An internet search to find information about the effects of electromagnetic fields on public health is highly dangerous to humans and other living organisms.
What do you mean by Electromagnetic fields?Electromagnetic fields may be defined as a combination of invisible electric and magnetic fields of force. They are typically generated by natural phenomena like the Earth's magnetic field but also by human activities, mainly through the use of electricity.
Electromagnetic fields highly impact numerous members of the public and have attributed a diffuse collection of symptoms to low levels of exposure to electromagnetic fields at home. Reported symptoms include headaches, anxiety, depression, nausea, fatigue, and loss of appetite.
Moderate to high Exposure to magnetic fields is strong enough can lead to dizziness, seeing light flashes, and feeling tingling or pain through stimulation of nerves. Exposure to radiofrequency fields that are strong enough can lead to the heating of body tissue, and result in damage to tissues and organs.
Therefore, an internet search to find information about the effects of electromagnetic fields on public health is well described above.
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A proton of kinetic energy 2. 80 MeV travels head-on toward a lead nucleus which is fixed in space. Assuming that the proton does not penetrate the nucleus and that the only force between proton and nucleus is the Coulomb force, calculate the smallest center-to-center separation dp between proton and nucleus when the proton momentarily stops. If the proton were replaced with an alpha particle (which contains two protons) of the same initial kinetic energy, the alpha particle would stop at center-to-center separation da. What is da/dp?
The smallest center-to-center separation dp between proton and nucleus when the proton momentarily stops is 4.17 x 10^-14m and the ratio da/dp is 2:1.
Given the kinetic energy of proton (KE) = 2.80MeV
The charge if proton (q1) = 1.6 x 10^-19C
The proton hits a lead nucleus. So, the atomic number of lead = 82
The charge on lead nucleus (q2) = 82e = 82 x 1.6 x 10^-19
The Coulomb force is the sole force that exists between the proton and the nucleus because the proton cannot enter the nucleus.
We know that KE = q1V where V is the potential difference
We know that from coulombs law V = kq2/r where r is separation distance
Then r = dp such that dp = kq1/V = kqxq2/KE = kq1q2/KE
dp = (8.9 x 10^9)(1e)(82e)/2.8 MeV
dp = 1167.68 x 10^-10/2.8 x 10^6 = 4.17 x 10^-14m
The the smallest center-to-center separation dp between proton and nucleus is 4.17 x 10^-14m
If the proton was replaced by two alpha particle charge (q1) = 2e
The separation between alpha particle and nucleus = da
da = (8.9 x 10^9)(2e)(82e)/2.8x10^6eV = 2335.36x10^-16/2.8 = 8.34x10^-14m
Hence the required ratio of da/dp = 8.34x10^-14m/4.17 x 10^-14m = 2:1
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describe a relationship between an atomic property and nuclear power generation
Atomic properties, such as the number of protons and neutrons in the nucleus of an atom, determine an element's atomic number and its ability to undergo nuclear reactions.
What's the relationship between Atomic properties and nuclear power generation?
In the process of nuclear power generation, atoms of a specific element, such as uranium or plutonium, are induced to undergo nuclear fission, releasing a large amount of energy in the form of heat.
This heat is then used to generate electricity in a nuclear power plant. Thus, the atomic properties of the fuel used in a nuclear power plant play a critical role in the generation of nuclear power.
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write the functio of the following
1.Eardrum
2.Middle
3.Conknea
4.Pina
The eardrum is the thin piece of tissue which is present between the outer and middle ear. This is responsible for the hearing capacity of an individual.
What are the different parts of Ear?The eardrum, middle ear, cochlea, and pinna are important parts of the Ear. The eardrum is a thin piece of tissue which separates the outer and middle ear. Damage to this eardrum may harm hearing capacity. Mastoiditis is an infection of the bony air cells which are present in the mastoid bone, that is located just behind the ear.
Middle ear has three tiny bones including the malleus, incus and stapes. These bones transfer sound vibrations from eardrum to the inner ear.
The cochlea is a hollow, spiral-shaped bone which is found in the inner ear that plays a key role in the sense of hearing and it also participates in the process of auditory transduction. Sound waves are transduced into electrical impulses which the brain can interpret as individual frequencies of sound.
The auricle or pinna is the visible portion of the outer ear. It is responsible for collecting the sound waves and channels them into the ear canal, where the sound is amplified.
