex]

The time at which the pilot will black out with 49 m/s² acceleration = 4.9 s

Let the time taken to reach Mach 3 be t.

Then the final velocity will be,

[tex]v _f = 3 \times v[/tex]

[tex]v _f = 3 \times 331[/tex]

[tex]v _f = 993 \: m/s[/tex]

[tex]v _f = v _i + at[/tex]

[tex]993 = 0 + (49)t[/tex]

[tex]t = 20.26 \: s[/tex]

Thus, the time taken to reach Mach 3 is 20.26 s.it is greater than the time interval at which the pilot will black out. So the pilot will black out.

The greatest speed pilot can reach with an acceleration of 5g before he blacks out is,

[tex]v _f = 0 +( 49 \times 4.9)[/tex]

[tex]v _f = 240.1 \: m/s[/tex]

Therefore, the greatest speed pilot can reach with an acceleration of 5g before he blacks out is 240 m/s.

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A satellite in orbit around Earth is in uniform circular motion. What is the angle between the velocity vector and acceleration vector at any given point on the orbit?
A. 90°
B. 45°
C. 180°
D. 0°

Answers

The correct answer is A. 90 Degrees

The angle between the velocity vector and acceleration vector at any given point in the orbit would be 90 degrees, therefore the correct answer is option A.

What is acceleration?

The rate of change of the velocity with respect to time is known as the acceleration of the object. Generally, the unit of acceleration is considered as meter/seconds².

As given in the If a  satellite in orbit around Earth is in a uniform circular motion then we have to find the angle between the velocity vector and acceleration vector.

In a uniform circular motion, the angle between the velocity vector and acceleration vector is always π/2.

The angle between the velocity vector and acceleration vector at any given point in the orbit would be 90 degrees.

Thus, the correct answer is option A.

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I really need help how dono do this

Answers

Answer:

As mentioned before middle thing nucleus and blue things with +1 charge (positive) [I am talking about the key] are protons anything else that you need help with?

the engineer of an intercity train observes a rock slide blocking the train's path 210.0 m ahead and activates the train's emergency brakes. the train decelerates uniformly at 1.6 m/s2 for 12.10 s before reaching the rock slide. what is the speed with which the train reaches the rock slide?

Answers

The speed with which the train reaches the rock slide is 19.36 m/s

What is acceleration?

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

a is the acceleration v is the final velocity u is the initial velocity t is the time

How to determine the initial velocityFinal velocity (v) = 0 m/sTime (t) = 12.1 sDeceleration (a) = –1.6 m/s²Initial velocity (u) =?

The initial velocity of the train can be obtained as illustrated below:

–1.6 = (0 – u) / 12.1

Cross multiply

0 – u = –1.6 × 12.1

– u = –19.36

Divide both sides by –1

u = –19.36 / –1

u = 19.36 m/s

Thus, the train uses 19.36 m/s to reach the rock slide

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Why does the total amount of energy before and after
any energy transformations remain the same?

Answers

Answer:

Energy cannot be created or destroyed

The total amount of energy remains the same even though it may change forms. The amount of energy before and after any energy transformations remain the same because energy cannot be created or destroyed.

Explanation:

The half-life of the isotope br3574 is 25.4 minutes. if a 4.0-mg sample is given to a patient, how much of the isotope remains after 90.0 minutes?

Answers

half-life of the isotope br3574 is 25.4 minute The amount of isotope remained after 90min = 0.01g

number of periods= time/ half life

= 90/25,=3.6

so at each time 4/3.6=1.1, 1.1/7.2= 0.15 and 0.15/10.8=0.01g

The period of time it takes for one-half of a radioactive isotope to decay is known as the half-life. A given radioactive isotope's half-life is constant; it is unaffected by external factors and independent of the isotope's starting concentration.

or

Half-life is the length of time it takes for a radioactive element to decay to half of its initial value. This suggests that a source's activity has a half-life when it takes time for it to decrease to half its initial value

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two or more of the following sets of displacements when carried out in the order shown have the same resultant which are they

Answers

(a), (b), and (C) have the same resultant.

In two-dimensional,

When a body moves in the east direction or positive x-axis then is denoted by [tex]\hat{i}[/tex] and when the body moves in the north direction or positive y-axis then is denoted by [tex]\hat{j}[/tex].

