There are a total of 50 numbers that are between 1 and 50. Halft of these numbers are even (divisible by 2 ) and half of then odd.
There are 25 integers that are not even and in total there are 50 integers; thereofre, the probablity of finding an even integer is
25/50 = 1/2
Suppose a normal distribution has a mean of 98 and a standard deviation of6. What is P(x < 110)?A. 0.84B. 0.16C. 0.025O D. 0.975
We know that
• The mean is 98.
,• The standard deviation is 6.
,• The given x-value is 110.
First, we find the z-value using the following formula
[tex]Z=\frac{x-\mu}{\sigma}_{}[/tex]Replacing the given information, we have
[tex]Z=\frac{110-98}{6}=\frac{12}{6}=2_{}[/tex]The z-value or z-score is 2.
Then, we use a z-table to find the probability when P(x<110), or P(z<2).
We obtain a probability of 0.97, which approximates to D.
Hence, the probability would be D.Mean player age Mean Absolute Team Three golf teams wanted to compare the ages of their players. Each team calculated their players' mean age in years and the mean absolute deviation of their ages. They displayed the results in this table. 9.5 45 Appleton Coalvale 31 15.9 Which statements are true? Summerton 43 16.1 Select each correct answer. Team Coalvale's players ages and Team Summerton's players ages vary about the same amount Team Summerton's players ages and Team Appleton's players ages vary about the same amount Team Appleton's players ages vary less than do Team Summerton's players ages. Team Appleton's players ages vary more than do Team Coalvale's players ages. a ? 7+ O i JOTE to search
Given:
• Appleton: Mean = 45; Mean Absolute deviation = 9.5
,• Coalvale: Mean = 31; Mean Absolute deviation = 15.9
,• Summerton: Mean = 43; Mean Absolute deviation = 16.1
Using the given data, let's select the correct statements.
From the data we can see the difference between the Mean Absolute Deviations of team Coalvale and Summerton is (16.1 - 15.9) = 0.2
This means the ages of team Coalvale and Summerton vary about the same about.
The Mean Absolute deviation of Appleton is far from other mean absolute deviation. This means the players ages for team Appleton vary less than others.
Therefore, the correct statements are:
• Team Coalvale's players ages and Team Summerton's players ages vary about the same amount.
• Team Appleton's players ages vary less than do Team Summerton's players ages.
ANSWER:
• Team Coalvale's players ages and Team Summerton's players ages vary about the same amount.
• Team Appleton's players ages vary less than do Team Summerton's players ages.
You cut a piece of wood that is 69 inches long. The wood is cut into 3 pieces. The second piece is 8 inches
longer than the first. The third piece is 8 inches longer than the second piece. Find the length of each of
the three pieces.
The length of piece one will be 15 inch, the length of piece two will be 23 inch and the length of third piece will be 31 inch as per the given conditions of "You cut a piece of wood that is 69 inches long. The wood is cut into 3 pieces. The second piece is 8 inches longer than the first. The third piece is 8 inches longer than the second piece."
What is system of equation?A finite set of equations for which common solutions are sought is referred to in mathematics as a set of simultaneous equations, also known as a system of equations or an equation system.
What is equation?In mathematics, an equation is an expression or a statement that consists of two algebraic expressions that have the same value and are separated from one another by the equal symbol. It is an otherwise stated statement that has been mathematically quantified.
Here,
according to the question,
x+y+z=69
y=x+8
z=y+8
z=x+16
3x+24=69
3x=45
x=15
y=23
z=31
According to the conditions specified, piece one will be 15 inches long, piece two will be 23 inches long, and piece three will be 31 inches long. "You chop a 69-inch-long piece of wood. Three pieces of the wood are cut out. Eight inches longer than the first piece is the second one. Eight inches longer than the second piece is the third one."
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Hello can you please help me with problem number 12
Turn the 48in to ft
[tex]\begin{gathered} 1ft=12in \\ \\ 48in\times\frac{1ft}{12in}=4ft \end{gathered}[/tex]Then, 48 inches is equal to 4ft.
Comparing the given quatities you get that:
48inches > (greater than) 3ftLaney can finish 17 math problems in 51 minutes while Hayden can finish 6 problems in 18 minutes. Is this a proportional relationship.
Given data:
The 17 maths problem finish by Laney in 51 minutes.
The 6 maths problem finish by Hayden in 18 minutes.
The time taken by Laney to finish 1 problem is,
17 prob=51 minutes
1 prob=3 minute.
