At 25 ∘C
, the equilibrium partial pressures for the reaction

A(g)+2B(g)↽−−⇀C(g)+D(g)

were found to be A=5.63
atm, B=5.00
atm, C=5.47
atm, and D=5.63
atm.

What is the standard change in Gibbs free energy of this reaction at 25 ∘C ?

Δ∘rxn= ? kJmol

Therefore, the standard enthalpy change for reaction (3) is -152.6 kJ.

To determine the standard enthalpy change for reaction (3), we can use Hess's law, which states that the overall enthalpy change for a reaction is the sum of the enthalpy changes for each step of the reaction.

We can see that reaction (1) has the same products as reaction (3) but in reverse order. We can use reaction (1) to reverse the formation of FeO:

2Fe(s) + O2(g) → 2FeO(s) ΔH° = -544.0 kJ

2FeO(s) → 2Fe(s) + O2(g) ΔH° = +544.0 kJ (reversed)

We can also use reaction (2) to form ZnO, which is a product in reaction (3):

2Zn(s) + O2(g) → 2ZnO(s) ΔH° = -696.6 kJ

Now, we can add the two reactions to get the overall reaction (3):

2FeO(s) + 2Zn(s) → 2Fe(s) + 2ZnO(s)

We add the enthalpies of the two reactions to get the enthalpy change for reaction (3):

ΔH° = (+544.0 kJ) + (-696.6 kJ)

ΔH° = -152.6 kJ

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Answer:

The molar ratio of oxygen to water in the given chemical equation is 150₂ : 6H₂O which can be simplified to 25₂ : H₂O or 25 : 3 1.

The mole ratios are determined using the coefficients of the substances in the balanced chemical equation 1. In order to determine the mole ratio, we need to begin with a balanced chemical equation. For this reaction, the balanced chemical equation is:

2C6H6 + 150₂ = 6H₂O +12CO2

The mole ratios for this reaction are:

2molC6H6 : 150molO2 : 6molH2O : 12molCO2

I hope that helps! Let me know if you have any other questions.

As a result, aluminium (Al) and 7.37 litres of hydrochloric acid (HCl) can react to produce 225.46 moles of hydrogen gas (H2).

As a result, when 8 moles of aluminium are entirely consumed during the process of dissolving it in HCl solution, 12 moles of hydrogen gas are created.

The chemical reaction between aluminium (Al) and hydrochloric acid (HCl) has the following balanced chemical equation:

[tex]3 H2 + 2 AlCl3 = 2 HCl + 2 Al[/tex]

According to the equation, 2 moles of HCl result in 3 moles of H2. In order to determine the amount of H2 generated, we must first determine how many moles of HCl are contained in 7.37 litres of acid.

The following formula can be used to determine the quantity of HCl:

Volume in litres times concentration in moles per litre equals moles.

Since the HCl concentration is not specified in the inquiry, we are unable to immediately calculate the moles. However, we may convert the volume in litres to the mass in grams using the density of HCl, and then use the molar mass of HCl to calculate the number of moles.

At standard circumstances (0 °C and 1 abm), HCl has a density of roughly 1.49 g/mL. As a result, 7.37 litres of HCl have the following mass:

Density equals mass, therefore 7.37 L times 1.49 g/mL equals 10.9763 kg.

Since HCl has a molar mass of about 36.46 g/mol, there are the following moles of HCl:

[tex]10.9763 kg / 36.46 g/mol = 300.61 mol is the formula for moles of HCl.[/tex]

Now, we can determine the number of moles of H2 created using the mole ratio from the balanced equation: moles of[tex]H2 = (moles of HCl / 2) x (3/2) = (300.61 mol / 2) x (3/2) = 225.46 mol[/tex]

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The following formula can be used to calculate the activation energy: ln (k 1 /k 1) = É a /R x (1/S n 1 - 1/T 2). where. E an is the reaction's activation energy, expressed in J/mol.