For option (a),

2m east, 3m north, 4m west

Let's say the initial position is origin then,

[tex]2\hat{i} + 3\hat{j} - 4\hat{i} = - 2\hat{i} + 3\hat{j}[/tex]

Then the displacement is:

= √ [ (-2)² + (3)² ]

= √[ 4 + 9] = √13 m

For (b),

2m north, 3m west, 4m east

[tex]2\hat{j} - 3\hat{i} + 4\hat{i} = \hat{i} + 2\hat{j}[/tex]

The displacement will be:

= √[ (1)² + (2)² ]

= √5 m

For (c),

2m east, 4m west, 3m north

Then,

[tex]2\hat{i} - 4\hat{i} + 3\hat{j} = -2\hat{i} + 3\hat{j}[/tex]

The resultant of displacement is:

= √[ (-2)² + (3)² ]

= √[ 4 + 9]

= √13 m

For (d),

3m north, 2m east, 4m west​

Then,

[tex]3\hat{j} + 2\hat{i} - 4\hat{i} = -2\hat{i} + 3\hat{j}[/tex]

Then, the resultant of displacement will be:

= √[ (-2)² + (3)² ]

= √[ 4 + 9]

= √13 m

Hence (a), (c), and (d) have the same resultant.

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The complete question is mentioned below:

two or more of the following sets of displacement, when carried out in the order shown, have the same resultant, which are they? (a) 2m east, 3m north, 4m west (b) 2m north, 3m west, 4m east (c) 2m east, 4m west, 3m north (d) 3m north, 2m east, 4m west​

A gas with initial state variables p1, v1, and t1 is cooled in an isochoric process until p2=13p1.part aby what factor does the volume change?

Answers

If the volume is held constant, a process is said to be isochoric (or iso-volumetric). The work that the system performs in any isochoric process is always zero.

In thermodynamics, a condition in which a system's volume doesn't change is referred to as an isochoric process. A pressure volume diagram serves as the model for this operation (PV diagram). Consequently, Q1 / Q2 = T1 / T2 or Q1 / Q2 = Q2 / T2 as these two equations are equivalent. The term "lower amount of heat" refers to the proportion of heat to temperature. The total of the reduced amount of heat is therefore zero for the Carnot heat engine. As a result, we can see that in an isochoric process, the volume is constant, and no work is being done. The gas's intrinsic energy is the only thing that changes.

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A scientist reads relevant literature and designs her experiment. She repeats her experiment several times and collects an entire set of data every time. As compared to a single data set, the multiple data sets lead her to modified conclusions.

How is skepticism important to the progress of science in this scenario?

Answers

In this scenario, skepticism is important to the progression of science as it led to collection of several complete data sets.

In the given scenario, the scientist is performing a experimental scientific method. It is based on observations, hypothesis and experiments. This method is done because of skepticism. Since she performs the experiment multiple times, it leads to collection of several complete data sets.

Skepticism is different from denial. Skepticism allows scientists to come to a logical conclusion with evidence that can be confirmed by others. If a person is in denial, they would simply reject any information that is different from their beliefs even though they were presented with evidence disproving their theory.

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If the price elasticity of demand for labor is 0.15 and the wage increased from $11 to $16 an hour, what is the predicted decrease in the level of employment in percentage terms?

Answers

The predicted  decrease in level of employment percentage is calculated as 6.81%

Elasticity of demand for labor = % Change in Demand for Labor/ % Change in wage

Elasticity of demand for labor = 0.15

% Change in wage = (16-11)/11×100 = 45.45%

Elasticity of demand for labor = % Change in Demand for Labor/ % Change in wage

0.15 = % Change in Demand for Labor/45.45%

% Change in Demand for Labor =   45.45%×0.15

                                                                 = 6.81%

What is price elasticity of demand means?

Price elasticity of demand is that the ratio of the percentage change in quantity demanded of a product to the percentage change in price. Economists employ it to know how supply and demand change when a product's price changes

Why is price elasticity of demand important?

Price elasticity is that the measure of the market's response to price changes. Elasticity is vital to pricing decisions because it helps us understand whether raising prices or lowering prices will enable us to achieve our pricing objectives.

