Considering the ideal gas law, 116.06 moles of are needed to fill a 2000 L weather balloon at 210 K and 1 atm pressure.
An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.
The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:
P×V = n×R×T
where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas. The universal constant of ideal gases R has the same value for all gaseous substances.
In this case, you know:
P= 1 atmV=2000 Ln= ?R= 0.082057 [tex]\frac{atmL}{molK}[/tex]T= 210 KReplacing in the ideal gas law:
1 atm× 2000 L = n× 0.082057 [tex]\frac{atmL}{molK}[/tex]× 210 K
Solving:
[tex]n=\frac{1 atmx 2000 L}{0.082057 \frac{atmL}{molK}x 210 K}[/tex]
n=116.06 moles
Finally, 116.06 moles of are needed to fill a 2000 L weather balloon at 210 K and 1 atm pressure.
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https://brainly.com/question/4147359?referrer=searchResultshow to find change in kinetic energy with velocity
Answer:
We know that ΔK = Kf - Ki = 1/2 m Vf^2 - 1/2 m Vi^2 = 1/2m(Vf^2-Vi^2) = 1/2 m ΔV^2.
The mass remains the same, just calculate the difference of squared velocities and multiply it by half of the mass.
given how the quantity work—which has units of energy—was defined, another unit for energy, equivalent to the joule (j), is
Answer:
I think you ask for another way of writing the joule (J). It can be expressed as the product between a force applied to a body and the deployment of the body (not necessarily caused by that force applied), so N*m (newton * meter).
The quantity work—which has units of energy—was defined, another unit for energy, equivalent to the joule (j), is Newton ·meter (N· m).
What is unit of physical quantities?The quantity with a constant magnitude that is used to measure the magnitudes of other quantities of the same type is referred to as a unit in physics.
A unit shouldn't alter as time or environmental factors like pressure and temperature change.It ought to be precisely defined.It need to be readily available and repeatable.Unit of work is that of energy, that is, Joule (J).
Again, work = force × displacement
Unit of work = Unit of force × Unit of displacement = Newton . meter (N.m).
Hence, the quantity work—which has units of energy—was defined, another unit for energy, equivalent to the joule (j), is Newton ·meter (N· m).
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PLEASE HELP also i know this isnt physics but there was no HOPE/Gym subject for me to choose.
Answer:
Plan B.
Because flexibility is best improved by stretching.
Explanation:
Improving and increasing flexibility is done by having stretching sessions daily which maintains and widens the range of motion in the joints and stretches muscles.
An object with a mass of 13.2 kg is accelerating at 9.4 m/s? What force is being applied on the object?
Round your answer to the appropriate number of significant figures and use the following formula:
force = mass x acceleration
Force = mass x acceleration:
Force = 13.2 kg x 9.4 m/s
Force = 124.08
Force = 124 Newtons
The force will be = 124 N
What is newton's second law of motion?
Newton's second law is a quantitative description of the changes that a force can produce on the motion of a body. It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.
according to newton's second law of motion
Force = mass * acceleration
given
mass = 13.2 kg
acceleration = 9.4 m/s
force = 13.2 * 9.4
= 124.08 N
Rounding off answer to the appropriate number of significant figures
force = 124 N
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A force f is applied horizontally to block A of mass m1 which is in contact with a block B of mass m2. If the surfaces are frictionless, the force exerted by A on B is given by?
Answer:
Reaction force = Weight
the force exerted by A on B is equal.
M1a = M2a
Explanation: I think the answer is right if wrong message me.
You are pulling a friend on a sled with a constant velocity using a rope held
horizontally in the snow. Using a spring scale attached to the rope, you
measure the tension to be 112 N. The combined mass of the sled and your
friend is 57.4 kg. Write the surface force the ground exerts on the sled in
component form, and determine its magnitude.
Here are all the steps.
When you are pulling a sled with constant velocity with a rope then the ground exerts a surface force on the sled will be equal to 573.56 N.