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a limited access zone for masonry construction should?
A limited access zone is an area next to a masonry wall that is being built and is clearly marked to restrict access by workers.
The restricted area must extend the entire length of the wall and have a height equivalent to the height of the proposed wall plus four feet. On the un-scaffolded side of the wall, a limited access zone must be formed. For a maximum wall height of 10.668 meters, the load-bearing masonry wall should be at least 304.8 mm (1 foot) thick (35 ft.). Additionally, for every additional 10.668 meters, the brick wall's thickness must be increased by 101.6 mm (4 inches) (35 ft).
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a physical pendulum in the form of a planar object moves in simple harmonic motion with a frequency of 0.450 hz. the pendulum has a mass of 2.20 kg, and the pivot is located 0.350 m from the center of mass. determine the moment of inertia of the pendulum about the pivot poin
The moment of inertia of the pendulum about the pivot point is 0.385 kgm2.
A physical pendulum in the form of a planar object moves in simple harmonic motion when it oscillates about a pivot point, and the frequency of oscillation is determined by the moment of inertia of the pendulum about the pivot point.
The frequency of oscillation of the pendulum is given as 0.450 Hz. The moment of inertia of the pendulum I can be calculated using the equation:
[tex]I= ML^{2}[/tex]
where m is the mass of the pendulum and L is the distance from the pivot point to the center of mass.
In this case, the mass of the pendulum is 2.20 kg and the distance from the pivot point to the center of mass is 0.350 m, so the moment of inertia is:
[tex]I=(2.20)(0.350)^{2} \\0.385 Kgm^{2}[/tex]
So, the moment of inertia of the pendulum about the pivot point is
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f the airplane is traveling at a constant rate of 200 m/s. what is the acceleration the pilot is experiencing when the plane is at x
The acceleration the pilot is experiencing when the plane is at x will depend upon the situation and the specific events or maneuvers that are taking place.
If the plane is traveling at a constant rate of 200 m/s and no other forces are acting on it, the pilot won't experience any acceleration. Constant velocity means that there is no acceleration.
If in this case, the plane is in a turn, climbing or descending, the pilot will experience an acceleration due to the centripetal force acting on the pilot in the direction towards the center of the turn or the force due to gravity acting on the pilot in the case of climbing or descending.
Without more information about the situation, it is not possible to determine the acceleration the pilot is experiencing.
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in our current universe, where was most of the carbon, nitrogen, and oxygen made?
Most of the carbon, nitrogen, and oxygen in the universe were made in stars through nuclear fusion. Specifically, carbon and oxygen are produced in the later stages of a star's life through the fusion of helium atoms, and nitrogen is produced through the fusion of helium and carbon atoms. This process is known as nucleosynthesis.
What is Nucleosynthesis?Nucleosynthesis is the process by which new atomic nuclei are created. This can happen through a variety of mechanisms, including nuclear fusion and nuclear fission.
The most common type of nucleosynthesis is stellar nucleosynthesis, which occurs in stars. Through the fusion of lighter elements, heavier elements are formed. The fusion of hydrogen nuclei (protons) produces helium, and this process releases a large amount of energy in the form of light and heat. More massive stars can fuse elements up to iron.
Big Bang nucleosynthesis is another important type of nucleosynthesis, which occurred a few minutes after the Big Bang. During this process, protons and neutrons came together to form the nuclei of the lightest elements, such as hydrogen, helium, and lithium.
Another form of nucleosynthesis is explosive nucleosynthesis, which can happen in supernovae. When a massive star exhausts its nuclear fuel and dies, the outer layers of the star are violently expelled and can fuse into heavier elements.
Overall, nucleosynthesis is responsible for the creation of all elements heavier than hydrogen and helium, which were formed during the Big Bang.
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what unit of measurement is used to describe extraordinary large distances, such as the distance of other stars from our own?
Unit of measurement used to describe extraordinary large distances, such as distance of other stars from our own is called light year.
What is meant by light year?The unit of measurement most commonly used to describe large distances in astronomy is light-year. A light-year is the distance that light travels in one year, and is equivalent to about 5.88 trillion miles (9.46 trillion kilometers).
This unit is used because it is the most convenient way to express large distances in space, such as the distance between stars, galaxies and other celestial objects. For example, our nearest star system, Alpha Centauri, is around 4.37 light-years away, and Andromeda galaxy, closest galaxy to our Milky way, is about 2.5 million light-years away.