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What steps could the company take to help ensure that electric engines become the dominant design?

Answers

Drive defensively. Simply said, aggressive driving accelerates the rate of battery drain in your electric vehicle.

Speed up. When feasible, try to maintain your speed under 60 mph.

What are electric engines ?

An electric motor is a mechanical device that converts electrical energy into mechanical energy. The majority of electric motors function by producing torque that is applied to the motor shaft through the interaction of the motor's magnetic field and the electric current flowing through a wire winding.

Drive defensively. Simply said, aggressive driving accelerates the rate of battery drain in your electric vehicle.Hurry up. Whenever possible, aim to maintain a speed of less than 60 mph.Make the most of regenerative braking.Don't be too hot.Cool Off With The AC.Tend To Get TiredKeep it Light.Remain Slick.

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What is the total distance traveled of the object in the graph? Thank you! (:

Answers

0 km,that’s because the object came back to the starting point

What is the minimum diameter of a steel wire if it is to support a mass of 80 kg?

Answers

The minimum diameter of a steel wire if it is to support a mass of 80 kg is 1.41 * 10⁻³ m.

What will be the minimum diameter of a steel wire if it is to support a mass of 80 kg?

The minimum diameter, d of the steel wire can be calculated thus:

Stress, α = Force/area

α = 5.0 × 10⁸ Pa.

mass, m = 80 kg

Force = 80 * 98 = 784 N

Area = force/α

area = 784/5.0 × 10⁸

area = 1.57 * 10⁻⁶

Area = πd²/4

d = √(4 * area/π)

d = √(4 *  1.57 * 10⁻⁶ * 7/22)

diameter = 1.41 * 10⁻³ m

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Note that the complete question is given below:

What is the minimum diameter of a steel wire if it is to support a mass of 80 kg? The elastic limit of steel is 5.0 × 10⁸ Pa.

calculate the power output (in watts) during 1 minute of exercise on the cycle ergometer, given the following

Answers

The power output would be 981 watts.

Solution

Metered energy for one metering interval, measured in kWh per meter in interval, multiplied by the number of metering intervals in an hour equals power output.

The average rate of electric energy delivery during the course of one metering interval, expressed as an hourly rate of delivery in kWh, is the outcome.

The maximum power, stated in kW, that a charging station, pool, or shore-side energy supply system is theoretically capable of giving to a linked car or vessel is the installation’s “power output.”

What are energy and work?

Work is the process of transferring energy into an object to move it in some way.

Energy is the term used to describe the capacity to accomplish tasks. Acted upon

Calculation

60 kg x 9.81 = 588.6N

100m/min = 5/3 m/s

Power= v.w

= 588.6 x 5/3

=981 watts

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A truck traveling at 62 mph brakes to a stop in 175 feet. what was the average acceleration and stopping time?

Answers

The average acceleration is -7.09 m/s² and the stopping time is 3.87 sec.

Given,

Final velocity, v = 0

Initial velocity, u = 62 mph

Converting mph to km/h and to m/s, we get

u = 99.2 km/h

Or, u = 27.5 m/s

Displacement, s = 175 feet

Or, s = 53.3 meter

By using the third equation of motion, we get

v² - u² = 2as

0 - (27.5)² = 2 × a × 53.3

Or, acceleration(a) = -7.09 m/s²

Now, by the first equation of motion,

v = u + at

Or, - u = at

-27.5 = -7.09 × t

Or, t = 27.5/7.09

t = 3.87 sec

The stopping time (t) is 3.87 sec

Hence, the average acceleration is -7.09 m/s², and the time is 3.87 sec.

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he atmosphere exerts a pressure of 14.7 lbf/in.2 on top of the 6-in.-diameter piston. the absolute pressure of the air inside the cylinder is 16 lbf/in.2 the local acceleration of gravity is g

Answers

The absolute pressure of the air inside the cylinder is 16 lbf/in

1.3psig.

A straightforward idea is pressure—the measurement of force in a certain space.

There are several approaches of comprehending the strain, nevertheless, depending on the query.

Here are some tips for differentiating pressure measurement types and units when describing when and why such pressure measurements are employed.

Calculate the mass of the piston by applying the equilibrium condition.