What is tension?The pulling force delivered axially by a cable, string, chain, or by either end of a rod, truss member, or another such 3-D object is known as tension in physics. Tension can be described as the action-reaction pair of forces acting at each end while tension is a polar opposite of compression.
A restoring force causes tension when atoms or molecules are torn apart at the atomic level and build up potential energy.
When you are trying to move upward and push in a positive way,
F = - 112 i + 57.4 (9.8) j
F = -112 i + 562.52 j
[tex]F = \sqrt{(-112)^2+ (562.52)^2}[/tex]
[tex]F =\sqrt{12544 + 316428.7}[/tex]
F = 573.56 N
Therefore, the surface force the ground exerts on the sled is 572.52 N.
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I desperately need help with my Physics Exam I am failing this class will mark Brainliest to whoever helps the most: PART 1 (I don't want to overwhelm anyone so I'm posting my questions in parts) Also the questions marked are incorrect, so just work with the 3 remaining answers.
10000000 thank you's
A wave completes one vibration as it moves a distance of 2 meters at a speed of 20 meters per second. What is the frequency of the wave?
I need the Formula,Known,Substitute & Solve Answer with Units
Answer:
I put the answer
Explanation:
Can you see it
10Hz is the frequency of the wave.
How to find the frequency of the wave?
To calculate the frequency of a wave, divide the velocity of the wave by the wavelength. Write your answer in Hertz or Hz
Given,
F = 2
λ=2m
v=20m/s
By applying the formula, we get
V = Fλ
F = V / λ
F = 20 / 2
=10Hz
Wave frequency is the number of waves that pass a fixed point in a given amount of time.
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The length of daylight changes as the seasons change during the year. what causes these changes in the number of daylight hours?
Answer:
The earth travels around the sun in a (parabolic) path known as the ecliptic.
The axis of the earth's rotation is tilted about 23 deg to the ecliptic.
At the winter solstice (around Dec. 21), the sun will appear to be at its farthest south in its orbit. (This marks the beginning of winter for observers in the northern hemisphere and the beginning of summer for an observer in the southern hemisphere)
The tilt of the axis of the earth's rotation causes the change in the daylight hours.
can someone explain it please ?
Answer:
The value of [tex]\theta=63.43^0[/tex]
Explanation:
Range of projectile [tex]\mathrm{R}=\frac{\mathrm{u}^{2} \cdot \sin 2 \theta}{\mathrm{g}}[/tex]
Height of projectile [tex]\mathrm{h}=\frac{\mathrm{u}^{2} \cdot \sin ^{2} \theta}{2 \cdot \mathrm{g}}[/tex]
Here we have
[tex]R=2h\\\\\frac{\mathrm{u}^{2} \cdot \sin 2 \theta}{\mathrm{g}}=2\frac{\mathrm{u}^{2} \cdot \sin ^{2} \theta}{2 \cdot \mathrm{g}}\\\\\sin 2 \theta=\sin ^{2} \theta\\\\2\sin \theta\cos \theta=\sin ^{2} \theta\\\\\tan \theta=2\\\\\theta=63.43^0[/tex]
Range be R and height be h
[tex]\boxed{\sf R=\dfrac{u^2sin2\theta}{g}}[/tex]
[tex]\boxed{\sf h=\dfrac{u^2sin^2\theta}{2g}}[/tex]
u=initial velocitytheta is angle of projection.g=acceleration due to gravityATQ
[tex]\\ \sf\longmapsto R=2h[/tex]
[tex]\\ \sf\longmapsto \dfrac{u^2sin2\theta}{g}=\dfrac{2u^2sin^2\theta}{2g}[/tex]
Cancelling required ones[tex]\\ \sf\longmapsto sin^2\theta=sin2\theta[/tex]
sin2O=2sinOcosO[tex]\\ \sf\longmapsto sin^2\theta=2sin\theta cos\theta [/tex]
[tex]\\ \sf\longmapsto \dfrac{sin^2\theta}{sin\theta cos\theta=2[/tex]
[tex]\\ \sf\longmapsto \dfrac{sin\theta}{cos\theta}=2[/tex]
[tex]\\ \sf\longmapsto tan\theta=2[/tex]
[tex]\\ \sf\longmapsto \theta=tan^{-1}(2)[/tex]
[tex]\\ \sf\longmapsto \theta=63.4°[/tex]
what does the slope of the curve on a velocity vs. time graph represent?