What does a scientific reaction mean?

reaction definitions in science. reaction. one or more new compounds are formed as a result of the reorganization of the atoms and molecules of two substances when come into contact. Electrons of one material interact with all those of another to produce chemical reactions.

What chemical process changes one substance into another?

Chemical reaction is the process through which two or more compounds, known as reactants, change into one or more new ones, known as products. Chemical components or compounds make up substances. The atoms that make up the reactants are rearranged in a chemical reaction to produce various products.

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Answer:

1) 9 moles

2) 8.75 moles

3) 1.76 moles

4) 10.2 moles

Explanation:

Okay so mole ratio is 2:1

So, 9 moles of HI is required for 4.5 moles of Iodine gas

Mol ratio of water to CaCl2 is 2:1

So, 17.5 moles of water produced is (17.5/2) moles of CaCl2 i.e. 8.75 moles

Okay so mol ratio of Hydrogen to NH3 is 3:2

So, 2.64 moles of hydrogen is (2.64 * 2)/3 moles of NH3 i.e. 1.76 moles

Once again, mol ratio of Hydrogen to NH3 is 3:2

When 15.3 moles of hydrogen is used, (15.3 * 2)/3 moles of NH3 i.e. 10.2 moles

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Answer: 40. g

Explanation:

To find the grams in 0.89 moles of CO2, we just need to use the molar mass of CO2. The molar mass which tells us how many grams are in a mole for an element or compound.

The molar mass of CO2 is equal to the molar mass of carbon, 12.0107, and 2 oxygens, 2*15.9994 (you can find the molar mass of an element on any periodic table). Add these, and you get the molar mass of CO2 to be 44.01 g/mol, a helpful value to remember.

Now, just multiply the molar mass by the amount of moles to find grams.

[tex]\frac{44.01g}{mole} * 0.89mole[/tex], moles cancel out, [tex]\frac{44.01g}{mole} * 0.89mole=40.48g[/tex]

There are 2 significant figures in the question, so I will round this answer to 2 significant figures, 40. g

The sign of entropy change of the universe at room temperature is b.) positive, spontaneous

The concept of entropy is a measure of the degree of disorder or randomness in a system. In thermodynamics, it is a measure of the number of ways in which the energy of a system can be distributed among its constituent particles.

The second law of thermodynamics states that the entropy of the universe always increases for spontaneous processes. This means that, in any spontaneous process, the total entropy change of the system and its surroundings must be positive.

At room temperature (298.15 K), a process that is spontaneous will always result in an increase in the entropy of the universe, and the sign of the entropy change will be positive.

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54.2 g of CaCl2 must be dissolved in 1000 g of water to raise the boiling point to 100.75°C.

To solve this problem, we can use the formula:

ΔTb = Kb × m × i

where ΔTb is the boiling point elevation, Kb is the molal boiling point elevation constant for water, m is the molality of the solution, and i is the van't Hoff factor, which represents the number of particles into which the solute dissociates.

We can rearrange this formula to solve for the molality of the solution:

m = ΔTb / (Kb × i)

We know that ΔTb is 0.75°C (100.75°C - 100°C), Kb is 0.51°C/m, and i for CaCl2 is 3 (since it dissociates into 3 ions in water). Substituting these values, we get:

m = 0.75°C / (0.51°C/m × 3) = 0.490 m

To find the mass of CaCl2 needed to make a 0.490 m solution in 1000 g of water, we can use the formula:

moles of solute = molality × mass of solvent (in kg)

We convert 1000 g of water to 1 kg, and then use the molecular weight of CaCl2 to convert from moles to grams:

moles of CaCl2 = 0.490 m × 1 kg = 0.490 mol

mass of CaCl2 = 0.490 mol × 110.98 g/mol = 54.2 g

Therefore, 54.2 g of CaCl2 must be dissolved in 1000 g of water to raise the boiling point to 100.75°C.

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Answer:

Molecules in the skin are moving faster than molecules in the glass.

Explanation:

Put it in your own words.