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a rock is shot vertically upward from the edge of the top of a tall building. the rock reaches its maximum height above the top of the building 1.75s after being shot. then, after barely missing the edgr of the building as it falls downward, the rock stikes the ground 6.0 s after ut us kaybcged, in si units, how tall is the building ?
The building's height is 143.8 m in SI units, and the rock strikes the ground 6.0 seconds after just missing the building's edgr as it slides downhill.
The kinematic equations of motion that explain the vertical motion of the rock may be used to calculate the height of the construction. We may use the following equations because the rock is launched vertically upward:
Y equals vi*t plus (1/2)at2 vf
^2 = vi^2 + 2ay
The maximum height will be determined first:
y = 0 * 1.75 + (1/2)(-9.8) y = vi*t + (1/2)at2 (1.75)
^2 \sy = 15.0625 m
We shall now determine the ultimate velocity:
vf = -24.3 m/s when vf = vi + 2ay when vf = 0 + 2*(-9.8)*15.0625
Using the final velocity and duration, we can now determine the height of the building:
y=vit+(1/2)at2 y=-24.36+(1/2)(-9.8) (6)
^2 \sy = -143.8 m
The metric system that serves as the industry standard for measurements is called the International System of Units (SI).
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an electron is placed at a point where the electric field (due to other charges) is where is a constant with si units of n/c. what is the electric force on the electron? (e is the elementary charge: e
The electric force e = 1.6*10^-19 C) for an electron is placed at a point where the electric field (due to other charges) is where is a constant.
The electron would be an elementary particle with either an elementary electric charge of -1. Electrons are the initial generation of both the lepton particle family as well as are widely regarded as elementary particles due to the lack of known components as well as substructure.
The electric force on the electron is equal to the electric field multiplied by the charge of the electron:
F = E*e = (n/c)*1.6*10^-19 C = 1.6*10^-19*n N
The nucleus and electrons are drawn to one another by the electric force. The void created by a positive or negative charge is referred to as an electric field since it generates a field there.
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A rod 21.5 cm long is uniformly charged and
has a total charge of -19.4 µC.
Find the magnitude of the electric field
along the axis of the rod at a point 21.8888 cm
from the center of the rod. The Coulomb con-
stant is 8.98755 × 10⁹ Nm²/C².
Answer in units of N/C. Answer in units
of N/C.
Answer:
The electric field can be found using Coulomb's law, which states that the force on a point charge due to a uniform distribution of charges is given by the equation:
E = k * Q / r^2
where E is the electric field, k is Coulomb's constant, Q is the total charge, and r is the distance from the point charge to the center of the distribution of charges.
In this problem, we are given that the rod is uniformly charged and has a total charge of -19.4 µC. We are also told that the distance from the point to the center of the rod is 21.8888 cm. To find the electric field, we can substitute these values into Coulomb's law:
E = (8.98755 * 10^9 Nm^2/C^2) * (-19.4 * 10^-6 C) / (21.8888 cm)^2
converting cm to m to get the units of N/C
E = (8.98755 * 10^9 Nm^2/C^2) * (-19.4 * 10^-6 C) / (0.218888 m)^2
E = -5.54717 N/C
The magnitude of the electric field along the axis of the rod at a point 21.8888 cm from the center of the rod is -5.54717 N/C.
Note that the negative sign on the answer indicates that the electric field points in the opposite direction of the distance vector.
Many drugs under development are delivered by nanoparticles in the bloodstream. To monitor changes in the nanoparticles, investigators can retrieve them from the blood by using a device with electrodes that apply oscillating electric fields. The nanoparticles, which are electrically conducting, are strongly attracted to the nearest electrode, while blood cells, which are poor conductors, experience only a weak force toward the nearest electrode, and suspended ions in the blood experience no net force. Explain why the conducting nanoparticles are strongly attracted to the electrodes while other components of the blood are not
The conducting nanoparticles are strongly attracted to the electrodes because they are affected by the oscillating electric fields due to their electrical conductivity, while the other components of the blood, such as blood cells and ions, experience only a weak or no force due to their poor conductivity or lack of charge.