Simmiarly, the time taken by Hayden to finish 1 problem is,
6 prob=18 minutes
1 prob=3 minute.
As, the time taken by the Laney and Hayden to solve one problem is same .
Thus, the given relationship is proportional one.
If f(x) = ln [ sin2(2x)(e-2x+1) ] , then f’(x) is
I want to solve ?
Here we will write our function in regular form using an identity.
[tex]log(ab)=loga+logb[/tex][tex]log(a/b)=loga-logb[/tex]Therefore, the rule of our function [tex]f(x)[/tex] will be as follows.
[tex]f(x)=ln(sin^2(2x))+ln(e^{-2x}+1)[/tex]The derivative of the natural logarithm [tex]ln(x)[/tex] function is of the following form.
[tex](ln(x))'=\frac{x'}{x}[/tex]It is found by dividing the derivative of the function in [tex]lnx[/tex] by the function in [tex]lnx[/tex].
For example:
[tex](ln(5x))'=\frac{(5x)'}{5x} =\frac{5}{5x} =\frac{1}{x}[/tex]According to this information, let's take the derivative of our function.
[tex]f'(x)=\frac{2sin(4x)}{sin^2(2x)} +\frac{-\frac{2}{e^{2x}} }{e^{-2x}+1}[/tex][tex]f'(x)=4cot(2x)-\frac{2}{1+e^{2x}}[/tex]Rules:[tex]((sin2x)²)'=2.2sin(2x)cos(2x)=2sin(4x)[/tex][tex](e^x)'=x'.e^x[/tex]value of a machine10(thousands of dollars)01 2 3 4 5 6 7 8 9 10Age of Machine(years)Which equation best represents the relationship between x, the age of the machine in years, and y, thevalue of the machine in dollars over this 10-year period?F.y = -0.002x + 2,500G.y = -500x + 8,000H.y = 500x + 8,000J.y = 0.002x + 2,500
To find the right answer, first, we find the slope.
Let's use the slope formula, and the points (0,8) and (8,4).
[tex]m=\frac{y_2-y_1_{}}{x_2-x_1}[/tex]Replacing the points, we have.
[tex]m=\frac{4-8}{8-0}=\frac{-4}{8}=-\frac{1}{2}=-0.5[/tex]However, the Value is express in thousands of dollars, which means the slope is -500.
Observe that G is the only equation with the correct slope.
Therefore, G is the right answer.Two figures are similar. The smaller figure has dimensions that are 3:4 the size of the largerfigure. If the area of the larger figure is 100 square units, what is the area of the smallerfigure?
Answer:
56.25
Explanation:
We are told that the side lengths of the smaller figure are 3/4 the length of the larger figure.
[tex]S_{small}=\frac{3}{4}\times S_{large}[/tex]Now since the area is proportional to the equal of the side lengths, we have
[tex]A_{small}=S_{small}^2^[/tex][tex]A_{small}=(\frac{3}{4})^2\times S_{large}^2[/tex][tex]=A_{small}=(\frac{3}{4})^2\times A_{large}^2[/tex]The last is true since A_large = S^2_large.
Now we are told that A_large = 100 square units; therefore,
[tex]A_{small}=(\frac{3}{4})^2\times100[/tex][tex]\Rightarrow A_{small}=\frac{9}{16}\times100[/tex]which we evaluate to get
[tex]A_{small}=\frac{9}{16}\times100=56.25[/tex][tex]\boxed{A_{small}=56.25.}[/tex]Hence, the area of the smaller figure is 56.25.
The measure of side VT is 60 inches. Find the length of side VProunded to the nearest tenth.
It is important to notice that side VP is the hypothenuse of the triangle, and VT is the adjacent leg to 30°.
To find VP, we just have to use the cosine function
[tex]\begin{gathered} \cos 30=\frac{VT}{VP} \\ \cos 30=\frac{60}{VP} \\ VP=\frac{60}{\cos 30} \\ VP\approx69.3 \end{gathered}[/tex]Hence, VP is 69.3 inches long.Which postulate or theorem proves that ∆ABC and ∆EDC are congruent?
O AAS Congruence Theorem
O HL Congruence Theorem
O SAS Congruence Postulate
O SSS Congruence Postulate B
1. Which fraction equals a repeatingdecimal?530АC503013B.1325D1013
5/30 = 1/6 = 0.16666667
13/25 = 0.52
30/50 = 3/5 = 0.6
13/10 = 1.3
As you can see the fraction which is equal to a repeating decimal is:
5/30 = 1/6 = 0.16666667
I need help with #1 and 2 please I’m struggling
The slope of a line perpendicular to other line is the negative reciprocal of the slope.