Answer:

The energy from the ice transferred to the glass.

The sandwich contains approximately 71.25 grams of carbohydrates.

Calories are a unit of measurement used to quantify the amount of energy contained in food and beverages. The number of calories in a particular food is determined by the amounts of carbohydrates, fats, proteins, and other nutrients it contains.

To determine the number of grams of carbohydrates in the sandwich, we need to use the fact that carbohydrates, fats, and proteins have different calorie densities. Specifically, carbohydrates and proteins each contain about 4 calories per gram, while fats contain about 9 calories per gram.

First, let's calculate the total number of calories coming from the fat and protein in the sandwich:

Total calories = calories from carbohydrates + calories from fat + calories from protein

475 Calories = calories from carbohydrates + 10g x 9 Calories/g + 25g x 4 Calories/g

475 Calories = calories from carbohydrates + 90 Calories + 100 Calories

475 Calories - 190 Calories = calories from carbohydrates

285 Calories = calories from carbohydrates

Now that we know the number of calories from carbohydrates, we can use the calorie density of carbohydrates to determine the number of grams of carbohydrates:

285 Calories = carbohydrates in grams x 4 Calories/g

71.25 g = carbohydrates in grams

Therefore, the sandwich contains approximately 71.25 grams of carbohydrates.

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Answer:

o

Mass number

Atomic number

Number of electrons

Proton number

Explanation:

The ΔG for the reaction at 298 K and the given partial pressures is -55.53 kJ/mol.

What is ΔG ?

The Gibbs free energy change for a reaction under non-standard conditions can be calculated using the following equation:

ΔG = ΔG° + RTln(Q)

where ΔG is the Gibbs free energy change, ΔG° is the standard Gibbs free energy change, R is the gas constant (8.314 J/(mol·K)), T is the temperature in kelvin, and Q is the reaction quotient.

The reaction quotient, Q, can be calculated using the partial pressures of the gases involved in the reaction:

Q = (P(NH3))² / (P(N2) x P(H2)³)

Plugging in the given values, we get:

Q = (0.75 atm)² / (0.35 atm x 0.30 atm³) = 0.2667

Now we can calculate the ΔG for the reaction:

ΔG = ΔG° + RTln(Q)

ΔG = (-32.8 kJ/mol) + (8.314 J/(mol·K) x 298 K x ln(0.2667))

ΔG = -32.8 kJ/mol + (-22.73 kJ/mol)

ΔG = -55.53 kJ/mol

Therefore, the ΔG for the reaction at 298 K and the given partial pressures is -55.53 kJ/mol.

What is reaction quotient?

Reaction quotient, commonly denoted as Q, is a measure of the relative concentrations of reactants and products in a chemical reaction at a particular moment in time. It is calculated by dividing the concentration of the products raised to their stoichiometric coefficients by the concentration of the reactants raised to their stoichiometric coefficients.

The equation for the reaction quotient Q is similar to the equilibrium constant Kc, but with the concentrations of the reactants and products at any time during the reaction, rather than at equilibrium. When the reaction is at equilibrium, the reaction quotient is equal to the equilibrium constant.

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The amount of carbon dioxide produced by all the idling described in the problem would be 89.6 kg per week.

What is Global Warming?

Global warming refers to the long-term increase in Earth's average surface temperature, primarily caused by human activities such as burning fossil fuels (coal, oil, and natural gas), deforestation, and industrial processes that release large amounts of greenhouse gases into the atmosphere.

Using the atomic masses from the periodic table, we get:

Molar mass of octane = (8 x 12.01 g/mol) + (18 x 1.01 g/mol) = 114.22 g/mol

Since the molecular formula of octane (C8H18) contains 8 carbon atoms, it produces 8 molecules of carbon dioxide (CO2) per molecule of octane during combustion.

So, the amount of carbon dioxide produced by burning 11,200 grams of octane would be:

11,200 g * (8 x 1 mol CO2 / 1 mol octane) = 89,600 g or 89.6 kg of carbon dioxide produced in a week.