How do nanoparticles interact with the immune system?Nanoparticles can interact with the immune system in various ways. They can be engulfed by immune cells, such as macrophages, which can then present antigens to other immune cells, triggering an immune response. They can also evade detection by the immune system by escaping from phagocytic cells or by disguising themselves as host molecules. Additionally, the size, surface chemistry, and shape of nanoparticles can affect how they interact with immune cells, influencing the type of immune response they elicit. Some nanoparticles may also have immunomodulatory properties, meaning they can modulate the immune response in a desired way.
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what are the magnitude and direction of the elctric force on an electron in a uniform electric field of strength 2360n/c that points due east?
The magnitude of an electron's electric force in a uniform electric field of strength 2360 N/C pointing due east is 3,781 x 10⁻¹⁶ N (positive)
Electric force is defined as the repulsive or attractive interaction between two charged bodies. Newton's laws of motion describe the impact and effects of any force on the given body.
The formula for electric force:
F = E x q
Where,
F = electric force (N)
E = electric field (N/C)
q = charge (Coulomb)
An electron is also negatively charged, with a charge of 1.60217662 10⁻¹⁹ C.
Hence, the magnitude of an electron's electric force in a uniform electric field of strength 2360 N/C pointing due east is:
F = E x q
= (2360 N/C) x (1.60217662 x 10⁻¹⁹ C)
= 3,781 x 10⁻¹⁶ N
The direction is positive.
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Two cannons / same amount of powder / same size cannon balls / one is short and the other is long, Which one would send the cannon ball a greater distance? Explain using physics
A cannon is a large-caliber gun that belongs to the artillery category. It typically fires a projectile propelled by an explosive chemical.
What are Cannons?Before smokeless powder was developed in the late 19th century, gunpowder, sometimes known as "black powder," served as the main propellant.
Depending on their intended purpose on the battlefield, different types of gun combine and balance these characteristics to differing degrees. Cannons differ in gauge, effective range, mobility, rate of fire, angle of fire, and firepower.
The word "cannon" is borrowed from a number of languages, with the original meanings typically being "tube," "cane," or "reed."
Therefore, A cannon is a large-caliber gun that belongs to the artillery category. It typically fires a projectile propelled by an explosive chemical.
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what are the sign and magnitude in coulombs of a point charge that produces a potential of -2.00 v at a distance of 5.00 mm? c
-1.11 × 10⁻¹³ is the sign and magnitude in coulombs of a point charge that produces a potential of -2.00 v at a distance of 5.00 mm.
Given:
Potential = -2.00 V
Distance = 5.00 mm
= 5 × 10⁻³ m
We know that electric potential due to charge is
V = kq/r
where,
v = Electric potential energy
q = point charge
r = distance between any point near the charge to the point of the charge
k = coulomb constant
Now put the values in above equation then we get the value of q from the above equation
[tex]-2 = \frac{8.99 \times 10^{9} \times q}{5 \times 10^{-3}}[/tex]
[tex]q = \frac{-2 \times 5 \times 10^{-3}}{8.99 \times 10^{9}}[/tex]
q = -1.11 × 10⁻¹³
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if the truck has four-wheel drive, and the cabinet is wooden, what is it's maximum acceleration (in m/s2)?
The maximum acceleration will be 4.9 m/s², if the truck has four wheels and the static friction coefficient is 1.
Let the mass of the truck, M
Let the force require to overcome the static friction is F.
Let the acceleration in the forward direction is a.
Coefficient of static friction, μ = 1
4 wheels(2 rear and 2 front wheels) will share the equal force of friction resistance. Force of friction will be equal to the forward force applied by the truck.
That will be F₁/2 = F₂/2 = F
F₁/2 = F₂/2 = μMg/2 = F
μMg/2 = Ma
a = μg/2
a = (1×9.81)/2
a = 4.9 m/s²
--The give question is incomplete, the complete question is:
"The truck has four-wheel drive, and the cabinet is wooden, what is it's maximum acceleration (in m/s2), if the coefficient of static friction is 1?"
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in the bohr model of the hydrogen atom, an electron orbits a proton in a circular orbit of radius 0.53 x 10e-10 m. what is the electric potential at the electron's orbit due to the proton?