Answer:
the slope of velocity-time graph represent an object acceleration
which research model refers to the study of an individual group or community over a predetermined period
Developing Psychological Theories: Mastery Test
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Hope this helps :)
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a 280 nm thin film with index of refraction 1.6 floats on waterwhat is the largest wavelength of reflected light for which constructive interference occur? answer in units of m.
Answer:
Inside the film the wavelength will be λ/n
For constructive interference to occur the film must be λf/4 thick where λf is the wavelength of the light in the film - there will be a 180 degree phase shift at the water/film interface since the index of refraction of the film is greater than that of water - and the light has to travel λ/2 inside the film for constructive interference to occur
280 nm / 1.6 * 4 = 700 nm is the greatest wavelength allowed
Note that 700 nm is also the upper wavelength of the visible spectrum
how do you think the liquid density affects the buoyancy of objects placed in the liquid?
Answer:
density can be written as:
d = F / V (weight density) or M / V (mass density)
Since F in the first equation can be written as
B = d V where B is the buoyant force and is proportional to the
weight of the liquid displaced
For a given volume the weight of the liquid displaced is proportional to the density and hence the buoyant force
Write AT LEAST 10 SENTENCES based on ONE event that has happened in your life.
Please do it am so tired
Sorry your tired, ill try to make it worth reading.
One day I walked outside, I looked around. THEN BAM a wasp lands right on my face. Its hideously sharp stinger impaled my flesh. I could almost hear it going deeper and deeper. I screamed and ran around in circles until it finely flew away. As I started walking to the door I could feel my heart pules where the thing had stung. I opened the door and went into the bathroom. Right in the middle of my face just above my nose was a red dot, with a slightly less red ring around it, like an ateroid impact. I sat down and went over the entire event five times. I decided to go back outside, as I walked around the corner, another wasp landed on me.
At which point does a substance have the greatest amount of kinetic energy
Help please I will mark you the brainly!
D)
Explanation:
Coz the position changes with time but the position change is not constant throughout time So, D) does not have constant velocity
Yoo what it do I don’t know the answer tho
Answer:
You should try your best to answer the question.
For a uniformly accelerated motion the graph of displacement versus time would be
Explanation:
hope this may help you
have a nice day
45. 3. (III) A 7.26 kg bowling ball hangs from the end of a 2.5 m rope. The ball is pulled back until the rope makes an angle of 45 with the vertical. a. What is the increase in the ball’s potential energy when it is lifted? b. If the ball is released from rest and swings downward like a pendulum, how much kinetic energy will the ball have at the bottom of its swing? c. How fast will the ball be moving at the bottom of its swing?
Explanation:
For the first question look at the picture. It should be pretty clear. Remember that cos45° = sqrt2 / 2.
2) We calculate it thanks to the conservation of mechanical energy:
Em1 = Em2
U1 + K1 = U2 + K2
K1 = 0J
U2 = 0j
U1 = K2
3) mgh = 1/2mv^2
v = sqrt(2gh)
I need help to build a mouse trap race car for my science class and this is my final and these are the materials I have.
So, your science teacher has given your class the classic "mousetrap car" assignment: to make, design, and build a small vehicle powered by the snapping action of a mousetrap to make your car travel as far as possible. If you want to come out ahead of all the other students in your class, you'll need to make your car as efficient as possible so you can squeeze every last inch out of your "car". With the right approach, it's possible to streamline your car's design for maximum distance using only common home materials. You could also buy a mousetrap car kit from any craft store and skip wondering if it will work.