This means, if the slope of a line is x, the slope of a perpendicular line will be:
[tex]-\frac{1}{x}[/tex]Then , the first thing we should do is to find the slope of f(x).
To find the slope of a line that passes two points P and Q we use:
[tex]\begin{gathered} \begin{cases}P=(x_p,y_p) \\ Q=(x_q,y_q)\end{cases} \\ \text{slope}=\frac{y_p-y_q}{x_p-x_q} \end{gathered}[/tex]In this case, we can use P = (1, 4) and Q = (-3, 2)
Then:
[tex]\text{slope}=\frac{4-2}{1-(-3)}=\frac{2}{4}=\frac{1}{2}[/tex]Now, we know that the slope of g(x) is perpendicular to f(x) which has a slope of 1/2
The reciprocal is:
[tex]\frac{1}{2}\Rightarrow\frac{2}{1}=2[/tex]And to make it the negative, we multiply by (-1):
[tex]2\cdot(-1)=-2[/tex]Thus, g(x) has a slope equal to -2
The standard deviation of the weights of elephants is known to be approximately 15 pounds. We wish to construct a 95% confidence interval for the mean weight of newborn elephant calves. Fifty newborn elephants are weighed. The sample mean is 244 pounds. The sample standard deviation is 11 pounds. Round all answers to the nearest hundredth. Conclusion: We estimate with 95% confidence that the mean weight of all elephants is between?
Confidence interval is written as
point estimate ± margin of error
In this case, the point estimate is the sample mean
the formula for calculating margin of error is expressed as
[tex]\text{margin of error = z }\times\frac{\sigma}{\sqrt[]{n}}[/tex]where
σ = population standard deviation
n = sample size
z is the z score corresponding to a 95% confidence level. From the standard normal distribution table, z = 1.96
From the information given,
σ = 15
n = 50
sample mean = 244
By substituting these values into the formula,
[tex]\text{margin of error = 1.96 }\times\frac{15}{\sqrt[]{50}}\text{ = 4.16}[/tex]Thus,
confidence interval = 244 ± 4.16
Lower limit of conidence interval = 244 - 4.16 = 239.84
Upper limit of conidence interval = 244 + 4.16 = 248.16
Conclusion: We estimate with 95% confidence that the mean weight of all elephants is between 239.84 pounds and 248.16 pounds
PLEASE HELP! To prepare for a bike race, Rex rides his bike for 12 miles each day for 3 days. The app he uses only tracks distance in kilometers. If 1 mile = 1.61 kilometers, what is Rex's distance in kilometers? Round the answer to the nearest hundredth. 7.45 kilometers 19.32 kilometers 22.36 kilometers 57.96 kilometers
Based on the distance that Rex rode every day for three days, Rex's distance in 3 days in kilometers can be found to be 57.96 kilometers.
How to find the distance in miles?First, find the distance that Rex rode in those three days in miles. This can be found as:
= Number of miles rode per day x Number of days
= 12 x 3
= 36 miles
Then convert this to kilometers.
If one mile is 1.61 kilometers, then 36 miles would be:
= Number of miles x Miles per kilometer
= 36 x 1.61
= 57.96 kilometers
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If Rex rides his bike for 12 miles each day for 3 days. Then distance in kilometers is 57.96.
What is Distance?The length along a line or line segment between two points on the line or line segment.
Speed=Distance / Time
Distance=Speed × Time.
Given that Rex rides his bike for 12 miles each day for 3 days
and 1 mile = 1.61 kilometre.
Let us convert 12 miles to kilometres
12×1.61=19.32 km
Now let us calculate the Distance as the speed is 19.32km and time is 3 days.
By the formula to get distance we have to multiply speed and time.
Distance=19.32×3
=57.96
Hence Rex's distance in kilometers is 57.96.
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Translate each sentence into an equation. Then find each number.
The sum of six, and a number divided by two is 0.
the possible answers are:
y/2-6=0;y=12
2y+6=0;y=-3
y/2+6=0;y=12
y/2+6=0;y=-12
The sum of six and a number divided by two is zero is translating into an equation is y/2+6 = 0, and the number is y = -12
The given sentence is "The sum of six and a number is divided by two is 0"
Consider the number as y
A number is divided by two = y/2
The sum of 6 and a number divided by two = y/2 + 6
The sum of six and a number is divided by two is 0
y/2 + 6 = 0
We have to solve the equation
Move the 6 to the right hand side of the equation
y/2 = -6
Move the 2 to the right hand side of the equation
y = -6×2
Multiply the numbers
y = -12
Hence, the sum of six and a number divided by two is zero is translating into an equation is y/2+6 = 0, and the number is y = -12
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Two sides of a triangle have lengths 5 and 4. Which of the following can NOT be the length of the third side?