The electric potential is 27.2V
The electric potential (also called the electric field potential, potential drop, the electrostatic potential) is defined as the amount of work energy needed to move a unit of electric charge from a reference point to the specific point in an electric field.When an object is moved against the electric field, it gains some amount of energy which is defined as the electric potential energy. The electric potential of the charge is obtained by dividing the potential energy by the quantity of charge. When work is done in moving a charge of 1 coulomb from infinity to a particular point due to an electric field against the electrostatic force, then it is said to be 1 volt of the electrostatic potential at a point.Electric potential is given by equation: V = kq/r
where,
k = Coulomb's constant = 9 ×10⁹ N m²/C²
r = Radius = 0.53×10⁻¹⁰ m
Putting these values in above equation we get:
V = (9 ×10⁹)(1.6 × 10⁻¹⁹)/( 0.53×10⁻¹⁰) = 27.2 V
So the electric potential is 27.2V
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a 2-wire circuit supplies a 36a load that's located 100 ft from the panelboard. the load is wired with 1 awg aluminum conductors in pvc conduit. what's the total alternating-current ohms-to-neutral resistance of the circuit conductors?
The total voltage drop across the 1 awg aluminum conductors is 0.58 volts, if the current carried by the conductor is 36 Ampere.
Current carrying by the conductor, I = 36 A
length of the wire, l = 100 ft.
According to the ampacity Chart For AWG Aluminum Wires, The resistance of the 1 awg aluminum wire is 0.161Ω/1000 ft
So the resistance of the 100 ft wire would be, R = (0.161 × 100)/1000
R = 0.0161 Ω
So the total voltage drop will be, V = IR
V = 36 × 0.0161
V = 0.58 volt
So the total voltage drop across the conductor will be 0.58 volt.
--The given question is incomplete, the complete question is:
"a 2-wire circuit supplies a 36a load that's located 100 ft from the panelboard. the load is wired with 1 awg aluminum conductors in pvc conduit. What will be the total potential drop across the circuit conductors?"
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You weigh 750 N.
What would you weigh if the Earth were
three times as massive as it is and its radius
were four times its present value?
Answer in units of N.
Earth suddenly has 3 times as much mass ... weight is 3 times as much
You're suddenly 4 times as far from the center ... weight = (1/4²) = 1/16
New weight = (original weight) x (3/16)
New weight = (750 N) x (3/16)
New weight = 140.6 N
what is the air temperature where a tuning fork has a frequency of 534 hz and a wavelength of 64 cm?
The air temperature where a tuning fork has a frequency of 534 hz and a wavelength of 64 cm is calculated to be 16.63 °C.
Frequency of the tuning fork = 534 hz
Wavelength = 64 cm = 64/100 m = 0.64 m
Temperature = ?
We know the relation between speed of air and temperature as,
v = 331 √(1+ T/273) ----(1)
where, T is in Celsius
The relation between speed, wavelength and frequency is said to be,
v = frequency × wavelength = 534 × 0.64 = 341.76 m/s ----(2)
Placing (2) in (1),
341.76 = 331 √(1+ T/273)
1.03 = √(1+ T/273)
1+ T/273 = 1.0609
T/273 = 0.0609
T = 16.63 °C
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a concave mirror forms an image on a screen twice as large as the object. both object and screen are then moved to produce an image on the screen that is three times the size of the object. if the screen is moved 75 cm in the process, how far is the object moved? what is the focal length of the mirror?
The size of the image is determined by the distance between the object and the mirror (object distance) and the distance between the mirror and the screen (image distance).
Using the formula for image distance (1/f = 1/object distance + 1/image distance), we can find the focal length of the mirror:
1/f = 1/object distance + 1/image distance (twice the object size)
1/f = 1/object distance + 2
1/f = 1/object distance + 1/image distance (three times the object size)
1/f = 1/object distance + 3
We know that the image distance (the distance from the mirror to the screen) is 75 cm in both scenarios, so we can set up the equations using that information:
1/f = 1/object distance + 2 (twice the object size)
75 = 2 * object distance + f
1/f = 1/object distance + 3 (three times the object size)
75 = 3 * object distance + f
Solving for object distance in the first equation:
object distance = (75 - f) / 2
Substituting that into the second equation:
75 = 3 * ((75 - f) / 2) + f
Simplifying and solving for f:
75 = (225 - 3f) / 2 + f
150 = 225 - 3f
3f = 75
f = 25 cm
So the focal length of the mirror is 25 cm.
To find the distance the object is moved, we can use the equation for object distance:
object distance = (75 - f) / 2
object distance = (75 - 25) / 2
object distance = 25 cm
So, the object is moved 25 cm in the process.