Use large rear wheels. Large wheels have greater rotational inertia than small wheels. In practice, this means that once they start rolling, they're harder to stop rolling. This makes large wheels perfect for distance-based contests — theoretically, they'll accelerate less quickly than smaller wheels, but they'll roll much longer and they'll travel a greater distance overall. So, for maximum distance, make the wheels on the drive axle (the one the mousetrap is tied to, which is usually the rear one) very large. The front wheel is a little less important — it can be large or small. For a classic drag racer look, you'll want big wheels in the back and smaller ones in front.
Use thin, light wheels. Thinner wheels have less friction and may go farther if the distance is what you want or need with your mousetrap racer. It's also important to take the weight of the wheels themselves into account — any unneeded weight will ultimately slow your car down or lead to added friction. In addition, it's worth noting that wide wheels can even have a small negative effect on the car's drag due to air resistance. For these reasons, you'll want to use the thinnest, lightest wheels available for your car.
Old CDs or DVDs work fairly well for this purpose — they're large, thin, and extremely light. In this case, a plumbing washer may be used to reduce the hole size in the middle of the CD (to fit the axle better).
If you have access to old vinyl, these also work extremely well, though they may be too heavy for the smallest mousetraps.
Use a narrow rear axle. Assuming your car is a rear-wheel-drive car, each time your rear axle turns, the rear wheels turn. If your rear axle is extremely skinny, your mousetrap car will be able to turn it more times for the same length of string than it would if it were wider. This translates to turning your rear wheels more times, meaning greater distance! For this reason, it's a wise idea to make your axle out of the skinniest material available that can still support the weight of the frame and wheels.
Narrow wooden dowel rods are a great, easily-accessible choice here. If you have access to thin metal rods, these are even better — when lubricated, they usually have less friction.
Create traction by giving the edges of the friction of the wheels. If the wheels slip against the ground when the trap is sprung, energy is wasted — the mousetrap works to make the wheels turn, but you don't get any extra distance. If this happens with your car, adding a friction-inducing material to the rear wheels may reduce their slippage. To keep your weight requirements down, use only as much as is necessary to give the tips of the wheels some grip and no extra. Some suitable materials are:[1]
Electrical tape
Rubber bands
Additionally, placing a piece of sandpaper under the rear wheels at the start line can reduce slippage as the car begins to move (when it is most likely)
The position as a function of time for two objects moving along a straight line is shown in the graph,
Which statement is true about the distances the two object have traveled at time ty?
Object 1 has traveled a greater distance.
B
Object 2 has traveled a greater distance.
Both objects have traveled the same distance
D
The total distance traveled by each object cannot be compared using the graph.
The distance traveled by object 1 is greater than the distance traveled by object 2.
The shortest distance between two points is a straight line. More distance is covered when the path of motion is curved.
The distance traveled by each object at different time is compared as follows;
[tex]at \ t_ A , \ \ \ d_1>d_2 \ \ \ (d_2 = 0)\\\\at \ t_B, \ \ d_1 > d_2 \\\\at \ t_C, \ \ \ d_2 > d_1 \\\\at \ t_D \ \ \ d_1 = d_2\\\\at \ t_f \ \ \ d_2 > d_1 \ \ \ (d_1 = 0)[/tex]
The major distinguishing distance traveled by each occurs at [tex]t_B[/tex] and [tex]t_C[/tex].
[tex]d_{(t_B)} > d_{(t_C)} \\\\d_1 > d_2[/tex]
Thus, we can conclude that the distance traveled by object 1 is greater than the distance traveled by object 2.
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It takes a car 4 seconds to slow down from 22 m/s to 6 m/s , what was its acceleration?