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Answer:

Explanation:

dilute solutions of hydrochloric acid (HCl), sulphuric acid (H₂SO₄), and nitric acid (HNO₃) react with active metals to produce a salt and hydrogen gas.

Active metals react strongly and quickly with other elements and compounds due to the electrons in its structure and its ease of sharing the electrons with other elements.

The most active metals are found in Groups 1  and 2 of the Periodic Table (i.e. the left side), and include lithium, potassium, magnesium, and calcium. Metals such as aluminium, lead, and zinc, are less active than magnesium or calcium, but are generally still labelled as 'active'. Metals such as copper, gold, or silver are inactive and will not react.

Therefore, in the provided question, all the metals listed, except for copper, will produce a metal salt + hydrochloric acid. Copper will not react.

In general:

For chemical reaction (3), the standard enthalpy change is 279.0 kJ.

To find the standard enthalpy change for reaction (3), use Hess's Law which states that the overall enthalpy change of a reaction is independent of the pathway between the initial and final states.

Obtain the required reaction by subtracting the enthalpy change of reaction (2) from that of reaction (1) as follows:

(1) 2C(s) + H₂(g) → C₂H₂(g) ΔH° = 226.7 kJ

(2) 2C(s) + 2H₂(g) → C₂H₄(g) ΔH° = 52.3 kJ

(3) C₂H₂(g) + H₂(g) → C₂H₄(g) ΔH° = ?

To get the enthalpy change for reaction (3), flip the reaction (2) and multiply by 1/2 so that the reactants match those in reaction (1):

(2) C₂H₄(g) → 2C(s) + 2H₂(g) ΔH° = -52.3 kJ

Now write the reaction (3) as the difference between (1) and (2):

(1) 2C(s) + H₂(g) → C₂H₂(g) ΔH° = 226.7 kJ

(2) C₂H₄(g) → 2C(s) + 2H₂(g) ΔH° = -52.3 kJ

(3) C₂H₂(g) + H₂(g) → C₂H₄(g) ΔH° = 279.0 kJ

Therefore, the standard enthalpy change for reaction (3) is 279.0 kJ.

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The molecular formula of the compound, given that it contains 51.39% carbon, 8.64% hydrogen, and 39.97% nitrogen is C₆H₁₂N₄

To obtain the molecular formula, we must first determine the empirical formula. Details on how to obtain the empirical formula is given beloww:

Divide by their molar mass

C = 51.39 / 12 = 4.283

H = 8.64 / 1 = 8.64

N = 39.97 / 14 = 2.855

Divide by the smallest

C = 4.283 / 2.855 = 1.5

H = 8.64 / 2.855 = 3

N = 2.855 / 2.855 = 1

Multiply through by 2 to express in whole number

C = 1.5 × 2 = 3

H = 3 × 2 = 6

N = 1 × 2 = 2

Thus, we can conclude that the empirical formula is C₃H₆N₂

Finally, we shall determine the molecular formula. Details below

Molecular formula = empirical × n = mass number

[C₃H₆N₂]n = 140.22

[(12×3) + (1×6) + (14×2)]n = 140.22

70n = 140.22

Divide both sides by 70

n = 140.22 / 70

n = 2

Molecular formula = [C₃H₆N₂]n

Molecular formula = [C₃H₆N₂]₂

Molecular formula = C₆H₁₂N₄

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Consider that after recrystallization, you obtained 7.0 g of dry pure substance from 10.0 g of impure material. Your recovery rate is then 70% (7/10 × 100).

Recrystallization recovery percentages are often lower than 100%, though occasionally they might be higher (see the following issue). This is brought on by impurity loss, material that was left in the liquid solution after dissolving, and "mechanical losses."

The amount if pure compound that is present in the finished chemical synthesis product is calculated using the percent recovery. The ratio of actual yield to theoretical yield is used to compute percent yield. The ratio of the pure compound to the starting compound is used to calculate percent recovery.