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high-speed stroboscopic photographs show that the head of a 200-g golf club is traveling at 55 m/s just before it strikes a 46-g golf ball at rest on a tee. after the collision, the club head travels (in the same direction) at 40 m/s. find the speed of the golf ball just after impact
The speed of the golf ball just after impact will be 65.22 m/s when the head of a 200-g golf club is traveling at 55 m/s just before it strikes a 46-g golf ball at rest on a tee. after the collision, the club head travels (in the same direction) at 40 m/s.
Initially, head just before it strikes
m1 = 200 g, u1 = 55 m/s
mass of ball m2 = 46 g at rest u2 = 0
After the collision,
head speed v1 = 40 m/s
find: speed of golf ball, v2
Now, applying the Conservation of Linear Momentum
m1u1 + m2u2 = m1v1 + m2v2 {Both traveling in same direction}
200(55) + 0 = 200(40) + 46(v2)
or v2 = 200 x 15/46
or v2 = 65.22 m/s
Therefore, the speed of the golf ball just after impact will be 65.22 m/s when the head of a 200-g golf club is traveling at 55 m/s just before it strikes a 46-g golf ball at rest on a tee. after the collision, the club head travels (in the same direction) at 40 m/s.
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you have 2.97 amps traveling on the secondary ct circuit of a 2000:5 ct, what are the primary amps on the 69kv bus?
The primary amps on the 69kv bus would be 14.835 amps.
To determine the primary amps on the 69kv bus in this scenario, you would need to use the CT ratio of 2000:5. The CT ratio is used to convert the current on the secondary side of the CT to the current on the primary side. In this case, the secondary current is 2.97 amps, so you would multiply that by the ratio of 2000:5 (2000/5 = 400) to get the primary current.
2.97 amps x 400 = 14.835 amps.
Therefore the primary current on the 69kv bus is 14.835 amps.
It's important to note that this calculation assumes that the CT is functioning correctly and that the primary and secondary circuits are properly connected.
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5. Explain how changes in ther-
mal energy and changes in
state of matter are related.
Thermal energy absorption or release can cause a change in the state of matter.
How are changes in the state of matter connected to thermal energy?Thermal energy is either supplied or subtracted when a particular piece of matter changes states, but the temperature stays constant. Thermal energy , for instance, is what causes the bonds inside a solid to disintegrate when it is melted.Thermal energy absorption or release can cause a change in the state of matter. State change refers to this alteration. Figure 11's graph illustrates how the temperature of an ice container varies when thermal energy is gradually supplied to it . As a result of being heated, its temperature increases.To learn more about thermal energy refer to:
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a proton moves in a region of constant electrical field. does it follow that the protons velocity is parallel to the electric fieldd?
Yes, it does follow that the proton's velocity is parallel to the electric field.
This is because when a particle moves in a constant electric field, it will experience a force equal to its charge multiplied by the magnitude of the electric field. This force will cause the particle to accelerate in the direction of the electric field, resulting in a velocity that is parallel to the electric field.
Additionally, the particle's acceleration is proportional to the electric field's magnitude, so if the electric field is increased, the particle will accelerate faster and its velocity will become more parallel to the electric field. This is why it is important to ensure that the electric field is constant when conducting experiments involving particles in an electric field.
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An 8. 0-kg history textbook is placed on a 1. 25-m high desk. How large is the gravitational potential energy of the textbook-earth system relative to the floor
The textbook-earth system has a gravitational potential energy of 98 J relative to the floor.
What is gravitational potential energy?Gravitational energy, also known as gravitational potential energy, is the potential energy possessed by a massive object in relation to another massive object as a result of gravity. It is the potential energy associated with the gravitational field that is released when two objects collide. Gravitational potential energy is the energy that an object possesses or acquires as a result of a change in its position when it is in a gravitational field. In layman's terms, gravitational potential energy is energy that is related to gravitational force or gravity.
Here,
The energy possessed by a body due to its placement in gravitational field. It is given by:
G.P.E. = m g h
m is the mass of the object, g is the acceleration due to gravity and h is the height.
mass of the book, m = 8.0 kg
height of the desk on which book is kept, h = 1.25 m
acceleration due to gravity, g = 9.8 m/s²
G.P.E = 8.0 kg × 9.8 m/s² × 1.25 m = 98 J
The gravitational potential energy of the textbook-earth system relative to the floor is 98 J.