∑F_y=0

p_(air)A_(piston)- p_(atm)A_(piston)-m_(piston)g=0

(p_(air)-p_(atm))A_(piston)-m_(piston)g=0

m_(piston)=(p_(air)-p_(atm))A_(piston)/g ______(1)

Calculate the area of the piston,

A_piston= πD^2/4

=π×D^2/4

=π×6^2/4

=28.274 in^2

By substituting the value in m_(piston)=(p_(air)-p_(atm))A_(piston)/g

=(16.14.7 lbf/in.^2)(28.274 in.^2)/32.2 ft/s^2(32.2 ft/s^2/1lbf)

=36.756 lbm

b)

Calculate the gage pressure if the air,

p_(gage) = p_(abs)-p_(atm)

p_(gage)=16-14.7

=1.3psig

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Jollibee takes in Php 190,000 in an 8-hour period. Write a direct variation equation for the
relationship between income and number of hours. Estimate how many hours it would take
the restaurant to earn Php 1,000,000.

Answers

The direct variation equation is I = kh and it will take 42.1 hours for the restaurant to earn Php 1,000,000.

The direct variation equation has the form y = kx, where k is the constant proportionality. It is a linear equation with two variables.

In an 8-hour period, Jollibee takes in Php 190000.

The direct variation equation is given as y = kx, where y is directly proportional to x.

Hours worked (h) directly affect income (I), where k is the variational constant.

Therefore,

I = k × h

190000 = k × (8)

k = 23750 / 190000

Now, when the restaurant earns Php 1,000,000.

Therefore, using the direct variation equation:

Income = variable constant × number of hours

I = k × h

1,000,000 = (23750) × h

h = 1,000,000 / 23750

h = 42.1 hours

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at the instant the traffic light turns green, a car that has been waiting at an intersection starts ahead with a constant acceleration of 3.20 m/s2 . at the same instant a truck, traveling with a constant speed of 22.0 m/s , overtakes and passes the car.

Answers

The distance at which the car meets the truck after the traffic light turns green is at 302.5 m

We know that,

s = ut + 1/2 a[tex]t^{2}[/tex]

v = s / t

where,

s = Distance

u = Initial velocity

t = Time

a = Acceleration

Given that,

The car has with a constant acceleration of 3.2 m / [tex]s^{2}[/tex]

Initial velocity of car = 0

Velocity of truck = 22 m / s

After the traffic signal distance travelled by the car and truck are equal and time taken is also equal.

For the truck,

s = v * t

For the car,

s = ut + 1/2 a[tex]t^{2}[/tex]

vt = ut + 1/2 a[tex]t^{2}[/tex]

22 * t = 0 + 1/2 * 3.2 * [tex]t^{2}[/tex]

t = 13.75 s

s = v * t = 22 * 13.75

s = 302.5 m

Velocity is the distance travelled by an object with respect to time. It is denoted by V.

Therefore, the distance at which the car meets the truck after the traffic light turns green is at 302.5 m

The given question is incomplete. The complete question is

At the instant the traffic light turns green, a car that has been waiting at an intersection starts ahead with a constant acceleration of 3.20 m/[tex]s^{2}[/tex] . at the same instant a truck, traveling with a constant speed of 22.0 m/s , overtakes and passes the car. How far beyond the traffic signal will the car overtake the truck?

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Use the drop-down menus to answer the questions.
If two vectors are perpendicular to each other, how should you add them?
If two vectors are not perpendicular to each other, how should you add them?

Answers

Addition of vectors can be done using the Pythagorean theorem for perpendicular vectors and the Parallelogram law of vector addition for non-perpendicular vectors.

The head of the first vector must meet the tail of the second vector in order for the two vectors to be added together, according to the triangle law of vector addition. We may thus acquire the resulting sum vector by connecting the head of the second vector to the tail of the first vector.

Addition of vectors which are perpendicular is done using the Pythagorean theorem,

[tex]C^2 = A^2 + B^2\\C = \sqrt{A^2 + B^2}[/tex]

Addition of vectors not perpendicular to each other is done using the Parallelogram law of vector addition:

[tex]R = \sqrt{A^2 + B^2 + 2AB cos\theta}[/tex]

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