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A 5-kg object experiences the greatest gravitational force at sea level. The correct option is D.

The term force has a particular definition in science. At this standard, it is perfectly acceptable to refer to a force as both a push and maybe a pull. A force is not one that an object possesses or possesses. Another object applies a force to another. The concept of a force is not restricted to living or non-living things.

What exactly is balanced force?

Balance occurs when the forces applied have similar strengths & act in opposite directions. These forces cancel each other out, and the movements of the object on which they act remain unchanged. The correct option is D.

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The final volume of the ideal gas is 156.6 L.

A sample of an ideal gas is allowed to expand adiabatically while producing external work (W) at first. The volume is then maintained at its new value with the help of heat Q until the pressure returns to its initial level.

We can use the combined gas law to solve this problem:

(P1 × V1) / T1 = (P2 × V2) / T2

where P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P2 and V2 are the final pressure and volume, respectively. Since the gas is kept at a constant temperature, we can simplify this to:

P1 × V1 = P2 × V2

Plugging in the given values, we get:

2.01 bar × 78.3 L = 1.00 bar × V2

Solving for V2, we get:

V2 = (2.01 bar × 78.3 L) / 1.00 bar = 157 L

Therefore, the final volume of gas is 157 L.

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The mass of calcium in the original urine sample would be 0.0140 g.

First, we need to find the masses of calcium and magnesium oxalates in the original sample. Let x be the mass of calcium oxalate and y be the mass of magnesium oxalate. Then we have:

x + y = mass of the mixed oxalate precipitate

Next, we need to use the information given to find the mass of calcium in the original sample. The mass of calcium oxide formed after ignition is equal to the mass of calcium oxalate in the original sample. We can calculate the mass of calcium oxide using the mass of calcium carbonate formed and the molar mass ratio of calcium carbonate to calcium oxide.

The balanced chemical equations for the reactions are:

CaC2O4 -> CaCO3 + CO2

CaCO3 -> CaO + CO2

The molar mass of CaCO3 is 100.09 g/mol, and the molar mass of CaO is 56.08 g/mol.

From the given information, we have:

0.0433 g = (x + y)(100.09 g/mol + 80.15 g/mol) / (128.10 g/mol + 80.15 g/mol)

0.0285 g = x(56.08 g/mol) + y(40.31 g/mol)

Solving these equations simultaneously, we get:

x = 0.0140 g

y = 0.0053 g

Therefore, the mass of calcium in the original sample (which is equal to the mass of calcium oxide formed after ignition) is:

0.0140 g

So the mass of calcium in the original sample is 0.0140 g.

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Percent yield = 1566%, The percent yield is greater than 100%, which means that the student obtained more product than the theoretical yield.

The theoretical yield is the maximum amount of product that could be produced in a chemical reaction, based on stoichiometric calculations. The actual yield is the amount of product that is actually obtained from the reaction in a laboratory experiment.

To calculate the percent yield of the experiment, we need to compare the actual yield to the theoretical yield.

The balanced chemical equation for the formation of alum from aluminum and potassium hydroxide is:

2 Al + 2 KOH + 4 H₂O + 1/2 O₂ → KAl(SO₄)₂·12H₂O

From this equation, we can see that the mole ratio of aluminum to alum is 2:1. This means that for every 2 moles of aluminum used, we should theoretically obtain 1 mole of alum.

First, we need to convert the mass of aluminum foil used to moles of aluminum:

0.0432 g Al × 1 mol Al/26.98 g Al = 0.001600 mol Al

Next, we can use the mole ratio to calculate the theoretical yield of alum:

Theoretical yield = 0.001600 mol Al × 1 mol KAl(SO₄)₂·12H₂O/2 mol Al × 474.39 g KAl(SO₄)₂·12H₂O/1 mol KAl(SO₄)₂·12H₂O

= 0.0382 g KAl(SO₄)₂·12H₂O

Now we can calculate the percent yield:

Percent yield = actual yield/theoretical yield × 100%

Actual yield = 0.5987 g

Percent yield = 0.5987 g/0.0382 g × 100% = 1566%

The percent yield is greater than 100%, which means that the student obtained more product than the theoretical yield. This could be due to experimental error, such as incomplete drying of the crystals or loss of product during the experiment. It's also possible that the student accidentally used more aluminum foil than intended.