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two positive point charges having equal charge values are surrounded by water and the distance between them is 0.378 m. if the magnitude of the total electric force on one of them is 148 n, what must be the charge of one of these particles in coulombs?
The charge on each of the particles must be 4.33 × 10⁻⁴ C, if the force between them is 148 N, and the distance between them 0.378 m.
The force between the particles is, F = 148 N
Permittivity of the free space, ε₀ = 8.8 × 10⁻¹² Far/meter
Distance between the particles, r = 0.378 m
Let the charge on each particles is equal = q
Dielectric constant of water, k = 80
Permittivity of the water, ε = kε₀ = 80 × 8.8 × 10⁻¹²
ε = 704 × 10⁻¹²
The force between two charge, F = (1/(4πε))(q²/r²)
148 = q²/(4×π×704 × 10⁻¹²×0.378²)
q² = 148 × 4×π×704 × 10⁻¹²×0.378²
q² = 1.87 × 10⁻⁷
q = 4.33 × 10⁻⁴ C
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how much energy is stored by the electric field between two square plates, 7.9 cm on a side, separated by a 2.1- mm air gap? the charges on the plates are equal and opposite and of magnitude 14 nc . express your answer using two significant figures and include the appropriate units.
Energy is stored by the electric field between two square plates, 7.9 cm on a side, separated by a 2.1- mm is 0.18MV/m.
The electric field stored between two square plates, 7.9 cm on a side, separated by a 2.1-mm air gap is calculated by using the equation
E=V/d, where E is the electric field, V is the voltage, and d is the distance between the plates. The voltage is equal to the charge on the plates divided by the area of the plates,
V=Q/A.
Therefore, the electric field is equal to 14 nC/(7.9 cm)².
The electric field stored is 0.18 MV/m. This energy is expressed using two significant figures and includes the appropriate units.
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what property of a mineral indicates that it has cleavage?
Cleavage is the tendency of a mineral to break along smooth flat surfaces when struck. It is a property that reflects the crystal structure and is an indication of the mineral's internal atomic arrangement. A mineral with cleavage will break along specific planes, often yielding flat and smooth surfaces.
What type of minerals typically exhibit cleavage?Cleavage is a property of minerals that refers to the way they split or break along certain planes. Minerals that exhibit cleavage have a tendency to break along specific, smooth and flat surfaces. This property is caused by the internal arrangement of atoms in the mineral's crystal structure. Minerals that typically exhibit cleavage include micas, halite, calcite, fluorite, quartz, and feldspar. Minerals that exhibit good cleavage can be easily separated into thin sheets or plates, making them useful for a variety of industrial and commercial applications.
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Cleavage is a property of a mineral that indicates its tendency to break along certain flat surfaces, rather than in a random pattern.
What do you mean by Cleavage?Bond cleavage, also known as bond fission, is the splitting of chemical bonds in chemistry. When a molecule is split into two or more pieces, this is commonly referred to as dissociation. According to how the bond is broken, there are generally two types of bond cleavage: homolytic and heterolytic.
In chemistry, cleavage essentially refers to the bond breaking. There are two types of cleavage: (1) An equal distribution of electrons between the two atoms causes a link between them to cleave. (2) In this form of connection, the most electronegative atom receives the bond's electron.
The presence of cleavage is an indicator of the arrangement of atoms in the crystal structure of the mineral, and the direction of the cleavage surfaces is determined by the crystal lattice. The term "cleavage" is often used interchangeably with the term "fracture," although fracture refers to any type of break in the mineral, regardless of whether it follows a specific pattern or not.
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2.
A loaded Boeing 747 jumbo jet has a mass of 200,000 kg. What net force is required to give the plane an
acceleration of 3. 5 m/s down the runway for takeoffs?
Answer:
We can use Newton's second law of motion to calculate the net force required to accelerate an object. The equation is:
F = ma
Where:
F = net force (N)
m = mass of the object (kg)
a = acceleration (m/s^2)
Given that the mass of the loaded Boeing 747 is 200,000 kg and the desired acceleration is 3.5 m/s^2. We can substitute these values into the equation:
F = 200,000 kg * 3.5 m/s^2 = 700,000 N
Therefore, the net force required to give the plane an acceleration of 3.5 m/s^2 is 700,000 N. This is a significant force, which is required to overcome the inertia of the massive object, and to move it down the runway.