SOLUTION
From the triangle inequality theorem, the sum of the lengths any two sides must be greater than the length of the third side
So, looking at the options and looking at 4 and 5, it means that 5 is the longest side. So
[tex]\begin{gathered} 4+2=6>5 \\ 4+4=8>5 \\ 4+1=5=5 \\ 4+3=8>5 \end{gathered}[/tex]So since 4 + 1 = 5 and 5 is not greater than 5, hence 1 cannot be the length of the 3rd side.
The answer is option C
When finding the height of a triangle, you need to find the equation of the lineperpendicular to the base of the triangle that passes through the vertex opposite thebase and then find the point of the intersection of the base and the perpendicular line. True Or False?
EXPLANATION:
Given;
We are given the step by step procedure to find the height of a triangle.
Required;
We are required to determine if the step by step solution is true or false.
Solution/Explanation;
When finding the height of a triangle, we may use the Pythagoras theorem or we may use trigonometric ratios for right angled triangles.
Note that the Pythagoras' theorem is also used only for right angled triangles and one of the three sides will be the height of the triangle.
When required to calculate the the height of a triangle given a line perpendicular to the base (that is, at a 90 degree angle with the base), and passing through the vertex opposite the base, the triangle can be effectively split into two parts along the perpendicular and the perpendicular line will then become the height. Also depending on the amount of information available, we may use the Pythagoras' theorem (if the other two sides are given). Alternatively we may use the trigonometric ratios if one other side and one of the angles is given.
Therefore,
ANSWER:
FALSE
Gabe made a scale drawing of a neighborhood park. The scale of the drawing was 1 millimeter : 6 meters. If the actual length of the volleyball court is 18 meters, how long is the volleyball court in the drawing?
what is the expression written in simplified radical form.
question is attached below.
please help
The expression 6√27 + 11√75 written in simplified radical form is 73√3.
What is an expression?An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.
Example: 2 + 3x + 4y = 7 is an expression.
We have,
6√27 + 11√75
We will simplify the radicals into the simplest form.
Radical means the numbers under square roots and cube roots.
6√27
= 6 √(9 x 3)
= 6 x √9 x √3
= 6 x √3² x √3
= 6 x 3 x √3
= 18√3
11√75
= 11 x √(25 x 3)
= 11 x √25 x √3
= 11 x √5² x √3
= 11 x 5 x √3
= 55√3
Now,
6√27 + 11√75
= 18√3 + 55√3
= (18 + 55)√3
= 73√3
Thus,
The expression 6√27 + 11√75 written in simplified radical form is 73√3.
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Determine the rate of change of a line that passes through the coordinates G (-13, -4) andB (7, -12). Reduce when necessary. (Show all work)
EXPLANATION:
-We must first identify the points that correspond to the x-axis and the points that correspond to the y-axis.
-To calculate the slope, then we apply the formula of the slope or rate of change which is the following:
[tex]\begin{gathered} \text{the rate of change :} \\ m=\frac{y2-y1}{x2-x1}\text{ } \end{gathered}[/tex]-now we must correctly locate the points in the formula.
[tex]\begin{gathered} G\text{ }(-13,-4),\text{ X1}=-13\text{ and y1}=-4 \\ B(7,-12);\text{ X2}=7\text{ and y2}=-12 \\ m=\frac{-12-(-4)}{7-(-13)}\text{ }=\frac{-12+4}{7+13}=\frac{-8}{20}=\frac{-4}{10} \\ simplify;\text{ }\frac{-4}{10}=\frac{-2}{5} \end{gathered}[/tex]-
1 + 3 4 Solve. 3 A 8 B 2 3 1) 1. Illuminate Education TM, Inc.
Given:
[tex]\frac{1}{2}+\frac{3}{4}[/tex]Let's add the fractions above.
To perform the addition, find the Lowest Common Multiple (LCM) of the denominators.
LCM of 2 and 4 = 4
Divide each denominator by the LCM and multiply the result with the numerator.
Thus, we have:
[tex]\begin{gathered} \frac{1}{2}+\frac{3}{4} \\ \\ \frac{2+3}{4}=\frac{5}{4} \\ \\ \frac{5}{4} \end{gathered}[/tex]Convert the improper fraction (5/4) to mixed fraction.