To Find The Acceleration of A Car Slowing Down:
The change in speed is the final speed minus the initial speed. To find acceleration, divide the change in velocity by the length of time during which the velocity changed.
a narrow slit is illuminated with sodium yellow light of wavelength 589 nm. if the central maximum extends to ±30.0°, how wide is the slit?
Answer:
because of the gravity of the earth
4) What process produces carbon dioxide?
a) photosynthesis
b) replication
c) mutation
d) respiration
5) What happens during cytokinesis?
a) a spindle forms
b) chloroplasts release energy
c) the cytoplasm divides
d) chromosomes
plz answer asap
Answer:
d and c are the answers :)
calculate the resultant force acting on the object and state its direction
[tex]\\ \sf\Rrightarrow F_{net}=F_1+F_2+F_3+F_4[/tex]
[tex]\\ \sf\Rrightarrow F_{net}=20N+20N+10N-10N[/tex]
[tex]\\ \sf\Rrightarrow F_{net}=40N[/tex]
Direction is east.1. Which among the sports you stated above are you familiar with?
I am familiar with Russian Mountaineering
Two spherical balloons are filled with water. The first balloon has a radius of 3 cm, and the second has a radius of 6 cm. How much greater is the volume of water in the larger balloon than in the smaller balloon? Use 3. 14 to approximate pi. Round to the nearest hundredth if necessary. Enter your answer as a decimal in the box.
Answer:
V = 4/3 R^3
V2 / V1 = (R2 / R1)^3 = 2^3 = 8
8.00
The volume of water in the larger balloon is 8 times greater than in the smaller balloon
We'll begin by calculating the volume of each balloon.
For smaller balloon:Radius (r) = 3 cmPi (π) = 3.14Volume (V) =?V = 4/3 πr³
V = 4/3 × 3.14 × 3³
V = 113.04 cm³For larger balloon:Radius (r) = 6 cmPi (π) = 3.14Volume (V) =?V = 4/3 πr³
V = 4/3 × 3.14 × 6³
V = 904.32 cm³Finally, we shall determine how much greater the larger balloon is to the smaller balloon
Volume of smaller balloon = 113.04 cm³Volume of larger balloon = 904.32 cm³Greatness =?Greatness => large / small
Large / small = 904.32 / 113.04
Large / small = 8
Cross multiply
Large = 8 × smallTherefore, the larger balloon is 8 times greater than the smaller balloon.
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You want to replace the resistor in your
boiler with a more efficient one during win-
tertime. Would you replace it with another
one double the length or half the length?
To make the boiler more efficient, we would replace the resistor with another double the length.
We know that the resistance of the resistor in the boiler is given by R = ρl/A where
ρ = resistivity, l = length of resistor and,A = cross-sectional area of resistor.Also, the power generated by the resistor is P = i²R where
i = current and R = resistance.If i is constant, we see that P ∝ R.
So, to increase the efficiency, the value of the resistance has to increase.
Also, since R = ρl/A and ρ and A are constant, we see that R ∝ l.
Since P ∝ R and R ∝ l ⇒ P ∝ l.
So, to increase the efficiency, we would double the length of the resistor.
So, to make the boiler more efficient, we would replace the resistor with another double the length.
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In the United States, radioactive waste is divided into three main categories based on their activity, their heat generation potential, and what they physically contain.
Low level radioactive waste is the least dangerous type of nuclear waste. It contains relatively small amounts of radioactive substances with short half-lives.
Which of the following methods is most commonly used to dispose of low level radioactive wastes?
A.
activating reactions so the material is no longer radioactive
B.
sealing the waste into steel tanks and burying the tanks deep into the ground
C.
compacting the waste and burying it in a shallow landfill
D.
sealing in a biohazard bag and disposing the bag with ordinary trash
Answer:
C.Compacting the waste and burying it in a shallow landfill.
Explanation:
It is buried in a shallow landfill because it is less reactive.