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3.4 g of HCl is therefore equivalent to roughly 0.0932 moles of HCl.

Since each molecule of HCl contains one mole of hydrogen and one mole of chlorine, the mole quantity of HCl equals the mole quantity of hydrogen and chlorine in the sample.

Approximately 36.46 g/mol is the molar mass of hydrochloric acid (HCl). We must divide the mass by the molar mass to determine the number of moles of HCl in 3.4 g of HCl:

Mass of HCl / molar mass of HCl equals moles of HCl.

3.4 grams per 36.46 grams per mole of HCl

A mole of HCl is equal to 0.0932 mol.

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In the peroxodisulfate ion, Peroxydisulfate-, all the atoms have oxidation values that add up to +6.

Most often, the polymerization of different alkenes, such as styrene, acrylonitrile, and fluoroalkenes, is started using salts of peroxydisulfate. The homolysis of peroxydisulfate causes polymerization to begin. 2 [Peroxydisulfate] [Sulfate]

Ag: +1

Sulfur: 0

Nitrogen: +2 (in Nitric oxide)

Oxygen: -2 (in Water)

Hydrogen: +1 (in Water)

The peroxodisulfate ion, Peroxydisulfate-, consists of one disulfate (Peroxydisulfate-) group and two peroxy (Oxygen2-) groups. Normal oxygen oxidation number is 2, however in a peroxy group it is -1. The charge of the ion, which is -2, is equal to the total sum of the oxidation numbers of all the atoms in the ion. As a result, we may write:

2(-1) + 2x + 8(-2) = -2

-2 + 2x - 16 = -2

2x = 12

x = +6

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The pH of .3 M NH, where is K = 1.7 x 10^-5 is 11.87 calculated from the equation of dissociation constant.

Kb= [A] /[A + ][X− ]

​1.7×10 −5 = x ^2 /0.3

⇒x= 7.5 ×10 −3

∴[OH − ][H + ]=7.5 ×10 −3

[H + ] =10 ^−14 ⇒pH=11.87

When describing the acidity or basicity of an aqueous solution, chemists use the pH scale, which is also known as acidity and previously stood for "potential of hydrogen". Greater pH values are seen in basic or alkaline solutions than acidic solutions.

Potential hydrogen is the meaning of the acronym pH, which indicates how much hydrogen is present in liquids and how active the hydrogen ion is.

As a first step, we shall ascertain the pKa of the solution before calculating its Ka. When a solution reaches the equivalence point, its pH and pKa are equal. So, by using a titration curve and the Ka = - log pKa equation, we may rapidly ascertain the value of Ka.

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Answer: the wavelength of the photon is approximately 3.58 × 10^-18 meters.

Explanation: where E is the energy of the photon, h is Planck's constant, f is the frequency of the photon, c is the speed of light, and λ is the wavelength of the photon.

We can rearrange this equation to solve for the wavelength:

λ = hc/E

where all variables have their previously defined meanings.

First, we need to convert the energy from joules to electronvolts (eV), which is a more commonly used unit for photon energy:

8.87 × 10^-28 J = 8.87 × 10^-28 J / 1.602 × 10^-19 J/eV = 5.53 × 10^-10 eV

Next, we can substitute the given values into the equation:

λ = (6.626 × 10^-34 J s) × (2.998 × 10^8 m/s) / (5.53 × 10^-10 eV)

Simplifying, we get:

λ = 3.580 × 10^-18 m

Finally, we can express the wavelength in scientific notation with three significant figures:

λ = 3.58 × 10^-18 m