We have:
[tex]\frac{5}{4}=1\frac{1}{4}[/tex]ANSWER:
[tex]1\frac{1}{4}[/tex]The function f(x) = 5x+3 is one to one. Find an equation for f-1(x) the inverse function.
Given the function:
[tex]f\mleft(x\mright)=5x+3[/tex]To find the inverse function, we make x the subject of the equation.
[tex]\begin{gathered} 5x=f(x)-3 \\ x=\frac{f(x)-3}{5} \end{gathered}[/tex]Next, we replace x with f-1(x) and f(x) with x.
Therefore, the inverse function is:
[tex]f^{-1}(x)=\frac{x-3}{5}[/tex]Use the commutative property of multiplication to write an equivalent expression to 69xuse the distributive property to write an equivalent expression to 8(c+5) that has no grouping symbols.
Answer
69x = 69 × x = x × 69
8 (c + 5)
= 8c + 40
Explanation
The commutative property of multiplication for two numbers a and b, is given as
a × b = b × a = ab
69x = 69 × x = x × 69 = 69x
Question 2
The distributive property for openingh brackets involving three numbers a, b and c is given as
a (b + c)
= ab + ac
So, for this question
8 (c + 5)
= 8c + 40
Hope this Helps!!!
I need help with this math problem
Answer: [tex]s=4f[/tex]
Step-by-step explanation:
The scaled copy has a side length four times of the original figure, so the equation is [tex]s=4f[/tex].
the four faced of a rectangular pyrimid below are painted yellow. how many square feet will be painted
The number of square feet to be painted is equal to the surface area of the four face painted yellow.
Total Surface Area (TSA) =
[tex]4(\frac{1}{2}bh)[/tex]By Pythagoras Theorem,
[tex]\begin{gathered} h^2+1.5^2=5^2 \\ h^2=5^2-1.5^2 \\ h=\sqrt[]{25-2.25}\text{ =}\sqrt[]{22.75}=4.7697\text{ fe}et \end{gathered}[/tex]find the height of the trapezoidA=80 CM2 7Cm9CM
The area formula for trapezoids is
[tex]A=\frac{(B+b)h}{2}[/tex]Where B = 9 cm, b = 7 cm, and A = 80 cm2. Let's replace these dimensions to find h
[tex]\begin{gathered} 80=\frac{(9+7)\cdot h}{2} \\ 160=16h \\ h=\frac{160}{16} \\ h=10 \end{gathered}[/tex]Hence, the height is 10 cm.Below is the graph of a polynomial function with real coefficients. All local extrema of the function are shown in the graph.
Given
A graph of a polynomial with the real coefficients.
To find:
a) The intervals in which the function is increasing is,
[tex]\begin{gathered} (-\infty,-5) \\ (-2,2) \\ (6,\infty) \end{gathered}[/tex]b) The value of x at which the unction has local minima.
From the graph shown in the figure, there is only one local minimum at x=-2.
c) The sign of the functions leading coefficient is positive.
Since the graph is moving upwards.
d) The degree of the function is 5.
A small toy rocket is launched from a 32-foot pad. The height ( h, in feet) of the rocket t seconds after taking off is given by the formula h=−2t2+0t+32 . How long will it take the rocket to hit the ground?t=______(Separate answers by a comma. Write answers as integers or reduced fractions.)
Given: A small toy rocket is launched from a 32-foot pad. The height (h, in feet) of the rocket t seconds after taking off is given by the formula
[tex]h=-2t^2+0t+32[/tex]Required: To find out how long will it take the rocket to hit the ground.
Explanation: When the rocket touches the ground its height will be zero i.e.,
[tex]\begin{gathered} -2t^2+0t+32=0 \\ 2t^2=32 \\ t^2=16 \end{gathered}[/tex]Which gives
[tex]t=\pm4[/tex]Neglecting the negative value of t since time cannot be negative. We have
[tex]t=4\text{ seconds}[/tex]Final Answer: Time, t=4 seconds.
Enter an algebraic inequality for the sentence. Use x as your variable. The quotient of five times a number and 9 is no more than 15. The answer is ____ < ____
Answer:
[tex]\frac{5x}{9}\leq15[/tex]write the function below in slope. Show ALL the steps and type the answer.
This is a simple question to solve. First, let's take a look at a slope-intercept form equation as follows:
Once we know how a slope-intercept form looks like all we need to do is to simplify our equation to find that as follows:
And that is our slope-intercept form: